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  • how escape quotes when inserting into database in PHP

    - by Mauro74
    Hi all, I'm quite new to PHP so sorry if sounds such an easy problem... :) I'm having an error message when inserting content which contains quotes into my db. here's what I tried trying to escape the quotes but didn't work: $con = mysql_connect("localhost","xxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("test", $con); $nowdate = date('d-m-Y') $title = sprintf($_POST[title], mysql_real_escape_string($_POST[title])); $body = sprintf($_POST[body], mysql_real_escape_string($_POST[body])); $sql="INSERT INTO articles (title, body, date) VALUES ('$title','$body','$nowdate'),"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); Could you provide any solution please? Thanks in advance. Mauro

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  • Lightweight multi os monitoring plateform

    - by user293995
    Hi, I have a project where the is windows, freebsd and linux servers. I have to monitor some services : mysql replication status www status status with regexp on a webpage space on disk Is there open source software to do this and rapid to deploy ? Thanks in advance Best regards

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  • Adding STI to Existing Table...

    - by keruilin
    I want to add STI to an existing table using a custom type column. Let's call this taste_type whose corresponding model is Fruit. In the Fruit model I have: set_inheritance_column :taste_type In my migration to add STI I have: class AddSTI < ActiveRecord::Migration def self.up add_column :fruits, :taste_type, :string, :limit => 100, :null => false Fruit.reset_column_information Fruit.find_by_id(1).update_attributes({:taste_type => 'Sour'}) end def self.down remove_column :fruits, :taste_type end end When I run the migration, I get the following error: Mysql::Error: Column 'taste_type' cannot be null: ... Any idea what's going? I can get the migration to run if I comment the set_inheritance_column in the Fruit model, then uncomment it after I run the migration. Obviously, I don't want to do this, however.

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  • Frequency Table by user in SQL

    - by Roberto
    Very basic SQL question (DB is MySQL): I want a table of number of transactions by users. User ID Transaction count 1 43 2 213 3 0 4 23 5 0 In a table I have the two relevant records (user_id and buy_count). How could I get the table I want? Thanks, Roberto

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  • PHP vs Phpmyadmin

    - by user330306
    Hi there, I've got this code which i execute on phpmyadmin which works 100% Create Temporary Table Searches ( id int, dt datetime); Create Temporary Table Searches1 ( id int, dt datetime, count int); insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; insert into Searches1(id, dt, count) select b.savedSearchesId, (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', count(b.savedSearchesId) as 'cnt' from tblSavedSearchesDetails b group by b.savedSearchesId; insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); update tblSavedSearchResults inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id Set tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; However when i put the same code in php as below it generates an error $dba = DbConnect::CreateDbaInstance(); $query = ""; $query.="Create Temporary Table Searches ( id int, dt datetime); "; $query.="Create Temporary Table Searches1 ( id int, dt datetime, count int); "; $query.="insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; "; $query.="insert into Searches1(id, dt, count) "; $query.="select "; $query.=" b.savedSearchesId, "; $query.=" (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', "; $query.=" count(b.savedSearchesId) as 'cnt' "; $query.="from tblSavedSearchesDetails b "; $query.="group by b.savedSearchesId; "; $query.="insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) "; $query.="select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); "; $query.="update tblSavedSearchResults "; $query.="inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id "; $query.="Set tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; "; $dba->DbQuery($query) or die(mysql_error()); I get the following error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Create Temporary Table Searches1 ( id int, dt datetime, count int) insert into S' at line 1 Please if someone could assist me with this ... Thanks

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  • PHP URL Security Question

    - by TaG
    I want to have users store the url in my database I'm using php mysql and htmlpurifier I was wondering if the following code was good way to filter out bad data? Here is the Partial PHP code. $url = mysqli_real_escape_string($mysqli, $purifier->purify(htmlspecialchars(strip_tags($_POST['url'])));

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  • SQL GUI Programs

    - by jake
    Are there any programs with a gui which let you create a SQL database, create tables, define the primary and foreign keys and insert data? I am tired of having to use the mysql command line client, very tedious.

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  • why this left join query failed to load all the data in left table ?

    - by lzyy
    users table +-----+-----------+ | id | username | +-----+-----------+ | 1 | tom | | 2 | jelly | | 3 | foo | | 4 | bar | +-----+-----------+ groups table +----+---------+-----------------------------+ | id | user_id | title | +----+---------+-----------------------------+ | 2 | 1 | title 1 | | 4 | 1 | title 2 | +----+---------+-----------------------------+ the query SELECT users.username,users.id,count(groups.title) as group_count FROM users LEFT JOIN groups ON users.id = groups.user_id result +----------+----+-------------+ | username | id | group_count | +----------+----+-------------+ | tom | 1 | 2 | +----------+----+-------------+ where is the rest users' info? the result is the same as inner join , shouldn't left join return all left table's data? PS:I'm using mysql

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  • date() is showing December 1969

    - by Doug
    $sql = "SELECT * FROM news ORDER BY `news_id` DESC LIMIT 1"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_assoc($result); $date = $row['time_posted']; echo "<i> " .date("Y/m/d", $date) . "</i>: "; I used timestamp in mysql. So, what's the problem?

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  • ORDER BY letters and not numbers of a field

    - by Jon
    Is there a way to order mysql results by the first letter and ignore numbers? For example, I have a list of addresses: 123 Main Street 456 Second Street 234 Third Street and I want to order by the street name and ignore the street number. Is there an easy way to do this?

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  • creating a primary key format

    - by ryn6
    how do i create a primary key for an account with a format like this: ABC-123 ABC-124 ABC-125 another example: BCA-111 BCA-112 BCA-113 and so on. by the way im using mysql.is it possible to do auto increment when using this format?

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  • Pound symbol not displaying on web page

    - by Gublooo
    Hello I have a mysql database table to store country name and currency symbol - the CHARSET has correctly set to UTF8. This is example data inserted into the table insert into country ( country_name, currency_name, currency_code, currency_symbol) values ('UK','Pounds','GBP','£'); When I look in the database - the pound symbol appears fine - but when I retrieve it from the database and display it on the website - a weird square symbol shows up with a question mark inside instead of the pound symbol. You can look at it here - http://www.didyouswipe.com/profile/view-profile/user_id/181 Please advice Thanks

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  • Making Browser Auto-Scroll to Most Recently Submitted Comment.

    - by John
    Hello, I made a comment on a Wordpress blog and I noticed that after I submitted the comment, the top of the browser was flush with the top of my comment. In other words, the web page was auto-scrolled down to the top of my comment. How can I do this? I am using a comment system with PHP / MySQL. Thanks in advance, John

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  • derby + hibernate ConstraintViolationException using manytomany relationships

    - by user364470
    Hi, I'm new to Hibernate+Derby... I've seen this issue mentioned throughout the google, but have not seen a proper resolution. This following code works fine with mysql, but when I try this on derby i get exceptions: ( each Tag has two sets of files and vise-versa - manytomany) Tags.java @Entity @Table(name="TAGS") public class Tags implements Serializable { @Id @GeneratedValue(strategy=GenerationType.AUTO) public long getId() { return id; } @ManyToMany(targetEntity=Files.class ) @ForeignKey(name="USER_TAGS_FILES",inverseName="USER_FILES_TAGS") @JoinTable(name="USERTAGS_FILES", joinColumns=@JoinColumn(name="TAGS_ID"), inverseJoinColumns=@JoinColumn(name="FILES_ID")) public Set<data.Files> getUserFiles() { return userFiles; } @ManyToMany(mappedBy="autoTags", targetEntity=data.Files.class) public Set<data.Files> getAutoFiles() { return autoFiles; } Files.java @Entity @Table(name="FILES") public class Files implements Serializable { @Id @GeneratedValue(strategy=GenerationType.AUTO) public long getId() { return id; } @ManyToMany(mappedBy="userFiles", targetEntity=data.Tags.class) public Set getUserTags() { return userTags; } @ManyToMany(targetEntity=Tags.class ) @ForeignKey(name="AUTO_FILES_TAGS",inverseName="AUTO_TAGS_FILES") @JoinTable(name="AUTOTAGS_FILES", joinColumns=@JoinColumn(name="FILES_ID"), inverseJoinColumns=@JoinColumn(name="TAGS_ID")) public Set getAutoTags() { return autoTags; } I add some data to the DB, but when running over Derby these exception turn up (the don't using mysql) Exceptions SEVERE: DELETE on table 'FILES' caused a violation of foreign key constraint 'USER_FILES_TAGS' for key (3). The statement has been rolled back. Jun 10, 2010 9:49:52 AM org.hibernate.event.def.AbstractFlushingEventListener performExecutions SEVERE: Could not synchronize database state with session org.hibernate.exception.ConstraintViolationException: could not delete: [data.Files#3] at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:96) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66) at org.hibernate.persister.entity.AbstractEntityPersister.delete(AbstractEntityPersister.java:2712) at org.hibernate.persister.entity.AbstractEntityPersister.delete(AbstractEntityPersister.java:2895) at org.hibernate.action.EntityDeleteAction.execute(EntityDeleteAction.java:97) at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:268) at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:260) at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:184) at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:321) at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:51) at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1206) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:613) at org.hibernate.context.ThreadLocalSessionContext$TransactionProtectionWrapper.invoke(ThreadLocalSessionContext.java:344) at $Proxy13.flush(Unknown Source) at data.HibernateORM.removeFile(HibernateORM.java:285) at data.DataImp.removeFile(DataImp.java:195) at booting.DemoBootForTestUntilTestClassesExist.main(DemoBootForTestUntilTestClassesExist.java:62) I have never used derby before so maybe there is something crutal that i'm missing 1) what am I doing wrong? 2) is there any way of cascading properly when I have 2 many-to-many relationships between two classes? Thanks!

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  • ignoring saturday and sunday

    - by bsandrabr
    I am pulling in all the records from my customer database(mysql) for the last ten days $offset1 =strtotime("-10 day"); $date3=date("Y-m-d",$offset1); SELECT * FROM customers WHERE date between '$date3' and '$date' AND customer.custid = '$custid' ORDER by date DESC I would like to leave out the dates falling on a saturday or sunday and would like to put this in my query rather than the php If you can help thanks

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  • distributed system programming with php

    - by ranganaMIT
    Hi guys, I'm doing a system for a hospital in my country as the final year project of my degree, my supervisor specially asked me to use php and mysql for this. i don't have any experience with distributed systems and php programming, can any one help me out to build my base and improove my knowledge stating some sites, books to refer to overcome this matter. regards, rangana.

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  • how to send JSON data with server error response code 500

    - by kapil.israni
    I wanted to know if theres a way to send a JSON data along with HTTP response code 500. Basically I want my rest client to know that there is some error on the backend and along with it send a JSON error data structure like this. {"error" : [ {"code": "1001", "desc": "Some error description"}, {"code": "1002", "desc": "Some other error description"} ] } This is using the following java stack = Java 6/JAX-RS/Jersey/Tomcat If not, then is there a way to send a custom response code along with JSON data. Basically looking from JAX-RS API it looks that you can only send JSON data along with 200 OK?? Any thoughts?? I am guessing RESTEasy would be the same, right??

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