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  • UnicodeDecodeError from a GET-parameter in webapp2

    - by Aneon
    I'm getting a UnicodeDecodeError when recieving a GET-parameter from webapp2 that contains unicode characters, and then using it to do a NDB query. I get the same error message when manually running a unicode() on the parameter in the handler, so there either seems to be a problem in webapp2's URL routing or I've missed something. Preferably, all GET-parameters should be converted to unicode before getting passed into the handler so I don't need to do manual conversions in all of my handlers. I actually think it's worked before in an earlier version. The full error message read: UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 1: ordinal not in range(128) The GET-parameter contains the following string: göteborg. It looks fine when I raise an Exception on it, but gives me an error when I (or NDB) use unicode() on it. EDIT: In NDB, it fails on the following code: File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore_types.py", line 1562, in PackString pbvalue.set_stringvalue(unicode(value).encode('utf-8')) Thanks.

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  • How can I access the "through" object of a Django ManyToManyField?

    - by Macha
    I have the following models in my Django app. How can I from the Team model find all the User objects who have accepted as True in the Membership model? I know I need to use Team.objects.filter(), but I'm not sure how to check the value of the accepted field. from django.contrib.auth.models import User class Team(models.Model): members = models.ManyToManyField(User, through="Membership") class Membership(models.Model): user = models.ForeignKey(User) team = models.ForeignKey(Team) accepted = models.BooleanField(default=False)

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  • Find all A^x in a given range

    - by Austin Henley
    I need to find all monomials in the form AX that when evaluated falls within a range from m to n. It is safe to say that the base A is greater than 1, the power X is greater than 2, and only integers need to be used. For example, in the range 50 to 100, the solutions would be: 2^6 3^4 4^3 My first attempt to solve this was to brute force all combinations of A and X that make "sense." However this becomes too slow when used for very large numbers in a big range since these solutions are used in part of much more intensive processing. Here is the code: def monoSearch(min, max): base = 2 power = 3 while 1: while base**power < max: if base**power > min: print "Found " + repr(base) + "^" + repr(power) + " = " + repr(base**power) power = power + 1 base = base + 1 power = 3 if base**power > max: break I could remove one base**power by saving the value in a temporary variable but I don't think that would make a drastic effect. I also wondered if using logarithms would be better or if there was a closed form expression for this. I am open to any optimizations or alternatives to finding the solutions.

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  • twitter api post rate limit

    - by Xavier
    Does anyone know Twitter's rate limit on posting? Looking at their web page they claimed to not have one but I get an exception thrown if my program posts too fast... Any help is appreciated.

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  • Is there an efficient way to figure out the headers, cookies, and get/post data being passed to a si

    - by kryptobs2000
    More specifically I'm looking for something, perhaps an add-on for firefox, once enabled it logs all of this information as it's passed to and from the server. I'm doing some web scripting and this would be really handy. If anyone is wondering specifically what I'm doing currently I'm trying to make a script to repost my craigslist ad every 2 days since I handle a few things on there. Might even go so far as to make a simple gui to manage the submissions. I do suspect this goes against the ToS, for that reason I don't plan to release the code. Besides cl is already bad enough with spam, I'm not trying to contribute further to it, figured I'd say what I'm doing for the sake of being honest though. I don't have any bad intentions with this, just some things I've been trying to sell an ad for my pc repair business. I've been reposting some things for months now and so often I just forget to do it.

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  • wxpython Prevent Ctrl+Enter from changing the focus

    - by RSabet
    I have two wxListCtrl and want to process the Ctrl+Enter keyboard event without letting wx change the focus to the other ListCtrl. I have event handlers for wx.EVT_KEY_DOWN, wx.EVT_KEY_UP, wx.EVT_CHAR and KillFocus, but KillFocus is always called first, then the focus changes and the the keyboard handlers are called for the wrong ListCtrl. Is there a way to prevent wx from changing the focus, when Ctrl+Enter is pressed ?

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  • maching strings

    - by kiran
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions for def countSubStringMatch(target,key): and def countSubStringMatchRecursive (target, key): For the remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures.

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  • a function that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n

    - by martin
    I need to write a function called multipleOf3 that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n and here is the result i want [Note: No number returned can be greater than the value of the parameter n] Examples: multipleOf3(0) -- 0 multipleOf3(1) -- 0 multipleOf3(2) -- 0 multipleOf3(3) -- 0 or 3 multipleOf3(20) -- 0 or 3 or 6 or 9 or 12 or 15 or 18

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  • Is it possibile to modify a link value with Beautifulsoup without recreating the all link?

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo</a> <a href="http://www.bar.com" rel="nofollow">this is bar</a> </p> is it possible to modify the <a> node values ("this i foo" and "this is bar") adding the suffix "PARSED" to the value without recreating the all link? The result need to be like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo_PARSED</a> <a href="http://www.bar.com" rel="nofollow">this is bar_PARSED</a> </p> And code should be something like: from BeautifulSoup import BeautifulSoup soup = BeautifulSoup(html) for link_tag in soup.findAll('a'): link_tag.string = link_tag.string + '_PARSED' #This obviously does not work

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  • Search one element of a list in another list recursively

    - by androidnoob
    I have 2 lists old_name_list = [a-1234, a-1235, a-1236] new_name_list = [(a-1235, a-5321), (a-1236, a-6321), (a-1234, a-4321), ... ] I want to search recursively if the elements in old_name_list exist in new_name_list and returns the associated value with it, for eg. the first element in old_name_list returns a-4321, second element returns a-5321, and so on until old_name_list finishes. I have tried the following and it doesn't work for old_name, new_name in zip(old_name_list, new_name_list): if old_name in new_name[0]: print new_name[1] Is the method I am doing wrong or I have to make some minor changes to it? Thank you in advance.

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  • directory and file related doubts??

    - by kaushik
    i have a directory with around 1000 files....i want to run a same code for each of these file... my code requires the file name to be inputted. i have written code to copy the information of one into other in other format... please suggest a method to copy all 1000 files one by one without need to change the file name every time and i have a field serial_num which need to be continous i.e if 1st file has upto 30 then while coping other file it should continue from 30not from 0 again require suggestion please thanks..

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  • if else-if making code look ugly any cleaner solution?

    - by Vishal
    I have around 20 functions (is_func1, is_fucn2, is_func3...) returning boolean I assume there is only one function which returns true and I want that! I am doing: if is_func1(param1, param2): # I pass 1 to following abc(1) # I pass 1 some_list.append(1) elif is_func2(param1, param2): # I pass 2 to following abc(2) # I pass 1 some_list.append(2) ... . . elif is_func20(param1, param2): ... Please note: param1 and param2 are different for each, abc and some_list take parameters depending on the function. The code looks big and there is repetition in calling abc and some_list, I can pull this login in a function! but is there any other cleaner solution? I can think of putting functions in a data structure and loop to call them.

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  • Own params to PeriodicTask run() method in Celery

    - by Alex Isayko
    Hello to all! I am writing a small Django application and I should be able to create for each model object its periodical task which will be executed with a certain interval. I'm use for this a Celery application, but i can't understand one thing: class ProcessQueryTask(PeriodicTask): run_every = timedelta(minutes=1) def run(self, query_task_pk, **kwargs): logging.info('Process celery task for QueryTask %d' % query_task_pk) task = QueryTask.objects.get(pk=query_task_pk) task.exec_task() return True Then i'm do following: >>> from tasks.tasks import ProcessQueryTask >>> result1 = ProcessQueryTask.delay(query_task_pk=1) >>> result2 = ProcessQueryTask.delay(query_task_pk=2) First call is success, but other periodical calls returning the error - TypeError: run() takes exactly 2 non-keyword arguments (1 given) in celeryd server. So, can i pass own params to PeriodicTask run() ? Thanks!

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  • Convert octet string to human readable

    - by Michael Lang
    Using the pysnmp framework i get some values doing a snmp walk. Unfortunately for the oid 1.3.6.1.21.69.1.5.8.1.2 (DOCS-CABLE-DEVICE-MIB) i get a weird result which i cant correctly print here since it contains ascii chars like BEL ACK When doing a repr i get: OctetString('\x07\xd8\t\x17\x03\x184\x00') But the output should look like: 2008-9-23,3:24:52.0 the format is called "DateAndTime". How can i translate the OctetString output to a "human readable" date/time ?

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  • GTK+: How do I process RadioMenuItem choice without marking it chosen? And vise versa

    - by eugene.shatsky
    In my program, I've got a menu with a group of RadioMenuItem entries. Choosing one of them should trigger a function which can either succeed or fail. If it fails, this RadioMenuItem shouldn't be marked chosen (the previous one should persist). Besides, sometimes I want to set marked item without running the choice processing function. Here is my current code: # Update seat menu list def update_seat_menu(self, seats, selected_seat=None): seat_menu = self.builder.get_object('seat_menu') # Delete seat menu items for menu_item in seat_menu: # TODO: is it a good way? does remove() delete obsolete menu_item from memory? if menu_item.__class__.__name__ == 'RadioMenuItem': seat_menu.remove(menu_item) # Fill menu with new items group = [] for seat in seats: menu_item = Gtk.RadioMenuItem.new_with_label(group, str(seat[0])) group = menu_item.get_group() seat_menu.append(menu_item) if str(seat[0]) == selected_seat: menu_item.activate() menu_item.connect("activate", self.choose_seat, str(seat[0])) menu_item.show() # Process item choice def choose_seat(self, entry, seat_name): # Looks like this is called when item is deselected, too; must check if active if entry.get_active(): # This can either succeed or fail self.logind.AttachDevice(seat_name, '/sys'+self.device_syspath, True) Chosen RadioMenuItem gets marked irrespective of the choose_seat() execution result; and the only way to set marked item without triggering choose_seat() is to re-run update_seat_menu() with selected_seat argument, which is an overkill. I tried to connect choose_seat() with 'button-release-event' instead of 'activate' and call entry.activate() in choose_seat() if AttachDevice() succeeds, but this resulted in whole X desktop lockup until AttachDevice() timed out, and chosen item still got marked.

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  • delete common dictionaries in list based on a value

    - by pythoonatic
    How would I delete all corresponding dictionaries in a list of dictionaries based on one of the dictionaries having a character in it. data = [ { 'x' : 'a', 'y' : '1' }, { 'x' : 'a', 'y' : '1/1' }, { 'x' : 'a', 'y' : '2' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, ] For example, how would I delete all of the x = a due to one of the y in the x=a having a / in it? Based on the example data above, here is where I would like to get to: cleaneddata = [ { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, ]

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  • Common elements comparison between 2 lists.

    - by Daniel
    def common_elements(list1, list2): """ Return a list containing the elements which are in both list1 and list2 >>> common_elements([1,2,3,4,5,6], [3,5,7,9]) [3, 5] >>> common_elements(['this','this','n','that'],['this','not','that','that']) ['this', 'that'] """ for element in list1: if element in list2: return list(element) Got that so far, but can't seem to get it to work! Thanks

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  • Sleeping a thread blocking stdin

    - by Sid
    Hey, I'm running a function which evaluates commands passed in using stdin and another function which runs a bunch of jobs. I need to make the latter function sleep at regular intervals but that seems to be blocking the stdin. Any advice on how to resolve this would be appreciated. The source code for the functions is def runJobs(comps, jobQueue, numRunning, limit, lock): while len(jobQueue) >= 0: print(len(jobQueue)); if len(jobQueue) > 0: comp, tasks = find_computer(comps, 0); #do something time.sleep(5); def manageStdin(): print "Global Stdin Begins Now" for line in fileinput.input(): try: print(eval(line)); except Exception, e: print e; --Thanks

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  • Why is numpy c extension slow?

    - by Bitwise
    I am working on large numpy arrays, and some native numpy operations are too slow for my needs (for example simple operations such as "bitwise" A&B). I started looking into writing C extensions to try and improve performance. As a test case, I tried the example given here, implementing a simple trace calculation. I was able to get it to work, but was surprised by the performance: for a (1000,1000) numpy array, numpy.trace() was about 1000 times faster than the C extension! This happens whether I run it once or many times. Is this expected? Is the C extension overhead that bad? Any ideas how to speed things up?

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  • How can I receive percent encoded slashes with Django on App Engine?

    - by J. Frankenstein
    I'm using Django with Google's App Engine. I want to send information to the server with percent encoded slashes. A request like http:/localhost/turtle/waxy%2Fsmooth that would match against a URL like r'^/turtle/(?P<type>([A-Za-z]|%2F)+)$'. The request gets to the server intact, but sometime before it is compared against the regex the %2F is converted into a forward slash. What can I do to stop the %2Fs from being converted into forward slashes? Thanks!

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  • How can I refresh wx.Frame?

    - by aF
    Hello, I have 3 panels and I want to make drags on them. The problem is that when I do a drag on one this happens: How can I refresh the frame to happear its color when the panel is no longer there?

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  • How to quickly parse a list of strings

    - by math
    If I want to split a list of words separated by a delimiter character, I can use >>> 'abc,foo,bar'.split(',') ['abc', 'foo', 'bar'] But how to easily and quickly do the same thing if I also want to handle quoted-strings which can contain the delimiter character ? In: 'abc,"a string, with a comma","another, one"' Out: ['abc', 'a string, with a comma', 'another, one'] Related question: How can i parse a comma delimited string into a list (caveat)?

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  • Word filter that groups words?

    - by Legend
    Is there any library that achieves the following: Convert Microsoft Windows 98 Microsoft Windows XP Windows 7 Windows Ultimate Desktop Windows to Windows 4 The complicated part here is to recognize that "Desktop Windows" is an anomaly here and not count it. If nothing is added before the word "Windows", perhaps it can be counted but if there is something else and the suffix does not match any popular suffix, it can still be counted. Maybe I am a little vague here but perhaps someone could have an idea about what I am talking about here. Any suggestions?

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