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• Problem running VBScript from my UIAccess VB app using MSScriptControl

  - by Ray

  I'm trying to run some VBSCRIPT from within my application. This works fine when I run my program from within VB. But once I add "UIAccess=true" to my manifest and digitally sign my exe with my certificate, I am unable to run the code any more. It gives errors when I try to interface with any program saying "429: ActiveX component can't create object: 'myApp.Application'". Anyone have any idea why it would run fine in the IDE but not with an application with uses UIAccess? Here is the code: Dim scriptRunner As New MSScriptControl.ScriptControlClass scriptRunner.Language = "VBScript" scriptRunner.AllowUI = True scriptRunner.Timeout = 3000 scriptRunner.AddCode(scriptStr) scriptRunner = Nothing

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• odd behavior setting timeouts inside a function with global references in javascript

  - by Pablo

  Here is the the function and the globals: $note_instance = Array(); $note_count = 0; function create(text){ count = $note_count++; time = 5000; $note_instance[count] = $notifications.notify("create", text); setTimeout(function(){ $note_instance[count].close() }, time); } The function simply opens a notification, a sets a timeout to close it in 5 seconds. so if i call this create("Good Note 1"); create("Good Note 2"); create("Good Note 3"); Ecah note should close 5 seconds from their creation, however always and only the last note closes, in this case "Good Note 3". Each note object has its own entry in the the $note_instance global array so the timeouts should no be overwriting themselves. What am i missing here folks? Thanks in advance

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• VB6 ActiveX exe - what is the proper registration sequence?

  - by Timbuck

  I have recently updated a Visual Basic 6 application that is an ActiveX exe, running on Windows XP. I have a couple of testers for this application who have received a copy of the exe and are attempting to run it. However, they are getting an error message "Unexpected error;quitting" when trying to do so. A key difference between their testing and my testing is that on the machines I tested on, I have admin rights and was able to register the application using the appname.exe /regserver command line. Reading the details at MS Support about file registration appears unclear: Visual Basic ActiveX EXE files register themselves the first time you run the EXE. However, you cannot use the EXE as a COM server until it is registered. So does this mean that after the first time the users run the exe that the application should be correctly registered, and the error I am receiving is sign of something other than an incorrectly registered application? Or does this mean that the application will not work properly until such time as the file is explicitly registered using the appname.exe /regserver command line? nb - during a production distribution, the software would be sent out to client PCs using Systems Management Server, which isn't an option for this testing.

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• app.config and 64-bit machines

  - by Dale Lutes

  I have an app that works fine on 32-bit systems, but fails on XP 64 bit systems. I've tracked it down to the connection string defined in my app.config thus: <connectionStrings> <clear/> <add name="IFDSConnectionString" connectionString="Data Source=fdsdata;Initial Catalog=IFDS; Trusted_Connection=true;Connect Timeout=0" providerName="System.Data.SqlClient" /> </connectionStrings> When I try to reference it in code, I find that the ConfigurationManager.ConnectionStrings collection only contains the LocalSqlServer connection string from the machine.config file and not my custom string. Another oddity is that it works fine when I run the app out of Visual Studio. It is only when I run out of the release folder that the connection string does not get defined. The application's .exe.config file is there in the release folder along with the .exe file and is up to date.

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• Error using 'send_file' for ruby/rails - help appreciated

  - by user1653279

  I am trying to create a link to download a file from the file system. For this, I define the following in the "license_helper.rb" file: def license_download_link(license, link_text = nil) if link_text.blank? link_text = image_tag("download_icon.png", :border => 0, :width => 32, :height =>32, :alt => 'Download License', :title => 'Download License') end tempLicenseFile = "tempLicense.xml" File.open("#{tempLicenseFile}", 'w') do |tf| tf.puts license.data end command = "./runLicenseEncoder.bat #{tempLicenseFile}" generateEncryptedLicenseFile = `#{command}` theLicenseFile = "license.xml" link_to link_text, "license/download" end My "view" just calls this helper class: <td><%= license_download_link(license, ' ') %></td> In the 'routes.rb' file, I have defined the following: map.licensedownload "license.xml", :controller = 'licenses', :action = 'download' map.download "/licenses/download", :controller = 'licenses', :action = 'download' In the 'controller', I have 'licenses_controller.rb' which includes the following: def download theLicense = @license licenseFileName = "license.xml" send_file "#{licenseFileName}" , :type => "application/xml", :filename => "#{licenseFileName}" end However, I am unable to obtain the '@license' attribute from the database in the controller. Could someone please let me know what I am doing wrong here and why I am unable to get the value for "@license". Thanks for your time, Regards, --- AJ

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• Asynchronous SQL Operations

  - by Paul Hatcherian

  I've got a problem I'm not sure how best to solve. I have an application which updates a database in response to ad hoc requests. One request in particular is quite common. The request is an update that by itself is quite simple, but has some complex preconditions. For this request the business layer first requests a set of data from the data layer. The business logic layer evaluated the data from the database and parameters from the request, from this the action to be performed is determined, and the request's response message(s) are created. The business layer now executes the actual update command that is the purpose of the request. This last step is the problem, this command is dependent on the state of the database, which might have changed since the business logic ran. Locking down the data read in this operation across several round-trips to the database doesn't seem like a good idea either. Is there a 'best-practice' way to accomplish something like this? Thanks!

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• Accessing and inheriting Windows Message for other Windows Message in Delphi

  - by HX_unbanned

  I am using WMSysCommand messages to modify Caption bar button ( Maximize / Minimize ) behaivor and recent update requiered to use WMNCHitTest, but I do not want to split these two related messages in multiplie procedures because of lengthy code. Can I access private declaration ( message ) from other message? And if I can - How to do it? procedure TForm1.WMNCHitTest(var Msg: TWMNCHitTest) ; begin SendMessage(Handle, HTCAPTION, WM_NCHitTest, 0); // or other wParam or lParam ???? end; procedure TForm1.WMSysCommand; begin if (Msg.CmdType = SC_MAXIMIZE or 61488) or (Msg.Result = htCaption or 2) then // if command is Maximize or reciever message of Caption Bar click begin if CheckWin32Version(6, 0) then Constraints.MaxHeight := 507 else Constraints.MaxHeight := 499; Constraints.MaxWidth := 0; end else if (Msg.CmdType = SC_MINIMIZE or 61472) or (Msg.Result = htCaption or 2) then // if command is Minimize begin if (EnsureRange(Width, 252, 510) >= (510 / 2)) then PreviewOpn.Caption := '<' else PreviewOpn.Caption := '>'; end; DefaultHandler(Msg); // reset Message handler to default ( Application ) end; Soo ... do I think correctly and sipmly do not know correct commands or I am thinking total bullsh*t? Regards. Thanks for any help...

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• How to convert a byte array of 19200 bytes in size where each byte represents 4 pixels (2 bits per p

  - by Klinger

  I am communicating with an instrument (remote controlling it) and one of the things I need to do is to draw the instrument screen. In order to get the screen I issue a command and the instrument replies with an array of bytes that represents the screen. Below is what the instrument manual has to say about converting the response to the actual screen: The command retrieves the framebuffer data used for the display. It is 19200 bytes in size, 2-bits per pixel, 4 pixels per byte arranged as 320x240 characteres. The data is sent in RLE encoded form. To convert this data into a BMP for use in Windows, it needs to be turned into a 4BPP. Also note that BMP files are upside down relative to this data, i.e. the top display line is the last line in the BMP. I managed to unpack the data, but now I am stuck on how to actually go from the unpacked byte array to a bitmap. My background on this is pretty close to zero and my searches have not revealed much either. I am looking for directions and/or articles I could use to help me undestand how to get this done. Any code or even pseudo code would also help. :-) So, just to summarize it all: How to convert a byte array of 19200 bytes in size, where each byte represents 4 pixels (2 bits per pixel), to a bitmap arranged as 320x240 characters. Thanks in advance.

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• Which Namespaces Must Be Used to Connect to SQL Server with ADO.NET?

  - by every_answer_gets_a_point

  i am using this example to connect c# to sql server. can you please tell me what i have to include in order to be able to use sqlconnection? it must be something like: using Sqlconnection; ??? string connectionString = @"Data Source=.\SQLEXPRESS;AttachDbFilename=""C:\SQL Server 2000 Sample Databases\NORTHWND.MDF"";Integrated Security=True;Connect Timeout=30;User Instance=True"; SqlConnection sqlCon = new SqlConnection(connectionString); sqlCon.Open(); string commandString = "SELECT * FROM Customers"; SqlCommand sqlCmd = new SqlCommand(commandString, sqlCon); SqlDataReader dataReader = sqlCmd.ExecuteReader(); while (dataReader.Read()) { Console.WriteLine(String.Format("{0} {1}", dataReader["CompanyName"], dataReader["ContactName"])); } dataReader.Close(); sqlCon.Close();

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• How much effort does it take to spoof an Ip Address in a call to a webservice?

  - by Rory Becker

  I don't want to know how... Just how complicated.... I'm thinking of securing a webservice or 2 based on the incoming client ipaddress of the caller. Is this in any way secure? Surely if the IPaddress was being spoofed then the result would have to be sent back to the address that was being spoofed and therefore not reach the spoofer? Update: Ok so from what I can tell.... I should create a Gettoken() method which checks the IPaddress and passes out a cryptographically significant token with a timeout to any valid IP address. This is then required by any other method before any kind of side effect is allowed. Since an Attacker can't (likely) get the token without having a valid IP, he will be unable to validly call any of my "dangerous" webmethods ?

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• How do I capture Chinese input via SCIM with STDIN in Perl?

  - by KCArpe

  I use SCIM on Linux for Chinese and Japanese language input. Unfortunately, when I try to capture input using Perl's STDIN, the input is crazy. As roman characters are typed, SCIM tries to guess the correct final characters. ^H (backspace) codes are used to delete previously suggested chars on the command line. (As you type, SCIM tries to guess final Asian chars and displays them.) However, these backspace chars are shown literally as ^H and not interpreted correctly. Example one-liner: perl -e 'print "Chinese: "; my $s = <STDIN>; print $s' When I enable SCIM Chinese or Japanese language input, as I type, e.g., nihao = ??, here is the result: ?^H?^H?^H?^H?^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H?? At the very end of this string, you can see "??" (nihao/hello). At a normal bash prompt, if I type nihao (with Chinese enabled), the results is perfect. This has something to do with interpretation of backspace chars (or control chars) during Perl's STDIN. The same thing happens when using command 'read' in Bash. Witness: read -p 'Chinese: ' s && echo $s

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• Getting a particular menu item from MainMenu

  - by Garry

  I have a nib (winA.xib) that contains a window. My app delegate contains an NSWindowController subclass called WinAController. WinAController has a property (NSMenu *mainMenu) that I want to point to the MainMenu. I have set it after I instantiate WinAController with this code: WinAController = [[WinAController alloc] initWithWindowNibName:@"WinA"]; WinAController.mainMenu = [NSApp mainMenu]; I have a menu item underneath the "Window" top-level menu item on MainMenu that invokes the [WinAController showWindow] method and displays WinA. I want to toggle the on/off state of this menu item depending on whether WinA is visible or not. WinAController also has another property (NSMenuItem *myMenuItem). How can I get a reference to a sub menu of the "Window" top-level menu item. The title of sub menu item I want to get is "Command". I have tried this: if (mainMenu != nil) { myMenuItem = [mainMenu itemAtIndex:[mainMenu indexOfItemWithTitle:@"Command"]]; } But it doesn't seem to work. Where am I going wrong? Thanks,

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• Keep a javascript variable after an ajax call

  - by Guillaume le Floch

  I'm new in javascript and jQuery. I'm using ajax calls to get data from my server. The fact is, I'm losing my javascript variables after the call .. Here is what I did : the variable is define outside any function and treat in an other function. var a = 0; function myfunction(url){ $.ajax({ url: url, timeout: 20000, success: function(data){ // Do some stuff // The a variable is now undefined }, error: function(){ // Do some stuff } }); } Everything is working fine, the only thing is that I need to keep my variables ... but it looks like it's gone .. Does anyone know why? Thanks

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• Creating UTF-8 files in Java from a runnable Jar

  - by RuntimeError

  I have a little Java project where I've set the properties of the class files to UTF-8 (I use a lot of foreign characters not found on the default CP1252). The goal is to create a text file (in Windows) containing a list of items. When running the class files from Eclipse itself (hitting Ctrl+F11) it creates the file flawlessly and opening it in another editor (I'm using Notepad++) I can see the characters as I wanted. +--------------------------------------------------+ ¦ Universidade2010 (18/18)¦ ¦ hidden: 0¦ +--------------------------------------------------¦ But, when I export the project (using Eclipse) as a runnable Jar and run it using 'javaw -jar project.jar' the new file created is a mess of question marks ???????????????????????????????????????????????????? ? Universidade2010 (19/19)? ? hidden: 0? ???????????????????????????????????????????????????? I've followed some tips on how to use UTF-8 (which seems to be broken by default on Java) to try to correct this so now I'm using Writer w = new OutputStreamWriter(fos, "UTF-8"); and writing the BOM header to the file like in this question already answered but still without luck when exporting to Jar Am I missing some property or command-line command so Java knows I want to create UTF-8 files by default ?

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• make arm architecture c library in mac

  - by gamegamelife

  I'm trying to make my own c library in Mac and include it to my iphone program. The c code is simple , like this: math.h: int myPow2(int); math.c: #include "math.h" int myPow2(int num) { return num*num; } I search how to make the c library file ( .a or .lib ..etc) seems need to use gcc compiler (Is there other methods?) so I use this command: gcc -c math.c -o math.o ar rcs libmath.a math.o And include it in iPhone Project. Now it has the problem when build xcode iphone project. "file was built for unsupported file format which is not the architecture being linked" I found some pages discuss about the problem, but no detail how to make the i386/arm architecture library. And I finally use this command to do it: gcc -arch i386 -c math.c -o math.o /Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/arm-apple-darwin10-gcc-4.2.1 -c math.c -o math.o I dont know if this method is correct? Or there has another method to do it?

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• Webservice for serial port devices

  - by camx

  Hi I want to create a remote webservice for an application that is now avaliable only localy. This application controlls three devices (each is controlled separately) connected on serial port. The problem is that I don't know how to take care of passing back information that a device return requested data. For example - I send move command to the motion device (which is very slow and can take a minute or more). Can I just set a big timeout on the client side (and server side) and return for example a true/false if operation is completed or is this a bad idea? Is SOAP with big timeouts ok? And the other question is if Mono on Linux (Ubuntu 9.10, Mono 2.4) is stable enought for making a web service or should I chose Java or some other language? I'm open for recommendations. Thanks for your help!

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• Toastr.js notifications as modal notfication

  - by Maxsteel

  I know it's not what toastr (or toast notifs in general) are meant to be used for, but I want to use them as a modal notification. My idea is following. On toast show: toastr.options.onShown = function() { //Create an overlay on the entire page} Overlay: #overlay { background-color: rgba(0, 0, 0, 0.8); z-index: 999; position: absolute; left: 0; top: 0; width: 100%; height: 100%; display: none; } And on toast close: toastr.options.onHidden = function() { //make overlay go away } Also, I'm setting timeout of toast to 0 so it won't disappear by itself. Question: I want the toast notification to stay atop the overlay and not behind it as overlay will cover everything. How can I do it?

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• jQuery blockUI and AJAX POST

  - by oompahloompah

  I am using jQuery BlockUI in a project. For a particular user action, I want to block the UI, and then POST data to the server. When the timeout event occurs OR the server returns, I want to unblock the page. I can't seem to implement this behaviour. This is what I have so far (not working) $(document).ready(function(){ $('#test').click(function(event){ $.blockUI({ message: $('#syntax-chk') }); $.ajax({ type: 'POST', url: 'www.example.com', data: somedata, dataType: "json" }); setTimeout(function() { $.unblockUI({ onUnblock: function(){ alert('onUnblock'); } }); }, 2000); }); can anyone spot what I may be doing wrong?

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• jQuery.Form wont submit

  - by kim

  Im´trying to submit a form without refreshing the page, but I´m having a problem. When I click submit the page refreshes and anothing gets posted. Here is the code, what am I doing wrong? (I´m a newbie) jQuery 1.4.2 and the jQuery Form Plugin 2.43 is present. tnx $(document).ready(function() { var options = { target: '#output2', url: https://graph.facebook.com/<%=fbUid%>/feed, type: post, clearForm: true // clear all form fields after successful submit //dataType: null // 'xml', 'script', or 'json' (expected server response type) //resetForm: true // reset the form after successful submit // $.ajax options can be used here too, for example: //timeout: 3000 }; // bind to the form's submit event $('#fbPostStatus').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit(options); // !!! Important !!! // always return false to prevent standard browser submit and page navigation return false; }); });

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• ipad subview not loading before code is executing

  - by ethan Criss

  I have a command that should be loading a subview before a particular piece of time intensive code executes. However the command runs, the timely code executes and then the subview shows up. Is there anything I can do to fix this problem? progressViewController = [[ProgressView alloc] initWithNibName:@"ProgressView" bundle:[NSBundle mainBundle]]; [self.view addSubview:[progressViewController view]]; NSString *name=@"guy"; NSString *encodedName =[[NSString alloc] init]; int asci; for(int i=0; i < [name length]; i++) { //NSLog(@"1"); asci = [name characterAtIndex:i]; NSString *str = [NSString stringWithFormat:@"%d,", asci]; encodedName =[encodedName stringByAppendingFormat: str]; } NSString *urlString = [NSString stringWithFormat:@"someurl.com"]; NSURL *theUrl = [[NSURL alloc] initWithString:urlString]; NSString *result=[NSString stringWithContentsOfURL:theUrl]; result = [result substringFromIndex:61]; result = [result substringToIndex:[result length] - 20]; NSLog(result); outLab.text=result; [[progressViewController view] removeFromSuperview];

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• Stopping process in /etc/inittab kills spawned process. Doesn't happen in rc.local.

  - by Paul

  Hi, I'm trying to execute a firmware upgrade while my programming is running in inittab. My program will run 2 commands. One to extract the installer script from the tarball and the other to execute the installer script. In my code I'm using the system() function call. These are the 2 command strings below, system ( "tar zvxf tarball.tar.gz -C / installer.sh 2>&1" ); system( "nohup installer.sh tarball >/dev/null 2>&1 &" ); The installer script requires the tarball to be an argument. I've tried using sudo but i still have the same problem. I've tried nohup with no success. The installer script has to kill my program when doing the firmware upgrade but the installer script will stay alive. If my program is run from the command line or rc.local, on my target device, my upgrade works fine, i.e. when my program is killed my installer script continues. But I need to run my program from /etc/inittab so it can respawn if it dies. To stop my program in inittab the installer script will hash it out and execute "telinit q". This is where my program dies (but thats what I want it to do), but it also kills my installer script. Does anyone know why this is happening and what can I do to solve it? Thanks in advance.

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• Unexpected output using subprocess in Python

  - by Vic

  I am trying to run a shell command from within my Python (version 2.6.5) code, but it is generating different output than the same command run within the shell (bash): bash: ~> ifconfig eth0 | sed -rn 's/inet addr:(([0-9]{1,3}\.){3}[0-9]{1,3}).*/\1/p' | sed 's/^[ \t]*//;s/[ \t]*$//' 192.168.1.10 Python: >>> def get_ip(): ... cmd_string = "ifconfig eth0 | sed -rn \'s/inet addr:(([0-9]{1,3}\.){3}[0-9]{1,3}).*/\1/p' | sed 's/^[ \t]*//;s/[ \t]*$//\'" ... process = subprocess.Popen(cmd_string, shell=True, stdout=subprocess.PIPE) ... out, err = process.communicate() ... return out ... >>> get_ip() '\x01\n' My guess is that I need to escape the quotes somehow when running in python, but I am not sure how to go about this. NOTE: I cannot install additional modules or update python on the machine that this code needs to be run on. It needs to work as-is with Python 2.6.5 and the standard library.

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• Tkinter, Python: How do I save text entered in the Entry widget? How do I move a label?

  - by user3692825

  I am a newbie at programming and my program is not stellar but hopefully it's ok because I have only been using it for a couple days now. I am having trouble in my class "Recipie". In this class I am having trouble saving the text in my Entry widget. I know to use the .get() option but when I try to print it, it doesn't (whether it is within that defined method or not). So that is my main concern. I want it to save the text entered as a string when I press the button: b. My other minor question is, how can I move the label. When I have tried I have used the height and width options, but that just expands the label. I want to move the text to create a title above my Entry boxes. Is label the right widget to use or would it be easier to use a message box widget? So it would look like, for example (but like 8 pixels down and 20 to the right): ingredients textbox button labeled as: add an ingredient And I am not sure the option .pack(side="...") or .place(anchor="...") are the right options to use for my buttons or entry boxes or labels. Any help is greatly appreciated!!! And if you could add comments to your code explaining what you did, that would be so helpful. Thank you!!! import Tkinter class Recipie(Tkinter.Tk): def __init__(self): Tkinter.Tk.__init__(self) self.title("New Recipie") self.geometry("500x500") def name(self): name = Tkinter.Label(self, text="Title:", width=39) name.place(anchor="nw") insert_name = Tkinter.Entry(self) insert_name.pack() insert_name.focus_set() def ingredients(self): e = Tkinter.Entry(self) e.pack() e.focus_set() def addingredient(self): but = Tkinter.Button(self, text="Add Ingredients", width=15, command=self.ingredients) but.pack(side="bottom") def procedure(self): txt = Tkinter.Label(self, text="List the Steps:") txt.place(anchor="n") p = Tkinter.Entry(self) p.place(anchor="nw") p.focus_set() def savebutton(self): print insert_name.get() print e.get() print p.get() b = Tkinter.Button(self, text="Save Recipie", width=15, command=savebutton) top = Recipie() top.mainloop()

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• Warn user when new data is inserted on database

  - by João Menighin

  I don't know how to search about this so I'm kinda lost (the two topics I saw here were closed). I have a news website and I want to warn the user when a new data is inserted on the database. I want to do that like here on StackOverflow where we are warned without reloading the page or like in facebook where you are warned about new messages/notifications without reloading. Which is the best way to do that? Is it some kind of listener with a timeout that is constantly checking the database? It doesn't sounds efficient... Thanks in advance.

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• how to delete in Mysql

  - by Ian Moss

  i want to delete a element in mysql. the problem is that my connection not succesfully open and they give me error unable to connect even same connectionstring work elsewhere in current project. well when my code open the connection they work fine. but a small function try to delete a row in Mysql. i am confused what is goes wrong because :- same connectionstring work elsewhere in project i trying but a function only have a project [unable to connect] the [unable to connect] problem come when my code trying to delete the rows in mysql. i use sqlyog to open the connection and they work fine as other code work and their is no problem i got when i run the command on sqlyog. conclusion:- why connection not open if they work elsewhere in the project and in also in sqlyog. any reason for unable to connect. because connection can not open offcourse command never run so what is reason upon the connection unable to connect. well any suggestion , thing you feel and trick you have to solve this issue i have. thanks

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