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  • phpmyadmin “Forbidden: You don't have permission to access /phpmyadmin on this server.”

    - by Caterpillar
    I need to modify the file /etc/httpd/conf.d/phpMyAdmin.conf in order to allow remote users (not only localhost) to login # phpMyAdmin - Web based MySQL browser written in php # # Allows only localhost by default # # But allowing phpMyAdmin to anyone other than localhost should be considered # dangerous unless properly secured by SSL Alias /phpMyAdmin /usr/share/phpMyAdmin Alias /phpmyadmin /usr/share/phpMyAdmin <Directory "/usr/share/phpMyAdmin/"> Options Indexes FollowSymLinks MultiViews AllowOverride all Order Allow,Deny Allow from all </Directory> <Directory /usr/share/phpMyAdmin/setup/> <IfModule mod_authz_core.c> # Apache 2.4 <RequireAny> Require ip 127.0.0.1 Require ip ::1 </RequireAny> </IfModule> <IfModule !mod_authz_core.c> # Apache 2.2 Order Deny,Allow Allow from All Allow from 127.0.0.1 Allow from ::1 </IfModule> </Directory> # These directories do not require access over HTTP - taken from the original # phpMyAdmin upstream tarball # <Directory /usr/share/phpMyAdmin/libraries/> Order Deny,Allow Deny from All Allow from None </Directory> <Directory /usr/share/phpMyAdmin/setup/lib/> Order Deny,Allow Deny from All Allow from None </Directory> <Directory /usr/share/phpMyAdmin/setup/frames/> Order Deny,Allow Deny from All Allow from None </Directory> # This configuration prevents mod_security at phpMyAdmin directories from # filtering SQL etc. This may break your mod_security implementation. # #<IfModule mod_security.c> # <Directory /usr/share/phpMyAdmin/> # SecRuleInheritance Off # </Directory> #</IfModule> When I get into phpmyadmin webpage, I am not prompted for user and password, before getting the error message: Forbidden: You don't have permission to access /phpmyadmin on this server. My system is Fedora 20

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  • Fedora 14 update probelem

    - by Marko
    How is everybody doin? :) Im having this problem with Fedora 14 update for last couple of weeks.. when I run yum update I get the following result: Running rpm_check_debug ERROR with rpm_check_debug vs depsolve: kernel-uname-r = 2.6.32.10-90.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.10-90.fc12.i686.PAE-1:195.36.15-1.fc12.1.i686 kernel-uname-r = 2.6.32.16-150.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.16-150.fc12.i686.PAE-1:195.36.31-1.fc12.2.i686 kernel-uname-r = 2.6.32.21-168.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.21-168.fc12.i686.PAE-1:195.36.31-1.fc12.5.i686 kernel-uname-r = 2.6.32.10-90.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.10-90.fc12.i686.PAE-1:195.36.15-1.fc12.1.i686 kernel-uname-r = 2.6.32.16-150.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.16-150.fc12.i686.PAE-1:195.36.31-1.fc12.2.i686 kernel-uname-r = 2.6.32.21-168.fc12.i686.PAE is needed by (installed) kmod-nvidia-2.6.32.21-168.fc12.i686.PAE-1:195.36.31-1.fc12.5.i686 Please report this error in http://yum.baseurl.org/report ** Found 9 pre-existing rpmdb problem(s), 'yum check' output follows: VirtualBox-3.2-3.2.10_66523_fedora13-1.i686 has missing requires of libpython2.6.so.1.0 VirtualBox-3.2-3.2.10_66523_fedora13-1.i686 has missing requires of python(abi) = ('0', '2.6', None) 1:kmod-nvidia-2.6.32.10-90.fc12.i686.PAE-195.36.15-1.fc12.1.i686 has missing requires of kernel-uname-r = ('0', '2.6.32.10', '90.fc12.i686.PAE') 1:kmod-nvidia-2.6.32.16-150.fc12.i686.PAE-195.36.31-1.fc12.2.i686 has missing requires of kernel-uname-r = ('0', '2.6.32.16', '150.fc12.i686.PAE') 1:kmod-nvidia-2.6.32.21-168.fc12.i686.PAE-195.36.31-1.fc12.5.i686 has missing requires of kernel-uname-r = ('0', '2.6.32.21', '168.fc12.i686.PAE') mysql-workbench-gpl-5.2.28-1fc13.i386 has missing requires of libpython2.6.so.1.0 pysvn-1.7.2-1.fc13.i686 has missing requires of python(abi) = ('0', '2.6', None) system-config-display-2.2-1.fc12.i686 has missing requires of libpython2.6.so.1.0 system-config-display-2.2-1.fc12.i686 has missing requires of python(abi) = ('0', '2.6', None) does anybody have a similar issue?

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  • SSLVerifyClient optional with location-based exceptions

    - by Ian Dunn
    I have a site that requires authentication in order to access certain directories, but not others. (The "directories" are really just rewrite rules that all pass through /index.php) In order to authenticate, the user can either login with a standard username/password, or submit a client-side x509 certificate. So, Apache's vhost conf looks something like this: SSLCACertificateFile /etc/pki/CA/certs/redacted-ca.crt SSLOptions +ExportCertData +StdEnvVars SSLVerifyClient none SSLVerifyDepth 1 <LocationMatch "/(foo-one|foo-two|foo-three)"> SSLVerifyClient optional </LocationMatch> That works fine, but then large file uploads fail because of the behavior documented in bug 12355. The workaround for that is to set SSLVerifyClient require (or optional) as the default, so now the conf looks like this SSLCACertificateFile /etc/pki/CA/certs/redacted-ca.crt SSLOptions +ExportCertData +StdEnvVars SSLVerifyClient optional SSLVerifyDepth 1 <LocationMatch "/(bar-one|bar-two|bar-three)"> SSLVerifyClient none </LocationMatch> That fixes the upload problem, but the SSLVerifyClient none doesn't work for bar-one, bar-two, etc. Those directories are still prompted to present a certificate. Additionally, I also need the root URL to accessible without the user being prompted for a certificate. I'm afraid that will cancel out the workaround, though.

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  • Exclamation 403 forbidden for cgi-bin/ and cannot protect site with password

    - by gasgdasdgasdg
    First problem i have is i am getting 403 forbidden error for cgi-bin/ I have created a new /var/www2/ i can access it fine. php runs fine. Second problem is I cannot password protect it. i first tried doing htpasswd, it asks for login but everytime i login it keeps asking for new one. its getting frustrating, i have tried all tricks. and doesn't seem to work. this is a virtual host config inside sites-available. httpd.conf is empty but i have apache2.conf Code: NameVirtualHost 12.12.12.12. <VirtualHost 12.12.12.12> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /var/www2/cgi-bin/ <Directory "/var/www2/cgi-bin/"> AllowOverride Options Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch AddHandler cgi-script cgi pl Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost>

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  • Why is cron mailing me program output even though I've redirected to /dev/null?

    - by Server Fault
    I'm trying to restart a system process through cron and getting emailed the startup output of the process. I thought redirecting STDOUT and SDTERR to /dev/null would "silence" the output but alas, this has not work. How can I get cron to silently restart this service? crontab entry: 0 6 * * * service sympa stop &>/dev/null; service sympa start &> /dev/null sample output from restart email: Stopping Sympa bounce manager bounced ...done. * Stopping Sympa task manager task_manager ...done. * Stopping Sympa mailing list archive manager archived ...done. * Stopping Sympa mailing list manager sympa ...done. ... waiting Prototype mismatch: sub Lock::LOCK_SH () vs none at /home/sympa/bin/Lock.pm line 38. Constant subroutine LOCK_SH redefined at /home/sympa/bin/Lock.pm line 38. Prototype mismatch: sub Lock::LOCK_EX () vs none at /home/sympa/bin/Lock.pm line 39. Constant subroutine LOCK_EX redefined at /home/sympa/bin/Lock.pm line 39. Prototype mismatch: sub Lock::LOCK_NB () vs none at /home/sympa/bin/Lock.pm line 40. Constant subroutine LOCK_NB redefined at /home/sympa/bin/Lock.pm line 40.

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  • How to Set Up an SMTP Submission Server on Linux

    - by Kevin Cox
    I was trying to set up a mail server with no luck. I want it to accept mail from authenticated users only and deliver them. I want the users to be able to connect over the internet. Ideally the mail server wouldn't accept any incoming mail. Essentially I want it to accept messages on a receiving port and transfer them to the intended recipient out port 25. If anyone has some good links and guides that would be awesome. I am quite familiar with linux but have never played around with MTA's and am currently running debian 6. More Specific Problem! Sorry, that was general and postfix is complex. I am having trouble enabling the submission port with encryption and authentication. What Works: Sending mail from the local machine. (sendmail [email protected]). Ports are open. (25 and 587) Connecting to 587 appears to work, I get a "need to starttls" warning and starttls appears to work. But when I try to connect with the next command I get the error below. # openssl s_client -connect localhost:587 -starttls smtp CONNECTED(00000003) depth=0 /CN=localhost.localdomain verify error:num=18:self signed certificate verify return:1 depth=0 /CN=localhost.localdomain verify return:1 --- Certificate chain 0 s:/CN=localhost.localdomain i:/CN=localhost.localdomain --- Server certificate -----BEGIN CERTIFICATE----- MIICvDCCAaQCCQCYHnCzLRUoMTANBgkqhkiG9w0BAQUFADAgMR4wHAYDVQQDExVs b2NhbGhvc3QubG9jYWxkb21haW4wHhcNMTIwMjE3MTMxOTA1WhcNMjIwMjE0MTMx OTA1WjAgMR4wHAYDVQQDExVsb2NhbGhvc3QubG9jYWxkb21haW4wggEiMA0GCSqG SIb3DQEBAQUAA4IBDwAwggEKAoIBAQDEFA/S6VhJihP6OGYrhEtL+SchWxPZGbgb VkgNJ6xK2dhR7hZXKcDtNddL3uf1YYWF76efS5oJPPjLb33NbHBb9imuD8PoynXN isz1oQEbzPE/07VC4srbsNIN92lldbRruDfjDrAbC/H+FBSUA2ImHvzc3xhIjdsb AbHasG1XBm8SkYULVedaD7I7YbnloCx0sTQgCM0Vjx29TXxPrpkcl6usjcQfZHqY ozg8X48Xm7F9CDip35Q+WwfZ6AcEkq9rJUOoZWrLWVcKusuYPCtUb6MdsZEH13IQ rA0+x8fUI3S0fW5xWWG0b4c5IxuM+eXz05DvB7mLyd+2+RwDAx2LAgMBAAEwDQYJ KoZIhvcNAQEFBQADggEBAAj1ib4lX28FhYdWv/RsHoGGFqf933SDipffBPM6Wlr0 jUn7wler7ilP65WVlTxDW+8PhdBmOrLUr0DO470AAS5uUOjdsPgGO+7VE/4/BN+/ naXVDzIcwyaiLbODIdG2s363V7gzibIuKUqOJ7oRLkwtxubt4D0CQN/7GNFY8cL2 in6FrYGDMNY+ve1tqPkukqQnes3DCeEo0+2KMGuwaJRQK3Es9WHotyrjrecPY170 dhDiLz4XaHU7xZwArAhMq/fay87liHvXR860tWq30oSb5DHQf4EloCQK4eJZQtFT B3xUDu7eFuCeXxjm4294YIPoWl5pbrP9vzLYAH+8ufE= -----END CERTIFICATE----- subject=/CN=localhost.localdomain issuer=/CN=localhost.localdomain --- No client certificate CA names sent --- SSL handshake has read 1605 bytes and written 354 bytes --- New, TLSv1/SSLv3, Cipher is DHE-RSA-AES256-SHA Server public key is 2048 bit Secure Renegotiation IS supported Compression: NONE Expansion: NONE SSL-Session: Protocol : TLSv1 Cipher : DHE-RSA-AES256-SHA Session-ID: E07926641A5EF22B15EB1D0E03FFF75588AB6464702CF4DC2166FFDAC1CA73E2 Session-ID-ctx: Master-Key: 454E8D5D40380DB3A73336775D6911B3DA289E4A1C9587DDC168EC09C2C3457CB30321E44CAD6AE65A66BAE9F33959A9 Key-Arg : None Start Time: 1349059796 Timeout : 300 (sec) Verify return code: 18 (self signed certificate) --- 250 DSN read:errno=0 If I try to connect from evolution I get the following error: The reported error was "HELO command failed: TCP connection reset by peer".

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  • Install mod_perl2 on Apache 2.2.14 (Ubuntu10.04)

    - by MICADO
    Hi guys, I have installed via synaptic package ibapache2-mod-perl2. I tried this line in httpd.conf: "LoadModule perl_module modules/mod_perl.so" Apache tells me when I reload the server : "[warn] module perl_module is already loaded, skipping". Well ok, but when i try to look in the browser to a repertory i don't have access .Apache send me the error : Forbidden You don't have permission to access /cgi-bin/ on this server. Apache/2.2.14 (Ubuntu) Server at 192.168.0.10 Port 90 But this should show modperl is installed and that's not the case... I would like my virtual host that follows run with mod_perl2 <VirtualHost v1:80> ServerAdmin webmaster@localhost ServerName v1 DocumentRoot /var/www/v1 <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www/v1/html/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /var/www/v1/cgi-bin/ <Directory "/var/www/v1/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> I'd like to know how to configure mod_perl2. Do i have to change something in the apache configuration file to make my cgi repertory works with mod_perl2? Thanks to any help!

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  • Apache Virtualhosts with PHP and custom logs - how to isolate PHP errors?

    - by Repox
    I'm trying to setup a simple hosting enviroment for my application on an Ubuntu server. I created a virtualhost like this: <VirtualHost *:80> ServerAdmin [email protected] ServerName www.example.com ServerAlias example.com DocumentRoot /home/owner/example.com/docs <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /home/owner/example.com/docs/> Options -Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /home/owner/example.com/logs/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /home/owner/example.com/logs/access.log combined php_flag log_errors on php_value error_log /home/owner/example.com/logs/php-error.log </VirtualHost> Now, my problem is that PHP errors and warnings are thrown in the error.log - not the php-error.log as I was hoping. How can achieve this?

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  • windows server 2003 speed issues

    - by farzinSH
    I have a HP server with windows server 2003 and 50 windows XP clients. Since a week and a half the networks speed suddenly drop 2-3 times per day. It gets so slow that none of the clients could work with the HIS program installed on them. We tried so many different things such as replacing the hubs,switches and even some wires. Every time one of these changes solves the problem and the network goes back to its normal state. I checked everything. Even when I disconnected all the clients from the server and connected it to just one computer the problem still remained for 2 hours. I just narrowed down the problem to the couple of likely speculations as follows: viruses? (Updated Kaspersky running on the server shows none) server hardware failure? Physical memory usage on the server? (Because the last time the problem occurred none of the changes above solved the issue so I restarted the server an checked the physical memory usage which was 2 GBs. But I noticed it's increasing over time to over 9 GBs...the server has 16 GBs of RAM.) I surfed the internet and got nothing. Any help would do us a lot....thanks in advance

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  • Where is meta.local_fields set in django.db.models.base.py ?

    - by BryanWheelock
    I'm getting the error: Exception Value: (1110, "Column 'about' specified twice") As I was reviewing the Django error page, I noticed that the customizations the model User, seem to be appended to the List twice. This seems to be happening here in django/db/model/base.py in base_save(): values = [(f, f.get_db_prep_save(raw and getattr(self, f.attname) or f.pre_save(self, True))) for f in meta.local_fields] this is what Django error page shows values to be: values = [(<django.db.models.fields.CharField object at 0xa78996c>, u'kallie'), (<django.db.models.fields.CharField object at 0xa7899cc>, ''), (<django.db.models.fields.CharField object at 0xa789a2c>, ''), (<django.db.models.fields.EmailField object at 0xa789a8c>, u'[email protected]'), (<django.db.models.fields.CharField object at 0xa789b2c>, 'sha1$d4a80$0e5xxxxxxxxxxxxxxxxxxxxddadfb07'), (<django.db.models.fields.BooleanField object at 0xa789bcc>, False), (<django.db.models.fields.BooleanField object at 0xa789c6c>, True), (<django.db.models.fields.BooleanField object at 0xa789d2c>, False), (<django.db.models.fields.DateTimeField object at 0xa789dcc>, u'2010-02-03 14:54:35'), (<django.db.models.fields.DateTimeField object at 0xa789e2c>, u'2010-02-03 14:54:35'), # this is where the values from the User model customizations show up (<django.db.models.fields.BooleanField object at 0xa8c69ac>, False), (<django.db.models.fields.CharField object at 0xa8c688c>, None), (<django.db.models.fields.PositiveIntegerField object at 0xa8c69cc>, 1), (<django.db.models.fields.CharField object at 0xa8c69ec>, 'b5ab1603b2308xxxxxxxxxxx75bca1'), (<django.db.models.fields.SmallIntegerField object at 0xa8c6dac>, 0), (<django.db.models.fields.SmallIntegerField object at 0xa8c6e4c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xa8c6e8c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xa8c6ecc>, 10), (<django.db.models.fields.DateTimeField object at 0xa8c6eec>, u'2010-02-03 14:54:35'), (<django.db.models.fields.CharField object at 0xa8c6f2c>, ''), (<django.db.models.fields.URLField object at 0xa8c6f6c>, ''), (<django.db.models.fields.CharField object at 0xa8c6fac>, ''), (<django.db.models.fields.DateField object at 0xa8c6fec>, None), (<django.db.models.fields.TextField object at 0xa8cb04c>, ''), # at this point User model customizations repeats itself (<django.db.models.fields.BooleanField object at 0xa663b0c>, False), (<django.db.models.fields.CharField object at 0xaa1e94c>, None), (<django.db.models.fields.PositiveIntegerField object at 0xaa1e34c>, 1), (<django.db.models.fields.CharField object at 0xaa1e40c>, 'b5ab1603b2308050ebd62f49ca75bca1'), (<django.db.models.fields.SmallIntegerField object at 0xa8c6d8c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xaa2378c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xaa237ac>, 0), (<django.db.models.fields.SmallIntegerField object at 0xaa237ec>, 10), (<django.db.models.fields.DateTimeField object at 0xaa2380c>, u'2010-02-03 14:54:35'), (<django.db.models.fields.CharField object at 0xaa2384c>, ''), (<django.db.models.fields.URLField object at 0xaa2388c>, ''), (<django.db.models.fields.CharField object at 0xaa238cc>, ''), (<django.db.models.fields.DateField object at 0xaa2390c>, None), (<django.db.models.fields.TextField object at 0xaa2394c>, '')] Since this app is in Production, I can't figure out how to use pdb.set_trace() to see what's going on inside of save_base. The customizations to User are: User.add_to_class('email_isvalid', models.BooleanField(default=False)) User.add_to_class('email_key', models.CharField(max_length=16, null=True)) User.add_to_class('reputation', models.PositiveIntegerField(default=1)) User.add_to_class('gravatar', models.CharField(max_length=32)) User.add_to_class('email_feeds', generic.GenericRelation(EmailFeed)) User.add_to_class('favorite_questions', models.ManyToManyField(Question, through=FavoriteQuestion, related_name='favorited_by')) User.add_to_class('badges', models.ManyToManyField(Badge, through=Award, related_name='awarded_to')) User.add_to_class('gold', models.SmallIntegerField(default=0)) User.add_to_class('silver', models.SmallIntegerField(default=0)) User.add_to_class('bronze', models.SmallIntegerField(default=0)) User.add_to_class('questions_per_page', models.SmallIntegerField(choices=QUESTIONS_PER_PAGE_CHOICES, default=10)) User.add_to_class('last_seen', models.DateTimeField(default=datetime.datetime.now)) User.add_to_class('real_name', models.CharField(max_length=100, blank=True)) User.add_to_class('website', models.URLField(max_length=200, blank=True)) User.add_to_class('location', models.CharField(max_length=100, blank=True)) User.add_to_class('date_of_birth', models.DateField(null=True, blank=True)) User.add_to_class('about', models.TextField(blank=True)) Django1.1.1 Python 2.5

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  • CSS * {margin: 0;padding: 0;} override

    - by StealthRT
    Hey all, i am in need of some help with figuring out how to override the "* {margin: 0;padding: 0;}" in my css. The reason why is that i have this css: .postcomments { width: 547px; padding: 5px 5px 5px 5px; margin: 0 0 5px 0;} .postcomments a { text-decoration: underline;} .postcomments ul { margin: 0; padding: 0; list-style-type: none;} .postcomments ul li { width: 547px; margin: 0 0 5px 0; padding: 0; list-style-type: none;} .postcomments .right { color: #474747; font-size: 11px; background: #fff url('http://www.nextbowluser.com/img/ucBG.gif') no-repeat top left; line-height: 17px; padding: 5px 0 0 0; width: 430px; position: relative; float: right; min-height: 50px;} .postcomments .right .bottom { padding: 0 5px 15px 5px; background: #fff url('http://www.nextbowluser.com/img/ucBG.gif') no-repeat bottom right; min-height: 50px;} .postcomments .arrow { left: -15px; top: 20px; position: absolute;} .avatar { border: none !important;} .postcomments .left {float: left; margin: 0 7px 0 0;} .postcomments .gravatar { background: #fff; width: 80px; height: 60px; margin: 0 0px 0 0; padding: 3px;} .postcomments .name { font-size: 11px; margin: 2px 0 0 0; color: #000;} .avatar { border: none !important;} and it displays just fine WITHOUT the * {margin: 0;padding: 0;}: 1st comment 2nd comment 3rd comment However, when i add that to the CSS, it makes the comments stack wrong: 1st comment 2nd comment 3rd comment I would just take out the * {margin: 0;padding: 0;} but some other things on the page needs that in order for that to be displayed correctly. So my question is, how can i override the {margin: 0;padding: 0;} for just that postcomments part of the page? Thanks! :o) David

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  • Word Anagram Hashing Algorithm?

    - by Ahmed Said
    Given set of words, we need to find the anagram words and display each category alone using the best algorithm input: man car kile arc none like output: man car arc kile like none the best solution I am developing now is based on a hashtable, but I am thinking about equation to convert anagram word into integer value exmaple: man = 'm'+'a'+'n' but this will not give unique values any suggestions?

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  • jquery ui tabs close button beneath the text

    - by Pradyut Bhattacharya
    Hi I m using jquery ui tabs and i m using them with the function of dynamically closing them. the example page here where clicking on the link 'add tab' leads to adding of tabs in the tabs panel... now in firefox the close buttons are displayed beneath the text of the tab which is leading to garbled text in the tab panel or the body of the tabs like other browsers how can i display it in same line the css i m using is .ui-tabs { padding: .20em; zoom: 1; } .ui-tabs .ui-tabs-nav { list-style: none; position: relative; padding: .2em .2em 0; height:27px; } .ui-tabs .ui-tabs-nav li { position: relative; float: left; border-bottom-width: 0 !important; margin: 0 .2em -1px 0; padding: 0; font-size:63.5%; } .ui-tabs .ui-tabs-nav li a { float: left; text-decoration: none; padding: .5em 1em; } .ui-tabs .ui-tabs-nav li.ui-tabs-selected { padding-bottom: 1px; border-bottom-width: 0; } .ui-tabs .ui-tabs-nav li.ui-tabs-selected a, .ui-tabs .ui-tabs-nav li.ui-state-disabled a, .ui-tabs .ui-tabs-nav li.ui-state-processing a { cursor: text; } .ui-tabs .ui-tabs-nav li a, .ui-tabs.ui-tabs-collapsible .ui-tabs-nav li.ui-tabs-selected a { cursor: pointer; font: 62.5%; } .ui-tabs .ui-tabs-panel { padding: 1em 1.4em; display: block; border-width: 0; background:black; color:white; font-size: 12px; } .ui-tabs .ui-tabs-hide { display: none !important; font: 62.5%; } #tabs .ui-tabs-nav li a:hover { float: left; text-decoration: none; padding: .5em 1em; background-color: #868472; } #tabs-profile .ui-tabs-nav li { position: relative; float: left; border-bottom-width: 0 !important; margin: 0 .2em -1px 0; padding: 0; font-size:75%; } Please help thanks Pradyut India

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  • Ignoring hover style in inside image

    - by user289249
    I want the style to apply on the "a" elements, and not the img. Here's an example: a:hover {background: #555;} I tried to do something like this: a:hover img {background: none;} though I knew it's not going to do anything. The solution I found in this question didn't work for me, because the "display: none" is moving the image when hovering.

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  • CSS sliding doors technique for buttons, IE8 problem

    - by Kelvin
    Hello All! I used sliding doors technique, explained here: http://www.oscaralexander.com/tutorials/how-to-make-sexy-buttons-with-css.html With only one exception, that I decided to add one more image for "hover" effect. My code works well for all browsers, except IE8 (and maybe earlier versions). a.submit-button:active and a.submit-button:active span are simply blocked by "hover" and never work. Does anyone knows solution for this? Thanks a lot in advance! <style type="text/css"> .clear { /* generic container (i.e. div) for floating buttons */ overflow: hidden; width: 100%; } a.submit-button { background: transparent url('images/button-1b.png') no-repeat scroll top right; color: #fff; display: block; float: left; font: bold 13px sans-serif, arial; height: 28px; margin-right: 6px; padding-right: 18px; /* sliding doors padding */ text-decoration: none; outline: none; } a.submit-button span { background: transparent url('images/button-1a.png') no-repeat; display: block; line-height: 14px; padding: 6px 0 8px 24px; } a.submit-button:hover { background-position: right -28px; outline: none; /* hide dotted outline in Firefox */ color: #fff; } a.submit-button:hover span { background-position: 0px -28px; } a.submit-button:active { background-position: right -56px; color: #e5e5e5; outline: none; } a.submit-button:active span { background-position: 0px -56px; padding: 7px 0 7px 24px; /* push text down 1px */ } </style> And this is the button: <div class="clear"> <a class="submit-button" href="#" onclick="this.blur();"><span>Hello All</span></a> </div>

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  • Flowplayer in fancybox?

    - by kastru
    I am trying to get the Flowplayer to be shown inside a Fancybox, but can't quite get it working. This is my code so far; $("a.video_link").click(function () { $.fancybox({ 'autoScale': false, 'transitionIn': 'none', 'transitionOut': 'none', 'title': this.title, 'width': 680, 'height': 495, 'href': '/flowplayer/flowplayer.swf?video=myvideo.flv', /* have also tried a couple of other options for the url settings, but without luck) 'type': 'swf', 'swf': { 'wmode': 'transparent', 'allowfullscreen': 'true' } }); return false; }); Any suggestions?

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  • Odd behavior in Django Form (readonly field/widget)

    - by jamida
    I'm having a problem with a test app I'm writing to verify some Django functionality. The test app is a small "grade book" application that is currently using Alex Gaynor's readonly field functionality http://lazypython.blogspot.com/2008/12/building-read-only-field-in-django.html There are 2 problems which may be related. First, when I flop the comment on these 2 lines below: # myform = GradeForm(data=request.POST, instance=mygrade) myform = GradeROForm(data=request.POST, instance=mygrade) it works like I expect, except of course that the student field is changeable. When the comments are the shown way, the "studentId" field is displayed as a number (not the name, problem 1) and when I hit submit I get an error saying that studentId needs to be a Student instance. I'm at a loss as to how to fix this. I'm not wedded to Alex Gaynor's code. ANY code will work. I'm relatively new to both Python and Django, so the hints I've seen on websites that say "making a read-only field is easy" are still beyond me. // models.py class Student(models.Model): name = models.CharField(max_length=50) parent = models.CharField(max_length=50) def __unicode__(self): return self.name class Grade(models.Model): studentId = models.ForeignKey(Student) finalGrade = models.CharField(max_length=3) # testbed.grades.readonly is alex gaynor's code from testbed.grades.readonly import ReadOnlyField class GradeROForm(ModelForm): studentId = ReadOnlyField() class Meta: model=Grade class GradeForm(ModelForm): class Meta: model=Grade // views.py def modifyGrade(request,student): student = Student.objects.get(name=student) mygrade = Grade.objects.get(studentId=student) if request.method == "POST": # myform = GradeForm(data=request.POST, instance=mygrade) myform = GradeROForm(data=request.POST, instance=mygrade) if myform.is_valid(): grade = myform.save() info = "successfully updated %s" % grade.studentId else: # myform=GradeForm(instance=mygrade) myform=GradeROForm(instance=mygrade) return render_to_response('grades/modifyGrade.html',locals()) // template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myform.as_table }} </table> <input type="submit" value="Submit"> </form> // Alex Gaynor's code from django import forms from django.utils.html import escape from django.utils.safestring import mark_safe from django.forms.util import flatatt class ReadOnlyWidget(forms.Widget): def render(self, name, value, attrs): final_attrs = self.build_attrs(attrs, name=name) if hasattr(self, 'initial'): value = self.initial return mark_safe("<span %s>%s</span>" % (flatatt(final_attrs), escape(value) or '')) def _has_changed(self, initial, data): return False class ReadOnlyField(forms.FileField): widget = ReadOnlyWidget def __init__(self, widget=None, label=None, initial=None, help_text=None): forms.Field.__init__(self, label=label, initial=initial, help_text=help_text, widget=widget) def clean(self, value, initial): self.widget.initial = initial return initial

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  • CSS Footer bar bottom center issue

    - by StealthRT
    Hey all, i am trying to get my bottom bar to center on the screen but i am unable to do so. <style type="text/css"> body { background: #fffff; margin: 0; padding: 0; font: 10px normal Verdana, Arial, Helvetica, sans-serif; } * {margin: 0; padding: 0; outline: none;} #bottomBar { position: fixed; bottom: 0px; left: 0px; z-index: 9999; background: #e3e2e2; border: 1px solid #c3c3c3; border-bottom: none; width: 500px; min-width: 500px; margin: 0px auto; -moz-opacity:.90; filter:alpha(opacity=90); opacity:.90; } *html #bottomBar {margin-top: -1px; position: absolute; top:expression(eval(document.compatMode &&document.compatMode=='CSS1Compat') ?documentElement.scrollTop+(documentElement.clientHeight-this.clientHeight) : document.body.scrollTop +(document.body.clientHeight-this.clientHeight));} #bottomBar ul {padding: 0; margin: 0;float: left;width: 100%;list-style: none;border-top: 1px solid #fff;} #bottomBar ul li{padding: 0; margin: 0;float: left;position: relative;} #bottomBar ul li a{padding: 5px;float: left;text-indent: -9999px;height: 16px; width: 16px;text-decoration: none;color: #333;position: relative;} html #bottomBar ul li a:hover{ background-color: #fff; } a.PDF{background: url(http://www.xxx.com/img/pdficon.png) no-repeat center center; } </style> <div id="bottomBar"> <ul id="mainpanel"> <li style="padding-top:5px; font-family:Arial, Helvetica, sans-serif; padding-left: 5px;">First time here? Be sure to check out the "this" button above or download the PDF here -></li> <li><a href="http://www.xxx.com" class="PDF">Download PDF <small>Download PDF</small></a></li> </ul> </div> Thanks! David

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  • How can join two django querysets in one?

    - by diegueus9
    I need order a Queryset by date in desc order, but i need put in the end the objects at the end, I do this: qs1 = Model.objects.exclude(date=None).order_by('-date') qs2 = Model.objects.filter(date=None).order_by('-date') and my list is: l = list(qs1)+list(qs2) There is a more efficiently way for this?

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  • two galleryView on the same page problem!

    - by user334922
    I'm using two galleryView on the same page, but the navigation control get crazy, and navigate the worng gallery sometimes.i think is because the gallery create the frame with the same name. how can i fix? $('#photos').galleryView({ panel_width: 650, panel_height: 400, frame_width: 60, frame_height: 60, transition_speed: 1200, transition_interval:0, border: 'none', nav_theme: 'dark' }); $('#videos').galleryView({ panel_width: 650, panel_height: 400, frame_width: 60, frame_height: 60, transition_speed: 1200, transition_interval:0, border: 'none', nav_theme: 'dark' });

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  • In python, changing MySQL query based on function variables

    - by ensnare
    I'd like to be able to add a restriction to the query if user_id != None ... for example: "AND user_id = 5" but I am not sure how to add this into the below function? Thank you. def get(id, user_id=None): query = """SELECT * FROM USERS WHERE text LIKE %s AND id = %s """ values = (search_text, id) results = DB.get(query, values) This way I can call: get(5) get(5,103524234) (contains user_id restriction)

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  • Comparing two large sets of attributes

    - by andyashton
    Suppose you have a Django view that has two functions: The first function renders some XML using a XSLT stylesheet and produces a div with 1000 subelements like this: <div id="myText"> <p id="p1"><a class="note-p1" href="#" style="display:none" target="bot">?</a></strong>Lorem ipsum</p> <p id="p2"><a class="note-p2" href="#" style="display:none" target="bot">?</a></strong>Foo bar</p> <p id="p3"><a class="note-p3" href="#" style="display:none" target="bot">?</a></strong>Chocolate peanut butter</p> (etc for 1000 lines) <p id="p1000"><a class="note-p1000" href="#" style="display:none" target="bot">?</a></strong>Go Yankees!</p> </div> The second function renders another XML document using another stylesheet to produce a div like this: <div id="myNotes"> <p id="n1"><cite class="note-p1"><sup>1</sup><span>Trololo</span></cite></p> <p id="n2"><cite class="note-p1"><sup>2</sup><span>Trololo</span></cite></p> <p id="n3"><cite class="note-p2"><sup>3</sup><span>lololo</span></cite></p> (etc for n lines) <p id="n"><cite class="note-p885"><sup>n</sup><span>lololo</span></cite></p> </div> I need to see which elements in #myText have classes that match elements in #myNotes, and display them. I can do this using the following jQuery: $('#myText').find('a').each(function() { var $anchor = $(this); $('#myNotes').find('cite').each(function() { if($(this).attr('class') == $anchor.attr('class')) { $anchor.show(); }); }); However this is incredibly slow and inefficient for a large number of comparisons. What is the fastest/most efficient way to do this - is there a jQuery/js method that is reasonable for a large number of items? Or do I need to reengineer the Django code to do the work before passing it to the template?

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  • Python form POST using urllib2 (also question on saving/using cookies)

    - by morpheous
    I am trying to write a function to post form data and save returned cookie info in a file so that the next time the page is visited, the cookie information is sent to the server (i.e. normal browser behavior). I wrote this relatively easily in C++ using curlib, but have spent almost an entire day trying to write this in Python, using urllib2 - and still no success. This is what I have so far: import urllib, urllib2 import logging # the path and filename to save your cookies in COOKIEFILE = 'cookies.lwp' cj = None ClientCookie = None cookielib = None logger = logging.getLogger(__name__) # Let's see if cookielib is available try: import cookielib except ImportError: logger.debug('importing cookielib failed. Trying ClientCookie') try: import ClientCookie except ImportError: logger.debug('ClientCookie isn\'t available either') urlopen = urllib2.urlopen Request = urllib2.Request else: logger.debug('imported ClientCookie succesfully') urlopen = ClientCookie.urlopen Request = ClientCookie.Request cj = ClientCookie.LWPCookieJar() else: logger.debug('Successfully imported cookielib') urlopen = urllib2.urlopen Request = urllib2.Request # This is a subclass of FileCookieJar # that has useful load and save methods cj = cookielib.LWPCookieJar() login_params = {'name': 'anon', 'password': 'pass' } def login(theurl, login_params): init_cookies(); data = urllib.urlencode(login_params) txheaders = {'User-agent' : 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'} try: # create a request object req = Request(theurl, data, txheaders) # and open it to return a handle on the url handle = urlopen(req) except IOError, e: log.debug('Failed to open "%s".' % theurl) if hasattr(e, 'code'): log.debug('Failed with error code - %s.' % e.code) elif hasattr(e, 'reason'): log.debug("The error object has the following 'reason' attribute :"+e.reason) sys.exit() else: if cj is None: log.debug('We don\'t have a cookie library available - sorry.') else: print 'These are the cookies we have received so far :' for index, cookie in enumerate(cj): print index, ' : ', cookie # save the cookies again cj.save(COOKIEFILE) #return the data return handle.read() # FIXME: I need to fix this so that it takes into account any cookie data we may have stored def get_page(*args, **query): if len(args) != 1: raise ValueError( "post_page() takes exactly 1 argument (%d given)" % len(args) ) url = args[0] query = urllib.urlencode(list(query.iteritems())) if not url.endswith('/') and query: url += '/' if query: url += "?" + query resource = urllib.urlopen(url) logger.debug('GET url "%s" => "%s", code %d' % (url, resource.url, resource.code)) return resource.read() When I attempt to log in, I pass the correct username and pwd,. yet the login fails, and no cookie data is saved. My two questions are: can anyone see whats wrong with the login() function, and how may I fix it? how may I modify the get_page() function to make use of any cookie info I have saved ?

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  • QTreeWidget activate item signals

    - by serge
    Hi everyone, I need to do some actions when item in QTreeWidget activates, but following code doestn't gives me expected result: class MyWidget(QTreeWidget): def __init__(self, parent=None): super(MyWidget, self).__init__(parent) self.connect(self, SIGNAL("activated(QModelIndex)"), self.editCell) def editCell(self, index): print index or class MyWidget(QTreeWidget): def __init__(self, parent=None): super(MyWidget, self).__init__(parent) self.connect(self, SIGNAL("itemActivated(QTreeWidgetItem, int)"), self.editCell) def editCell(self, item, column=0): print item What am i doing wrong or how to hadnle item activation in the right way? Thanks in advance, Serge

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