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  • Xpath question Xml Xpath

    - by Ibrar Afzal
    I need an xpath expression that would return the value of I need to get the value of this node. the value to extract is my xpath expression is //rates/rate[loantype='30-Year Fixed Rate'] The issue hre is that there are three value each node has a subtype element. Beside fileter for loantype I also need to filter for subtype. I am not sure how to do it in xpath. I have the following xml 40-Year Fixed Rate A 3 5.375 1.000 5.491 0 1 40-Year Fixed Rate B 5.500 0.500 5.579 0 1 40-Year Fixed Rate C 5.625 0.000 5.667 0 1 30-Year Fixed Rate A 3 5.000 1.000 5.134 0 1 30-Year Fixed Rate B 5.125 0.500 5.215 0 1 30-Year Fixed Rate C 5.250 0.000 5.297 0 1 20-Year Fixed Rate A 3 4.875 1.000 5.055 0 1 20-Year Fixed Rate B 5.000 0.500 5.121 0 1 20-Year Fixed Rate C 5.125 0.000 5.187 0 1 15-Year Fixed Rate A 3 4.250 1.000 4.467 0 1 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 15-Year Fixed Rate C 4.500 0.000 4.570 0 1 10-Year Fixed Rate A 3 4.125 1.000 4.435 0 1 10-Year Fixed Rate B 4.250 0.500 4.454 0 1 10-Year Fixed Rate C 4.375 0.000 4.473 0 1 High-Balance 15-Year Fixed Rate D 3 4.250 1.000 4.461 0 1 High-Balance 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 High-Balance 15-Year Fixed Rate C 4.500 0.000 4.563 0 1 High-Balance 30-Year Fixed Rate D 3 5.000 1.000 5.130 0 1 High-Balance 30-Year Fixed Rate B 5.125 0.500 5.211 0 1 High-Balance 30-Year Fixed Rate C 5.250 0.000 5.293 0 1 30-Year Fixed Rate Jumbo A 2 5.125 1.000 5.254 1 1 30-Year Fixed Rate Jumbo B 5.250 0.500 5.336 1 1 30-Year Fixed Rate Jumbo C 5.375 0.000 5.417 1 1 -- 15-Year Fixed Rate Jumbo A 2 5.000 1.000 5.220 1 1 15-Year Fixed Rate Jumbo B 5.125 0.500 5.270 1 1 15-Year Fixed Rate Jumbo C 5.250 0.000 5.320 1 1 -- 3/1 30-Year Adjustable Rate A 3 3.625 1.000 3.431 0 0 3/1 30-Year Adjustable Rate B 3.875 0.500 3.448 0 0 3/1 30-Year Adjustable Rate C 4.125 0.000 3.465 0 0 3/1 40-Year Adjustable Rate A 3 3.875 1.000 3.438 0 0 3/1 40-Year Adjustable Rate B 4.125 0.500 3.453 0 0 3/1 40-Year Adjustable Rate C 4.375 0.000 3.467 0 0 5/1 30-Year Adjustable Rate A 3 3.375 1.000 3.401 0 0 5/1 30-Year Adjustable Rate B 3.625 0.500 3.457 0 0 5/1 30-Year Adjustable Rate C 3.875 0.000 3.514 0 0 5/1 40-Year Adjustable Rate A 3 3.625 1.000 3.441 0 0 5/1 40-Year Adjustable Rate B 3.875 0.500 3.481 0 0 5/1 40-Year Adjustable Rate C 4.125 0.000 3.531 0 0 7/1 30-Year Adjustable Rate A 3 3.875 1.000 3.670 0 0 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 10/1 30-Year Adjustable Rate A 3 4.375 1.000 4.092 0 0 10/1 30-Year Adjustable Rate B 4.625 0.500 4.217 0 0 10/1 30-Year Adjustable Rate C 4.875 0.000 4.342 0 0 -- 2/2 ARM 30-Year (Purchase only) DH 5.250 0.000 3.709 0 0 -- High-Balance 5/1 30-Year Adjustable Rate D 3 3.375 1.000 3.366 0 0 High-Balance 5/1 30-Year Adjustable Rate B 3.625 0.500 3.404 0 0 High-Balance 5/1 30-Year Adjustable Rate C 3.875 0.000 3.454 0 0 High-Balance 7/1 30-Year Adjustable Rate D 3 3.875 1.000 3.670 0 0 High-Balance 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 High-Balance 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 3/1 30-Year Jumbo Adjustable Rate A 2 4.875 1.000 3.719 1 0 3/1 30-Year Jumbo Adjustable Rate B 5.000 0.500 3.708 1 0 3/1 30-Year Jumbo Adjustable Rate C 5.125 0.000 3.704 1 0 -- 3/1 40-Year Jumbo Adjustable Rate A 2 5.250 1.000 3.733 1 0 3/1 40-Year Jumbo Adjustable Rate B 5.375 0.500 3.727 1 0 3/1 40-Year Jumbo Adjustable Rate C 5.500 0.000 3.725 1 0 -- 5/1 30-Year Jumbo Adjustable Rate A 3 4.375 1.000 3.791 1 0 5/1 30-Year Jumbo Adjustable Rate B 4.500 0.500 3.803 1 0 5/1 30-Year Jumbo Adjustable Rate C 4.625 0.000 3.814 1 0 5/1 40-Year Jumbo Adjustable Rate A 2 5.000 1.000 3.922 1 0 5/1 40-Year Jumbo Adjustable Rate B 5.125 0.500 3.925 1 0 5/1 40-Year Jumbo Adjustable Rate C 5.250 0.000 3.936 1 0 -- 7/1 30-Year Jumbo Adjustable Rate A 3 4.950 1.000 4.261 1 0 7/1 30-Year Jumbo Adjustable Rate B 5.075 0.500 4.286 1 0 7/1 30-Year Jumbo Adjustable Rate C 5.200 0.000 4.311 1 0 2/2 ARM 30-Year Jumbo (Purchase only) DH 6.500 0.000 4.260 1 0 -- 30 Due in 7 Fixed Rate JUMBO Balloon A 6.375 1.000 6.613 1 0 30 Due in 7 Fixed Rate JUMBO Balloon B 6.500 0.500 6.625 1 0 40 due in 7 Fixed Rate offer1 5.250 0.000 5.374 0 0 1 40 Due in 7 Fixed Rate JUMBO Balloon offer2 6.500 0.000 6.625 1 0 1 Interest Only HELOC A To 80% LTV 3.250 0 1 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 75% LTV 6.000 6.000 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 75% LTV 6.00 6.153 0 2 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 80% LTV 6.250 6.250 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 80% LTV 6.25 6.403 0 2 Home Equity Loan - 7Yrs B $100,000.01 - $250,000.00 Up to 90% LTV 6.99 7.145 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 75% LTV 6.50 6.612 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 80% LTV 6.75 6.863 0 2 Home Equity Loan - 10,15Yrs D $5,000-$250,000.00 Up to 90% LTV 7.50 7.614 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 75% LTV 7.50 7.566 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 80% LTV 7.75 7.817 0 2 Home Equity Loan - 20Yrs F $5,000-$250,000.00 Up to 90% LTV 8.50 8.569 0 2 Equity Edge $5,000-$25,000.00 Up to 125% LTV 12.00 12.188 Current Index 0.350 Prime Index 3.250 03/26/2010

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  • Question on Scala Closure (From "Programming in Scala")

    - by Ekkmanz
    I don't understand why authors said that Code Listing 9.1 from "Programming in Scala" use closure. In chapter 9, they show how to refactor code into more less duplicated form, from this original code: object FileMatcher { private def filesHere = (new java.io.File(".")).listFiles def filesEnding(query: String) = for (file <- filesHere; if file.getName.endsWith(query)) yield file def filesContaining(query: String) = for (file <- filesHere; if file.getName.contains(query)) yield file def filesRegex(query: String) = for (file <- filesHere; if file.getName.matches(query)) yield file } To the second version: object FileMatcher { private def filesHere = (new java.io.File(".")).listFiles def filesMatching(query: String, matcher: (String, String) => Boolean) = { for (file <- filesHere; if matcher(file.getName, query)) yield file } def filesEnding(query: String) = filesMatching(query, _.endsWith(_)) def filesContaining(query: String) = filesMatching(query, _.contains(_)) def filesRegex(query: String) = filesMatching(query, _.matches(_)) } Which they said that there is no use of closure here. Now I understand until this point. However they introduced the use of closure to refactor even some more, shown in Listing 9.1: object FileMatcher { private def filesHere = (new java.io.File(".")).listFiles private def filesMatching(matcher: String => Boolean) = for (file <- filesHere; if matcher(file.getName)) yield file def filesEnding(query: String) = filesMatching(_.endsWith(query)) def filesContaining(query: String) = filesMatching(_.contains(query)) def filesRegex(query: String) = filesMatching(_.matches(query)) } Now they said that query is a free variable but I don't really understand why they said so? Since ""query"" seems to be passed from top method down to string matching function explicitly.

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  • iPhone Mapkit Blue Dot / User Location Region Zoom Question

    - by user290031
    Hey All, Is is possible to set a region based on a current location in a mapview only one time. I want my iphone app to get the current location, zoom into that current location, and then allow the user to scroll around. However, because my setRegion code is in my didUpdateToLocation function, every time the current location is updated, so is the region, and I can't scroll around on the map. I tried putting this setRegion code in the viewDidLoad function, but the user's current location isn't initialized at this point, so it doesn't work right. Any ideas?

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  • BizTalk Business Rules Engine - Repeating Elements Question

    - by Andrew Cripps
    Hello I'm trying to create what I think should be a relatively simple business rule to operate over repeating elements in an XML schema. Consider the following XML snippet (this is simplified with namespaces removed, for readability): <Root> <AllAccounts> <Account id="1" currentPayment="10.00" arrearsAmount="25.00"> <AllCustomers> <Customer id="20" primary="true" canSelfServe="false" /> <Customer id="21" primary="false" canSelfServe="false" /> </AllCustomers> </Account> <Account id="2" currentPayment="10.00" arrearsAmount="15.00"> <AllCustomers> <Customer id="30" primary="true" canSelfServe="false" /> <Customer id="31" primary="false" canSelfServe="false" /> </AllCustomers> </AllAccounts> </Root> What I want to do is to have two rules: Set /Root/AllAccounts/Account[x]/AllCustomers/Customer[primary='true']/canSelfServe = true IF arrearsAmount < currentPayment Set /Root/AllAccounts/Account[x]/AllCustoemrs/Customer[primary='true']/canSelfServer = false IF arrearsAmount = currentPayment Where [x] is 0...number of /Root/AllAccounts/Account records present in the XML. I've tried two simple rules for this, and each rule seems to fire x * x times, where x is the number of Account records in the XML. I only want each rule to fire once for each Account record. Any help greatly appreciated! Thanks Andrew

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  • Question about the MIT License and open/closed source

    - by stck777
    Hallo, I have a small useful application (Websites managment tool developed in Java) which I want to publish online for free (every one can use it for free). But I do not want to make it opne source yet. It is additional affort to clean up the code, documantation and so on... And this is just a small useful tool. Can I use the MIT license in this case, or the MIT license obligates me to distribute the source code? Which license is best in this case? Thanks.

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  • Objective-C Xcode: Prefix.pch question?

    - by Johannes Jensen
    I have two files independant on each other. Let's just call it Class1 and Class2. In Class1, I need Class2, and in Class2 I need Class1. I have a prefix file where I include all my files, and I get some syntax errors because I do #import "Class1.h" #import "Class2.h" How would I define both of them so they can use each other? What am I doing wrong?

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  • sequential search homework question

    - by Phenom
    Consider a disk file containing 100 records a. How many comparisons would be required on the average to find a record using sequential search, if the record is known to be in the file? I figured out that this is 100/2 = 50. b. If the record has a 68% probability of being in the file, how many comparisons are required on average? This is the part I'm having trouble with. At first I thought it was 68% * 50, but then realized that was wrong after thinking about it. Then I thought it was (100% - 68%) * 50, but I still feel that that is wrong. Any hints?

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  • Dreamweaver CS4 InstanceEditable question

    - by jason
    I have a client who has a website, with 100's of pages and they all have instance editables which I am really not familiar with as i just use PHP includes. They require me to edit the webpage live via Dreamweaver's built in FTP. How do these IE's work and whats the best approach for this? I don't want screw it up...

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  • WPF binding only inside XAML (simple question)

    - by 0xDEAD BEEF
    Why this works <myToolTip:UserControl1> <TextBlock Text="{Binding Path=TestString, RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type myToolTip:UserControl1}}}"/> </myToolTip:UserControl1> BUT this does not <myToolTip:UserControl1 x:Name="userControl"> <TextBlock Text="{Binding Path=TestString, ElementName=userControl}"/> </myToolTip:UserControl1> and is there realy no shorter (faster) fay, to acces usercontrols elements?! Sincerely, 0xDEAD BEEF

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  • mysql - query group/concat question??

    - by tom smith
    I have a situation where I return results with mutiple rows. I'm looking for aw way to return a single row, with the multiple items in separate cols within the row. My initial query: SELECT a.name, a.city, a.address, a.abbrv, b.urltype, b.url FROM jos__universityTBL as a LEFT JOIN jos__university_urlTBL as b on b.universityID = a.ID WHERE a.stateVAL = 'CA' ...my output: | University Of Southern Califor | Los Angeles | | usc | 2 | http://web-app.usc.edu/ws/soc/api/ | | University Of Southern Califor | Los Angeles | | usc | 4 | http://web-app.usc.edu/ws/soc/api/ | | University Of Southern Califor | Los Angeles | | usc | 1 | www.usc.edu | | San Jose State University | San Jose | | sjsu | 2 | http://info.sjsu.edu/home/schedules.html | | San Jose State University | San Jose | | sjsu | 4 | https://cmshr.sjsu.edu/psp/HSJPRDF/EMPLOYEE/HSJPRD/c/COMMUNITY_ACCESS.CLASS_SEARCH.GBL?FolderPath=PORTAL_ROOT_OBJECT.PA_HC_CLASS_SEARCH | | San Jose State University | San Jose | | sjsu | 1 | www.sjsu.edu My tbl schema... mysql> describe jos_universityTBL; +----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------------+--------------+------+-----+---------+----------------+ | name | varchar(50) | NO | UNI | | | | repos_dir_name | varchar(50) | NO | | | | | city | varchar(20) | YES | | | | | stateVAL | varchar(5) | NO | | | | | address | varchar(50) | NO | | | | | abbrv | varchar(20) | NO | | | | | childtbl | varchar(200) | NO | | | | | userID | int(10) | NO | | 0 | | | ID | int(10) | NO | PRI | NULL | auto_increment | +----------------+--------------+------+-----+---------+----------------+ 9 rows in set (0.00 sec) mysql> describe jos_university_urlTBL; +--------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+--------------+------+-----+---------+----------------+ | universityID | int(10) | NO | | 0 | | | urltype | int(5) | NO | | 0 | | | url | varchar(200) | NO | MUL | | | | actionID | int(5) | YES | | 0 | | | status | int(5) | YES | | 0 | | | ID | int(10) | NO | PRI | NULL | auto_increment | +--------------+--------------+------+-----+---------+----------------+ 6 rows in set (0.00 sec) I'm really trying to get something like: |<<the concated urltype-url >>| ucs | losangeles | usc.edu | 1-u1 | 2-u2 | 3-u2 | Any pointers would be helpful!

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  • django views question

    - by Hulk
    In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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  • Antlr question: cannot get Antlr tool to compile simple file from ANTLRWorks

    - by Don Henton
    Here is the grammar file: grammar fred; test : 'fred'; Here is the batch file to launch the tool: SET JAVA_HOME=C:\Program Files\Java\jdk1.6.0_24 SET PATH=%PATH%;%JAVA_HOME%\bin SET ANTLR_HOME=c:/users/don/workspace/antlrAssign/lib/ java -cp %ANTLR_HOME%/antlr-3.3-complete.jar antlr.Tool fred.g Here's the result: ANTLR Parser Generator Version 2.7.7 (20060906) 1989-2005 fred.g:1:1: unexpected token: grammar error: Token stream error reading grammar(s): fred.g:3:19: expecting ''', found 'r' fred.g:1:1: rule grammar trapped: fred.g:1:1: unexpected token: grammar TokenStreamException: expecting ''', found 'r' Prior postings refer to "org.antlr.Tool" but the 3.3 jar has it located as above. The idea was to create a debug version of a tree parser, and according to the documentation, you have to use the command line tool. Has anyone seen this before? Am I nuts? It's two lines long and its dying on the first word in the file. Of course this compiles in antlrworks. Any help appreciated, I can't afford any more adjustments to my medications.

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  • Javascript Noob Question. Need Help With Simple Script

    - by three3
    Hi everyone, I am new to JavaScript (only a couple of days of reading a book) and I am stuck on this code snippet. I have looked at it over and over again but cannot seem to figure out why it is not working. I am sure it is something really simple that I have just looked over but I really just need a fresh pair of eyes to look at this. The code is supposed to update a placeholder image on a page without the page having to reload. But when I am clicking on the link of an image, it is taking me to the link where the image is located instead of replacing the placeholder image. Here is my HTML code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Image Gallery</title> <script type="text/javascript" src="scripts/showPic.js"></script> </head> <body> <h1>Snapshots</h1> <ul> <li> <a href="images/cat.jpg" onclick="showPic(this); return false;" title="A Cat">Cat</a> </li> <li> <a href="images/night.jpg" onclick="showPic(this); return false;" title="Night">Night</a> </li> <li> <a href="images/coke.jpg" onclick="showPic(this); return false;" title="Coke">Coke</a> </li> <li> <a href="images/sport.jpg" onclick="showPic(this); return false;" title="Sports">Sport</a> </li> <li> <a href="images/mnms.png" onclick="showPic(this); return false;" title="MnM's">MnM's</a> </li> <li> <a href="images/kid.jpg" onclick="showPic(this); return false;" title="A Kid">Kid</a> </li> </ul> <br /> <img id="placeholder" src="images/placeholder.jpg" alt="Place Holder Image" /> </body> </html> And here is the JavaScript function I am using to get this done: <script type="text/javascript"> function showPic(whichpic) { var source = whichpic.getAttribute("href"); var placeholder = document.getElementById("placeholder"); placeholder.setAttribute("src",source); } </script> Any help is greatly appreciated and thanks in advance for the help.

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  • A detail question when applying genetic algorithm to traveling salesman

    - by burrough
    I read various stuff on this and understand the principle and concepts involved, however, none of paper mentions the details of how to calculate the fitness of a chromosome (which represents a route) involving adjacent cities (in the chromosome) that are not directly connected by an edge (in the graph). For example, given a chromosome 1|3|2|8|4|5|6|7, in which each gene represents the index of a city on the graph/map, how do we calculate its fitness (i.e. the total sum of distances traveled) if, say, there is no direct edge/link between city 2 and 8. Do we follow some sort of greedy algorithm to work out a route between 2 and 8, and add the distance of this route to the total? This problem seems pretty common when applying GA to TSP. Anyone who's done it before please share your experience. Thanks.

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  • DCOMCNFG Question...

    - by Tony
    Hello, I have a COM DLL that I registered via RegSvr32 but it does not show up in DComCnfg. Any help as to why? I think I am missing a few registry keys, but I do not understand why I would, i thought RegSvr32 did that for me. Thanks for any help.

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  • C++ question: boost::bind receive other boost::bind

    - by user355034
    I want to make this code work properly, what should I do? giving this error on the last line. what am I doing wrong? i know boost::bind need a type but i'm not getting. help class A { public: template <class Handle> void bindA(Handle h) { h(1, 2); } }; class B { public: void bindB(int number, int number2) { std::cout << "1 " << number << "2 " << number2 << std::endl; } }; template struct Wrap_ { Wrap_(Han h) : h_(h) {} template<typename Arg1, typename Arg2> void operator()(Arg1 arg1, Arg2 arg2) { h_(arg1, arg2); } Han h_; }; template inline Wrap_<Handler> make(Handler h) { return Wrap_<Handler> (h); } int main() { A a; B b; ((boost::bind)(&B::bindB, b, _1, _2))(1, 2); ((boost::bind)(&A::bindA, a, make(boost::bind(&B::bindB, b, _1, _2))))(); /i want compiled success and execute success this code/ }

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  • Question about Objective C calling convention and argument passing on ARM

    - by overboming
    I want to know how objective C runtime handle arguments when I call a objective C method like [NSString stringWithFomat:@"%@, %@", @"Hello", @"World"] There are three arguments for this objective C call, how does it work compared to typical way on a ARM system. I have known register r0, r1, r2, r3 will hold first 4 arguments, how about there are additional arguments? How does it put them on a stack and pop them later?

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  • SHELL OR PERL QUESTION

    - by user150674
    I have a very large file, named 'ColCheckMe', tab-delimited, that you are asked to process. You are told that each line in 'ColCheckMe' has 7 columns, and that the values in the 5th column are integers. Using shell functions indicate how you would verify that these conditions were satisfied in 'ColCheckMe' K got this... nawk ‘ NF != 7 { Printf(“[%d] has invalid [%d] number of fileds\n”, FNR, NF) } $5 !~ /^[0-9]+$/ { Printf(“[%d] 5th field is invalid [%s]\n”, FNR, $5) }’ ColCheckMe Now, 2. In with the similar file, you are told that each value in column 1 is unique. How would I verify that? Also write a shell function that counts the number of occurrences of the word “SpecStr” in the file 'ColCheckMe' Any one can help in SHELL or everything including the first in PERL Scripting.

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  • C++ Set Erase Entry Question

    - by Wallace
    Hi. I encountered a problem here. I'm using C++ multiset. This is the test file. Score: 3-1 Ben Steven Score: 1-0 Ben Score: 0-0 Score: 1-1 Cole Score: 1-2 Ben I'm using while loop and ifstream (fin1) to read in from the test file above. multiset<string, less<string> > myset; while(!fin1.eof()) { fin1 >> scoreName; if(scoreName == "Score:") { //calculates number of matches played } else { goalCheck = scoreName.substr(1,1); if(goalCheck == "-") { string lGoal, rGoal; lGoal = scoreName.substr(0,1); rGoal = scoreName.substr(2,1); int leftGoal, rightGoal; leftGoal = atoi(lGoal.c_str()); rightGoal = atoi(rGoal.c_str()); if(leftGoal > rightGoal) //if team wins { //some computations } else if(leftGoal < rightGoal) //if team loses { //computations } else if(leftGoal == rightGoal) //if team draws { //computations } else { myset.insert(myset.begin(), scoreName); } } } I'm inserting all names into myset (regardless of wins/loses/draws) in my last else statement. But I only require the names of those matches who won/draw. Those names whose matches lost will not be included in myset. In the test file above, there's only one match that lost (1-2) and I wanted to remove "Ben". How can I do that? I tried to use myset.erase(), but I'm not sure how to get it point to Ben and remove it from myset. Any help is much appreciated. Thanks.

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  • UILabel fade-in fade-out question

    - by Oscar Peli
    Hi there, I got the following code inside an NSTimer selector: [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:2.0]; [infoLbl setAlpha:0]; [UIView commitAnimations]; [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:2.0]; [infoLbl setAlpha:1]; [UIView commitAnimations]; So I want to implement a simple fade-in/fade-out loop upon a UILabel (infoLbl). Well, with this code I get only the fade-in step, since the UILabel suddenly disappear, then fades-in. Some suggestion? Thanks.

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  • Prolog : Simple question

    - by abduls85
    I want to add any strings user entered into a list run :- write('How many students you have: '),read(x),nl. enterNameOfStudents(x). enterNameOfStudents(x) :- for(A, 1, x, 1),write('Please enter the names of students'),read(A),??????,nl,fail. What do i put in the ?????? portion to ensure that whatever the user enter will go into a user-defined list which will be used for further processing later ? Please help. I have tried numerous stuff like append and other but it does not work :(

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