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  • How to join list of strings?

    - by satsurae
    Hi all, This is probably seriously easy to solve for most of you but I cannot solve this simply putting str() around it can I? I would like to convert this list: ['A','B','C'] into 'A B C'. Thanks in advance!!

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  • SQL Join query, getting ManagerName

    - by user279521
    I have an tblEmployeeProfile & a tblPersonnel. tblPersonnel is an HR table, that consists of all employees in the company; tblEmployeeProfile contains details about an employee's position. tblPersonnel.PersonnelID tblPersonnel.FirstName tblPersonnel.MiddleName tblPersonnel.LastName tblPersonnel.PhoneNumber tblPersonnel.Email tblEmployeeProfile.EmployeeID tblEmployeeProfile.ManagerID tblEmployeeProfile.DepartmentID tblEmployeeProfile.JobCategoryID tblEmployeeProfile.SalaryID I want to return a record with the following fields: EmployeeID, FirstName, MiddleName, LastName, Email, ManagerFullName where EmployeeID = @EmployeeID *tblEmployeeProfile.ManagerID = tblPersonnel.PersonnelID* I can't seem to get the query correct for getting the ManagerFullName

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  • Can I store and join based on external attributes in Lucene/Solr

    - by Kibbee
    Is there a way to store information about documents that are stored in Lucene such that I don't have to update the entire document to update certain attributes about the documents? For instance, let's say I had a bunch of documents, and that I wanted to update a permissions list of who was allowed to see the documents on a daily, or more frequent, basis. Would it be possible to update all the permissions each day, without updating all the documents. I could do it by keeping a exactly which permissions were added and removed, but I would rather just be able to take the end list of permissions, and use that, rather than have to keep track of all the permission changes and post those entire documents to Lucene.

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  • mysql joins - how to find all children that belongs to ALL parents

    - by kimsia
    I have three mysql tables items the columns are id, title items_in_categories the columns are id, item_id, category_id categories the columns are id, title I want to find all the items that belong to ALL the stated categories. Not any one category, but ALL categories Eg, if I want to search all the items that belongs to category id 3 and 5 I would like to use as simple a way as possible. I have tried AND and a nested NOT EXISTS as stated in the mysql manual. Nothing worked.

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  • Problem in Union Join For MySQL Query

    - by Mac Taylor
    hey guys i managed to select from a table that saves my latest posts but i need to have double condition in selection here is my code : $sql_query = "SELECT b.*,u.username AS MY_Sender FROM TABLE_users u,TABLE_blogs b Where b.reciever = '0' AND u.user_id = b.sender UNION SELECT b.*,u.username AS MY_reciever FROM TABLE_users u,TABLE_blogs b Where b.reciever != '0' AND u.user_id = b.reciever ORDER BY bid DESC LIMIT 0,7 "; but MY_reciever is Null and empty Am i wrong in using UNION for this need ?!

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  • Hibernate inserting into join table

    - by Karl
    I got several entities. Two of them got a many-to-many relation. When I do a bigger operation on these entities it fails with this exception: org.hibernate.exception.ConstraintViolationException: could not insert collection rows: I execute the operation i a @Transactional context. I don't do any explicit flushing i my daos. The flush is triggered by a query. In the queue are 15 elements (all of the same structure). one of them always fails (but it's always a different one (I checked) and always at a different position). Does anybody have a hint for me for what I might do wrong? My Mapping: @ManyToMany(targetEntity = CategoryImpl.class) protected Set<Category> categories = new HashSet<Category>();

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  • SQL COUNT records in table 2 JOINS away

    - by Fred K
    Using MySQL, I have three tables: projects: ID name 1 "birthday party" 2 "soccer match" 3 "wine tasting evening" 4 "dig out garden" 5 "mountainbiking" 6 "making music" batches: ID projectID templateID when 1 1 1 7 days before 2 1 1 1 day before 3 4 2 21 days before 4 4 1 7 days before 5 5 1 7 days before 6 3 5 7 days before 7 3 3 14 days before 8 5 1 14 days before templates: ID message 1 "Hi, I'd like to invite ..." 2 "Dear Sir, Madam, ..." 3 "Can you please ..." 4 "Would you like to ..." 5 "To all dear friends ..." 6 "Does any of you guys ..." I would like to display a table of templates and the number of projects they're used in. So, the result should be: templateID projectCount 1 3 2 1 3 1 4 0 5 1 6 0 I've tried all kinds of SQL queries using various JOINs, but I guess this is too complicated for me. Is it possible to get this result using a single SQL statement?

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  • PHP: Doctrine: order joined records

    - by Sebastian Bechtel
    Hi, I'm new to doctrine: I have a problem with the sorting of joined records. A sample. I've got an Article model which is associated with a Source model in 1 <- n. The source model has a property called 'position' with an integer value. Now I want to fetch an article with it's sources orderes by the position. My DQL looks like this: $q = Doctrine_Query::create() ->select('a.title, s.content') ->from('Article a') ->leftJoin('a.Source s') ->where('a.id = ?') ->orderBy('s.position'); The result doesn't change if I edit the position. Best regards, Sebastian

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  • Best way to do one-to-many "JOIN" in CouchDB

    - by mit
    There are CouchDB documents that are list elements: { "type" : "el", "id" : "1", "content" : "first" } { "type" : "el", "id" : "2", "content" : "second" } { "type" : "el", "id" : "3", "content" : "third" } There is one document that defines the list: { "type" : "list", "elements" : ["2","1"] , "id" : "abc123" } As you can see the third element was deleted, it is no longer part of the list. So it must not be part of the result. Now I want a view that returns the content elements including the right order. The result could be: { "content" : ["second", "first"] } In this case the order of the elements is already as it should be. Another possible result: { "content" : [{"content" : "first", "order" : 2},{"content" : "second", "order" : 1}] } I started writing the map function: map = function (doc) { if (doc.type === 'el') { emit(doc.id, {"content" : doc.content}); //emit the id and the content exit; } if (doc.type === 'list') { for ( var i=0, l=doc.elements.length; i<l; ++i ){ emit(doc.elements[i], { "order" : i }); //emit the id and the order } } } This is as far as I can get. Can you correct my mistakes and write a reduce function? Remember that the third document must not be part of the result. Of course you can write a different map function also. But the structure of the documents (one definig element document and an entry document for each entry) cannot be changed.

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  • How to get multiple counts with one SQL query?

    - by Crobzilla
    I am wondering how to write this query. I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it is part of a much bigger query. SELECT distributor_id, COUNT(*) AS TOTAL, COUNT(*) WHERE level = 'exec', COUNT(*) WHERE level = 'personal' I need this all returned in one query. Also, it need to be in one row, so the following won't work: 'SELECT distributor_id, COUNT(*) GROUP BY distributor_id'

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  • Trying to create fields based on a case statement

    - by dido
    I'm having some trouble with the query below. I am trying to determine if the "category" field is A, B or C and then creating a field based on the category. That field would sum up payments field. But I'm running into error saying "incorrect syntax near keyword As". I am creating this in a SQL View. Using SQL Server 2008 SELECT r.id, r.category CASE WHEN r.category = 'A' then SUM(r.payment) As A_payments WHEN r.category = 'B' then SUM(r.payment) As B_payments WHEN r.category = 'C' then SUM(r.payment) As C_payments END FROM r_invoiceTable As r GROUP BY r.id, r.category I have data where all of the above cases should be executed because the data that I have has A,B and C Sample Data- r_invoiceTable Id --- Category ---- Payment 222 A ---- 50 444 A ---- 30 111 B ---- 90 777 C ---- 20 555 C ---- 40 Desired Output A_payments = 80, B_payments = 90, C_payments = 60

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  • Marking up table joins in the Microstrategy project metadata with the architect tool?

    - by ConcernedOfTunbridgeWells
    Hi, I am evaluating Microstrategy 9.0.1 and attempting to build a prototype metadata layer using its Architect tool. The tool doesn't seem to have any specific means to mark up joins in the way that the editing tools for SSRS data source views or Business Objects universes do. How does this work in Microstrategy - I have never used this before and may be making invalid assumptions based on other systems I have seen. If one does do this with MicroStrategy, how is it done?

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  • Many to many self join through junction table

    - by Peter
    I have an EF model that can self-reference through an intermediary class to define a parent/child relationship. I know how to do a pure many-to-many relationship using the Map command, but for some reason going through this intermediary class is causing problems with my mappings. The intermediary class provides additional properties for the relationship. See the classes, modelBinder logic and error below: public class Equipment { [Key] public int EquipmentId { get; set; } public virtual List<ChildRecord> Parents { get; set; } public virtual List<ChildRecord> Children { get; set; } } public class ChildRecord { [Key] public int ChildId { get; set; } [Required] public int Quantity { get; set; } [Required] public Equipment Parent { get; set; } [Required] public Equipment Child { get; set; } } I've tried building the mappings in both directions, though I only keep one set in at a time: modelBuilder.Entity<ChildRecord>() .HasRequired(x => x.Parent) .WithMany(x => x.Children ) .WillCascadeOnDelete(false); modelBuilder.Entity<ChildRecord>() .HasRequired(x => x.Child) .WithMany(x => x.Parents) .WillCascadeOnDelete(false); OR modelBuilder.Entity<Equipment>() .HasMany(x => x.Parents) .WithRequired(x => x.Child) .WillCascadeOnDelete(false); modelBuilder.Entity<Equipment>() .HasMany(x => x.Children) .WithRequired(x => x.Parent) .WillCascadeOnDelete(false); Regardless of which set I use, I get the error: The foreign key component 'Child' is not a declared property on type 'ChildRecord'. Verify that it has not been explicitly excluded from the model and that it is a valid primitive property. when I try do deploy my ef model to the database. If I build it without the modelBinder logic in place then I get two ID columns for Child and two ID columns for Parent in my ChildRecord table. This makes sense since it tries to auto create the navigation properties from Equipment and doesn't know that there are already properties in ChildRecord to fulfill this need. I tried using Data Annotations on the class, and no modelBuilder code, this failed with the same error as above: [Required] [ForeignKey("EquipmentId")] public Equipment Parent { get; set; } [Required] [ForeignKey("EquipmentId")] public Equipment Child { get; set; } AND [InverseProperty("Child")] public virtual List<ChildRecord> Parents { get; set; } [InverseProperty("Parent")] public virtual List<ChildRecord> Children { get; set; } I've looked at various other answers around the internet/SO, and the common difference seems to be that I am self joining where as all the answers I can find are for two different types. Entity Framework Code First Many to Many Setup For Existing Tables Many to many relationship with junction table in Entity Framework? Creating many to many junction table in Entity Framework

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  • Merging two arrays in PHP

    - by Industrial
    Hi everyone, I am trying to create a new array from two current arrays. Tried array_merge, but it will not give me what I want. $array1 is a list of keys that I pass to a function. $array2 holds the results from that function, but doesn't contain any non-available resuls for keys. So, I want to make sure that all requested keys comes out with 'null':ed values, as according to the shown $result array. It goes a little something like this: $array1 = array('item1', 'item2', 'item3', 'item4'); $array2 = array( 'item1' => 'value1', 'item2' => 'value2', 'item3' => 'value3' ); Here's the result I want: $result = array( 'item1' => 'value1', 'item2' => 'value2', 'item3' => 'value3', 'item4' => '' ); It can be done this way, but I don't think that it's a good solution - I really don't like to take the easy way out and suppress PHP errors by adding @:s in the code. This sample would obviously throw errors since 'item4' is not in $array2, based on the example. foreach ($keys as $k => $v){ @$array[$v] = $items[$v]; } So, what's the fastest (performance-wise) way to accomplish the same result?

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  • Inner join 2 tables one to many 2 where clauses

    - by user2892350
    I'm a relative rookie at this,so please bear with me... I have 2 tables: OrderDetail and OrderMaster...both have a column named SalesOrder. OrderDetail table has multiple rows per unique SalesOrder. OrderMaster table has one row per unique SalesOrder. OrderDetail has a column named LineType. OrderMaster has a column named OrderStatus. I want to select all records from OrderDetail that have a LineType of "1" AND whose matching SalesOrder line in the OrderMaster table has a OrderStatus column value of "4". In plain English, orders with a Status 4 are open and ready to ship, LineType value of 1 means the Detail Line is a product code. How should this query be structured? It's going into VS 2008 (VB). Many thanks in advance!!! Mike

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  • Oracle join issue

    - by acadia
    Hello, I have 3 tables and I am joining these 2 tables as follows: SELECT EMP.FNAME,EMP.LNAME,EMP.AGE,EMPD.TQ,EMPD.TA,CTY.CITY_NAME FROM EMPLOYEE EMP,EMPLOYEE_DETAIL EMPD, CITY CTY WHERE EMP.EMP_ID=EMPD.EMP_ID AND EMPD_CITY_ID=CTY.CITY_ID I want to display records even if City record is not in CITY table. For eg. if City_ID record for say 10 is not in City table but there is an employee detail record with City_id 10 it should display City_name as null instead of not displaying the record at all. Appreciate your help

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  • select row from table and substitute a field with one from another column if it exists

    - by EarthMind
    I'm trying construct a PostgreSQL query that does the following but so far my efforts have been in vain. Problem: There are two tables: A and B. I'd like to select all columns from table A (having columns: id, name, description) and substitute the "A.name" column with the value of the column "B.title" from table B (having columns: id, table_A_id title, langcode) where B.table_A_id is 5 and B.langcode is "nl" (if there are any rows). My attempts: SELECT A.name, case when exists(select title from B where table_A_id = 5 and langcode= 'nl') then B.title else A.name END FROM A, B WHERE A.id = 5 and B.table_A_id = 5 and B.langcode = 'nl' -- second try: SELECT COALESCE(B.title, A.name) as name from A, B where A.id = 5 and B.table_A_id = 5 and exists(select title from B where table_A_id = 5 and langcode= 'nl') I've tried using a CASE and COALESCE() but failed due to my inexperience with both concepts. Thanks in advance.

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  • SQL OUTER JOIN with NEWID to generate random data for each row

    - by CL4NCY
    Hi, I want to generate some test data so for each row in a table I want to insert 10 random rows in another, see below: INSERT INTO CarFeatures (carID, featureID) SELECT C.ID, F.ID FROM dbo.Cars AS C OUTER APPLY ( SELECT TOP 10 ID FROM dbo.Features ORDER BY NEWID() ) AS F Only trouble is this returns the same values for each row. How do I order them randomly?

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  • select row from table and substitute a field with one from another column if not null

    - by EarthMind
    I'm trying construct a PostgreSQL query that does the following but so far my efforts have been in vain. Problem: There are two tables: A and B. I'd like to select all columns from table A (having columns: id, name, description) and substitute the "A.name" column with the value of the column "B.title" from table B (having columns: id, table_A_id title, langcode) where B.table_A_id is 5 and B.langcode is "nl" (if there are any rows). I've tried using a CASE and COALESCE() but failed due to my inexperience with both concepts. Thanks in advance.

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  • How to coerce type of ActiveRecord attribute returned by :select phrase on joined table?

    - by tribalvibes
    Having trouble with AR 2.3.5, e.g.: users = User.all( :select => "u.id, c.user_id", :from => "users u, connections c", :conditions => ... ) Returns, e.g.: => [#<User id: 1000>] >> users.first.attributes => {"id"=>1000, "user_id"=>"1000"} Note that AR returns the id of the model searched as numeric but the selected user_id of the joined model as a String, although both are int(11) in the database schema. How could I better form this type of query to select columns of tables backing multiple models and retrieving their natural type rather than String ? Seems like AR is punting on this somewhere. How could I coerce the returned types at AR load time and not have to tack .to_i (etc.) onto every post-hoc access?

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  • T-SQL Self Join in combination with aggregate function

    - by Nick
    Hi, i have the following table. CREATE TABLE [dbo].[Tree]( [AutoID] [int] IDENTITY(1,1) NOT NULL, [Category] [varchar](10) NULL, [Condition] [varchar](10) NULL, [Description] [varchar](50) NULL, CONSTRAINT [PK_Tree] PRIMARY KEY CLUSTERED ( [AutoID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO the data looks like this: INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('1','Alpha','Type 1') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('1','Alpha','Type 1') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('2','Alpha','Type 2') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('2','Alpha','Type 2') go I try now to do the following: SELECT Category,COUNT(*) as CategoryCount FROM Tree where Condition = 'Alpha' group by Category but i wish also to get the Description for each Element. I tried several subqueries, self joins etc. i always come to the problem that the subquery cannot return more than one record. The problem is caused by a poor database design which i cannot change and i run out of ideas to get this done in a single query ;-(

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  • Grails many to many using a third 'join' class

    - by andy mccullough
    I read that a m:m relationship often means there is a third class that isn't yet required. So I have m:m on User and Project, and I created a third domain class, ProjectMembership The three domains are as follows (minimized for illustration purposes): User class User { String name static hasMany = [projectMemberships : ProjectMembership] } Project Membership class ProjectMembership { static constraints = { } static belongsTo = [user:User, project:Project] } Project: class Project { String name static hasMany = [projectMemberships : ProjectMembership] static constraints = { } } If I have the ID of the user, how can I get a list of Project objects that they are assigned to?

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