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  • ExtJs - Set a fixed width in a center layout in a Panel

    - by Benjamin
    Hi all, Using ExtJs. I'm trying to design a main which is divided into three sub panels (a tree list, a grid and a panel). The way it works is that you have a tree list (west) with elements, you click on an element which populates the grid (center), then you click on an element in the grid and that generates the panel (west). My main panel containing the three other ones has been defined with a layout 'border'. Now the problem I face is that the center layout (the grid) has been defined in the code with a fixed width and the west panel as an auto width. But when the interface gets generated, the grid width is suddenly taking all the space in the interface instead of the west panel. The code looks like that: var exploits_details_panel = new Ext.Panel({ region: 'east', autoWidth: true, autoScroll: true, html: 'test' }); var exploit_commands = new Ext.grid.GridPanel({ store: new Ext.data.Store({ autoDestroy: true }), sortable: true, autoWidth: false, region: 'center', stripeRows: true, autoScroll: true, border: true, width: 225, columns: [ {header: 'command', width: 150, sortable: true}, {header: 'date', width: 70, sortable: true} ] }); var exploits_tree = new Ext.tree.TreePanel({ border: true, region: 'west', width: 200, useArrows: true, autoScroll: true, animate: true, containerScroll: true, rootVisible: false, root: {nodeType: 'async'}, dataUrl: '/ui/modules/select/exploits/tree', listeners: { 'click': function(node) { } } }); var exploits = new Ext.Panel({ id: 'beef-configuration-exploits', title: 'Auto-Exploit', region: 'center', split: true, autoScroll: true, layout: { type: 'border', padding: '5', align: 'left' }, items: [exploits_tree, exploit_commands, exploits_details_panel] }); Here 'var exploits' is my main panel containing the three other sub panels. The 'exploits_tree' is the tree list containing some elements. When you click on one of the elements the grid 'exploit_commands' gets populated and when you click in one of the populated elements, the 'exploits_details_panel' panel gets generated. How can I set a fixed width on 'exploit_commands'? Thanks for your time.

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  • How can I make a WPF TreeView data binding lazy and asynchronous?

    - by pauldoo
    I am learning how to use data binding in WPF for a TreeView. I am procedurally creating the Binding object, setting Source, Path, and Converter properties to point to my own classes. I can even go as far as setting IsAsync and I can see the GUI update asynchronously when I explore the tree. So far so good! My problem is that WPF eagerly evaluates parts of the tree prior to them being expanded in the GUI. If left long enough this would result in the entire tree being evaluated (well actually in this example my tree is infinite, but you get the idea). I would like the tree only be evaluated on demand as the user expands the nodes. Is this possible using the existing asynchronous data binding stuff in the WPF? As an aside I have not figured out how ObjectDataProvider relates to this task. My XAML code contains only a single TreeView object, and my C# code is: public partial class Window1 : Window { public Window1() { InitializeComponent(); treeView.Items.Add( CreateItem(2) ); } static TreeViewItem CreateItem(int number) { TreeViewItem item = new TreeViewItem(); item.Header = number; Binding b = new Binding(); b.Converter = new MyConverter(); b.Source = new MyDataProvider(number); b.Path = new PropertyPath("Value"); b.IsAsync = true; item.SetBinding(TreeView.ItemsSourceProperty, b); return item; } class MyDataProvider { readonly int m_value; public MyDataProvider(int value) { m_value = value; } public int[] Value { get { // Sleep to mimick a costly operation that should not hang the UI System.Threading.Thread.Sleep(2000); System.Diagnostics.Debug.Write(string.Format("Evaluated for {0}\n", m_value)); return new int[] { m_value * 2, m_value + 1, }; } } } class MyConverter : IValueConverter { public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture) { // Convert the double to an int. int[] values = (int[])value; IList<TreeViewItem> result = new List<TreeViewItem>(); foreach (int i in values) { result.Add(CreateItem(i)); } return result; } public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture) { throw new InvalidOperationException("Not implemented."); } } } Note: I have previously managed to do lazy evaluation of the tree nodes by adding WPF event handlers and directly adding items when the event handlers are triggered. I'm trying to move away from that and use data binding instead (which I understand is more in spirit with "the WPF way").

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  • Right-click context menu for Java JTree?

    - by arcanex
    I'm trying to implement pop-up menus in Java JTree. I've sub-classed DefaultTreeCellRenderer (to change node appearance) and DefaultTreeCellEditor (to create Components to attach event listeners to, since apparently the Components that DefaultTreeCellRenderer.getTreeCellRendererComponent() returns can't do it?). I don't really want to "edit" the nodes, just be able to pop-up a menu when a node gets right-clicked, but this is the only way I can think of doing it right now... Below is the code that I have so far-- I'm just trying to figure out how to capture MouseEvents. It sort of works, but badly. What's a better way to accomplish what I'm trying to do here? private class My_TreeCellRenderer extends DefaultTreeCellRenderer { My_TreeCellRenderer() { super (); } public Component getTreeCellRendererComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) { super.getTreeCellRendererComponent(tree, value, selected, expanded, leaf, row, hasFocus); // set label text and tool tips setText(((My_Object)value).getTreeLabel()); setToolTipText(((My_Object)value).getTreeToolTip()); return this; } } private class My_TreeCellEditor extends DefaultTreeCellEditor { private MouseAdapter ma; My_TreeCellEditor(JTree tree, DefaultTreeCellRenderer renderer) { super (tree, renderer); ma = new MouseAdapter() { public void mousePressed(MouseEvent e) { if (e.isPopupTrigger()) { System.out.println("My Popup"); } } public void mouseReleased(MouseEvent e) { if (e.isPopupTrigger()) { System.out.println("My Popup"); } } }; } public Component getTreeCellEditorComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row) { String src_filename = null; // return non-editing component Component c = renderer.getTreeCellRendererComponent(tree, value, selected, expanded, leaf, row, true); // add mouse listener if it's not listening already MouseListener mouseListeners[] = c.getMouseListeners(); int i; for (i=0; i < mouseListeners.length && mouseListeners[i] != ma; i++); if (i >= mouseListeners.length) c.addMouseListener(ma); return c; } protected boolean canEditImmediately(EventObject event) { if (event instanceof MouseEvent && ((MouseEvent)event).getClickCount() == 1) return true; else return false; } }

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  • jQuery accordion menu - keep accordion menu open to the page I am on

    - by MelissaTA
    Hi everyone, I hope you can help. I'm very new to jQuery and am working on a five- or six-level accordion menu for my side navigation. I got the majority of the code I have so far from Dane Peterson @ daneomatic.com (thanks Dane!). But, I'm stuck on one thing: I'd like to have my accordion/tree work like this: When I navigate down into, say, level three, and click on the link to open the page linked to that level, how do I indicate once the level three page loads that I'm on that page? Also, how do I keep the tree open to that level when I load the page? I guess what I'm asking is: is there a way for the accordion/tree to automatically update to show what page you're at, and have the tree open to that level? Thanks in advance!

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  • Exposing a pointer in Boost.Python

    - by Goose Bumper
    I have this very simple C++ class: class Tree { public: Node *head; }; BOOST_PYTHON_MODULE(myModule) { class_<Tree>("Tree") .def_readwrite("head",&Tree::head) ; } I want to access the head variable from Python, but the message I see is: No to_python (by-value) converter found for C++ type: Node* From what I understand, this happens because Python is freaking out because it has no concept of pointers. How can I access the head variable from Python? I understand I should use encapsulation, but I'm currently stuck with needing a non-encapsulation solution.

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  • Whats wrong with this HQL query?

    - by ManBugra
    did i encounter a hibernate bug or do i have an error i dont see: select enty.number from EntityAliasName enty where enty.myId in ( select cons.myId from Consens cons where cons.number in ( select ord.number from Orders ord where ord.customer = :customer and ord.creationDate < ( select max(ord.creationDate) from Orders ord where ord.customer = :customer ) ) ) what i do get is the following: org.hibernate.util.StringHelper.root(StringHelper.java:257) Caused by: java.lang.NullPointerException at org.hibernate.util.StringHelper.root(StringHelper.java:257) at org.hibernate.persister.entity.AbstractEntityPersister.getSubclassPropertyTableNumber(AbstractEntityPersister.java:1391) at org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns(BasicEntityPropertyMapping.java:54) at org.hibernate.persister.entity.AbstractEntityPersister.toColumns(AbstractEntityPersister.java:1367) at org.hibernate.hql.ast.tree.FromElement.getIdentityColumn(FromElement.java:320) at org.hibernate.hql.ast.tree.IdentNode.resolveAsAlias(IdentNode.java:154) at org.hibernate.hql.ast.tree.IdentNode.resolve(IdentNode.java:100) at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:117) at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:113) at org.hibernate.hql.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:854) at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRef(HqlSqlBaseWalker.java:1172) at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRefLhs(HqlSqlBaseWalker.java:5167) at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRef(HqlSqlBaseWalker.java:1133) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:1993) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:1932) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1476) at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:580) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:288) at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:231) at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254) at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185) at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136) at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101) at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80) at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:94) at org.hibernate.impl.SessionFactoryImpl.checkNamedQueries(SessionFactoryImpl.java:484) at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:394) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1341) using: Hibernate 3.3.2.GA / postgresql

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  • jquery dynatree class methods

    - by Jj Zhang
    I'm a new user of dynatree plugin. When I read the documentation, I found the list of tree and node class member functions, such as tree.getRoot(), node.countChildren(). However, when I tried to use them, it complained that no such methods were found. Here is a sample code I am testing with: var tree = ("#test").dynatree(treeData); var rootNode = tree.getRoot(); //not working var rootNode2 = ("#test").dynatree("getRoot"); //this works var numChildren = rootNode2.countChildren(); //not working Help please. Thanks. -JJ

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  • Git - Ignore certain files contained in specific folders

    - by Jim
    I'm using msysgit and have a project tree that contains many bin/ folders in the tree. Using the .gitignore file in the root of the project I need to ignore all .dll files that reside within a bin/ folder anywhere in the project tree. I've tried "bin/*.dll" but that doesn't work, I assume it is only working against the bin/ folder in the root of the project.

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  • javascript compare two DOM trees

    - by Paul
    I want to compare the change of a DOM node after a user event is fired on it; but I don't know on which element a user would fire, so my idea is to (1) save the DOM tree before an event and (2) compare the saved tree with the updated DOM tree when an event is fired. My question are (1) is there any better way? and (2) if there is no other way, what would be the fast algorithm to compare two DOM trees?

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  • how to pass an xml file to lxml to parse?

    - by BeeBand
    I'm trying to parse an xml file using lxml. xml.etree allowed me to simply pass the file name as a parameter to the parse function, so I attempted to do the same with lxml. My code: from lxml import etree from lxml import objectify file = "C:\Projects\python\cb.xml" tree = etree.parse(file) but I get the error: Traceback (most recent call last): File "cb.py", line 5, in <module> tree = etree.parse(file) File "lxml.etree.pyx", line 2698, in lxml.etree.parse (src/lxml/lxml.etree.c:4 9590) File "parser.pxi", line 1491, in lxml.etree._parseDocument (src/lxml/lxml.etre e.c:71205) File "parser.pxi", line 1520, in lxml.etree._parseDocumentFromURL (src/lxml/lx ml.etree.c:71488) File "parser.pxi", line 1420, in lxml.etree._parseDocFromFile (src/lxml/lxml.e tree.c:70583) File "parser.pxi", line 975, in lxml.etree._BaseParser._parseDocFromFile (src/ lxml/lxml.etree.c:67736) File "parser.pxi", line 539, in lxml.etree._ParserContext._handleParseResultDo c (src/lxml/lxml.etree.c:63820) File "parser.pxi", line 625, in lxml.etree._handleParseResult (src/lxml/lxml.e tree.c:64741) File "parser.pxi", line 565, in lxml.etree._raiseParseError (src/lxml/lxml.etr ee.c:64084) lxml.etree.XMLSyntaxError: AttValue: " or ' expected, line 2, column 26 What am I doing wrong?

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  • Python question, how to pass an xml file to lxml to parse?

    - by BeeBand
    I'm relatively new to python, my code is: from lxml import etree from lxml import objectify file = "C:\Projects\python\cb.xml" tree = etree.parse(file) but I get the error: Traceback (most recent call last): File "cb.py", line 5, in <module> tree = etree.parse(file) File "lxml.etree.pyx", line 2698, in lxml.etree.parse (src/lxml/lxml.etree.c:4 9590) File "parser.pxi", line 1491, in lxml.etree._parseDocument (src/lxml/lxml.etre e.c:71205) File "parser.pxi", line 1520, in lxml.etree._parseDocumentFromURL (src/lxml/lx ml.etree.c:71488) File "parser.pxi", line 1420, in lxml.etree._parseDocFromFile (src/lxml/lxml.e tree.c:70583) File "parser.pxi", line 975, in lxml.etree._BaseParser._parseDocFromFile (src/ lxml/lxml.etree.c:67736) File "parser.pxi", line 539, in lxml.etree._ParserContext._handleParseResultDo c (src/lxml/lxml.etree.c:63820) File "parser.pxi", line 625, in lxml.etree._handleParseResult (src/lxml/lxml.e tree.c:64741) File "parser.pxi", line 565, in lxml.etree._raiseParseError (src/lxml/lxml.etr ee.c:64084) lxml.etree.XMLSyntaxError: AttValue: " or ' expected, line 2, column 26 What am I doing wrong?

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  • Theory of formal languages - Automaton

    - by dader51
    Hi everybody ! I'm wondering about formal languages. I have a kind of parser : It reads à xml-like serialized tree structure and turn it into a multidimmensionnal array. I figured out that i need at least three variables to achieve the job : $tree = array(); // a new array $pTree = array(&$tree); // a new array which the first element points to $tree; $deep = 0; plus the one containing the sentence splitted into words. My point is on the similarities between the algorithm deing used and the differents kinds of automatons ( state machines turing machines stack ... ). The $words variable is the "tape" of the automaton, the test/conditions of the algorithm are transitions, $deep is the state and $tree is the output. I cannont figure what is $pTree. So the question is : which is the automaton I implictly use here, and to which formal languages family does it fit ? And what's about recursion ?

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  • TicTacToe AI Making Incorrect Decisions

    - by Chris Douglass
    A little background: as a way to learn multinode trees in C++, I decided to generate all possible TicTacToe boards and store them in a tree such that the branch beginning at a node are all boards that can follow from that node, and the children of a node are boards that follow in one move. After that, I thought it would be fun to write an AI to play TicTacToe using that tree as a decision tree. TTT is a solvable problem where a perfect player will never lose, so it seemed an easy AI to code for my first time trying an AI. Now when I first implemented the AI, I went back and added two fields to each node upon generation: the # of times X will win & the # of times O will win in all children below that node. I figured the best solution was to simply have my AI on each move choose and go down the subtree where it wins the most times. Then I discovered that while it plays perfect most of the time, I found ways where I could beat it. It wasn't a problem with my code, simply a problem with the way I had the AI choose it's path. Then I decided to have it choose the tree with either the maximum wins for the computer or the maximum losses for the human, whichever was more. This made it perform BETTER, but still not perfect. I could still beat it. So I have two ideas and I'm hoping for input on which is better: 1) Instead of maximizing the wins or losses, instead I could assign values of 1 for a win, 0 for a draw, and -1 for a loss. Then choosing the tree with the highest value will be the best move because that next node can't be a move that results in a loss. It's an easy change in the board generation, but it retains the same search space and memory usage. Or... 2) During board generation, if there is a board such that either X or O will win in their next move, only the child that prevents that win will be generated. No other child nodes will be considered, and then generation will proceed as normal after that. It shrinks the size of the tree, but then I have to implement an algorithm to determine if there is a one move win and I think that can only be done in linear time (making board generation a lot slower I think?) Which is better, or is there an even better solution?

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  • Python constructor does weird things with optional parameters

    - by christangrant
    Can you help me understand of the behaviour and implications of the python __init__ constructor. It seems like when there is an optional parameter and you try and set an existing object to a new object the optional value of the existing object is preserved and copied. Ok that was confusing... so look at an example I concocted below. In the code below I am trying to make a tree structure with nodes and possibly many children . In the first class NodeBad, the constructor has two parameters, the value and any possible children. The second class NodeGood only takes the value of the node as a parameter. Both have an addchild method to add a child to a node. When creating a tree with the NodeGood class, it works as expected. However, when doing the same thing with the NodeBad class, it seems as though a child can only be added once! The code below will result in the following output: Good Tree 1 2 3 [< 3 >] Bad Tree 1 2 2 [< 2 >, < 3 >] Que Pasa? Here is the Example: #!/usr/bin/python class NodeBad: def __init__(self, value, c=[]): self.value = value self.children = c def addchild(self, node): self.children.append(node) def __str__(self): return '< %s >' % self.value def __repr__(self): return '< %s >' % self.value class NodeGood: def __init__(self, value): self.value = value self.children = [] def addchild(self, node): self.children.append(node) def __str__(self): return '< %s >' % self.value def __repr__(self): return '< %s >' % self.value if __name__ == '__main__': print 'Good Tree' ng = NodeGood(1) # Root Node rootgood = ng ng.addchild(NodeGood(2)) # 1nd Child ng = ng.children[0] ng.addchild(NodeGood(3)) # 2nd Child print rootgood.value print rootgood.children[0].value print rootgood.children[0].children[0].value print rootgood.children[0].children print 'Bad Tree' nb = NodeBad(1) # Root Node rootbad = nb nb.addchild(NodeBad(2)) # 1st Child nb = nb.children[0] nb.addchild(NodeBad(3)) # 2nd Child print rootbad.value print rootbad.children[0].value print rootbad.children[0].children[0].value print rootbad.children[0].children

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  • Questions about linux root file system.

    - by smwikipedia
    I read the manual page of the "mount" command, at it reads as below: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. My questions are: Where is this "big tree" located? Suppose I have 2 disks, if I mount them onto some point in the "big tree", does linux place some "special marks" in the mount point to indicate that these 2 "mount directories" are indeed seperate disks?

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  • protection points in survivable mutlicast network

    - by wantobegeek
    I am working on a project on survivable multicasting.I want to propose a hybrid scheme(protection and restoration) for that purpose.Can anyone help me with an approach to decide protection points in a multicast tree??(The protection points will be those points upto which there will be an alternate path from the multicast source(protection) and from protection point to the multicast destination the path will be dynamically restored.).Pls suggest an approach to find the protection points.I found an approach name caterpillar tree which assigns the nodes on the spine of caterpillar tree as protection points.Is there any other such approach..?

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  • EXT JS toLayout on Viewport doesnt show anything...

    - by Nazariy
    After reading many example about adding new components in to existing container without reloading whole page I run in to small problem while combining tree and tabs inside Viewport component. What I'm trying to do is to register on click event to tree node and load in to content container new component, depending on node type it can be tabpanel, gridpanel or any other available component. here is short example of tree object: { xtype: 'treepanel', id: 'tree-panel', listeners: { click: function(n) { var content = Ext.getCmp('content-panel'); content.setTitle(n.attributes.qtip); //remove all components from content-panel content.removeAll(); content.add(dummy_tabs2); content.doLayout(); return; } }} All DOM manipulation went fine, everything registered properly, new Title shown, but dummy_tabs2 are not shown. I did try to set various properties for doLayout(true|false, true|false) but nothing happens. Am I doing something wrong?

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  • WPF TreeView PreviewMouseDown on TreeViewItem

    - by imekon
    If I handle the PreviewMouseDown event on TreeViewItem, I get events for everything I click on that TreeViewItem include the little +/- box to the left (Windows XP). How can I distinguish that? I tried the following: // We've had a single click on a tree view item // Unfortunately this is the WHOLE tree item, including the +/- // symbol to the left. The tree doesn't do a selection, so we // have to filter this out... MouseDevice device = e.Device as MouseDevice; // This is bad. The whole point of WPF is for the code // not to know what the UI has - yet here we are testing for // it as a workaround. Sigh... // This is broken - if you click on the +/- on a item, it shouldn't // go on to be processed by OnTreeSingleClick... ho hum! if (device.DirectlyOver.GetType() != typeof(Path)) { OnTreeSingleClick(sender); } What I'm after is just single click on the tree view item excluding the extra bits it seems to include.

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  • JTree keep expanding problem

    - by newbie123
    I want to keep my jTree file expanded. I using below code to expand the jTree : public void expandAll(JTree tree) { int row = 0; while (row < tree.getRowCount()) { tree.expandRow(row); row++; } } It works, but when I add in new file or delete file the jtree collapse back. How can keep the jTree expanded?

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  • Using Python, what's the best way to create a set of files on disk for testing?

    - by Chris R
    I'm looking for a way to create a tree of test files to unit test a packaging tool. Basically, I want to create some common file system structures -- directories, nested directories, symlinks within the selected tree, symlinks outside the tree, &c. Ideally I want to do this with as little boilerplate as possible. Of course, I could hand-write the set of files I want to see, but I'm thinking that somebody has to have automated this for a test suite somewhere. Any suggestions?

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  • g_tree_insert overwrites all data

    - by pechenie
    I wonder how I should use the GTree (from GLib) to store data? Every new value I insert into GTree with g_tree_insert routine is overwrite the previous one! GTree *tree; //init tree = g_tree_new( g_str_equal ); //"g_str_equal" is a GLib default compare func //... for( i = 0; i < 100; ++i ) g_tree_insert( tree, random_key(), random_value() ); //insert some random vals // printf( "%d", g_tree_nnodes( tree ) ); //should be 100? NO! Prints "1"!!! What am I doing wrong? Thank you.

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  • Problem in setting backgound color to my TreeCellRenderer

    - by Sunil Kumar Sahoo
    Hi I have cretaed my own renderer. I want the back ground should be blue. I have set background color as blue also. But I donot know what is tha problem that the background color of my renderer always seems to be white. I have post the code. please help where I am wrong so that the background color becomes white. class CheckTreeCellRenderer extends JPanel implements TreeCellRenderer { private CheckTreeSelectionModel selectionModel; private MyRenderer delegate; private TristateCheckBox checkBox = new TristateCheckBox("", null, true); public static final State NOT_SELECTED = new State(); public static final State SELECTED = new State(); public static final State DONT_CARE = new State(); public CheckTreeCellRenderer(MyRenderer delegate, CheckTreeSelectionModel selectionModel) { this.delegate = delegate; this.selectionModel = selectionModel; setLayout(new BorderLayout()); setOpaque(true); setBackground(new Color(207, 219, 234)); checkBox.setState(Boolean.TRUE); checkBox.setOpaque(true); checkBox.setBackground(new Color(207, 219, 234)); } public Component getTreeCellRendererComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) { Component renderer = delegate.getTreeCellRendererComponent(tree, value, selected, expanded, leaf, row, hasFocus); TreePath path = tree.getPathForRow(row); if (path != null) { if (selectionModel.isPathSelected(path, true)) { checkBox.setState(Boolean.TRUE); } else { checkBox.setState(selectionModel.isPartiallySelected(path) ? null : Boolean.FALSE); } } renderer.setBackground(new Color(207, 219, 234)); tree.setOpaque(true); tree.setBackground(new Color(207, 219, 234)); this.setOpaque(true); this.setBackground(new Color(207, 219, 234)); add(checkBox, BorderLayout.WEST); add(renderer, BorderLayout.CENTER); return this; } }

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  • JSF 2.0: Preserving component state across multiple views

    - by tlind
    The web application I am developing using MyFaces 2.0.3 / PrimeFaces 2.2RC2 is divided into a content and a navigation area. In the navigation area, which is included into multiple pages using templating (i.e. <ui:define>), there are some widgets (e.g. a navigation tree, collapsible panels etc.) of which I want to preserve the component state across views. For example, let's say I am on the home page. When I navigate to a product details page by clicking on a product in the navigation tree, my Java code triggers a redirect using navigationHandler.handleNavigation(context, null, "/detailspage.jsf?faces-redirect=true") Another way of getting to that details page would be by directly clicking on a product teaser that is shown on the home page. The corresponding <h:link> would lead us to the details page. In both cases, the expansion state of my navigation tree (a PrimeFaces tree component) and my collapsible panels is lost. I understand this is because the redirect / h:link results in the creation of a new view. What is the best way of dealing with this? I am already using MyFaces Orchestra in my project along with its conversation scope, but I am not sure if this is of any help here (since I'd have to bind the expansion/collapsed state of the widgets to a backing bean... but as far as I know, this is not possible). Is there a way of telling JSF which component states to propagate to the next view, assuming that the same component exists in that view? I guess I could need a pointer into the right direction here. Thanks! Update 1: I just tried binding the panels and the tree to a session-scoped bean, but this seems to have no effect. Also, I guess I would have to bind all child components (if any) manually, so this doesn't seem like the way to go. Update 2: Binding UI components to non-request scoped beans is not a good idea (see link I posted in a comment below). If there is no easier approach, I might have to proceed as follows: When a panel is collapsed or the tree is expanded, save the current state in a session-scoped backing bean (!= the UI component itself) The components' states are stored in a map. The map key is the component's (hopefully) unique, relative ID. I cannot use the whole absolute component path here, since the IDs of the parent naming containers might change if the view changes, assuming these IDs are generated programmatically. As soon as a new view gets constructed, retrieve the components' states from the map and apply them to the components. For example, in case of the panels, I can set the collapsed attribute to a value retrieved from my session-scoped backing bean.

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  • Thread-safety of read-only memory access

    - by Edmund
    I've implemented the Barnes-Hut gravity algorithm in C as follows: Build a tree of clustered stars. For each star, traverse the tree and apply the gravitational forces from each applicable node. Update the star velocities and positions. Stage 2 is the most expensive stage, and so is implemented in parallel by dividing the set of stars. E.g. with 1000 stars and 2 threads, I have one thread processing the first 500 stars and the second thread processing the second 500. In practice this works: it speeds the computation by about 30% with two threads on a two-core machine, compared to the non-threaded version. Additionally, it yields the same numerical results as the original non-threaded version. My concern is that the two threads are accessing the same resource (namely, the tree) simultaneously. I have not added any synchronisation to the thread workers, so it's likely they will attempt to read from the same location at some point. Although access to the tree is strictly read-only I am not 100% sure it's safe. It has worked when I've tested it but I know this is no guarantee of correctness! Questions Do I need to make a private copy of the tree for each thread? Even if it is safe, are there performance problems of accessing the same memory from multiple threads?

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  • Selective Checkout or a View, on a project in repository

    - by Yossi Zach
    I have a bunch of interconnected projects which share the same project tree. I'm looking for a version control system which provides a possibility to checkout a subset of the project tree. If my the full project tree looks like this: Project Root |-Feature1 | |-SubFeature11 | \-SubFeature12 |-Feature2 | |-SubFeature21 | \-SubFeature22 |-file1 \-file2 I want be able to checkout only subset like this: Project Root |-Feature1 | \-SubFeature12 |-Feature2 | \-SubFeature22 |-file1 \-file2 So do you know any version control system that allows to do selective checkout or a view on a repository?

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