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  • How do I convert tuple of tuples to list in one line (pythonic)?

    - by ThinkCode
    query = 'select mydata from mytable' cursor.execute(query) myoutput = cursor.fetchall() print myoutput (('aa',), ('bb',), ('cc',)) Why is it (cursor.fetchall) returning a tuple of tuples instead of a tuple since my query is asking for only one column of data? What is the best way of converting it to ['aa', 'bb', 'cc'] ? I can do something like this : mylist = [] myoutput = list(myoutput) for each in myoutput: mylist.append(each[0]) I am sure this isn't the best way of doing it. Please enlighten me!

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  • f# one list to another?

    - by mamu
    I have a list of tuples with three values in tuples I want to create new List of strings out of previous list with one value out of tuples. List [(string * string * int) ] List[ for i in columns -> i.getfirstvalueintuple] How can i do that? very basic question but i can't figure it out. Also is there any other way of building another kind of list or seq out of existing list?

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  • Can Anyone point me to a Android Market catalog or application list.

    - by Doug
    I'm up and running in Eclipse, have worked through several tutorials and would like to start developing my first marketable app. Is there anyplace I can find a comprehensive list or catalog of what's available on the Android marketplace? I'd hate to waste a lot of development time building an app that has twelve free versions already available.

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  • Java - Adding a Node in a doubly-linked list.

    - by jacobnlsn
    Hi, I am working on some code were I need to add a Node into a doubly linked-list, this is the code I have so far: Node tempNext = cursor.getNext(); temp = new Node(item, null, cursor, tempNext); tempNext.setPrev(temp); cursor is the Node that is right before the new added Node should go.

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  • How do I randomly select from a list in Python?

    - by Liam Block
    Basically, I've got a homework task of programming a text based battle simulator in Python. Obviously I've gone with pokémon... I would like the enemy to be randomly selected, however I don't know how to randomly select from a list... foo = ['a', 'b', 'c', 'd', 'e'] from random import choice print choice(foo) This is what I've been told to try but I've got no modules or anything imported... How can I make this work, appreciated.

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  • Elegent way to collapse or expand sub-sequences of a list in Python?

    - by forgot
    I want to collapse or expand sub-sequences of a list e.g. ['A', 'B', 'D', 'E', 'H'] -> ['AB', 'DE', 'H'] and vice versa currently I wrote some ugly code like: while True: for i, x in enumerate(s): if x == 'A' and s[i+1] == 'B': s[i:i+2] = 'AB' break else: break For people who asking 'why do that thing': Actually I'm working on a optimizing compiler and this is the peephole part. Writing pattern matching is a little annoying.

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  • How to determine whether a linked list contains a loop?

    - by ET
    During a preparation for a job interview, I encountered the following question: How can you determine whether a linked list (of any type) contains a loop, using additional space complexity of O(1)? You cannot assume that the loop starts at the first node (and of course, the loop doesn't have to contain all nodes). I couldn't find the answer, though I have the feeling it's quite simple...

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  • How can I acquire an aggregated list of known proxy IP addresses?

    - by Howard3
    I'd like to use this to help maintain a good defence against people trying to skirt the rules of my system. I've found TOR endpoints, nothing that's readily available to be shot into a script (needs to be parsed) but they work. However I need a list which goes beyond TOR yet I cannot find anything conclusive just yet. Any suggestions would be greatly appreciated.

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  • How should I grab pairs from a list in python?

    - by tomaski
    Say I have a list that looks like this: ['item1', 'item2', 'item3', 'item4', 'item5', 'item6', 'item7', 'item8', 'item9', 'item10'] Using Python, how would I grab pairs from it, where each item is included in a pair with both the item before and after it? ['item1', 'item2'] ['item2', 'item3'] ['item3', 'item4'] ['item4', 'item5'] ['item5', 'item6'] ['item6', 'item7'] ['item7', 'item8'] ['item8', 'item9'] ['item9', 'item10'] Seems like something i could hack together, but I'm wondering if someone has an elegant solution they've used before?

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  • Office 365 - Outlook shows Global Address List clicking "Rooms" during a meeting request

    - by TheCleaner
    This appears to be a "known" issue, but apparently no fix for it. However, I've been impressed before at the tenacity of the experts here to figure out an answer/fix. ISSUE When booking a New Meeting in Outlook (2013 or 2010) and choosing the Rooms button: The default list that opens is the Offline Global Address List: Which means a user has to change from the Offline Global Address List to the All Rooms list as shown here in order to easily pick from the list of actual rooms/resources: This isn't the default however for On-Premise Exchange servers. They default "correctly" to the All Rooms list when you click the Rooms button in the meeting request. While the option of using the Room Finder is there and does work, users have to know to click the Room Finder choice and it doesn't fix the actual root issue here. MY RESEARCH A few links I've found: http://community.office365.com/en-us/forums/158/t/41013.aspx http://community.office365.com/en-us/forums/148/p/24139/113954.aspx http://community.office365.com/en-us/forums/172/t/58824.aspx It was suggested that it might be that the "msExchResourceAddressLists attribute has incorrect value set". I checked my config by running: Get-OrganizationConfig | Select-Object ResourceAddressLists and the output was what it should be: ResourceAddressLists -------------------- {\All Rooms} QUESTION Does anyone have a fix that will make the All Rooms list be the default list when clicking the Rooms button in Outlook when using Office 365 / Exchange Online?

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