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  • nested list comprehension using intermediate result

    - by KentH
    I am trying to grok the output of a function which doesn't have the courtesy of setting a result code. I can tell it failed by the "error:" string which is mixed into the stderr stream, often in the middle of a different conversion status message. I have the following list comprehension which works, but scans for the "error:" string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can't figure out how to use a single scan. Here's the working code: errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e] The obvious (and wrong) way to simplify is to save the "find" result errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()] However, I get "UnboundLocalError: local variable 'e' referenced before assignment". Blindly reversing the 'for's in the comprehension also fails. How is this done? THanks. Kent

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  • How to check if a file is a textfile?

    - by daniels
    I have a folder full of files and i want to search some string inside them. The issue is that some files may be zip,exe,ogg,etc. Can i check somehow what kind of file is it so i only open and search through txt, php, etc files. I can't rely on the file extension.

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  • twitter api post rate limit

    - by Xavier
    Does anyone know Twitter's rate limit on posting? Looking at their web page they claimed to not have one but I get an exception thrown if my program posts too fast... Any help is appreciated.

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  • Pagination of Date-Based Generic Views in Django

    - by Apreche
    I have a pretty simple question. I want to make some date-based generic views on a Django site, but I also want to paginate them. According to the documentation the object_list view has page and paginate_by arguments, but the archive_month view does not. What's the "right" way to do it?

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  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

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  • Common elements comparison between 2 lists.

    - by Daniel
    def common_elements(list1, list2): """ Return a list containing the elements which are in both list1 and list2 >>> common_elements([1,2,3,4,5,6], [3,5,7,9]) [3, 5] >>> common_elements(['this','this','n','that'],['this','not','that','that']) ['this', 'that'] """ for element in list1: if element in list2: return list(element) Got that so far, but can't seem to get it to work! Thanks

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  • Filtering SQLAlchemy query on attribute_mapped_collection field of relationship

    - by bsa
    I have two classes, Tag and Hardware, defined with a simple parent-child relationship (see the full definition at the end). Now I want to filter a query on Tag using the version field in Hardware through an attribute_mapped_collection, eg: def get_tags(order_code=None, hardware_filters=None): session = Session() query = session.query(Tag) if order_code: query = query.filter(Tag.order_code == order_code) if hardware_filters: for k, v in hardware_filters.iteritems(): query = query.filter(getattr(Tag.hardware, k).version == v) return query.all() But I get: AttributeError: Neither 'InstrumentedAttribute' object nor 'Comparator' object associated with Tag.hardware has an attribute 'baseband The same thing happens if I strip it back by hard-coding the attribute, eg: query.filter(Tag.hardware.baseband.version == v) I can do it this way: query = query.filter(Tag.hardware.any(artefact=k, version=v)) But why can't I filter directly through the attribute? Class definitions class Tag(Base): __tablename__ = 'tag' tag_id = Column(Integer, primary_key=True) order_code = Column(String, nullable=False) version = Column(String, nullable=False) status = Column(String, nullable=False) comments = Column(String) hardware = relationship( "Hardware", backref="tag", collection_class=attribute_mapped_collection('artefact'), ) __table_args__ = ( UniqueConstraint('order_code', 'version'), ) class Hardware(Base): __tablename__ = 'hardware' hardware_id = Column(Integer, primary_key=True) tag_id = Column(String, ForeignKey('tag.tag_id')) product_id = Column(String, nullable=True) artefact = Column(String, nullable=False) version = Column(String, nullable=False)

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  • How do I parse youtube xml for a specific entry?

    - by sharataka
    I am trying to return the duration of the video but am having trouble. #YOUTUBE FEED #download the file: file = urllib2.urlopen('http://gdata.youtube.com/feeds/api/videos/2s0vk2wEMtA') #convert to string: data = file.read() #close file because we dont need it anymore: file.close() #entire feed root = etree.fromstring(data) for entry in root: for item in entry: print item When I print item, I see as the last element: Element '{http://gdata.youtube.com/schemas/2007}duration' at 0x10c4fb7d0 But I don't know how to get the value from this. Any advice?

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  • element-wise lookup on one ndarray to another ndarray of different shapes

    - by fahhean
    Hi, I am new to numpy. Am wonder is there a way to do lookup of two ndarray of different shapes? for example, i have 2 ndarrays as below: X = array([[0, 3, 6], [3, 3, 3], [6, 0, 3]]) Y = array([[0, 100], [3, 500], [6, 800]]) and would like to lookup each element of X in Y, then be able to return the second column of Y: Z = array([[100, 500, 800], [500, 500, 500], [800, 100, 500]]) thanks, fahhean

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  • how to trigger a script located on a machine in one domain from a machine on another domain

    - by user326814
    Hi, I am basically from QA. What we testers do each day is 1. Open a web browser. Type in http://11.12.13.27.8080/cruisecontrol (since we are in a particular network, only we can access this) 2. Check if the latest nightly build has been successful. If it is successful, deploy it on a test environment by clicking on 'Deploy this build' link. This deploying takes around 1-1.5 hours. During this time we cannot use our machines to work on anything else. Only after this deploying can we begin to test. Now, i wanted to know if its possible to do the below. When at home in the morning, i use something which will trigger a script (which will be on my machine at workplace). This script will inturn automatically deploy the build. I already have such a similar script. What i want to know is how is it possible to trigger this script from my home machine? Is it even possible? For e.g the external trigger will say "Deploy xxx branch on yyy test environment". So the script on my workplace machine will be invoked and it will automatically deploy it before i actually come to my desk. Please help. I am from QA and have no idea about all this.

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  • How can I retrieve all the returned variables from a function?

    - by user1447941
    import random def some_function(): example = random.randint(0, 1) if example == 1: other_example = 2 else: return False return example, other_example With this example, there is a chance that either one or two variables will be returned. Usually, for one variable I'd use var = some_function() while for two, var, var2 = some_function(). How can I tell how many variables are being returned by the function?

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  • Word filter that groups words?

    - by Legend
    Is there any library that achieves the following: Convert Microsoft Windows 98 Microsoft Windows XP Windows 7 Windows Ultimate Desktop Windows to Windows 4 The complicated part here is to recognize that "Desktop Windows" is an anomaly here and not count it. If nothing is added before the word "Windows", perhaps it can be counted but if there is something else and the suffix does not match any popular suffix, it can still be counted. Maybe I am a little vague here but perhaps someone could have an idea about what I am talking about here. Any suggestions?

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  • sending the data from form to db in django

    - by BharatKrishna
    I have a form in which I can input text through text boxes. How do I make these data go into the db on clicking submit. this is the code of the form in the template. <form method="post" action="app/save_page"> <p> Title:<input type="text" name="title"/> </p> <p> Name:<input type="text" name="name"/> </p> <p> Phone:<input type="text" name="phone"/> </p> <p> Email:<input type="text" name="email"/> </p> <p> <textarea name="description" rows=20 cols=60> </textarea><br> </p> <input type="submit" value="Submit"/> </form> I have a function in the views.py for saving the data in the page. But I dont know how to impliment it properly: def save_page(request): title = request.POST["title"] name = request.POST["name"] phone = request.POST["phone"] email = request.POST["email"] description = request.POST["description"] Now how do I send these into the db? And what do I put in views.py so that those data goes into the db? so how do I open a database connection and put those into the db and save it? should I do something like : connection=sqlite3.connect('app.db') cursor= connection.cursor() ..... ..... connection.commit() connection.close() Thank you.

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  • Choosing randomly all the elements in the the list just once

    - by Dalek
    How is it possible to randomly choose a number from a list with n elements, n time without picking the same element of the list twice. I wrote a code to choose the sequence number of the elements in the list but it is slow: >>>redshift=np.array([0.92,0.17,0.51,1.33,....,0.41,0.82]) >>>redshift.shape (1225,) exclude=[] k=0 ng=1225 while (k < ng): flag1=0 sq=random.randint(0, ng) while (flag1<1): if sq in exclude: flag1=1 sq=random.randint(0, ng) else: print sq exclude.append(sq) flag1=0 z=redshift[sq] k+=1 It doesn't choose all the sequence number of elements in the list.

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  • how to get all 'username' from my model 'MyUser' on google-app-engine ..

    - by zjm1126
    my model is : class MyUser(db.Model): user = db.UserProperty() password = db.StringProperty(default=UNUSABLE_PASSWORD) email = db.StringProperty() nickname = db.StringProperty(indexed=False) and my method which want to get all username is : s=[] a=MyUser.all().fetch(10000) for i in a: s.append(i.username) and the error is : AttributeError: 'MyUser' object has no attribute 'username' so how can i get all 'username', which is the simplest way . thanks

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  • Django database - how to add this column in raw SQL.

    - by alex
    Suppose I have my models set up already. class books(models.Model): title = models.CharField... ISBN = models.Integer... What if I want to add this column to my table? user = models.ForeignKey(User, unique=True) How would I write the raw SQL in my database so that this column works?

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  • sql select from a large number of IDs

    - by Claudiu
    I have a table, Foo. I run a query on Foo to get the ids from a subset of Foo. I then want to run a more complicated set of queries, but only on those IDs. Is there an efficient way to do this? The best I can think of is creating a query such as: SELECT ... --complicated stuff WHERE ... --more stuff AND id IN (1, 2, 3, 9, 413, 4324, ..., 939393) That is, I construct a huge "IN" clause. Is this efficient? Is there a more efficient way of doing this, or is the only way to JOIN with the inital query that gets the IDs? If it helps, I'm using SQLObject to connect to a PostgreSQL database, and I have access to the cursor that executed the query to get all the IDs.

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  • Own params to PeriodicTask run() method in Celery

    - by Alex Isayko
    Hello to all! I am writing a small Django application and I should be able to create for each model object its periodical task which will be executed with a certain interval. I'm use for this a Celery application, but i can't understand one thing: class ProcessQueryTask(PeriodicTask): run_every = timedelta(minutes=1) def run(self, query_task_pk, **kwargs): logging.info('Process celery task for QueryTask %d' % query_task_pk) task = QueryTask.objects.get(pk=query_task_pk) task.exec_task() return True Then i'm do following: >>> from tasks.tasks import ProcessQueryTask >>> result1 = ProcessQueryTask.delay(query_task_pk=1) >>> result2 = ProcessQueryTask.delay(query_task_pk=2) First call is success, but other periodical calls returning the error - TypeError: run() takes exactly 2 non-keyword arguments (1 given) in celeryd server. So, can i pass own params to PeriodicTask run() ? Thanks!

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  • list in loop, Nonetype errors

    - by user2926755
    Here is my Code def printList(stringlist): empty = [] if stringlist is None: print empty else: print stringlist def add (stringlist, string): string = [] if string is None else string if stringlist is not None: stringlist.insert(0, string) else: stringlist.append(1) it somehow appears "AttributeError: 'NoneType' object has no attribute 'append'" I was originally looking for the code to be run like this: >>> myList = None >>> printList(myList) [] >>> for word in ['laundry','homework','cooking','cleaning']: myList = add(myList, word) printList(myList) [laundry] [homework, laundry] [cooking, homework, laundry] [cleaning, cooking, homework, laundry]

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