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  • PHP array minor problem

    - by Sennheiser
    I'm really not sure how to explain this. It's so simple I can't fathom why it's not working. I have a loop. It puts a bunch of strings into an array. If I fill a single variable with any given string, it will output it perfectly. But filling an array with the strings will make it give me the dreaded: Array Array Array Array Array Array Array Array Note: my strings are not all 'Array'. The way I loop is: while(...) { $arr[] = $resultFromLoop; } Here is my var_dump. array(1) { ["tagName"]=> string(5) "magic" } array(1) { ["tagName"]=> string(4) "nunu" } array(1) { ["tagName"]=> string(5) "books" } array(1) { ["tagName"]=> string(0) "" } array(1) { ["tagName"]=> string(3) "zzz" } array(1) { ["tagName"]=> string(4) "grey" } array(1) { ["tagName"]=> string(3) "new" } array(1) { ["tagName"]=> string(6) "flight" }

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  • PHP while loop, table row

    - by Elliott
    Hi, I'm trying to loop through a database and output data into a div, if there are 3 divs horizontally accross it will the start a new tr until it reaches another 3 etc. It is currently outputted like : [] [] [] [] [] [] Currently I have it working when it reaches 3 it starts a new row, but I don't know how I can only echo a new tr once? As it creates a new table row each time. echo '<table><tr>'; while ($result) { $i ++; if ($i&3) { echo '<td> <div>Row Data</div> </td>'; } else { echo '<tr> <td> <div>Row Data</div> </td></tr>'; } } echo '</tr></table>'; The $result variable is the recordset from my sql query, everything works fine I just don't know how to only create a new table row once? Thanks

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  • cache problem uinsg php and jquery

    - by pradeep
    hi , i am using jquery stars plugin and asking users to rate . the form works well,but caching has become a big problem. even after refresh of the page .it does not show the latest ratings . only after i clear the cache new ratings gets showed.

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  • PHP MYSQL SIMPLE SEARCH ISSUE

    - by Kunal
    Hi I have a table with the following structure: id int(11), name varchar(250) I have lots of records in the table but when I am trying to find a particluar record which has the following value on the name field: Lorem ipsum d\'olor sit amet The query is simply returning a blank recordset. I am not being able to figure out this weird behaviour, when my query is as simple as follows: SELECT * FROM slot_games WHERE name='Lorem ipsum d\'olor sit amet' Would appreciate your help please! Thanks in advance.

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  • "Distance" between colours in PHP

    - by Phil
    I'm looking for a function that can accurately represent the distance between two colours as a number or something. For example I am looking to have an array of HEX values or RGB arrays and I want to find the most similar colour in the array for a given colour eg. I pass a function a RGB value and the 'closest' colour in the array is returned

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  • PHP: Remove blank line before text

    - by Bailey
    Occasionally, my email-to-support-ticket system catches an extra line break before the message itself, thus my messages look like this: " Hello. I have been wondering if y..." What can I use to get rid of that line before the text? It is on random occasion due to email providers and the way they format their emails using mime. I have already tried the trim functions but no luck. (Yes, I also tried ltrim) Once processed it should look like: "Hello. I have been wondering if y..."

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  • PHP sort multidimensional array by value

    - by stef
    How can I sort this array by the value of the "order" key? Even though the values are currently sequential, they will not always be. Array ( [0] => Array ( [hashtag] => a7e87329b5eab8578f4f1098a152d6f4 [title] => Flower [order] => 3 ) [1] => Array ( [hashtag] => b24ce0cd392a5b0b8dedc66c25213594 [title] => Free [order] => 2 ) [2] => Array ( [hashtag] => e7d31fc0602fb2ede144d18cdffd816b [title] => Ready [order] => 1 ) )

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  • php values of one array to key of another array

    - by mark
    I have 2 arrays $arr1 = Array ( [0] => 12 [1] => 4 [2] => 8 [3] => xx [4] => 1 [5] => 1year [6] => 7 ) $arr2 = Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 4 [4] => 5 [5] => 6 [6] => 7 ) I want to create a new array with the values of a2 as keys in $arr1. My resultant array should be like this $arr3 = Array ( [1] => 12 [2] => 4 [3] => 8 [4] => xx [5] => 1 [6] => 1year [7] => 7 )

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  • Using PHP to Seperate Results of a txt file

    - by outbreak
    I am trying to display the last 10 lines of a File and from there take those results and break them down to 10 individual lines.. Currently the code I have found from examples is: $filearray = file("test.txt"); $lastfifteenlines = array_slice($filearray,-10); echo implode($lastfifteenlines, "\n") It display's the 10 items I need however it does not break them down onto individual lines the current results are: 1.0.0.11 1.0.0.12 1.0.0.13 1.0.0.14 1.0.0.15 I need that to instead display as: 1.0.0.11 1.0.0.12 1.0.0.13 1.0.0.14 1.0.0.15 Thanks in Advance for the Asistance!

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  • Difference between :: and -> in PHP

    - by vrode
    I always see people in serious projects use :: everywhere, and - only occasionally in local environment. I only use - myself and never end up in situations when I need a static value outside of a class. Am I a bad person? As I understand, the only situation when -> won't work is when I try following: class StaticDemo { private static $static } $staticDemo = new StaticDemo( ); $staticDemo->static; // wrong $staticDemo::static; // right But am I missing out on some programming correctness when I don't call simple public methods by :: ? Or is it just so that I can call a method without creating an instance?

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  • wp e-commerce php modification

    - by user1015687
    Here are a few lines of code from a wordpress plugin (WP E-commerce) that calculate the price. Now what i want is that if 'cart_item' are more than 3 in quantity then the price should be (number of items * 4) else the function should work as it is listed below. Thnks for help. function calculate_subtotal($for_shipping = false) { 1047 global $wpdb; 1048 if($for_shipping == true ) { 1049 $total = 0; 1050 foreach($this->cart_items as $key => $cart_item) { 1051 if($cart_item->uses_shipping == 1) { 1052 $total += $cart_item->total_price; 1053 } 1054 } 1055 } else { 1056 $total = 0; 1057 if($this->subtotal == null) { 1058 foreach($this->cart_items as $key => $cart_item) { 1059 $total += $cart_item->total_price; 1060 } 1061 $this->subtotal = $total; 1062 } else { 1063 $total = $this->subtotal; 1064 } 1065 } 1066 return $total; 1067 }

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  • PHP object cannot find method

    - by Daniel Hertz
    Hello, So I have a very simple class that has a method called getThumbUrl() but when I try calling this method on an instance I get Notice: Undefined property: FlickrImage::$getFullUrl But it is clearly there. Here is the code of the function: public function getThumbUrl() { return "http://farm".$this->_farm.".static.flickr.com/".$this->_server."/".$this->_id."_".$this->_secret."_t.jpg"; } And here is where it fails: foreach($photos as $photo) { echo "<img src='$photo->getFullUrl()' />"; } Any ideas? Thanks!

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  • Can't figure out what's wrong with my php/sql statement

    - by Olegious
    So this is probably a dumb beginner question, but I've been looking at it and can't figure it out. A bit of background: just practicing making a web app, a form on page 1 takes in some values from the user, posts them to the next page which contains the code to connect to the DB and populate the relevant tables. I establish the DB connection successfully, here's the code that contains the query: $conn->query("SET NAMES 'utf9'"); $query_str = "INSERT INTO 'qa'.'users' ('id', 'user_name','password' ,'email' ,'dob' ,'sx') VALUES (NULL, $username, $password, $email, $dob, $sx);"; $result = @$conn->query($query_str); Here's the error that is returned:Insert query failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''qa'.'users' ('id', 'user_name' ,'password' ,'email' ,'dob' ,'s' at line 1 Thanks in advance!

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  • PHP: constant as variable in function

    - by m4recek
    I'm trying to use constant as a function paramter, is it possible to check type of this constant. Example of what I want: class ApiError { const INVALID_REQUEST = 200; } class Response { public function status(ApiError $status) { //function code here } } USE: $response = new Response(); $response->status(ApiError::INVALID_REQUEST); This shoud check that given $status is constant of class ApiError. Is something like this possible?

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  • help with php MVC problem

    - by aprencai
    hello, I have groups on my site and the urls have the following hierarchy: / groups / {id_group} / / groups / {id_group} / news / groups / {id_group} / gallery / groups / {id_group} / events / groups / {id_group} / events / {id_event} / groups / {id_group} / events / {id_event} / news / groups / {id_group} / events / {id_event} / gallery / groups / {id_group} / events / {id_event} / news As you can see a group can have news, gallery, etc. and in turn an event that is in a group can also have news, gallery, etc. How to implement this approach in a framework without specifying any specific one?, ie I would like some guidance on what would have modules, controllers, etc. Thanks.

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  • Best method to cache objects in PHP?

    - by Martin Bean
    Hi, I'm currently developing a large site that handles user registrations. A social networking website for argument's sake. However, I've noticed a lag in page loads and deciphered that it is the creation of objects on pages that's slowing things down. For example, I have a Member object, that when instantiated with an ID passed as a construct parameter, it queries the database for that members' row in the members database table. Not bad, but this is created each time a page is loaded; and called more than once when say, calling an array of that particular members' friends, as a new Member object is created for each friend. So on a single page I can have upwards of seven of the same object, but containing different properties. What I'm wanting to do is to find a way to reduce the database load, and to allow persist objects between page loads. For example, the logged in user's object to be created on login (which I can do) but then stored somewhere for retrieval so I don't have to keep re-creating the object between page loads. What is the best solution for this? I've had a look at Memcache, but with it being a third-party module I can't have the web host install it on this occasion. What are my alternatives, and/or best practices in my case? Thanks in advance.

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  • [PHP] How to unset object's inherited properties ?

    - by vbklv
    I have an Object ( [id] => 1 [parent_id] => 0 [result:Database:private] => [db:Database:private] => mysqli Object ( [affected_rows] => 0 ... ) ) Obviously, the Object has inherited the 'db' and 'result' properties of the parent Database class. unset($object-result) nor unset($object-result:Database) nor unset($object-result:Database:private) work. How could I unset those properties when they are no longer needed (i.e. when the object properties are about to be output)? Is it a generally a good idea to have a database object as an inherited property of other classes (extend one Database class with all other classes that use database connections)?

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  • Displaying SQL results using PHP

    - by mouthpiec
    Hi, I have an SQL query that returns an amount of tuples (about 50). Now I need to display the results, 15 tuples at a time, then I will have a "view more" button to view the next 15 results. Can you please help me how I can make this? The issue is that I cannot use the 'limits' because each time I run the query the results will be different, hence when pressing view more, I may get the same results of the same page. thanks

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  • php adding value to session

    - by antikbd
    I am trying to implement a 'shopping cart' where, if the 'Add to Cart' has been clicked, the respective item is either added to the cart or incremented by one if already present. However, the following code isn't working and giving me a "Cannot use a scalar value as an array" error. Any help would be highly appreciated. if (isset($_POST['fan']) && ($_POST['fan']=="Add to Cart")) { if (($_SESSION['cart']['fan']==0) || (!isset($_SESSION['cart']['fan']))) { $_SESSION['cart']['fan']=1; } else { $_SESSION['cart']['fan']++; } }

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