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  • How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

    - by EugeneP
    How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

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  • out-of-the-box way to get an idmap from hibernate for a given entity?

    - by Geert-Jan
    Over and over again I notive myself getting a list from hibernate, and the first thing next is put it in an idmap like: List<House> entities = s.createCriteria(House.class).list(); Map<String,House> entitymap = new HashMap<String,House>(); for(TA_entity e:entities){ entitymap.put(e.getId(), e); } Is there a way to get this directly out of hibenerate? afterall Hibernate is familiar with the id.

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  • A typical lifecycle of a Hibernate object in a web app - ?

    - by EugeneP
    Describe please a typical lifecycle of a Hibernate object (that maps to a db table) in a web app. Suppose, you create a new instance of an object and persist in the db. But during the app lifetime you'll be working on a detached object and finally you need to update it in the database, for example on exit. How does it look like with hibernate and spring? p.s. Can transactions and sessions live between servlet transitions? So that we opened 1 session and use it in all servlets without a need to reopen it?

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  • Windows 7 unidentified network (or limited access) after hibernate.

    - by null
    My windows 7 network will show limited access or unidentified network after coming up from hibernation. In the office I normally use LAN connection, I turn-off my wireless card (DELL Latitude has on/off switch for the wireless card). When I back at home I will turn on the wireless card, but it will take about 15 seconds to detect my home WIFI and then show limited access. I will have to restart the notebook and it will be able to connect to my WIFI and internet. The problem will be solved if I restart the notebook, but that defeats the purpose of hibernation doesn't it? I have tried uninstalling the wireless card driver but still does not solve it. I also tried updating my network card driver but windows says I am using the latest driver. On support.dell.com also showing I am using the latest driver.

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  • Delete all previous records and insert new ones

    - by carlos
    When updating an employee with id = 1 for example, what is the best way to delete all previous records in the table certificate for this employee_id and insert the new ones?. create table EMPLOYEE ( id INT NOT NULL auto_increment, first_name VARCHAR(20) default NULL, last_name VARCHAR(20) default NULL, salary INT default NULL, PRIMARY KEY (id) ); create table CERTIFICATE ( id INT NOT NULL auto_increment, certificate_name VARCHAR(30) default NULL, employee_id INT default NULL, PRIMARY KEY (id) ); Hibernate mapping <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD//EN" "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd"> <hibernate-mapping> <class name="Employee" table="EMPLOYEE"> <id name="id" type="int" column="id"> <generator class="sequence"> <param name="sequence">employee_seq</param> </generator> </id> <set name="certificates" lazy="false" cascade="all"> <key column="employee_id" not-null="true"/> <one-to-many class="Certificate"/> </set> <property name="firstName" column="first_name"/> <property name="lastName" column="last_name"/> <property name="salary" column="salary"/> </class> <class name="Certificate" table="CERTIFICATE"> <id name="id" type="int" column="id"> <param name="sequence">certificate_seq</param> </id> <property name="employee_id" column="employee_id" insert="false" update="false"/> <property name="name" column="certificate_name"/> </class> </hibernate-mapping>

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  • validator="" attribute of <h:inputtext> in jsf causing exception

    - by Amit
    We are trying to migrate from WS5 to WAS7 and the jsf code is causing the following error Original Exception: Error Message: JSPG0227E: Exception caught while translating /jsp/listView/listViewUPD_MAP_UM01.jsp: JSPG0301E: Invalid attribute, validator, for deferred method returning void. Error Code: 500 Target Servlet: /jsp/listView/listViewUPD_MAP_UM01.jsp Error Stack: com.ibm.ws.jsp.translator.JspTranslationException: JSPG0227E: Exception caught while translating /jsp/listView/listViewUPD_MAP_UM01.jsp: JSPG0301E: Invalid attribute, validator, for deferred method returning void. at com.ibm.ws.jsp.translator.visitor.generator.BaseTagGenerator.evaluateAttribute(BaseTagGenerator.java:527)

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  • Simple JQuery Validator addMethod not working

    - by tehaaron
    Updated question on the bottom I am trying to validate a super simple form. Eventually the username will be compared to a RegExp statement and the same will go for the password. However right now I am just trying to learn the Validator addMethod format. I currently have this script: JQuery.validator.addMethod( "legalName", function(value, element) { if (element.value == "bob") { return false; } else return true; }, "Use a valid username." ); $(document).ready(function() { $("#form1").validate({ rules: { username: { legalName: true } }, }); }); Which if I am not mistaken should return false and respond with "Use a valid username." if I were to put "bob" into the form. However, it is simply submitting it. I am linking to JQuery BEFORE Validator in the header like instructed. My uber simple form looks like this: <form id="form1" method="post" action=""> <div class="form-row"><span class="label">Username *</span><input type="text" name="username" /></div> <div class="form-row"><input class="submit" type="submit" value="Submit"></div> </form> Finally how would I go about restructing the addMethod function to return true if and false at the else stage while keeping the message alert for a false return? (ignore this last part if you don't understand what I was trying to say :) ) Thanks in advance. Thank to everyone who pointed out my JQuery - jQuery typo. New Ideally, I am trying to turn this into a simple login form (username/password). It is for demonstration only so it wont have a database attached or anything, just some simple js validations. I am looking to make the username validate for <48 characters, only english letters and numbers, no special characters. I thought a whitelist would be easiest so I had something like this: ^[a-zA-Z0-9]*${1,48} but I am not sure if that is proper JS RegExp (it varies from Ruby RegExp if I am not mistaken?...Usually I use rubular.com). Password will be similar but require some upper/lowercase and numbers. I believe I need to make another $.validator.addMethod for legalPassword that will look very similar.

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  • Localized Date Validator

    - by Blithe
    Is there a way to use user's culture to localize the Range Validator for date? I am looking for a good way to validate date and avoiding to provide a fix format (e.g.: do a dd/mm/yyyy using Regular Expression Validator)

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  • Using the jQuery Validator

    - by ScG
    I am using $.validator.addMethod How can I print the validation message in a control. I have a div id="err" where I want to print the message Here is what my method looks like $.validator.addMethod('something', function(value, element) { return false; }, 'I want to display this message in a Div with ID=error')

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  • jQuery Validator - Dynamic Text

    - by James
    Adding a validator to my form: jQuery.validator.addMethod('whatever', function(val, el) { // whatever goes here }, 'A maximum of ' + $('#my_id_here').val() + ' categories can be selected.'); This doesn't fly. I always get undefined. Is this a good, simple way to do this? Thanks

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  • JQuery URL Validator

    - by Vincent
    All, I am trying to use JQuery's URL Validator plugin. http://docs.jquery.com/Plugins/Validation/Methods/url I have a text box that has a URL. I want to write a function which takes the textbox value, uses the jquery's validator plugin to validate urls and returns true or false. Something like Ex: function validateURL(textval) { // var valid = get jquery's validate plugin return value if(valid) { return true; } return false; } I wanted this to be a reusable function.. Thanks

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  • How to convert an ORM to its subclass using Hibernate ?

    - by Gaaston
    Hi everybody, For example, I have two classes : Person and Employee (Employee is a subclass of Person). Person : has a lastname and a firstname. Employee : has also a salary. On the client-side, I have a single HTML form where i can fill the person informations (like lastname and firstname). I also have a "switch" between "Person" and "Employee", and if the switch is on Employee I can fill the salary field. On the server-side, Servlets receive informations from the client and use the Hibernate framework to create/update data to/from the database. The mapping i'm using is a single table for persons and employee, with a discriminator. I don't know how to convert a Person in an Employee. I firstly tried to : load the Person p from the database create an empty Employee e object copy values from p into e set the salary value save e into the database But i couldn't, as I also copy the ID, and so Hibernate told me they where two instanciated ORM with the same id. And I can't cast a Person into an Employee directly, as Person is Employee's superclass. There seems to be a dirty way : delete the person, and create an employee with the same informations, but I don't really like it.. So I'd appreciate any help on that :) Some precisions : The person class : public class Person { protected int id; protected String firstName; protected String lastName; // usual getters and setters } The employee class : public class Employee extends Person { // string for now protected String salary; // usual getters and setters } And in the servlet : // type is the "switch" if(request.getParameter("type").equals("Employee")) { Employee employee = daoPerson.getEmployee(Integer.valueOf(request.getParameter("ID"))); modifyPerson(employee, request); employee.setSalary(request.getParameter("salary")); daoPerson.save(employee ); } else { Person person = daoPerson.getPerson(Integer.valueOf(request.getParameter("ID"))); modifyPerson(employee, request); daoPerson.save(person); } And finally, the loading (in the dao) : public Contact getPerson(int ID){ Session session = HibernateSessionFactory.getSession(); Person p = (Person) session.load(Person.class, new Integer(ID)); return p; } public Contact getEmployee(int ID){ Session session = HibernateSessionFactory.getSession(); Employee = (Employee) session.load(Employee.class, new Integer(ID)); return p; } With this, i'm getting a ClassCastException when trying to load a Person using getEmployee. XML Hibernate mapping : <class name="domain.Person" table="PERSON" discriminator-value="P"> <id name="id" type="int"> <column name="ID" /> <generator class="native" /> </id> <discriminator column="type" type="character"/> <property name="firstName" type="java.lang.String"> <column name="FIRSTNAME" /> </property> <property name="lastName" type="java.lang.String"> <column name="LASTNAME" /> </property> <subclass name="domain.Employee" discriminator-value="E"> <property name="salary" column="SALARY" type="java.lang.String" /> </subclass> </class> Is it clear enough ? :-/

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  • How to handle large dataset with JPA (or at least with Hibernate)?

    - by Roman
    I need to make my web-app work with really huge datasets. At the moment I get either OutOfMemoryException or output which is being generated 1-2 minutes. Let's put it simple and suppose that we have 2 tables in DB: Worker and WorkLog with about 1000 rows in the first one and 10 000 000 rows in the second one. Latter table has several fields including 'workerId' and 'hoursWorked' fields among others. What we need is: count total hours worked by each user; list of work periods for each user. The most straightforward approach (IMO) for each task in plain SQL is: 1) select Worker.name, sum(hoursWorked) from Worker, WorkLog where Worker.id = WorkLog.workerId group by Worker.name; //results of this query should be transformed to Multimap<Worker, Long> 2) select Worker.name, WorkLog.start, WorkLog.hoursWorked from Worker, WorkLog where Worker.id = WorkLog.workerId; //results of this query should be transformed to Multimap<Worker, Period> //if it was JDBC then it would be vitally //to set resultSet.setFetchSize (someSmallNumber), ~100 So, I have two questions: how to implement each of my approaches with JPA (or at least with Hibernate); how would you handle this problem (with JPA or Hibernate of course)?

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  • How can I go through a Set in JSP? (Hibernate Associations)

    - by Parris
    Hi All, So I am pretty new to JSP. I have tried this a few ways. Ways that would make sense in PHP or automagicy frameworks... I am probably thinking too much in fact... I have a hibernate one to many association. That is class x has many of class y. In class x's view.jsp. I would like to grab all of class y, where the foreign key of y matches the primary key of x and display them. It seems that hibernate properly puts this stuff into a set. Now, the question is how can I iterate through this set and then output it's contents... I am kind of stumped here. I tried to write a scriptlet, <% java.util.Iterator iter = aBean.getYs().iter(); // aBeans is the bean name // getYs would return the set and iter would return an iterator for the set while(iter.hasNext) { model.X a = new iter.next() %> <h1><%=a.getTitle()%></h1> <% } %> It would seem that that sort of thing should work? Hmmmmmm

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  • JSP/Struts2/Hibernate: loop through a self-referencing table.

    - by TBW
    Hello everyone, Let's say we have a self-referencing table called PERSON, with the following columns: ID, PARENT, where PARENT is a foreign key to the ID column of another element in the PERSON table. Of course, many persons can have the same parent. I use Hibernate 3 in lazy fetching mode to deal with the database. Hibernate fetches a person element from the database, which is then put in the ValueStack by the Struts2 action, to be used on the result JSP page. Now the question is : In JSP, how can I do to display all the child (and the child's child, and so on, like a family tree) of this person element? Of course, for the n+1 children I can use the < s:iterator tag over the person.person. I can also nest another < s:iterator tag over person.person.person to get the n+2 children. But what if I want to do this in an automated manner, up to the last n+p child, displaying in the process all the children of all the n+1..n+p elements? I hope I have been clear enough. Thank you all for your time. -- TBW.

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  • Hibernate saveOrUpdate fails when I execute it on empty table.

    - by Vladimir
    I'm try to insert or update db record with following code: Category category = new Category(); category.setName('catName'); category.setId(1L); categoryDao.saveOrUpdate(category); When there is a category with id=1 already in database everything works. But if there is no record with id=1 I got following exception: org.hibernate.StaleStateException: Batch update returned unexpected row count from update [0]; actual row count: 0; expected: 1: Here is my Category class setters, getters and constructors ommited for clarity: @Entity public class Category { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; private String name; @ManyToOne private Category parent; @OneToMany(fetch = FetchType.LAZY, mappedBy = "parent") private List<Category> categories = new ArrayList<Category>(); } In the console I see this hibernate query: update Category set name=?, parent_id=? where id=? So looks like hibernates tryis to update record instead of inserting new. What am I doing wrong here?

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  • Ordering the results of a Hibernate Criteria query by using information of the child entities of the

    - by pkainulainen
    I have got two entities Person and Book. Only one instance of a specific book is stored to the system (When a book is added, application checks if that book is already found before adding a new row to the database). Relevant source code of the entities is can be found below: @Entity @Table(name="persons") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Person extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @ManyToMany(targetEntity=Book.class) @JoinTable(name="persons_books", joinColumns = @JoinColumn( name="person_id"), inverseJoinColumns = @JoinColumn( name="book_id")) private List<Book> ownedBooks = new ArrayList<Book>(); } @Entity @Table(name="books") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Book extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @Column(name="name") private String name = null; } My problem is that I want to find persons, which are owning some of the books owned by a specific persons. The returned list of persons should be ordered by using following logic: The person owning most of the same books should be at the first of the list, second person of the the list does not own as many books as the first person, but more than the third person. The code of the method performing this query is added below: @Override public List<Person> searchPersonsWithSimilarBooks(Long[] bookIds) { Criteria similarPersonCriteria = this.getSession().createCriteria(Person.class); similarPersonCriteria.add(Restrictions.in("ownedBooks.id", bookIds)); //How to set the ordering? similarPersonCriteria.addOrder(null); return similarPersonCriteria.list(); } My question is that can this be done by using Hibernate? And if so, how it can be done? I know I could implement a Comparator, but I would prefer using Hibernate to solve this problem.

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  • How to lock a transaction for reading a row and then inserting in Hibernate?

    - by at
    I have a table with a name and a name_count. So when I insert a new record, I first check what the maximum name_count is for that name. I then insert the record with that maximum + 1. Works great... except with mysql 5.1 and hibernate 3.5, by default the reads don't respect transaction boundaries. 2 of these inserts for the same name could happen at the same time and end up with the same name_count, which completely screws my application! Unfortunately, there are some specific situations where the above is actually fairly common. So what do I do? I assume I can do a pessimistic lock where any row I read is locked for further reading until I commit or roll-back my transaction. Or I can do an optimistic lock with a version column that automatically keeps trying until there are no conflicts? What's the best approach for my situation and how do I specify it in Hibernate 3.5 and mysql 5.1? The above table is massive and accessed frequently.

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  • Persistence provider caller does not implement the EJB3 spec

    - by Joshua
    WARN [Ejb3Configuration] Persistence provider caller does not implement the EJB3 spec correctly. PersistenceUnitInfo.getNewTempClassLoad er() is null. How do you get rid of the above warning? 0:42:08,032 INFO [PersistenceUnitDeployment] Starting persistence unit pe rsistence.unit:unitName=k12-ear.ear/k12-ejb-1.0.0.jar#k12 10:42:08,371 INFO [Version] Hibernate Annotations 3.4.0.GA 10:42:08,442 INFO [Environment] Hibernate 3.3.1.GA 10:42:08,450 INFO [Environment] hibernate.properties not found 10:42:08,486 INFO [Environment] Bytecode provider name : javassist 10:42:08,492 INFO [Environment] using JDK 1.4 java.sql.Timestamp handling 10:42:08,754 INFO [Version] Hibernate Commons Annotations 3.1.0.GA 10:42:08,989 INFO [Version] Hibernate EntityManager 3.4.0.GA 10:42:09,211 INFO [Ejb3Configuration] Processing PersistenceUnitInfo [ name: k12 ...] 10:42:09,458 WARN [Ejb3Configuration] Persistence provider caller does not implement the EJB3 spec correctly. PersistenceUnitInfo.getNewTempClassLoad er() is null. 10:42:09,620 WARN [Ejb3Configuration] Defining hibernate.transaction.flush _before_completion=true ignored in HEM 10:42:09,745 DEBUG [AnnotationConfiguration] Execute first pass mapping pro cessing

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  • Validating DataAnnotations with Validator class

    - by Pablote
    I'm trying to validate a class decorated with dataannotation with the Validator class. It works fine when the attributes are applied to the same class. But when I try to use a metadata class it doesn't work. Is there anything I should do with the Validator so it uses the metadata class? Here's some code.. this works: public class Persona { [Required(AllowEmptyStrings = false, ErrorMessage = "El nombre es obligatorio")] public string Nombre { get; set; } [Range(0, int.MaxValue, ErrorMessage="La edad no puede ser negativa")] public int Edad { get; set; } } this doesnt work: [MetadataType(typeof(Persona_Validation))] public class Persona { public string Nombre { get; set; } public int Edad { get; set; } } public class Persona_Validation { [Required(AllowEmptyStrings = false, ErrorMessage = "El nombre es obligatorio")] public string Nombre { get; set; } [Range(0, int.MaxValue, ErrorMessage = "La edad no puede ser negativa")] public int Edad { get; set; } } this is how I validate the instances: ValidationContext context = new ValidationContext(p, null, null); List<ValidationResult> results = new List<ValidationResult>(); bool valid = Validator.TryValidateObject(p, context, results, true); thanks.

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  • How to run validator from javascript?

    - by David Shochet
    Here is a part of my code: <asp:ListBox ID="lbRD" runat="server" DataSourceID="RDSqlDataSource" onchange="JSFillDetail();" DataTextField="????????" DataValueField="ID" Width="188px" Height="200px"/> <asp:TextBox ID="txtDescription" runat="server" /> <asp:RequiredFieldValidator ID="txtDescriptionRequiredFieldValidator" runat="server" ErrorMessage="???????? ???????? ???????????? ??? ??????????" ControlToValidate="txtDescription" /> I have a listbox, a textbox and a required field validator on my page. When the user selects something from the listbox, the selected item appears in the textbox using a javascript function. When the page is submitted, the validator reports an error in case the textbox is empty. If after that the user selects something from the listbox, the error message is still displayed, even though the textbox is not empty anymore. How can I make the validator validate the textbox, or even better, to clear the error message from the javascript function that fills the textbox? Thanks, David

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  • Connection hangs after time of inactivity

    - by Sinuhe
    In my application, Spring manages connection pool for database access. Hibernate uses these connections for its queries. At first glance, I have no problems with the pool: it works correctly with concurrent clients and a pool with only one connection. I can execute a lot of queries, so I think that I (or Spring) don't leave open connections. My problem appears after some time of inactivity (sometimes 30 minutes, sometimes more than 2 hours). Then, when Hibernate does some search, it lasts too much. Setting log4j level to TRACE, I get this logs: ... 18:27:01 DEBUG nsactionSynchronizationManager - Retrieved value [org.springframework.orm.hibernate3.SessionHolder@99abd7] for key [org.hibernate.impl.SessionFactoryImpl@7d2897] bound to thread [http-8080-Processor24] 18:27:01 DEBUG HibernateTransactionManager - Found thread-bound Session [org.hibernate.impl.SessionImpl@8878cd] for Hibernate transaction 18:27:01 DEBUG HibernateTransactionManager - Using transaction object [org.springframework.orm.hibernate3.HibernateTransactionManager$HibernateTransactionObject@1b2ffee] 18:27:01 DEBUG HibernateTransactionManager - Creating new transaction with name [com.acjoventut.service.GenericManager.findByExample]: PROPAGATION_REQUIRED,ISOLATION_DEFAULT 18:27:01 DEBUG HibernateTransactionManager - Preparing JDBC Connection of Hibernate Session [org.hibernate.impl.SessionImpl@8878cd] 18:27:01 TRACE SessionImpl - setting flush mode to: AUTO 18:27:01 DEBUG JDBCTransaction - begin 18:27:01 DEBUG ConnectionManager - opening JDBC connection Here it gets frozen for about 2 - 10 minutes. But then continues: 18:30:11 DEBUG JDBCTransaction - current autocommit status: true 18:30:11 DEBUG JDBCTransaction - disabling autocommit 18:30:11 TRACE JDBCContext - after transaction begin 18:30:11 DEBUG HibernateTransactionManager - Exposing Hibernate transaction as JDBC transaction [jdbc:oracle:thin:@212.31.39.50:30998:orcl, UserName=DEVELOP, Oracle JDBC driver] 18:30:11 DEBUG nsactionSynchronizationManager - Bound value [org.springframework.jdbc.datasource.ConnectionHolder@843a9d] for key [org.apache.commons.dbcp.BasicDataSource@7745fd] to thread [http-8080-Processor24] 18:30:11 DEBUG nsactionSynchronizationManager - Initializing transaction synchronization ... After that, it works with no problems, until another period of inactivity. IMHO, it seems like connection pool returns an invalid/closed connection, and when Hibernate realizes that, ask another connection to the pool. I don't know how can I solve this problem or things I can do for delimiting it. Any help achieving this will be appreciate. Thanks. EDIT: Well, it finally was due a firewall rule. Database detects the connection is lost, but pool (dbcp or c3p0) not. So, it tries to query the database with no success. What is still strange for me is that timeout period is very variable. Maybe the rule is specially strange or firewall doesn't work correctly. Anyway, I have no access to that machine and I can only wait for an explanation. :(

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