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  • Why does PHP 5.2 disallow abstract static class methods?

    - by Artem Russakovskii
    After enabling strict warnings in PHP 5.2, I saw a load of strict standards warnings from a project that was originally written without strict warnings: Strict Standards: Static function Program::getSelectSQL() should not be abstract in Program.class.inc The function in question belongs to an abstract parent class Program and is declared abstract static because it should be implemented in its child classes, such as TVProgram. I did find references to this change here: Dropped abstract static class functions. Due to an oversight, PHP 5.0.x and 5.1.x allowed abstract static functions in classes. As of PHP 5.2.x, only interfaces can have them. My question is: can someone explain in a clear way why there shouldn't be an abstract static function in PHP?

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  • i want to display an item in between a for each loop

    - by atif
    i had this code <ul class="links"<?php if($this->getName()): ?> id="<?php echo $this->getName() ?>"<?php endif;?>> <?php foreach($_links as $_link): ?> <?php if ($_link instanceof Mage_Core_Block_Abstract):?> <?php echo $_link->toHtml() ?> <?php else: ?> <li<?php if($_link->getIsFirst()||$_link->getIsLast()): ?> class="<?php if($_link->getIsFirst()): ?>first<?php endif; ?><?php if($_link->getIsLast()): ?> last<?php endif; ?>"<?php endif; ?> <?php echo $_link->getLiParams() ?>><?php echo $_link->getBeforeText() ?><a href="<?php echo $_link->getUrl() ?>" title="<?php echo $_link->getTitle() ?>" <?php echo $_link->getAParams() ?>><?php echo $_link->getLabel() ?></a><?php echo $_link->getAfterText() ?></li> <?php endif;?> <?php endforeach; ?> </ul> now i know that i had four links but i want to insert "wishlist" after 1st so how could i do that?

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  • looking for advise on importing excel into mysql with php

    - by Ole Media
    Alright, see if I can pick your brains from you all. I'm currently working on a project where all the information comes from different clients, the only thing in common is that the received data is done with excel. The excel spread sheet that they present is just a bunch of references and codes, and the problem than I'm facing is that I need the references and codes to be entered in certain format in order for the website to work. The perfect situation will be to go to each client and teach how I would need the data, but I can't do that because of the large number of clients, and more importantly I will be interrupting their work flow. Each client has its own codes and reference model and they are not willing to change their process The good news is that there is a standard pattern for the codes, but I'm talking close to 200 thousand codes with a bunch of combination. They way that we are currently solving the problem is that we have a person who checks each excel sheet received, runs a few macros, and manually fixes those codes in which the macro was not able to fix. The person that is doing this, is already burn out and frustrated and I would like to automatize this process with php. Suggestions?

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  • Optimise & improve performance of this MYSQL query

    - by David
    SELECT u.id, u.honour, COUNT(*) + 1 AS rank FROM user_info u INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id = '$id' AND u2.status = 'Alive' AND u2.rank != '14' This query is currently utterly raping my server. It works out based on your honour what rank you are within the 'user_info' table which stores it out of all our users. Screenshot for explain. http://cl.ly/370z0v2Y3v2X1t1r1k2A SELECT u.id, u.honour, COUNT(*)+1 as rank FROM user_info u USE INDEX (prestigeOptimiser) INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id='3' AND u2.status='Alive' AND u2.rank!='14'

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  • Can a PHP object respond to an undefined method?

    - by Nathan Long
    Rails relies on some of the neat aspects of Ruby. One of those is the ability to respond to an undefined method. Consider a relationship between Dog and Owner. Owner has_many :dogs and Dog belongs_to :owner. If you go into script/console, get a dog object with fido = Dog.find(1), and look at that object, you won't see a method or attribute called Owner. What you will see is an owner_id. And if you ask for fido.owner, the object will do something like this (at least, this is how it appears to me): I'm being asked for my .owner attribute. I don't have one of those! Before I throw a NoMethodError, do I have a rule about how to deal with this? Yes, I do: I should check and see if I have an owner_id. I do! OK, then I'll do a join and return that owner object. PHP's documentation is - ahem - a bit lacking sometimes, so I wonder if anyone here knows the answer to this: Can I define similar behavior for objects in PHP? If not, do you know of a workaround for flexible model joins like these?

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  • Finding mySQL duplicates, then merging data

    - by Michael Pasqualone
    I have a mySQL database with a tad under 2 million rows. The database is non-interactive, so efficiency isn't key. The (simplified) structure I have is: `id` int(11) NOT NULL auto_increment `category` varchar(64) NOT NULL `productListing` varchar(256) NOT NULL Now the problem I would like to solve is, I want to find duplicates on productListing field, merge the data on the category field into a single result - deleting the duplicates. So given the following data: +----+-----------+---------------------------+ | id | category | productListing | +----+-----------+---------------------------+ | 1 | Category1 | productGroup1 | | 2 | Category2 | productGroup1 | | 3 | Category3 | anotherGroup9 | +----+-----------+---------------------------+ What I want to end up is with: +----+----------------------+---------------------------+ | id | category | productListing | +----+----------------------+---------------------------+ | 1 | Category1,Category2 | productGroup1 | | 3 | Category3 | anotherGroup9 | +----+----------------------+---------------------------+ What's the most efficient way to do this either in pure mySQL query or php?

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  • PHP 5.1.6 ArrayAccess error when iterating over object

    - by kenny99
    Hi, I'm having to develop a site on PHP 5.1.6 and I've just come across a bug in my site which isn't happening on 5.2+. When using foreach() to iterate over an object, I get the following error: "Fatal error: Objects used as arrays in post/pre increment/decrement must return values by reference..." Does anyone know how to get around this issue? if (strpos($post['feeding_type'], 'comm')) { foreach ($post['commercial_brands'] as $brand) { $comm_food = new Commercial_food_Model; $comm_food->brand = $brand; $comm_food->feeding_type_id = $f_type->id; $comm_food->save(); } }

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  • Why might this work on my server but not my schools?

    - by Doug
    I created a captcha just now, and it works PERFECTLY on my own server. On the school's server, it doesn't generate an image. Why might this be? The difference in code is one line. *Edit:*Originally, it was working, but I deleted the directory by mistake and I do not know why did it suddenly work in the first place. Source code on school server: <?php session_save_path("/ichanged/this/path/for/this/post/"); session_start(); $img=imagecreatefromjpeg("bg.jpg"); if( empty($_SESSION['captcha_numbers']) ) { $captcha_numbers = 'error'; } else { $captcha_numbers = $_SESSION['captcha_numbers']; } $image_numbers=$captcha_numbers; $red=rand(100,150); $green=rand(100,255); $blue=rand(100,255); $color=imagecolorallocate($img,255-$red,255-$green,255-$blue); $text=imagettftext($img,12,rand(-7,7),rand(10,20),rand(20,30),$color,"fonts/M04.TTF",$image_numbers); header("Content-type:image/jpeg"); header("Content-Disposition:inline ; filename=secure.jpg"); imagejpeg($img); ?> Source code on my server: <?php session_start(); $img=imagecreatefromjpeg("bg.jpg"); if( empty($_SESSION['captcha_numbers']) ) { $captcha_numbers = 'error'; } else { $captcha_numbers = $_SESSION['captcha_numbers']; } $image_numbers=$captcha_numbers; $red=rand(100,150); $green=rand(100,255); $blue=rand(100,255); $color=imagecolorallocate($img,255-$red,255-$green,255-$blue); $text=imagettftext($img,12,rand(-7,7),rand(10,20),rand(20,30),$color,"fonts/M04.TTF",$image_numbers); header("Content-type:image/jpeg"); header("Content-Disposition:inline ; filename=secure.jpg"); imagejpeg($img); ?>

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  • Elegant Method of Inserting Code Between Loops

    - by DeathMagus
    In web development, I often find I need to format and print various arrays of data, and separate these blocks of data in some manner. In other words, I need to be able to insert code between each loop, without said code being inserted before the first entry or after the last one. The most elegant way I've found to accomplish this is as follows: function echoWithBreaks($array){ for($i=0; $i<count($array); $i++){ //Echo an item if($i<count($array)-1){ //Echo "between code" } } } Unfortunately, there's no way that I can see to implement this solution with foreach instead of for. Does anyone know of a more elegant solution that will work with foreach?

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  • How does Zend_Db_Table_Select work?

    - by jwhat
    I'm trying to figure out how to use Zend_Db_Table_Abstract correctly. I want to return just the name column from my query. Can you please explain what's wrong with the following code? class Model_DbTable_Foo extends Zend_Db_Table_Abstract { protected $_name = 'foo'; public function getFooById($id) { $select = $this->select(true)->columns('name')->where('id=' . $id); $row = $this->fetchRow($select); print_r($row->toArray()); } }

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  • Passing along variable inside link works only on first word in multiple-word-variables, why?

    - by Camran
    I have this code below. As you can see I am passing two variables along with the link. The second variabye (category) works whenever it consists of one word, but some categories are two words or more, and then on the receiving php page where I fetch the variable only the first word is fetched. Any ideas? Example: I pass along this: Rims & Tires Only this comes through: Rims $display_table .= "<a href='../ad.php?ad_id=$row[ad_id]&category=$row[category]' target='_parent'>"; Here is how I fetch it in the receiving php file (which the link is to): $cat = $_GET['category']; echo $cat; //displays only first word of multiple word categories. Thanks

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  • mysqli insert into database

    - by Simon
    Hello all i have this script and i will not insert into the database and i get no errors :S, do you know what it is? function createUser($username, $password) { $mysql = connect(); if($stmt = $mysql->prepare('INSERT INTO users (username, password, alder, hood, fornavn, efternavn, city, ip, level, email) VALUES (?,?,?,?,?,?,?,?,?,?)')) { $stmt->bind_param('ssssssssss',$username,$password, $alder, $hood, $fornavn, $efternavn, $city, $ip, $level, $email); $stmt->execute(); $stmt->close(); } else { echo 'error: ' . $mysql->error; }

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  • Fatal error: Cannot use string offset as an array

    - by learner
    Array ( [0] = Array ( [auth_id] = 1 [auth_section] = Client Data Base [auth_parent_id] = 0 [auth_admin] = 1 [sub] = Array ( [0] = Array ( [auth_id] = 2 [auth_section] = Client Contact [auth_parent_id] = 1 [auth_admin] = 1 ) ) ) [1] => Array ( [auth_id] => 6 [auth_section] => All Back Grounds [auth_parent_id] => 0 [auth_admin] => ,4 [sub] => Array ( [0] => Array ( [auth_id] => 7 [auth_section] => Edit Custom [auth_parent_id] => 6 [auth_admin] => 1 ) ) ) [2] => Array ( [auth_id] => 20 [auth_section] => Order Mail [auth_parent_id] => 0 [auth_admin] => 1 [sub] => ) } When I process the sub inner array it shows this error how can I avoid that :)

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  • PHP mysql_real_escape_string() returning `NULL`

    - by DavidYell
    I'm using PHP Version 5.1.6 and trying to escape a query string from my $_GET array. However my script is returning a NULL after it's escaped. It seems that mysql_escape_string() works fine, but it's deprecated, so I don't want to use it. Having checked over the phpinfo() the MySQL lib is all loaded fine from what I can see. Has anyone experienced this kind of thing before? $term = $_GET['q']; var_dump($term); // string(7) "richard" echo "<br />"; $sterm = mysql_real_escape_string($term, $db); var_dump($sterm); // NULL It's very strange to me, I can't imagine why this function wouldn't work.

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  • PHP returns a negative number?

    - by Legend
    I am trying to query a bittorrent tracker and am using unpack to get the list of IPs from the response. So, something like this: $ip = unpack("N", $peers); $ip_add = ($ip[1]>>24) . "." . (($ip[1]&0x00FF0000)>>16) . "." . (($ip[1]&0x0000FF00)>>8) . "." . ($ip[1]&0x000000FF); But, for some reason, I am getting the following IP addresses when I print $ip_add: 117.254.136.66 121.219.20.250 -43.7.52.163 Does anyone know what could be going wrong?

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  • Only show certain items in a mysql database using php and time()

    - by Jon
    Is there a way to only show the items that are older than a certain date in a php mysql array? I'm using this query method and sorting by lastpost_cl: $query="SELECT * FROM properties ORDER BY lastpost_cl"; $result=mysql_query($query); $num = mysql_num_rows ($result); mysql_close(); and I was thinking the way of checking the time would be: if (time() <= strtotime($lastpost_cl)) { } How can I combine the two and only show lastpost_cl that are older that the current time?

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  • mysql get last auto increment value

    - by Mick
    Hi I have a field in mySql table called jobnumber which auto increments with each new entry. What I want to do is when a user views my form, get the value of the next 'jobnumber' . But I want to do this before any entry is made to the table. IE so when a user looks at a form it will display something like 'this is job number 6954' I have tried $rr = mysql_insert_id() but this only work after I have made an entry Can anyone help please thanks

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  • PHP Magento Screen Scraping

    - by Grant unwin
    I am trying to scrape a suppliers magento site in an effort to save some time because of there being around 2000 products I need to gather info for. I'm totally OK with writing a screen scraper for pretty much anything but i've encountered a major problem. Im using get_file_contentsto gather the html of the product page. The problem is: You need to be logged in, to view the product page. Its a standard magento login, so how can I get round this in my screen scraper? I don't require a full script, just advice on a method. Thanks

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  • Using curl_init in Zend Application is causing Session Error

    - by Gublooo
    Hey guys I'm getting this weird error in my Zend application with this piece of code: $curl = curl_init(); curl_setopt($curl, CURLOPT_URL, 'www.xyz.com/ab.php'); curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); $data = curl_exec($curl); curl_close($curl); This is the error, I get: Fatal error: Uncaught exception 'Zend_Session_Exception' with message 'session has already been started by session.auto-start or session_start() When I remove that code everything works fine. Any idea ?? Thanks

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  • cPanel's SMTP or google hosted SMTP ?

    - by praveen
    Hi, I'm wondering what mail servers I should use for sending mail through my website, avoiding them sent as spam. Hostgator SMTP google hosted SMTP I found that to avoid a mail sent as spam it should have the same host in "From:" and "Received". How to overcome this? Thanks

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