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  • Creating Actions from UIActionSheets help

    - by user337174
    I am using two UIAction sheets within my current project. I can get one to work perfectly fine but when i insert a second action sheet it runs the same arguements as the first. How do i define the actionsheets seperatly? -(IBAction) phoneButtonClicked:(id)sender { // open a dialog with just an OK button UIActionSheet *actionSheet = [[UIActionSheet alloc] initWithTitle:nil delegate:self cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:[NSString stringWithFormat:@"Phone: %@",phone],nil]; actionSheet.actionSheetStyle = UIActionSheetStyleDefault; [actionSheet showInView:self.view]; // show from our table view (pops up in the middle of the table) [actionSheet release]; } -(IBAction) mapButtonClicked:(id)sender { // open a dialog with just an OK button UIActionSheet *mapActionSheet = [[UIActionSheet alloc] initWithTitle:nil delegate:self cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:[NSString stringWithFormat:@"Map"],nil]; mapActionSheet.actionSheetStyle = UIActionSheetStyleDefault; [mapActionSheet showInView:self.view]; // show from our table view (pops up in the middle of the table) [mapActionSheet release]; } -(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex { if(buttonIndex == 0){ NSString *callPhone = [NSString stringWithFormat:@"tel:%@",phone]; NSLog(@"Calling: %@", callPhone); [[UIApplication sharedApplication] openURL:[NSURL URLWithString:callPhone]]; } }

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  • Wrapping an additional element around an existing XDocument

    - by user1382827
    Let's say I have a converted HTML document, and I wanted to wrap an extra tag around the parent, so that I could read the head and body. How would I do that with C#? The file is used as an XDocument. change <html> <head> <!-- data --> </head> <body> <!-- data --> </body> </html> to <open> <html> <head> <!-- data --> </head> <body> <!-- data --> </body> </html> </open>

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  • jsf, richfaces, popup window

    - by Hubidubi
    Hi I would like to make a list-detail view with richfaces. There will be a link for every record in the list that should open a new window containing record details. I tried to implement the link this way: <a4j:commandLink oncomplete="window.open('/pages/serviceDetail.jsf','popupWindow', 'dependent=yes, menubar=no, toolbar=no, height=500, width=400')" actionListener="#{monitoringBean.recordDetail}" value="details" /> I use <a4j:keepAlive beanName="monitoringBean" ajaxOnly="false" /> for both the list and the detail page. recordDetail method fills the data of the selected record to a variable of the bean that I would like to display on the detail page. The problem is that keepalive doesn't work, so I get new bean instance on the detail page every time. So the the previously selected record from the other bean is not accessible here. Is there a way to pass parameter (id) to the detail page to handle record selection. Or is there any way to make keepalive work? (I this this would be the easiest). Thanks

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  • how to append a string to next line in perl

    - by tprayush
    hi all , i have a requirement like this.. this just a sample script... $ cat test.sh #!/bin/bash perl -e ' open(IN,"addrss"); open(out,">>addrss"); @newval; while (<IN>) { @col_val=split(/:/); if ($.==1) { for($i=0;$i<=$#col_val;$i++) { print("Enter value for $col_val[$i] : "); chop($newval[$i]=<STDIN>); } $str=join(":"); $_="$str" print OUT; } else { exit 0; } } close(IN); close(OUT); ' when i run this scipt... $ ./test.sh Enter value for NAME : abc Enter value for ADDRESS : asff35 Enter value for STATE : XYZ Enter value for CITY : EIDHFF Enter value for CONTACT : 234656758 $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758 when ran it second time $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758ioret:56fgdh:ghdgh:afdfg:987643221 ## it is appended in the same line... i want it to be added to the next line..... NOTE: i want to do this by explitly using the filehandles in perl....and not with redirection operators in shell. please help me!!!

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  • How to move point on arc?

    - by bbZ
    I am writing an app that is simulating RobotArm movement. What I want to achieve, and where I have couple of problems is moving a Point on arc (180degree) that is arm range of movement. I am moving an arm by grabbing with mouse end of arm (Elbow, the Point I was talking about), robot can have multiple arms with diffrent arm lenghts. If u can help me with this part, I'd be grateful. This is what I have so far, drawing function: public void draw(Graphics graph) { Graphics2D g2d = (Graphics2D) graph.create(); graph.setColor(color); graph.fillOval(location.x - 4, location.y - 4, point.width, point.height); //Draws elbow if (parentLocation != null) { graph.setColor(Color.black); graph.drawLine(location.x, location.y, parentLocation.x, parentLocation.y); //Connects to parent if (arc == null) { angle = new Double(90 - getAngle(parentInitLocation)); arc = new Arc2D.Double(parentLocation.x - (parentDistance * 2 / 2), parentLocation.y - (parentDistance * 2 / 2), parentDistance * 2, parentDistance * 2, 90 - getAngle(parentInitLocation), 180, Arc2D.OPEN); //Draws an arc if not drawed yet. } else if (angle != null) //if parent is moved, angle is moved also { arc = new Arc2D.Double(parentLocation.x - (parentDistance * 2 / 2), parentLocation.y - (parentDistance * 2 / 2), parentDistance * 2, parentDistance * 2, angle, 180, Arc2D.OPEN); } g2d.draw(arc); } if (spacePanel.getElbows().size() > level + 1) {//updates all childElbows position updateChild(graph); } } I just do not know how to prevent moving Point moving outside of arc line. It can not be inside or outside arc, just on it. Here I wanted to put a screenshot, sadly I don't have enough rep. Am I allowed to put link to this? Maybe you got other ways how to achieve this kind of thing. Here is the image: Red circle is actual state, and green one is what I want to do. EDIT2: As requested, repo link: https://github.com/dspoko/RobotArm

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  • Labels aren't shown properly in combo box

    - by Vishal
    The below code show the labels from previously selected list any ideas? Steps to reproduce: Click on List AB Open the list but don't select / click any item Now click on List CD Open the list again and you see A, B as labels instead of C,D but if you click on any item then everything comes properly <mx:Script> <![CDATA[ import mx.collections.ArrayCollection; public var ab:ArrayCollection=new ArrayCollection([{label: A, data: 1}, {label: B, data: 2}]); public var cd:ArrayCollection=new ArrayCollection([{label: C, data: 3}, {label: D, data: 4}]); private function abClick(event:Event):void { cb.dataProvider=ab; } private function cdClick(event:Event):void { cb.dataProvider=cd; } ]]> </mx:Script> <mx:Panel title="ComboBox Control Example" height="75%" width="75%" layout="horizontal" paddingTop="10" paddingBottom="10" paddingLeft="10" paddingRight="10"> <mx:ComboBox id="cb" width="150"/> <mx:Button label="List AB" click="abClick(event);"/> <mx:Button label="List CD" click="cdClick(event);"/> </mx:Panel>

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  • How to use WebSockets refresh multi-window for play framework 1.2.7

    - by user2468652
    My code can work.But only refresh a page of one window. If I open window1 and window2 , both open websocket connect. I keyin word "test123" in window1, click sendbutton. Only refresh window1. How to refresh window1 and window2 ? Client <script> window.onload = function() { document.getElementById('sendbutton').addEventListener('click', sendMessage,false); document.getElementById('connectbutton').addEventListener('click', connect, false); } function writeStatus(message) { var html = document.createElement("div"); html.setAttribute('class', 'message'); html.innerHTML = message; document.getElementById("status").appendChild(html); } function connect() { ws = new WebSocket("ws://localhost:9000/ws?name=test"); ws.onopen = function(evt) { writeStatus("connected"); } ws.onmessage = function(evt) { writeStatus("response: " + evt.data); } } function sendMessage() { ws.send(document.getElementById('messagefield').value); } </script> </head> <body> <button id="connectbutton">Connect</button> <input type="text" id="messagefield"/> <button id="sendbutton">Send</button> <div id="status"></div> </body> Play Framework WebSocketController public class WebSocket extends WebSocketController { public static void test(String name) { while(inbound.isOpen()) { WebSocketEvent evt = await(inbound.nextEvent()); if(evt instanceof WebSocketFrame) { WebSocketFrame frame = (WebSocketFrame)evt; System.out.println("received: " + frame.getTextData()); if(!frame.isBinary()) { if(frame.getTextData().equals("quit")) { outbound.send("Bye!"); disconnect(); } else { outbound.send("Echo: %s", frame.getTextData()); } } } } } }

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  • Amazon Product API ResponseGroups and Default results

    - by aboxy
    A. In our application, most of the data we work with is stored as free text .i.e. there is no categorization done as of now. We are using openNLP libraries to make sense of the data(extract keywords/classify) and do a query to Amazon web services to pull the results of the query. We use searchindex=All and keywords=. Results are not always returned and we basically get 'AWS.ECommerceService.NoExactMatches' How to avoid that? 1) Is there a way to specify default results if no match found? e.g. Amazon carousel widget does that if the search query did not return results, it basically show some computer items. 2) Should I batch the request always and add another search criteria to every request? If my first criteria does not pull any results, we can be sure that our 2nd query will always pull results(possibly caching?) Here is one search criteria 'Open Circle Hoop Earrings Polished Stainless Steel Open Circle Hoop Earrings Polished Stainless Steel DiamondShark' This return no results via API. On Amazon site,I get alternative suggestions with some results which are pretty relevant. Is there a way to pull those results? B. We just need a thumbnail image and a title and description for our app. Which responseGroup is appropriate? We are using medium rt now but there is awful lot of information even with that responseGroup. Any help is appreciated. thanks

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  • mysql: storing arbitrary data

    - by Hailwood
    Background: I was asking a question on stack overflow regarding creating tables on the fly where this conversation ensued: This smells like a terrible idea! In fact, it smells just like this one. What in the world do you want to use this for? – deceze @deceze: very true, However, How else would you store the contents of these CSV files. They must be stored in mysql for indexing. The only solid fact about them is that they all have a mobile column with a standard format. The CSV can have an arbitrary amount of columns with an arbitrary amount of rows. They can (with no exaggeration) range from a single row, 35 column csv to an 80k row single column CSV. I am open to other ideas. – Hailwood There are many solutions for this, from attribute-value schemas to JSON storage and NoSQL storage. Open a new question about it. Whatever you do though, don't dynamically create tables! – deceze Question: So my question is, What would you say is the best way to store this data? Are you in agreement with deceze about not creating dynamic tables?

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  • Can't get gravity to work with RMagick and 'caption'

    - by mph
    I'm using RMagick 2.12.2 with ImageMagick 6.5.6-10 on Snow Leopard. I'm trying to put captions on a collection of photos, and I'm getting the caption to work (i.e. it appears on the image), but I can't get the gravity parameter to work correctly. No matter what I set it to, I end up with some variation on NorthGravity. For instance: Setting it to SouthWestGravity gives me NorthWestGravity. Setting it to SouthEastGravity gives me NorthEastGravity. Setting it to CenterGravity gives me NorthGravity. In other words, I can't get the caption to come down off the top of the image. I'd consider using "annotate," but I need "caption" so the lengthy caption text for each image will wrap. What am I doing wrong? Here's the code: #!/usr/bin/env ruby require "rubygems" require "yaml" require "RMagick" include Magick base_dir = "/Users/mike/Desktop/caption_test" photo_log = File.open("#{base_dir}/photo_log.yaml" ) YAML::load_documents(photo_log) do |doc| caption = doc["photo-caption"] filename = doc["file"] canvas = ImageList.new.from_blob(open("#{base_dir}/#{filename}") { |f| f.read } ) canvas << Magick::Image.read("caption:#{caption}") { self.gravity = SouthWestGravity self.size = "#{canvas.first.columns}" self.font = "Helvetica Neue" self.pointsize = 12 self.background_color = "#fff" }.first canvas.flatten_images.write("#{base_dir}/images/#{filename}") end

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  • Android XML Preference issue. Can't make it persistent

    - by Budius
    I have a very simple activity just to show the preference fragment: public class PreferencesActivity extends Activity { Fragment frag = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); FragmentTransaction ft = getFragmentManager().beginTransaction(); if (frag == null) { // If not, instantiate and add it to the activity frag = new PrefsFragment(); ft.add(android.R.id.content, frag, frag.getClass().getName()); } else { // If it exists, simply attach it in order to show it ft.attach(frag); } ft.commit(); } private static class PrefsFragment extends PreferenceFragment { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); addPreferencesFromResource(R.xml.preferences); } } } and preferences.xml with persistent to true: <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android" android:enabled="true" android:persistent="true" android:title="@string/settings" > <EditTextPreference android:dialogTitle="@string/dialog_ip" android:negativeButtonText="@android:string/cancel" android:persistent="true" android:positiveButtonText="@android:string/ok" android:title="@string/ip" /> </PreferenceScreen> if I open the EditTextPreference, write something, close the dialog and open it again. The value is still there. But that's it... if I click the Back button, and enter the again on the preferences screen, I already lost what was written. If you exit the application also doesn't save. Am I missing something here? Running on: Android 4.0.3 Asus TF300

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  • x86 Assembly: Before Making a System Call on Linux Should You Save All Registers?

    - by mudge
    I have the below code that opens up a file, reads it into a buffer and then closes the file. The close file system call requires that the file descriptor number be in the ebx register. The ebx register gets the file descriptor number before the read system call is made. My question is should I save the ebx register on the stack or somewhere before I make the read system call, (could int 80h trash the ebx register?). And then restore the ebx register for the close system call? Or is the code I have below fine and safe? I have run the below code and it works, I'm just not sure if it is generally considered good assembly practice or not because I don't save the ebx register before the int 80h read call. ;; open up the input file mov eax,5 ; open file system call number mov ebx,[esp+8] ; null terminated string file name, first command line parameter mov ecx,0o ; access type: O_RDONLY int 80h ; file handle or negative error number put in eax test eax,eax js Error ; test sign flag (SF) for negative number which signals error ;; read in the full input file mov ebx,eax ; assign input file descripter mov eax,3 ; read system call number mov ecx,InputBuff ; buffer to read into mov edx,INPUT_BUFF_LEN ; total bytes to read int 80h test eax,eax js Error ; if eax is negative then error jz Error ; if no bytes were read then error add eax,InputBuff ; add size of input to the begining of InputBuff location mov [InputEnd],eax ; assign address of end of input ;; close the input file ;; file descripter is already in ebx mov eax,6 ; close file system call number int 80h

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Javascript and jQuery (Fancybox) question

    - by songdogtech
    Javascript and jQuery (Fancybox) question I'm using the Javascript function below for Twitter sharing (as well as other services; the function code is simplified to just Twitter for this question) that grabs the to-be-shared page URL and title and it is invoked in the link with onclick. That results in the Twitter share page loading in a pop up browser window, i.e.<img src="/images/twitter_16.png" onclick="share.tw()" /> In order to be consistent with other design aspects of the site, what I'd like to be able to do is have the Twitter share page open not in a standard browser window but in a Fancybox (jQuery) window. Fancybox can load an external page in an iFrame when the img or href link contains a class (in this case class="iframe" ) in the link and in the document ready function in the header. Right now, of course, when I give the iframe class to the link that also has the onclick share.tw(), I get two popups: one browser window popup with the correct Twitter share page loaded, and a Fancybox jQuery popup that shows a site 404. How can I change the function to use Fancybox to present the Twitter share page? Is that a correct way to approach it? Or is there a better way, such as implementing the share function in jQuery, too? Thanks... Javascript share function: var share = { tw:function(title,url) { this.share('http://twitter.com/home?status=##URL##+##TITLE##',title,url); }, share:function(tpl,title,url) { if(!url) url = encodeURIComponent(window.location); if(!title) title = encodeURIComponent(document.title); tpl = tpl.replace("##URL##",url); tpl = tpl.replace("##TITLE##",title); window.open(tpl,"sharewindow"+tpl.substr(6,15),"width=640,height=480"); } }; It is invoked, i.e.: <img src="/images/twitter_16.png" onclick="share.tw()" /> Fancybox function, invoked by adding class="iframe" in the img or href link $(".iframe").fancybox({ 'width' : '100%', 'height' : '100%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' });

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  • Replacing a word in a text file with a value using python

    - by Jamde Jam
    I have been trying to replace a word in a text file with a value (say 1), but my outfile is blank.I am new to python (its only been a month since I have been learning it). My file is relatively large, but I just want to replace a word with the value 1 for now. Here is a segment of what the file looks like: NAME SECOND_1 ATOM 1 6 0 0 0 # ORB 1 ATOM 2 2 0 12/24 0 # ORB 2 ATOM 3 2 12/24 0 0 # ORB 2 ATOM 4 2 0 0 4/24 # ORB 3 ATOM 5 2 0 0 20/24 # ORB 3 ATOM 6 2 0 0 8/24 # ORB 3 ATOM 7 2 0 0 16/24 # ORB 3 ATOM 8 6 0 0 12/24 # ORB 1 ATOM 9 2 12/24 0 12/24 # ORB 2 ATOM 10 2 0 12/24 12/24 # ORB 2 #1 #2 #3 I want to first replace the word ATOM with the value 1. Next I want to replace #ORB with a space. Here is what I am trying thus far. input = open('SECOND_orbitsJ22.txt','r') output=open('SECOND_orbitsJ22_out.txt','w') for line in input: word=line.split(',') if(word[0]=='ATOM'): word[0]='1' output.write(','.join(word)) Can anyone offer any suggestions or help? Thanks so much.

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  • sql server mdf file database attachment

    - by jnsohnumr
    hello all i'm having a bear of a time getting visual studio 2010 (ultimate i think) to properly attach to my database. it was moved from original spot to #MYAPP#/#MYAPP#.Web/App_Data/#MDF_FILE#.mdf. I have three instances of sql server running on this machine. i have tried to replace the old mdf file with my new one and cannot get the connectionstring right for it. what i'm really wanting to do is to just open some DB instance, run a DB create script. Then I can have a DB that was generated via my edmx (generate database from model) in silverlight business application (c#) right now, when i go to server explorer in VS, choose add new connection, choose MS SQL Server Database FIle (SqlClient), choose my file location (app_data directory), use windows authentication, and hit the Test Connection button I get the following error: Unable to open the physical file "". Operating system error 5: "5(Access Denied.)". An attempt to attach to an auto-named database for file"" failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share. The mdf file was created on the same machine by connecting to (local) on the sql server management studio, getting a new query, pasting in the SQL from the generated ddl file, adding a CREATE DATABASE [NcrCarDatabase]; GO before the pasted SQL, and executing the query. I then disconnected from the DB in management studio, closed management studio, navigated to the DATA directory for that instance, and copying the mdf and ldf files to my application's app_data folder. I am then trying to connect to the same file inside visual studio. I hope that gives more clarity to my problems :). Connection string is: Data Source=.\SQLEXPRESS;AttachDbFilename=C:\SourceCode\NcrCarDatabase\NcrCarDatabase.Web\App_Data\NcrCarDatabase.mdf;Integrated Security=True;Connect Timeout=30;User Instance=True

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  • Rails problem with Delayed_Job and Active Record

    - by Michael Waxman
    I'm using Delayed_Job to grab a Twitter user's data from the API, but it's not saving it in the model for some reason! Please help! (code below) class BandJob < Struct.new(:band_id, :band_username) #parameter def perform require 'json' require 'open-uri' band = Band.find_by_id(band_id) t = JSON.parse(open("http://twitter.com/users/show/#{band_username}.json").read) band.screen_name = t['screen_name'] band.profile_background_image = t['profile_background_image_url'] band.url = 'http://' + band_username + '.com' band.save! end end To clarify, I'm actually not getting any errors, it's just not saving. Here's what my log looks like: * [JOB] acquiring lock on BandJob [4;36;1mDelayed::Job Update (3.1ms)[0m [0;1mUPDATE "delayed_jobs" SET locked_at = '2009-11-09 18:59:45', locked_by = 'host:dhcp128036151228.central.yale.edu pid:2864' WHERE (id = 10442 and (locked_at is null or locked_at < '2009-11-09 14:59:45') and (run_at <= '2009-11-09 18:59:45')) [0m [4;35;1mBand Load (1.5ms)[0m [0mSELECT * FROM "bands" WHERE ("bands"."id" = 34) LIMIT 1[0m [4;36;1mBand Update (0.6ms)[0m [0;1mUPDATE "bands" SET "updated_at" = '2009-11-09 18:59:45', "profile_background_image" = 'http://a3.twimg.com/profile_background_images/38193417/fbtile4.jpg', "url" = 'http://Coldplay.com', "screen_name" = 'coldplay' WHERE "id" = 34[0m [4;35;1mDelayed::Job Destroy (0.5ms)[0m [0mDELETE FROM "delayed_jobs" WHERE "id" = 10442[0m * [JOB] BandJob completed after 0.5448 1 jobs processed at 1.8011 j/s, 0 failed ... Thanks!

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  • Can I dispose a DataTable and still use its data later?

    - by Eduardo León
    Noob ADO.NET question: Can I do the following? Retrieve a DataTable somehow. Dispose it. Still use its data. (But not send it back to the database, or request the database to update it.) I have the following function, which is indirectly called by every WebMethod in a Web Service of mine: public static DataTable GetDataTable(string cmdText, SqlParameter[] parameters) { // Read the connection string from the web.config file. Configuration configuration = WebConfigurationManager.OpenWebConfiguration("/WSProveedores"); ConnectionStringSettings connectionString = configuration.ConnectionStrings.ConnectionStrings["..."]; SqlConnection connection = null; SqlCommand command = null; SqlParameterCollection parameterCollection = null; SqlDataAdapter dataAdapter = null; DataTable dataTable = null; try { // Open a connection to the database. connection = new SqlConnection(connectionString.ConnectionString); connection.Open(); // Specify the stored procedure call and its parameters. command = new SqlCommand(cmdText, connection); command.CommandType = CommandType.StoredProcedure; parameterCollection = command.Parameters; foreach (SqlParameter parameter in parameters) parameterCollection.Add(parameter); // Execute the stored procedure and retrieve the results in a table. dataAdapter = new SqlDataAdapter(command); dataTable = new DataTable(); dataAdapter.Fill(dataTable); } finally { if (connection != null) { if (command != null) { if (dataAdapter != null) { // Here the DataTable gets disposed. if (dataTable != null) dataTable.Dispose(); dataAdapter.Dispose(); } parameterCollection.Clear(); command.Dispose(); } if (connection.State != ConnectionState.Closed) connection.Close(); connection.Dispose(); } } // However, I still return the DataTable // as if nothing had happened. return dataTable; }

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • Google Maps API v3 - infoWindows all have same content

    - by paulriedel
    Hello, I've been having problems with the infoWindows and Google Maps API v3. Initially, I've ran into the problem that everyone else has of closing infoWindows when opening a new one. I thought to have solved the problem by defining "infowindow" beforehand. Now they close when I click on a new marker, but the content is the same. How should I re-structure my code to make sure the content is the right one each time - and only one infoWindow is open at a given time? Thank you! Paul var allLatLngs = new Array(); var last = 0; var infowindow; function displayResults(start, count){ if(start === undefined){ start = last; } if(count === undefined){ count = 20; } jQuery.each(jsresults, function(index, value) { if(index >= start && index < start+count){ var obj = jQuery.parseJSON(value); $("#textresults").append(index + ": <strong>" + obj.name + "</strong> " + Math.round(obj.distanz*100)/100 + " km entfernt" + "<br/>"); var myLatlng = new google.maps.LatLng(obj.geo_lat, obj.geo_lon); allLatLngs.push(myLatlng); var contentString = '<strong>'+obj.name+'</strong>'; infowindow = new google.maps.InfoWindow({ content: contentString }); var marker = new google.maps.Marker({ position: myLatlng, //title:"Hello World!" }); marker.setMap(map); google.maps.event.addListener(marker, 'click', function() { if (infowindow) { infowindow.close(map,marker); } infowindow.open(map,marker); }); } }); last = start+count;

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  • read contents of a xml file into a data grid view

    - by syedsaleemss
    Im using c# .net , windows form application. I have a XML file which contains two columns and some rows of data. now i have to fill this data into a data grid view. im using a button, when i click on the button an open dialog box will appear. i have to select the xml file name and when i click on open the contents of that xml file should come to the data grid view. i have tried with the following code: { XmlDataDocument xmlDatadoc=new XmlDataDocument(); XmlDatadoc.Dataset.ReadXml(filename); ds=xmlDatadoc.Dataset; datagridview1.DataSource=ds.DefaultViewManager; datagridview1.Datamember="language"; } My xml file is: <languages> <language> <key> key1</key> <value>value1</value> <language> <language> <key> key2</key> <value>value2</value> <language> </languages> Its working fine but only for "language" . I need it to work file other xml files also.

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  • jQuery panels - close one when opening another

    - by justme
    I have two slide panel in the same page. Need that, when one is open and the and user clicks on the other one, that makes, at the same time, close the first one when opening the second. Now they are overlapping... Can you help me, please? thanks This is what i have on the page: I have two slide panel in the same page. Need that, when one is open and the and user clicks on the other one, that makes, at the same time, close the first one when opening the second. Now they are overlapping... Can you help me, please? thanks This is what i have on the page <script type="text/javascript" src="jquery.js"></script> <script type="text/javascript"> $(document).ready(function(){ $(".btn-slide").click(function(){ $("#panel").slideToggle('fast'); $("#panel2").slideToggle("fast"); $(this).toggleClass("active"); }); }); $(document).ready(function(){ $(".btn-slide2").click(function(){ $("#panel2").slideUp('fast'); $("#panel").slideToggle("fast"); $(this).toggleClass("active"); }); </script>

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  • jquery dialog is clearing my form fields and I need to return a value from a jquery dialog

    - by Seth
    1.) I have a jQuery dialog that is opened whenever a particular textbox is focused. The dialog's contents are loaded from ajax and the unique ID of the textbox that was focused is passed in the ajax call (like this): $('[name=start_airport[]],[name=finish_airport[]]').click(function(){   var id = $(this).attr('id');   if($('#use_advanced_airport_selector').attr('checked')) {     $('#advanced_airport_selector').dialog({       open : function() {         $(this).load('/flight-booker/advanced-airport-selector.php?callerID='+id);       }     });     $('#advanced_airport_selector').dialog('open');   } }); (where advanced_airport_selector is an empty div) THAT PART WORKS FINE. However, when I make my ajax call within my dialog, all my form values are reset! No matter what I do, when that dialog opens, all form values are reset (not just the value of the textbox that was focused). I simply don't understand what would cause this behavior! But that's only issue #1. 2.) I need to be able to return a value from that dialog box. I am passing the ID in the ajax query so that I can use a jquery selector to update the caller's value after certain actions are performed within the dialog box. However, I can't actually access that textbox because of DOM_ERRORS that I've never come across. It doesn't make any sense! There's way to much code to post, and it's really hard to explain, so sorry if I'm unclear as to what I'm asking.

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  • file cretaed using exec could not be accessed immediately after creation?

    - by Holicreature
    HI I'm using exec in php to execute a command and it will create a .png file in a temp folder.. After creating that i'm trying to open that file and read contents and process them,, but i end up file could not read error.. I think the time taken by the exec to execute and create a file is the cause for the issue.. but i dont know how to fix it? i tried sleep() but it makes my script to run slow <?php error_reporting(E_ALL); extension_loaded('ffmpeg') or die('Error in loading ffmpeg'); //db connection codes $max_width = 120; $max_height = 72; $path ="/path/"; $qry="select id, input_file, output_file from videos where thumbnail='' or thumbnail is null;"; $res=mysql_query($qry); $cnt = 1; while($row = mysql_fetch_array($res,MYSQL_ASSOC)) { $outfile = $row[output_file]; $imgname = $cnt.".png"; $srcfile = "/path/".$outfile; echo "####$srcfile####"; exec("ffmpeg -i ".$srcfile." -r 1 -ss 00:00:05 -f image2 -s 120x72 ".$path.$imgname); $nname = "./temp/".$imgname; echo "nname===== $nname"; $fileo = fopen($nname,"rb"); if($fileo) { $imgData = addslashes(file_get_contents($nname)); .. ... .... } else echo "Could not open<br><br>"; $cnt = $cnt + 1: } ?>

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