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  • How does Hibernate detect dirty state of an entity object?

    - by ???'Lenik
    Is it using some kind of byte codes modification to the original classes? Or, maybe Hibernate get the dirty state by compare the given object with previously persisted version? I'm having a problem with hashCode() and equals() methods for complicated objects. I feel it would be very slow to compute hash code if the object has collection members, and cyclic references are also a problem. If Hibernate won't use hashCode()/equals() to check the dirty state, I guess I should not use equals()/hashCode() for the entity object (not value object), but I'm also afraid if the same operator (==) is not enough. So, the questions are: How does Hibernate know if a property of an object is changed? Do you suggest to override the hashCode()/equals() methods for complicated objects? What if they contains cyclic references? And, also, Would hashCode()/equals() with only the id field be enough?

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  • What is the fastest way to get the persisted object after calling Hibernate's saveOrUpdate?

    - by Dave
    I'm using Hibernate 3.2.1.ga, hibernate annotations 3.2.1.ga, and hibernate-jpa-2.0-api. I can't upgrade at this time as I'm working with legacy code. I have this generic method for saving or updating objects ... protected void saveOrUpdate(Object obj) { final Session session = sessionFactory.getCurrentSession(); session.saveOrUpdate(obj); } You can assume that every argument, "obj," will have a member field that is marked with the "@Id" annotation. I would like to change the return type to return an Object that represents the persisted object in the database (meaning if "obj" didn't contain an id before, what is returned is the database object with a populated id. What is the fastest way to do this given my versioning and generic constraints?

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  • How can creating the SessionFactory become slow after updating Hibernate?

    - by DR
    In my Java SE application I used Hibernate 3.4 and creating the SessionFactory took about 5 seconds. Today I updated to Hibernate 3.5.1 and suddenly it takes over a minute. What can be the cause of such a dramatic effect? I tried different things the better part of the day and I have no clue... Some data I collected According to the profiler the most time is spent in PersisterFactory.createClassPersister and in that method ProxyFactory.createClass takes the most time. The log shows nothing unusual Changing hibernate.bytecode.use_reflection_optimizer makes no difference

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  • Automating the input of query criteria

    - by Steve Wren
    New user to this site and found an extremely informative answer to a question I had but can't find an answer to this one. Using Access 2010, I have 42 different criteria that I need to run individually using the same query. Rather than have 42 queries, or an input parameter dialogue box where I need to enter the criteria 42 times, can I automate this so that the 42 criteria are sourced sequentially from a different table and input to the query using a macro/ module etc. Unfortunately I have no experience of SQL/VBA so am struggling. Any help would be greatly appreciated.

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  • What could be some objective criteria to compare languages? [closed]

    - by rvcoutinho
    I am performing a study on different programming languages (and its related technologies) for a mature corporate architecture. In order to conduct these studies, I need formulate some criteria prior to this evaluation. Some general (and well known) criteria are: readability, writability, reliability, cost and others (such as well-definedness, generality and portability). That said, I present the following questions: What criteria should I not forget? How to make these criteria objective?

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  • Why so Long time span in creating Session Factory?

    - by vijay.shad
    Hi My project is web application running in the tomcat container. This application is a spring framework based hibernate application. The problem with this is it takes a lot of time when creates session factory. here is the logs 2010-04-15 23:05:28,053 DEBUG [SessionFactoryImpl] Session factory constructed with filter configurations : {} 2010-04-15 23:05:28,053 DEBUG [SessionFactoryImpl] instantiating session factory with properties: {java.vendor=Sun Microsystems Inc., sun.java.launcher=SUN_STANDARD, catalina.base=/usr/local/InstalledPrograms/apache-tomcat-6.0.20, sun.management.compiler=HotSpot Tiered Compilers, catalina.useNaming=true, os.name=Linux, sun.boot.class.path=/usr/java/jdk1.6.0_17/jre/lib/resources.jar:/usr/java/jdk1.6.0_17/jre/lib/rt.jar:/usr/java/jdk1.6.0_17/jre/lib/sunrsasign.jar:/usr/java/jdk1.6.0_17/jre/lib/jsse.jar:/usr/java/jdk1.6.0_17/jre/lib/jce.jar:/usr/java/jdk1.6.0_17/jre/lib/charsets.jar:/usr/java/jdk1.6.0_17/jre/classes, java.util.logging.config.file=/usr/local/InstalledPrograms/apache-tomcat-6.0.20/conf/logging.properties, java.vm.specification.vendor=Sun Microsystems Inc., hibernate.generate_statistics=true, java.runtime.version=1.6.0_17-b04, hibernate.cache.provider_class=org.hibernate.cache.EhCacheProvider, user.name=root, shared.loader=, tomcat.util.buf.StringCache.byte.enabled=true, hibernate.connection.release_mode=auto, user.language=en, java.naming.factory.initial=org.apache.naming.java.javaURLContextFactory, sun.boot.library.path=/usr/java/jdk1.6.0_17/jre/lib/i386, java.version=1.6.0_17, java.util.logging.manager=org.apache.juli.ClassLoaderLogManager, user.timezone=Canada/Pacific, sun.arch.data.model=32, java.endorsed.dirs=/usr/local/InstalledPrograms/apache-tomcat-6.0.20/endorsed, sun.cpu.isalist=, sun.jnu.encoding=UTF-8, file.encoding.pkg=sun.io, package.access=sun.,org.apache.catalina.,org.apache.coyote.,org.apache.tomcat.,org.apache.jasper.,sun.beans., file.separator=/, java.specification.name=Java Platform API Specification, java.class.version=50.0, user.country=US, java.home=/usr/java/jdk1.6.0_17/jre, java.vm.info=mixed mode, os.version=2.6.18-128.el5, path.separator=:, java.vm.version=14.3-b01, hibernate.jdbc.batch_size=25, java.awt.printerjob=sun.print.PSPrinterJob, sun.io.unicode.encoding=UnicodeLittle, package.definition=sun.,java.,org.apache.catalina.,org.apache.coyote.,org.apache.tomcat.,org.apache.jasper., java.naming.factory.url.pkgs=org.apache.naming, sun.rmi.dgc.client.gcInterval=3600000, user.home=/root, java.specification.vendor=Sun Microsystems Inc., java.library.path=/usr/java/jdk1.6.0_17/jre/lib/i386/server:/usr/java/jdk1.6.0_17/jre/lib/i386:/usr/java/jdk1.6.0_17/jre/../lib/i386:/usr/java/packages/lib/i386:/lib:/usr/lib, java.vendor.url=http://java.sun.com/, java.vm.vendor=Sun Microsystems Inc., hibernate.dialect=org.hibernate.dialect.MySQL5InnoDBDialect, sun.rmi.dgc.server.gcInterval=3600000, common.loader=${catalina.home}/lib,${catalina.home}/lib/*.jar, java.runtime.name=Java(TM) SE Runtime Environment, java.class.path=:/usr/local/InstalledPrograms/apache-tomcat-6.0.20/bin/bootstrap.jar, hibernate.bytecode.use_reflection_optimizer=false, java.vm.specification.name=Java Virtual Machine Specification, java.vm.specification.version=1.0, catalina.home=/usr/local/InstalledPrograms/apache-tomcat-6.0.20, sun.cpu.endian=little, sun.os.patch.level=unknown, hibernate.cache.use_query_cache=true, hibernate.connection.provider_class=org.springframework.orm.hibernate3.LocalDataSourceConnectionProvider, java.io.tmpdir=/usr/local/InstalledPrograms/apache-tomcat-6.0.20/temp, java.vendor.url.bug=http://java.sun.com/cgi-bin/bugreport.cgi, server.loader=, os.arch=i386, java.awt.graphicsenv=sun.awt.X11GraphicsEnvironment, java.ext.dirs=/usr/java/jdk1.6.0_17/jre/lib/ext:/usr/java/packages/lib/ext, user.dir=/, line.separator=, java.vm.name=Java HotSpot(TM) Server VM, hibernate.cache.use_second_level_cache=true, file.encoding=UTF-8, java.specification.version=1.6, hibernate.show_sql=true} 2010-04-15 23:08:53,516 DEBUG [AbstractEntityPersister] Static SQL for entity: com.vsd.model.Order There you can see the time delay of more than 3 mins in executing these processes. My database is mysql and database server is running on the local machine only. The container environment is Centos Linux system. I am clueless about why it takes that much of time in executing these process, But when i do the same task from under eclipse it does not take that much of time. Development environment is Windows.

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  • How do I query through a many-to-many relationship using NHibernate Criteria and Lambda Extensions?

    - by Brian Kendig
    In my database I have a Person table and an Event table (parties, meetings, &c.). This many-to-many relationship is represented through an Invitation table. Each Person can have many Invitations. Each Event can also have many Invitations. If I want a list of Events to which a Person is invited, I can use this HQL query: IQuery query = Session.CreateQuery("SELECT i.Event from Invitation i where i.Person = :p"); query.SetParameter("p", person); return query.List<Person>(); How would I write this query with NHibernate criteria and Lambda Extensions?

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  • Hibernate & Sleep broken after IE 9 RTM installation in Windows 7 x64.

    - by AKa
    I have a question about hibernation. I installed Internet Explorer 9 RTM x64 on my Windows 7 x64 SP1 desktop machine. After this, computer don't entry the hibernation or (hybrid) sleep state properly. After I hibernate the computer the monitor become blank screen and the keyboard and mouse are inactive. But the machine is still running and there isn't any possibility to switch them off as only with power button. But this is recognized on next start as ineligible because of log entry with message “The previous system shutdown at xx:xx:xx on ?xx.?xx.?x was unexpected“ and menu with safe mode option. I’m clearly not sure if it has something to do with Internet Explorer installation, but I’m definitely guaranteed that before of this I never had some problems with hibernation or (hybrid) sleep. In Windows logs isn’t something suspect. I switched the hibernation off and on, installed new drivers for mainboard, graphic and network card, checked the hard disk, nothing was helpful. This is really sad, beacuse I don't like to switch the computer completely off because it takes longer to boot. Any suggestions?

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  • NonUniqueObjectException during DAO integration test?

    - by HDave
    I have a JPA/Hibernate application and am trying to get it to run against H2 and MySQL. Currently I am using Atomikos for transactions and C3P0 for connection pooling. Despite my best efforts my DAO integration tests are failing with org.hibernate.NonUniqueObjectException. I do tend to re-use the same object (same ID even) over and over for all the different tests and I am sure that is the cause, but I can see in the logs that Spring Test and Atomikos are clearly rolling back the transaction associated with each test method. I would have thought the rollback would have also cleared the persistence context too. On a hunch, I added an a call to dao.clear() at the beginning of the faulty test methods and the problem went away!! Rollback doesn't clear the persistence context...hmmm.... Not sure if this is relevant, but I see a possible autocommit setting problem in the log file: [20100613 23:06:34] DEBUG [main] SessionFactoryImpl.(242) | instantiating session factory with properties: .....edited for brevity.... hibernate.connection.autocommit=true, ....more stuff follows Because I am using connection pooling, I figure that Hibernate is where I'll have to indicate I want autocommit off. I found the autocommit property documented here and I put it in my EntityManagerFactory config as follows: <bean id="myappTestLocalEmf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="myapp-core" /> <property name="persistenceUnitPostProcessors"> <bean class="com.myapp.core.persist.util.JtaPersistenceUnitPostProcessor"> <property name="jtaDataSource" ref="myappPersistTestJdbcDataSource" /> </bean> </property> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="database" value="$DS{hibernate.database}" /> <property name="databasePlatform" value="$DS{hibernate.dialect}" /> </bean> </property> <property name="jpaProperties"> <props> <prop key="hibernate.transaction.factory_class">com.atomikos.icatch.jta.hibernate3.AtomikosJTATransactionFactory</prop> <prop key="hibernate.transaction.manager_lookup_class">com.atomikos.icatch.jta.hibernate3.TransactionManagerLookup</prop> <prop key="hibernate.connection.autocommit">false</prop> <prop key="hibernate.format_sql">true"</prop> <prop key="hibernate.use_sql_comments">true</prop> </property> </bean>

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  • Getting all objects with a certain element inside a collection of strings with criteria API.

    - by Jens Jansson
    Hey. I'm trying to build a Hibernate Criteria query to find entities that have a specific element inside a collection. We can take as an example a Book -object that looks like this: public class Book { private Long id; private String title; private Set<String> authors = new HashSet<String>(); } The entity is mapped like this: <class name="Book" table="Book"> <id name="id" column="BOOK_ID"> <generator class="native"/> </id> <property name="title"/> <set name="authors" table="Book_Authors"> <key column="BOOK_ID"/> <element type="string" column="AUTHORS"/> </set> </class> Now I would like to find out which books are written by Matt. With pure SQL I can do a query like this: String author = "Matt"; String query = "SELECT * FROM Book " + "WHERE BOOK_ID IN " + "(SELECT BOOK_ID FROM Book_Authors " + "WHERE authors = :author )"; List<Book> result = session.createSQLQuery(query) .addEntity(Book.class) .setParameter("author", author) .list(); This works all good and well, and I get out all books that Matt has been a part of writing. The project I work in, however, uses the Criteria API instead of raw SQL, and I haven't found a way to express the same query in that form. I've taken a look on the Restrictions API and the closest I've found is Restions.in(propertyName, collection) but that works the other way around (one value in object, many values to match against). Any ideas?

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  • Cryptswap not mounted?

    - by woody
    I believe i have my swap set up but am not sure because on start up it says that it is something along the lines of "could not mount /dev/mapper/cryptswap1 M for manual S for skip". But it appears to be mounted. When i run free -m the output is: total used free shared buffers cached Mem: 3887 769 3117 0 54 348 -/+ buffers/cache: 366 3520 Swap: 4026 0 4026 and sudo bklid is: /dev/sda1: UUID="9fb3ccd6-3732-4989-bfa4-e943a09f1153" TYPE="ext4" /dev/mapper/cryptswap1: UUID="bd9fe154-8621-48b3-95d2-ae5c91f373fd" TYPE="swap" and cat /etc/crypttab is: cryptswap1 /dev/sda5 /dev/urandom swap,cipher=aes-cbc-essiv:sha256 my /etc/fstab is: # /etc/fstab: static file system information. # # Use 'blkid' to print the universally unique identifier for a # device; this may be used with UUID= as a more robust way to name devices # that works even if disks are added and removed. See fstab(5). # # proc /proc proc nodev,noexec,nosuid 0 0 # / was on /dev/sda1 during installation UUID=9fb3ccd6-3732-4989-bfa4-e943a09f1153 / ext4 errors=remount-ro 0 1 # swap was on /dev/sda5 during installation #UUID=bb0e378e-8742-435a-beda-ae7788a7c1b0 none swap sw 0 0 /dev/mapper/cryptswap1 none swap sw 0 0 The file /etc/polkit-1/localauthority/50-local.d/com.ubuntu.enable-hibernate.pkla already exists and its contents are: [Re-enable hibernate by default] Identity=unix-user:* Action=org.freedesktop.upower.hibernate ResultActive=yes Is my swap not setup correctly or is it not mounting?

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  • Hibernate not releasing data base connections

    - by cedar715
    Following is the configuration details: <property name="hibernateProperties"> <props> <prop key="hibernate.dialect"> org.hibernate.dialect.Oracle9iDialect </prop> <prop key="hibernate.show_sql">false</prop> <prop key="hibernate.cache.provider_class"> org.hibernate.cache.OSCacheProvider </prop> <prop key="hibernate.cache.use_second_level_cache"> true </prop> <!-- <prop key="hibernate.hbm2ddl.auto">update</prop>--> <!-- HIBERNATE CONNECTION POOLING!!--> <prop key="c3p0.acquire_increment">5</prop> <prop key="c3p0.idle_test_period">100</prop> <!-- seconds --> <prop key="c3p0.max_statements">5</prop> <prop key="c3p0.min_size">15</prop> <prop key="c3p0.max_size">100</prop> <prop key="c3p0.timeout">100</prop> <!-- seconds --> </props> </property> Our application is developed through Spring & Hibernate. Once we bring the application up and hit it, its opening 140 connections and not releasing it. Our DAO looks like this: import org.springframework.orm.hibernate3.support.HibernateDaoSupport; ... public class ActionDAO extends HibernateDaoSupport implements IActionDAO { public Action findById(ActionPK actionPK) { return (Action) getHibernateTemplate().get(Action.class, actionPK); } public void add(Action action) { getHibernateTemplate().save(action); } }

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  • How do I escape a LIKE clause using NHibernate Criteria?

    - by Jon Seigel
    The code we're using is straight-forward in this part of the search query: myCriteria.Add( Expression.InsensitiveLike("Code", itemCode, MatchMode.Anywhere)); and this works fine in a production environment. The issue is that one of our clients has item codes that contain % symbols which this query needs to match. The resulting SQL output from this code is similar to: SELECT ... FROM ItemCodes WHERE ... AND Code LIKE '%ItemWith%Symbol%' which clearly explains why they're getting some odd results in item searches. Is there a way to enable escaping using the programmatic Criteria methods? Addendum: We're using a slightly old version of NHibernate, 2.1.0.4000 (current as of writing is 2.1.2.4853), but I checked the release notes, and there was no mention of a fix for this. I didn't find any open issue in their bugtracker either. We're using SQL Server, so I can escape the special characters (%, _, [, and ^) in code really easily, but the point of us using NHibernate was to make our application database-engine-independent as much as possible. Neither Restrictions.InsensitiveLike() nor HqlQueryUtil.GetLikeExpr() escape their inputs, and removing the MatchMode parameter makes no difference as far as escaping goes.

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  • JPA 2 Criteria API: why is isNull being ignored when in conjunction with equal?

    - by Vítor Souza
    I have the following entity class (ID inherited from PersistentObjectSupport class): @Entity public class AmbulanceDeactivation extends PersistentObjectSupport implements Serializable { private static final long serialVersionUID = 1L; @Temporal(TemporalType.DATE) @NotNull private Date beginDate; @Temporal(TemporalType.DATE) private Date endDate; @Size(max = 250) private String reason; @ManyToOne @NotNull private Ambulance ambulance; /* Get/set methods, etc. */ } If I do the following query using the Criteria API: CriteriaBuilder cb = em.getCriteriaBuilder(); CriteriaQuery<AmbulanceDeactivation> cq = cb.createQuery(AmbulanceDeactivation.class); Root<AmbulanceDeactivation> root = cq.from(AmbulanceDeactivation.class); EntityType<AmbulanceDeactivation> model = root.getModel(); cq.where(cb.isNull(root.get(model.getSingularAttribute("endDate", Date.class)))); return em.createQuery(cq).getResultList(); I get the following SQL printed in the log: FINE: SELECT ID, REASON, ENDDATE, UUID, BEGINDATE, VERSION, AMBULANCE_ID FROM AMBULANCEDEACTIVATION WHERE (ENDDATE IS NULL) However, if I change the where() line in the previous code to this one: cq.where(cb.isNull(root.get(model.getSingularAttribute("endDate", Date.class))), cb.equal(root.get(model.getSingularAttribute("ambulance", Ambulance.class)), ambulance)); I get the following SQL: FINE: SELECT ID, REASON, ENDDATE, UUID, BEGINDATE, VERSION, AMBULANCE_ID FROM AMBULANCEDEACTIVATION WHERE (AMBULANCE_ID = ?) That is, the isNull criterion is totally ignored. It is as if it wasn't even there (if I provide only the equal criterion to the where() method I get the same SQL printed). Why is that? Is it a bug or am I missing something?

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  • JPA @TableGenerator shared between multiple entities

    - by Mauricio
    Hi Guys, I have a 'dog' Entitiy with an @Id and a @TableGenerator ... @TableGenerator(table = "seq", name = "dog_gen", pkColumnName = "seq_name", valueColumnName="seq_val") @Id @GeneratedValue(strategy = GenerationType.TABLE, generator = "dog_gen") private Long id; ... Is there a way to reuse the same table generator (dog_gen) in other entity? I want to keep the same id sequence in two independent Entities, say dog=1, dog=2, dog=3, cat=4, cat=5, dog=6 and so on... Both entities don't share a common superclass to implement some kind of inheritance with the id property. If I add the @GeneratedValue( generator="dog_gen") on my cat entity, omitting the @TableGenerator declaration throws an Exception saying it can't find the generator when starting the context. Caused by: org.hibernate.AnnotationException: Unknown Id.generator: dog_gen at org.hibernate.cfg.BinderHelper.makeIdGenerator(BinderHelper.java:413) at org.hibernate.cfg.AnnotationBinder.bindId(AnnotationBinder.java:1795) at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1229) at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:733) at org.hibernate.cfg.AnnotationConfiguration.processArtifactsOfType(AnnotationConfiguration.java:498) at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:277)

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  • Is this possible: JPA/Hibernate query with list property in result ?

    - by Kdeveloper
    In hibernate I want to run this JPQL / HQL query: select new org.test.userDTO( u.id, u.name, u.securityRoles) FROM User u WHERE u.name = :name userDTO class: public class UserDTO { private Integer id; private String name; private List<SecurityRole> securityRoles; public UserDTO(Integer id, String name, List<SecurityRole> securityRoles) { this.id = id; this.name = name; this.securityRoles = securityRoles; } ...getters and setters... } User Entity: @Entity public class User { @id private Integer id; private String name; @ManyToMany @JoinTable(name = "user_has_role", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = {@JoinColumn(name = "security_role_id") } ) private List<SecurityRole> securityRoles; ...getters and setters... } But when Hibernate 3.5 (JPA 2) starts I get this error: org.hibernate.hql.ast.QuerySyntaxException: Unable to locate appropriate constructor on class [org.test.UserDTO] [SELECT NEW org.test.UserDTO (u.id, u.name, u.securityRoles) FROM nl.test.User u WHERE u.name = :name ] Is a select that includes a list as a result not possible? Should I just create 2 seperate queries?

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  • when to use Hibernate vs. Simple ResultSets for small application

    - by luke
    I just started working on upgrading a small component in a distributed java application. The main application is a rather complicated applet/servlet combo running on JBoss and it extensively uses Hibernate for its DataAccess. The component i am working on however is very a very straightforward data importing service. Basically the workflow is Listen for a network event Parse the data packet, extract a set of identifiers Map the identifier set to a primary key in our database Parse the rest of the packet and insert items in a related table using the foreign key found in step 3 Repeat in the previous version of this component it used a hibernate based DAL, that is no longer usable for a variety of reasons (in particular it is EOL), so I am in charge of replacing the Data Access layer for this component. So on the one hand I think i should use Hibernate because that's what the rest of the application does, but on the other i think i should just use regular java.sql.* classes because my requirements are really straightforward and aren't expected to change any time soon. So my question is (and i understand it is subjective) at what point do you think that the added complexity of using an ORM tool (in terms of configuration, dependencies...) is worth it? UPDATE due to the way the DataAccesLayer for the main application was written (weird dependencies) i cannot easily use it, i would have to implement it myself.

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  • Database connection timeout

    - by Clinton Bosch
    Hi I have read so many articles on the Internet about this problem but none seem to have a clear solution. Please could someone give me a definite answer as to why I am getting database timeouts. The app is a GWT app that is being hosted on a Tomcat 5.5 server. I use spring and the session factory is created in the applicationContext.xml as follows <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${connection.dialect}</prop> <prop key="hibernate.connection.username">${connection.username}</prop> <prop key="hibernate.connection.password">${connection.password}</prop> <prop key="hibernate.connection.url">${connection.url}</prop> <prop key="hibernate.connection.driver_class">${connection.driver.class}</prop> <prop key="hibernate.show_sql">${show.sql}</prop> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.c3p0.min_size">5</prop> <prop key="hibernate.c3p0.max_size">20</prop> <prop key="hibernate.c3p0.timeout">1800</prop> <prop key="hibernate.c3p0.max_statements">50</prop> <prop key="hibernate.c3p0.idle_test_period">300</prop> </props> </property> <property name="annotatedClasses"> <list> <value>za.co.xxxx.traintrack.server.model.Answer</value> <value>za.co.xxxx.traintrack.server.model.Company</value> <value>za.co.xxxx.traintrack.server.model.CompanyRegion</value> <value>za.co.xxxx.traintrack.server.model.Merchant</value> <value>za.co.xxxx.traintrack.server.model.Module</value> <value>za.co.xxxx.traintrack.server.model.Question</value> <value>za.co.xxxx.traintrack.server.model.User</value> <value>za.co.xxxx.traintrack.server.model.CompletedModule</value> </list> </property> </bean> <bean id="dao" class="za.co.xxxx.traintrack.server.DAO"> <property name="sessionFactory" ref="sessionFactory"/> <property name="adminUsername" value="${admin.user.name}"/> <property name="adminPassword" value="${admin.user.password}"/> <property name="godUsername" value="${god.user.name}"/> <property name="godPassword" value="${god.user.password}"/> </bean> All works fine untile the next day: INFO | jvm 1 | 2010/06/15 14:42:27 | 2010-06-15 18:42:27,804 WARN [JDBCExceptionReporter] : SQL Error: 0, SQLState: 08S01 INFO | jvm 1 | 2010/06/15 14:42:27 | 2010-06-15 18:42:27,821 ERROR [JDBCExceptionReporter] : The last packet successfully received from the server was 38729 seconds ago.The last packet sent successfully to the server was 38729 seconds ago, which is longer than the server configured value of 'wait_timeout'. You should consider either expiring and/or testing connection validity before use in your application, increasing the server configured values for client timeouts, or using the Connector/J connection property 'autoReconnect=true' to avoid this problem. INFO | jvm 1 | 2010/06/15 14:42:27 | Jun 15, 2010 6:42:27 PM org.apache.catalina.core.ApplicationContext log INFO | jvm 1 | 2010/06/15 14:42:27 | SEVERE: Exception while dispatching incoming RPC call I have read so many different things (none of which worked), please help

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