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  • PHP & MySQL pagination display problem.

    - by TaG
    I asked a similar question like this yesterday but after waiting for ever I figured out part of the problem but now I'm stuck again I'm trying to display ... when the search results are to long because my pagination links will keep on displaying and will not stop until every link is displayed on the page. For example I'm trying to achieve the following in the example below. Can some one help me fix my code so I can update my site. Thanks This is what I want to be able to do. First Previous 1 2 ... 5 6 7 8 9 10 11 12 13 ... 199 200 Next Last Here is my pagination code that displays the links. $display = 20; if (isset($_GET['p']) && is_numeric($_GET['p'])) { $pages = $_GET['p']; } else { $q = "SELECT COUNT(id) FROM comments WHERE user_id=3"; $r = mysqli_query ($mysqli, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); $row = mysqli_fetch_array ($r, MYSQLI_NUM); $records = $row[0]; if ($records > $display) { $pages = ceil ($records/$display); } else { $pages = 1; } } if (isset($_GET['s']) && is_numeric($_GET['s'])) { $start = $_GET['s']; } else { $start = 0; } //content goes here if ($pages > 1) { echo '<br /><p>'; $current_page = ($start/$display) + 1; if ($current_page != 1) { echo '<a href="index.php">First</a>'; } if ($current_page != 1) { echo '<a href="index.php?s=' . ($start - $display) . '&p=' . $pages . '">Previous</a> '; } for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="index.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '">' . $i . '</a> '; } else { echo '<span>' . $i . '</span> '; } } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($start + $display) . '&p=' . $pages . '">Next</a>'; } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($pages - 1) . '&p=' . $pages . '">Last</a>'; } echo '</p>'; }

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  • No Method Error in Ruby

    - by JayG
    Hi, I currently have a Rails Apps that lets users drag and drop certain elements of the webpage and updates the application based on the users choice. This is done with the help of the Rails helpers and AJAX. However I keep running into a "NoMethodError" in Ruby. NoMethodError in ProjectsController#member_change undefined method `symbolize_keys' for nil:NilClass Here is the method that is being called. My trace says that error is occurring in this line: before = u.functions_for(r.authorizable_id) u.roles << r unless u.roles.include? r u.save flag_changed = true after = u.functions_for(r.authorizable_id) And here is the function being called def member_change flag_changed = false params['u'] =~ /role_(\d+)_user_(\d+)/ drag_role_id = $1 user_id = $2 params['r'] =~ /role_(\d+)/ drop_role_id = $1 if u=User.find(user_id) if r=Role.find(drop_role_id) if drag_role_id.to_i !=0 and old_r=Role.find(drag_role_id) if drag_role_id == drop_role_id #fom A to A => nothing happen flash.now[:warning] = _('No Operation...') elsif r.authorizable_id == old_r.authorizable_id #the same project? old_r.users.delete(u) unless old_r.valid? flash.now[:warning] = _('Group "Admin" CAN NOT be EMPTY.') old_r.users << u #TODO: better recovery member_edit #if flag_changed render :action => :member_edit, :layout => 'module_with_flash' return end old_r.save r.users << u unless r.users.include? u r.save flag_changed = true before = u.functions_for(r.authorizable_id) after = u.functions_for(r.authorizable_id) added = after - before removed = before - after added.each do |f| ApplicationController::send_msg(:function,:create, {:function_name => f.name, :user_id => u.id, :project_id => r.authorizable_id }) end removed.each do |f| ApplicationController::send_msg(:function,:delete, {:function_name => f.name, :user_id => u.id, :project_id => r.authorizable_id }) end flash.now[:notice] = _( 'Move User to Group' ) + " #{ r.name }" else flash.now[:warning] = _('You can\'t move User between Groups that belong to different Projects.') end else before = u.functions_for(r.authorizable_id) u.roles << r unless u.roles.include? r u.save flag_changed = true after = u.functions_for(r.authorizable_id) added = after - before added.each do |f| ApplicationController::send_msg(:function,:create, {:function_name => f.name, :user_id => u.id, :project_id => r.authorizable_id }) end flash.now[:notice] = _( 'Add User into Group' ) + " #{ r.name }" end else flash.now[:warn] = _( 'Group doesn\'t exist!' ) + ": #{ r.name }" end else flash.now[:warning] = _( 'User doesn\'t exist!' ) + ": #{ u.login }" end member_edit #if flag_changed render :action => :member_edit, :layout => 'module_with_flash' end and the JavaScript used to call the function jQuery('#RemoveThisMember').droppable({accept:'.RolesUsersSelection', drop:function(ev,ui){ if (confirm("This will remove User from this Group, are you sure?")) {jQuery.ajax({data:'u=' + encodeURIComponent(jQuery(ui.draggable).attr('id')), success:function(request){jQuery('#module_content').html(request);}, type:'post', url:'/of/projects/11/member_delete'});} }, hoverClass:'ProjectRoleDropDelete_active'}) Any ideas? Thanks,

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  • HTML CheckBox labels within a container are not displayed as expected

    - by Tiny
    The following HTML code attempts to display checkboxes inside a <div></div> container. <div style="overflow: auto; width: auto; display:block; max-height:130px; max-width:200px; background-color: #FFF; height: auto; border: 1px double #336699; padding-left: 2px;"> <label for="chk12" style='white-space: nowrap;'> <input type='checkbox' id="chk12" name='chk_colours' value="12" class='validate[required] text-input text'> <div style='background-color:#FF8C00; width: 180px;' title="darkorange">&nbsp;&nbsp;</div> </label> <label for="chk11" style='white-space: nowrap;'> <input type='checkbox' id="chk11" name='chk_colours' value="11" class='validate[required] text-input text'> <div style='background-color:#D9D919; width: 180px;' title="brightgold">&nbsp;&nbsp;</div> </label> <label for="chk10" style='white-space: nowrap;'> <input type='checkbox' id="chk10" name='chk_colours' value="10" class='validate[required] text-input text'> <div style='background-color:#76EE00; width: 180px;' title="chartreuse2">&nbsp;&nbsp;</div> </label> <label for="chk9" style='white-space: nowrap;'> <input type='checkbox' id="chk9" name='chk_colours' value="9" class='validate[required] text-input text'> <div style='background-color:#2E0854; width: 180px;' title="indigo">&nbsp;&nbsp;</div> </label> <label for="chk8" style='white-space: nowrap;'> <input type='checkbox' id="chk8" name='chk_colours' value="8" class='validate[required] text-input text'> <div style='background-color:#292929; width: 180px;' title="gray16">&nbsp;&nbsp;</div> </label> </div> What it displays can be visible in the following snap shot. It is seen that various colour stripes which are displayed using the following <div> tag <div style='background-color:#FF8C00; width: 180px;' title="darkorange">&nbsp;&nbsp</div> are displayed below their respective checkboxes which are expected to be displayed in a straight line even though I'm using the white-space: nowrap; style attribute. How to display each stripe along with its respective checkbox in a straight line? It was explained in one of my questions itself but in that question each checkbox had a text label in place of such colour stripes. Here it is. I tried to do as mentioned in the accepted answer of that question but to no avail in this case.

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  • Basic C question, concerning memory allocation and value assignment

    - by VHristov
    Hi there, I have recently started working on my master thesis in C that I haven't used in quite a long time. Being used to Java, I'm now facing all kinds of problems all the time. I hope someone can help me with the following one, since I've been struggling with it for the past two days. So I have a really basic model of a database: tables, tuples, attributes and I'm trying to load some data into this structure. Following are the definitions: typedef struct attribute { int type; char * name; void * value; } attribute; typedef struct tuple { int tuple_id; int attribute_count; attribute * attributes; } tuple; typedef struct table { char * name; int row_count; tuple * tuples; } table; Data is coming from a file with inserts (generated for the Wisconsin benchmark), which I'm parsing. I have only integer or string values. A sample row would look like: insert into table values (9205, 541, 1, 1, 5, 5, 5, 5, 0, 1, 9205, 10, 11, 'HHHHHHH', 'HHHHHHH', 'HHHHHHH'); I've "managed" to load and parse the data and also to assign it. However, the assignment bit is buggy, since all values point to the same memory location, i.e. all rows look identical after I've loaded the data. Here is what I do: char value[10]; // assuming no value is longer than 10 chars int i, j, k; table * data = (table*) malloc(sizeof(data)); data->name = "table"; data->row_count = number_of_lines; data->tuples = (tuple*) malloc(number_of_lines*sizeof(tuple)); tuple* current_tuple; for(i=0; i<number_of_lines; i++) { current_tuple = &data->tuples[i]; current_tuple->tuple_id = i; current_tuple->attribute_count = 16; // static in our system current_tuple->attributes = (attribute*) malloc(16*sizeof(attribute)); for(k = 0; k < 16; k++) { current_tuple->attributes[k].name = attribute_names[k]; // for int values: current_tuple->attributes[k].type = DB_ATT_TYPE_INT; // write data into value-field int v = atoi(value); current_tuple->attributes[k].value = &v; // for string values: current_tuple->attributes[k].type = DB_ATT_TYPE_STRING; current_tuple->attributes[k].value = value; } // ... } While I am perfectly aware, why this is not working, I can't figure out how to get it working. I've tried following things, none of which worked: memcpy(current_tuple->attributes[k].value, &v, sizeof(int)); This results in a bad access error. Same for the following code (since I'm not quite sure which one would be the correct usage): memcpy(current_tuple->attributes[k].value, &v, 1); Not even sure if memcpy is what I need here... Also I've tried allocating memory, by doing something like: current_tuple->attributes[k].value = (int *) malloc(sizeof(int)); only to get "malloc: * error for object 0x100108e98: incorrect checksum for freed object - object was probably modified after being freed." As far as I understand this error, memory has already been allocated for this object, but I don't see where this happened. Doesn't the malloc(sizeof(attribute)) only allocate the memory needed to store an integer and two pointers (i.e. not the memory those pointers point to)? Any help would be greatly appreciated! Regards, Vassil

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  • won't repaint a different Month after pressing button in my calendar

    - by DarkStar123
    I'm trying to build a Calendar in Java as a little project I thought of, But I can't seem to change the name of the Month every time I click the Next button. here's my code! package drawing; import javax.swing.*; import java.awt.*; import java.awt.event.*; public class Drawing_something extends JPanel{ int[] calender_squares = {1, 2, 3, 4, 5, 6, 7}; String[] Month = {"January", "February", "March", "April","May","June","July", "August","September","October","November","December"}; int i = 0; Graphics c; @Override public void paintComponent(Graphics c){ super.paintComponent(c); this.setBackground(Color.WHITE); int WIDTH = 55, HEIGHT = 65; for (int in: calender_squares) { for (int counter = 0; counter < 7; counter++){ c.drawRect(50, 50, 100, 100); c.drawRect(50, 50, 700, 500); c.copyArea(50, 50, 600, 500, 100, 0); c.copyArea(50, 50, 600, 400, 0, 100); } } for (int date = 1; date <= 30; date++) { String s = String.valueOf(date); c.drawString(s, WIDTH, HEIGHT); if (date <= 6){ WIDTH += 100; } else if (date == 7){ WIDTH = 55; HEIGHT = 165; }else if (date <= 13){ WIDTH += 100; }else if (date == 14){ WIDTH = 55; HEIGHT = 265; }else if (date <= 20){ WIDTH += 100; }else if (date == 21){ WIDTH = 55; HEIGHT = 365; }else if (date <= 27){ WIDTH += 100; }else if (date == 28){ WIDTH = 55; HEIGHT = 465; }else if (date <= 30){ WIDTH += 100; } } c.setFont(new Font("default", Font.BOLD, 40)); c.drawString(Month[i], 320, 45); } public Drawing_something(){ setLayout(new BorderLayout()); JButton N = new JButton("NEXT"); JButton B = new JButton("BACK"); JPanel P = new JPanel(); P.add(B); P.add(N); add(P, BorderLayout.SOUTH); B.addActionListener(new HandlerClass()); N.addActionListener(new NextClass()); } public class HandlerClass implements ActionListener{ public void actionPerformed(ActionEvent e){ } } public class NextClass implements ActionListener{ public void actionPerformed(ActionEvent e){ if (i == 11){ i = 0; } i = i + 1; c.drawString(Month[i], 320, 45); } } public static void main(String[] args){ JFrame mainFrame = new JFrame("Calender"); mainFrame.add(new Drawing_something()); mainFrame.setSize(850, 650); mainFrame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); mainFrame.setVisible(true); } } if anyone could help that would be much appreciated!! Thanks in advance!!

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  • Help for creating a random String

    - by Max
    I need to create a random string which should be between the length of 6 to 10 but it sometimes generates only about the length of 3 to 5. Here's my code. Can anyone would be able to find out the problem? :( int lengthOfName = (int)(Math.random() * 4) + 6; String name = ""; /* randomly choosing a name*/ for (int j = 0; j <= lengthOfName; j++) { int freq = (int)(Math.random() * 100) + 1; if(freq <= 6){ name += "a"; }if(freq == 7 && freq == 8){ name += "b"; }if(freq >= 9 && freq <= 11){ name += "c"; }if(freq >= 12 && freq <= 15){ name += "d"; }if(freq >= 16 && freq <= 25){ name += "e"; }if(freq == 26 && freq == 27){ name += "f"; }if(freq == 28 && freq == 29){ name += "g"; }if(freq >= 30 && freq <= 33){ name += "h"; }if(freq >= 34 && freq <= 48){ name += "i"; }if(freq == 49 && freq == 50){ name += "j"; }if(freq >= 51 && freq <= 55){ name += "k"; }if(freq >= 56 && freq <= 60){ name += "l"; }if(freq == 61 && freq == 62){ name += "m"; }if(freq >= 63 && freq <= 70){ name += "n"; }if(freq >= 71 && freq <= 75){ name += "o"; }if(freq == 76 && freq == 77){ name += "p"; }if(freq == 78){ name += "q"; }if(freq >= 79 && freq <= 84){ name += "r"; }if(freq == 85 && freq == 86){ name += "s"; }if(freq == 87 && freq == 88){ name += "t"; }if(freq >= 89 && freq <= 93){ name += "u"; }if(freq == 94){ name += "v"; }if(freq == 95 && freq == 96){ name += "w"; }if(freq == 97){ name += "x"; }if(freq == 98 && freq == 99){ name += "y"; }if(freq == 100){ name += "z"; } }

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  • How to Load In Content with jQuery?

    - by ClarkSKent
    Hello, I am trying to add ajax functionality to my pagination so the content loads in the same page instead of the user having to navigate to another page when clicking the page links. I should mention that I am using this php pagination class. Being new to jquery, I am unsure of how to properly do this with the pagination class. This is what the main page looks like: <?php $categoryId=$_GET['category']; echo $categoryId; ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_page.js"></script> <?php //Include the PS_Pagination class include('ps_pagination.php'); //Connect to mysql db $conn = mysql_connect('localhost', 'root', 'root'); mysql_select_db('ajax_demo',$conn); $sql = "select * from explore where category='$categoryId'"; //Create a PS_Pagination object $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); //The paginate() function returns a mysql //result set for the current page $rs = $pager->paginate(); //Loop through the result set echo "<table width='800px'>"; while($row = mysql_fetch_assoc($rs)) { echo "<tr>"; echo"<td>"; echo $row['id']; echo"</td>"; echo"<td>"; echo $row['site_description']; echo"</td>"; echo"<td>"; echo $row['site_price']; echo"</td>"; echo "</tr>"; } echo "</table>"; echo "<ul id='pagination'>"; echo "<li>"; //Display the navigation echo $pager->renderFullNav(); echo "</li>"; echo "</ul>"; ?> <div id="loading" ></div> <div id="content" ></div> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Any help on this would be great. Thanks.

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  • PHP $_GET and $_POST are returning empty arrays--trying to paginate SQL data

    - by George88
    I have set up the following: Database class ($db) Pagination class ($paginator) I am attempting to write a basic system to let me administrate pages. I have a page "page_manager.php" in which I include both my database class (database.php) and my pagination class (paginate.php). In my pagination class I have a function which echoes my SQL data. I've come up with a way to echo an HTML < select element with the necessary IDs, which allows me to successfully echo the corresponding results (10 per page), based on the value of the < select element. So, "1" will echo the first 10 results in the database, "2" will echo from 11-20, "3" will echo from 21-30, etc., etc.. I have added an onChange event to the < select element which will copy its value (using "this.value") to a hidden form field. I then submit this form using document.getElementById().submit(); This will then add the $_GET variable to the URL, so the URL becomes ".../?pagenumber_form=X". However, when I try to grab this value back from the URL, the $_GET['pagenumber_form'] is empty. Some code: <span style='font-family: tahoma; font-size: 10pt;'>Page #</span> <select id="page_number_selection" onchange='javascript: document.getElementById("pagenumber_form").value = this.value; document.getElementById("pagenumber").submit();'> <?php for($i = 1; $i <= $this->num_pages; $i++) echo"<option id='" . $i . "'>" . $i . "</option>"; ?> </select> <form name="pagenumber" id="pagenumber" action="" method="get"> <input type="text" name="pagenumber_form" id="pagenumber_form" /> </form> So, I've tried using $_POST as well, but the same thing happens. I want to use $_GET, for a couple of reasons: it's easier to see what is happening with my values and the data I'm using doesn't need to be secure. To recap: the $_GET variable is being added to the URL when I change the < select element, and the corresponding value gets added to the URL as: ".../?pagenumber_form=X", but when I try to use the value in PHP, for example... $page_number = $_GET['pagenumber_form']; ... I get a NULL value. :-( Can anybody help me out please? Thank you. EDIT: I've just made a discovery. If I move my print_r($_GET) to my main index page, then the superglobals are returning as expected. My site structure is like this: index.php - JavaScript buttons use AJAX HTTP requests to include the "responseText" as the .innerHTML of my main < div . The "responseText" is the contents the page itself, in this case page_manager.php, which in turn includes pagination.php. So in other words, my site is built from PHP includes, which doesn't seem to be compatible with HTTP superglobals. Any idea how I can get around this problem? Thank you :-).

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  • Issue with undefined namespace

    - by SoBeK
    "xmlns="VL01" Seems to be causing the style-sheet to fail(works fine if removed), do no know how to address it the style-sheet. I feel like this is basic XLST 101 but I am having a hard time wrapping my brain around it. Any assisting would be greatly appreciated. Cheers XML <?xml version="1.0" encoding="utf-8"?> <Report xsi:schemaLocation="VL01 http://site.com/ReportServer?%2FVMS%20Reports%2FVL01&amp;rs%3ACommand=Render&amp;rs%3AFormat=XML&amp;rs%3ASessionID=lk44ff55z5q3ck3b5pfuxo45&amp;rc%3ASchema=True" Name="VL01" textbox41="VL01 - Checklist Report&#xD;&#xA;" textbox1946=" 2) Target Element&#xD;&#xA;     Target Element List&#xD;&#xA;        Windows 7&#xD;&#xA;3) Report Options&#xD;&#xA; xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="VL01"> <list2> <Item_Collection> <Item /> </Item_Collection> </list2> <list1> <list1_Details_Group_Collection> <list1_Details_Group Key="V0001070" EffectiveDate="04 Mar 1998 16:03:47:000" LongName2="Name..."/> </list1_Details_Group_Collection> </list1> </Report> XSL <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <xsl:output method="xml" version="4.0" indent="yes"/> <xsl:variable name="var-checklist_name"> <xsl:value-of select="substring-after(substring-before(translate(Report/@textbox1946, '&#xD;&#xA;', ''),'3)'),'Target&#x00A0;Element&#x00A0;List')"/> </xsl:variable><xsl:template match="/"> <html> <body> <table> <xsl:apply-templates select="Report/list1/list1_Details_Group_Collection"/> </table> </body> </html> </xsl:template> <xsl:template match="Report/list1/list1_Details_Group_Collection"> <xsl:for-each select="list1_Details_Group"> <Import_List> <Checklist_Name> <xsl:value-of select="normalize-space(translate($var-checklist_name, '&#x00A0;', ' '))"/> </Checklist_Name> <Vuln_ID><xsl:value-of select="number(substring-after(@VulKey,'V'))"/></Vuln_ID> <Short_Name><xsl:value-of select="substring(@LongName2,1,255)"/></Short_Name> <Release_Date><xsl:value-of select="substring(@EffectiveDate,1,11)"/></Release_Date> </Import_List> </xsl:for-each> </xsl:template> </xsl:stylesheet>

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  • antlr line after line processing

    - by pawloch
    I'm writing simple language in ANTLR, and I'd like to write shell where I can put line of code, hit ENTER and have it executed, enter another line, and have it executed. I have already written grammar which execute all alines of input at one. Example input: int a,b,c; string d; string e; d=\"dziala\"; a=4+7; b=a+33; c=(b/11)*2; grammar Kalkulator; options { language = Java; output=AST; ASTLabelType=CommonTree; } tokens { NEG; } @header { package lab4; } @lexer::header { package lab4; } line : (assignment | declaration)* EOF ; declaration : type^ IDENT (','! IDENT)* ';'! ; type : 'int' | 'string' ; assignment : IDENT '='^ expression ';'! ; term : IDENT | INTEGER | STRING_LITERAL | '('! expression ')'! ; unary : (( negation^ | '+'! ))* term ; negation : '-' -> NEG ; mult : unary ( ('*'^ | '/'^) unary )* ; exp2 :mult ( ('-'^ | '+'^) mult)* ; expression : exp2 ('&'^ exp2)* ; fragment LETTER : ('a'..'z'|'A'..'Z'); fragment DIGIT : '0'..'9'; INTEGER : DIGIT+; IDENT : LETTER (LETTER | DIGIT)* ; WS : (' ' | '\t' | '\n' | '\r' | '\f')+ {$channel=HIDDEN;}; STRING_LITERAL : '\"' .* '\"'; and: tree grammar Evaluator; options { language = Java; tokenVocab = Kalkulator; ASTLabelType = CommonTree; } @header { package lab4; import java.util.Map; import java.util.HashMap; } @members { private Map<String, Object> zmienne = new HashMap<String, Object>(); } line returns [Object result] : (declaration | assignment { result = $assignment.result; })* EOF ; declaration : ^(type ( IDENT { if("string".equals($type.result)){ zmienne.put($IDENT.text,""); //add definition } else{ zmienne.put($IDENT.text,0); //add definition } System.out.println($type.result + " " + $IDENT.text);//write output } )* ) ; assignment returns [Object result] : ^('=' IDENT e=expression) { if(zmienne.containsKey($IDENT.text)) {zmienne.put($IDENT.text, e); result = e; System.out.println(e); } else{ System.out.println("Blad: Niezadeklarowana zmienna"); } } ; type returns [Object result] : 'int' {result="int";}| 'string' {result="string";} ; expression returns [Object result] : ^('+' op1=expression op2=expression) { result = (Integer)op1 + (Integer)op2; } | ^('-' op1=expression op2=expression) { result = (Integer)op1 - (Integer)op2; } | ^('*' op1=expression op2=expression) { result = (Integer)op1 * (Integer)op2; } | ^('/' op1=expression op2=expression) { result = (Integer)op1 / (Integer)op2; } | ^('%' op1=expression op2=expression) { result = (Integer)op1 \% (Integer)op2; } | ^('&' op1=expression op2=expression) { result = (String)op1 + (String)op2; } | ^(NEG e=expression) { result = -(Integer)e; } | IDENT { result = zmienne.get($IDENT.text); } | INTEGER { result = Integer.parseInt($INTEGER.text); } | STRING_LITERAL { String t=$STRING_LITERAL.text; result = t.substring(1,t.length()-1); } ; Can I make it process line-by-line or is that easier to make it all again?

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  • Rearrange array

    - by bradenkeith
    Array starts like this: Array ( [SMART Board] => Array ( [0] => sb1 [1] => sb2 [2] => sb3 ) [Projector] => Array ( [0] => pr1 [1] => pr2 [2] => pr3 ) [Speakers] => Array ( [0] => sp1 [1] => sp2 [2] => sp3 ) [Splitter] => Array ( [0] => spl1 [1] => spl2 [2] => spl3 ) [Wireless Slate] => Array ( [0] => ws1 [1] => ws2 [2] => ws3 ) ) The keys are used as my table columns titles. Their individual arrays are to carry the column information. I have split it up even further with array_slice and array_merge_recursive to look pretty as 2 arrays - 1 holds the column names, the other looks like this: Array ( [0] => sb1 [1] => sb2 [2] => sb3 [3] => pr1 [4] => pr2 [5] => pr3 [6] => sp1 [7] => sp2 [8] => sp3 [9] => spl1 [10] => spl2 [11] => spl3 [12] => ws1 [13] => ws2 [14] => ws3 ) However, when trying to write the table I'm getting keys 0, 1, 2 as the column data, then row break then 3, 4, 5 then row break... etc. I need it to be 0, 3, 6, 9, 12 row break 1, 4, 7, 10, 13 row break etc... How can I either rearrange my array to allow for this, or rewrite how the data goes into the table so that the correct information lines up with the appropriate column? foreach(unserialize($dl->data) as $data){ //first 3 are specialinstructions, system, and room $uniques = array_slice($data,0,3); $rows = array_slice($data,3); $rows2 = array_merge_recursive($rows2, $rows); //get the specialinstructions, system, and room foreach($uniques as $unique){ echo $unique."<br/>"; }///foreach uniques echo "<br>"; }///foreach unserialized $numberofrooms = count($rows2[key($rows2)]); $numberofproducts = count($rows2); print_r($rows2); unset($rows); //write the individual rows foreach($rows2 as $header=>$rowset){ $headers[] = $header; foreach($rowset as $row){ $rows[] = $row; }//foreach rowset }//foreach rows2 echo "<p>"; print_r($rows); echo '<table class="data-table"> <caption>DL</caption> <thead><tr>'; foreach($headers as $header){ echo "<th>".$header."</th>"; } echo '</tr></thead>'; echo '<tbody>'; $i = 0; foreach($rows as $row){ if($i == 3 || $i == 0){ echo "<tr>"; $i = 1; } echo '<td>'.$row.'</td>'; if($i == 2){ echo "</tr>"; } $i++; } echo '</tbody></table>';

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  • C Program not running as intended, hangs after input

    - by user41419
    The program I am writing to take a number and display that number as a calculator would display it (shown below) is compiling with no issues, but when I try to run it, I am able to input my number, but nothing happens. It seems like it is "hanging", since no further output is shown as I would have expected. Might anyone know what the problem is? #include <stdio.h> #define MAX_DIGITS 20 char segments[10][7] = /* seven segment array */ {{'1','1','1','1','1','1','0'}, /* zero */ {'0','1','1','0','0','0','0'}, /* one */ {'1','1','0','1','1','0','1'}, /* two */ {'1','1','1','1','0','0','1'}, /* three */ {'0','1','1','0','0','1','1'}, /* four */ {'1','0','1','1','0','1','1'}, /* five */ {'1','0','1','1','1','1','1'}, /* six */ {'1','1','1','0','0','0','0'}, /* seven */ {'1','1','1','1','1','1','1'}, /* eight */ {'1','1','1','0','0','1','1'}};/* nine */ char digits[3][MAX_DIGITS * 4]; /* digits array */ int i, j; /* count variables */ int adjust; /* output formatting */ int main(void) { clear_digits_array(); int digit[20]; for (i = 0; i < 20; i++) { digit[i] = 0; } int count = 20; int position = 0; printf("Enter a number: "); int number = scanf("%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d", &digit[0], &digit[1], &digit[2], &digit[3], &digit[4], &digit[5], &digit[6], &digit[7], &digit[8], &digit[9], &digit[10], &digit[11], &digit[12], &digit[13], &digit[14], &digit[15], &digit[16], &digit[17], &digit[18], &digit[19]); //NOTHING HAPPENS AFTER HERE printf("Got input, number is %d", number); while (count > 0) { printf("Reading digits, count is %d", count); process_digit(digit[20 - count], position); position++; count--; } print_digits_array(); printf("\n"); return 0; } void clear_digits_array(void) { /* fill all positions in digits array with blank spaces */ for (i = 0; i < 3; i++) { for (j = 0; j < (MAX_DIGITS * 4); j++) { digits[i][j] = ' '; } } } void process_digit(int digit, int position) { /* check each segment to see if segment should be filled in for given digit */ for (i = 0; i < 7; i++) { printf("Processing digit %d at position %d, i is %d", digit, position, i); if (segments[digit][i] == 1) { switch (i) { case 0: digits[0][(position * 4) + 1] = '_'; break; case 1: digits[1][(position * 4) + 2] = '|'; break; case 2: digits[2][(position * 4) + 2] = '|'; break; case 3: digits[2][(position * 4) + 1] = '_'; break; case 4: digits[2][(position * 4) + 0] = '|'; break; case 5: digits[1][(position * 4) + 0] = '|'; break; case 6: digits[1][(position * 4) + 1] = '_'; break; } } } } void print_digits_array(void) { /* print each character in digits array */ for (i = 0; i < 3; i++) { for (j = 0; j < (MAX_DIGITS * 4); j++) { printf("%c", digits[i][j]); } printf("/n"); } }

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  • Generating 2-dimensional vla ends in segmentation fault

    - by Framester
    Hi, further developing the code from yesterday (seg fault caused by malloc and sscanf in a function), I tried with the help of some tutorials I found on the net to generate a 2-dim vla. But I get a segmentation fault at (*data)[i][j]=atof(p);. The program is supposed to read a matrix out of a text file and load it into a 2d array (cols 1-9) and a 1D array (col 10) [Example code] #include<stdio.h> #include<stdlib.h> #include<math.h> #include<string.h> const int LENGTH = 1024; void read_data(float ***data, int **classes, int *nrow,int *ncol, char *filename){ FILE *pfile = NULL; char line[LENGTH]; if(!( pfile=fopen(filename,"r"))){ printf("Error opening %s.", filename); exit(1); } int numlines=0; int numcols=0; char *p; fgets(line,LENGTH,pfile); p = strtok (line," "); while (p != NULL){ p = strtok (NULL, ", "); numcols++; } while(fgets(line,LENGTH,pfile)){ numlines++; } rewind(pfile); int numfeats=numcols-1; *data=(float**) malloc(numlines*sizeof(float*)); *classes=(int *)malloc(numlines*sizeof(int)); if(*classes == NULL){ printf("\nOut of memory."); exit(1); } int i=0; while(fgets(line,LENGTH,pfile)){ p = strtok (line," "); for(int j=0;j<numfeats;j++) { (data)[i]=malloc(numfeats*sizeof(float)); printf("%i ",i); (*data)[i][j]=atof(p); p = strtok (NULL, ", "); } (*classes)[i]=atoi(p); i++; } fclose(pfile); *nrow=numlines; *ncol=numfeats; } int main() { char *filename="somedatafile.txt"; float **data2; int *classes2; int r,c; read_data(&data2,&classes2, &r, &c,filename) ; for(int i=0;i<r;i++){ printf("\n"); for(int j=0;j<c;j++){ printf("%f",data2[i][j]); } } return 1; } [Content of somedatafile.txt] 50 21 77 0 28 0 27 48 22 2 55 0 92 0 0 26 36 92 56 4 53 0 82 0 52 -5 29 30 2 1 37 0 76 0 28 18 40 48 8 1 37 0 79 0 34 -26 43 46 2 1 85 0 88 -4 6 1 3 83 80 5 56 0 81 0 -4 11 25 86 62 4 55 -1 95 -3 54 -4 40 41 2 1 53 8 77 0 28 0 23 48 24 4 37 0 101 -7 28 0 64 73 8 1 ...

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  • Object reference not set to an instance of an object- Linked List Example

    - by Zoro Roronoa
    I am seeing following errors : Object reference not set to an instance of an object! Check to determinate if the object is null before calling the method! I'am new with C#,and I made a program for Sorted Linked Lists. Here is the code where the error comes! public void Insert(double data) { Link newLink = new Link(data); Link current = first; Link previous = null; if (first == null) { first = newLink; } else { while (data > current.DData && current != null) { previous = current; current = current.Next; } previous.Next = newLink; newLink.Next = current; } } It says that the current referenc is null while (data current.DData && current != null), but I assigned it current = first; Please Help ! The rest is the complete code of the Program! class Link { double dData; Link next=null; public Link Next { get { return next; } set { next = value; } } public double DData { get { return dData; } set { dData = value; } } public Link(double dData) { this.dData = dData; } public void DisplayLink() { Console.WriteLine("Link : "+ dData); } } class SortedList { Link first; public SortedList() { first = null; } public bool IsEmpty() { return (this.first == null); } public void Insert(double data) { Link newLink = new Link(data); Link current = first; Link previous = null; if (first == null) { first = newLink; } else { while (data > current.DData && current != null) { previous = current; current = current.Next; } previous.Next = newLink; newLink.Next = current; } } public Link Remove() { Link temp = first; first = first.Next; return temp; } public void DisplayList() { Link current; current = first; Console.WriteLine("Display the List!"); while (current != null) { current.DisplayLink(); current = current.Next; } } } class SortedListApp { public void TestSortedList() { SortedList newList = new SortedList(); newList.Insert(20); newList.Insert(22); newList.Insert(100); newList.Insert(1000); newList.Insert(15); newList.Insert(11); newList.DisplayList(); newList.Remove(); newList.DisplayList(); } }

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  • Sending typedef struct containing void* by creating MPI drived datatype.

    - by hankol
    what I understand studying MPI specification is that an MPI send primitive refer to a memory location (or a send buffer) pointed by the data to be sent and take the data in that location which then passed as a message to the another Process. Though it is true that virtual address of a give process will be meaningless in another process memory address; It is ok to send data pointed by pointer such as void pointer as MPI will any way pass the data itself as a message For example the following works correctly: // Sender Side. int x = 100; void* snd; MPI_Send(snd,4,MPI_BYTE,1,0,MPI_COMM_WORLD); // Receiver Side. void* rcv; MPI_Recv(rcv, 4,MPI_BYTE,0,0,MPI_COMM_WORLD); but when I add void* snd in a struct and try to send the struct this will no succeed. I don't understand why the previous example work correctly but not the following. Here, I have defined a typedef struct and then create an MPI_DataType from it. With the same explanation of the above the following should also have succeed, unfortunately it is not working. here is the code: #include "mpi.h" #include<stdio.h> int main(int args, char *argv[]) { int rank, source =0, tag=1, dest=1; int bloackCount[2]; MPI_Init(&args, &argv); typedef struct { void* data; int tag; } data; data myData; MPI_Datatype structType, oldType[2]; MPI_Status stat; /* MPI_Aint type used to idetify byte displacement of each block (array)*/ MPI_Aint offsets[2], extent; MPI_Comm_rank(MPI_COMM_WORLD, &rank); offsets[0] = 0; oldType[0] = MPI_BYTE; bloackCount[0] = 1; MPI_Type_extent(MPI_INT, &extent); offsets[1] = 4 * extent; /*let say the MPI_BYTE will contain ineteger : size of int * extent */ oldType[1] = MPI_INT; bloackCount[1] = 1; MPI_Type_create_struct(2, bloackCount,offsets,oldType, &structType); MPI_Type_commit(&structType); if(rank == 0){ int x = 100; myData.data = &x; myData.tag = 99; MPI_Send(&myData,1,structType, dest, tag, MPI_COMM_WORLD); } if(rank == 1 ){ MPI_Recv(&myData, 1, structType, source, tag, MPI_COMM_WORLD, &stat); // with out this the following printf() will properly print the value 99 for // myData.tag int x = *(int *) myData.data; printf(" \n Process %d, Received : %d , %d \n\n", rank , myData.tag, x); } MPI_Type_free(&structType); MPI_Finalize(); } Error message running the code: [Looks like I am trying to access an invalid memory address space in the second process] [ubuntu:04123] *** Process received signal *** [ubuntu:04123] Signal: Segmentation fault (11) [ubuntu:04123] Signal code: Address not mapped (1) [ubuntu:04123] Failing at address: 0xbfe008bc [ubuntu:04123] [ 0] [0xb778240c] [ubuntu:04123] [ 1] GenericstructType(main+0x161) [0x8048935] [ubuntu:04123] [ 2] /lib/i386-linux-gnu/libc.so.6(__libc_start_main+0xf3) [0xb750f4d3] [ubuntu:04123] [ 3] GenericstructType() [0x8048741] [ubuntu:04123] *** End of error message *** Can some please explain to me why it is not working. any advice will also be appreciated thanks,

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  • Reflector error or optimisation?

    - by David_001
    Long story short: I used reflector on the System.Security.Util.Tokenizer class, and there's loads of goto statements in there. Here's a brief example snippet: Label_0026: if (this._inSavedCharacter != -1) { num = this._inSavedCharacter; this._inSavedCharacter = -1; } else { switch (this._inTokenSource) { case TokenSource.UnicodeByteArray: if ((this._inIndex + 1) < this._inSize) { break; } stream.AddToken(-1); return; case TokenSource.UTF8ByteArray: if (this._inIndex < this._inSize) { goto Label_00CF; } stream.AddToken(-1); return; case TokenSource.ASCIIByteArray: if (this._inIndex < this._inSize) { goto Label_023C; } stream.AddToken(-1); return; case TokenSource.CharArray: if (this._inIndex < this._inSize) { goto Label_0272; } stream.AddToken(-1); return; case TokenSource.String: if (this._inIndex < this._inSize) { goto Label_02A8; } stream.AddToken(-1); return; case TokenSource.NestedStrings: if (this._inNestedSize == 0) { goto Label_030D; } if (this._inNestedIndex >= this._inNestedSize) { goto Label_0306; } num = this._inNestedString[this._inNestedIndex++]; goto Label_0402; default: num = this._inTokenReader.Read(); if (num == -1) { stream.AddToken(-1); return; } goto Label_0402; } num = (this._inBytes[this._inIndex + 1] << 8) + this._inBytes[this._inIndex]; this._inIndex += 2; } goto Label_0402; Label_00CF: num = this._inBytes[this._inIndex++]; if ((num & 0x80) != 0) { switch (((num & 240) >> 4)) { case 8: case 9: case 10: case 11: throw new XmlSyntaxException(this.LineNo); case 12: case 13: num &= 0x1f; num3 = 2; break; case 14: num &= 15; num3 = 3; break; case 15: throw new XmlSyntaxException(this.LineNo); } if (this._inIndex >= this._inSize) { throw new XmlSyntaxException(this.LineNo, Environment.GetResourceString("XMLSyntax_UnexpectedEndOfFile")); } byte num2 = this._inBytes[this._inIndex++]; if ((num2 & 0xc0) != 0x80) { throw new XmlSyntaxException(this.LineNo); } num = (num << 6) | (num2 & 0x3f); if (num3 != 2) { if (this._inIndex >= this._inSize) { throw new XmlSyntaxException(this.LineNo, Environment.GetResourceString("XMLSyntax_UnexpectedEndOfFile")); } num2 = this._inBytes[this._inIndex++]; if ((num2 & 0xc0) != 0x80) { throw new XmlSyntaxException(this.LineNo); } num = (num << 6) | (num2 & 0x3f); } } goto Label_0402; Label_023C: num = this._inBytes[this._inIndex++]; goto Label_0402; Label_0272: num = this._inChars[this._inIndex++]; goto Label_0402; Label_02A8: num = this._inString[this._inIndex++]; goto Label_0402; Label_0306: this._inNestedSize = 0; I essentially wanted to know how the class worked, but the number of goto's makes it impossible. Arguably something like a Tokenizer class needs to be heavily optimised, so my question is: is Reflector getting it wrong, or is goto an optimisation for this class?

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  • How is it possible my array is broken?

    - by user1812765
    I have this piece of code: public lot merge (lot otherlot){ wafer[] mWaferarray = new wafer[16]; byte[] bytearray = new byte[16]; wafer resultwafer = new wafer(bytearray); wafer w1; wafer w2; int i; int[][] assignmentmatrix = HungarianAlgorithm.computeAssignments(convertinttofloat (solutionmatrix(otherlot))); for (i=0; i != assignmentmatrix.length ;i++){ w1 = otherlot.getWaferarray()[assignmentmatrix[i][0]]; w2 = getWaferarray()[assignmentmatrix[i][1]]; resultwafer.setWafer(w1.wafercompare(w2)); mWaferarray[i] = resultwafer; mWaferarray[i].print(); } System.out.println("HERE\n"); mWaferarray[5].toString(); resultlot = new lot(mWaferarray); resultlot.print();// Problem occurs here. return resultlot; } As you can see I create an array of wafers (selfdefined class). Then I fill this up with new wafers. When I print this array (mWaferarray[i].print()) it gives me the wanted results. But when I go out of the "for"-loop the array is broken and it is as if the last item I add to mWaferarray fills it up (the entire array, 16 long, is filled with this wafer). So if run this program this is what I get: 1011110010111100 0011011111111110 0111110111101101 1010111001101111 0110110111101111 1010110101111010 1010110111011110 1011111010111100 1111110011101110 0111111111011011 1111111111011010 1101111011111010 1010110101011110 0101111011011010 1011111011011000 0101111011011010 HERE 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 0101111011011010 As you can see it is as if the array is filled with the last wafer. I have been looking at this for some time now, I hope you guy can help me out. Thx in advance PS: my print functions are written like this: void print(){ int j; for (j=0; j != waferarray.length ;j++){ waferarray[j].print(); } } EDIT: added code for lot this is the beginning of the lot class public class lot { wafer[] waferarray = new wafer[16]; lot resultlot; public lot (wafer wafer1,wafer wafer2,wafer wafer3,wafer wafer4, wafer wafer5,wafer wafer6,wafer wafer7,wafer wafer8, wafer wafer9,wafer wafer10,wafer wafer11,wafer wafer12, wafer wafer13,wafer wafer14,wafer wafer15,wafer wafer16){ waferarray[0] = wafer1; waferarray[1] = wafer2; waferarray[2] = wafer3; waferarray[3] = wafer4; waferarray[4] = wafer5; waferarray[5] = wafer6; waferarray[6] = wafer7; waferarray[7] = wafer8; waferarray[8] = wafer9; waferarray[9] = wafer10; waferarray[10] = wafer11; waferarray[11] = wafer12; waferarray[12] = wafer13; waferarray[13] = wafer14; waferarray[14] = wafer15; waferarray[15] = wafer16; } public lot (wafer[] thiswaferarray){ waferarray = thiswaferarray; }

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  • Using JavaScript, how do I write the same text to multiple HTML elements, or how do I write text to all HTML elements of the same class?

    - by myfavoritenoisemaker
    I am writing this program to take a root music note and populate tables with various scales from that root note. So, many of the tables cells will have the exact same value in them. I realize I can call my "useScale" function for every single that I need to write text to but since there will be repeats, it seemed like there should be a way to run my function once and apply the results to multiple but it did not work to use the document.getElementsByClassName("").innerHTML, I had been using "ById" which worked fine but each ID must be unique so, I can't write to multiple elements. Here's my code, I'd love some suggestions. many thanks Root Note <input type="text" name="defineRootNote" id="rootNoteCapture" size="2"/> <button onclick="findScale()">Submit</button> <table id="majorTriad"> <th>Major Triad</th> <tr><td>1st</td><td class="root"> </td></tr> <tr><td>3rd</td><td class="3rd"> </td></tr> <tr><td>5th</td><td class="5th"> </td></tr> </table> <table id="minorTriad"> <th>Minor Triad</th> <tr><td>1st</td><td class="root"> </td></tr> <tr><td>3 Flat</td><td class="3Flat"> </td></tr> <tr><td>5th</td><td class="5th"> </td></tr> </table> <script type="text/javascript"> function findScale(rootNote){ var rootNote = document.getElementById("rootNoteCapture").value; rootNote = rootNote.toUpperCase(); var scaleCheck = ["A", "A#", "AB", "B", "BB", "C", "C#", "D", "D#", "DB", "E", "EB", "F", "F#", "G", "G#", "GB"]; if (scaleCheck.indexOf(rootNote) == -1) { document.getElementById("root").innerHTML = "Invalid Entry"; } else { switch(rootNote){ case "AB": rootNote = "G#"; break; case "BB": rootNote = "A#"; break; case "DB": rootNote = "C#"; break; case "EB": rootNote = "D#"; break; case "GB": rootNote = "F#"; break; rootNote = rootNote; } document.getElementsByClassName("root").innerHTML = rootNote; document.getElementsByClassName("3rd").innerHTML = useScale(rootNote, 4); document.getElementsByClassName("5th").innerHTML = useScale(rootNote, 7); document.getElementsByClassName("3Flat").innerHTML = useScale(rootNote, 3); } } function useScale(startPoint, offset){ var scale = ["A", "A#", "B", "C", "C#", "D", "D#", "E", "F", "F#", "G", "G#"]; var returnNote = null; var scalePoint = scale.indexOf(startPoint); for (var i = 0; i < offset; ){ i = i + 1; //console.log(i); //console.log(scalePoint); scalePoint ++; if (scalePoint > 11) {scalePoint = 0;} } returnNote = scale[scalePoint]; return returnNote; } </script>

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  • How to Sync Specific Folders With Dropbox

    - by Matthew Guay
    Would you like to sync specific folders with Dropbox instead of automatically syncing all of your folders to all of your computers?  Here’s how using Selective Sync available in the latest Beta version of Dropbox. Dropbox is a great tool for keeping your important files synced between your computers, and we have covered many interesting things you can do with your Dropbox account.  But until now, there was no way to only sync certain folders with each computer; it was all or nothing.  This could be frustrating if you wanted to store large files from one computer but didn’t want them on a computer with a smaller hard drive.  The latest Beta version of Dropbox allows you to selectively choose which folders to sync between computers. Please Note: This feature is currently only available in the 0.8 beta version of Dropbox. Setup the new Beta Download the new beta version of Dropbox 0.8 (link below); choose the correct download for your system.  Run the installer as normal. It only took a couple seconds to install, though it made the taskbar disappear briefly at the end of the installation on our tests.  Strangely, the installer doesn’t let you know it’s finished installing; if you already had a previous version of Dropbox installed, it will simply start working from your system tray as before.  If this is a new installation of Dropbox, you will be asked to enter your Dropbox account info or create a new account.   Selectively Sync Folders By default, Dropbox will still sync all of your Dropbox folders to all of your computers.  Once this beta is installed, you can choose individual folders or subfolders you don’t want to sync.  Right-click the Dropbox icon in your system tray and select Preferences. Click the Advanced tab on the top, and then click the new Selective Sync button. Now uncheck any folders you don’t want to sync to this computer.  These folders will still exist on your other machines and in the Dropbox web interface, but they will not be downloaded to this computer. The default view only shows your top-level folders in your Dropbox account.  If you wish to sync certain folders but exclude their subfolders, click the Switch to Advanced View button.   Expand any folder and uncheck any subfolders you don’t want to sync.  Notice that the parent folder’s check box is filled now, showing that it is partially synced. Click OK when you’ve made the changes you want.  Dropbox will then make sure you know these folders will stop syncing to this computer; click OK again if you’re sure you don’t want to sync these folders.   Dropbox will cleanup your folder and remove the files and folders you don’t want synced.   Next time you open your Dropbox folder, you’ll notice that the folders we unchecked are no longer in this computer’s Dropbox folder.  They are still in our Dropbox online account, and on any other computers we’re syncing with. If you add a new folder with the same name as a folder you stopped syncing, you’ll notice a grey minus icon over the folder.  This folder will not sync with your other computers or your online Dropbox account. If you want to add these folders back to this computer’s Dropbox, just repeat the steps, this time checking the folders you want to sync.  If you have any folders that were not syncing before, their names will have (Selective Sync Conflict) added to the end, and will sync with all of your computers. Conclusion We’re excited that we can now choose exactly which folders we want synced on each computer.  Since everything is still synced with the online Dropbox, we can still access any of the folders from anywhere.  This makes your Dropbox much more versatile, and can help you keep the folders synced exactly the way you want. Links Download the new Dropbox 0.8.64 beta Signup for Dropbox Similar Articles Productive Geek Tips Add "My Dropbox" to Your Windows 7 Start MenuSync Your Pidgin Profile Across Multiple PCs with DropboxUser Guide to Dropbox Shared FoldersUse Any Folder For Your Ubuntu Desktop (Even a Dropbox Folder)Shut Down or Reboot a Solaris System TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 2010 World Cup Schedule Boot Snooze – Reboot and then Standby or Hibernate Customize Everything Related to Dates, Times, Currency and Measurement in Windows 7 Google Earth replacement Icon (Icons we like) Build Great Charts in Excel with Chart Advisor tinysong gives a shortened URL for you to post on Twitter (or anywhere)

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  • Recent Innovations to ILOM

    - by B.Koch
    by Josh Rosen If you are wondering how Oracle can make some of the most advanced, reliable, and fault tolerant servers on the market, look no further than Oracle Integrated Lights Out Manager or ILOM.  We build ILOM into every server we create, from Oracle x86 Systems such as X3-2 to the SPARC T-Series family. Oracle ILOM is an embedded service processor, but it's really more than that.  It's a computer within a computer.  It's smart, it's tightly integrated into all aspects of the server's operation, and it's a big reason why Oracle servers are used for some of the most mission-critical workloads out there. To understand the value of ILOM, there is no better place to start than its fault management capability.  We have taken the sophisticated fault management architecture from Solaris, developed and refined over a decade, and built it into each and every ILOM. ILOM detects a potential issue at its earliest stage, watching low-level sensors.   If the root cause of a problem is not clear from a single error reading, ILOM will look for other clues and combine multiple pieces of information to correctly identify a failing component. ILOM provides peace of mind. We tailor our fault management for each new server platform that we produce.  You can rest assured that it's always actively keeping the server healthy.  And if there is a problem, you can be confident it will let you know by sending you a notification by e-mail or trap. We also heard IT managers tell us they needed a Ph.D. in computer engineering to manage today's servers. It doesn't have to be that way.  Thanks to the latest innovations to Oracle ILOM, we present hardware inventory and status in way that makes sense – to anyone.  Green means everything is healthy and red means something is wrong.  When a component needs to be replaced a clear message indicates where the problem is and points you at a knowledge article about that problem.  It's that simple. Simpler management and simple interfaces mean reduced complexity and lower costs to manage.  And we know that's really important. ILOM does all this while also providing advanced service processor features you depend on for managing enterprise class systems.  You can remotely control the server power, interact with a virtual video console for the server, and mount media on the server remotely.  There is no need to spend money on a KVM switch to get this functionality. And when people hear how advanced ILOM is, they can't believe ILOM is free.  All features are enabled and included with each Oracle server that you buy.  There are no advanced licenses you need to purchase or features to unlock. Configuring ILOM has also never been easier.  It is now possible to configure almost all aspects of the server directly from ILOM.  This includes changing BIOS settings, persistently modifying boot order, and optimizing power settings -- all directly from ILOM. But Oracle's innovation does not stop with ILOM.  Oracle has engineered Oracle Enterprise Manager Ops Center to integrate directly with ILOM, providing centralized management across all of our servers. Ops Center will discover each of your Oracle servers over the network by searching for ILOMs.  When it finds one, it knows how to communicate with ILOM to monitoring and configure that server from application to disk. Since every server that Oracle produces, from x86 Systems to SPARC T-Series up and down the line, comes with Oracle ILOM, you can manage all Oracle servers in the same way.  And while all of our servers may have different components on the inside, each with their specialized functions, the way you integrate them and the way you monitor and manage them is exactly the same. Oracle ILOM is state-of-art.  If you are looking for a server that make systems management simple and is easy to integrate and maintain, check out the latest advances to Oracle ILOM. Josh Rosen is a Principal Product Manager at Oracle and previously spent more than a decade as a developer and architect of system management software. Josh has worked on system management for many of Oracle's hardware products ranging from the earliest blade systems to the latest Oracle x86 servers.

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  • Oracle Linux and Oracle VM pricing guide

    - by wcoekaer
    A few days ago someone showed me a pricing guide from a Linux vendor and I was a bit surprised at the complexity of it. Especially when you look at larger servers (4 or 8 sockets) and when adding virtual machine use into the mix. I think we have a very compelling and simple pricing model for both Oracle Linux and Oracle VM. Let me see if I can explain it in 1 page, not 10 pages. This pricing information is publicly available on the Oracle store, I am using the current public list prices. Also keep in mind that this is for customers using non-oracle x86 servers. When a customer purchases an Oracle x86 server, the annual systems support includes full use (all you can eat) of Oracle Linux, Oracle VM and Oracle Solaris (no matter how many VMs you run on that server, in case you deploy guests on a hypervisor). This support level is the equivalent of premier support in the list below. Let's start with Oracle VM (x86) : Oracle VM support subscriptions are per physical server on which you deploy the Oracle VM Server product. (1) Oracle VM Premier Limited - 1- or 2 socket server : $599 per server per year (2) Oracle VM Premier - more than 2 socket server (4, or 8 or whatever more) : $1199 per server per year The above includes the use of Oracle VM Manager and Oracle Enterprise Manager Cloud Control's Virtualization management pack (including self service cloud portal, etc..) 24x7 support, access to bugfixes, updates and new releases. It also includes all options, live migrate, dynamic resource scheduling, high availability, dynamic power management, etc If you want to play with the product, or even use the product without access to support services, the product is freely downloadable from edelivery. Next, Oracle Linux : Oracle Linux support subscriptions are per physical server. If you plan to run Oracle Linux as a guest on Oracle VM, VMWare or Hyper-v, you only have to pay for a single subscription per system, we do not charge per guest or per number of guests. In other words, you can run any number of Oracle Linux guests per physical server and count it as just a single subscription. (1) Oracle Linux Network Support - any number of sockets per server : $119 per server per year Network support does not offer support services. It provides access to the Unbreakable Linux Network and also offers full indemnification for Oracle Linux. (2) Oracle Linux Basic Limited Support - 1- or 2 socket servers : $499 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management. It includes ocfs2 as a clustered filesystem. (3) Oracle Linux Basic Support - more than 2 socket server (4, or 8 or more) : $1199 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management. It includes ocfs2 as a clustered filesystem (4) Oracle Linux Premier Limited Support - 1- or 2 socket servers : $1399 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management, XFS filesystem support. It also offers Oracle Lifetime support, backporting of patches for critical customers in previous versions of package and ksplice zero-downtime updates. (5) Oracle Linux Premier Support - more than 2 socket servers : $2299 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management, XFS filesystem support. It also offers Oracle Lifetime support, backporting of patches for critical customers in previous versions of package and ksplice zero-downtime updates. (6) Freely available Oracle Linux - any number of sockets You can freely download Oracle Linux, install it on any number of servers and use it for any reason, without support, without right to use of these extra features like Oracle Clusterware or ksplice, without indemnification. However, you do have full access to all errata as well. Need support? then use options (1)..(5) So that's it. Count number of 2 socket boxes, more than 2 socket boxes, decide on basic or premier support level and you are done. You don't have to worry about different levels based on how many virtual instance you deploy or want to deploy. A very simple menu of choices. We offer, inclusive, Linux OS clusterware, Linux OS Management, provisioning and monitoring, cluster filesystem (ocfs), high performance filesystem (xfs), dtrace, ksplice, ofed (infiniband stack for high performance networking). No separate add-on menus. NOTE : socket/cpu can have any number of cores. So whether you have a 4,6,8,10 or 12 core CPU doesn't matter, we count the number of physical CPUs.

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  • Windows 7 doesn't boot after Ubuntu install

    - by Omu
    I had windows 7 installed on my pc, then I installed Ubuntu 10.10/ During the installation process I have chosen to manually set my partitions: I set a 10GB drive for ubuntu root 1GB drive for swap and for boot drive I've chosen the one used by windows 7 Now I can boot ubuntu, I have the windows 7 option in the boot list, but when I choose Windows 7, it shows me a black screen for a second and returns back to boot screen. Boot Info Script 0.55 dated February 15th, 2010 ============================= Boot Info Summary: ============================== = Windows is installed in the MBR of /dev/sda sda1: _________________________________________________________________________ File system: ntfs Boot sector type: Grub 2 Boot sector info: Grub 2 is installed in the boot sector of sda1 and looks at sector 304908237 of the same hard drive for core.img, but core.img can not be found at this location. No errors found in the Boot Parameter Block. Operating System: Windows 7 Boot files/dirs: /bootmgr /Boot/BCD /Windows/System32/winload.exe sda2: _________________________________________________________________________ File system: ntfs Boot sector type: Windows XP Boot sector info: No errors found in the Boot Parameter Block. Operating System: Boot files/dirs: sda3: _________________________________________________________________________ File system: Extended Partition Boot sector type: - Boot sector info: sda5: _________________________________________________________________________ File system: ext4 Boot sector type: - Boot sector info: Operating System: Ubuntu 10.10 Boot files/dirs: /boot/grub/grub.cfg /etc/fstab /boot/grub/core.img sda4: _________________________________________________________________________ File system: swap Boot sector type: - Boot sector info: =========================== Drive/Partition Info: ============================= Drive: sda ___________________ _____________________________________________________ Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders, total 312581808 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes Partition Boot Start End Size Id System /dev/sda1 * 63 62,894,474 62,894,412 7 HPFS/NTFS /dev/sda2 62,894,478 291,579,749 228,685,272 7 HPFS/NTFS /dev/sda3 291,579,811 309,157,937 17,578,127 5 Extended /dev/sda5 291,579,813 309,157,937 17,578,125 83 Linux /dev/sda4 309,159,936 312,580,095 3,420,160 82 Linux swap / Solaris blkid -c /dev/null: ____________________________________________________________ Device UUID TYPE LABEL /dev/sda1 1266BB2766BB0A8D ntfs /dev/sda2 BEDBF1147C76F703 ntfs DATA /dev/sda3: PTTYPE="dos" /dev/sda4 dd38226d-c7c9-4ae5-a726-6d18d34a22e4 swap /dev/sda5 e1dafd1c-f855-406b-8f9a-f9d527c70255 ext4 /dev/sda: PTTYPE="dos" ============================ "mount | grep ^/dev output: =========================== Device Mount_Point Type Options /dev/sda5 / ext4 (rw,errors=remount-ro,commit=0) =========================== sda5/boot/grub/grub.cfg: =========================== # # DO NOT EDIT THIS FILE # # It is automatically generated by grub-mkconfig using templates # from /etc/grub.d and settings from /etc/default/grub # ### BEGIN /etc/grub.d/00_header ### if [ -s $prefix/grubenv ]; then set have_grubenv=true load_env fi set default="0" if [ "${prev_saved_entry}" ]; then set saved_entry="${prev_saved_entry}" save_env saved_entry set prev_saved_entry= save_env prev_saved_entry set boot_once=true fi function savedefault { if [ -z "${boot_once}" ]; then saved_entry="${chosen}" save_env saved_entry fi } function recordfail { set recordfail=1 if [ -n "${have_grubenv}" ]; then if [ -z "${boot_once}" ]; then save_env recordfail; fi; fi } function load_video { insmod vbe insmod vga } insmod part_msdos insmod ext2 set root='(hd0,msdos5)' search --no-floppy --fs-uuid --set e1dafd1c-f855-406b-8f9a-f9d527c70255 if loadfont /usr/share/grub/unicode.pf2 ; then set gfxmode=640x480 load_video insmod gfxterm fi terminal_output gfxterm insmod part_msdos insmod ext2 set root='(hd0,msdos5)' search --no-floppy --fs-uuid --set e1dafd1c-f855-406b-8f9a-f9d527c70255 set locale_dir=($root)/boot/grub/locale set lang=en insmod gettext if [ "${recordfail}" = 1 ]; then set timeout=-1 else set timeout=10 fi ### END /etc/grub.d/00_header ### ### BEGIN /etc/grub.d/05_debian_theme ### set menu_color_normal=white/black set menu_color_highlight=black/light-gray ### END /etc/grub.d/05_debian_theme ### ### BEGIN /etc/grub.d/10_linux ### menuentry 'Ubuntu, with Linux 2.6.35-22-generic' --class ubuntu --class gnu-linux --class gnu --class os { recordfail insmod part_msdos insmod ext2 set root='(hd0,msdos5)' search --no-floppy --fs-uuid --set e1dafd1c-f855-406b-8f9a-f9d527c70255 linux /boot/vmlinuz-2.6.35-22-generic root=UUID=e1dafd1c-f855-406b-8f9a-f9d527c70255 ro quiet splash initrd /boot/initrd.img-2.6.35-22-generic } menuentry 'Ubuntu, with Linux 2.6.35-22-generic (recovery mode)' --class ubuntu --class gnu-linux --class gnu --class os { recordfail insmod part_msdos insmod ext2 set root='(hd0,msdos5)' search --no-floppy --fs-uuid --set e1dafd1c-f855-406b-8f9a-f9d527c70255 echo 'Loading Linux 2.6.35-22-generic ...' linux /boot/vmlinuz-2.6.35-22-generic root=UUID=e1dafd1c-f855-406b-8f9a-f9d527c70255 ro single echo 'Loading initial ramdisk ...' initrd /boot/initrd.img-2.6.35-22-generic } ### END /etc/grub.d/10_linux ### ### BEGIN /etc/grub.d/20_linux_xen ### ### END /etc/grub.d/20_linux_xen ### ### BEGIN /etc/grub.d/20_memtest86+ ### menuentry "Memory test (memtest86+)" { insmod part_msdos insmod ext2 set root='(hd0,msdos5)' search --no-floppy --fs-uuid --set e1dafd1c-f855-406b-8f9a-f9d527c70255 linux16 /boot/memtest86+.bin } menuentry "Memory test (memtest86+, serial console 115200)" { insmod part_msdos insmod ext2 set root='(hd0,msdos5)' search --no-floppy --fs-uuid --set e1dafd1c-f855-406b-8f9a-f9d527c70255 linux16 /boot/memtest86+.bin console=ttyS0,115200n8 } ### END /etc/grub.d/20_memtest86+ ### ### BEGIN /etc/grub.d/30_os-prober ### menuentry "Windows 7 (loader) (on /dev/sda1)" { insmod part_msdos insmod ntfs set root='(hd0,msdos1)' search --no-floppy --fs-uuid --set 1266bb2766bb0a8d chainloader +1 } ### END /etc/grub.d/30_os-prober ### ### BEGIN /etc/grub.d/40_custom ### # This file provides an easy way to add custom menu entries. Simply type the # menu entries you want to add after this comment. Be careful not to change # the 'exec tail' line above. ### END /etc/grub.d/40_custom ### ### BEGIN /etc/grub.d/41_custom ### if [ -f $prefix/custom.cfg ]; then source $prefix/custom.cfg; fi ### END /etc/grub.d/41_custom ### =============================== sda5/etc/fstab: =============================== # /etc/fstab: static file system information. # # Use 'blkid -o value -s UUID' to print the universally unique identifier # for a device; this may be used with UUID= as a more robust way to name # devices that works even if disks are added and removed. See fstab(5). # # proc /proc proc nodev,noexec,nosuid 0 0 /dev/sda5 / ext4 errors=remount-ro 0 1 # swap was on /dev/sda4 during installation UUID=dd38226d-c7c9-4ae5-a726-6d18d34a22e4 none swap sw 0 0 =================== sda5: Location of files loaded by Grub: =================== 156.1GB: boot/grub/core.img 156.3GB: boot/grub/grub.cfg 149.9GB: boot/initrd.img-2.6.35-22-generic 156.3GB: boot/vmlinuz-2.6.35-22-generic 149.9GB: initrd.img 156.3GB: vmlinuz

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  • Infiniband: a highperformance network fabric - Part I

    - by Karoly Vegh
    Introduction:At the OpenWorld this year I managed to chat with interesting people again - one of them answering Infiniband deepdive questions with ease by coffee turned out to be one of Oracle's IB engineers, Ted Kim, who actually actively participates in the Infiniband Trade Association and integrates Oracle solutions with this highspeed network. This is why I love attending OOW. He granted me an hour of his time to talk about IB. This post is mostly based on that tech interview.Start of the actual post: Traditionally datatransfer between servers and storage elements happens in networks with up to 10 gigabit/seconds or in SANs with up to 8 gbps fiberchannel connections. Happens. Well, data rather trickles through.But nowadays data amounts grow well over the TeraByte order of magnitude, and multisocket/multicore/multithread Servers hunger data that these transfer technologies just can't deliver fast enough, causing all CPUs of this world do one thing at the same speed - waiting for data. And once again, I/O is the bottleneck in computing. FC and Ethernet can't keep up. We have half-TB SSDs, dozens of TB RAM to store data to be modified in, but can't transfer it. Can't backup fast enough, can't replicate fast enough, can't synchronize fast enough, can't load fast enough. The bad news is, everyone is used to this, like back in the '80s everyone was used to start compile jobs and go for a coffee. Or on vacation. The good news is, there's an alternative. Not so-called "bleeding-edge" 8gbps, but (as of now) 56. Not layers of overhead, but low latency. And it is available now. It has been for a while, actually. Welcome to the world of Infiniband. Short history:Infiniband was born as a result of joint efforts of HPAQ, IBM, Intel, Sun and Microsoft. They planned to implement a next-generation I/O fabric, in the 90s. In the 2000s Infiniband (from now on: IB) was quite popular in the high-performance computing field, powering most of the top500 supercomputers. Then in the middle of the decade, Oracle realized its potential and used it as an interconnect backbone for the first Database Machine, the first Exadata. Since then, IB has been booming, Oracle utilizes and supports it in a large set of its HW products, it is the backbone of the famous Engineered Systems: Exadata, SPARC SuperCluster, Exalogic, OVCA and even the new DB backup/recovery box. You can also use it to make servers talk highspeed IP to eachother, or to a ZFS Storage Appliance. Following Oracle's lead, even IBM has jumped the wagon, and leverages IB in its PureFlex systems, their first InfiniBand Machines.IB Structural Overview: If you want to use IB in your servers, the first thing you will need is PCI cards, in IB terms Host Channel Adapters, or HCAs. Just like NICs for Ethernet, or HBAs for FC. In these you plug an IB cable, going to an IB switch providing connection to other IB HCAs. Of course you're going to need drivers for those in your OS. Yes, these are long-available for Solaris and Linux. Now, what protocols can you talk over IB? There's a range of choices. See, IB isn't accepting package loss like Ethernet does, and hence doesn't need to rely on TCP/IP as a workaround for resends. That is, you still can run IP over IB (IPoIB), and that is used in various cases for control functionality, but the datatransfer can run over more efficient protocols - like native IB. About PCI connectivity: IB cards, as you see are fast. They bring low latency, which is just as important as their bandwidth. Current IB cards run at 56 gbit/s. That is slightly more than double of the capacity of a PCI Gen2 slot (of ~25 gbit/s). And IB cards are equipped usually with two ports - that is, altogether you'd need 112 gbit/s PCI slots, to be able to utilize FDR IB cards in an active-active fashion. PCI Gen3 slots provide you with around ~50gbps. This is why the most IB cards are configured in an active-standby way if both ports are used. Once again the PCI slot is the bottleneck. Anyway, the new Oracle servers are equipped with Gen3 PCI slots, an the new IB HCAs support those too. Oracle utilizes the QDR HCAs, running at 40gbp/s brutto, which translates to a 32gbp/s net traffic due to the 10:8 signal-to-data information ratio. Consolidation techniques: Technology never stops to evolve. Mellanox is working on the 100 gbps (EDR) version already, which will be optical, since signal technology doesn't allow EDR to be copper. Also, I hear you say "100gbps? I will never use/need that much". Are you sure? Have you considered consolidation scenarios, where (for example with Oracle Virtual Network) you could consolidate your platform to a high densitiy virtualized solution providing many virtual 10gbps interfaces through that 100gbps? Technology never stops to evolve. I still remember when a 10mbps network was impressively fast. Back in those days, 16MB of RAM was a lot. Now we usually run servers with around 100.000 times more RAM. If network infrastrucure speends could grow as fast as main memory capacities, we'd have a different landscape now :) You can utilize SRIOV as well for consolidation. That is, if you run LDoms (aka Oracle VM Server for SPARC) you do not have to add physical IB cards to all your guest LDoms, and you do not need to run VIO devices through the hypervisor either (avoiding overhead). You can enable SRIOV on those IB cards, which practically virtualizes the PCI bus, and you can dedicate Physical- and Virtual Functions of the virtualized HCAs as native, physical HW devices to your guests. See Raghuram's excellent post explaining SRIOV. SRIOV for IB is supported since LDoms 3.1.  This post is getting lengthier, so I will rename it to Part I, and continue it in a second post. 

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  • Using Windows Previous Versions to access ZFS Snapshots (July 14, 2009)

    - by user12612012
    The Previous Versions tab on the Windows desktop provides a straightforward, intuitive way for users to view or recover files from ZFS snapshots.  ZFS snapshots are read-only, point-in-time instances of a ZFS dataset, based on the same copy-on-write transactional model used throughout ZFS.  ZFS snapshots can be used to recover deleted files or previous versions of files and they are space efficient because unchanged data is shared between the file system and its snapshots.  Snapshots are available locally via the .zfs/snapshot directory and remotely via Previous Versions on the Windows desktop. Shadow Copies for Shared Folders was introduced with Windows Server 2003 but subsequently renamed to Previous Versions with the release of Windows Vista and Windows Server 2008.  Windows shadow copies, or snapshots, are based on the Volume Snapshot Service (VSS) and, as the [Shared Folders part of the] name implies, are accessible to clients via SMB shares, which is good news when using the Solaris CIFS Service.  And the nice thing is that no additional configuration is required - it "just works". On Windows clients, snapshots are accessible via the Previous Versions tab in Windows Explorer using the Shadow Copy client, which is available by default on Windows XP SP2 and later.  For Windows 2000 and pre-SP2 Windows XP, the client software is available for download from Microsoft: Shadow Copies for Shared Folders Client. Assuming that we already have a shared ZFS dataset, we can create ZFS snapshots and view them from a Windows client. zfs snapshot tank/home/administrator@snap101zfs snapshot tank/home/administrator@snap102 To view the snapshots on Windows, map the dataset on the client then right click on a folder or file and select Previous Versions.  Note that Windows will only display previous versions of objects that differ from the originals.  So you may have to modify files after creating a snapshot in order to see previous versions of those files. The screenshot above shows various snapshots in the Previous Versions window, created at different times.  On the left panel, the .zfs folder is visible, illustrating that this is a ZFS share.  The .zfs setting can be toggled as desired, it makes no difference when using previous versions.  To make the .zfs folder visible: zfs set snapdir=visible tank/home/administrator To hide the .zfs folder: zfs set snapdir=hidden tank/home/administrator The following screenshot shows the Previous Versions panel when a file has been selected.  In this case the user is prompted to view, copy or restore the file from one of the available snapshots. As can be seen from the screenshots above, the Previous Versions window doesn't display snapshot names: snapshots are listed by snapshot creation time, sorted in time order from most recent to oldest.  There's nothing we can do about this, it's the way that the interface works.  Perhaps one point of note, to avoid confusion, is that the ZFS snapshot creation time isnot the same as the root directory creation timestamp. In ZFS, all object attributes in the original dataset are preserved when a snapshot is taken, including the creation time of the root directory.  Thus the root directory creation timestamp is the time that the directory was created in the original dataset. # ls -d% all /home/administrator         timestamp: atime         Mar 19 15:40:23 2009         timestamp: ctime         Mar 19 15:40:58 2009         timestamp: mtime         Mar 19 15:40:58 2009         timestamp: crtime         Mar 19 15:18:34 2009 # ls -d% all /home/administrator/.zfs/snapshot/snap101         timestamp: atime         Mar 19 15:40:23 2009         timestamp: ctime         Mar 19 15:40:58 2009         timestamp: mtime         Mar 19 15:40:58 2009         timestamp: crtime         Mar 19 15:18:34 2009 The snapshot creation time can be obtained using the zfs command as shown below. # zfs get all tank/home/administrator@snap101NAME                             PROPERTY  VALUEtank/home/administrator@snap101  type      snapshottank/home/administrator@snap101  creation  Mon Mar 23 18:21 2009 In this example, the dataset was created on March 19th and the snapshot was created on March 23rd. In conclusion, Shadow Copies for Shared Folders provides a straightforward way for users to view or recover files from ZFS snapshots.  The Windows desktop provides an easy to use, intuitive GUI and no configuration is required to use or access previous versions of files or folders. REFERENCES FOR MORE INFORMATION ZFS ZFS Learning Center Introduction to Shadow Copies of Shared Folders Shadow Copies for Shared Folders Client

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  • Easing the Journey to the Private Cloud with Oracle Consulting

    - by MichaelM-Oracle
    By Sanjai Marimadaiah, Senior Director, Strategy & Business Development – Cloud Solutions, Oracle Consulting Services Business leaders are now leading the charge on how their firms can profit from cloud solutions. Agility and innovation are becoming the primary drivers of the business case for the cloud, even more than the anticipated cost savings. Leaders need to find the right strategy and optimize the use of cloud-based applications across their enterprise-computing infrastructure. The Problem – Current State With prevalent IT practices, many organizations find that they run multiple IT solutions serving similar business needs. This has led to the proliferation of technology stacks, for example: Oracle 10g on Sun T4 running Solaris 9; Oracle 11g on Exadata running Linux; or Oracle 12c on commodity x86 servers. This variance has a huge impact on an organization’s agility and expenses, and requires IT professionals with varied skills as well as on-going training for different systems and tools. Fortunately there is a practical business strategy to overcome this unneeded redundancy. Thus begins a journey to the right cloud computing solution. The Solution – Cloud Services from Oracle Consulting Services (OCS) Oracle Consulting Services (OCS ) works closely with our clients as trusted advisors to proactively respond to business needs and IT concerns. OCS understands that making the transition to cloud solutions begins with a strategic conversation, based on its deep expertise for successfully completing private cloud service engagements with several companies. For a journey to the cloud, Oracle Consulting Services leads the client through four phases– standardization, consolidation, service delivery, and enterprise cloud – to achieve optimal returns. Phase 1 - Standardization Oracle Consulting Services (OCS) works with clients to evaluate their business requirements and propose a set of standard solutions stacks for various IT solutions. This is an opportune time to evaluate cloud ready solutions, such as Oracle 12c, Oracle Exadata, and the Oracle Database Appliance (ODA). The OCS consultants, together with the delivery team, then turn to upgrading and migrating existing solution stacks to standardized offerings. OCS has the expertise and tools to complete this stage in a fraction of the time required by other IT services companies. Clients quickly realize cost savings in tools, processes, and type/number of resources required. This standardization also improves agility of the IT organizations and their abilities to respond to the needs of various business units. Phase 2 - Consolidation During the consolidation phase, OCS consultants programmatically consolidate hundreds of databases into a smaller number of servers to improve utilization, reduce floor space, and optimize maintenance costs. Consolidation helps clients realize huge savings in CapEx investments and shrink OpEx costs. The use of engineered systems, such as Oracle Exadata, greatly reduces the client’s risk of moving to a new solution stack. OCS recommends clients to pursue Phase 1 (Standardization) and Phase 2 (Consolidation) simultaneously to reduce the overall time, effort, and expense of the cloud journey. Phase 3 - Service Delivery Once a client is on a path of standardization and consolidation, OCS consultants create Service Catalogues based on the SLAs requirements and the criticality of the solutions. The number and types of Service Catalogues (Platinum, Gold, Silver, Bronze, etc.) vary from client to client. OCS consultants also implement a variety of value-added cloud solutions, including monitoring, metering, and charge-back solutions. At this stage, clients are able to achieve a high level of understanding in their cloud journey. Their IT organizations are operating efficiently and are more agile in responding to the needs of business units. Phase 4 - Enterprise Cloud In the final phase of the cloud journey, the economics of the IT organizations change. Business units can request services on-demand; applications can be deployed and consumed on a pay-as-you-go model. OCS has the expertise and capabilities to establish processes, programs, and solutions required for IT organizations to transform how they interact with business units. The Promise of Cloud Solutions Depending the size and complexity of their business model, some clients are able to abbreviate some phases of their cloud journey. Cloud solutions are still evolving and there is rapid pace of innovation to transform how IT organizations operate. The lesson is clear. Cloud solutions hold a lot of promise for business agility. Business leaders can now leverage an additional set of capabilities and services. They can ramp up their pace of innovation. With cloud maturity, they can compete more effectively in their respective markets. But there are certainly challenges ahead. A skilled consulting services partner can play a pivotal role as a trusted advisor in the successful adoption of cloud solutions. Oracle Consulting Services has expertise and a portfolio of services to help clients succeed on their journey to the cloud.

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