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  • Adding STI to Existing Table...

    - by keruilin
    I want to add STI to an existing table using a custom type column. Let's call this taste_type whose corresponding model is Fruit. In the Fruit model I have: set_inheritance_column :taste_type In my migration to add STI I have: class AddSTI < ActiveRecord::Migration def self.up add_column :fruits, :taste_type, :string, :limit => 100, :null => false Fruit.reset_column_information Fruit.find_by_id(1).update_attributes({:taste_type => 'Sour'}) end def self.down remove_column :fruits, :taste_type end end When I run the migration, I get the following error: Mysql::Error: Column 'taste_type' cannot be null: ... Any idea what's going? I can get the migration to run if I comment the set_inheritance_column in the Fruit model, then uncomment it after I run the migration. Obviously, I don't want to do this, however.

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  • Import Namespace System.Query

    - by GateKiller
    I am trying to load Linq on my .Net 3.5 enabled web server by adding the following to my .aspx page: <%@ Import Namespace="System.Query" %> However, this fails and tells me it cannot find the namespace. The type or namespace name 'Query' does not exist in the namespace 'System' I have also tried with no luck: System.Data.Linq System.Linq System.Xml.Linq I believe that .Net 3.5 is working because var hello = "Hello World" seems to work. Can anyone help please? Cheers, Stephen PS: I just want to clarify that I don't use Visual Studio, I simple have a Text Editor and write my code directly into .aspx files.

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  • Embedding a YouTube Video Based on a PHP Variable

    - by jeffpm
    I have a website that I am creating for a class project. The website shows information about bands (which is stored in a mysql database). I am trying to spruce up the site a bit, and I would like to embed a YouTube video based on the band's name. Say, for instance, I have "Led Zeppelin" stored in my database. How can I take a PHP variable containing "Led Zeppelin", search YouTube using that variable, find a random video, and then embed that in the website? From the research I've done, it seems you can only embed YouTube videos if you know the exact address of the video. Thanks!

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  • Optimizing a Soundex Query for finding similar names

    - by xkingpin
    My application will offer a list of suggestions for English names that "sound like" a given typed name. The query will need to be optimized and return results as quick as possible. Which option would be most optimal for returning results quickly. (Or your own suggestion if you have one) A. Generate the Soundex Hash and store it in the "Names" table then do something like the following: (This saves generating the soundex hash for at least every row in my db per query right?) select name from names where NameSoundex = Soundex('Ann') B. Use the Difference function (This must generate the soundex for every name in the table?) select name from names where Difference(name, 'Ann') = 3 C. Simple comparison select name from names where Soundex(name) = Soundex('Ann') Option A seems like to me it would be the fastest to return results because it only generates the Soundex for one string then compares to an indexed column "NameSoundex" Option B should give more results than option A because the name does not have to be an exact match of the soundex, but could be slower Assuming my table could contain millions of rows, what would yield the best results?

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  • Error Creating View From Importing MysqlDump

    - by Joshua
    I don't speak SQL... Please, anybody help me. What does this mean?: Error SQL query: /*!50001 CREATE ALGORITHM=UNDEFINED *//*!50001 VIEW `v_sr_videntity` AS select `t`.`c_id` AS `ID`,`User`.`c_id` AS `UserID`,`videntityfingerprint`.`ID` AS `VIdentityFingerPrintID`,`videntityfingerprint`.`FingerPrintID` AS `FingerPrintID`,`videntityfingerprint`.`FingerPrintFingerPrint` AS `FingerPrintFingerPrint` from ((`t_SR_u_Identity` `t` join `t_SR_u_User` `User` on((`User`.`c_r_Identity` = `t`.`c_id`))) join `vi_sr_videntity_0` `VIdentityFingerPrint` on((`videntityfingerprint`.`c_r_Identity` = `t`.`c_id`))) */; MySQL said: #1054 - Unknown column 'videntityfingerprint.ID' in 'field list' What does this mean? What is it expecting? How do I fix it? This file was created by mysqldump, so why are there errors when I import it?

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  • How to write a SQL query for numerous conditions with lots of fields in ASP.NET

    - by Yongwei Xing
    Hi all I have a ASP.NET site. There is a table in the SQL Server with more than 30 fields. I need make a page on which there are many filters to query data from database based on the filters you select or input. One filter for one fields in the database. The filter would be dropdown list, textbox,checkbox or listbox. If you do not choose one filter, it means select all for this field. So there are lots of combination for these fields. Is there any simple way to write such page and query for this requirement? Best Regards,

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  • DBnull in Linq query causing problems

    - by nat
    hi there i am doing a query thus: int numberInInterval = (from dsStatistics.J2RespondentRow item in jStats.J2Respondent where item.EndTime > dtIntervalLower && item.EndTime <= dtIntervalUpper select item).count(); there appear to be some dbnulls in the endtime column.. any way i can avoid these? tried adding && where item.endtime != null.. and even != dbnull.value do i have to do a second (first) query to grab all that arent null then run the above one? im sure its super simple fix, but im still missing it.. as per thanks nat

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  • Get multiple records with one query

    - by Lewy
    User table: name lastname Bob Presley Jamie Cox Lucy Bush Find users q = Query.new("Bob Presley, Cox, Lucy") q.find_users => {0=>{:name=>"Bob", :lastname=>"Presley"}, 1=>{:lastname=>"Cox"}, 2=>{:name=>"Lucy"}} Question: I've got hash with few names and lastnames. I need to build Activerecord query to fetch all users from that hash. I can do object = [] hash = q.find_users hash.each do |data| #check if data[:lastname] and data[:name] exist # object << User.where(:name => ..., :lastname => ...) end But I think it is higly inefficient. How should I do this ?

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  • How to add if statement in SQL ?

    - by shin
    I have a following MySQL with two parameters, $catname and $limit=1. And it is working fine. SELECT P.*, C.Name AS CatName FROM omc_product AS P LEFT JOIN omc_category AS C ON C.id = P.category_id WHERE C.Name = '$catname' AND p.status = 'active' ORDER BY RAND() LIMIT 0, $limit Now I want to add another parameter $order. $order can be either ODER BY RAND() or ORDER BY product_order in the table omc_product. Could anyone tell me how to write this query please? Thanks in advance.

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  • Entity-attribute-value model using codeigniter / php

    - by John Stewart
    SO I am trying to create a way to structure my database to be able customize forms. I looked into EAV pattern and here is my db structure: Table form - form_id - form_name - form_added_on - form_modified_at Table: form_fields - field_id - form_id - field_type (TEXT, RADIO etc..) - field_default_value - field_required Table: form_data - data_id - field_id - form_id - field_value so now I can store any custom form into the database and if I want to get the values for an individual form I can simply join it by "form_id" .. the problem: I want to be able to search through all the forms for a specific field value. How can I do that with EAV model? Also, I thought about just storing the custom data as a serialized (JSON) object but then I am not sure how can I query that data. Please note that I am using Codeigniter with MYSQL. So if conversation can use Codeigniter libraries if needed.

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  • SQL Server 2005 - query with case statement

    - by user329266
    Trying to put a single query together to be used eventually in a SQL Server 2005 report. I need to: Pull in all distinct records for values in the "eventid" column for a time frame - this seems to work. For each eventid referenced above, I need to search for all instances of the same eventid to see if there is another record with TaskName like 'review1%'. Again, this seems to work. This is where things get complicated: For each record where TaskName is like review1, I need to see if another record exists with the same eventid and where TaskName='End'. Utimately, I need a count of how many records have TaskName like 'review1%', and then how many have TaskName like 'review1%' AND TaskName='End'. I would think this could be accomplished by setting a new value for each record, and for the eventid, if a record exists with TaskName='End', set to 1, and if not, set to 0. The query below seems to accomplish item #1 above: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000'))) AS T WHERE seq = 1 order by eventid And the query below seems to accomplish #2: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 order by eventid This will bring back the eventid's that also have a TaskName='End': SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 and eventid in (Select eventid from eventrecords where TaskName = 'End') order by eventid So I've tried the following to TRY to accomplish #3: SELECT eventid, TimeStamp, TaskName, filepath FROM (SELECT eventid, TimeStamp, filepath, TaskName, ROW_NUMBER() OVER(PARTITION BY eventid ORDER BY TimeStamp DESC) AS seq FROM eventrecords where ((TimeStamp >= '2010-4-1 00:00:00.000') and (TimeStamp <= '2010-4-21 00:00:00.000')) and TaskName like 'Review1%') AS T WHERE seq = 1 and case when (eventid in (Select eventid from eventrecords where TaskName = 'End') then 1 else 0) as bit end order by eventid When I try to run this, I get: "Incorrect syntax near the keyword 'then'." Not sure what I'm doing wrong. Haven't seen any examples anywhere quite like this. I should mention that eventrecords has a primary key, but it doesn't seem to help anything when I include it, and I am not permitted to change the table. (ugh) I've received one suggestion to use a cursor and temporary table, but am not sure how badley that would bog down performance when the report is running. Thanks in advance.

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  • Hard to append a table with many records into another without generating duplicates

    - by Bill Mudry
    I may seem to be a bit wordy at first but for the hope it will be easier for all of you to understand what I am doing in the first place. I have an uncommon but enjoyable activity of collecting as many species of wood from around the world as I can (over 2,900 so far). Ok, that is the real world. Meanwhile I have spent over 8 years compiling over 5.8 meg of text data on all the woods of the world. That got so large that learning some basic PHP and MySQL was most welcome so I could build a new database driven home for all this research. I am still slow at it but getting there. The original premise was to find evidence of as many species of woods in the world I can. The more names identified, the more successful the project. I have named the project TAXA for ease of conversation (short for Taxonomy). You are most welcome to take a look at what I have so far at www.prowebcanada.com/taxa. It is 95% dynamically driven. So far I am reporting about 6,500 botanical wood names and, as said above, the more I can report, the more successful is the project. I have a file of all the woods in the second largest wood collection in the world, the Tervuren wood collection in the Netherlands with over 11,300 wood names even after cleaning out all duplicates. That is almost twice the number I am reporting now so porting all the new wood names from Tervuren to the 'species' table where I keep the reported data would be a major desirable advancement in the project. At one point I was able to add all the Tervuren records to the species table but over 3,000 duplicates also formed. They were not in the Tervuren file in the first place but represent the same wood names common to both files. It is common sense that there would be woods common to both that when merged would create new duplicates. At one point and with the help of others from another forum, I may very well have finally got the proper SQL statement. When I ran it, though, the system said (semi-amusingly at first) ----- that it had gone away! After looking up on the Net what could have have done this, one reason is that the MySQL timeout lapses and probably because of the large size of files I am running. I am running this on a rented account on Godaddy so I cannot go about trying to adjust any config file. For safety, I copied the tervuren.sql file as tervuren_target.sql and the species.sql file as species_master.sql tp use as working files just to make sure I protect the original files from destruction or damage. Later I can name the species_master back to just species.sql once I am happy all worked well. The species file has about 18 columns in it but only 5 columns match the columns in the Tervuren file (name for name and collation also). The rest of the columns are just along for the ride, so to speak. The common key in both is the 'species_name" columns in both. I am not sure it is at all proper to call one a primary key and the other a foreign key since there really is no relational connection to them. One is just more data for the other and can disappear after, never to be referred to the working code in the application. I have been very surprised and flabbergasted on how hard it can be to append records from one large table into another (with same column names plus others) without generating NEW duplicates in the first place. Watch out thinking that a SELECT DISTINCT statement may do the job because absolutely NO records in the species table must get destroyed in the process and there is no way (well, that I know of) to tell the 'DISTINCT" command this. Yes, the original 'species' table has duplicates in it even before all this but, trust me ---- they have to be removed the long hard way manually record by record or I will lose precious information. It is more important to just make sure no NEW duplicates form through bringing in new names in the tervuren_target.species_name into species.species_name. I am hoping and thinking that a straight SQL solution should work --- except for that nasty timeout. How do I get past that? Could it mean that I may have to turn to a PHP plus SQL method?? Or ..... would I have to break up the Tervuren files into a few smaller ones and run them independently (hope not....)" So far, what seems should be easy has proven to be unexpectedly tricky. I appreciate any help you can give but start from the assumption that this may be harder to do right than it may seem on the surface. By the way --- I am running a quad 64 bit system with Windows 7, so at least I have some fairly hefty power on the client end. I have a direct ethernet cable feeding a cable connection to the Internet. Once I get an algorithm and code working for this, I also have many other lists to process that could make the 'species' table grow even more. It could be equivalent to (ahem) lighting a rocket under my project (especially compared to do this record by record manually)! This is my first time in this forum, so I do not know how I can receive any replies. Do I have to to come back here periodically or are replies emailed out also? It would be great if you CC'd copies to me at billmudry at rogers.com :-) Much thanks for your patience and help, Bill Mudry Mississauga, Ontario Canada (next to Toronto).

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  • HQL query for entity with max value

    - by Rob
    I have a Hibernate entity that looks like this (accessors ommitted for brevity): @Entity @Table(name="FeatureList_Version") @SecondaryTable(name="FeatureList", pkJoinColumns=@PrimaryKeyJoinColumn(name="FeatureList_Key")) public class FeatureList implements Serializable { @Id @Column(name="FeatureList_Version_Key") private String key; @Column(name="Name",table="FeatureList") private String name; @Column(name="VERSION") private Integer version; } I want to craft an HQL query that retrieves the most up to date version of a FeatureList. The following query sort of works: Select f.name, max(f.version) from FeatureList f group by f.name The trouble is that won't populate the key field, which I need to contain the key of the record with the highest version number for the given FeatureList. If I add f.key in the select it won't work because it's not in the group by or an aggregate and if I put it in the group by the whole thing stops working and it just gives me every version as a separate entity. So, can anybody help?

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  • What frameworks to use to bootstrap my first production scala project ?

    - by Jacques René Mesrine
    I am making my first foray into scala for a production app. The app is currently packaged as a war file. My plan is to create a jar file of the scala compiled artifacts and add that into the lib folder for the war file. My enhancement is a mysql-backed app exposed via Jersey & will be integrated with a 3rd party site via HttpClient invocations. I know how to do this via plain java. But when doing it in scala, there are several decision points that I am pussyfooting on. scala 2.7.7 or 2.8 RC ? JDBC via querulous Is this API ready for production ? sbt vs maven. I am comfortable with maven. Is there a scala idiomatic wrapper for HttpClient (or should I use it just like in java) ? I'd love to hear your comments and experiences on starting out with scala. Thanks

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  • Determine Click-thru Percentage With PHP

    - by Lea
    Hi all, I am currently working on a small sponsorship application(PHP/MySql) for my personal blog, and am almost finish, but I am stuck on how to calculate the click-thru rate of my sponsors campaigns. I was always terrible with working out percentages, so any practical help would be appreciated. The data is stored in the DB as simple numbers.. So as expected, when a page refreshes, or a sponsors ad is clicked, the data updates with an incrementation of 1. So using these values...say $clicks and $impressions, how would I determine the click-thru rate? What would be the sum I would use to calculate? An example function would really be appreciated. Kind Regards, Lea

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  • Complicated idea - how to create car racing for my RPG game's players

    - by Donator
    So, I want to create car racing for my RPG game's players. Player can create race and choose how many participants can participate in race. After race is being created, other people can join it. When the maximum participants are collected, race begins. My idea, when the last participant joins, then instantly choose the winner (who's car is the best, that person wins), but how can I do it? If I choose to pick the winner after the last participant joins, then I have to put many queries in one page (select data from table, then delete the race, then select players' cars' statistics and pick the winner and then again, using mysql, send message to everyone). But this idea is really not optimal and it will lag cruelly for that last person. Maybe you have any ideas how I can avoid lag and make it more optimal. Thank you very much.

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  • Django: query with ManyToManyField count?

    - by AP257
    In Django, how do I construct a COUNT query for a ManyToManyField? My models are as follows, and I want to get all the people whose name starts with A and who are the lord or overlord of at least one Place, and order the results by name. class Manor(models.Model): lord = models.ManyToManyField(Person, null=True, related_name="lord") overlord = models.ManyToManyField(Person, null=True, related_name="overlord") class Person(models.Model): name = models.CharField(max_length=100) So my query should look something like this... but how do I construct the third line? people = Person.objects.filter( Q(name__istartswith='a'), Q(lord.count > 0) | Q(overlord.count > 0) # pseudocode ).order_by('name'))

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  • Nhibernate criteria query inserts an extra order by expression when using JoinType.LeftOuterJoin and Projections

    - by Aaron Palmer
    Why would this nhibernate criteria query produce the sql query below? return Session.CreateCriteria(typeof(FundingCategory), "fc") .CreateCriteria("FundingPrograms", "fp") .CreateCriteria("Projects", "p", JoinType.LeftOuterJoin) .Add(Restrictions.Disjunction() .Add(Restrictions.Eq("fp.Recipient.Id", recipientId)) .Add(Restrictions.Eq("p.Recipient.Id", recipientId)) ) .SetProjection(Projections.ProjectionList() .Add(Projections.GroupProperty("fc.Name"), "fcn") .Add(Projections.Sum("fp.ObligatedAmount"), "fpo") .Add(Projections.Sum("p.ObligatedAmount"), "po") ) .AddOrder(Order.Desc("fpo")) .AddOrder(Order.Desc("po")) .AddOrder(Order.Asc("fcn")) .List<object[]>(); SELECT this_.Name as y0_, sum(fp1_.ObligatedAmount) as y1_, sum(p2_.ObligatedAmount) as y2_ FROM fundingCategories this_ inner join fundingPrograms fp1_ on this_.fundingCategoryId = fp1_.fundingCategoryId left outer join projects p2_ on fp1_.fundingProgramId = p2_.fundingProgramId WHERE (fp1_.recipientId = 6 /* @p0 */ or p2_.recipientId = 6 /* @p1 */) GROUP BY this_.Name ORDER BY p2_.name asc, y1_ desc, y2_ desc, y0_ asc It is incorrectly putting the p2_name asc into the ORDER BY statement, and causing it to crash. This only happens when I use JoinType.LeftOuterJoin on my Projects criteria. Is this a known nhibernate bug? I'm using nhibernate 2.0.1.4000. Thanks for any insight.

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  • Grouping with operands question

    - by Filip
    I have a table: mysql> desc kursy_bid; +-----------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+-------+ | datetime | datetime | NO | PRI | NULL | | | currency | varchar(6) | NO | PRI | NULL | | | value | varchar(10) | YES | | NULL | | +-----------+-------------+------+-----+---------+-------+ 3 rows in set (0.01 sec) I would like to select some rows from a table, grouped by some time interval (can be one day) where I will have the first row and the last row of the group, the max(value) and min(value). I tried: select datetime, (select value order by datetime asc limit 1) open, (select value order by datetime desc limit 1) close, max(value), min(value) from kursy_bid_test where datetime > '2009-09-14 00:00:00' and currency = 'eurpln' group by month(datetime), day(datetime), hour(datetime); but the output is: | open | close | datetime | max(value) | min(value) | +--------+--------+---------------------+------------+------------+ | 1.4581 | 1.4581 | 2009-09-14 00:00:05 | 4.1712 | 1.4581 | | 1.4581 | 1.4581 | 2009-09-14 01:00:01 | 1.4581 | 1.4581 | As you see open and close is the same (but they shouldn't be). What should be the query to do what I want?

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  • ms-access: DB engine cannot find input table or query

    - by every_answer_gets_a_point
    here's the query: SELECT * FROM (SELECT [Occurrence Number], [Occurrence Date], [1 0 Preanalytical (Before Testing)], [Cup Type], NULL as [2 0 Analytical (Testing Phase)], [2 0 Area], NULL as [3 0 Postanalytical ( After Testing)],NULL as [4 0 Other], [Practice Code], [Specimen ID #] FROM [Lab Occurrence Form] WHERE NOT ([1 0 Preanalytical (Before Testing)] IS NULL) UNION SELECT [Occurrence Number], [Occurrence Date],NULL, [Cup Type],[2 0 Analytical (Testing Phase)], [2 0 Area], NULL,NULL, [Practice Code], [Specimen ID #] FROM [Lab Occurrence Form] WHERE NOT ([2 0 Analytical (Testing Phase)] IS NULL) UNION SELECT [Occurrence Number], [Occurrence Date],NULL, [Cup Type],NULL, [2 0 Area], [3 0 Postanalytical ( After Testing)],NULL, [Practice Code], [Specimen ID #] FROM [Lab Occurrence Form] WHERE NOT ([3 0 Postanalytical ( After Testing)] IS NULL) UNION SELECT [Occurrence Number], [Occurrence Date],NULL, [Cup Type],NULL, [2 0 Area], NULL, [4 0 Other] FROM [Lab Occurrence Form], [Practice Code], [Specimen ID #] WHERE NOT ([4 0 Other] IS NULL) ) AS mySubQuery ORDER BY mySubQuery.[Occurrence Number]; for some reason it doesnt like [Practice Code]. it's definitely a column in the table so i dont understand the problem. the error is the microsoft office access database engine cannot find the input table or query 'Practice Code'........

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  • can't login to phpmyadmin

    - by user574383
    Hi, i am new at linux but i need phpmyadmin on my centos server. I did this: cd /var/www/html/ (document root of apache) wget http://sourceforge.net/projects/phpmyadmin/path/to/latest/version tar xvfz phpMyAdmin-3.3.9-all-languages.tar.gz mv phpMyAdmin-3.3.9-all-languages phpmyadmin rm phpMyAdmin-3.3.9-all-languages.tar.gz cd phpmyadmin/ cp config.sample.inc.php config.inc.php Ok so then i just got to a webbrowser and go to www.$ip/phpmyadmin and i am presented with a login screen asking for username and password. How can i get these credentials to log in? I'd like to log in as root i guess. But i don't know how to setup a root account and create a password for root using the cli and mysql. Please help? Thanks.

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  • Lexing partial SQL in C#

    - by Chris T
    I'd need to parse partial SQL queries (it's for a SQL injection auditing tool). For example '1' AND 1=1-- Should break down into tokens like [0] => [SQL_STRING, '1'] [1] => [SQL_AND] [2] => [SQL_INT, 1] [3] => [SQL_AND] [4] => [SQL_INT, 1] [5] => [SQL_COMMENT] [6] => [SQL_QUERY_END] Are their any at least lexers for SQL that I base mine off of or any good tools like bison for C# (though I'd rather not write my own grammar as I need to support most if not all the grammar of MySQL 5)

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  • sql query question

    - by bu0489
    hey guys, just having a bit of difficulty with a query, i'm trying to figure out how to show the most popular naturopath that has been visited in a centre. My tables look as follows; Patient(patientId, name, gender, DoB, address, state,postcode, homePhone, businessPhone, maritalStatus, occupation, duration,unit, race, registrationDate , GPNo, NaturopathNo) and Naturopath (NaturopathNo, name, contactNo, officeStartTime, officeEndTime, emailAddress) now to query this i've come up with SELECT count(*), naturopathno FROM dbf10.patient WHERE naturopathno != 'NULL' GROUP BY naturopathno; which results in; COUNT(*) NATUROPATH 2 NP5 1 NP6 3 NP2 1 NP1 2 NP3 1 NP7 2 NP8 My question is, how would I go about selecting the highest count from this list, and printing that value with the naturopaths name? Any suggestions are very welcome, Brad

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  • Select count / duplicates

    - by mike
    Hello! I have a table with all U.S. zip codes. each row contains the city and state name for the zip code. I'm trying to get a list of cities that show up in multiple states. This wouldn't be a problem if there weren't X amount of zip codes in the same city... So basically, I just want to the city in a state to count as 1 instead of it counting the city/state 7 times because there are 2+ zip codes in that city/state... I'm not really sure how to do this. I know I need to use count but how do I tell the mysql to only count a given city/state combo as 1?

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