Search Results

Search found 1341 results on 54 pages for 'jack allan'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 43/54 | < Previous Page | 39 40 41 42 43 44 45 46 47 48 49 50  | Next Page >

  • javascript replace text with images problem

    - by Amit Malhotra
    I'm extremely new to JS and have this code that I'm trying to tweak. WHen I was adding the array, I had tested it with only a couple of items and it was working fine, now it just doesn't work, and I can't figure out what is wrong with it!! Basically, I'm trying to change every instance of a card type with an image on a webpage Here's the code: window.onload = function(){ var cardname = new Array(); cardname[0] = "Ace of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_a.svg/88px-Ornamental_h_a.svg.png' />"; cardname[1] = "2 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_2.svg/88px-Ornamental_h_2.svg.png' />"; cardname[2] = "3 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_3.svg/88px-Ornamental_h_3.svg.png' />"; cardname[3] = "4 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_4.svg/88px-Ornamental_h_4.svg.png' />"; cardname[4] = "5 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_5.svg/88px-Ornamental_h_5.svg.png' />"; cardname[5] = "6 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_6.svg/88px-Ornamental_h_6.svg.png' />"; cardname[6] = "7 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_7.svg/88px-Ornamental_h_7.svg.png' />"; cardname[7] = "8 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_8.svg/88px-Ornamental_h_8.svg.png' />"; cardname[8] = "9 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_9.svg/88px-Ornamental_h_9.svg.png' />"; cardname[9] = "10 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/9/91/Ornamental_h_10.svg/88px-Ornamental_h_10.svg.png' />"; cardname[10] = "Jack of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_j.svg/88px-Ornamental_h_j.svg.png' />"; cardname[11] = "Queen of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_q.svg/88px-Ornamental_h_q.svg.png' />"; cardname[12] = "King of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_k.svg/88px-Ornamental_h_k.svg.png' />"; cardname[13] = "Ace of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_a.svg/88px-Ornamental_s_a.svg.png' />"; cardname[14] = "2 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_2.svg/88px-Ornamental_s_2.svg.png' />"; cardname[15] = "3 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_3.svg/88px-Ornamental_s_3.svg.png' />"; cardname[16] = "4 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_4.svg/88px-Ornamental_s_4.svg.png' />"; cardname[17] = "5 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_5.svg/88px-Ornamental_s_5.svg.png' />"; cardname[18] = "6 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_6.svg/88px-Ornamental_s_6.svg.png' />"; cardname[19] = "7 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_7.svg/88px-Ornamental_s_7.svg.png' />"; cardname[20] = "8 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_8.svg/88px-Ornamental_s_8.svg.png' />"; cardname[21] = "9 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_9.svg/88px-Ornamental_s_9.svg.png' />"; cardname[22] = "10 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_10.svg/88px-Ornamental_s_10.svg.png' />"; cardname[23] = "Jack of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/78/Ornamental_s_j.svg/88px-Ornamental_s_j.svg.png' />"; cardname[24] = "Queen of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_q.svg/88px-Ornamental_s_q.svg.png' />"; cardname[25] = "King of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_k.svg/88px-Ornamental_s_k.svg.png' />"; cardname[26] = "Ace of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_a.svg/88px-Ornamental_c_a.svg.png' />"; cardname[27] = "2 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_2.svg/88px-Ornamental_c_2.svg.png' />"; cardname[28] = "3 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_3.svg/88px-Ornamental_c_3.svg.png' />"; cardname[29] = "4 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_4.svg/88px-Ornamental_c_4.svg.png' />"; cardname[30] = "5 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_5.svg/88px-Ornamental_c_5.svg.png' />"; cardname[31] = "6 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_6.svg/88px-Ornamental_c_6.svg.png' />"; cardname[32] = "7 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_7.svg/88px-Ornamental_c_7.svg.png' />"; cardname[33] = "8 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_8.svg/88px-Ornamental_c_8.svg.png' />"; cardname[34] = "9 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_9.svg/88px-Ornamental_c_9.svg.png' />"; cardname[35] = "10 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_10.svg/88px-Ornamental_c_10.svg.png' />"; cardname[36] = "Jack of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_j.svg/88px-Ornamental_c_j.svg.png' />"; cardname[37] = "Queen of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_q.svg/88px-Ornamental_c_q.svg.png' />"; cardname[38] = "King of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_k.svg/88px-Ornamental_c_k.svg.png' />"; cardname[39] = "Ace of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_a.svg/88px-Ornamental_d_a.svg.png' />"; cardname[40] = "2 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_2.svg/88px-Ornamental_d_2.svg.png' />"; cardname[41] = "3 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_3.svg/88px-Ornamental_d_3.svg.png' />"; cardname[42] = "4 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_4.svg/88px-Ornamental_d_4.svg.png' />"; cardname[43] = "5 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_5.svg/88px-Ornamental_d_5.svg.png' />"; cardname[44] = "6 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_6.svg/88px-Ornamental_d_6.svg.png' />"; cardname[45] = "7 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_7.svg/88px-Ornamental_d_7.svg.png' />"; cardname[46] = "8 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_8.svg/88px-Ornamental_d_8.svg.png' />"; cardname[47] = "9 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_9.svg/88px-Ornamental_d_9.svg.png' />"; cardname[48] = "10 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_10.svg/88px-Ornamental_d_10.svg.png' />"; cardname[49] = "Jack of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_j.svg/88px-Ornamental_d_j.svg.png' />"; cardname[50] = "Queen of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_q.svg/88px-Ornamental_d_q.svg.png' />"; cardname[51] = "King of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_k.svg/88px-Ornamental_d_k.svg.png' />"; var j, k, findit, part, page, repl; var page = document.body.innerHTML; for(var i=0; i<cardname.length; i++){ part = cardname[i].split("^"); findit = part[0]; repl = part[1]; while (page.indexOf(findit) >=0){ var j = page.indexOf(findit); var k = findit.length; page = page.substr(0,j) + repl + page.substr(j+k); } } document.body.innerHTML = page; } any help would be appreciated to figure out why this code is not working!

    Read the article

  • Delete duplicate records from a SQL table without a primary key

    - by Shyju
    I have the below table with the below records in it create table employee ( EmpId number, EmpName varchar2(10), EmpSSN varchar2(11) ); insert into employee values(1, 'Jack', '555-55-5555'); insert into employee values (2, 'Joe', '555-56-5555'); insert into employee values (3, 'Fred', '555-57-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); insert into employee values (1, 'Jack', '555-55-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6 ,'Lisa', '555-70-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); I dont have any primary key in this table .But i have the above records in my table already. I want to remove the duplicate records which has the same value in EmpId and EmpSSN fields. Ex : Emp id 5 Can any one help me to frame a query to delete those duplicate records Thanks in advance

    Read the article

  • Aggregate survey results recursively by manager

    - by Ian Roke
    I have a StaffLookup table which looks like this. UserSrn | UserName | ManagerSrn =============================== ABC1 | Jerome | NULL ABC2 | Joe | ABC1 ABC3 | Paul | ABC2 ABC4 | Jack | ABC3 ABC5 | Daniel | ABC3 ABC6 | David | ABC2 ABC7 | Ian | ABC6 ABC8 | Helen | ABC6 The staff structure looks like this. |- Jerome | |- Joe || ||- Paul ||| |||- Jack ||| |||- Daniel || ||- David ||| |||- Ian ||| |||- Helen I have a list of SurveyResponses that looks like this. UserSrn | QuestionId | ResponseScore ==================================== ABC2 | 1 | 5 ABC2 | 3 | 4 ABC4 | 16 | 3 ... What I am trying to do sounds pretty simple but I am struggling to find a neat, quick way of doing it. I want to create a sproc that takes an Srn and returns back all the staff under that Srn in the structure. If there is a score for QuestionId of 16 then that indicates a completed survey. I would like to return a line for the Srn entered (The top manager) with a count of completed surveys for the direct reports under that manager. Under that I would like each manager under the original manager with a count of completed surveys for each of their direct reports and so on. I would like to see the data as such below when I set the top manager to be Joe (ABC2). UserName | Completed | Total ============================ Joe | 2 | 2 Paul | 1 | 2 David | 0 | 2 TOTAL | 3 | 6

    Read the article

  • Why does the following Toggle function perform four different operations instead of two?

    - by marcamillion
    You can see the implementation here: http://jsfiddle.net/BMWZd/8/ What I am trying to do, when you click on 'John Brown', you see the first element at top turn black. When you click it again, the border of the dotted circle disappears, then when you click 'John Brown' again, you see something else, then finally once again it all disappears. What I am trying to achieve is when you click it once, everything turns black (like it does now), then you click it again, everything disappears and goes back to the original state. Important distinction, what I mean is...when one of the names in the box are not clicked. So if you clicked John Brown then moved to Jack Dorsey, the #1 at top should stay black. But if you were to click Jack Dorsey again, i.e. you 'unclicked' it, then it should disappear. Also, how do I tighten it up, so that it responds quicker. Now when you click it, it feels like there is a little bit of a lag between when it was clicked and when it responds. Edit1: If anyone is interested...the UI that this will be used in is for my webapp - http://www.compversions.com

    Read the article

  • Is it bad practice to make a setter return "this"?

    - by Ken Liu
    Is it a good or bad idea to make setters in java return "this"? public Employee setName(String name){ this.name = name; return this; } This pattern can be useful because then you can chain setters like this: list.add(new Employee().setName("Jack Sparrow").setId(1).setFoo("bacon!")); instead of this: Employee e = new Employee(); e.setName("Jack Sparrow"); ...and so on... list.add(e); ...but it sort of goes against standard convention. I suppose it might be worthwhile just because it can make that setter do something else useful. I've seen this pattern used some places (e.g. JMock, JPA), but it seems uncommon, and only generally used for very well defined APIs where this pattern is used everywhere. Update: What I've described is obviously valid, but what I am really looking for is some thoughts on whether this is generally acceptable, and if there are any pitfalls or related best practices. I know about the Builder pattern but it is a little more involved then what I am describing - as Josh Bloch describes it there is an associated static Builder class for object creation.

    Read the article

  • Flash CS4 [AS3]: Playing Card Deck Array

    - by Ben
    I am looking to make a card game in Flash CS4 using AS3 and I am stuck on the very first step. I have created graphics for a standard 52 card deck of playing cards and imported them into the library in Flash and then proceeded to convert them all to Movie Clips. I have also used the linkage to make them available in the code. The movie clips and the linkage are named in sequence, as in the Ace of Clubs would be C1, two of Diamonds is called D2, Jack of Spades is S11. (C = Clubs, D = Diamonds, S = Spades, H = Hearts and numbers 1 through 13 are the card values. 1 being Ace, 11 being Jack, 12 being Queen, 13 being King). As far as I know my next step would be to arrange the cards into an array. This is the part that I am having problems with. Can someone please point me in the right direction, what would be the best way to do this. Could you provide me with a bit of sample code as well? I have had a look at few tutorials online but they are all telling me different things, some are incomplete and the rest...well...they're just cr*ppy. Thanks in advance! Ben

    Read the article

  • iPodMusicPlayer playbackState inaccurate after odd conditions

    - by Shane Costello
    I have a simple music player app that runs into a really weird problem. First of all, while playing music and in the locked state, I allow the user to double click the Home button and use the locked iPod music controls. I did notice however that while in the locked state, my app doesn't receive any of its registered notifications. For the most part, this is fine anyway. But, if the user is playing music for at least 15 minutes (I'm not sure why but any less and this problem doesn't occur) while in the locked state, and using some kind of headphone or aux jack, then unplugs the headphone/aux jack while the device is still playing music, the iPodMusicPlayer will auto-pause. Which is exactly what I would want it to do, but after this happens, when the user unlocks their device and gives focus to the app again, the iPodMusicPlayer's playbackState is inaccurate. - (IBAction)playPause:(id)sender { if ([musicPlayer playbackState] == MPMusicPlaybackStatePlaying) { [musicPlayer pause]; } else { [musicPlayer play]; } } where musicPlayer = [MPMusicPlayerController iPodMusicPlayer]. Under normal circumstances, this runs perfectly fine. But after these conditions, my breakpoint will hit the condition for MPMusicPlaybackStatePlaying while the music is paused, and vice versa. The only way I've been able to fix this is to either make a new selection of music or to terminate the app and reopen. I've tried tons of a workarounds to fix this problem programmatically, but nothing turns out a 100% bug free fix. Does anyone have any clue as to why this happens in the first place?

    Read the article

  • NVelocity (or Velocity) as a stand-alone formula evaluator

    - by dana
    I am using NVelocity in my application to generate html emails. My application has an event-driven model, where saving and/or updating of objects causes these emails to be sent out. Each event can trigger zero, one or multiple multiple emails. I want to be able to configure which emails get sent out at run-time without having to modify code. I was thinking I could leverage the NVelocity #if() directive to do this. Here is my idea... Step 1) Prior to email sending, the administrator must configure a formula for NVelocity to evaluate. For example: $User.FirstName == "Jack" Step 2) When an object is saved or created, build an NVelocity template in memory based on the input formula. For example: String formula = GetFormulaFromDB(); // $User.FirstName == "Jack" String templ = "#if( " + formula + ") 1 #else 0 #end"; Step 3) Execute the NVelocity engine in memory against the template. Check the results to see if we have to send the email: String result = VelocityMerge(templ); // utility function if( result.Trim() == "1" ) { SendEmail(); } I know this is not exactly what NVelocity was intended to do, but I think it just might work :) One of the benefits of doing things this way is that the same syntax can be used for the formula as is used inside the template. Does anybody have any words of caution or suggestions? Is there a way to execute the #if() directive without jumping through hoops like I have above? Is there a recommended way to validate the formula syntax ahead of time? Thanks.

    Read the article

  • Why are my bound parameters all identical (using Linq)?

    - by Scott Stafford
    When I run this snippet of code: string[] words = new string[] { "foo", "bar" }; var results = from row in Assets select row; foreach (string word in words) { results = results.Where(row => row.Name.Contains(word)); } I get this SQL: -- Region Parameters DECLARE @p0 VarChar(5) = '%bar%' DECLARE @p1 VarChar(5) = '%bar%' -- EndRegion SELECT ... FROM [Assets] AS [t0] WHERE ([t0].[Name] LIKE @p0) AND ([t0].[Name] LIKE @p1) Note that @p0 and @p1 are both bar, when I wanted them to be foo and bar. I guess Linq is somehow binding a reference to the variable word rather than a reference to the string currently referenced by word? What is the best way to avoid this problem? (Also, if you have any suggestions for a better title for this question, please put it in the comments.) Note that I tried this with regular Linq also, with the same results (you can paste this right into Linqpad): string[] words = new string[] { "f", "a" }; string[] dictionary = new string[] { "foo", "bar", "jack", "splat" }; var results = from row in dictionary select row; foreach (string word in words) { results = results.Where(row => row.Contains(word)); } results.Dump(); Dumps: bar jack splat

    Read the article

  • Speaking at UK DevConnections in www.DevConnections.com/uk and discount codes

    - by Testas
     HiI will be speaking at the UK DevConnections on Analysis Services at the ExCeL conference centre in London on 13th-15th June 2011. Join top SQL Server names such as Paul Randall, Kimberley Tripp, Simon Sabin and Allan Mitchell ( to name a few), at the IT & DevConnections powered by Microsoft UK  in London on 13th-15th June 2011. With UK DevConnections you can combine SQL Sessions with other Microsoft technology stacks. Microsoft and leading independent industry presenters will deliver in-depth presentations and cutting edge sessions on  SharePoint Windows Exchange and Unified Communications SQL Server Silverlight ASP.Net Virtualisation Cloud and Azure As a speaker I have a discount code that entitles give 20% off the cost to register for IT&DEvConnections in June.  The code is sql-bits, if people register before the 31st March when the Super Early Bird offer ends you will only pay £639.20 +vat (normal price £999)Furthermore, there are preferential hotel rates for this event at: https://logicalvenues.vbookings.co.uk/b/pentonlondon0611/  So if you want to attend a conference with a wide spectrum of technologies, then DevConnections may be up your street Thanks  Chris

    Read the article

  • ArchBeat Link-o-Rama Top 20 for June 17-23, 2012

    - by Bob Rhubart
    The most popular item shared via my social networks for the week of June 17-23, 2012. Simple Made Easy | Rich Hickey InfoQ: Current Trends in Enterprise Mobility Cloud Bursting between AWS and Rackspace | High Scalability A Distributed Access Control Architecture for Cloud Computing Congrats to @MNEMONIC01 on his new book: Oracle WebLogic Server 12c: First Look BI Architecture Master Class for Partners - Oracle Architecture Unplugged Guide to integration architecture | Stephanie Mann Oracle Data Integrator 11g - Faster Files | David Allan Recap: EMEA User Group Leaders Meeting Latvia May 2012 Starting a cluster | Mark Nelson SOA, Cloud & Service Technology Symposium 2012 London - Special Oracle Discount Enterprise 2.0 Conference: Building Social Business | Oracle WebCenter Blog FY13 Oracle PartnerNetworkr Kickoff - Tues June 26, 2012 | @oraclepartners Why should you choose Oracle WebLogic 12c instead of JBoss EAP 6? | Ricardo Ferreira Call for Nominations: Oracle Fusion Middleware Innovation Awards 2012 - Win a free pass to #OOW12 Hibernate4 and Coherence | Rene van Wijk Eclipse and Oracle Fusion Development - Free Virtual Event, July 10th Why building SaaS well means giving up your servers | GigaOM Personas - what, why & how | Mascha van Oosterhout Oracle Public Cloud Architecture | Tyler Jewell Thought for the Day "There is only one thing more painful than learning from experience and that is not learning from experience." — Archibald McLeish (May 7, 1892 – April 20, 1982) Source: SoftwareQuotes.com

    Read the article

  • Best way to connect a desktop computer to a 3g network

    - by dbyrne
    A friend of mine is moving to a building with no Internet connectivity. Ethernet and wifi are out of the question. What is the best way for him to get his desktop connected? The most obvious solution is for him to get an unlimited 3G data plan. What is the best way for him to set this up? I am assuming he should get something like Verizon's MiFi 3G access point, but does this have an ethernet jack?

    Read the article

  • iphone dictionary autocorrect [closed]

    - by Raj More
    I have the iPhone 3G with OS 3.1 3.0.1 on it. Every time I type a text message that includes the word "me", it gets auto corrected to "mr". So my friends get a text that says "call mr when you get done" or "jack told mr about it yesterday" how do i change this autocorrect so it stops changing my "me" to a "mr"?

    Read the article

  • rs232 PTZ cameras software program for control

    - by Noel
    Does anyone know of a program that would allow you to control multiple IR cameras via usb (computer jack) to rs232 (camera hardware)? We have a cameraswitcher, very low key, that I can press buttons and it willswitch the view of the camera from one to the next. currently I control the cameras by sellecting the cameras via a remote control for change of angles. Does anyone know anything that could give me some ability to do manual controls via my computer?. Please Advise, thanks!

    Read the article

  • Optical SPDIF audio from motherboard not working with receiver

    - by simon b
    Hi, I hope someone can help; I can't get my SPDIF optical out working through my receiver and all the responses I can see on the web assume you have a sound card, while I settled for the (seemingly high end) sound on my motherboard (Asus P7P55D-E PRO), which appears to limit some of my options. My set-up is a "new out of the box" one and is: *Windows 7 PC (using PowerDVD10 for DVDs/Blurays and Windows media player for music) *Asus P7P55D-E PRO motherboard - has 8-channel audio TRS jacks and SPDIF optical and coaxial out *An old Yamaha receiver, whose only multi-channel input options are optical in and 6 channel RCA in. However, it still can handle DTS and DD *Boston Acoustic Soundware XS 5.1 speakers I've currently got the SPDIF optical out from the motherboard connected to the in on my receiver, have SPDIF enabled in the sound menu and the light is glowing red down the fibre. But I'm getting no sound at all. What I want is to be able to play DVDs/BluRays in 5.1 but also to be able to play music in multi-channel mode (even though I know this will be "fake" multichannel; it's more about where I sit in the room and my requirement to use the sub because the Boston is a satellite/sub set-up) My questions are: *Will optical work at all for multi-channel? THe latest posts I can see suggest it does but some people seem to say optical only outputs stereo. Whom to believe? *Even if it does work, I've read that I have to disable AC-3 decoding, or make various other changes, which don't seem to be possible without the menu options that a sound-card brings. Is the motherboard-only option just too inflexible? *Although my SPDIF device is enabled in the sound menu, it insists under "Jack information" that it is a "rear panel RCA jack", when of course it is not (both TOSLINK and rCA jacks do exist). Has the PC just forgotten that it has an optical? *I think I could relatively easily connect the 8-channel 3.5mm TRS jacks to my receiver 6-ch input jacks by way of TRS/RCA cables, but would that not stop me from being able to play music from media-player in multi-channel mode, as I'm not sure the motherboard can cope *Or do I need to bite the bullet and buy a sound-card? And if so, how can I be sure the one I get doesn't have the same problem? Any thoughts gratefully received, Cheers, simon

    Read the article

  • Good Audio Splitter

    - by Jeremy White
    I need to get audio from my computer's headphone jack and push the output to 2 sets of speakers. I have tried using a cheap splitter from Fry's, but one set of speakers ends up acting as a microphone (!?) for the other set of speakers. What's the best way to split headphone output and get best quality with no interference on each set of speakers? I would, of course, also be interested in why the cheap splitter causes one set of speakers to start acting as a microphone.

    Read the article

  • Looking for a fiber optic "switch" or "router" for home use

    - by Shrout1
    The gist of my question: What is a "fiber optic" switch called? I.E. a layer 2 ethernet switch that uses fiber TX and RX connections and sends layer 2 network traffic between the fiber strands that are connected. Can someone purchase a dedicated fiber switch that does not have copper ethernet ports? What is the current average price of a device like this? Not necessarily looking for product endorsements, just information Might not make sense to go this route if it is too cost prohibitive What type of fiber connector is used for terminating a fiber strand into a jack on the wall? Can fiber be "patched" using two jacks and a "patch" cable? Is signal loss a concern with the longest runs at 100-200ft, a patch cable and media converters? The full story: My parents had unterminated fiber optic cable and terminated Cat5e run throughout their home when it was built in 2004. 10 years later the Cat5e isn't providing the throughput that my father needs to accomplish multiple streams of HD and fast system backups throughout the house. He can't reach gigabit speeds across the distance of the Cat5e runs. We are both interested in terminating the fiber connections and using them as high speed "backbones" to copper switches in each room of the house. It would be easy to attain gigabit speeds (or better, eventually) using the fiber. I have searched and searched for a "fiber optic switch" or "fiber optic router" and cannot find the correct term to describe this piece of hardware. We can use fiber media converters at the end points of each connection, however it would be nice to have a "patch panel" set up in the network closet in the basement that has fiber connections on it and switches the ethernet streams between the connections/systems in the house. Each fiber media converter costs between $50-$100 a piece... After 10 or so terminated connections it might make sense to find a piece of hardware that does not require media converters. That would depend upon the cost of this hardware Somewhat unrelated, if we are able to route between these fiber strands successfully, what is the physical connector type used in a jack on the wall? Just like RJ45 has a wall outlet (depicted below): What is the fiber optic equivalent of this? In the interim could we "patch" a couple fiber strands together in the network closet? Would signal loss be of concern with a run length of 100-200 feet, a patch cable and two media converters? If that would work then it could be used until the funds are available for more.

    Read the article

  • Windows not remembering default audio device?

    - by Lynda
    I prefer the audio output on my computer to use the standard audio jack output due to volume issues. But I am using a monitor with HDMI. I have chosen to set the default audio device to be "Speakers" But every time I reboot the default audio device is the HDMI Output again. I am running Windows 7 64bit. Why does it not remember the default device? (I do shutdown and boot up properly without errors.)

    Read the article

  • Cheap hackable portable mp3 player

    - by monov
    I want something that will: play mp3s fit in my pocket have a 3.5mm audio jack let me write software for it cost $50 max I guess a cheap mobile phone could satisfy that too. Don't care much for brand names. Any ideas?

    Read the article

  • Best way to connect a desktop computer to a 3g network

    - by dbyrne
    A friend of mine is moving to a building with no Internet connectivity. Ethernet and wifi are out of the question. What is the best way for him to get his desktop connected? The most obvious solution is for him to get an unlimited 3G data plan. What is the best way for him to set this up? I am assuming he should get something like Verizon's MiFi 3G access point, but does this have an ethernet jack?

    Read the article

  • Free alternative to Audio Hijack Pro?

    - by Tim Visher
    I'd like to record what I hear coming out of the main audio jack on my Mac. Nothing fancier than that. I'm aware of Audio Hijack Pro but that really does much more than I'm looking for and comes with a steep price tag. If it's the only tool that can do the job that's fine but I was hoping to find something that simply captured all audio coming from the computer and dumped it to a file. Thanks in advance!

    Read the article

  • Can I use an Apple AirPort Express as a wireless-to-wired bridge?

    - by Chris
    I have a wireless network using an Apple AirPort Extreme. That device is set up in my office and hooked up to the cable modem. I have a TV in another room which can accept a wired internet connection (not wireless enabled). Can I use an Apple AirPort Express's ethernet jack to create a wireless-to-wired bridge? If not, what device would I use to do the same thing?

    Read the article

  • Free alternative to Audio Hijack Pro?

    - by Tim Visher
    I'd like to record what I hear coming out of the main audio jack on my Mac. Nothing fancier than that. I'm aware of Audio Hijack Pro but that really does much more than I'm looking for and comes with a steep price tag. If it's the only tool that can do the job that's fine but I was hoping to find something that simply captured all audio coming from the computer and dumped it to a file. Any suggestions?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 39 40 41 42 43 44 45 46 47 48 49 50  | Next Page >