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  • Web page database query optimization

    - by morpheous
    I am putting together a web page which is quite 'expensive' in terms of database hits. I don't want to start optimizing at this stage - though with me trying to hit a deadline, I may end up not optimizing at all. Currently the page requires 18 (that's right eighteen) hits to the db. I am already using joins, and some of the queries are UNIONed to minimize the trips to the db. My local dev machine can handle this (page is not slow) however, I feel if I release this into the wild, the number of queries will quickly overwhelm my database (MySQL). I could always use memcache or something similar, but I would much rather continue with my other dev work that needs to be completed before the deadline - at least retrieving the page works - its simply a matter of optimization now (if required). My question therefore is - is 18 db queries for a single page retrieval completely outrageous - (i.e. I should put everything on hold and optimize the hell of the retrieval logic), or shall I continue as normal, meet the deadline and release on schedule and see what happens? [Edit] Just to clarify, I have already done the 'obvious' things like using (single and composite) indexes for fields used in the queries. What I haven't yet done is to run a query analyzer to see if my indexes etc are optimal.

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  • Help with SQL Query

    - by djfrear
    With regards to the following statement: Select * From explorer.booking_record booking_record_ Inner Join explorer.client client_ On booking_record_.labelno = client_.labelno Inner Join explorer.tour_hotel tour_hotel_ On tour_hotel_.tourcode = booking_record_.tourrefcode Inner Join explorer.hotelrecord hotelrecord_ On tour_hotel_.hotelcode = hotelrecord_.hotelref Where booking_record_.bookingdate Not Like '0000-00-00' And booking_record_.tourdeparturedate Not Like '0000-00-00' And hotelrecord_.hotelgroup = "LPL" And Year(booking_record_.tourdeparturedate) Between Year(AddDate(Now(), Interval -5 Year)) And Year(Now()) My MySQL skills are certainly not up to scratch, the actual result set I wish to find is "a customer who has been to 5 or more LPL hotels in the past 5 years". So far I havent got as far as dealing with the count as I'm getting a huge number of results with some 250+ per customer. I assume this is to do with the way I'm joining tables. Schema wise the booking_record table contains a tour reference code, which links to tour_hotel which then contains a hotelcode which links to hotelrecord. This hotelrecord table contains the hotelgroup. The client table is joined to the booking_record via a booking reference and a client may have many bookings. If anyone could suggest a way for me to do this I'd be very grateful and hopefully learn enough to do it myself next time! I've been scratching my head over this one for a few hours now! Customers may have many bookings within booking_record Daniel.

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  • Stored procedure using cursor in mySql.

    - by RAVI
    I wrote a stored procedure using cursor in mysql but that procedure is taking 10 second to fetch the result while that result set have only 450 records so, I want to know that why that proedure is taking that much time to fetch tha record. procedure as below: DELIMITER // DROP PROCEDURE IF EXISTS curdemo123// CREATE PROCEDURE curdemo123(IN Branchcode int,IN vYear int,IN vMonth int) BEGIN DECLARE EndOfData,tempamount INT DEFAULT 0; DECLARE tempagent_code,tempplantype,tempsaledate CHAR(12); DECLARE tempspot_rate DOUBLE; DECLARE var1,totalrow INT DEFAULT 1; DECLARE cur1 CURSOR FOR select SQL_CALC_FOUND_ROWS ad.agentCode,ad.planType,ad.amount,ad.date from adplan_detailstbl ad where ad.branchCode=Branchcode and (ad.date between '2009-12-1' and '2009-12-31')order by ad.NUM_ID asc; DECLARE CONTINUE HANDLER FOR SQLSTATE '02000' SET EndOfData = 1; DROP TEMPORARY TABLE IF EXISTS temptable; CREATE TEMPORARY TABLE temptable (agent_code varchar(15), plan_type char(12),sale double,spot_rate double default '0.0', dATE DATE); OPEN cur1; SET totalrow=FOUND_ROWS(); while var1 <= totalrow DO fetch cur1 into tempagent_code,tempplantype,tempamount,tempsaledate; IF((tempplantype='Unit Plan' OR tempplantype='MIP') OR tempplantype='STUP') then select spotRate into tempspot_rate from spot_amount where ((monthCode=vMonth and year=vYear) and ((agentCode=tempagent_code and branchCode=Branchcode) and (planType=tempplantype))); INSERT INTO temptable VALUES(tempagent_code,tempplantype,tempamount,tempspot_rate,tempsaledate); else INSERT INTO temptable(agent_code,plan_type,sale,dATE) VALUES(tempagent_code,tempplantype,tempamount,tempsaledate); END IF; SET var1=var1+1; END WHILE; CLOSE cur1; select * from temptable; DROP TABLE temptable; END // DELIMITER ;

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  • MySQL query pulling from two tables, display in correct fields

    - by Matt Nathanson
    I'm trying to select all fields in two separate tables as long as they're sharing a common ID. //mysql query $result = mysql_query("SELECT * FROM project, links WHERE project.id = links.id and project.id = $clientID") //displaying the link if ($row['url'] != null){ echo "<div class='clientsection' id='links'>Links</div>"; echo "<a class='clientlink' id='link1' href='" . $row['url'] . "'>" . $row['name'] . "</a>"; } else { echo "<a class='clientlink' id='link1' href='" . $row['url'] . "' style='display:none;'>" . $row['name'] . "</a>"; }; As you can see, my tables are "projects", and "links" Each is sharing a common field "id" for reference. It looks as though where both links.id and project.id are equal, it outputs anything, but when there is no links.id associated with a given $clientID the container relative to the $clientID doesn't display at all. Essentially I'm using this to add links dynamically to a specific client in this CMS and if there are no links, I want the container to show up anyway. Hopefully I've expressed myself clearly, any pointers in the right direction are appreciated. Thanks!

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  • How do I write this MySQL query?

    - by CT
    I am working on an Asset DB using a lamp stack. In this example consider the following 5 tables: asset, server, laptop, desktop, software All tables have a primary key of id, which is a unique asset id. Every object has all asset attributes and then depending on type of asset has additional attributes in the corresponding table. If the type is a server, desktop or laptop it also has items in the software table. Here are the table create statements: // connect to mysql server and database "asset_db" mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); // create asset table mysql_query("CREATE TABLE asset( id VARCHAR(50) PRIMARY KEY, company VARCHAR(50), location VARCHAR(50), purchase_date VARCHAR(50), purchase_order VARCHAR(50), value VARCHAR(50), type VARCHAR(50), notes VARCHAR(200))") or die(mysql_error()); echo "Asset Table Created.</br />"; // create software table mysql_query("CREATE TABLE software( id VARCHAR(50) PRIMARY KEY, software VARCHAR(50), license VARCHAR(50))") or die(mysql_error()); echo "Software Table Created.</br />"; // create laptop table mysql_query("CREATE TABLE laptop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Laptop Table Created.</br />"; // create desktop table mysql_query("CREATE TABLE desktop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Desktop Table Created.</br />"; // create server table mysql_query("CREATE TABLE server( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Server Table Created.</br />"; ?> How do I query the database so that if I search by id, I receive all related fields to that asset id? Thank you.

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  • Adding one subquery makes query a little slower, adding another makes it way slower

    - by Jason Swett
    This is fast: select ba.name, penamt.value penamt, #address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id #join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 And this is fast: select ba.name, #penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id #join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 But this is slow: select ba.name, penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 Why is it fast when I include just one of the two subqueries but slow when I include both? I would think it should be twice as slow when I include both, but it takes a really long time. On on MySQL.

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  • help with mysql triggers (checking values before insert)

    - by user332817
    hi I'm quite new to mysql and I'm trying to figure out how to use triggers. what I'm trying to do: I have 2 tables, max and sub_max, when I insert a new row to sub_max I want to check if the SUM of the values with the same foreign_key as the new row are less than the value in the max table. I think this sounds confusing so here are my tables: CREATE TABLE max( number INT , MaxAmount integer NOT NULL) CREATE TABLE sub_max( sub_number INT , sub_MaxAmount integer NOT NULL, number INT, FOREIGN KEY ( number ) REFERENCES max( number )) and here is my code for the trigger, I know the syntax is off but this is the best I could do from looking up tutorials. CREATE TRIGGER maxallowed after insert on submax FOR EACH ROW BEGIN DECLARE submax integer; DECLARE maxmax integer; submax = select sum(sub_MaxAmount) from sub_max where sub_number = new.sub_number; submax = submax + new. sub_MaxAmount; maxmax = select MaxAmount from max where number = new.number ; if max>maxmax rollback? END I wanted to know if I'm doing this remotely correctly. Thanks in advance.

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  • php and mysql listing databases and looping through results

    - by Jacksta
    Beginner help needed :) I am doign an example form a php book which lists tables in databases. I am getting an error on line 36: $db_list .= "$table_list"; <?php //connect to database $connection = mysql_connect("localhost", "admin_cantsayno", "cantsayno") or die(mysql_error()); //list databases $dbs = @mysql_list_dbs($connection) or die(mysql_error()); //start first bullet list $db_list = "<ul>"; $db_num = 0; //loop through results of functions while ($db_num < mysql_num_rows($dbs)) { //get database names and make each a list point $db_names[$db_num] = mysql_tablename($dbs, $db_num); $db_list .= "<li>$db_names[$db_num]"; //get table names and make another list $tables = @mysql_list_tables($db_names[$db_num]) or die(mysql_error()); $table_list = "<ul>"; $table_num = 0; //loop through results of function while ($table_num < mysql_num_rows($tables)){ //get table names and make each bullet point $table_names[$table_num] = mysql_tablename($tables, $table_num); $table_list .= "<li>$table_names[$table_num]"; $table_num++; } //close inner bullet list and increment number to continue $table_list .= "</ul>" $db_list .= "$table_list"; $db_num++; } //close outer bullet list $db_list .= "</ul>"; ?> <html> <head> <title>MySQL Tables</title> </head> <body> <p><strong>Data bases and tables on local host</strong></p> <? echo "$db_list"; ?> </body>

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  • MySQL get point in time totals from related tables

    - by batfastad
    Hi everyone We have an order book and invoicing system and I've been tasked with trying to output monthly rolling totals from these tables. But I don't know really where to start with this. I think there's some SQL syntax that I don't even know about yet. I'm familiar with INNER/LEFT/JOINS and GROUP BY etc but grouping by date is confusing since I don't know how to limit the data to only the current date that's being grouped by at that point. I think this will involve joining the tables to themselves or possibly a sub-select. I always thought it best to avoid sub-selects apart from when absolutely necessary. Basically the system has 3 tables orders: order_id, currency, order_stamp orders_lines: order_line_id, invoice_id, order_id, price invoices: invoice_id, invoice_stamp order_stamp and invoice_stamp are UTC unix timestamps stored as integers, not MySQL timestamps. I'm trying to get a listing by year/month showing the total of current unbilled orders (sum of price), at that point in time. Current orders are ones where order_stamp is less than or equal to 00:00 on the 1st of the month. Unbilled orders are ones where invoice_stamp is null or invoice_stamp is greater than 00:00 on the 1st of the month. At that point in time there may not be a related invoice yet and invoice_id might be null. Anyone got any suggestions on what I should join to what and what I need to group by? Cheers, B

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  • Combinationally unique MySQL tables

    - by Jack Webb-Heller
    So, here's the problem (it's probably an easy one :P) This is my table structure: CREATE TABLE `users_awards` ( `user_id` int(11) NOT NULL, `award_id` int(11) NOT NULL, `duplicate` int(11) NOT NULL DEFAULT '0', UNIQUE KEY `award_id` (`award_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 So it's for a user awards system. I don't want my users to be granted the same award multiple times, which is why I have a 'duplicate' field. The query I'm trying is this (with sample data of 3 and 2) : INSERT INTO users_awards (user_id, award_id) VALUES ('3','2') ON DUPLICATE KEY UPDATE duplicate=duplicate+1 So my MySQL is a little rusty, but I set user_id to be a primary key, and award_id to be a UNIQUE key. This (kind of) created the desired effect. When user 1 was given award 2, it entered. If he/she got this twice, only one row would be in the table, and duplicate would be set to 1. And again, 2, etc. When user 2 was given award 1, it entered. If he/she got this twice, duplicate updated, etc. etc. But when user 1 is given award 1 (after user 2 has already been awarded it), user 2 (with award 1)'s duplicate field increases and nothing is added to user 1. Sorry if that's a little n00bish. Really appreciate the help! Jack

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  • Too many columns to index - use mySQL Partitions?

    - by Christopher Padfield
    We have an application with a table with 20+ columns that are all searchable. Building indexes for all these columns would make write queries very slow; and any really useful index would often have to be across multiple columns increasing the number of indexes needed. However, for 95% of these searches, only a small subset of those rows need to be searched upon, and quite a small number - say 50,000 rows. So, we have considered using mySQL Partition tables - having a column that is basically isActive which is what we divide the two partitions by. Most search queries would be run with isActive=1. Most queries would then be run against the small 50,000 row partition and be quick without other indexes. Only issue is the rows where isActive=1 is not fixed; i.e. it's not based on the date of the row or anything fixed like that; we will need to update isActive based on use of the data in that row. As I understand it that is no problem though; the data would just be moved from one partition to another during the UPDATE query. We do have a PK on id for the row though; and I am not sure if this is a problem; the manual seemed to suggest the partition had to be based on any primary keys. This would be a huge problem for us because the primary key ID has no basis on whether the row isActive.

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  • Time calculations with MySQL TIMEDIFF

    - by Oli
    Hi there, I have the following table: mysql> SELECT id,start1,stop1,start2,stop2 FROM times; +----+---------------------+---------------------+---------------------+---------------------+ | id | start1 | stop1 | start2 | stop2 | +----+---------------------+---------------------+---------------------+---------------------+ | 4 | 2010-04-23 08:05:00 | 2010-04-23 12:15:00 | 2010-04-23 12:45:00 | 2010-04-23 16:50:00 | | 2 | 2010-04-26 09:30:00 | 2010-04-26 12:10:00 | 2010-04-26 12:50:00 | 2010-04-26 16:50:00 | | 7 | 2010-04-28 08:45:00 | 2010-04-28 11:45:00 | 2010-04-28 13:10:00 | 2010-04-28 17:29:00 | | 6 | 2010-04-27 09:30:00 | 2010-04-27 12:15:00 | 2010-04-27 12:55:00 | 2010-04-27 18:44:00 | +----+---------------------+---------------------+---------------------+---------------------+ I want to sum total worktime and the difference to the "needed work hours". It works pretty well with the statement below, but for unknown reasons it doesn't work for id 6. start*/stop* fields are in format datetime. SELECT *, TIME_FORMAT(TIMEDIFF(totaltime,'08:24'),'%H:%i') AS diff, totaltime > '08:24' AS redorgreen FROM ( SELECT DATE_FORMAT(start1,'%a %e. %M %Y') AS date, TIME_FORMAT(SUM(TIMEDIFF(stop1,start1) + TIMEDIFF(stop2,start2)),'%H:%i') AS totaltime, TIME_FORMAT(start1,'%H:%i') AS start1, TIME_FORMAT(stop1,'%H:%i') AS stop1, TIME_FORMAT(start2,'%H:%i') AS start2, TIME_FORMAT(stop2,'%H:%i') AS stop2, id as id FROM times GROUP BY id ASC ) AS somethingwedontneed; This is the result: select id, TIME_FORMAT(SUM(TIMEDIFF(stop1,start1) + TIMEDIFF(stop2,start2)),'%H:%i') AS totaltime from times group by id; +----+-----------+ | id | totaltime | +----+-----------+ | 2 | 06:40 | | 4 | 08:15 | | 6 | NULL | | 7 | 07:19 | +----+-----------+ Thanks in advance for every hint.

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  • Why Doesn’t Partition Elimination Work?

    - by Paul White
    Given a partitioned table and a simple SELECT query that compares the partitioning column to a single literal value, why does SQL Server read all the partitions when it seems obvious that only one partition needs to be examined? Sample Data The following script creates a table, partitioned on the char(3) column ‘Div’, and populates it with 100,000 rows of data: USE Sandpit; GO CREATE PARTITION FUNCTION PF ( char (3)) AS RANGE RIGHT FOR VALUES ( '1' , '2' , '3' , '4' , '5' , '6' , '7' , '8' , '9'...(read more)

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  • mysql spitting lots of "table marked as crashed" errors

    - by Shawn
    Hi, I have a mysql server(version: 5.5.3-m3-log Source distribution ) and it keeps showing lots of 110214 3:01:48 [ERROR] /usr/local/mysql/libexec/mysqld: Table './mydb/tablename' is marked as crashed and should be repaired 110214 3:01:48 [Warning] Checking table: './mydb/tablename' I'm wondering what can be the possible casues and how to fix it. Here is a full list mysql configuration : connect_errors = 6000 table_cache = 614 external-locking = FALSE max_allowed_packet = 32M sort_buffer_size = 2G max_length_for_sort_data = 2G join_buffer_size = 256M thread_cache_size = 300 #thread_concurrency = 8 query_cache_size = 512M query_cache_limit = 2M query_cache_min_res_unit = 2k default-storage-engine = MyISAM thread_stack = 192K transaction_isolation = READ-COMMITTED tmp_table_size = 246M max_heap_table_size = 246M long_query_time = 3 log-slave-updates = 1 log-bin = /data/mysql/3306/binlog/binlog binlog_cache_size = 4M binlog_format = MIXED max_binlog_cache_size = 8M max_binlog_si ze = 1G relay-log-index = /data/mysql/3306/relaylog/relaylog relay-log-info-file = /data/mysql/3306/relaylog/relaylog relay-log = /data/mysql/3306/relaylog/relaylog expire_logs_days = 30 key_buffer_size = 1G read_buffer_size = 1M read_rnd_buffer_size = 16M bulk_insert_buffer_size = 64M myisam_sort_buffer_size = 2G myisam_max_sort_file_size = 5G myisam_repair_threads = 1 max_binlog_size = 1G interactive_timeout = 64 wait_timeout = 64 skip-name-resolve slave-skip-errors = 1032,1062,126,1114,1146,1048,1396 The box is running on centos-5.5. Thanks for your help.

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  • Cant get php script to connect to asterisk internal mysql database

    - by Bilbo
    Im trying to get a PHP script to connect to Asterisks internal sql database. I tried the to use the standard method for example $con = mysqli_connect("192.168.1.126","root","mysql","asterisk"); However when I log into the asterisk server to access the mysql database all i need it to type "mysql" and im logged in. Im wondering is it possible for my php script to connect to asterisk internal database. //edit The following mysql error is shown Warning: mysqli_connect(): (HY000/2003): Can't connect to MySQL server on '192.168.1.126' (111) in /var/www/html/project/sipSubScript.php on line 6 Failed to connect to MySQL: Can't connect to MySQL server on '192.168.1.126' (111)

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  • problem with MySQL installation : template configuration file cannot be found

    - by user35389
    Trying to install MySQL onto the Windows XP machine. While going through the installation steps (in the "MySQL Server Instance Config. Wizard"), I get to a point where it the window reads: MySQL Server Instance Configuration (bold header) Choose the configuration for the server instance. Ready to execute... o Prepare configuration o Write configuration file o Start service o Apply security settings (this line is greyed out) Please press [Execute] to start the configuration. [ Back ] [ Execute ] [ Cancel ] So I press execute, and then a red X appears in the second step: Write configuration file and at the bottom, where it originally said: Please press [Execute] to start the configuration. It now says: The template configuration file cannot be found at C:\Program Files\MySQL\MySQL Server 5.0\bin\my-template.cnf I'm unsure what it means, but I canceled the config wizard and looked in the directory that had been created (C:\Program Files\MySQL\MySQL Server 5.0). There are some configuration settings files, and there are 4 folders: bin data Docs share

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  • MySQL replication/connection failing over SSL

    - by Marcel Tjandraatmadja
    I set up two MySQL servers where one is replicating from the other. They both work perfectly, but once I turn on SSL I get the following error: ERROR 2026 (HY000): SSL connection error I get the same error running from command line like so: mysql --ssl=1 --ssl-ca=/etc/mysql/certificates/ca-cert.pem --ssl-cert=/etc/mysql/certificates/client-cert.pem --ssl-key=/etc/mysql/certificates/client-key.pem --user=slave --password=slavepassword --host=master.url.com Both MySQL servers are running on version 5.0.77. There is a difference that MySQL in the master server was compiled under x86_64 while in the slave server under i686. Also both machines are running CentOS 5. Plus I generated certificates as per this page. Any idea for finding a solution?

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  • Rails: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock'

    - by misbehavens
    So I've got a Ruby on Rails application that I am trying to run (in development) on Snow Leopard. I've got it working on my Ubuntu computer, but now I need to get my Snow Leopard environment set up. Originally, I installed the MySQL 2.8.1 Ruby Gem and was running into this issue: uninitialized constant MysqlCompat::MysqlRes But thanks to this tutorial I was able to resolve it by running this command and installing a previous version of the Gem: export ARCHFLAGS="-arch i386 -arch x86_64" ;sudo gem install --no-rdoc --no-ri -v=2.7 mysql -- --with-mysql-dir=/usr/local/mysql --with-mysql-config=/usr/local/mysql/bin/mysql_config Now that I've resolved that issue, I'm running into a different error: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' This happens when I try to run rake db:migrate as well as when the server is running. How can I resolve this issue?

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  • Troubleshooting MySQL : can connect to localhost but not to 127.0.0.1 or IP

    - by mireille raad
    Hello, I'd appreciate some help on this, it is bit tricky to find the correct keywords to google :) Using PHP i am able to connect using the following connection string : $link = mysql_connect('localhost', 'wlek' , 'wlek'); but when i use 127.0.0.1 or 10.10.40.15 (self-IP), i am getting connection failed Could not connect: Can't connect to MySQL server on '10.10.40.15' (13) I used yum install mysql , yum install php yum install php-mysql 1 - is there anything more i should install for php ? 2 - any troubleshooting tips ? 3 - what keywords, links do u recommend | % | mir | xdb | | 10.10.40.15 | mir | xdb | | localhost | mir | xdb | [mysqld] datadir=/var/lib/mysql socket=/var/lib/mysql/mysql.sock user=mysql port=3306 bind-address=0.0.0.0 old_passwords=1 [mysqld_safe] log-error=/var/log/mysqld.log pid-file=/var/run/mysqld/mysqld.pid ~ appreciate it :)

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  • Installing isolated instance of MySQL on Windows using silent install with .msi

    - by Abram
    I'm trying to write an installer for an internal application we wrote. After it installs our application it then installs MySQL using the .msi installer in silent mode. I specify the install dir and data dir to that of a directory within my application's install directory, such as: msiexec /i @@MYSQL_INSTALLER_FILE@@ /qn INSTALLDIR="@@INSTALL_DIR@@\MySQL\" DATADIR="@@INSTALL_DIR@@\MySQL\" USERNAME="@@DB_USER@@" PASSWORD="@@DB_PASS@@" (the @@variable@@'s are replace by my installer routine using InstallJammer) Once installed, I use mysqld.exe to install a windows service with a custom service name and defaults file like so: mysqld.exe --install CustomMySQL --defaults-file="@@INSTALL_DIR@@\MySQL\my.ini" This works fine as long as there is not already another instance of MySQL installed. If there is it silently fails to install MySQL. Running the msi installer manually (double-click) shows an error that a previous version is already installed and just aborts. Is there a way to automate installing MySQL as an isolated instance, regardless of whether another version/instance is already installed?

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  • How to retrieve all MySQL settings?

    - by Max Kielland
    I have a configured MySQL server (MySQL 5.1.47-community) that works perfect. I installed a second server (MySQL 5.5.15-community) to see if the new version of MySQL would work with my application before upgrading. When I run the application against the new server it behaves different. When I run it against the old server (MySQL 5.1.47-community) everything works perfect. I remember that I set some parameters through the MySQL prompt to accept larger result set and some other stuff, now I can't remember what I did. So my question is: Is there a way to transfer all the MySQL settings from one server to another? Thanks.

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  • How to retrieve all MySQL settings?

    - by Max Kielland
    I have a configured MySQL server (MySQL 5.1.47-community) that works perfect. I installed a second server (MySQL 5.5.15-community) to see if the new version of MySQL would work with my application before upgrading. When I run the application against the new server it behaves different. When I run it against the old server (MySQL 5.1.47-community) everything works perfect. I remember that I set some parameters through the MySQL prompt to accept larger result set and some other stuff, now I can't remember what I did. So my question is: Is there a way to transfer all the MySQL settings from one server to another? Thanks.

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  • uninstall mysql on linux with plesk

    - by Arsenal
    I'm having trouble uninstalling linux on my centOS 4 that has plesk. I'm actually trying to upgrade my Mysql 4.1 version to Mysql 5.0 using the following command: yum update mysql I get an error list of conflicted files however. When I try to remove mysql 4.1 and perform a clean install but when I use yum remove mysql* It deletes all of its dependencies and appearantly some of these are files needed by plesk, which causes my plesk to stop working. A did a full restore and everything is okay now, but how can I remove mysql without ruining plesk? I have also tried: rpm -qa | grep mysql to get a list of all files and remove them one by one, but there's a duplicate in that list, so I can't delete those (because it says it doesn't know which one to take). Any help would be greatly appreciated!

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  • Creepy MySQL error during hard work

    - by Kiewic
    Hi, I have a MySQL database installed on a OpenSuse 11.1 server (it is a Bitnami image). The database works fine, it can stay many days without any error, but when MySQL receives a huge amount of transactions, it dies immediately. The next screen shows the error: Moreover, I don't know how to restart MySQL. I have tried this: /opt/bitnami/mysql/bin/mysqld start But it doesn't work, that gives me the next output: 110209 17:09:01 [ERROR] Fatal error: Please read "Security" section of the manual to find out how to run mysqld as root! 110209 17:09:01 [ERROR] Aborting 110209 17:09:01 [Note] /opt/bitnami/mysql/bin/mysqld.bin: Shutdown complete It doesn't matter which kind of statements are executing, if they are a huge amount, MySQL dies. The MySQL server version is 5.1.30 What can be causing these sudden failures?

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  • unable to install mysql completely on debian 5.0

    - by austin powers
    hi, its been a couple of days that I'm trying to install mysql on my vps which has debian 5.0 with 256mb ram. I've installed webmin also. here is the symptoms : after installing mysql using either webmin or apt-get I am trying to connect to mysql for changing root password but every time I cope with this error : ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: YES) so I start to investigate and I understand there is no root user inside mysql database when I use : UPDATE user SET password=PASSWORD('newpassword') WHERE user="root"; it says 0 row affected I reinstall mysql for several times but the same problem still exits. please help me how can I install mysql-server as well as mysql-client correctly. regards.

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