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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • MySQL: Combining multiple where conditions

    - by Karl
    I'm working on a menu system that takes a url and then queries the db to build the menu. My menu table is: +---------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | node_id | int(11) | YES | | NULL | | | parent | int(11) | YES | | NULL | | | weight | int(11) | YES | | NULL | | | title | varchar(250) | YES | | NULL | | | alias | varchar(250) | YES | | NULL | | | exclude | int(11) | YES | | NULL | | +---------+--------------+------+-----+---------+----------------+ The relevant columns for my question are alias, parent and node_id. So for a url like: http://example.com/folder1/folder2/filename Alias would potentially = "filename", "folder1", "folder2" Parent = the node_id of the parent folder. What I know is how to split the url up into an array and check the alias for a match to each part. What I don't know is how to have it then filter by parent whose alias matches "folder2" and whose parent alias matches "folder1". I'm imagining a query like so: select * from menu where alias='filename' and where parent = node_id where alias='folder2' and parent = node_id where alias='folder1' Except I know that the above is wrong. I'm hoping this can be done in a single query. Thanks for any help in advance!

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  • Formatting the output of a custom tool so I can double click an error in Visual Studio and the file opens

    - by Ben Scott
    I've written a command line tool that preprocesses a number of files then compiles them using CodeDom. The tool writes a copyright notice and some progress text to the standard output, then writes any errors from the compilation step using the following format: foreach (var err in results.Errors) { // err is CompilerError var filename = "Path\To\input_file.xprt"; Console.WriteLine(string.Format( "{0} ({1},{2}): {3}{4} ({5})", filename, err.Line, err.Column, err.IsWarning ? "" : "ERROR: ", err.ErrorText, err.ErrorNumber)); } It then writes the number of errors, like "14 errors". This is an example of how the error appears in the console: Path\To\input_file.xrpt (73,28): ERROR: An object reference is required for the non-static field, method, or property 'Some.Object.get' (CS0120) When I run this as a custom tool in VS2008 (by calling it in the post-build event command line of one of my project's assemblies), the errors appear nicely formatted in the Error List, with the correct text in each column. When I roll over the filename the fully qualified path pops up. The line and column are different to the source file because of the preprocessing which is fine. The only thing that stands out is that the Project given in the list is the one that has the post-build event. The problem is that when I double click an error, nothing happens. I would have expected the file to open in the editor. I'm vaugely aware of the Microsoft.VisualStudio.Shell.Interop namespace but I think it should be possible just by writing to the standard output.

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  • PHP's fopen is terminally failing

    - by Skittles
    Okay, I have GOT to be missing something totally rudimentary here. I have an extremely simple use of PHP's fopen function, but for some reason, it will not open the file no matter what I do. The odd part about this is that I use fopen in another function in the same script and it's working perfectly. I'm using the fclose in both functions. So, I know it's not a matter of a rogue file handle. I have confirmed the file's path and the existence of the target file also. I'm running the script at the command-line as root, so I know it's not apache that's the cause. And since I am running the script as root, I am fairly confident that permissions are not the issue. So, what on earth am I missing here? function get_file_list() { $file = '/home/site/tmp/return_files_list.txt'; $fp = fopen($file, 'r') or die("Could not open file: /home/site/tmp/return_files_list.txt for reading.\n"); $files_list = array(); while($line = fgets($fp)) { $files_list[] = $line; } fclose($fp); return $files_list; } function num_records_in_file($filename) { $fp = fopen( $filename, 'r' ); # or die("Could not open file: $filename\n"); $counter = 0; if ($fp) { while (!feof( $fp )) { $line = fgets( $fp ); $arr = explode( '|', $line ); if (( ( $arr[0] != 'HDR' && $arr[0] != 'TRL' ) && $arr[0] != '' )) { ++$counter; continue; } } } fclose( $fp ); return $counter; } As requested, here's both functions. The second function is passed an absolute path to the file. That is what I used to confirm that the file is there and that the path is correct.

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  • ASP.NET Image Upload Parameter Not Valid. Exception

    - by pennylane
    Hi Guys, Im just trying to save a file to disk using a posted stream from jquery uploadify I'm also getting Parameter not valid. On adding to the error message so i can tell where it blew up in production im seeing it blow up on: var postedBitmap = new Bitmap(postedFileStream) any help would be most appreciated public string SaveImageFile(Stream postedFileStream, string fileDirectory, string fileName, int imageWidth, int imageHeight) { string result = ""; string fullFilePath = Path.Combine(fileDirectory, fileName); string exhelp = ""; if (!File.Exists(fullFilePath)) { try { using (var postedBitmap = new Bitmap(postedFileStream)) { exhelp += "got past bmp creation" + fullFilePath; using (var imageToSave = ImageHandler.ResizeImage(postedBitmap, imageWidth, imageHeight)) { exhelp += "got past resize"; if (!Directory.Exists(fileDirectory)) { Directory.CreateDirectory(fileDirectory); } result = "Success"; postedBitmap.Dispose(); imageToSave.Save(fullFilePath, GetImageFormatForFile(fileName)); } exhelp += "got past save"; } } catch (Exception ex) { result = "Save Image File Failed " + ex.Message + ex.StackTrace; Global.SendExceptionEmail("Save Image File Failed " + exhelp, ex); } } return result; }

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  • kQuery : Trying to find a specific instance of a class by number

    - by mattelliottIT
    I guess I have just hit a mental block with this one; maybe some fresh eyes will help. Basically I have a few instance of the class "menu-item" which when clicked call the click function via jQuery and bring up a video. Instead of giving each on an id as well as a class I am trying to find which instance of the class was clicked (1, 2, 3, etc). Just can't seem to get it though. //click listener for menu-items $('.menu-item').click(function(event) { var o = $('.menu-item'); var count = o.length(); // switch(count) { case 0 : filename == 'letters'; break; case 1 : filename == 'the-gift'; break; } var videoPlayer = '<video controls width="618px">'; videoPlayer += '<source src="_video/' + filename + '.mp4" />'; videoPlayer += '</video>'; //place video $('#videoCont').html(videoPlayer); }); I'm trying to create an array there where each instance of the 'menu-item' is one array item. (btw, for now I am just proofing this with an mp4 filetype before I add in the ogv and webm formats). Thanks for any and all help!

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  • CSV is actually .... Semicolon Separated Values ... (Excel export on AZERTY)

    - by Bugz R us
    I'm a bit confused here. When I use Excel 2003 to export a sheet to CSV, it actually uses semicolons ... Col1;Col2;Col3 shfdh;dfhdsfhd;fdhsdfh dgsgsd;hdfhd;hdsfhdfsh Now when I read the csv using Microsoft drivers, it expects comma's and sees the list as one big column ??? I suspect Excel is exporting with semicolons because I have a AZERTY keyboard. However, doesn't the CSV reader then also have to take in account the different delimiter ? How can I know the appropriate delimiter, and/or read the csv properly ?? public static DataSet ReadCsv(string fileName) { DataSet ds = new DataSet(); string pathName = System.IO.Path.GetDirectoryName(fileName); string file = System.IO.Path.GetFileName(fileName); OleDbConnection excelConnection = new OleDbConnection (@"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + pathName + ";Extended Properties=Text;"); try { OleDbCommand excelCommand = new OleDbCommand(@"SELECT * FROM " + file, excelConnection); OleDbDataAdapter excelAdapter = new OleDbDataAdapter(excelCommand); excelConnection.Open(); excelAdapter.Fill(ds); } catch (Exception exc) { throw exc; } finally { if(excelConnection.State != ConnectionState.Closed ) excelConnection.Close(); } return ds; }

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  • wxPython: MainLoop() seems to hang

    - by BandGap
    Hi all, my problem stems from the use of wxApp as far as I can tell. Inside a litte subroutine I call a wx.MessageDialog to ask for a yes or no. I retrieve the answer an process some stuff acordingly. My example code below actually works (though it might be ugly) except that the Dialog box stays open after hitting one of the buttons... import wx from os import path def HasFile(filename): if path.isfile(filename ): app = wx.App() dial = wx.MessageDialog(None, 'Die Datei "'+filename+'" wurde gefunden.\nSoll sie eingelesen werden?', 'Bitte antworten', wx.YES_NO | wx.YES_DEFAULT | wx.ICON_QUESTION) result = dial.ShowModal() dial.EndModal(retCode=0) dial.Destroy() app.MainLoop() return result == wx.ID_YES else: return False So while the rest of the program does whatever is expected, the box just sits there. It also seems like my calls to matplotlib later on are producing errors (a Tkinter error to be precise), maybe because of the wx stuff? Edit: I tried to end the app with a call to app.Destroy(). This doesn't change the fact that the box is still there. When I issue a app.IsActive() afterwards the whole program exits (almost like a sys.exit())! How come? Edit 2: Adding a wxApp like this isn't a good idea since the other scripts get affected as well. Subsequent plotting commands don't get displayed and I don't know how to fix this. Thus I decided to remove the DialogBox alltogether.

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  • memory leak when removing objects in NSMutableArray

    - by user262325
    Hello everyone I hope to store MYFileObj to NSMutableArray (fileArray) and display data on an UITavleView(tableview). //----------------------------------MYFileObj #import <UIKit/UIKit.h> @interface MYFileObj : NSObject { NSString *fileName; } -(void) setFileName:(NSString *)s ; -(NSString *) fileName ; @end the array I want to store data NSMutableArray *fileArray; I created new object and add to fileArray MYFileObj *newobj=[[MYFileObj alloc] init ]; NSString *ss=[[NSString alloc] initWithFormat:@"%@",path] ; [newobj setFileName:ss]; [ss release]; [fileArray addObject:newobj]; [newobj release]; [atableview reloadData]; After the first time relaodData and do something, I want to reload fileArray and redraw atableview. //code to remove all object in atableview if([fileArray count]>0) { [fileArray removeAllObjects]; [atableview reloadData]; } I notice that there are memory leak. I hope to know the method "removeAllObjects" removes only MYFileObj themselves or also removes MYFileObj's member property "fileName"? Thanks interdev

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  • How good idea is it to use code contracts in Visual Studio 2010 Professional (ie. no static checking

    - by Lasse V. Karlsen
    I create class libraries, some which are used by others around the world, and now that I'm starting to use Visual Studio 2010 I'm wondering how good idea it is for me to switch to using code contracts, instead of regular old-style if-statements. ie. instead of this: if (String.IsNullOrWhiteSpace(fileName)) throw new ArgumentNullException("fileName"); (yes, I know, if it is whitespace, it isn't strictly null) use this: Contract.Requires(!String.IsNullOrWhiteSpace(fileName)); The reason I'm asking is that I know that the static checker is not available to me, so I'm a bit nervous about some assumptions that I make, that the compiler cannot verify. This might lead to the class library not compiling for someone that downloads it, when they have the static checker. This, coupled with the fact that I cannot even reproduce the problem, would make it tiresome to fix, and I would gather that it doesn't speak volumes to the quality of my class library if it seemingly doesn't even compile out of the box. So I have a few questions: Is the static checker on by default if you have access to it? Or is there a setting I need to switch on in the class library (and since I don't have the static checker, I won't) Are my fears unwarranted? Is the above scenario a real problem? Any advice would be welcome.

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  • Better way to download a binary file?

    - by geoff
    I have a site where a user can download a file. Some files are extremely large (the largest being 323 MB). When I test it to try and download this file I get an out of memory exception. The only way I know to download the file is below. The reason I'm using the code below is because the URL is encoded and I can't let the user link directly to the file. Is there another way to download this file without having to read the whole thing into a byte array? FileStream fs = new FileStream(context.Server.MapPath(url), FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fs); long numBytes = new FileInfo(context.Server.MapPath(url)).Length; byte[] bytes = br.ReadBytes((int) numBytes); string filename = Path.GetFileName(url); context.Response.Buffer = true; context.Response.Charset = ""; context.Response.Cache.SetCacheability(HttpCacheability.NoCache); context.Response.ContentType = "application/x-rar-compressed"; context.Response.AddHeader("content-disposition", "attachment;filename=" + filename); context.Response.BinaryWrite(bytes); context.Response.Flush(); context.Response.End();

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  • OpenSceneGraph C++ Access Violation reading location 0x00421000

    - by Kobojunkie
    Working with OpenSceneGraph, and I keep running into this violation issue that I would appreciate some help with. The problem is with the particular line below which happens to be the first in my main function. osg::ref_ptr<osg::Node> bench = osgDB::readNodeFile("Models/test.IVE"); I have my models folder right in my directory. The error is as below. Unhandled exception at 0x68630A6C (msvcr100.dll) in OSG3D.exe: 0xC0000005: Access violation reading location 0x00421000. And this is where the problem seems to be coming up. /** Read an osg::Node from file. * Return valid osg::Node on success, * return NULL on failure. * The osgDB::Registry is used to load the appropriate ReaderWriter plugin * for the filename extension, and this plugin then handles the request * to read the specified file.*/ inline osg::Node* readNodeFile(const std::string& filename) { return readNodeFile(filename,Registry::instance()->getOptions()); } I would appreciate details on how best to tackle this kind of exception message in the future. Are there tools that make this easy to debug or are there ways to capture the exact issues and fix them? I would appreciate any help with this. My ultimate goal is to learn how to better debug C++ related issues please. With this, it means reading through the compiler error list http://msdn.microsoft.com/en-us/library/850cstw1(v=vs.71).aspx is not enough

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  • Using the read function to read in a file.

    - by robUK
    Hello, gcc 4.4.1 I am using the read function to read in a wave file. However, when it gets to the read function. Execution seems to stop and freezes. I am wondering if I am doing anything wrong with this. The file size test-short.wave is: 514K. What I am aiming for is to read the file into the memory buffer chunks at a time. Currently I just testing this. Many thanks for any suggestions, #include <stdio.h> #include <stdlib.h> #include <errno.h> #include <fcntl.h> #include <string.h> #include <unistd.h> int main(void) { char buff = malloc(10240); int32_t fd = 0; int32_t bytes_read = 0; char *filename = "test-short.wav"; /* open wave file */ if((fd = (open(filename, O_RDWR)) == -1)) { fprintf(stderr, "open [ %s ]\n", strerror(errno)); return 1; } printf("Opened file [ %s ]\n", filename); printf("sizeof(buff) [ %d ]\n", sizeof(buff)); printf("strlen(buff) [ %d ]\n", strlen(buff)); bytes_read = read(fd, buff, sizeof(buff)); printf("Bytes read [ %d ]\n", bytes_read); return 0; }

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  • How to get from JRuby a correctly typed ruby implementation of a Java interface?

    - by Guss
    I'm trying to use JRuby (through the JSR233 interface included in JRuby 1.5) from a Java application to load a ruby implementation of a Java interface. My sample implementation looks like this: Interface: package some.package; import java.util.List; public interface ScriptDemoIf { int fibonacci(int d); List<String> filterLength(List<String> source, int maxlen); } Ruby Implementation: require 'java' include Java class ScriptDemo java_implements some.package.ScriptDemoIf java_signature 'int fibonacci(int d)' def fibonacci(d) d < 2 ? d : fibonacci(d-1) + fibonacci(d-2) end java_signature 'List<String> filterLength(List<String> source, int maxlen)' def filterLength(source, maxlen) source.find_all { |str| str.length <= maxlen } end end Class loader: public ScriptDemoIf load(String filename) throws ScriptException { ScriptEngine engine = new ScriptEngineManager().getEngineByName("jruby"); FileReader script = new FileReader(filename); try { engine.eval(new FileReader(script)); } catch (FileNotFoundException e) { throw new ScriptException("Failed to load " + filename); } return (ScriptDemoIf) m_engine.eval("ScriptDemo.new"); } (Obviously the loader is a bit more generic in real life - it doesn't assume that the implementation class name is "ScriptDemo" - this is just for simplicity). Problem - I get a class cast exception in the last line of the loader - the engine.eval() return a RubyObject type which doesn't cast down nicely to my interface. From stuff I read all over the web I was under the impression that the whole point of use java_implements in the Ruby section was for the interface implementations to be compiled in properly. What am I doing wrong?

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  • How to have synchronous writing to a file (Threads) ?

    - by bobby
    Hi all. I created and started some Threads that each one writes something to a common text file. but the following error appears to me: "The process cannot access the file 'C:\hello.txt' because it is being used by another process." void AccessFile() { int num = 5; Thread[] trds = new Thread[5]; for (int i = 0; i < num; i++) { trds[i] = new Thread(new ParameterizedThreadStart(WriteToFile)); } for (int i = 0; i < num; i++) { trds[i].Start(String.Format("{0}: Hello from thread id:#{1}", i, trds[i].ManagedThreadId)); } } void WriteToFile(object message) { string FileName = "C:\\hello.txt"; string mess = (string)message; System.IO.StreamWriter sw = null; FileStream objStream = null; sw = File.AppendText(FileName); if (sw == null) { objStream = new FileStream(FileName, FileMode.OpenOrCreate, FileAccess.ReadWrite, FileShare.ReadWrite); sw = new StreamWriter(objStream); } sw.WriteLine(mess); sw.Close(); sw.Dispose(); } the AccessFile() method is the starting point. could any one tell me what should i do?

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  • Making A Dynaically Created Excel Report Downloadable

    - by Nick LaMarca
    I have 2 blocks of code, if someone could help me put them together I would get the functionality I am looking for. The first block of code downloads a gridview to excel using the download dialog I am looking for: Public Overloads Overrides Sub VerifyRenderingInServerForm(ByVal control As Control) ' Verifies that the control is rendered End Sub Private Sub ExportToExcel(ByVal filename As String, ByVal gv As GridView, ByVal numOfCol As Integer) Response.Clear() Response.Buffer = True Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", filename)) Response.Charset = "" Response.ContentType = "application/vnd.ms-excel" Dim sw As New StringWriter() Dim hw As New HtmlTextWriter(sw) gv.AllowPaging = False gv.DataBind() 'Change the Header Row back to white color gv.HeaderRow.Style.Add("background-color", "#FFFFFF") For i As Integer = 0 To numOfCol - 1 gv.HeaderRow.Cells(i).Style.Add("background-color", "blue") gv.HeaderRow.Cells(i).Style.Add("color", "#FFFFFF") Next For i As Integer = 0 To gv.Rows.Count - 1 Dim row As GridViewRow = gv.Rows(i) 'Change Color back to white row.BackColor = System.Drawing.Color.White For j As Integer = 0 To numOfCol - 1 row.Cells(j).Style.Add("text-align", "center") Next 'Apply text style to each Row row.Attributes.Add("class", "textmode") 'Apply style to Individual Cells of Alternating Row If i Mod 2 <> 0 Then For j As Integer = 0 To numOfCol - 1 row.Cells(j).Style.Add("background-color", "#CCFFFF") row.Cells(j).Style.Add("text-align", "center") '#C2D69B 'row.Cells(j).Style.Add("font-size", "12pt") Next End If Next gv.RenderControl(hw) 'style to format numbers to string Dim style As String = "<style> .textmode { mso-number-format:\@; } </style>" Response.Write(style) Response.Output.Write(sw.ToString()) Response.Flush() Response.End() End Sub The second block of code is a sample report I am wish to be downloaded. So instead of downloading a gridview I want this function to accept a worksheet object.

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  • how to tune BufferedInputStream read()?

    - by technomax
    I am reading a BLOB column from a Oracle database, then writing it to a file as follows: public static int execute(String filename, BLOB blob) { int success = 1; try { File blobFile = new File(filename); FileOutputStream outStream = new FileOutputStream(blobFile); BufferedInputStream inStream = new BufferedInputStream(blob.getBinaryStream()); int length = -1; int size = blob.getBufferSize(); byte[] buffer = new byte[size]; while ((length = inStream.read(buffer)) != -1) { outStream.write(buffer, 0, length); outStream.flush(); } inStream.close(); outStream.close(); } catch (Exception e) { e.printStackTrace(); System.out.println("ERROR(img_exportBlob) Unable to export:"+filename); success = 0; } } The file size is around 3MB and it takes 40-50s to read the buffer. Its actually a 3D image data. So, is there any way by which I can reduce this time?

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  • Update paths of already-created Paperclip attachments

    - by Horace Loeb
    I used to have this buggy Paperclip config: class Photo < ActiveRecord::Base has_attached_file :image, :storage => :s3, :styles => { :medium => "600x600>", :small => "320x320>", :thumb => "100x100#" }, :s3_credentials => "#{RAILS_ROOT}/config/s3.yml", :path => "/:style/:filename" end This is buggy because two images cannot have the same size and filename. To fix this, I changed the config to: class Photo < ActiveRecord::Base has_attached_file :image, :storage => :s3, :styles => { :medium => "600x600>", :small => "320x320>", :thumb => "100x100#" }, :s3_credentials => "#{RAILS_ROOT}/config/s3.yml", :path => "/:style/:id_:filename" end Unfortunately this breaks all URLs to attachments I've already created. How can I update those file paths or otherwise get the URLs to work?

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  • incapsulation of a code inmatlab

    - by user531225
    my code is pathname=uigetdir; filename=uigetfile('*.txt','choose a file name.'); data=importdata(filename); element= (data.data(:,10)); in_array=element; pattern= [1 3]; locations = cell(1, numel(pattern)); for p = 1:(numel(pattern)) locations{p} = find(in_array == pattern(p)); end idx2 = []; for p = 1:numel(locations{1}) start_value = locations{1}(p); for q = 2:numel(locations) found = true; if (~any((start_value + q - 1) == locations{q})) found = false; break; end end if (found) idx2(end + 1) = locations{1}(p); end end [m2,n2]=size(idx2) res_name= {'one' 'two'}; res=[n n2]; In this code I finding a pattern in one of the column of my data file and counting how many times it's repeated. I have like 200 files that I want to do the same with them but unfotunatlly I'm stuck. this is what I have added so far pathname=uigetdir; files=dir('*.txt'); for k=1:length(files) filename=files(k).name; data(k)=importdata(files(k).name); element{k}=data(1,k).data(:,20); in_array=element;pattern= [1 3]; locations = cell(1, numel(pattern)); for p = 1:(numel(pattern)) locations{p} = find(in_array{k}== pattern(p)); end idx2{k} = []; how can I continue this code..??

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  • Undefined method 'size' for #<File:text.txt> (NoMethodError)

    - by user1354456
    This is the code I am running, it does fine until I get to line 15. The command I run is: ruby ex16.rb text.txt. This is a practice sample I'm writing which is meant to be a simple little text editor: filename = ARGV.first script = $0 puts "We're going to erase #{filename}." puts "if you don't want that, hit CTRL-C (^C)." puts "If you do want that, hit RETURN." print "? " STDIN.gets puts "Opening the file..." target = File.open(filename, 'w') puts "Truncating the file. Goodbye!" target.truncate(target.size) puts "Now I'm going to ask you for three lines." print "line 1: "; line1 = STDIN.gets.chomp() print "line 2: "; line2 = STDIN.gets.chomp() print "line 3: "; line3 = STDIN.gets.chomp()undefined method 'size' puts "I'm going to write these to the file." target.write(line1) target.write("\n") target.write(line2) target.write("\n") target.write(line3) target.write("\n") puts "And finally, we close it." target.close()

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  • Question about <foreach> task and the failonerror attribute?

    - by Mike M
    Hi guys, I have made a build file for the automated compilation of Oracle Forms files. An excerpt of the code is as follows: <target name="build" description="compiles the source code"> ... <foreach item="File" property="filename" failonerror="false" > <in> <items basedir="${source.directory}\${project.type}\Forms"> <include name="*.fmb" /> </items> </in> <do> <exec program="${forms.path}" workingdir="${source.directory}\${project.type}\Forms" commandline="module=${filename} userid=${username}/${password}@${database} batch=yes module_type=form compile_all=yes window_state=minimize" /> </do> </foreach> ... </target> The build file navigates to the directory containing the forms that the user desires fo compile and attempts to compile each form. The failonerror attribute is set to false so that the build file does not exit if a compilation error occurs. Unfortunately, however, though this prevents the build file from exiting when a compilation error occurs, it also appears to make the build file exit the task. This is a problem because, unless the form that does not compile successfully is the last to be tested (based on the filename of the form in alphanumerical decsending order), there will be one or more forms that the build file does not attempt to compile. So, for example, if the folder containing the forms that are desired to be compiled contains 10 forms and the first form does not compile successfully, the build file will not attempt to compile the remaining 9 forms (ie exit the task). Is there a way to make the build file attempt to compile remaining forms after encountering after failing to compile a form? Thanks in advance!

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  • send multiple file over TCP with C# using TcpClient

    - by xnoor
    I'm trying to send multiple files over TCP using C# TcpClient, for a single file it works great, but when I have multiple files, it sends only the first one. Here is my code: SENDING FILES try { TcpClient tcpClient = new TcpClient(); NetworkStream networkStream; FileStream fileStream = null; tcpClient.Connect(appUpdateMessage.receiverIpAddress, 12000); networkStream = tcpClient.GetStream(); byte[] byteSend = new byte[tcpClient.ReceiveBufferSize]; string startupPath = System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase).Substring(6); DirectoryInfo directoriesInfo = new DirectoryInfo(startupPath); DirectoryInfo[] directories = directoriesInfo.GetDirectories(); FileInfo[] files = directoriesInfo.GetFiles(); for (int iLoop = 0; iLoop < directories.Length; iLoop++) { FileInfo[] subdirectoryFiles = directories[iLoop].GetFiles(); foreach (FileInfo fi in subdirectoryFiles) { fileStream = new FileStream(fi.FullName, FileMode.Open, FileAccess.Read); BinaryReader binFile = new BinaryReader(fileStream); FileUpdateMessage fileUpdateMessage = new FileUpdateMessage(); fileUpdateMessage.fileName = fi.Name; fileUpdateMessage.fileSize = fi.Length; fileUpdateMessage.targetDirectory = fi.Directory.Name; MessageContainer messageContainer = new MessageContainer(); messageContainer.messageType = MessageType.FileProperties; messageContainer.messageContnet = SerializationManager.XmlFormatterObjectToByteArray(fileUpdateMessage); byte[] messageByte = SerializationManager.XmlFormatterObjectToByteArray(messageContainer); networkStream.Write(messageByte, 0, messageByte.Length); int bytesSize = 0; byte[] downBuffer = new byte[2048]; while ((bytesSize = fileStream.Read(downBuffer, 0, downBuffer.Length)) > 0) { networkStream.Write(downBuffer, 0, bytesSize); } fileStream.Close(); } } tcpClient.Close(); networkStream.Close(); return true; } catch (Exception ex) { //logger.Info(ex.Message); return false; } finally { } RECEIVING FILES try { TcpClient tcpClient = c as TcpClient; NetworkStream networkstream = tcpClient.GetStream(); FileStream fileStream = null; byte[] _data = new byte[1024]; int _bytesRead = 0; _bytesRead = networkstream.Read(_data, 0, _data.Length); MessageContainer messageContainer = new MessageContainer(); messageContainer = SerializationManager.XmlFormatterByteArrayToObject(_data, messageContainer) as MessageContainer; switch (messageContainer.messageType) { case MessageType.FileProperties: FileUpdateMessage fileUpdateMessage = new FileUpdateMessage(); fileUpdateMessage = SerializationManager.XmlFormatterByteArrayToObject(messageContainer.messageContnet, fileUpdateMessage) as FileUpdateMessage; string startupPath = @"d:updatefolder";//System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase).Substring(6); DirectoryInfo mainDirectory = new DirectoryInfo(startupPath); DirectoryInfo targetDirecotry = new DirectoryInfo(startupPath + "\\" + fileUpdateMessage.targetDirectory); if (!targetDirecotry.Exists) { mainDirectory.CreateSubdirectory(fileUpdateMessage.targetDirectory); } fileStream = new FileStream(startupPath + "\\" + fileUpdateMessage.targetDirectory + "\\" + fileUpdateMessage.fileName, FileMode.Create, FileAccess.Write, FileShare.ReadWrite); long filezie = fileUpdateMessage.fileSize; int byteSize = 0; byte[] downBuffer = new byte[2048]; while ((byteSize = networkstream.Read(downBuffer, 0, downBuffer.Length)) > 0) { fileStream.Write(downBuffer, 0, byteSize); if (this.InvokeRequired) { this.Invoke((MethodInvoker)delegate { //progressBar1.Value = Convert.ToInt32((byteSize * 100) / fileUpdateMessage.fileSize); progressBar1.Value = Convert.ToInt32((fileStream.Length * 100) / fileUpdateMessage.fileSize); lblFileName.Text = fileUpdateMessage.fileName; }); } else { //progressBar1.Value = Convert.ToInt32((byteSize * 100) / fileUpdateMessage.fileSize); lblFileName.Text = fileUpdateMessage.fileName; } } fileStream.Close(); networkstream.Close(); break; } } catch (Exception ex) { //logger.Error(ex.Message); } Any idea what I am doing wrong?

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  • 500 internal server error on certain page after a few hours

    - by Brian Leach
    I am getting a 500 Internal Server Error on a certain page of my site after a few hours of being up. I restart uWSGI instance with uwsgi --ini /home/metheuser/webapps/ers_portal/ers_portal_uwsgi.ini and it works again for a few hours. The rest of the site seems to be working. When I navigate to my_table, I am directed to the login page. But, I get the 500 error on my table page on login. I followed the instructions here to set up my nginx and uwsgi configs. That is, I have ers_portal_nginx.conf located i my app folder that is symlinked to /etc/nginx/conf.d/. I start my uWSGI "instance" (not sure what exactly to call it) in a Screen instance as mentioned above, with the .ini file located in my app folder My ers_portal_nginx.conf: server { listen 80; server_name www.mydomain.com; location / { try_files $uri @app; } location @app { include uwsgi_params; uwsgi_pass unix:/home/metheuser/webapps/ers_portal/run_web_uwsgi.sock; } } My ers_portal_uwsgi.ini: [uwsgi] #user info uid = metheuser gid = ers_group #application's base folder base = /home/metheuser/webapps/ers_portal #python module to import app = run_web module = %(app) home = %(base)/ers_portal_venv pythonpath = %(base) #socket file's location socket = /home/metheuser/webapps/ers_portal/%n.sock #permissions for the socket file chmod-socket = 666 #uwsgi varible only, does not relate to your flask application callable = app #location of log files logto = /home/metheuser/webapps/ers_portal/logs/%n.log Relevant parts of my views.py data_modification_time = None data = None def reload_data(): global data_modification_time, data, sites, column_names filename = '/home/metheuser/webapps/ers_portal/app/static/' + ec.dd_filename mtime = os.stat(filename).st_mtime if data_modification_time != mtime: data_modification_time = mtime with open(filename) as f: data = pickle.load(f) return data @a bunch of authentication stuff... @app.route('/') @app.route('/index') def index(): return render_template("index.html", title = 'Main',) @app.route('/login', methods = ['GET', 'POST']) def login(): login stuff... @app.route('/my_table') @login_required def my_table(): print 'trying to access data table...' data = reload_data() return render_template("my_table.html", title = "Rundata Viewer", sts = sites, cn = column_names, data = data) # dictionary of data I installed nginx via yum as described here (yesterday) I am using uWSGI installed in my venv via pip I am on CentOS 6 My uwsgi log shows: Wed Jun 11 17:20:01 2014 - uwsgi_response_writev_headers_and_body_do(): Broken pipe [core/writer.c line 287] during GET /whm-server-status (127.0.0.1) IOError: write error [pid: 9586|app: 0|req: 135/135] 127.0.0.1 () {24 vars in 292 bytes} [Wed Jun 11 17:20:01 2014] GET /whm-server-status => generated 0 bytes in 3 msecs (HTTP/1.0 404) 2 headers in 0 bytes (0 switches on core 0) When its working, the print statement in the views "my_table" route prints into the log file. But not once it stops working. Any ideas?

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  • If record exists in database, UPDATE a single column

    - by Doug
    I have a bulk uploading object in place that is being used to bulk upload roughly 25-40 image files at a time. Each image is about 100-150 kb in size. During the upload, I've created a for each loop that takes the file name of the image (minus the file extension) to write it into a column named "sku". Also, for each file being uploaded, the date is recorded to a column named DateUpdated, as well as some image path data. Here is my c# code: protected void graphicMultiFileButton_Click(object sender, EventArgs e) { //graphicMultiFile is the ID of the bulk uploading object ( provided by Dean Brettle: http://www.brettle.com/neatupload ) if (graphicMultiFile.Files.Length > 0) { foreach (UploadedFile file in graphicMultiFile.Files) { //strip ".jpg" from file name (will be assigned as SKU) string sku = file.FileName.Substring(0, file.FileName.Length - 4); //assign the directory where the images will be stored on the server string directoryPath = Server.MapPath("~/images/graphicsLib/" + file.FileName); //ensure that if image existes on server that it will get overwritten next time it's uploaded: file.MoveTo(directoryPath, MoveToOptions.Overwrite); //current sql that inserts a record to the db SqlCommand comm; SqlConnection conn; string connectionString = ConfigurationManager.ConnectionStrings["DataConnect"].ConnectionString; conn = new SqlConnection(connectionString); comm = new SqlCommand("INSERT INTO GraphicsLibrary (sku, imagePath, DateUpdated) VALUES (@sku, @imagePath, @DateUpdated)", conn); comm.Parameters.Add("@sku", System.Data.SqlDbType.VarChar, 50); comm.Parameters["@sku"].Value = sku; comm.Parameters.Add("@imagePath", System.Data.SqlDbType.VarChar, 300); comm.Parameters["@imagePath"].Value = "images/graphicsLib/" + file.FileName; comm.Parameters.Add("@DateUpdated", System.Data.SqlDbType.DateTime); comm.Parameters["@DateUpdated"].Value = DateTime.Now; conn.Open(); comm.ExecuteNonQuery(); conn.Close(); } } } After images are uploaded, managers will go back and re-upload images that have previously been uploaded. This is because these product images are always being revised and improved. For each new/improved image, the file name and extension will remain the same - so that when image 321-54321.jpg was first uploaded to the server, the new/improved version of that image will still have the image file name as 321-54321.jpg. I can't say for sure if the file sizes will remain in the 100-150KB range. I'll assume that the image file size will grow eventually. When images get uploaded (again), there of course will be an existing record in the database for that image. What is the best way to: Check the database for the existing record (stored procedure or SqlDataReader or create a DataSet ...?) Then if record exists, simply UPDATE that record so that the DateUpdated column gets today's date. If no record exists, do the INSERT of the record as normal. Things to consider: If the record exists, we'll let the actual image be uploaded. It will simply overwrite the existing image so that the new version gets displayed on the web. We're using SQL Server 2000 on hosted environment (DiscountAsp). I'm programming in C#. The uploading process will be used by about 2 managers a few times a month (each) - which to me is not a allot of usage. Although I'm a jr. developer, I'm guessing that a stored procedure would be the way to go. Just seems more efficient - to do this record check away from the for each loop... but not sure. I'd need extra help writing a sproc, since I don't have too much experience with them. Thank everyone...

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