mysql query - Page 429 - Developer IT

encrypt apache and mysql servers

- by stormdrain

I have a question about encrypting disks. I have 2 servers: 1 is apache for web/frontend and it talks to server 2 which is mysql. They are all for intranet only; no external access. I was looking into using PGP or GnuPG to encrypt the disks. I'm not clear, though, as to exactly how this would work. Where would the keys be stored? On the client? On apache? If there is a key on apache to access mysql, does there need to be a key for each user? If so, if key 1 is used to alter some data, would then that data be inaccessible to a user using key 2? And the apache key, would that only be accessible to users with local keys? Is encryption done on the fly? Does it degrade performance? What would be the best approach to encrypt the data on these servers, but have them accessible to users? Thanks!

Read the article

User Getting Logged Out After Making First Comment

- by John

Hello, I am using a login system that works well. I am also using a comment system. The comment function does not show up unless the user is logged in (as shown in commentformonoff.php below). When a user makes a comment, the info is passed from the function "show_commentbox" to the file comments2a.php. Then, the info is passed to the file comments2.php. When the site is first pulled up on a browser, after logging in and making a comment, the user is logged out. After logging in a second time during the same browser session, the user is no longer logged out after making a comment. How can I keep the user logged in after making the first comment? Thanks in advance, John Commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } ?> Function "show_commentbox": function show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl) { echo '<form action="http://www...com/.../comments/comments2a.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$_SESSION['username'].'" name="u"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.stripslashes($submission).'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="checkMax" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; } Included in comments2a.php: $uid = mysql_real_escape_string($_POST['uid']); $u = mysql_real_escape_string($_POST['u']); $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); $lastcommentid = mysql_insert_id(); header("Location: comments2.php?submission=".$submission."&submissionid=".$submissionid."&url=".$url."&submissiondate=".$submissiondate."&comment=".$comment."&subid=".$subid."&uid=".$uid."&u=".$u."&submittor=".$submittor."&countcomments=".$countcomments."&dispurl=".$dispurl."#comment-$lastcommentid"); exit(); Included in comments2.php: if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../comments/comments2.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'&submissiondate='.$submissiondate.'&submittor='.$submittor.'&countcomments='.$countcomments.'&dispurl='.$dispurl.'');} $uid = mysql_real_escape_string($_GET['uid']); $u = mysql_real_escape_string($_GET['u']);

Read the article

Copying contents of a MySQL table to a table in another (local) database

- by Philip Eve

I have two MySQL databases for my site - one is for a production environment and the other, much smaller, is for a testing/development environment. Both have identical schemas (except when I am testing something I intend to change, of course). A small number of the tables are for internationalisation purposes: TransLanguage - non-English languages TransModule - modules (bundles of phrases for translation, that can be loaded individually by PHP scripts) TransPhrase - individual phrases, in English, for potential translation TranslatedPhrase - translations of phrases that are submitted by volunteers ChosenTranslatedPhrase - screened translations of phrases. The volunteers who do translation are all working on the production site, as they are regular users. I wanted to create a stored procedure that could be used to synchronise the contents of four of these tables - TransLanguage, TransModule, TransPhrase and ChosenTranslatedPhrase - from the production database to the testing database, so as to keep the test environment up-to-date and prevent "unknown phrase" errors from being in the way while testing. My first effort was to create the following procedure in the test database: CREATE PROCEDURE `SynchroniseTranslations` () LANGUAGE SQL NOT DETERMINISTIC MODIFIES SQL DATA SQL SECURITY DEFINER BEGIN DELETE FROM `TransLanguage`; DELETE FROM `TransModule`; INSERT INTO `TransLanguage` SELECT * FROM `PRODUCTION_DB`.`TransLanguage`; INSERT INTO `TransModule` SELECT * FROM `PRODUCTION_DB`.`TransModule`; INSERT INTO `TransPhrase` SELECT * FROM `PRODUCTION_DB`.`TransPhrase`; INSERT INTO `ChosenTranslatedPhrase` SELECT * FROM `PRODUCTION_DB`.`ChosenTranslatedPhrase`; END When I try to run this, I get an error message: "SELECT command denied to user 'username'@'localhost' for table 'TransLanguage'". I also tried to create the procedure to work the other way around (that is, to exist as part of the data dictionary for the production database rather than the test database). If I do it that, way, I get an identical message except it tells me I'm denied the DELETE command rather than SELECT. I have made sure that my user has INSERT, DELETE, SELECT, UPDATE and CREATE ROUTINE privileges on both databases. However, it seems as though MySQL is reluctant to let this user exercise its privileges on both databases at the same time. How come, and is there a way around this?

Read the article

BASH echo write mysql input

- by jmituzas

Have a bash menu where variables write to file for mysql input. heres what I have: echo "CREATE DATABASE '$mysqldbn'; #GRANT ALL PRIVILEGES ON *.* TO '$mysqlu'@'$myhost' IDENTIFIED BY '$mysqlup' WITH GRANT OPTION; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES ON '$mysqldbn'.* TO '$mysqlu'@'$myhost' IDENTIFIED BY '$mysqlup'; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES ON '$mysqldbn'.* TO '$mysqlu'@'$myip' IDENTIFIED BY '$mysqlup'; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES ON '$mysqldbn'.* TO '$mysqlu'@'localhost' IDENTIFIED BY '$mysqlup'; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES< LOCK TABLES on '$mysqldbn'.* TO '$mysqlu'@'$rip' IDENTIFIED BY '$mysqlup';" > nmysql.db mysql -u root -p$mypass < nmysql.db problem is to get variables to show I had to put them in single quotes, the single quotes show up as I want for instances like '$mysqlu'@'localhost'. But how can I remove the quotes and still get to use the variable in the instance like, CREATE DATABASE '$mysqldbn' ? Double quotes wont work either, I am at a loss. Thanks in advance, Joe

Read the article

Python Loop for mysql statement

- by user552974

Hi, I have a project that i need to compile number of cities in each state and make an insert statement for mysql database. I think the easiest way to do it is via python but since i m a complete noob i would like to reach out all the python gurus here. Here is what the input looks like. Example below is for Florida. cities = ['Boca Raton', 'Boynton Beach', 'Bradenton', 'Cape Coral', 'Deltona'] and this what the output should be. INSERT INTO `oc_locations` (`idLocation`, `name`, `idLocationParent`, `friendlyName`) VALUES (1, 'Florida', 0, 'Florida'), (2, 'Boca Raton', 1, 'Boca Raton'), (3, 'Boynton Beach', 1, 'Boynton Beach'), (4, 'Bradenton', 1, 'Bradenton'), (5, 'Cape Coral', 1, 'Cape Coral'), (6, 'Deltona', 1, 'Deltona'), If you look at carefully the "idLocationParent" for "Florida" value is "0" so which means it is a top level value. This will be done for 50 states so ability to plug the state name into the mysql statement would be icing on the cake if there is a easy way to do it. Also alphabetical order and auto increment for the idLocation would be great. Here is an example of what i m trying to achieve concatenation is the part i need to figure out. for city in cities: print (1, 'city', 0, 'city'), city

Read the article

SELECT SUM PHP MySQL problem

- by user345426

This is driving me nuts! Below you will find my PHP/MySQL code but I will post the direct mySQL statement here: SELECT SUM( ot.value ) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP( o.date_purchased ) >=1262332800 AND UNIX_TIMESTAMP( o.date_purchased ) <=1264924800 AND o.sales_rep_id = '2' When I execute this statement inside of phpMyAdmin I get the sum for ot.value which is associated to "msa". Although, when I run my php code it does not return a value. Anyone see the problem? // works in phpMyAdmin but not displaying during PHP execution! $monthly_sales_amount_sql = "SELECT SUM(ot.value) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP(o.date_purchased) >= $start_timestamp AND UNIX_TIMESTAMP(o.date_purchased) <= $end_timestamp AND o.sales_rep_id = '" . $sales_rep_id "'"; $result = mysql_query($monthly_sales_amount_sql); $row = mysql_fetch_assoc($result); echo "MSA: " . $row['msa'] . "<BR><BR>";

Read the article

Heroku: Postgres type operator error after migrating DB from MySQL

- by sevennineteen

This is a follow-up to a question I'd asked earlier which phrased this as more of a programming problem than a database problem. http://stackoverflow.com/questions/2935985/postgres-error-with-sinatra-haml-datamapper-on-heroku I believe the problem has been isolated to the storage of the ID column in Heroku's Postgres database after running db:push. In short, my app runs properly on my original MySQL database, but throws Postgres errors on Heroku when executing any query on the ID column, which seems to have been stored in Postgres as TEXT even though it is stored as INT in MySQL. My question is why the ID column is being created as INT in Postgres on the data transfer to Heroku, and whether there's any way for me to prevent this. Here's the output from a heroku console session which demonstrates the issue: Ruby console for myapp.heroku.com >> Post.first.title => "Welcome to First!" >> Post.first.title.class => String >> Post.first.id => 1 >> Post.first.id.class => Fixnum >> Post[1] PostgresError: ERROR: operator does not exist: text = integer LINE 1: ...", "title", "created_at" FROM "posts" WHERE ("id" = 1) ORDER... ^ HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. Query: SELECT "id", "name", "email", "url", "title", "created_at" FROM "posts" WHERE ("id" = 1) ORDER BY "id" LIMIT 1 Thanks!

Read the article

displaying search results of more than one word

- by fusion

in my search form, if the user types 'good', it displays all the results which contain the keyword 'good'. however if the user types in 'good sweetest', it displays no results because there is no record with the two words appearing together; BUT appearing in an entry at different places. for example, the record says: A good action is an ever-remaining store and a pure yield the user types in 'good', it will show up this record, but if the user types in 'good' + 'pure', it will not show anything. or if the record contains the keyword 'good-deeds' and if the user types in 'good deeds' without the hyphen, it will not show anything. what i would like is that if the user types in 'good' + 'pure' or 'good deeds' it should records containing these keywords highlighting them. search.php code: $search_result = ""; $search_result = $_POST["q"]; $search_result = trim($search_result); //Check if the string is empty if ($search_result == "") { echo "<p class='error'>Search Error. Please Enter Your Search Query.</p>" ; exit(); } if ($search_result == "%" || $search_result == "_" || $search_result == "+" ) { echo "<p class='error1'>Search Error. Please Enter a Valid Search Query.</p>" ; exit(); } $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . mysql_real_escape_string($search_result) .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } function highlightWords($string, $word) { $string = preg_replace("/".preg_quote($word, "/")."/i", "<span class='highlight'>$0</span>", $string); /*** return the highlighted string ***/ return $string; } ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:18px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> search.html: <form name="myform" class="wrapper"> <input type="text" name="q" onkeyup="showUser()" class="txt_search"/> <input type="button" name="button" onclick="showUser()" class="button"/> <p> <div id="txtHint"></div> </form>

Read the article

displaying search results with two or more queries

- by fusion

in my search form, if the user types 'good', it displays all the results which contain the keyword 'good'. however if the user types in 'good sweetest', it displays no results because there is no record with the two words appearing together; BUT appearing in an entry at different places. for example, the record says: A good action is an ever-remaining store and a pure yield the user types in 'good', it will show up this record, but if the user types in 'good' + 'pure', it will not show anything. what i would like is that if the user types in 'good' + 'pure' it should records containing these keywords highlighting them. search.php code: $search_result = ""; $search_result = $_POST["q"]; $search_result = trim($search_result); //Check if the string is empty if ($search_result == "") { echo "<p class='error'>Search Error. Please Enter Your Search Query.</p>" ; exit(); } if ($search_result == "%" || $search_result == "_" || $search_result == "+" ) { echo "<p class='error1'>Search Error. Please Enter a Valid Search Query.</p>" ; exit(); } $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . mysql_real_escape_string($search_result) .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } function highlightWords($string, $word) { $string = preg_replace("/".preg_quote($word, "/")."/i", "<span class='highlight'>$0</span>", $string); /*** return the highlighted string ***/ return $string; } ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:18px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> search.html: <form name="myform" class="wrapper"> <input type="text" name="q" onkeyup="showUser()" class="txt_search"/> <input type="button" name="button" onclick="showUser()" class="button"/> <p> <div id="txtHint"></div> </form>

Read the article

inserts 'Array' into mysql table

- by Noah Smith

i want to insert an array into a mysql table. The array is produced by script scanning all the links, converting into absolute links and then displaying them in an array. i decided to mysql_query the array into the table but now i am stuck. it only posts 'Array', instead of every row from the array into a different row. Any ideas??! <?php require_once('simplehtmldom_1_5/simple_html_dom.php'); require_once('url_to_absolute/url_to_absolute.php'); $connect = mysql_connect("xxxx", "xxxx", "xxx") or die('Couldn\'t connect to MySQL Server: ' . mysql_error()); mysql_select_db("xxxx", $connect ) or die('Couldn\'t Select the database: ' . mysql_error( $connect )); $links = Array(); $URL = 'http://www.theqlick.com'; // change it for urls to grab // grabs the urls from URL $file = file_get_html($URL); foreach ($file->find('a') as $theelement) { $links[] = url_to_absolute($URL, $theelement->href); } print_r($links); mysql_query("INSERT INTO pages (url) VALUES ('$links[]')"); mysql_close($connect);

Read the article

MySql - JSON data not showing in html

- by Ramzie

I'm trying to create a drop down list from a MySql. The php is successfully fetching the data from the MySql. But my problem is the data is not showing on the drop down list in my HTML page? json_mysql_data2.php header("Content-Type: application/json"); require_once("con.php"); $i=0; $jsonData = array(); foreach ($conn_db->query("SELECT customerID FROM customers WHERE furniture='33' ") as $result){ $i++; $jsonData["article".$i]=$result['customerID']; } echo json_encode($jsonData); myJS.js $(document).ready(function(){ var ddlist = document.getElementById("ddlist"); var hr = new XMLHttpRequest(); hr.open("GET", "json_mysql_data2.php", true); hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); hr.onreadystatechange = function() { if(hr.readyState == 4 && hr.status == 200) { var d = JSON.parse(hr.responseText); for(var o in d){ if(d[o].title){ ddlist.innerHTML += '</option><option value='+d[o].title+'</option>'; } } } } hr.send("null"); ddlist.innerHTML = "Loading Customer ID...."; }); html <script src="myJS.js" type="text/javascript"></script> </head> <body> <div class="dlist"> Customer ID: <select id='EmpLst' name="dwlist" onchange='document.getElementById("val1").value = this.value;'><option value="">SELECT STUDENT ID</option> <div id="ddlist"></div> </select> </div>

Read the article

Ruby on Rail using MYSQL database

- by Joseph Misiti

Hey guys, New to rails, trying to figure out something simple. Seems as though I cannot migrate a very simple mysql database using "rake db:migrate" command. Here is the issue: I know rails defaults to sqllite right now, but I need to use mysql for a series of reasons. Use the following commands rails -d mysql MyMoviesSQL cd MyMoviesSQL script/generate scaffold Movies title:string rating:integer rake db:migrate never get past here because i see the following error: in /Users/user/websites/MyMovieSQL) rake aborted! NoMethodError: undefined method `ord' for 0:Fixnum: SET NAMES 'utf8' (See full trace by running task with --trace) using trace XXXXX-macbook-pro:MyMovieSQL user$ rake db:migrate --trace (in /Users/user/websites/MyMovieSQL) ** Invoke db:migrate (first_time) ** Invoke environment (first_time) ** Execute environment ** Execute db:migrate rake aborted! NoMethodError: undefined method ord' for 0:Fixnum: SET NAMES 'utf8' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract_adapter.rb:219:inlog' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:323:in execute' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:599:inconfigure_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:594:in connect' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:203:ininitialize' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:75:in new' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:75:inmysql_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:223:in send' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:223:innew_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:245:in checkout_new_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:188:incheckout' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:184:in loop' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:184:incheckout' /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/monitor.rb:242:in synchronize' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:183:incheckout' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:98:in connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:326:inretrieve_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_specification.rb:123:in retrieve_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_specification.rb:115:inconnection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:435:in initialize' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:400:innew' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:400:in up' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:383:inmigrate' /Library/Ruby/Gems/1.8/gems/rails-2.3.5/lib/tasks/databases.rake:116 /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in call' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:inexecute' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in each' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:inexecute' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:597:in invoke_with_call_chain' /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/monitor.rb:242:insynchronize' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:590:in invoke_with_call_chain' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:583:ininvoke' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2051:in invoke_task' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:intop_level' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in each' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:intop_level' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in standard_exception_handling' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2023:intop_level' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2001:in run' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:instandard_exception_handling' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:1998:in run' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/bin/rake:31 /usr/bin/rake:19:inload' /usr/bin/rake:19 no clue what is going on, if they want me to add a patch because the methods does not exist, please tell me which file to add it to, and also, how in the future do i figure out which file I need to patch (I see it looks like its a method in FixNum class) here is a patch to a problem that looks similar, but its a different version of ruby http://www.mail-archive.com/[email protected]/msg00250.html versions rails 2.3.5 ruby 1.8.6 gem list yeilds: * LOCAL GEMS * actionmailer (2.3.5, 1.3.6) actionpack (2.3.5, 1.13.6) actionwebservice (1.2.6) activerecord (2.3.5, 1.15.6) activeresource (2.3.5) activesupport (2.3.5, 1.4.4) acts_as_ferret (0.4.1) capistrano (2.0.0) cgi_multipart_eof_fix (2.5.0) daemons (1.0.9) dbi (0.4.3) deprecated (2.0.1) dnssd (0.6.0) fastthread (1.0.1) fcgi (0.8.7) ferret (0.11.4) gem_plugin (0.2.3) highline (1.2.9) hpricot (0.6) libxml-ruby (0.9.5, 0.3.8.4) mongrel (1.1.4) needle (1.3.0) net-sftp (1.1.0) net-ssh (1.1.2) rack (1.0.1) rails (2.3.5) rake (0.8.7, 0.7.3) RedCloth (3.0.4) ruby-openid (1.1.4) ruby-yadis (0.3.4) rubygems-update (1.3.6) rubynode (0.1.3) sqlite3-ruby (1.2.1) termios (0.9.4) thanks in advanced

Read the article

How to group data in PHP inside the while loop

- by christian

I query in a database and loop the result using while and heres the sample data retrieve: echo $db->f("FirstName")."===".$db->f("Question")."=".$db->f("Answer")."<br>"; Michael===Q2=allergy Michael===Q2=Hives Michael===Q6=A lot Michael===Q8_A=Daktacort Michael===Q1=Itch Michael===Q5=Smoke Michael===Q8_A=Diprogenta Christian===Q1=Stuffy Christian===Q6=A lot Christian===Q1=Clear Christian===Q5=Pollen How can I group them according to name and to their Q value? I want something like this result: Name Q1 Q2 ..... so on and so fort. Michael Itch Hives, Allergy Christian Stuffy

Read the article

Counting and joining two tables

- by Eikern

Read the article

SQL..Sum two rows

- by Cha

Sample data: LOCATION NAME LABEL1 LABEL2 SERVICE TIME NY Andrew A B HOUSE 2555 NY Andrew A B CAR 35 NJ Copley C A HOUSE 1025 NY Copley A B HOUSE 650 VA Dalton D C PET 25 What I want to do ias add another column where in it shows sum(Time) of rows with same data except for the Service.Also, the services that I need are only the sum of car and house.Is this possible? If not can you help me with the right query Sample output I need: LOCATION NAME LABEL1 LABEL2 SERVICE TIME SUM NY Andrew A B HOUSE 2555 **2590** NY Andrew A B CAR 35 NJ Copley C A HOUSE 1025 1025 NY Copley A B HOUSE 650 650

Read the article

Retreive a value inside a stored procedure and use it inside that stored procedure

- by sai

delimiter // CREATE DEFINER=root@localhost PROCEDUREgetData(IN templateName VARCHAR(45),IN templateVersion VARCHAR(45),IN userId VARCHAR(45)) BEGIN set @version = CONCAT("SELECT saveOEMsData_answersVersion FROMsaveOEMsData WHERE saveOEMsData_templateName = '",templateName,"' ANDsaveOEMsData_templateVersion = ",templateVersion," AND saveOEMsData_userId= ",userId); PREPARE s1 from @version; EXECUTE S1; END // delimiter ; I am retreiving saveOEMsData_answersVersion, but I have to use it in an IF loop, as in if the version == 1, then I would use a query, else I would use something else. But I am not able to use the version. Could someone help with this?? I am only able to print but not able to use the version for data manipulation. The procedure works fine but I am unable to proceed to next step which is the if condition. The if condition would have something like the below mentioned. IF(ver == 1) THEN SELECT "1"; END IF;

Read the article

Getting Phing's dbdeploy task to automatically rollback on delta error

- by Gordon

I am using Phing's dbdeploy task to manage my database schema. This is working fine, as long as there is no errors in the queries of my delta files. However, if there is an error, dbdeploy will just run the delta files up to the query with the error and then abort. This causes me some frustration, because I have to manually rollback the entry in the changelog table then. If I don't, dbdeploy will assume the migration was successful on a subsequent try. So the question is, is there any way to get dbdeploy use transactions or can you suggest any other way to have phing rollback automatically when an error occurs? Note: I'm not that proficient with Phing, so if this involves writing a custom task, any example code or a url with further information is highly appreciated. Thanks

Read the article

Removing non-alphanumeric characters in an Access Field.

- by Jacques Tardie

I need to remove hyphens from a string in a large number of access fields. What's the best way to go about doing this? Currently, the entries are follow this general format: 2010-54-1 2010-56-1 etc. I'm trying to run append queries off of this field, but I'm always getting validation errors causing the query to fail. I think the cause of this failure is the hypens in the entries, which is why I need to remove them. I've googled, and I see that there are a number of formatting guides using vbscript, but I'm not sure how I can integrate vb into Access. It's new to me :) Thanks in advance, Jacques

Read the article

Persistance JDO - How to query a property of a collection with JDOQL?

- by Sergio del Amo

I want to build an application where a user identified by an email address can have several application accounts. Each account can have one o more users. I am trying to use the JDO Storage capabilities with Google App Engine Java. Here is my attempt: @PersistenceCapable @Inheritance(strategy = InheritanceStrategy.NEW_TABLE) public class AppAccount { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Long id; @Persistent private String companyName; @Persistent List<Invoices> invoices = new ArrayList<Invoices>(); @Persistent List<AppUser> users = new ArrayList<AppUser>(); // Getter Setters and Other Fields } @PersistenceCapable @EmbeddedOnly public class AppUser { @Persistent private String username; @Persistent private String firstName; @Persistent private String lastName; // Getter Setters and Other Fields } When a user logs in, I want to check how many accounts does he belongs to. If he belongs to more than one he will be presented with a dashboard where he can click which account he wants to load. This is my code to retrieve a list of app accounts where he is registered. public static List<AppAccount> getUserAppAccounts(String username) { PersistenceManager pm = JdoUtil.getPm(); Query q = pm.newQuery(AppAccount.class); q.setFilter("users.username == usernameParam"); q.declareParameters("String usernameParam"); return (List<AppAccount>) q.execute(username); } But I get the next error: SELECT FROM invoices.server.AppAccount WHERE users.username == usernameParam PARAMETERS String usernameParam: Encountered a variable expression that isn't part of a join. Maybe you're referencing a non-existent field of an embedded class. org.datanucleus.store.appengine.FatalNucleusUserException: SELECT FROM com.softamo.pelicamo.invoices.server.AppAccount WHERE users.username == usernameParam PARAMETERS String usernameParam: Encountered a variable expression that isn't part of a join. Maybe you're referencing a non-existent field of an embedded class. at org.datanucleus.store.appengine.query.DatastoreQuery.getJoinClassMetaData(DatastoreQuery.java:1154) at org.datanucleus.store.appengine.query.DatastoreQuery.addLeftPrimaryExpression(DatastoreQuery.java:1066) at org.datanucleus.store.appengine.query.DatastoreQuery.addExpression(DatastoreQuery.java:846) at org.datanucleus.store.appengine.query.DatastoreQuery.addFilters(DatastoreQuery.java:807) at org.datanucleus.store.appengine.query.DatastoreQuery.performExecute(DatastoreQuery.java:226) at org.datanucleus.store.appengine.query.JDOQLQuery.performExecute(JDOQLQuery.java:85) at org.datanucleus.store.query.Query.executeQuery(Query.java:1489) at org.datanucleus.store.query.Query.executeWithArray(Query.java:1371) at org.datanucleus.jdo.JDOQuery.execute(JDOQuery.java:243) at com.softamo.pelicamo.invoices.server.Store.getUserAppAccounts(Store.java:82) at com.softamo.pelicamo.invoices.test.server.StoreTest.testgetUserAppAccounts(StoreTest.java:39) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:76) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50) at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193) at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52) at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191) at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42) at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184) at org.junit.runners.ParentRunner.run(ParentRunner.java:236) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:46) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) Any idea? I am getting JDO persistance totally wrong?

Read the article

SQL Join to only the maximum row puzzle

- by Billy ONeal

Given the following example data: Users +--------------------------------------------------+ | ID | First Name | Last Name | Network Identifier | +--------------------------------------------------+ | 1 | Billy | O'Neal | bro4 | +----+------------+-----------+--------------------+ | 2 | John | Skeet | jsk1 | +----+------------+-----------+--------------------+ Hardware +----+-------------------+---------------+ | ID | Hardware Name | Serial Number | +----+-------------------+---------------+ | 1 | Latitude E6500 | 5555555 | +----+-------------------+---------------+ | 2 | Latitude E6200 | 2222222 | +----+-------------------+---------------+ HardwareAssignments +---------+-------------+-------------+ | User ID | Hardware ID | Assigned On | +---------+-------------+-------------+ | 1 | 1 | April 1 | +---------+-------------+-------------+ | 1 | 2 | April 10 | +---------+-------------+-------------+ | 2 | 2 | April 1 | +---------+-------------+-------------+ | 2 | 1 | April 11 | +---------+-------------+-------------+ I'd like to write a SQL query which would give the following result: +--------------------+------------+-----------+----------------+---------------+-------------+ | Network Identifier | First Name | Last Name | Hardware Name | Serial Number | Assigned On | +--------------------+------------+-----------+----------------+---------------+-------------+ | bro4 | Billy | O'Neal | Latitude E6200 | 2222222 | April 10 | +--------------------+------------+-----------+----------------+---------------+-------------+ | jsk1 | John | Skeet | Latitude E6500 | 5555555 | April 11 | +--------------------+------------+-----------+----------------+---------------+-------------+ My trouble is that the maximum "Assigned On" date for each user needs to be selected for each individual user and used for the actual join ... Is there a clever way accomplish this in SQL?

Read the article

Specify which row to return on SQLite Group By

- by lozzar

I'm faced with a bit of a difficult problem. I store all the versions of all documents in a single table. Each document has a unique id, and the version is stored as an integer which is incremented everytime there is a new version. I need a query that will only select the latest version of each document from the database. While using GROUP BY works, it appears that it will break if the versions are not inserted in the database in the order of version (ie. it takes the maximum ROWID which will not always be the latest version). Note, that the latest version of each document will most likely be a different number (ie. document A is at version 3, and document B is at version 6). I'm at my wits end, does anybody know how to do this (select all the documents, but only return a single record for each document_id, and that the record returned should have the highest version number)?

Read the article

Update/Increment a single column on multiple rows at once

- by Jordan Feldstein

I'm trying to add rows to a column, keeping the order of the newest column set to one, and all other rows counting up from there. In this case, I add a new row with order=0, then use this query to update all the rows by one. "UPDATE favorits SET order = order+1" However, what happens is that all the rows are updated to the same value. I get a stack of favorites, all with order 6 for example, when it should be one with 1, the next with 2 and so on. How do I update these rows in a way that orders them the way they should be? Thanks, ~Jordan

Read the article

Best practice for storing global data in PHP?

- by user281434

Hi I'm running a web application that allows a user to log in. The user can add/remove content to his/her 'library' which is displayed on a page called "library.php". Instead of querying the database for the contents of the users library everytime they load "library.php", I want to store it globally for PHP when the user logs in, so that the query is only run once. Is there a best practice for doing this? fx. storing their library in an array in a session? Thanks for your time

Read the article

Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAV

- by brz dot net

I have to find the indentid from the status table based on below two conditions: 1. If there are more than one record having same indentid in status table and the same indentID has count1 in feasibilitystatus table then I don't want to display the record. 2. If there is only one record of indentid in status table and the same indentID has count0 in feasibilitystatus table then I don't want to display the record. Query: select distinct s.indentid from status s where s.status='true' and s.indentid not in( select case when count(s.indentid)>1 then (select indentid from feasibilitystatus group by indentid having count(indentid)>1) else (select indentid from feasibilitystatus group by indentid having count(indentid)>0) end as indentid from status) Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

Search Results

Search found 27396 results on 1096 pages for 'mysql query'.

Page 429/1096 | < Previous Page | 425 426 427 428 429 430 431 432 433 434 435 436 | Next Page >

- by stormdrain

- by John

- by Philip Eve

- by jmituzas

- by user552974

- by user345426

- by sevennineteen

- by fusion

- by fusion

- by Noah Smith

- by Ramzie

- by jeansymolanza

- by Joseph Misiti

- by christian

- by Eikern

- by Cha

- by sai

- by Gordon

- by Jacques Tardie

- by Sergio del Amo

- by Billy ONeal

- by lozzar

- by Jordan Feldstein

- by user281434

- by brz dot net

< Previous Page | 425 426 427 428 429 430 431 432 433 434 435 436 | Next Page >