Search Results

Search found 13518 results on 541 pages for 'daniel root'.

Page 422/541 | < Previous Page | 418 419 420 421 422 423 424 425 426 427 428 429  | Next Page >

  • having problems using Zend_Db_Table_Abstract::createRow()

    - by Gootik
    Hey, I have built a model that extends Zend_Db_Table_Abstract and I can't figure out why I can't use createRow(); here is my code: class Model_User extends Zend_Db_Table_Abstract { public function createUser() { $row = $this->createRow(); $row->name = 'test'; $row->save(); } } and in a controller I use: $userModel = new Model_User(); $userModel->createUser(); which when run displays an error An error occurred Application error here is my setup in application.ini resources.db.adapter = "pdo_mysql" resources.db.params.host = "localhost" resources.db.params.username = "root" resources.db.params.password = "pass" resources.db.params.dbname = "app_db" resources.db.isDefaultTableAdapter = true I am sure that my user/pass/dbname is correct. I would appreciate it if you point me in the right direction.

    Read the article

  • php/ssh2 script does not display the stdout to $stream

    - by kamal
    The following php script works for simple linux commands, like ps -ef , but when i use ./dstat -t -a , it seems to hang and i dont get the prompt back on my local machine. Kep in mind that all commands are executed over ssh on a remote host: <?php $target = time() . '_' . 'txt'; if($ssh = ssh2_connect('10.1.0.174', 22)) { if(ssh2_auth_password($ssh, 'root', 'kmoon77')) { //$stream = ssh2_exec($ssh, 'whoami'); $sCommand = 'dstat -a'; //$sCommand = 'ps -ef'; $stream = ssh2_exec($ssh, $sCommand); //$stream = ssh2_exec($ssh, 'pwd'); stream_set_blocking($stream, true); $data = ''; while($buffer = fread($stream, 4096)) { $data .= $buffer; } //fclose($stream); echo $data; // user } } ?>

    Read the article

  • C Different answers for a variable when running 'Debug' and 'Start without debug'

    - by Craz
    I keep getting this weird output from my code everytime I use the 'start without degugging' (ctrl-F5) as opposed to normal 'debug' (F5). When I try to find the following value of norm_differnece in debug (pressing F5) mode, it gives me the correct answer for norm_difference normdifference = 1.000000 but in 'start without debugging' (pressing ctrl-f5) the wrong output normdifference = 1456816083547664100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000.000000 The following is a segment of code which is gives the output Note: X[] = is a array of stored DOUBLE values for(i=0;i<n;i++){ sum_difference += (pow((X[i*n]-X[i]),2)); } norm_difference = sqrt(norm_difference); for(i=0;i<n;i++){ sum_norm_1 += pow(X[i],2); } norm_1 = sqrt(norm_1); //Take square root of the sum of squares for the row printf("normdifference = %f \n norm_1 = %f \n",norm_difference,norm_1);

    Read the article

  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

    Read the article

  • X11, how to detect I’m the last window/application on the display

    - by ts
    I have an x11 display with a windowmanager (sadly not a specific one, could be twm, dtwm, mwm, metacity …) , myApp and other applications with windows. I want to close the display if the other applications are closed and myApp is the only one with windows on the display. I do know the windows of myApp, but how do I distinguish between the windows of the windowmanger and of the other applications. I’m currently polling with xwininfo -tree -root -children and comparing this to what I’m expecting, but this only works in a ‘well defined’ environment. It seems that many of the above mentioned windowmanager don’t support EWMH.

    Read the article

  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

    Read the article

  • PHP Localhost Application connect to server database

    - by Cross Vander
    I want to ask about how to connect my localhost application (C:xampp/htdocs/myproject) to database at my server host (www.someweb.somedomain)? Am I possible to do that? If it is, how to connect it at my php config? Right now my config (server.php) is: <?php $host = "my web IP public:3306"; $user = "root"; $pass = ""; $db = "dispatcherDB"; $conn = mysql_connect($host, $user, $pass) or die ("Cant connect to mySQL"); mysql_select_db($db); ?> what I got: Warning: mysql_connect(): No connection could be made because the target machine actively refused it. in C:\xampp\htdocs\XMS\server.php on line 7 So, what must I filled for $host? I'm trying using website IP, it still can't connect. Maybe there's someone here have experience at this problem? Sorry for my bad English

    Read the article

  • How can i get my htaccess to work (subdomains)?

    - by user358994
    I'm sorta a noob at these things but I'm trying to make a simple virtual subdomain with .htaccess. I have wildcard enabled and after lots of digging, this is what I've come up with: rewriteEngine On rewriteCond %{HTTP_HOST} !^$ rewriteCond %{HTTP_HOST} !^(www\.)?khpedia\.com$ [NC] rewriteCond %{HTTP_HOST}<->%{REQUEST_URI} ^(www\.)?([^.]+).*<->/([^/]+) [NC] rewriteCond %2<->%3 !^(.*)<->\1$ [NC] rewriteRule ^(.+) /%2/$1 [L] My directory is setup as -root --wiki ----index.php --test Right now when I travel to wiki.khpedia.com, I get a page not found. When I travel to wiki.khpedia.com/index.php, it travels to wiki.khpedia.com/wiki/index.php. I am somehow also able to access wiki.khpedia.com/test. If it doesnt seem obvious yet, I want to be able to go to wiki.khpedia.com/index.php and see wiki.khpedia.com/wiki/index.php but not in my address bar. Sorry for the text block and thanks for the help.

    Read the article

  • Possible to use Javascript to access the client side's network(knowingly)

    - by Earlz
    I recently found an exploit in my router to basically give me root access. The catch? There is a nonce hidden form value that is randomly generated and must be sent in for it to work that makes it difficult to do "easily" So basically I'm wanting to do something like this in javascript: get http://192.168.1.254/blah use a regex or similar to extract the nonce value put the nonce value into a hidden field in the current page submit the form by POST to http://192.168.1.254/blah complete with the nonce value and other form values I want to send in. Is this at all possible using only HTML and Javascript? I'm open to things like "must save HTML file locally and then open", which I'm thinking is one way around the cross domain policy. But anyway, is this at all possible? I'm hoping for this to be able to run from at least Firefox and Chrome. The audience for this is those with some technical know how.

    Read the article

  • Linux File Permissions & Access Control Query

    - by Jason
    Hi, Lets say I am user: bob & group: users. There is this file: -rw----r-- 1 root users 4 May 8 22:34 testfile First question, why can't bob read the file as it's readable by others? Is it simply that if you are denied by group, then you are auto-blacklisted for others? I always assumed that the final 3 bits too precedence over user/group permission bits, guess I was wrong... Second question, how is this implemented? I suppose it's linked to the first query, but how does this work in relation to Access Control, is it related to how ACLs work / are queried? Just trying to understand how these 9 permission bits are actually implemented/used in Linux. Thanks alot.

    Read the article

  • CodeIgniter won't run in a subdirectory

    - by Tim Piele
    I have a CodeIgniter install running in our root web directory that I copied into a subdirectory called /dev... I edited the config/config.php file to reflect the change so it is now like this: $config['base_url'] = 'http://mysite.com/dev'; $config['sbase_url'] = 'https://mysite.com/dev'; $config['default_email'] = '[email protected]'; $config['site_url'] = 'http://mysite.com/dev'; This is my .htaccess file: <IfModule mod_rewrite.c> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L] </IfModule> When I hover over any links on the site they are correct, for example the contact us page link reads www.mysite.com/dev/contact but when I click any of the links I get a 404 error... Is there something common I am missing?

    Read the article

  • mysql_close(): supplied argument is not a valid MySQL-Link resource

    - by maxedison
    I'm trying to get the hang of using custom session handlers to store session data in a MySQL database. However, I keep getting the following warning: mysql_close(): supplied argument is not a valid MySQL-Link resource Here's the code I'm using, which I got from here: function _open(){ global $_sess_db; $_sess_db = mysql_connect("localhost", "root", "******"); if ($_sess_db) { return mysql_select_db('style', $_sess_db); } return false; } function _close(){ global $_sess_db; return mysql_close($_sess_db); //error happens here } The full text of the error message ultimately points to the final "return mysql_close($_sess_db);" line. I can confirm that the mysql_connect info does in fact work, and I do have the rest of the session handler functions defined as well. And in case it helps, I get these errors immediately upon page load, without actually calling any of the session handler functions, and without having any current sessions open.

    Read the article

  • Implementing an iterator over binary tree using C++ 11

    - by user1459339
    I would like to create an iterator over the binary tree so as to be able to use range-based for loop. I understand I ought to implement the begin() and end() function first. Begin should probably point to the root. According to the specification, however, the end() functions returns "the element following the last valid element". Which element (node) is that? Would it not be illegal to point to some "invalid" place? The other thing is the operator++. What is the best way to return "next" element in tree? I just need some advice to begin with this programming.

    Read the article

  • Preventing SQL injecting in a database class

    - by Josh
    I'm building a database class and thought it'd be a good idea to incorporate some form of SQL injection prevention (duh!). Here's the method that runs a database query: class DB { var $db_host = 'localhost'; var $db_user = 'root'; var $db_passwd = ''; var $db_name = 'whatever'; function query($sql) { $this->result = mysql_query($sql, $this->link); if(!$this->result) { $this->error(mysql_error()); } else { return $this->result; } } } There's more in the class than that but I'm cutting it down just for this. The problem I'm facing is if I just use mysql_real_escape_string($sql, $this->link); then it escapes the entire query and leads to a SQL syntax error. How can I dynamically find the variables that need to be escaped? I want to avoid using mysql_real_escape_string() in my main code blocks, i'd rather have it in a function. Thanks.

    Read the article

  • Immediately starting a new activity from an activity

    - by HowsItStack
    When I was originally learning about Android a few months ago I swear I read something about a way to immediately launch an activity when starting a task. I am curious about this now because I need to display an intro screen on launch but I don't want the intro screen to be the root activity. Does anyone know if there is something like this and if not what is the best way to handle an intro screen? I tried googling for a few hours to find it but can't for the life of me. Thanks for the help.

    Read the article

  • What statistics app should I use for my website?

    - by Camran
    I have my own server (with root access). I need statistics of users who visit my website etc etc... I have looked at an app called Webalyzer... Is this a good choice? I run apache2 on a Ubuntu 9 system... If you know of any good statistics apps for servers please let me know. And a follow-up question: All statistics are saved in log-files right? So how large would these log-files become then? Possibility to split them would be good, dont know if this is possible with Webalyzer though...

    Read the article

  • Array to string conversion in (cant get it to work)

    - by user2966551
    ok I am trying to pull a a specific row of data that corresponds to the username logged in. on my page I have started my session but for some reason I cant get the code to work.i keep getting a "Array to string conversion in " on the line " WHERE username = '$_SESSION[user]'");" what am I doing wrong? if I set username = a set username it works but I need it to draw from the session id so it will display different values based on whos logged in. <?php $con=mysqli_connect("localhost","root","xxx","xxxx"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $result = mysqli_query($con,"SELECT * FROM users WHERE username = '$_SESSION[user]'"); while($row = mysqli_fetch_array($result)) { echo $row['username'] . " " . $row['att']; echo "<br>"; } ?>

    Read the article

  • RVM 1.9.1 & nokogiri

    - by scaney
    Having trouble installing the nokogiri gem under rvm ruby 1.9.1. gem install nokogiri I'm getting ... /usr/include/libxml2... no libxml2 is missing. try 'port install libxml2' or 'yum install libxml2-devel' *** extconf.rb failed *** but i checked: sudo apt-get install libxml2 and i got: Reading state information... Done libxml2 is already the newest version. is this a root thing perhaps? RVM runs everything in userspace.

    Read the article

  • PHP] How can I connect to MySQL on wamp server?

    - by user294359
    This might be ridiculously easy for you.. but I've been struggling with this for an hour.. :( <?php $connect = mysql_connect("localhost:8080", "root", "mypassword"); echo($connect);?> This is the code that I'm trying to run - you can see that I'm using 8080 as my port number and, of course, I have html codes as well. However, it gives me the following error msgs whenever I try to open the php file. ==================================================================================== Warning: mysql_connect() [function.mysql-connect]: MySQL server has gone away in C:\wamp\www\php_sandbox\index.php on line 2 Warning: mysql_connect() [function.mysql-connect]: Error while reading greeting packet. PID=4932 in C:\wamp\www\php_sandbox\index.php on line 2 Warning: mysql_connect() [function.mysql-connect]: MySQL server has gone away in C:\wamp\www\php_sandbox\index.php on line 2 ===================================================================================== I don't know... what's wrong with this. Is it because of the port number?

    Read the article

  • Default http/admin port in dropwizard project

    - by mithrandir
    I have a dropwizard project and I have maintained a config.yml file at the ROOT of the project (basically at the same level as pom.xml). Here I have specified the HTTP port to be used as follows: http: port:9090 adminPort:9091 I have the following code in my TestService.java file public class TestService extends Service<TestConfiguration> { @Override public void initialize(Bootstrap<TestConfiguration> bootstrap) { bootstrap.setName("test"); } @Override public void run(TestConfiguration config, Environment env) throws Exception { // initialize some resources here.. } public static void main(String[] args) throws Exception { new TestService().run(new String[] { "server" }); } } I expect the config.yml file to be used to determine the HTTP port. However the app always seems to start with the default ports 8080 and 8081. Also note that I am running this from eclipse. Any insights as to what am I doing wrong here ?

    Read the article

  • phpMySql connection

    - by Eiriko Pedroza
    PL = VB.net Issue: format of the initialization string does not conform to specification starting at index 17 connection string: objconn.ConnectionString = ("server=" & txtServer.Text & ";" _ & "user id=" & "'" & txtUserId.Text & ";" _ & "password=" & txtPassword.Text & ";" _ & "database=try") Try objconn.Open() MsgBox("Connected") objconn.Close() Catch ex As Exception MsgBox(ex.ToString) End Try -objconn is declared as new mysqlconnection every time I run the application and try to login, i keep on receiving this error message, I already double checked my line of connection string. im using 'localhost' as server and 'root' as username, password is blank. thank you in advance for your response

    Read the article

  • php, OOP dosent allow me to fetch multilingual content?

    - by user3138823
    i have written bellow class for my database connection. class dbConnection { protected $dbLink; public $db_host = "127.0.0.1"; public $db_user = "root"; public $db_pass = ""; public $db_name = "answer"; function connect() { try { $dbLink = new PDO('mysql:host='.$this->db_host.';dbname='.$this->db_name, $this->db_user, $this->db_pass); return $dbLink; } catch (PDOException $e) { return $e->getMessage(); } } } but in my databse i have multilingual content ( collection type = utf8_general_ci ). when i try to fetch data it returns ???? instead of real data. please can any one tell me how can i improve my class to work with multilingual contents. Thanks.

    Read the article

  • Error 1045 MySQL during setup

    - by user1364513
    Could anyone explaine me the error 1045 during MySQL setup I ll be preciated. I'm getting this error after reinstalling. I 'm going to install on windows 7. On the last stage of installation i.e apply security settings I'm getting the following message:"The security settings could not be applied. Error Number 1045. Access denied for user 'root' @ 'loaclhost'(usinf password: NO)". I know another way how to fix it that is reinstalling of operating system, but I can't do it please help how can I solve it?. I'll be preciated. Thanks!

    Read the article

  • UIAlertView popups lock up keyboard actions

    - by TurbZ
    I have a strange behavior where if a UIAlert fires (like the one below) all subsequent keyboard or press behaviors are disabled / non responsive. Scrolling the screen still works but no action is fired from any button or keyboard presses. [[[[UIAlertView alloc] initWithTitle:@"Invalid Address" message:@"The email address you entered isn't valid. Please check and try again." delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil] autorelease] show]; Anyone experienced this behavior before and can shed some light? Or maybe guide me in the right direction to debug it further to get to the root cause? Thank you heaps!

    Read the article

  • Clone submodule into directory

    - by andypaxo
    I'm having an issue with creating a submodule in my project. If I create the submodule directly in the repository root, everything works fine. If the submodule is any deeper, the repository does not get cloned. For example, this works as expected: git submodule add git://someproject.com/.git someproject However, when I run the following command, the project is added to .gitmodules and an empty repository is created, but no code is pulled down (even after a git submodule update --init). The command does not produce any output. git submodule add git://someproject.com/.git lib/someproject

    Read the article

< Previous Page | 418 419 420 421 422 423 424 425 426 427 428 429  | Next Page >