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  • Dynamic URL to Stay the Same on all Pages

    - by JCBiggar
    so when my url looks like this: http://mywebsitehere.com/?kw=1 I am using this code below to do stuff with it: <?php if( isset($_GET['kw'] )){ //my div here } ?> It works great, and I am getting exactly what I want on the page. However, any link I click on that page will change the url structure and remove the ?kw=1 . Is there anyway to add the ?kw=1 to every link for that session? I have no clue how to do this? Any ideas or answers would be great! Thanks! Let me know if I need to give more to my question.

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  • c++ - FIFO implementation

    - by Narek
    While implementing a FIFO I have used the following structure: struct Node { T info_; Node* link_; Node(T info, Node* link=0): info_(info), link_(link) {} }; I think this a well known trick for lots of STL containers (for example for List). Is this a good practice? What it means for compiler when you say that Node has a member with a type of it's pointer? Is this a kind of infinite loop? And finally, if this is a bad practice, how I could implement a better FIFO.

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  • Calling Javascript after linking to another page

    - by kratos2488
    I am doing an integration with a support system (Helpstream) and I am currently working on doing some in-app context sensitive help. I have put in a link that will send the user to a section of Helpstream that will allow them to ask a question. Problem is, there are buttons on the page that call Javascript that will bring up a lightbox where the user fills out a form to submit a question. What I need to do is have that form come up after the user goes through the link, so essentially run the Javascript once the user hits the page. The call that I have to implement is NewTopic.CreateNew({type:"Question"}) Any tips would be greatly appreciated. Thanks in advance.

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  • open window with dynamic content

    - by julio
    Is it possible to open a window from PHP that has predefined content? It's obvious how you can open a window from a javascript link that frames an existing page, or just do a target=_blank from a regular a tag that references an existing page. But I am generating a bit of content, and want that content to be opened in a new link (or streamed to the viewer)-- something like (clearly psuedo code!): $content = "Hello World. <br />Nice to meet you!"; <a href="#" target="_blank" content=$content>Open up!</a> Is this possible? Thanks!

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  • How to animate/show a hidden div?

    - by Ricky Cortes
    So I'm trying to show a div with a toggle transition when a link is clicked. My code: $("nav ul li#about a").click(function (e) { $("div#about").slideToggle(200); e.preventDefault(); }); It works great, but I want this effect here: http://ricostacruz.com/jquery.transit/ Scroll down and find "TRANSITIONS FOR OTHER PROPERTIES". Do you see that scale effect (first demo box)? THAT is what I want instead of the slideToggle. So I want this similar effect to TOGGLE... transition IN and OUT when link is clicked. I hope you guys can help me :)

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  • php/mySQL error: mysql_num_rows(): supplied argument is not a valid MySQL result

    - by Michael Robinson
    I'm trying to INSERT INTO a mySQL database and I'm getting this error on: if (mysql_num_rows($login) == 1){ Here is the php, The php does add the user to the database. I can't figure it out. <? session_start(); require("config.php"); $u = $_GET['username']; $pw = $_GET['password']; $pwh = $_GET['passwordhint']; $em = $_GET['email']; $zc = $_GET['zipcode']; $check = "INSERT INTO family (loginName, email, password, passwordhint, location) VALUES ('$u', '$pw', '$pwh', '$em', '$zc')"; $login = mysql_query($check, $link) or die(mysql_error()); if (mysql_num_rows($login) == 1) { $row = mysql_fetch_assoc($login); echo 'Yes';exit; } else { echo 'No';exit; } mysql_close($link); ?> Thanks,

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  • file_get_contents not displaying any data

    - by Lance
    I'm doing $info = file_get_contents('http://USERNAME:[email protected]/v2/sales?client_key=CLIENT_KEY'); $info returns nothing. However, when I put the URL into my browser, JSON appears. I tried using cURL without any luck. $data = array('client_key' => 'CLIENT_KEY'); $link = "http://api.appfigures.com/v2/sales"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $link); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_POST, count($data)); curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data)); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); $jsonData = curl_exec($ch); curl_close($ch); print_r($jsonData); Thanks

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  • FireFox Toolbar Open Window in new Tab

    - by Mark
    Hi all, I have a Toolbarbutton <toolbarbutton context="TabMenue" id="esbTb_rss_reader" label="News" type="menu"> with a Context menue which comes up when the button is right clickt <menupopup id="TabMenue" > <menuitem label="New Tab" oncommand="esbTb_loadURLNewTab()"/> </menupopup> so this function should open the new window in a new tab function esbTb_loadURLNewTab() { window.open(ClickUrl,'name'); } I don't get it working that the new Window is showing up in a new tab it always opens a new firefox window. I tried also like described in this article to set the browser.link.open_newwindow and browser.link.open_newwindow.restriction preferences but that doesn't bringt anything. And I tried it with all Target attributes which came in my mind. So I'm grateful for any hints, tips what ever this is driving me crazy...

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  • Python Continue Loop

    - by Rob B.
    I am using the following code from this tutorial (http://jeriwieringa.com/blog/2012/11/04/beautiful-soup-tutorial-part-1/). from bs4 import BeautifulSoup soup = BeautifulSoup (open("43rd-congress.html")) final_link = soup.p.a final_link.decompose() trs = soup.find_all('tr') for tr in trs: for link in tr.find_all('a'): fulllink = link.get ('href') print fulllink #print in terminal to verify results tds = tr.find_all("td") try: #we are using "try" because the table is not well formatted. This allows the program to continue after encountering an error. names = str(tds[0].get_text()) # This structure isolate the item by its column in the table and converts it into a string. years = str(tds[1].get_text()) positions = str(tds[2].get_text()) parties = str(tds[3].get_text()) states = str(tds[4].get_text()) congress = tds[5].get_text() except: print "bad tr string" continue #This tells the computer to move on to the next item after it encounters an error print names, years, positions, parties, states, congress However, I get an error saying that 'continue' is not properly in the loop on line 27. I am using notepad++ and windows powershell. How do I make this code work?

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  • Running a packaged exe in the same folder as the installed firefox extension

    - by mustafabar
    I have read this thread, and some other How to run a local exe in my firefox extension The problem is, at deployment and using firefox 4.0.1, if I install the .xpi extension, the xpi is put inside the \Profiles...\extensions as **.xpi, which is a compressed format All the solutions assume that the the extension is put in a folder, thus they are accessing the folder as is, which I cannot do for example this guy says //**** get profile folder path **** var dsprops = Components.classes['@mozilla.org/file/directory_service;1'] .getService(Components.interfaces.nsIProperties); var ProfilePath = dsprops.get("ProfD", Components.interfaces.nsIFile).path; //**** initialize file **** var file = Components.classes["@mozilla.org/file/local;1"] .createInstance(Components.interfaces.nsILocalFile); file.initWithPath(ProfilePath); //**** append each step in the path **** file.append("extensions"); file.append("guid"); file.append("sample.exe"); guid in my case is installed as {f13b157f-b174-47e7-a34d-4815ddfdfeb8}.xpi which cannot be accessible this way

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  • Save information from MS crash reporter?

    - by DGentry
    On Windows XP when a process crashes, we get a dialog box with a link: "To view technical information about the error report, click here." The "click here" link brings up a whole lot of information in a window, but no obvious way to save it to a file. Is there a way? It would be very nice to be able to send that data to several different external vendors we're working with. The only other option I see in the dialog box is to send it to Microsoft, but this crash is likely not Microsoft's fault and there is no reason to send it to them.

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  • Facing problem in configuring Reporting Server

    - by idrees99
    Hi all, I am using Sql server 2005 express edition and i want to Install and configure Reporting server on my local machine.Now i have installed the reporting server but the issue is that i am unable to configure it properly.when ever i go to start the reporting services it gives me the following message: THE SQL SERVER REPORTING SERVICE(SQLEXPRESS)service on Local computer started and then stopped. Some services stop automatically if they have no work to do, for example, the performance Logs and Alerts service. I am using WindowsXp Professional. plz help me out as i have just started using sql server and i dont have any idea.

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  • Uploading files wont work on production server

    - by Camran
    I have a php script which uploads images to a temporary folder on the server. This works on my local computer with the local (virtual) server. (wampserver). However, on the production server (linux) I cant get it working. Everything is loading as it should, except for that the file doesn't show up on the server. My Q is, is there anything I should think about when moving to a production server with uploading images or files? I have set permissions on the folder where the images are supposed to go to 777 and also the php-code which uploads them to 777. Thanks

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  • Aliasing localhost in Tomcat

    - by Saurabh
    I have a web application "quicker" deployed in Tomcat5.5 version. Usually, I run this application by using url, localhost/quicker and it loads the index.jsp file which is the home page of application. I would like same application to be run using url, www.local.dev.mydomain.com/quicker. Would it be possible by doing some configuration in server.xml or some other place? One way of doing this is could be, modify hosts file in windows as - # 127.0.0.1 localhost 127.0.0.1 www.local.dev.mydomain.com But, I want to this in tomcat manner if possible.

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  • Removing exception

    - by Nikhil K
    I have used this code for extracting urls from web page.But in the line of 'foreach' it is showing Object reference not set to an instance of an object exception. What is the problem? how can i correct that? WebClient client = new WebClient(); string url = "http://www.google.co.in/search?hl=en&q=java&start=10&sa=N"; string source = client.DownloadString(url); HtmlDocument doc = new HtmlDocument(); doc.LoadHtml(source); foreach (HtmlNode link in doc.DocumentNode.SelectNodes("//a[@href and @rel='nofollow']")) { Console.WriteLine(link.Attributes["href"].Value); }

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  • Linker Error : Statically Linking of Boost Serialization Library

    - by Manikanda raj S
    I'm trying to link the Boost Serialization Library to my Code. But it doesn't seem to be working. g++ serialize.cpp -L"/usr/local/lib/libboost_serialization.a" Error : /tmp/ccw7eX4A.o: In function boost::archive::text_oarchive::text_oarchive(std::basic_ostream<char, std::char_traits<char> >&, unsigned int)': serializep.cpp:(.text._ZN5boost7archive13text_oarchiveC2ERSoj[_ZN5boost7archive13text_oarchiveC5ERSoj]+0x25): undefined reference toboost::archive::text_oarchive_impl::text_oarchive_impl(std::basic_ostream &, unsigned int)' .......... collect2: ld returned 1 exit status But when i link as a shared library, g++ serialize.cpp -lboost_serialization , it works fine. What am i missing here P.S : Other StackOverflow posts with the same question has no answers that work for the above error

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  • How to add visible menu item from php code (drupal)

    - by uta
    I have a content type with important "created" date field. And I have a menu link (in primary links) which is link to page that shows list of all nodes of my content type. (http://example.com/mycontenttype) I want to have menu links (visible in primary links) to each year when nodes of my content type are displayed (http://example.com/mycontenttype/2010). And I want to add these menu links from mymodule_nodeapi function, when the node is creating and only if it has a "created" date of new year. I know that I can create a pathes in mymodule_menu function, but it doesn't create a visible menu item. (Maybe I can somehow set parent_link_id or something else to do it?)

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  • PHP preg_match image between html tags

    - by Alvins
    I've got an html template like this: <div class="cont"> <div class="..."> <p>...<p> <img alt="" class="popup" src="DESIRED IMAGE LINK" style="..." /></p><p>...</p> .... And i want to extract "DESIRED IMAGE LINK" inside the "" tag, currently i'm using this: $pattern = '<div class="cont">.*?src=["\']?([^"\']?.*?(png|jpg|jpeg|gif))["\']?/i'; if (preg_match($pattern, $content, $image)) ..... But it doesn't work, the error is: warning: preg_match() [function.preg-match]: Unknown modifier '.' How can i fix it? Thanks

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  • Django template CSS/IMG is "off" in the URL

    - by erimar77
    I have /path/to/my/theme/static/css/frontend.css which is called by base.html <link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}css/frontend.css" media="all" /> In which I've got a background for the header: #header-wrapper min-width: 960px; height: 150px; background: transparent url(img/header-bg.png) repeat-x center bottom; } The file is /path/to/my/theme/static/img I've run manage.py collectstatic to gather the files and almost everything looks correct except the link generated looks like: http://example.com/static/css/img/header-bg.png In which the image does not show, because the correct URL is: http://example.com/static/img/header-bg.png Where am I going wrong??

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  • Help me with Php session vs Header redirect?

    - by python
    I have the following pages: *page1.php <?php if (isset($_GET['link'])) { session_start(); $_session['myvariable'] = 'Hello World'; header('Location: http://' . $_SERVER['SERVER_NAME'] . dirname($_SERVER['REQUEST_URI']) . '/page2.php'); exit; } ?> <a href="<?php print $_SERVER['REQUEST_URI'] . '?link=yes';?>">Click Here</a> *page2.php <?php print 'Here is page two, and my session variable: '; session_start(); print $_session['myvariable']; //This line could not output. exit; ?> When I try output $_session['myvariable'] I did not get the result hello world message. I could not find out the solution to fix it .?

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  • Locking a detail view if a user is editing the item...

    - by BenTheDesigner
    Hi All I am developing a user manager which must control access to the detail view of editable items. At present, when a user clicks 'edit', the application queries the link table to check if a user is currently editing that page, if not, it allows access to the page and then inserts a record into the link table preventing another user from editing the same page at the same time. My question is what would the best way to handle the removal of records if say a user exists the browser without saving etc, therefore no action to remove the record. I have a couple of ideas but would like other input before I decide. BenTheDesigner

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