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Granting administrator privileges to an application launched at startup without UAC prompt?

- by iKenndac

Background I've written a small C#/.NET 4.0 application that syncs various settings from a game installed in Program Files to and from other copies of the same game on different machines (think Chrome bookmark sync, but for this game). The sync itself is a relatively simple affair, dealing with files stored inside the game's Program Files folder. On my machine, this works fine without having to elevate my application through UAC. Windows 7 makes the game use Program Files virtualisation and my application works fine with that. However, on a lot of tester's machines, I'm getting reports that the application either can't work with the files and in come cases can't even see the game's folder! Having the user right-click and "Run as Administrator" solves the problem in every case. So, we just set the application's manifest to require admin privileges, right? That's fine (although not ideal) for when the user manually invokes the application or the sync process because they'll be interacting with the application and ready to accept a UAC request. However, one of the features of my application is a "Sync Automatically" option, which allows the user to "set and forget" the application. With this set, the application puts itself into the registry at HKCU\Software\Microsoft\Windows\CurrentVersion\Run to be run at startup and sits in the system tray syncing the settings in the background as needed. Obviously, I need to be smarter here. Presenting a UAC prompt as soon as the user logs in to their account or at random intervals afterwards isn't the way forwards. So, my question! What's the best way to approach a situation where I'd need to run an application at startup that needs administrator privileges? Is there a way to have the user authorise an installation that causes the system to automatically run the application with the correct privileges without a prompt at startup/login?

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cakephp group based permissions

- by Elwhis

Hey guys, I would like to have group based restrictions that would allow users to access only specified parts of the web. I am new to the whole ACL stuff and I didn't quite get it from the manual :/ therefore I would like to ask some questions. But before any questions, my routes look like this: Router::connect('/', array('controller' => 'users', 'action' => 'login')); Router::connect('/admin/:controller/:action/*', array('prefix' => 'admin', 'admin' => true)); Router::connect('/registered/:controller/:action/*', array('prefix' => 'registered', 'registered' => true)); 1.) How do I restrict users from any other group than Administrator to access ONLY the /registered/ part of the web 2.) How do I prevent anyone from using the default addresses like www.example.com/users/add on a global scale (I want only www.example.com/admin/users/add or www.example.com/registered/users/add type of addresses)? This kind of addresses is not event set in the routes.php but they still work. Any answers apprecated

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Print table data mysql php

- by Marcelo

Hi people, i'm having a problem trying to print some data of a table. I'm new at this php mysql stuff but i think my code is right. Here it is: <html> <body> <h1>Lista de usuários</h1> <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="sabs"; // Database name $tbl_name="doador"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); while($rows = mysql_fetch_array($result)){ echo $row['id'] . " " .$row['nome'] . " " . $row['sobrenome'] . " " . $row['email'] . " " . $row['login'] . " " . $row['senha'] . " " . $row['idade'] . " ". $row['peso'] . " " . $row['fuma'] . " " . $row['sexo'] . " " . $row['doencas']; echo "<BR/>"; } mysql_close(); ?> </body> </html> All columns of the echo command exist in my table in the database. Don't get why it's not printing those values. Thanks for the attention.

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Devise password reset issue (new_user?)

- by rabid_zombie

When a user's email is inputted into the forgot password form and submitted, I am receiving an error saying login can't be blank. I looked around devise.en.yml for this error message, but can't seem to find it anywhere. Here is my views/devise/passwords/new.html.haml: %div.registration_page %h2 Forgot your password? = form_for(resource, :as => resource_name, :url => user_password_path, :html => { :method => :post, :id => 'forgot_pw_form', :class => 'forgot_pw' }) do |f| %div = f.email_field :email, :placeholder => 'Email', :autofocus => true, :autocomplete => 'off' %div.email_error.error %input.btn.btn-success{:type => 'submit', :value => 'Send Instructions'} = render "devise/shared/links" The form is posting to users/password like it should, but I noticed that my forgot password form attaches class = 'new_user'. Here is what my form displays: <form accept-charset='UTF-8' action='/users/password' class='new_user' id='forgot_pw_form' method='post' novalidate='novalidate'></form> My routes for devise (I have custom sessions and registrations controllers): devise_for :users, :controllers => {:sessions => 'sessions', :registrations => 'registrations'} How can I setup devise's forgot password functionality? Why am I receiving this error message and why is that class being added there? I've tried: Adding my own passwords controller and adding new routes for my custom controller. Same error Adding my own class and id to the form. This successfully changes the id and class of the form, but reverts back to class and id of new_user Thanks.

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How to show alert in a jsp from a servlet and then redirect to another jsp?

- by Xaul Omar Tobar

I tried this but does not display the message only redirects login.jsp <form method="post" action="Login_Servlet" > <input name="idUsuario" type="text"/> <input name="password" type="password" /> <button type="submit">Entrar</button> </form> Login_Servlet response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); String userid= request.getParameter("idUser"); String password = request.getParameter("password"); Login_Service login_Service = new Login_Service(); boolean result = login_Servicio.aut(userid, password); Usuario user = login_Servicio.getUsuariosByUsuario(userid); if(result == true){ request.getSession().setAttribute("user", user); response.sendRedirect("vistas/Inicio.jsp"); } else{ out.println("<script type=\"text/javascript\">"); out.println("alert('User or password incorrect');"); out.println("</script>"); response.sendRedirect("index.jsp"); } Is it possible to display a message like this? if so I'm doing wrong?

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Facebook / Offline Permission - Trying to perform an action on a set of offline users.

- by blueigloo

Hi there, We're building an app which in part of its functionality tries to capture the number of likes associated to a particular video owned by a user. Users of the app are asked for extended off-line access and we capture the key for each user: The format is like this: 2.hg2QQuYeftuHx1R84J1oGg__.XXXX.1272394800-nnnnnn Each user has their offline / infinite key stored in a table in a DB. The object_id which we're interested in is also stored in the DB. At a later stage (offline) we try to run a batch job which reads the number of likes for each user's video. (See attached code) For some reason however, after the first iteration of the loop - which yields the likes correctly, we get a failure with the oh so familiar message: "Session key is invalid or no longer valid" Any insight would be most appreciated. Thanks, B List<DVideo> videoList = db.SelectVideos(); foreach (DVideo video in videoList) { long userId = 0; ConnectSession fbSession = new ConnectSession(APPLICATION_KEY, SECRET_KEY); //session key is attached to the video object for now. fbSession.SessionKey = video.UserSessionKey; fbSession.SessionExpires = false; string fbuid =video.FBUID; long.TryParse(fbuid, out userId); if (userId > 0) { fbSession.UserId = userId; fbSession.Login(); Api fbApi = new Facebook.Rest.Api(fbSession); string xmlQueryResult = fbApi.Fql.Query("SELECT user_id FROM like WHERE object_id = " + video.FBVID); XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(new StringReader(xmlQueryResult)); int likesCount = xmlDoc.GetElementsByTagName("user_id").Count; //Write entry in VideoWallLikes if (likesCount > 0) { db.CountWallLikes(video.ID, likesCount); } fbSession.Logout(); } fbSession = null; }

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How can i test my TSQL syntax?

- by acidzombie24

Quick question: How do i get some kind of database to use to test my sql syntax and create basic data. I have Sqlite Code which i'll soon put on a server. I have sql server 2008 installed with visual studio 2010. I tried connecting to the database and had no luck. I also tried using a .mdf file instead thinking its a file and i wont have connectivity issues. Wrong, i still couldnt connect and i used this site to help me (i'm aware its 2005) In that case i used var conn = new SqlConnection(@"Server=.\SQLExpress;AttachDbFilename=C:\dev\src\test\SQL_DB_VS_Test\test.mdf;Database=dbo;Trusted_Connection=Yes;"); exception Unable to open the physical file "C:\dev\src\test\SQL_DB_VS_Test\test.mdf". Operating system error 5: "5(Access is denied.)". Cannot attach the file 'C:\dev\src\test\SQL_DB_VS_Test\test.mdf' as database 'dbo'. with trusted = no i get Login failed for user ''. (What user am i suppose to set...). I created the .mdf with visual studio somehow.

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Pipelining String in Powershell

- by ChvyVele

I'm trying to make a simple PowerShell function to have a Linux-style ssh command. Such as: ssh username@url I'm using plink to do this, and this is the function I have written: function ssh { param($usernameAndServer) $myArray = $usernameAndServer.Split("@") $myArray[0] | C:\plink.exe -ssh $myArray[1] } If entered correctly by the user, $myArray[0] is the username and $myArray[1] is the URL. Thus, it connects to the URL and when you're prompted for a username, the username is streamed in using the pipeline. Everything works perfectly, except the pipeline keeps feeding the username ($myArray[0]) and it is entered as the password over and over. Example: PS C:\Users\Mike> ssh xxxxx@yyyyy login as: xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyy's password: Access denied xxxxx@yyyyy's password: FATAL ERROR: Server sent disconnect message type 2 (protocol error): "Too many authentication failures for xxxxx" Where the username has been substituted with xxxxx and the URL has been substituted with yyyyy. Basically, I need to find out how to stop the script from piping in the username ($myArray[0]) after it has been entered once. Any ideas? I've looked all over the internet for a solution and haven't found anything.

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Selenium problem locating by DOM

- by bartonlee

Hi, I'm trying to use the DOM to locate a form element in Selenium but I can't get it to work. Even if I use the example in the Selenium documentation it still fails, for example with this html... <html> <body> <form id="loginForm"> <input name="username" type="text" /> <input name="password" type="password" /> <input name="continue" type="submit" value="Login" /> <input name="continue" type="button" value="Clear" /> </form> </body> <html> and this command in the Selenium IDE... verifyElementPresent with target... dom=document.forms['loginForm'] I get [error] false in the log. The 'getElementById' example in the documentation does work, but none of the others. Can someone explain what I'm doing wrong here? Thanks.

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passing info from facebook to UITabBarController

- by EquinoX

When my app first start, it shows up a main page showing to login to facebook and then it goes to the UITabBarController. The code that I have in my app delegate is the following: //this is the .h @interface NMeAppDelegate : NSObject <UIApplicationDelegate> { UIWindow *window; MainViewController *controller; UITabBarController *tabBar; } @property (nonatomic, retain) IBOutlet UITabBarController *tabBar; @property (nonatomic, retain) MainViewController *controller; @property (nonatomic, retain) IBOutlet UIWindow *window; @end //this is the .m of the app delegate #import "NMeAppDelegate.h" @implementation NMeAppDelegate @synthesize window; @synthesize tabBar; @synthesize controller; #pragma mark - #pragma mark Application lifecycle - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { // Override point for customization after application launch. controller = [[MainViewController alloc] init]; [window addSubview:tabBar.view]; [window addSubview:controller.view]; [window makeKeyAndVisible]; return YES; } Inside of MainViewController, I actually have a Facebook * facebook object, which basically has all of the information that I need. Every information that I need for this apps is queried in the MainViewController. The problem is that after getting this info and now I am in the UITabViewController... how do I get those information that I already queried facebook for? I have a class called UserInfo as well, which basically has everything essential I need. I need to have the info from UserInfo so that the other ViewController in the UITabBarController have access to it.... I hope my question makes sense

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Choosing between Facebook iframe scrollbar or page cut off halfway

- by pg.

I have an iframe tab in facebook. I used "overflow:hidden" in the body tag and this code at the bottom of my page: <div id="fb-root"></div> <script type="text/javascript"> window.fbAsyncInit = function() { FB.init({ appId : 'MY_APP_ID', status : true, // check login status cookie : true, // enable cookies to allow the server to access the session xfbml : true // parse XFBML }); FB.Canvas.setAutoResize(100); }; (function() { var e = document.createElement('script'); e.async = true; e.src = document.location.protocol + '//connect.facebook.net/en_US/all.js'; document.getElementById('fb-root').appendChild(e); }()); </script> This removes the scrollbars and resizes the iframe. The problem is that my page is cut off after about 800px (that leaves about 400px). I've set the height in facebook to "fluid". It works absolutely fine in every other browser but not in IE8. As a side question, why does IE still exist? It's the absolute worst thing. Anyways, I added this to the head:  But that just gets me back to having the scrollbars again.

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Trying to join two independent forms

- by user248959

Hi, i'm trying to join two independent forms (login and register) in the same page. My idea is (just looking at the signin form): Create an action that shows both forms (partials): public function executeLoginAndRegister(sfWebRequest $request){ $this->form_signin = $this->getUser()->getAttribute('form_signin'); } Each partial calls to its action: form action="php? echo url_for('@sf_guard_signin') ?" method="post" In the actions i write this code public function executeSignin($request) { //... $this->form = new $MyFormclass(); if ($this->form->isValid()) { //... }else{ // save the form to show the error messages. $this->getUser()->setAttribute('form_signin', $this->form); return $this->forward('sfGuardAuth', 'loginAndRegister'); } } It works, but, for example, if i execute LoginAndRegister and submit incorrectly the signin form and I go to another page and then return to LoginAndRegister, i will find the submiting error messages... If i execute LoginAndRegister and submit incorrectly the signin form and open another browser tab, i will find the submiting error messages in the signin form of the second tab... Any idea? any better approach?

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Aligning left and right in a simple footer

- by Wolfram

I'm currently working on a simple footer, and I would like to align one line of text left and the other to the right. This is what I have so far: <div id="footer"> Last Updated: October 15, 2012  Contact Us Login  </div> #footer { font-family: Arial; font-size: .9em; color: #24ACAE; border-top: 1px solid #24ACAE; margin-left: 90px; margin-right: 90px; padding-top: 5px; } The above code results in the two lines of text being next to each other and I've tried various ways of fixing this such as putting the the 2nd line in a span and aligning right and even putting the lines into a table. None of what I have tried has resulted in both lines being properly aligned. Using a margin-left alone does not work because when the first line is updated and becomes longer, it will push the second line downwards. Relative positioning seems to have the same issue. Hopefully there's something simple that I'm overlooking.

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i not find how in powershell pass through http autentification then use a webservices (lotus/domino)

- by user1716616

We have here a domino/lotus webservices i want use with powershell. probleme is in front of webservices lotus admin ask a http autentification. how i can use this webservice?? here what i tryed first scrap the first page and get cookie. $url = "http://xxxxxxx/names.nsf?Login" $CookieContainer = New-Object System.Net.CookieContainer $postData = "Username=web.services&Password=jesuisunestar" $buffer = [text.encoding]::ascii.getbytes($postData) [net.httpWebRequest] $req = [net.webRequest]::create($url) $req.method = "POST" $req.Accept = "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8" $req.Headers.Add("Accept-Language: en-US") $req.Headers.Add("Accept-Encoding: gzip,deflate") $req.Headers.Add("Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7") $req.AllowAutoRedirect = $false $req.ContentType = "application/x-www-form-urlencoded" $req.ContentLength = $buffer.length $req.TimeOut = 50000 $req.KeepAlive = $true $req.Headers.Add("Keep-Alive: 300"); $req.CookieContainer = $CookieContainer $reqst = $req.getRequestStream() $reqst.write($buffer, 0, $buffer.length) $reqst.flush() $reqst.close() [net.httpWebResponse] $res = $req.getResponse() $resst = $res.getResponseStream() $sr = new-object IO.StreamReader($resst) $result = $sr.ReadToEnd() this seem work but now no idea how i can use cookie with a webservicesproxy??? ps: i success have this to work with c# + visualstudio (just the class reference is autobuilt and i don't understand half of this but it allow me to use .CookieContenaire on the generated webservice )

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On android how would I go about creating a prompt for an app that requires a user to enter a username before fully launching the app?

- by racl101

I'll preface this with I'm really new to working on Android. So I have to work on an existing app and create a screen that prompts the user for a username if one isn't entered then it won't launch the currently existing main activity (i.e. it won't fully launch the app. Instead it will just sit on that screen until a username is entered.) I suppose that it's tantamount to a web app login page in that it will not let a user past that page if the user is not authenticated and authorized. However, there's no authentication nor authorization in this app. Instead, on first run a user must simply register with a username and that username gets saved to the database and for any subsequent runs the app's main activity will just start because a user has registered to that phone. In fact, the app will not prompt the user for their name again unless the app gets deleted with all its data and reinstalled again. This implicitly means that I have to save the user's name in the database or some other kind of storage. So I was wondering what would be the best way of doing this in an app with an existing main activity? Should I try to accomplish this on that existing main activity or create a new activity to display this prompt screen and, in effect, block the main activity from running until the user enters their name? Any tutorials or links would be helpful and thank you in advance for any help.

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Creating a Variable From Two Others

- by John

Hello, In the HTML table below, I would like to add a third column that equals $row["countSubmissions"] times 10 plus $row["countComments"]. How could I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY countSubmissions DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.stripslashes($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.stripslashes($row["countComments"]).'</td>'; echo '</tr>'; } echo "</table>";

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Relating text fields to check boxes in Java

- by Finzz

This program requires the user to login and request a database to access. The program then gets a connection object, searches through the database storing the column names into a vector for later use. The problem comes with implementing text fields to allow the user to search for specific values within the database. I can get the check boxes and text fields to appear using a gridlayout and add them to a panel. How do I relate the text fields to their appropriate check box? I've tried adding them to a vector, but then they can't also be added to the panel as well. I've searched for a way to name the text fields as the loop cycles through the column names, but it seems impossible to do without having them declared ahead of time. This can't be done either, as it's impossible to determine the attributes that the user will request. I just need to be able to know the names of the text fields so I can test to see if the user entered information and perform the necessary logic. Let me know if you have to see the rest of the code to give an answer, but hopefully you get the general idea of what I'm trying to accomplish. Picture of UI: try { ResultSet r2 = con.getMetaData().getColumns("", "", rb.getText(), ""); colNames1 = new Vector<String>(); columns1 = new Vector<JCheckBox>(); while (r2.next()) { colNames1.add(r2.getString(4)); JCheckBox cb = new JCheckBox(r2.getString(4)); JTextField tf = new JTextField(10); columns1.add(cb); p3.add(cb); p3.add(tf); } }

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How do I daemonize an arbitrary script in unix?

- by dreeves

I'd like a daemonizer that can turn an arbitrary, generic script or command into a daemon. There are two common cases I'd like to deal with: I have a script that should run forever. If it ever dies (or on reboot), restart it. Don't let there ever be two copies running at once (detect if a copy is already running and don't launch it in that case). I have a simple script or command line command that I'd like to keep executing repeatedly forever (with a short pause between runs). Again, don't allow two copies of the script to ever be running at once. Of course it's trivial to write a "while(true)" loop around the script in case 2 and then apply a solution for case 1, but a more general solution will just solve case 2 directly since that applies to the script in case 1 as well (you may just want a shorter or no pause if the script is not intended to ever die (of course if the script really does never die then the pause doesn't actually matter)). Note that the solution should not involve, say, adding file-locking code or PID recording to the existing scripts. More specifically, I'd like a program "daemonize" that I can run like % daemonize myscript arg1 arg2 or, for example, % daemonize 'echo `date` >> /tmp/times.txt' which would keep a growing list of dates appended to times.txt. (Note that if the argument(s) to daemonize is a script that runs forever as in case 1 above, then daemonize will still do the right thing, restarting it when necessary.) I could then put a command like above in my .login and/or cron it hourly or minutely (depending on how worried I was about it dying unexpectedly). NB: The daemonize script will need to remember the command string it is daemonizing so that if the same command string is daemonized again it does not launch a second copy. Also, the solution should ideally work on both OS X and linux but solutions for one or the other are welcome. (If I'm thinking of this all wrong or there are quick-and-dirty partial solutions, I'd love to hear that too.)

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How do I ignore an "invalid" SSL certificate in Objective-C?

- by ipwnstuff

Currently I have: NSArray* array = [NSArray arrayWithObjects:@"auth.login",@"username",@"password", nil]; NSData* packed_array = [array messagePack]; NSURL* url = [NSURL URLWithString:@"https://192.168.1.149:3790/api/1.0"]; NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"RPC Server" forHTTPHeaderField:@"Host"]; [request setValue:@"binary/message-pack" forHTTPHeaderField:@"Content-Type"]; [request setValue:[NSString stringWithFormat:@"%d",[packed_array length]] forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:packed_array]; NSURLResponse *response; NSError *error; responseData = [NSMutableData dataWithData:[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]]; NSLog(@"response data: %@",[responseData messagePackParse]); NSLog(@"error: %@",error); - (BOOL)connection:(NSURLConnection *)connection canAuthenticateAgainstProtectionSpace:(NSURLProtectionSpace *)protectionSpace { NSLog(@"called canAuthenticateAgainstProtectionSpace"); return [protectionSpace.authenticationMethod isEqualToString:NSURLAuthenticationMethodServerTrust]; } - (void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge { NSLog(@"called didReceiveAuthenticationChallenge"); [challenge.sender useCredential:[NSURLCredential credentialForTrust:challenge.protectionSpace.serverTrust] forAuthenticationChallenge:challenge]; } Which returns "Error Domain=NSURLErrorDomain Code=-1202 "The certificate for this server is invalid"…" How should I be implementing the answer from this question?

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How would I construct a terminal command to download a folder with wget from a Media Temple (gs) ser

- by racl101

I'm trying to download a folder using wget on the Terminal (I'm usin a Mac if that matters) because my ftp client sucks and keeps timing out. It doesn't stay connected for long. So I was wondering if I could use wget to connect via ftp protocol to the server to download the directory in question. I have searched around in the internet for this and have attempted to write the command but it keeps failing. So assuming the following: ftp username is: [email protected] ftp host is: ftp.s12345.gridserver.com ftp password is: somepassword I have tried to write the command in the following ways: wget -r ftp://[email protected]:[email protected]/path/to/desired/folder/ wget -r ftp://serveradmin:[email protected]/path/to/desired/folder/ When I try the first way I get this error: Bad port number. When I try the second way I get a little further but I get this error: Resolving s12345.gridserver.com... 71.46.226.79 Connecting to s12345.gridserver.com|71.46.226.79|:21... connected. Logging in as serveradmin ... Login incorrect. What could I be doing wrong?

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Icons in menu are smaller than they should be

- by martinpelant

Hello I have a little problem. All the icons in my apk are smaller than the same icons in other apps (Gmail etc.) This is how it looks like in my apk and this is the same icon in Gmail.apk. I have copied these icons directly from SDK to the specific folders for hdpi, mdpi and ldpi. Here is an example of a hdpi icon I use and my menu.xml <?xml version="1.0" encoding="utf-8"?> <menu xmlns:android="http://schemas.android.com/apk/res/android"> <item android:id="@+id/refresh" android:title="@string/refresh" android:icon="@drawable/ic_menu_refresh" /> <item android:id="@+id/add" android:title="@string/add" android:icon="@drawable/ic_menu_add" /> <item android:id="@+id/login" android:title="@string/account" android:icon="@drawable/ic_menu_login" /> </menu> Does anybody know how to make these icon have the same size as in other apk's? I have tried the asset studio with no effect. UPDATE: If I reference an icon directly from android (android:drawable) then it has normal size. However not all icons can be referenced.

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Assistance with CC Processing script

- by JM4

I am currently implementing a credit card processing script, most as provided by the merchant gateway. The code calls functions within a class and returns a string based on the response. The end php code I am using (details removed of course) with example information is: <?php $gw = new gwapi; $gw->setLogin("username", "password"); $gw->setBilling("John","Smith","Acme, Inc.","888","Suite 200", "Beverly Hills", "CA","77777","US","555-555-5555","555-555-5556","[email protected]", "www.example.com"); // "CA","90210","US","[email protected]"); $gw->setOrder("1234","Big Order",1, 2, "PO1234","65.192.14.10"); $r = $gw->doSale("1.00","4111111111111111","1010"); print $gw->responses['responsetext']; ?> where setlogin allows me to login, setbilling takes the sample consumer information, set order takes the order id and description, dosale takes the amount charged, cc number and exp date. when all the variables are sent validated then sent off for processing, a string is returned in the following format: response=1&responsetext=SUCCESS&authcode=123456&transactionid=23456&avsresponse=M&orderid=&type=sale&response_code=100 where: response = transaction approved or declined response text = textual response authcode = transaction authorization code transactionid = payment gateway tran id avsresponse = avs response code orderid = original order id passed in tran request response_code = numeric mapping of processor response I am trying to solve for the following: How do I take the data which is passed back and display it appropriately on the page - If the transaction failed or AVS code doesnt match my liking or something is wrong, an error is displayed to the consumer; if the transaction processed, they are taken to a completion page and the transaction id is sent in SESSION as output to the consumer If the response_code value matches a table of values, certain actions are taken, i.e. if code =100, take to success page, if code = 300 print specific error on original page to customer, etc.

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Replacing mysql user authentication with openid

- by David

So, I'm working with a really old system which uses a person's mysql database credentials to authenticate to a web site (the database was originally only accessed from the command line, but is now accessed from a php frontend). Because of some internal reasons (and to preserve the user's history), I have to leave the old authentication intact. I've been charged with adding openid authentication to this system. Somehow I need to be able to retrieve a users mysql username and password upon logging into the site through openid (using the Zend framework, by the way). I've thought of simply requiring registration at the first login, where the user must provide their mysql credentials, but I'd rather not store the password plain text. I've also considered blanking everyone's mysql passwords, and just setting the user's mysql username manually (rather than having the user provide this, since they could provide any username). This is turning into a security nightmare. Does anyone have any suggestions for alternatives? This is running on a Linux server, by the way. Also, I can't use mysql pluggable authentication because the mysql version is 5.0 (pluggable authentication requires mysql 5.5), and no, I can't update it.

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Use where clause with Like in codeigniter

- by user2524013

I am working on a project. I am implementing the Search functionality in my System. I will have to show the search record from two tables base on the current use login. I have tried the following code: function searchActivity($limit,$offset,$keyword1,$keyword2,$recruiter_id) { $q=$this->db->select('*')->from('tbl_activity')->limit($limit,$offset); $this->db->join('tbl_job', 'tbl_job.job_id = tbl_activity.job_id_fk', 'left outer'); $this->db->order_by("activity_id", "ASC"); $this->db->like('job_title',$keyword1,'both'); $this->db->or_like('job_title',$keyword2,'both'); $this->db->or_like('activity_subject',$keyword1,'both'); $this->db->or_like('activity_subject',$keyword2,'both'); $this->db->or_like('activity_details',$keyword1,'both'); $this->db->or_like('activity_details',$keyword2,'both'); $this->db->where('tbl_activity.recruiter_id_fk',$recruiter_id); $ret['rows']=$q->get()->result(); return $ret; } I want to show search results based on the current user id, which is currently store in $recruiter. Thanks in advance.

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jQuery replacement for Default Button or Link

- by pyccki

As everyone knows, that default button doesn't work in FF, only IE. I've tried to put in the tag or in the and it's not working. I've found a js script to fix this issue, but for some reason it's not working for me. This script for a submit button, i need to use it for a LinkButton, which is should be the same. Link: <div id="pnl"> <a id="ctl00_cphMain_lbLogin" title="Click Here to LogIn" href="javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions("ctl00$cphMain$lbLogin", "", true, "Login1", "", false, true))">Log In</a> <input name="ctl00$cphMain$UserName" type="text" id="ctl00_cphMain_UserName" /> <input name="ctl00$cphMain$UserName" type="text" id="ctl00_cphMain_UserName1" /> </div> <script> $(document).ready(function() { $("#pnl").keypress(function(e) { if ((e.which && e.which == 13) || (e.keyCode && e.keyCode == 13)) { $("a[id$='_lbLogin']").click(); return true; } }); }); I know that i can override original function "*WebForm_FireDefaultButton*" in This post, but i really wanted to get this one to work. Thanx in advance!!!

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