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  • How to insert into data base using multi threading programming [closed]

    - by user1196650
    I am having a method and that method needs to do the following thing: It has to insert records into a database. No insert is done for the same table again. All inserts are into different tables. I need a multi threading logic which inserts the details into db using different threads. I am using oracle db and driver configuration and remaining stuff are perfect. Please help me with an efficient answer. Can anyone could provide me with a skeleton logic of the program.

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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  • ASP.NET permissions issues

    - by Paul
    Im using Windows Server 2008, IIS7, .NET 4 and when I use the FileUpload control to save a file to a directory I get : Access to the path 'C:\xxx\Websites\CMS\Admin\test' is denied. I have given the test folder full control permissions for NETWORK SERVICE but it makes no difference. I have given full control to the Everyone user but makes no difference. It might have something to do with the fact that up in the CMS folder there is a MVC web application and in the CMS\Admin folder there is a web forms web application. It is the web forms web application that is trying to upload the file and getting the permissions error. Can anyone offer a suggestion.

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  • MySQLI Prepared Statement Not Binding Properly

    - by Sev
    Any reason why the following code won't work? $dbconnection = db::getInstance(); //this is a singleton db class $stmt = $dbconnection->prepare("SELECT `id` from `table` where `username`=?"); $stmt->bind_param("s", $username); $stmt->execute(); $stmt->bind_result($uid); $stmt->fetch(); echo $uid; The same connection method is used elsewhere, and it works there. The only difference on that other page where it works, is that there are multiple rows fetched, not just one.

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  • PHP Localhost Application connect to server database

    - by Cross Vander
    I want to ask about how to connect my localhost application (C:xampp/htdocs/myproject) to database at my server host (www.someweb.somedomain)? Am I possible to do that? If it is, how to connect it at my php config? Right now my config (server.php) is: <?php $host = "my web IP public:3306"; $user = "root"; $pass = ""; $db = "dispatcherDB"; $conn = mysql_connect($host, $user, $pass) or die ("Cant connect to mySQL"); mysql_select_db($db); ?> what I got: Warning: mysql_connect(): No connection could be made because the target machine actively refused it. in C:\xampp\htdocs\XMS\server.php on line 7 So, what must I filled for $host? I'm trying using website IP, it still can't connect. Maybe there's someone here have experience at this problem? Sorry for my bad English

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  • Configuring jdbc-pool (tomcat 7)

    - by john
    i'm having some problems with tomcat 7 for configuring jdbc-pool : i`ve tried to follow this example: http://www.tomcatexpert.com/blog/2010/04/01/configuring-jdbc-pool-high-concurrency so i have: conf/server.xml <GlobalNamingResources> <Resource type="javax.sql.DataSource" name="jdbc/DB" factory="org.apache.tomcat.jdbc.pool.DataSourceFactory" driverClassName="com.mysql.jdbc.Driver" url="jdbc:mysql://localhost:3306/mydb" username="user" password="password" /> </GlobalNamingResources> conf/context.xml <Context> <ResourceLink type="javax.sql.DataSource" name="jdbc/LocalDB" global="jdbc/DB" /> <Context> and when i try to do this: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup("java:/comp/env"); DataSource datasource = (DataSource)envContext.lookup("jdbc/LocalDB"); Connection con = datasource.getConnection(); i keep getting this error: javax.naming.NameNotFoundException: Name jdbc is not bound in this Context at org.apache.naming.NamingContext.lookup(NamingContext.java:803) at org.apache.naming.NamingContext.lookup(NamingContext.java:159) pls help tnx

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  • A typical lifecycle of a Hibernate object in a web app - ?

    - by EugeneP
    Describe please a typical lifecycle of a Hibernate object (that maps to a db table) in a web app. Suppose, you create a new instance of an object and persist in the db. But during the app lifetime you'll be working on a detached object and finally you need to update it in the database, for example on exit. How does it look like with hibernate and spring? p.s. Can transactions and sessions live between servlet transitions? So that we opened 1 session and use it in all servlets without a need to reopen it?

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  • Data access layer design

    - by Sam
    I have a web app and a console application accessing a db. The db has 2 tables (A, B) one of which (A) is specific to the web app. When writing a data access layer, what is the best way to do it? Technically data access layer should provide access to all the data accessible. In doing so, methods to interact with A are exposed to the console application if we have single access layer. Does creating 2 access layers to 2 table in the same database makes any sense? What is a good way to do it?

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  • Improve C function performance with cache locality?

    - by Christoper Hans
    I have to find a diagonal difference in a matrix represented as 2d array and the function prototype is int diagonal_diff(int x[512][512]) I have to use a 2d array, and the data is 512x512. This is tested on a SPARC machine: my current timing is 6ms but I need to be under 2ms. Sample data: [3][4][5][9] [2][8][9][4] [6][9][7][3] [5][8][8][2] The difference is: |4-2| + |5-6| + |9-5| + |9-9| + |4-8| + |3-8| = 2 + 1 + 4 + 0 + 4 + 5 = 16 In order to do that, I use the following algorithm: int i,j,result=0; for(i=0; i<4; i++) for(j=0; j<4; j++) result+=abs(array[i][j]-[j][i]); return result; But this algorithm keeps accessing the column, row, column, row, etc which make inefficient use of cache. Is there a way to improve my function?

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  • How to create wordpress-like option table and get values for each row? (PHP-MySQL)

    - by Nacho
    Hi guys. I'm looking to create an options table in my db that makes every record a system option, so i can work with a little number of fields. my db has the following structure: 3 columns named id, name, and value following data is inserted as an example -- id - name - value 1 - uri - www.example.com 2 - sitename - Working it out 3 - base_folder - /folder1/folder2/ 4 - slogan - Just a slogan for the site -- that way i can include a large number of customizable system options very easily the problem is that i don't know how to retrieve them how do i get the value of uri and store it as a var? and better yet, how do i get, for exmaple, values of id 1 and 4 only without making a query each time? (i assume multiple queries are useless and a pretty ugly method) i know the question is pretty basic but i'm lost here. i'd really appreciate your answer! Thanks in advance

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  • JQuery .get() only passing first two data parameters in url

    - by The.Anti.9
    I have a $.get() call to a PHP page that takes 4 GET parameters. For some reason, despite giving the $.get() call all 4, it only passes the first two. When I look at the dev console in chrome, it shows the URL that gets called, and it only passes action and dbname. Heres the code: $.get('util/util.php', { action: 'start', dbname: db, url: starturl, crawldepth: depth }, function(data) { if (data == 'true') { status = 1; $('#0').append(starturl + "<ul></ul>"); $('#gobutton').hide(); $('#loading').show("slow"); while(status == 1) { setTimeout("update()",10000); } } else { show_error("Form data incomplete!"); } }); and heres the URL that I see in the developer console: http://localhost/pci/util/util.php?action=start&dbname=1hkxorr9ve1kuap2.db

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  • PHP send batch email [closed]

    - by qalbiol
    Possible Duplicate: Sending mass email using PHP I have a PHP script that sends an individual email to all users in my DB, such as a monthly / weekly newsletter. The code I am using goes as follows: $subject = $_POST['subject']; $message = $_POST['message']; // Get all the mailing list subscribers. $query = $db->prepare("SELECT * FROM maildb"); $query->execute(); // Loop through all susbcribers, and send and individual email. foreach ($query as $row) { // Setting maximum time limit to infinite. set_time_limit(0); $newMessage = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> </head> <body>'; // Search for the [unsubscribe] tag and replace it with a URL for the user to unsubscribe $newMessage .= str_replace("[unsubscribe]", "<a href='".BASE_URL."unsubscribe/".$row['hash']."/".$row['email']."'>unsubscribe</a>", $message); $newMessage .= '</body></html>'; $to = $row['email']; // Establish content headers $headers = "From: [email protected]"."\n"; $headers .= "Reply-To: [email protected]"."\n"; $headers .= "X-Mailer: PHP v.". phpversion()."\n"; $headers .= "MIME-Version: 1.0"."\n"; $headers .= "Content-Type: text/html; charset=iso-8859-1"."\n"; $headers .= "Content-Transfer-Encoding: 8bit;"; mail($to, $subject, $newMessage, $headers); // Send email to each individual user } This code works perfectly with a REALLY small database... I recently populated my test db with 200k+ users, and obviously this script fails, gets out of memory, and dies... I know this is a bad way to send so many emails, thats why I'd like to ask you for much more efficient ways to do this! Thank you very much!

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  • PHP & MySQL Problem

    - by Fincha
    I Have a script, getting text from DB and post it on other DB. Problem is, if I have a Text lngen then 840 Words, I can't call this page. Get an error about "Not Found" or "Connection brocken" or what ever. In FF i get no error, only blank page. I found out the Problem is in lenght of the query i send... but how can i fix it??? My it be the Problem, if a query is longer then 6000 Characters?

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  • Linq to SQL DateTime values are local (Kind=Unspecified) - How do I make it UTC?

    - by ericsson007
    Isn't there a (simple) way to tell Linq To SQL classes that a particular DateTime property should be considered as UTC (i.e. having the Kind property of the DateTime type to be Utc by default), or is there a 'clean' workaround? The time zone on my app-server is not the same as the SQL 2005 Server (cannot change any), and none is UTC. When I persist a property of type DateTime to the dB I use the UTC value (so the value in the db column is UTC), but when I read the values back (using Linq To SQL) I get the .Kind property of the DateTime value to be 'Unspecified'. The problem is that when I 'convert' it to UTC it is 4 hours off. This also means that when it is serialized it it ends up on the client side with a 4 hour wrong offset (since it is serialized using the UTC).

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  • Empty database output in CI

    - by den-javamaniac
    Hi. I'm building a simple app and trying to test DB result output. But unfortunately all I'm getting is an array of size 0. Here's the controller code excerpt: $data['query'] = $this->db->query('SELECT role_id, role_privilege FROM role'); $this->load->view('welcome_message', $data); And a view code excerpt: <?php echo count($query->result_array())."<br/>"; foreach ($query->result() as $row){ echo $row->role_id . '<br/>'; echo $row->role_privilege . '<br/>'; } echo 'Total result '.$query->num_rows(); ?> And what I get is next: 0 Total result Running query from a command line gives a 2 rowed output. Can someone point out what i'm missing?

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  • MySQL text field issues

    - by chenger
    This is quite a noobish question, I have searched for a few hours now and I know this has to be simple. I am using XAMPP and I am trying to learn some more about using PHP and mySQL together. When I create the DB and the table for information to store, I tried insert info to the table and it stores it as a .dat file rather than text. I know this has to be with how I am setting up the table or the DB but I have gone through things and I think I am just skipping over something. * Apache/2.2.12 (Win32) DAV/2 mod_ssl/2.2.12 OpenSSL/0.9.8k mod_autoindex_color PHP/5.3.0 mod_perl/2.0.4 Perl/v5.10.0 * MySQL client version: 5.1.37 * PHP extension: mysqli that is the phpmyadmin info.

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  • Won't connect to the database

    - by user1657958
    I'm confused...I'm using the same code in a different document and in there it's not a problem to get a connection to the database. But in the new document it's just not working...(password, username, database name...all is checked and correct) :-/ <?php define ("DB_HOST", "db1234567.db.hello.com"); // set database host define ("DB_USER", "db1234567"); // set database user define ("DB_PASS","password123"); // set database password define ("DB_NAME","db1234567"); // set database name $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die("Couldn't make connection."); $db = mysql_select_db(DB_NAME, $link) or die("Couldn't select database"); ?> In the browser I get this: "Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'db1234567'@'123.123.12.12 (using password: YES) in /homepages/12/1234567/test/test.php on line 8 Couldn't make connection." Would be cool if someone could help me :) I'm not seeing any error... Thx!

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