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  • How to keep same substrings in vim regex

    - by invisiblerhino
    Hi everyone. I'd ideally like a vim answer to this: I want to change [*, 1, *, *] to [*, 2, *, *] Here the stars refer to individual characters in the substring, which I would like to keep unchanged. For example [0, 1, 0, 1] to [0, 2, 0, 1] [1, 1, 1, 1] to [1, 2, 1, 1] If people know how to do this in perl or python or whatever, that would be equally good. Cheers

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  • Regex to delete HTML within <table> tags

    - by johnv
    I have an HTML document in .txt format containing multiple tables and other texts and I am trying to delete any HTML (anything within "<") if it's inside a table (between and ). For example: =================== other text <other HTML> <table> <b><u><i>bold underlined italic text</b></u></i> </table> other text <other HTML> ============== The final output would be as the following. Note that only HTML within and are removed. ============== other text <other HTML> <table> bold underlined italic text </table> other text <other HTML> ============= Any help is greatly appreciated!

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  • How to format given string using regex?

    - by icoolninja
    So I have defined variables in such a way in my file: public static final String hello_world = "hello world" public static final String awesome_world = "awesome world" public static final String bye_world= "bye world" I have many declarations like that. Is it possible to format them as(All '=' in a line): public static final String hello_world = "hello world" public static final String awesome_world = "awesome world" public static final String bye_world = "bye world" I can't even think of a way to do it. Any kind of help is appreciated. P.S If it matters, I use sublime text 2.

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  • Allow a new line anywhere in the regex?

    - by Scott Chamberlain
    I am having a find a replace in a bunch of RTF documents, The basic pattern I need is \{(?:\\\*)?\\field\\fldlock\{\\\*\\fldinst ?MERGEFIELD ?((?:\\.*?)?[\w\[\]]+?)(?:\\.*?)?\}(?:\{\\fldrslt\})?\} However I then found out there could potentialy be a newline before each slash, so it turned in to this. \{(?:\s*\\\*)?\s*\\field\s*\\fldlock\s*\{\s*\\\*\s*\\fldinst\s*MERGEFIELD\s*((?:\\.*?)?[\w\[\]]+?(?:\s*\\.*?)?)?\s*\}(?:\s*\{\s*\\fldrslt\s*\})?\s*\} But then I hit this it fails fees totaling $\protect {\field\fldlock{\*\fldinst MERGEFIELD ENTEROUTSTANDINGVETERINARYF EES}}\plain\f0\fs24\prot Is there way have to have it match a new line anywhere in the search too without adding (?:\r?\n)? everywhere? EDIT To clear up confusion on the new lines. I need to keep the newlines in the document, I only want to remove the newlines if they are inside my match, so in the final example I posted it should replace fees totaling $\protect {\field\fldlock{\*\fldinst MERGEFIELD ENTEROUTSTANDINGVETERINARYF EES}}\plain\f0\fs24\prot with fees totaling $\protect ENTEROUTSTANDINGVETERINARYFEES\plain\f0\fs24\prot

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  • Regex for zeroing in on build output text error

    - by Mike Atlas
    I'd like to quickly hone in on what failed in a build log output that is nearly 5k lines long, using Notepad++ as my editor for the file. Notepad++ has the nice ability to specify regular expressions, so I am wondering if there is a way to not match: Compile complete -- 0 errors, 0 warnings but to match, for example: Compile complete -- 1 errors, 0 warnings Compile complete -- 100 errors, 0 warnings where the match would be (1 or more) errors. If this isn't possible, I will probably just write a quick line-by-line parsing tool instead, but I was hoping someone on StackOverflow could whip out a regular expression in the same amount of time - I'm definitely not proficient enough with regular expressions to be able to write one for my needs in a short amount of time.

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  • Regular expression, how to find all tags A which do not contain tag IMG inside it?

    - by Kirzilla
    Hello, Let's suppose that we have such HTML code. We need to get all <a href=""></a> tags which DO NOT contain img tag inside it. <a href="http://domain1.com"><span>Here is link</span></a> <a href="http://domain2.com" title="">Hello</a> <a href="http://domain3.com" title=""><img src="" /></a> <a href="http://domain4" title=""> I'm the image <img src="" /> yeah</a> I'm using this regular expression to find out all links preg_match_all("!<a[^>]+href=\"?'?([^ \"'>]+)\"?'?[^>]*>(.*?)</a>!is", $content, $out); I can modify it preg_match_all("!<a[^>]+href=\"?'?([^ \"'>]+)\"?'?[^>]*>([^<>]+?)</a>!is", $content, $out); But how can I tell to exclude results containing <img substring inside of <a href=""></a>? Thank you

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  • Easy Regex question

    - by Aaron
    Trying to replace the first 12 digits of credit card numbers with X's in a predictable blob of text that contains the string: Credit Card Number: 1234123412341234 Here's my PHP function: preg_replace('/Credit Card Number: ([0-9]{12})/','Credit Card Number: XXXXXXXXXXXX',$str); Help?

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  • android RegEx external GPS string

    - by user1271363
    I have a problem with seperating information in a string i get from the external GPS stream. Heres a example of a string: $GPGSV,3,3,12,22,09,276,31,25,24,247,24,27,54,131,,32,04,359,19*71 $GPGLL,5703.85365,N,00953.88360,E,075510.00,A,A*69 $GPPWR,028a,1,0,1,1 $GPRMC,075511.00,A,5703.85369,N,00953.88430,E,0.335,302.17,070912,,,A*6E $GPVTG,302.17,T,,M,0.335,N,0.621,K,A*3A Want i am trying to do is to get the " $GPGLL,5703.85365,N,00953.88360,E,075510.00,A,A*69 " out so i can grab the longtitude and latitude and then update my textview with it. But keep getting string out of bounch exeption and i start wondering if i am handling this in the wrong way. Anyone that can put me in the right direction in how to solve this?

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  • Regex: How to leave out webding font characters?

    - by DS
    Hi, I've a free text field on my form where the users can type in anything. Some users are pasting text into this field from Word documents with some weird characters that I don't want to go in my DB. (e.g. webding font characters) I'm trying to get a regular expression that would give me only the alphanum and the punctuation characters. But when I try the following, the output is still all the characters. How can I leave them out? <html><body><script type="text/javascript">var str="???????";document.write(str.replace(/[^a-zA-Z 0-9 [:punct]]+/g, " "));</script></body></html>

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  • Is there a way to optimise finding text items on a page (not regex)

    - by Jeepstone
    After seeing several threads rubbishing the regexp method of finding a term to match within an HTML document, I've used the Simple HTML DOM PHP parser (http://simplehtmldom.sourceforge.net/) to get the bits of text I'm after, but I want to know if my code is optimal. It feels like I'm looping too many times. Is there a way to optimise the following loop? //Get the HTML and look at the text nodes $html = str_get_html($buffer); //First we match the <body> tag as we don't want to change the <head> items foreach($html->find('body') as $body) { //Then we get the text nodes, rather than any HTML foreach($body->find('text') as $text) { //Then we match each term foreach ($terms as $term) { //Match to the terms within the text nodes $text->outertext = str_replace($term, '<span class="highlight">'.$term.'</span>', $text->outertext); } } } For example, would it make a difference to determine check if I have any matches before I start the loop maybe?

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  • excluding a column in csv file with regex

    - by JPro
    Is there any way to exclude/delete/replace one field from a csv file with some regexp in notepad++? I have a csv file with some data like this: '1','data1','data2','data3','data4','data5','data6','data7','data8','data9', 'data10','data11','data12','data13','data14','data15','data16','data17','data18', 'data19','data20','data21','data22','data23','\'data24 with some commas, here and there and some "double quotes", and fullstops.','data25','data26' The only problem I am facing is with data24 WHERE I encounter \' and then "" and some wild characters like , and .. This is particularly fixed at 24 field. For the purpose of clarity, I have entered a newline here. But the entire text above is in juts one line. Any ideas on how to solve? Thanks.

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  • Regex to remove all but file name from links

    - by Moasely
    Hi, I am trying to write a regexp that removes file paths from links and images. href="path/path/file" to href="file" href="/file" to href="file" src="/path/file" to src="file" and so on... I thought that I had it working, but it messes up if there are two paths in the string it is working on. I think my expression is too greedy. It finds the very last file in the entire string. This is my code that shows the expression messing up on the test input: <script type="text/javascript" src="/javascripts/jquery.js"></script> <script type="text/javascript"> $(document).ready(function(){ var s = '<a href="one/keepthis"><img src="/one/two/keep.this"></a>'; var t = s.replace(/(src|href)=("|').*\/(.*)\2/gi,"$1=$2$3$2"); alert(t); }); </script> It gives the output: <a href="keep.this"></a> The correct output should be: <a href="keepthis"><img src="keep.this"></a> Thanks for any tips!

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  • what is regular expression not generated over {a,b}?

    - by Loop
    Hello all, I am really stuck with these 2 question for over 2 days now. trying to figure out what the question means.... my tutor is out of town too.... write a regular expression for the only strings that are not generated over {a,b} by the expression: (a+b)*a(a+b)*. explain your reasoning. and i tried the second question, do you think is there any better answer than this one? what is regular expression of set of string that contain an odd number of a's or exactly two b's................(a((a|b)(a|b))*|bb).... coz i know to represent any odd length of a's, the RE is a((a|b)(a|b))*

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  • Prevent RegEx Hang on Large Matches...

    - by developerjay
    This is a great regular expression for dates... However it hangs indefinitely on this one page I tried... I wanted to try this page ( http://pleac.sourceforge.net/pleac%5Fpython/datesandtimes.html ) for the fact that it does have lots of dates on it and I want to grab all of them. I don't understand why it is hanging when it doesn't on other pages... Why is my regexp hanging and/or how could I clean it up to make it better/efficient ? Python Code: monthnames = "(?:Jan\w*|Feb\w*|Mar\w*|Apr\w*|May|Jun\w?|Jul\w?|Aug\w*|Sep\w*|Oct\w*|Nov(?:ember)?|Dec\w*)" pattern1 = re.compile(r"(\d{1,4}[\/\\\-]+\d{1,2}[\/\\\-]+\d{2,4})") pattern4 = re.compile(r"(?:[\d]*[\,\.\ \-]+)*%s(?:[\,\.\ \-]+[\d]+[stndrh]*)+[:\d]*[\ ]?(PM)?(AM)?([\ \-\+\d]{4,7}|[UTCESTGMT\ ]{2,4})*"%monthnames, re.I) patterns = [pattern4, pattern1] for pattern in patterns: print re.findall(pattern, s) btw... when i say im trying it against this site.. I'm trying it against the webpage source.

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  • Does this e-mail-regex exclude valid addresses?

    - by neo
    I tried to create a regular expression which catches all RFC-valid addresses but it's ok if some false-positives come through (though hopefully not so many). This is waht I came up so far: /^\b\S+@\S+\.[^\s@]{2,}\b$/ Is there any RFC-valid address which doesn't match against this expression or do you have any suggestions to improve it? I don't mind the false positives but I would be glad if you show me a few, too.

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  • preg_replace or regex string translation

    - by ccolon
    I found some partial help but cannot seem to fully accomplish what I need. I need to be able to do the following: I need an regular expression to replace any 1 to 3 character words between two words that are longer than 3 characters with a match any expression: For example: walk to the beach == walk(.*)beach If the 1 to 3 character word is not preceded by a word that's longer than 3 characters then I want to translate that 1 to 3 letter word to ' ?' For example: on the beach == on ?the ?beach The simpler the rule the better (of course, if there's an alternative more complicated version that's more performant then I'll take that as well as I eventually anticipate heavy usage eventually). This will be used in a PHP context most likely with preg_replace. Thus, if you can put it in that context then even better!

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  • Regex preg_match issue with commas

    - by Serge Sf
    This is my code to pre_match when an amount looks like this: $ 99.00 and it works if (preg_match_all('/[$]\s\d+(\.\d+)?/', $tout, $matches)) { $tot2 = $matches[0]; $tot2 = preg_replace("/\\\$/", '', $tot2);} I need to do the same thing for a amount that looks like this (with a comma): $ 99,00 Thank you for your help (changing dot for comma do not help, there is an "escape" thing I do not understand... Idealy I need to preg_match any number that looks like an amount with dot or commas and with or without dollar sign before or after (I know, it's a lot to ask :) since on the result form I want to scan there are phone and street numbers... UPDATE (For some reason I cannot comment on replies) : To test properly, I need to preg_replace the comma by a dot (since we are dealings with sums, I don't think calculations can be done on numbers with commas in it). So to clarify my question, I should say : I need to transform, let's say "$ 200,24" to "200.24". (could be amounts bettween 0.10 to 1000.99) : $tot2 = preg_replace("/\\\$/", '', $tot2);} (this code just deals with the $ (it works), I need adaptation to deal also with the change of (,) for (.))

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  • Problem with Regex Validator - VAB

    - by sarae
    Hi, I do the validation through configuration files. But, RegexValidator does not work properly. This Validator not disciplined even to unknown regular expression!! Do you know about this problem? Many thanks!!!

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  • Using Regex to Split String

    - by Janusz Jasinski
    So I have a string like this (the hashtags are delimiters) A1###B2###C3###12345.jpg I was wondering how would I access A1, B2 and C3 STRING1###STRING2###STRING3###STRING4.jpg SOME###THING###HERE###MEH.jpg EXTRACT###THIS###PLEASE###pah.jpg In one instance I'd like to extract the first string. In another the second, in another the third. I will be using this with Adobe Bridge to extract metadata items from the filename I am looping through each filename so would need Var1 = FirstString Var2 = SecondString Var3 = ThirdString

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