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  • XMLHttpRequest() and outputting csv file

    - by sjw
    Initially, I developed a javascript function to use window.open to post contents of a form to a new window which simply opened the new window and initiated a csv file download. Now on reflection, I find the opening of the window superfluous and am trying to just execute a XMLHttpRequest() to download the csv. I am not getting what I want and I'm not 100% sure that I can so I thought I'd ask here for some assistance. When a form is submitted, I want to take all the form values and post them to another page which builds an SQL string and builds a csv based on the contents. (This I can do and works fine with XMLHttpRequest() as seen below) var xhReq = new XMLHttpRequest(); var parameters = ""; for ( i=0; i<formObj.elements.length; i++ ) { parameters += formObj.elements[i].name + "=" + encodeURI( formObj.elements[i].value ) + "&"; } xhReq.open("POST", outputLocation, false); xhReq.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xhReq.setRequestHeader("Content-length", parameters.length); xhReq.setRequestHeader("Connection", "close"); xhReq.send(parameters); document.write(xhReq.responseText); The code above calls the page ok, builds the csv ok, but it outputs the contents into the current browser window instead of initiating a csv file download. Can I achieve what I need using XMLHttpRequest() or am I going it about it the wrong way? Thanks

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  • How to use WebSockets refresh multi-window for play framework 1.2.7

    - by user2468652
    My code can work.But only refresh a page of one window. If I open window1 and window2 , both open websocket connect. I keyin word "test123" in window1, click sendbutton. Only refresh window1. How to refresh window1 and window2 ? Client <script> window.onload = function() { document.getElementById('sendbutton').addEventListener('click', sendMessage,false); document.getElementById('connectbutton').addEventListener('click', connect, false); } function writeStatus(message) { var html = document.createElement("div"); html.setAttribute('class', 'message'); html.innerHTML = message; document.getElementById("status").appendChild(html); } function connect() { ws = new WebSocket("ws://localhost:9000/ws?name=test"); ws.onopen = function(evt) { writeStatus("connected"); } ws.onmessage = function(evt) { writeStatus("response: " + evt.data); } } function sendMessage() { ws.send(document.getElementById('messagefield').value); } </script> </head> <body> <button id="connectbutton">Connect</button> <input type="text" id="messagefield"/> <button id="sendbutton">Send</button> <div id="status"></div> </body> Play Framework WebSocketController public class WebSocket extends WebSocketController { public static void test(String name) { while(inbound.isOpen()) { WebSocketEvent evt = await(inbound.nextEvent()); if(evt instanceof WebSocketFrame) { WebSocketFrame frame = (WebSocketFrame)evt; System.out.println("received: " + frame.getTextData()); if(!frame.isBinary()) { if(frame.getTextData().equals("quit")) { outbound.send("Bye!"); disconnect(); } else { outbound.send("Echo: %s", frame.getTextData()); } } } } } }

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  • Pymedia video encoding failed

    - by user1474837
    I am using Python 2.5 with Windows XP. I am trying to make a list of pygame images into a video file using this function. I found the function on the internet and edited it. It worked at first, than it stopped working. This is what it printed out: Making video... Formating 114 Frames... starting loop making encoder Frame 1 process 1 Frame 1 process 2 Frame 1 process 2.5 This is the error: Traceback (most recent call last): File "ScreenCapture.py", line 202, in <module> makeVideoUpdated(record_files, video_file) File "ScreenCapture.py", line 151, in makeVideoUpdated d = enc.encode(da) pymedia.video.vcodec.VCodecError: Failed to encode frame( error code is 0 ) This is my code: def makeVideoUpdated(files, outFile, outCodec='mpeg1video', info1=0.1): fw = open(outFile, 'wb') if (fw == None) : print "Cannot open file " + outFile return if outCodec == 'mpeg1video' : bitrate= 2700000 else: bitrate= 9800000 start = time.time() enc = None frame = 1 print "Formating "+str(len(files))+" Frames..." print "starting loop" for img in files: if enc == None: print "making encoder" params= {'type': 0, 'gop_size': 12, 'frame_rate_base': 125, 'max_b_frames': 90, 'height': img.get_height(), 'width': img.get_width(), 'frame_rate': 90, 'deinterlace': 0, 'bitrate': bitrate, 'id': vcodec.getCodecID(outCodec) } enc = vcodec.Encoder(params) # Create VFrame print "Frame "+str(frame)+" process 1" bmpFrame= vcodec.VFrame(vcodec.formats.PIX_FMT_RGB24, img.get_size(), # Covert image to 24bit RGB (pygame.image.tostring(img, "RGB"), None, None) ) print "Frame "+str(frame)+" process 2" # Convert to YUV, then codec da = bmpFrame.convert(vcodec.formats.PIX_FMT_YUV420P) print "Frame "+str(frame)+" process 2.5" d = enc.encode(da) #THIS IS WHERE IT STOPS print "Frame "+str(frame)+" process 3" fw.write(d.data) print "Frame "+str(frame)+" process 4" frame += 1 print "savng file" fw.close() Could somebody tell me why I have this error and possibly how to fix it? The files argument is a list of pygame images, outFile is a path, outCodec is default, and info1 is not used anymore. UPDATE 1 This is the code I used to make that list of pygame images. from PIL import ImageGrab import time, pygame pygame.init() f = [] #This is the list that contains the images fps = 1 for n in range(1, 100): info = ImageGrab.grab() size = info.size mode = info.mode data = info.tostring() info = pygame.image.fromstring(data, size, mode) f.append(info) time.sleep(fps)

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  • How to make quicksilver remember custom trigger

    - by corroded
    I am trying to make a custom trigger for my shell/apple script file to run so I can just launch my dev environment at the push of a button. So basically: I have a shell script(and some apple script included) in ~ named start_server.sh which does 3 things: start up solr server start up memcached start up script/server I have a saved quicksilver command(.qs) that opens up start_server.sh(so start_server.sh, then the action is "Run in Terminal") I created a custom trigger that calls this saved qs command. I did that then tested it and it works. I then tried to double check it so I quit quicksilver and when I checked the triggers it just said: "Open (null)" as the action. I set the trigger again and when i restarted QS the same thing happened again. I don't know why but my old custom trigger to open terminal has worked since forever so why doesn't this one work? Here's a screenie of the triggers after I restart QS: http://grab.by/4XWW If you have any other suggestion on how to make a "push button" start for my server then please do so :) Thanks! As an added note, I have already tried the steps on this thread but to no avail: http://groups.google.com/group/blacktree-quicksilver/browse_thread/thread/7b65ecf6625f8989

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  • Labels aren't shown properly in combo box

    - by Vishal
    The below code show the labels from previously selected list any ideas? Steps to reproduce: Click on List AB Open the list but don't select / click any item Now click on List CD Open the list again and you see A, B as labels instead of C,D but if you click on any item then everything comes properly <mx:Script> <![CDATA[ import mx.collections.ArrayCollection; public var ab:ArrayCollection=new ArrayCollection([{label: A, data: 1}, {label: B, data: 2}]); public var cd:ArrayCollection=new ArrayCollection([{label: C, data: 3}, {label: D, data: 4}]); private function abClick(event:Event):void { cb.dataProvider=ab; } private function cdClick(event:Event):void { cb.dataProvider=cd; } ]]> </mx:Script> <mx:Panel title="ComboBox Control Example" height="75%" width="75%" layout="horizontal" paddingTop="10" paddingBottom="10" paddingLeft="10" paddingRight="10"> <mx:ComboBox id="cb" width="150"/> <mx:Button label="List AB" click="abClick(event);"/> <mx:Button label="List CD" click="cdClick(event);"/> </mx:Panel>

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  • Wrapping an additional element around an existing XDocument

    - by user1382827
    Let's say I have a converted HTML document, and I wanted to wrap an extra tag around the parent, so that I could read the head and body. How would I do that with C#? The file is used as an XDocument. change <html> <head> <!-- data --> </head> <body> <!-- data --> </body> </html> to <open> <html> <head> <!-- data --> </head> <body> <!-- data --> </body> </html> </open>

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  • Amazon Product API ResponseGroups and Default results

    - by aboxy
    A. In our application, most of the data we work with is stored as free text .i.e. there is no categorization done as of now. We are using openNLP libraries to make sense of the data(extract keywords/classify) and do a query to Amazon web services to pull the results of the query. We use searchindex=All and keywords=. Results are not always returned and we basically get 'AWS.ECommerceService.NoExactMatches' How to avoid that? 1) Is there a way to specify default results if no match found? e.g. Amazon carousel widget does that if the search query did not return results, it basically show some computer items. 2) Should I batch the request always and add another search criteria to every request? If my first criteria does not pull any results, we can be sure that our 2nd query will always pull results(possibly caching?) Here is one search criteria 'Open Circle Hoop Earrings Polished Stainless Steel Open Circle Hoop Earrings Polished Stainless Steel DiamondShark' This return no results via API. On Amazon site,I get alternative suggestions with some results which are pretty relevant. Is there a way to pull those results? B. We just need a thumbnail image and a title and description for our app. Which responseGroup is appropriate? We are using medium rt now but there is awful lot of information even with that responseGroup. Any help is appreciated. thanks

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  • Javascript and jQuery (Fancybox) question

    - by songdogtech
    Javascript and jQuery (Fancybox) question I'm using the Javascript function below for Twitter sharing (as well as other services; the function code is simplified to just Twitter for this question) that grabs the to-be-shared page URL and title and it is invoked in the link with onclick. That results in the Twitter share page loading in a pop up browser window, i.e.<img src="/images/twitter_16.png" onclick="share.tw()" /> In order to be consistent with other design aspects of the site, what I'd like to be able to do is have the Twitter share page open not in a standard browser window but in a Fancybox (jQuery) window. Fancybox can load an external page in an iFrame when the img or href link contains a class (in this case class="iframe" ) in the link and in the document ready function in the header. Right now, of course, when I give the iframe class to the link that also has the onclick share.tw(), I get two popups: one browser window popup with the correct Twitter share page loaded, and a Fancybox jQuery popup that shows a site 404. How can I change the function to use Fancybox to present the Twitter share page? Is that a correct way to approach it? Or is there a better way, such as implementing the share function in jQuery, too? Thanks... Javascript share function: var share = { tw:function(title,url) { this.share('http://twitter.com/home?status=##URL##+##TITLE##',title,url); }, share:function(tpl,title,url) { if(!url) url = encodeURIComponent(window.location); if(!title) title = encodeURIComponent(document.title); tpl = tpl.replace("##URL##",url); tpl = tpl.replace("##TITLE##",title); window.open(tpl,"sharewindow"+tpl.substr(6,15),"width=640,height=480"); } }; It is invoked, i.e.: <img src="/images/twitter_16.png" onclick="share.tw()" /> Fancybox function, invoked by adding class="iframe" in the img or href link $(".iframe").fancybox({ 'width' : '100%', 'height' : '100%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' });

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  • sql server mdf file database attachment

    - by jnsohnumr
    hello all i'm having a bear of a time getting visual studio 2010 (ultimate i think) to properly attach to my database. it was moved from original spot to #MYAPP#/#MYAPP#.Web/App_Data/#MDF_FILE#.mdf. I have three instances of sql server running on this machine. i have tried to replace the old mdf file with my new one and cannot get the connectionstring right for it. what i'm really wanting to do is to just open some DB instance, run a DB create script. Then I can have a DB that was generated via my edmx (generate database from model) in silverlight business application (c#) right now, when i go to server explorer in VS, choose add new connection, choose MS SQL Server Database FIle (SqlClient), choose my file location (app_data directory), use windows authentication, and hit the Test Connection button I get the following error: Unable to open the physical file "". Operating system error 5: "5(Access Denied.)". An attempt to attach to an auto-named database for file"" failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share. The mdf file was created on the same machine by connecting to (local) on the sql server management studio, getting a new query, pasting in the SQL from the generated ddl file, adding a CREATE DATABASE [NcrCarDatabase]; GO before the pasted SQL, and executing the query. I then disconnected from the DB in management studio, closed management studio, navigated to the DATA directory for that instance, and copying the mdf and ldf files to my application's app_data folder. I am then trying to connect to the same file inside visual studio. I hope that gives more clarity to my problems :). Connection string is: Data Source=.\SQLEXPRESS;AttachDbFilename=C:\SourceCode\NcrCarDatabase\NcrCarDatabase.Web\App_Data\NcrCarDatabase.mdf;Integrated Security=True;Connect Timeout=30;User Instance=True

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  • mysql: storing arbitrary data

    - by Hailwood
    Background: I was asking a question on stack overflow regarding creating tables on the fly where this conversation ensued: This smells like a terrible idea! In fact, it smells just like this one. What in the world do you want to use this for? – deceze @deceze: very true, However, How else would you store the contents of these CSV files. They must be stored in mysql for indexing. The only solid fact about them is that they all have a mobile column with a standard format. The CSV can have an arbitrary amount of columns with an arbitrary amount of rows. They can (with no exaggeration) range from a single row, 35 column csv to an 80k row single column CSV. I am open to other ideas. – Hailwood There are many solutions for this, from attribute-value schemas to JSON storage and NoSQL storage. Open a new question about it. Whatever you do though, don't dynamically create tables! – deceze Question: So my question is, What would you say is the best way to store this data? Are you in agreement with deceze about not creating dynamic tables?

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  • Can I dispose a DataTable and still use its data later?

    - by Eduardo León
    Noob ADO.NET question: Can I do the following? Retrieve a DataTable somehow. Dispose it. Still use its data. (But not send it back to the database, or request the database to update it.) I have the following function, which is indirectly called by every WebMethod in a Web Service of mine: public static DataTable GetDataTable(string cmdText, SqlParameter[] parameters) { // Read the connection string from the web.config file. Configuration configuration = WebConfigurationManager.OpenWebConfiguration("/WSProveedores"); ConnectionStringSettings connectionString = configuration.ConnectionStrings.ConnectionStrings["..."]; SqlConnection connection = null; SqlCommand command = null; SqlParameterCollection parameterCollection = null; SqlDataAdapter dataAdapter = null; DataTable dataTable = null; try { // Open a connection to the database. connection = new SqlConnection(connectionString.ConnectionString); connection.Open(); // Specify the stored procedure call and its parameters. command = new SqlCommand(cmdText, connection); command.CommandType = CommandType.StoredProcedure; parameterCollection = command.Parameters; foreach (SqlParameter parameter in parameters) parameterCollection.Add(parameter); // Execute the stored procedure and retrieve the results in a table. dataAdapter = new SqlDataAdapter(command); dataTable = new DataTable(); dataAdapter.Fill(dataTable); } finally { if (connection != null) { if (command != null) { if (dataAdapter != null) { // Here the DataTable gets disposed. if (dataTable != null) dataTable.Dispose(); dataAdapter.Dispose(); } parameterCollection.Clear(); command.Dispose(); } if (connection.State != ConnectionState.Closed) connection.Close(); connection.Dispose(); } } // However, I still return the DataTable // as if nothing had happened. return dataTable; }

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • how to append a string to next line in perl

    - by tprayush
    hi all , i have a requirement like this.. this just a sample script... $ cat test.sh #!/bin/bash perl -e ' open(IN,"addrss"); open(out,">>addrss"); @newval; while (<IN>) { @col_val=split(/:/); if ($.==1) { for($i=0;$i<=$#col_val;$i++) { print("Enter value for $col_val[$i] : "); chop($newval[$i]=<STDIN>); } $str=join(":"); $_="$str" print OUT; } else { exit 0; } } close(IN); close(OUT); ' when i run this scipt... $ ./test.sh Enter value for NAME : abc Enter value for ADDRESS : asff35 Enter value for STATE : XYZ Enter value for CITY : EIDHFF Enter value for CONTACT : 234656758 $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758 when ran it second time $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758ioret:56fgdh:ghdgh:afdfg:987643221 ## it is appended in the same line... i want it to be added to the next line..... NOTE: i want to do this by explitly using the filehandles in perl....and not with redirection operators in shell. please help me!!!

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Rails problem with Delayed_Job and Active Record

    - by Michael Waxman
    I'm using Delayed_Job to grab a Twitter user's data from the API, but it's not saving it in the model for some reason! Please help! (code below) class BandJob < Struct.new(:band_id, :band_username) #parameter def perform require 'json' require 'open-uri' band = Band.find_by_id(band_id) t = JSON.parse(open("http://twitter.com/users/show/#{band_username}.json").read) band.screen_name = t['screen_name'] band.profile_background_image = t['profile_background_image_url'] band.url = 'http://' + band_username + '.com' band.save! end end To clarify, I'm actually not getting any errors, it's just not saving. Here's what my log looks like: * [JOB] acquiring lock on BandJob [4;36;1mDelayed::Job Update (3.1ms)[0m [0;1mUPDATE "delayed_jobs" SET locked_at = '2009-11-09 18:59:45', locked_by = 'host:dhcp128036151228.central.yale.edu pid:2864' WHERE (id = 10442 and (locked_at is null or locked_at < '2009-11-09 14:59:45') and (run_at <= '2009-11-09 18:59:45')) [0m [4;35;1mBand Load (1.5ms)[0m [0mSELECT * FROM "bands" WHERE ("bands"."id" = 34) LIMIT 1[0m [4;36;1mBand Update (0.6ms)[0m [0;1mUPDATE "bands" SET "updated_at" = '2009-11-09 18:59:45', "profile_background_image" = 'http://a3.twimg.com/profile_background_images/38193417/fbtile4.jpg', "url" = 'http://Coldplay.com', "screen_name" = 'coldplay' WHERE "id" = 34[0m [4;35;1mDelayed::Job Destroy (0.5ms)[0m [0mDELETE FROM "delayed_jobs" WHERE "id" = 10442[0m * [JOB] BandJob completed after 0.5448 1 jobs processed at 1.8011 j/s, 0 failed ... Thanks!

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  • x86 Assembly: Before Making a System Call on Linux Should You Save All Registers?

    - by mudge
    I have the below code that opens up a file, reads it into a buffer and then closes the file. The close file system call requires that the file descriptor number be in the ebx register. The ebx register gets the file descriptor number before the read system call is made. My question is should I save the ebx register on the stack or somewhere before I make the read system call, (could int 80h trash the ebx register?). And then restore the ebx register for the close system call? Or is the code I have below fine and safe? I have run the below code and it works, I'm just not sure if it is generally considered good assembly practice or not because I don't save the ebx register before the int 80h read call. ;; open up the input file mov eax,5 ; open file system call number mov ebx,[esp+8] ; null terminated string file name, first command line parameter mov ecx,0o ; access type: O_RDONLY int 80h ; file handle or negative error number put in eax test eax,eax js Error ; test sign flag (SF) for negative number which signals error ;; read in the full input file mov ebx,eax ; assign input file descripter mov eax,3 ; read system call number mov ecx,InputBuff ; buffer to read into mov edx,INPUT_BUFF_LEN ; total bytes to read int 80h test eax,eax js Error ; if eax is negative then error jz Error ; if no bytes were read then error add eax,InputBuff ; add size of input to the begining of InputBuff location mov [InputEnd],eax ; assign address of end of input ;; close the input file ;; file descripter is already in ebx mov eax,6 ; close file system call number int 80h

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  • Increasing figure size in Matplotlib

    - by Anirudh
    I am trying to plot a graph from a distance matrix. The code words fine and gives me a image in 800 * 600 pixels. The image being too small, All the nodes are packed together. I want increase the size of the image. so I added the following line to my code - figure(num=None, figsize=(10, 10), dpi=80, facecolor='w', edgecolor='k') After this all I get is a blank 1000 * 1000 image file. My overall code - import networkx as nx import pickle import matplotlib.pyplot as plt print "Reading from pickle." p_file = open('pickles/names') Names = pickle.load(p_file) p_file.close() p_file = open('pickles/distance') Dist = pickle.load(p_file) p_file.close() G = nx.Graph() print "Inserting Nodes." for n in Names: G.add_node(n) print "Inserting Edges." for i in range(601): for j in range(601): G.add_edge(Names[i],Names[j],weight=Dist[i][j]) print "Drawing Graph." nx.draw(G) print "Saving Figure." #plt.figure(num=None, figsize=(10, 10)) plt.savefig('new.png') print "Success!"

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  • Path String Combination Question.

    - by Nano HE
    Hi. Please see my code below. ifstream myLibFile ("libs//%s" , line); // Compile failed here ??? I want to combine the path string and open the related file again. #include <iostream> #include <fstream> #include <string> using namespace std; int main () { string line; ifstream myfile ("libs//Config.txt"); // There are several file names listed in the COnfig.txt file line by line. if (myfile.is_open()) { while (! myfile.eof() ) { getline (myfile,line); cout << line << endl; // Read details lib files based on the each line file name. string libFileLine; ifstream myLibFile ("libs//%s" , line); // Compile failed here ??? if (myLibFile.is_open()) { while (! myLibFile.eof() ) { print "success"; } myLibFile.close(); } } myfile.close(); } else cout << "Unable to open file"; return 0; }

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  • Google Maps API v3 - infoWindows all have same content

    - by paulriedel
    Hello, I've been having problems with the infoWindows and Google Maps API v3. Initially, I've ran into the problem that everyone else has of closing infoWindows when opening a new one. I thought to have solved the problem by defining "infowindow" beforehand. Now they close when I click on a new marker, but the content is the same. How should I re-structure my code to make sure the content is the right one each time - and only one infoWindow is open at a given time? Thank you! Paul var allLatLngs = new Array(); var last = 0; var infowindow; function displayResults(start, count){ if(start === undefined){ start = last; } if(count === undefined){ count = 20; } jQuery.each(jsresults, function(index, value) { if(index >= start && index < start+count){ var obj = jQuery.parseJSON(value); $("#textresults").append(index + ": <strong>" + obj.name + "</strong> " + Math.round(obj.distanz*100)/100 + " km entfernt" + "<br/>"); var myLatlng = new google.maps.LatLng(obj.geo_lat, obj.geo_lon); allLatLngs.push(myLatlng); var contentString = '<strong>'+obj.name+'</strong>'; infowindow = new google.maps.InfoWindow({ content: contentString }); var marker = new google.maps.Marker({ position: myLatlng, //title:"Hello World!" }); marker.setMap(map); google.maps.event.addListener(marker, 'click', function() { if (infowindow) { infowindow.close(map,marker); } infowindow.open(map,marker); }); } }); last = start+count;

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  • Android XML Preference issue. Can't make it persistent

    - by Budius
    I have a very simple activity just to show the preference fragment: public class PreferencesActivity extends Activity { Fragment frag = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); FragmentTransaction ft = getFragmentManager().beginTransaction(); if (frag == null) { // If not, instantiate and add it to the activity frag = new PrefsFragment(); ft.add(android.R.id.content, frag, frag.getClass().getName()); } else { // If it exists, simply attach it in order to show it ft.attach(frag); } ft.commit(); } private static class PrefsFragment extends PreferenceFragment { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); addPreferencesFromResource(R.xml.preferences); } } } and preferences.xml with persistent to true: <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android" android:enabled="true" android:persistent="true" android:title="@string/settings" > <EditTextPreference android:dialogTitle="@string/dialog_ip" android:negativeButtonText="@android:string/cancel" android:persistent="true" android:positiveButtonText="@android:string/ok" android:title="@string/ip" /> </PreferenceScreen> if I open the EditTextPreference, write something, close the dialog and open it again. The value is still there. But that's it... if I click the Back button, and enter the again on the preferences screen, I already lost what was written. If you exit the application also doesn't save. Am I missing something here? Running on: Android 4.0.3 Asus TF300

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  • Replacing a word in a text file with a value using python

    - by Jamde Jam
    I have been trying to replace a word in a text file with a value (say 1), but my outfile is blank.I am new to python (its only been a month since I have been learning it). My file is relatively large, but I just want to replace a word with the value 1 for now. Here is a segment of what the file looks like: NAME SECOND_1 ATOM 1 6 0 0 0 # ORB 1 ATOM 2 2 0 12/24 0 # ORB 2 ATOM 3 2 12/24 0 0 # ORB 2 ATOM 4 2 0 0 4/24 # ORB 3 ATOM 5 2 0 0 20/24 # ORB 3 ATOM 6 2 0 0 8/24 # ORB 3 ATOM 7 2 0 0 16/24 # ORB 3 ATOM 8 6 0 0 12/24 # ORB 1 ATOM 9 2 12/24 0 12/24 # ORB 2 ATOM 10 2 0 12/24 12/24 # ORB 2 #1 #2 #3 I want to first replace the word ATOM with the value 1. Next I want to replace #ORB with a space. Here is what I am trying thus far. input = open('SECOND_orbitsJ22.txt','r') output=open('SECOND_orbitsJ22_out.txt','w') for line in input: word=line.split(',') if(word[0]=='ATOM'): word[0]='1' output.write(','.join(word)) Can anyone offer any suggestions or help? Thanks so much.

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  • Werid onclick behavior of images on home screen widget

    - by kknight
    I wrote a home screen widget with one image on it. When the image is clicked, browser will be opened for a url link. Generally, it is working. But a weird thing is that, when I click background, then click the picture, the browser will not be open. Until I click the second time on the picture, the browser opens. The steps to reproduce is below: Click on the home screen widget background. Click on the image on the home screen. The browser is not opened. Click on the image again. The browser is opened. If I didn't click on the background, the image will react to click very well, i.e. browser will be open when the image is clicked the first time. The widget XML file is as below: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="320dip" android:layout_height="200dip" android:background="@drawable/prt_base" > <ImageView android:id="@+id/picture1" android:layout_width="134dip" android:layout_height="102dip" android:layout_marginLeft="62dip" android:layout_marginTop="6dip" android:scaleType="center" android:src="@drawable/picture1" /> </RelativeLayout> The code to set OnClick on the picture1 ImageView is as below: defineIntent = new Intent(Intent.ACTION_VIEW, Uri .parse("http://www.google.com")); pendingIntent = PendingIntent .getActivity(context, 0 /* no requestCode */, defineIntent, 0 /* no flags */); updateViews.setOnClickPendingIntent( picId, pendingIntent); Anyone knows what's wrong? Thanks.

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  • PhotoChooserTask + Navigation.

    - by user562405
    I taken two Images & added event (MouseButtonDown) for them. When first image handles event to open Gallery. Second image handles events for open camera. When user has choosed his image from the gallery, I want to navigate to next page. Its navigates. But before completing navigation process, it displays MainPage & then moves toward next page. I didnt want to display the MainPage once user chooses the image from the gallery. Plz help. Thanks in advance. public partial class MainPage : PhoneApplicationPage { PhotoChooserTask objPhotoChooser; CameraCaptureTask cameraCaptureTask; // Constructor public MainPage() { InitializeComponent(); objPhotoChooser = new PhotoChooserTask(); objPhotoChooser.Completed += new EventHandler<PhotoResult>(objPhotoChooser_Completed); cameraCaptureTask = new CameraCaptureTask(); cameraCaptureTask.Completed += new EventHandler<PhotoResult>(objCameraCapture_Completed); } void objPhotoChooser_Completed(object sender, PhotoResult e) { if (e != null && e.TaskResult == TaskResult.OK) { //Take JPEG stream and decode into a WriteableBitmap object App.CapturedImage = PictureDecoder.DecodeJpeg(e.ChosenPhoto); //Delay navigation until the first navigated event NavigationService.Navigated += new NavigatedEventHandler(navigateCompleted); } } void navigateCompleted(object sender, EventArgs e) { //Do the delayed navigation from the main page this.NavigationService.Navigate(new Uri("/ImageViewer.xaml", UriKind.RelativeOrAbsolute)); NavigationService.Navigated -= new NavigatedEventHandler(navigateCompleted); } void objCameraCapture_Completed(object sender, PhotoResult e) { if (e.TaskResult == TaskResult.OK) { //Take JPEG stream and decode into a WriteableBitmap object App.CapturedImage = PictureDecoder.DecodeJpeg(e.ChosenPhoto); //Delay navigation until the first navigated event NavigationService.Navigated += new NavigatedEventHandler(navigateCompleted); } } protected override void OnBackKeyPress(System.ComponentModel.CancelEventArgs e) { e.Cancel = true; } private void image1_MouseLeftButtonDown(object sender, MouseButtonEventArgs e) { objPhotoChooser.Show(); } private void image2_MouseLeftButtonDown(object sender, MouseButtonEventArgs e) { cameraCaptureTask.Show(); }

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  • Can't get gravity to work with RMagick and 'caption'

    - by mph
    I'm using RMagick 2.12.2 with ImageMagick 6.5.6-10 on Snow Leopard. I'm trying to put captions on a collection of photos, and I'm getting the caption to work (i.e. it appears on the image), but I can't get the gravity parameter to work correctly. No matter what I set it to, I end up with some variation on NorthGravity. For instance: Setting it to SouthWestGravity gives me NorthWestGravity. Setting it to SouthEastGravity gives me NorthEastGravity. Setting it to CenterGravity gives me NorthGravity. In other words, I can't get the caption to come down off the top of the image. I'd consider using "annotate," but I need "caption" so the lengthy caption text for each image will wrap. What am I doing wrong? Here's the code: #!/usr/bin/env ruby require "rubygems" require "yaml" require "RMagick" include Magick base_dir = "/Users/mike/Desktop/caption_test" photo_log = File.open("#{base_dir}/photo_log.yaml" ) YAML::load_documents(photo_log) do |doc| caption = doc["photo-caption"] filename = doc["file"] canvas = ImageList.new.from_blob(open("#{base_dir}/#{filename}") { |f| f.read } ) canvas << Magick::Image.read("caption:#{caption}") { self.gravity = SouthWestGravity self.size = "#{canvas.first.columns}" self.font = "Helvetica Neue" self.pointsize = 12 self.background_color = "#fff" }.first canvas.flatten_images.write("#{base_dir}/images/#{filename}") end

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