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  • Haskell FlatMap

    - by mvid
    I am a beginner interested in Haskell, and I have been trying to implement the flatmap (=) on my own to better understand it. Currently I have flatmap :: (t -> a) -> [t] -> [a] flatmap _ [] = [] flatmap f (x:xs) = f x : flatmap f xs which implements the "map" part but not the "flat". Most of the modifications I make result in the disheartening and fairly informationless Occurs check: cannot construct the infinite type: a = [a] When generalising the type(s) for `flatmap' error. What am I missing?

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  • Java Binary Tree. Priting InOrder traversal

    - by user69514
    I am having some problems printing an inOrder traversal of my binary tree. Even after inserting many items into the tree it's only printing 3 items. public class BinaryTree { private TreeNode root; private int size; public BinaryTree(){ this.size = 0; } public boolean insert(TreeNode node){ if( root == null) root = node; else{ TreeNode parent = null; TreeNode current = root; while( current != null){ if( node.getData().getValue().compareTo(current.getData().getValue()) <0){ parent = current; current = current.getLeft(); } else if( node.getData().getValue().compareTo(current.getData().getValue()) >0){ parent = current; current = current.getRight(); } else return false; if(node.getData().getValue().compareTo(parent.getData().getValue()) < 0) parent.setLeft(node); else parent.setRight(node); } } size++; return true; } /** * */ public void inOrder(){ inOrder(root); } private void inOrder(TreeNode root){ if( root.getLeft() !=null) this.inOrder(root.getLeft()); System.out.println(root.getData().getValue()); if( root.getRight() != null) this.inOrder(root.getRight()); } }

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  • How do you solve this Haskell problem using a fold map and take?

    - by Linda Cohen
    Define a function replicate which given a list of numbers returns a list with each number duplicated its value. Use a fold, map, and take .. replicate [5,1,3,2,8,1,2] output: [5,5,5,5,5,1,3,3,3,2,2,8,8,8,8,8,8,8,8,1,2,2] I've figure this out using List comprehension and recursion: replicate2 [] = [] replicate2 (n:nn) = take n(repeat n) ++ replicate2 nn but how would you use fold and map to do this? so far I have: replicate n = map (foldl1 (take n(repeat n)) n) n which is obviously wrong, but I think I am close.. so any help would be nice, THANKS!

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  • Set primary key with two integers

    - by user299196
    I have a table with primary key (ColumnA, ColumnB). I want to make a function or procedure that when passed two integers will insert a row into the table but make sure the largest integer always goes into ColumnA and the smaller one into ColumnB. So if we have SetKeysWithTheseNumbers(17, 19) would return |-----------------| |ColumnA | ColumnB| |-----------------| |19 | 17 | |-----------------| SetKeysWithTheseNumbers(19, 17) would return the same thing |-----------------| |ColumnA | ColumnB| |-----------------| |19 | 17 | |-----------------|

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  • How to make a increasing numbers after filenames in C?

    - by zaplec
    Hi, I have a little problem. I need to do some little operations on quite many files in one little program. So far I have decided to operate them in a single loop where I just change the number after the name. The files are all named TFxx.txt where xx is increasing number from 1 to 80. So how can I open them all in a single loop one after one? I have tried this: for(i=0; i<=80; i++) { char name[8] = "TF"+i+".txt"; FILE = open(name, r); /* Do something */ } As you can see the second line would be working in python but not in C. I have tried to do similiar running numbering with C to this program, but I haven't found out yet how to do that. The format doesn't need to be as it is on the second line, but I'd like to have some advice of how can I solve this problem. All I need to do is just be able to open many files and do same operations to them.

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  • understanding list[i-1] vs list[i]-1

    - by user3720527
    Hopefully this is a simple answer that I am just failing to understand. Full code is public static void mystery(int[] list) { for( int i = list.length - 1; i>1; i --) { if (list[i] > list[i - 1]) { list[i -1] = list[i] - 2; list[i]++; } } } } and lets say we are using a list of [2,3,4]. I know that it will output 2,2,5 but I am unclear how to actually work through it. I understand that the list.length is 3 here, and I understand that the for loop will only run once, but I am very unclear what happens at the list[i - 1] = list[i] - 2; area. Should it be list[2-1] = list[2] - 2? How does the two being outside the bracket effect it differently? Much thanks.

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  • How can I check if an order with a given increment id already exists in magento?

    - by Thomas Vander Stichele
    I am new to Magento. What's the proper way to check if an order with a given increment id already exists ? The obvious way: $order = Mage::getModel('sales/order')->loadByIncrementId($reservedOrderId); if ($order) { Mage::log('already have order with id ' . $reservedOrderId); return $order; } does not work, because I get a new and empty model instance back. What's the correct way in magento to see if I have no such model for that id ?

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  • Rearrange items in ListBox

    - by superexsl
    Hey, I have a ListBox with a number of ListBoxItem objects. What is the best way to allow users to rearrange the items by dragging and dropping? Do I have to use StackPanels instead? Thanks for any suggestions

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  • GROUP BY a date, with ordering by date.

    - by standard
    Take this simple query: SELECT DATE_FORMAT(someDate, '%y-%m-%d') as formattedDay FROM someTable GROUP BY formatterDay This will select rows from a table with only 1 row per date. How do I ensure that the row selected per date is the earliest for that date, without doing an ordered subquery in the FROM? Cheers

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  • second sorting with php usort

    - by bluedaniel
    So Ive got a pretty big array of data and need to sort them by two criteria. There is variable $data['important'] and $data['basic']. They are simple numbers and I am using uasort to sort $data firstly by important and then by basic. So Important | Basic 10 | 8 9 | 9 9 | 7 7 | 9 The usort function is a simple public function sort_by_important($a, $b) { if ($a[important] > $b[important]) { return -1; } elseif ($b[important] > $a[important]) { return 1; } else { return 0; } } How can I re-sort the array to the second variable and keep the Important ordering? Thanks everyone. EDIT How about adding a third sorting option after this even? So Important Basic Less

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  • MySQL: Is it possible to return a "mixed" dataset?

    - by Tom
    Hi, I'm wondering if there's some clever way in MySQL to return a "mixed/balanced" dataset according to a specific criterion? To illustrate, let's say that there are potential results in a table that can be of Type 1 or Type 2 (i.e. a column has a value 1 or 2 for each record). Is there a clever query that would be able to directly return results alternating between 1 and 2 in sequence: 1st record is of type 1, 2nd record is of type 2, 3rd record is of type 1, 4th record is of type 2, etc... Apologies if the question is silly, just looking for some options. Of course, I could return any data and do this in PHP, but it does add some code. Thanks.

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  • SQL to have one specific record at the top, all others below

    - by superdario
    Hey all, I am trying to put together a query that will display one specific record (found by the record's primary ID) at the top, and display all other records below it, sorted by date (I have "date_added" as one of the fields in the table, in addition to primary ID). I could do this with a UNION (first select would locate the record I want, and the other select would display all other records), but I'm wondering if is there perhaps a better way? I'm using Oracle, by the way.

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  • What is the difference between type.__getattribute__ and object.__getattribute__?

    - by Neil G
    Given: In [37]: class A: ....: f = 1 ....: In [38]: class B(A): ....: pass ....: In [39]: getattr(B, 'f') Out[39]: 1 Okay, that either calls super or crawls the mro? In [40]: getattr(A, 'f') Out[40]: 1 This is expected. In [41]: object.__getattribute__(A, 'f') Out[41]: 1 In [42]: object.__getattribute__(B, 'f') --------------------------------------------------------------------------- AttributeError Traceback (most recent call last) <ipython-input-42-de76df798d1d> in <module>() ----> 1 object.__getattribute__(B, 'f') AttributeError: 'type' object has no attribute 'f' What is getattribute not doing that getattr does? In [43]: type.__getattribute__(B, 'f') Out[43]: 1 What?! type.__getattribute__ calls super but object's version doesn't? In [44]: type.__getattribute__(A, 'f') Out[44]: 1

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  • Limiting the number of queries returns in SQL Server 2008

    - by Jose Sotero Villegas III
    This is my query SELECT Fullname, rank, id_no, TIN, birthdate, hair, eyes, Blood, height, weight, marks, name, address FROM [******_DOMAIN\****_*****].*******view Problem is, source table has too many duplicates, how do I my limit query to the latest row on the database? I'm using SQL Server 2008. Thanks In advance My next problem is that the view shows me a birthdate string format of yyyymmdd, I need to change it to mm/dd/yyyy can please provide me a function? using the same string above?

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  • Ordering the results of a Hibernate Criteria query by using information of the child entities of the

    - by pkainulainen
    I have got two entities Person and Book. Only one instance of a specific book is stored to the system (When a book is added, application checks if that book is already found before adding a new row to the database). Relevant source code of the entities is can be found below: @Entity @Table(name="persons") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Person extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @ManyToMany(targetEntity=Book.class) @JoinTable(name="persons_books", joinColumns = @JoinColumn( name="person_id"), inverseJoinColumns = @JoinColumn( name="book_id")) private List<Book> ownedBooks = new ArrayList<Book>(); } @Entity @Table(name="books") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Book extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @Column(name="name") private String name = null; } My problem is that I want to find persons, which are owning some of the books owned by a specific persons. The returned list of persons should be ordered by using following logic: The person owning most of the same books should be at the first of the list, second person of the the list does not own as many books as the first person, but more than the third person. The code of the method performing this query is added below: @Override public List<Person> searchPersonsWithSimilarBooks(Long[] bookIds) { Criteria similarPersonCriteria = this.getSession().createCriteria(Person.class); similarPersonCriteria.add(Restrictions.in("ownedBooks.id", bookIds)); //How to set the ordering? similarPersonCriteria.addOrder(null); return similarPersonCriteria.list(); } My question is that can this be done by using Hibernate? And if so, how it can be done? I know I could implement a Comparator, but I would prefer using Hibernate to solve this problem.

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  • @OrderBy: Sorting references

    - by Sven Moschel
    We have the following entity structure: @Entity public class SecurityRole { private List<Account> accounts; // ManyToMany } @Entity public class Account { private Employee owner; // OneToOne } @Entity public class Employee { private String lastName; } A security role can have many accounts. A account always has an employee. On the GUI we show the security roles in an mastertable. In the detail table we show the accounts of the role. To display the employee information we show "account.getOwner().getLastName()"; How can we use the @OrderBy annotation with this model? Is this possible? The problem is that the Account entity has no employee information that we can sort.

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  • Sort MySQL result set using comparison between 2 columns of same value type

    - by Kyobul
    Hello, I have a table containing last_updated_1 and last_updated_2 columns, used respectively for text and images update time on a post. I wish I could get a result set of 10 rows based on all time last updated records contained in the 2 columns, ex. row 1 = last_updated_1 record, row 2 = last_updated_2 record, row 3 = last_updated_1 record, etc. How could I compare inside a MySQL query the both columns values, to get unique & mixed result set ? Thank you in advance for your help

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  • Identify words with ascending characters from text file

    - by user2914000
    I am having a fair amount of trouble trying to write a program that counts the amount of ascending words (words in which each character is larger than the previous character) in a text file. I have tried a few different methods to solve this but cannot seem to get it working. If anyone could help me revise the code to work properly it would be appreciated. The code will print about 5 of the words from the list of nearly 20000, but none considered are ascending (the file does have many ascending words) and it sometimes prints the same word twice. I am printing theWord to the console simply to see if the code works. import java.util.Scanner; import java.io.*; public class { public static void main (String [] args) throws FileNotFoundException{ String theWord; Scanner inputFile = new Scanner(new File("file.txt")); boolean ascending = true; int i = 1; while(inputFile.hasNextLine()){ theWord = inputFile.nextLine(); if(theWord.length() >= 2){ while(i < theWord.length() - 1){ if(theWord.charAt(i) <= theWord.charAt(i + 1)){ ascending = true; System.out.println("+ " + theWord); totalNum = totalNum + 1; } else{ ascending = false; System.out.println("= " + theWord); } i++; } } }

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  • How does the Keyword Order in the domain name effects SEO?

    - by Sushil
    From the Google keyword research tool, I see "chuck norris jokes" has global 246,000 searches. And again searching "jokes chuck norris" has the same search result. But as see, order of keyword in search terms has, "hello how are you" and "how are you hello" has clearly different results. Now instead of search term (assuming "chuck norris jokes"), I was wondering, if I had to register chucknorrisjokes.com and jokeschucknorris.com, would it effect the ranking on the search result? Or would it be the same? As we see here, both the domains has the same keywords, just in different order. How would that effect? I hope what I am trying to say is clear.

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  • What is the most effective order to learn SQL Server, LINQ, and Entity Framework?

    - by user1525474
    I am trying to get some advice on what order I should learn about SQL Server, LINQ, and Entity Framework to be able to better work with ASP.NET Webforms and MVC. From what I've been able to learn so far, many recommend learning LINQ or Entity Framework before learning SQL Server. It also appears that many companies are looking for people with knowledge in LINQ-to-SQL and Entity Framework without mentioning SQL Server. However, my understanding is that LINQ-to-SQL and Entity Framework translate code into SQL Server queries, making this a poor approach. Is there a correct or best order in which to learn these technologies?

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  • Saving child collections with NHibernate

    - by Ben
    Hi, I am in the process or learning NHibernate so bare with me. I have an Order class and a Transaction class. Order has a one to many association with transaction. The transaction table in my database has a not null constraint on the OrderId foreign key. Order class: public class Order { public virtual Guid Id { get; set; } public virtual DateTime CreatedOn { get; set; } public virtual decimal Total { get; set; } public virtual ICollection<Transaction> Transactions { get; set; } public Order() { Transactions = new HashSet<Transaction>(); } } Order Mapping: <class name="Order" table="Orders"> <cache usage="read-write"/> <id name="Id"> <generator class="guid"/> </id> <property name="CreatedOn" type="datetime"/> <property name="Total" type="decimal"/> <set name="Transactions" table="Transactions" lazy="false" inverse="true"> <key column="OrderId"/> <one-to-many class="Transaction"/> </set> Transaction Class: public class Transaction { public virtual Guid Id { get; set; } public virtual DateTime ExecutedOn { get; set; } public virtual bool Success { get; set; } public virtual Order Order { get; set; } } Transaction Mapping: <class name="Transaction" table="Transactions"> <cache usage="read-write"/> <id name="Id" column="Id" type="Guid"> <generator class="guid"/> </id> <property name="ExecutedOn" type="datetime"/> <property name="Success" type="bool"/> <many-to-one name="Order" class="Order" column="OrderId" not-null="true"/> Really I don't want a bidirectional association. There is no need for my transaction objects to reference their order object directly (I just need to access the transactions of an order). However, I had to add this so that Order.Transactions is persisted to the database: Repository: public void Update(Order entity) { using (ISession session = NHibernateHelper.OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { session.Update(entity); foreach (var tx in entity.Transactions) { tx.Order = entity; session.SaveOrUpdate(tx); } transaction.Commit(); } } } My problem is that this will then issue an update for every transaction on the order collection (regardless of whether it has changed or not). What I was trying to get around was having to explicitly save the transaction before saving the order and instead just add the transactions to the order and then save the order: public void Can_add_transaction_to_existing_order() { var orderRepo = new OrderRepository(); var order = orderRepo.GetById(new Guid("aa3b5d04-c5c8-4ad9-9b3e-9ce73e488a9f")); Transaction tx = new Transaction(); tx.ExecutedOn = DateTime.Now; tx.Success = true; order.Transactions.Add(tx); orderRepo.Update(order); } Although I have found quite a few articles covering the set up of a one-to-many association, most of these discuss retrieving of data and not persisting back. Many thanks, Ben

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  • SQL SERVER – Puzzle – Statistics are not Updated but are Created Once

    - by pinaldave
    After having excellent response to my quiz – Why SELECT * throws an error but SELECT COUNT(*) does not?I have decided to ask another puzzling question to all of you. I am running this test on SQL Server 2008 R2. Here is the quick scenario about my setup. Create Table Insert 1000 Records Check the Statistics Now insert 10 times more 10,000 indexes Check the Statistics – it will be NOT updated Note: Auto Update Statistics and Auto Create Statistics for database is TRUE Expected Result – Statistics should be updated – SQL SERVER – When are Statistics Updated – What triggers Statistics to Update Now the question is why the statistics are not updated? The common answer is – we can update the statistics ourselves using UPDATE STATISTICS TableName WITH FULLSCAN, ALL However, the solution I am looking is where statistics should be updated automatically based on algorithm mentioned here. Now the solution is to ____________________. Vinod Kumar is not allowed to take participate over here as he is the one who has helped me to build this puzzle. I will publish the solution on next week. Please leave a comment and if your comment consist valid answer, I will publish with due credit. Here is the script to reproduce the scenario which I mentioned. -- Execution Plans Difference -- Create Sample Database CREATE DATABASE SampleDB GO USE SampleDB GO -- Create Table CREATE TABLE ExecTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Insert One Thousand Records -- INSERT 1 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 1000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Display statistics of the table - none listed sp_helpstats N'ExecTable', 'ALL' GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here -- NOTE: Replace your _WA_Sys with stats from above query DBCC SHOW_STATISTICS('ExecTable', _WA_Sys_00000004_7D78A4E7); GO -------------------------------------------------------------- -- Round 2 -- Insert Ten Thousand Records -- INSERT 2 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 10000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here -- NOTE: Replace your _WA_Sys with stats from above query DBCC SHOW_STATISTICS('ExecTable', _WA_Sys_00000004_7D78A4E7); GO -- You will notice that Statistics are still updated with 1000 rows -- Clean up Database DROP TABLE ExecTable GO USE MASTER GO ALTER DATABASE SampleDB SET SINGLE_USER WITH ROLLBACK IMMEDIATE; GO DROP DATABASE SampleDB GO Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Index, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Statistics, Statistics

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  • Spring MVC managing multiple views with single controller

    - by Sudhir
    I am trying to implement order management module. There are different order types (approximately about 15). Each order has a seperate view. But the actions performed on UI are same irrespective of order type. Below is the structure of my DTO abstract class Order abstract class SecurityOrder extends Order abstract class TermDepositOrder extends Order ..... ..... ..... I am trying to implement a single controller capable of managing all views. Something similar to the one below: @Controller public class OrderController<F extends Order> { public F validate(F order) { } public F insert(F order) { } } I am not sure how spring mvc would be able to map request parameters properly to the order instance as it doesn't know which order instance to populate. Is it possible to achieve this with single controller or should I go with a controller for each order type and duplicate same code across all controllers?

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  • Is my DFD accurate?

    - by Dummy Derp
    This is my first ever DFD that I made after my fair share of learning but I have no way of verifying whether it is correct or not. Although I have taken utmost care to make sure it is right, I may be wrong. Here is the scenario: Bebop Records is a mail-order company that distributes CDs and tapes at discount prices to record club members. When an order processing clerk receives an order form, he or she verifies that the sender is a club member by checking the Member file. If the sender is not a member, the clerk returns the order along with a membership application form. If the customer is a member, the clerk verifies the order item data by checking the Item file. Then the clerk enters the order data and saves it to the Daily Order file. The clerk also prints an invoice and shipping list for each order, which are forwarded to Order Fulfilment. And here is my diagram:

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  • Please suggest me the ( Interaction model of view model) MVVM design in the simple scenario discusse

    - by Jack
    Data Layer I have an Order class as an entity. This Order entity is my model object. Order can be different types, let it be A B C D Also Order class may have common properties like Name, Time of creation, etc. Also based on the order type there are different fields that are not common. View Layer The view contains the following Main Menu ListView The Main Menu contains the drop down menu button which is used to create the order based on the type selected from the drop down. The drop down contains the Order types ( A ,B , C and D). There are different user control based on the order type. Like for example if user chooses to create an order of type A then different view with different inputs field is popped up. Hence, there are four user control for each order type. If user selects A option from the drop down then Order of type A is created and vica versa. Now below is the List View that contains the List of orders so far created by the user. To Edit any particular order user may double click the list view row. Based on the order type clicked by the user in the listview, the view of that order type opens in edit mode. For example if user selects an order type A from the list view then view for order type A open in edit mode. Please suggest me interaction model for view model's in the scenario discussed above. Please excume me if the query is very basic, since I am new new to MVVM and WPF ,

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