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  • Getting user data from Active Directory using PL/SQL

    - by David Neale
    I had a discussion today regarding an Oracle procedure I wrote some time ago. I wanted to get 7500 user email addresses from Active Directory using PL/SQL. AD will return a maximum of 1000 rows and the LDAP provider used by Oracle will not support paging. Therefore, my solution was to filter on the last two characters of the sAMAccountName (*00,*01,*02...etc.). This results in 126 queries (100 for account names ending in digits, 26 for those ending in a letter...this was sufficient for my AD setup). The person I was speaking to (it was a job interview by the way) said he could have done it a better way, but he would not tell me what that method was. Could anybody hazard a guess at what this method was?

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  • Need help in setting application name with JPA (EclipseLink)

    - by enrique
    hello everybody i am using JPA with EclipseLink and oracle as DB and i need to set the property v$session of jdbc4 it allows to set an identification name to the application for auditing purposes but i had no lucky setting it up....i have been trying through entitiyManager following the example in this page: http://wiki.eclipse.org/Configuring_a_EclipseLink_JPA_Application_(ELUG) it does not show any error but does not set the application name at all... when i see the audit in oracle it is not being audited with the name i set by code "Customers" but with OS_program_name=JDBC Thin Client it means that the property in the code is not being set properly and i have no idea where the issue is, the code i am using is the following : emProperties.put("v$session.program","Customers"); factory=Persistence.createEntityManagerFactory("clients",emProperties); em=factory.createEntityManager(emProperties); em.merge(clients); does anybody know how to do it or any idea.... thanks.-

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  • If don't own proprietary database engine, what is best way to convert database to mysql?

    - by John Robertson
    I work for a very small company. I was recently faced with the question of whether there is a good way to convert a proprietary database to a MySQL database without owning the proprietary database engine e.g. if one is given a large oracle database file (or choose your favorite proprietary database engine format), but doesn't have a license for the oracle database engine, is there a good, perfectly reliable way to convert it to a MySQL database format that can be read with the MySQL database engine? My question is very vague as to which proprietary format is the source just because there would be multiple sources and it looks like they would be "various and sundry". My suspicion is that there is no perfectly reliable way, especially for a wide variety of proprietary databases. If there are a few proprietary formats for which this is possible, I would still be interested in knowing, though "various and sundry" is probably the real issue. Minimizing cost, effort and correct conversion are key so I think this is probably is the not possible list. -John

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  • In SQL, what does Group By mean without Count(*), or Sum(), Max(), avg(), ..., and what are some use

    - by Jian Lin
    In SQL, if we use Group By without Count(*) or Sum(), etc, then the result is as follows: mysql> select * from sentGifts; +--------+------------+--------+------+---------------------+--------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | +--------+------------+--------+------+---------------------+--------+ | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | | 2 | 2010-04-24 | 123 | 4568 | 2010-04-24 01:56:04 | 100 | | 3 | 2010-04-24 | 123 | NULL | NULL | 1 | | 4 | 2010-04-24 | NULL | 111 | 2010-04-24 03:10:42 | 2 | | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | | 6 | 2010-04-24 | 11 | 222 | 2010-04-24 03:54:49 | 6 | | 7 | 2010-04-24 | 1 | 2 | 2010-04-24 03:58:45 | 6 | +--------+------------+--------+------+---------------------+--------+ 7 rows in set (0.00 sec) mysql> select *, count(*) from sentGifts group by whenSent; +--------+------------+--------+------+---------------------+--------+----------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | count(*) | +--------+------------+--------+------+---------------------+--------+----------+ | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | 1 | | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | 6 | +--------+------------+--------+------+---------------------+--------+----------+ 2 rows in set (0.00 sec) mysql> select * from sentGifts group by whenSent; +--------+------------+--------+------+---------------------+--------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | +--------+------------+--------+------+---------------------+--------+ | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | +--------+------------+--------+------+---------------------+--------+ 2 rows in set (0.00 sec) Only 1 row is returned per "group". What does it mean when there is no "Count(*)", etc when using "Group By", and what are it uses? thanks.

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  • issue when outputting an http:// address in a sub-array with json and php

    - by Patrick
    Im trying to achieve an output like this {"status":"ok","0":{"id":"11","title":"digg","url":"http://www.digg.com"}} but instead i am getting this {"status":"ok","0":{"id":"11","title":"digg","url":"http:\/\/www.digg.com"}} this is the php code im using to generate the json $links = array('id'=>'11','title'=>'digg','url'=>"http://www.digg.com"); $msg = array('status'=>'ok',$links); echo json_encode($msg); any idea what is causing this?

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  • Temporary intermediate table

    - by user289429
    In our project to generate massive reports in oracle we use some permanent table to hold intermediate results. For example to generate one report we run few queries and populate the table, at the final step we join the intermediate table with huge application tables. These intermediate tables are cleared for next report run. We have few concerns in performance areas. These intermediate tables are transactional and don't have statistics. Is it good idea to join these with application tables which are partitioned and have up to date statistics. We need these results stored in the intermediate tables to be available across requests from UI hence we are not in a position to use oracle provided temporary tables. Any thoughts on what could be done would be appreciated.

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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  • How to display multiple categories and products underneath each category?

    - by shin
    Generally there is a category menu and each link to a category page where shows all the items under that category. Now I need to show all the categories and products underneath with PHP/MySQL in the same page. So it will be like this. Category 1 description of category 1 item 1 item 2 .. Category 2 description of category 2 item 5 item 6 .. Category 3 description of category 3 item 8 item 9 ... ... I have category and product table in my database. But I am not sure how to proceed. CREATE TABLE IF NOT EXISTS `omc_product` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `thumbnail` varchar(255) NOT NULL, `image` varchar(255) NOT NULL, `product_order` int(11) DEFAULT NULL, `class` varchar(255) DEFAULT NULL, `grouping` varchar(16) DEFAULT NULL, `status` enum('active','inactive') NOT NULL, `category_id` int(11) NOT NULL, `featured` enum('none','front','webshop') NOT NULL, `other_feature` enum('none','most sold','new product') NOT NULL, `price` float(7,2) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; CREATE TABLE IF NOT EXISTS `omc_category` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `status` enum('active','inactive') NOT NULL, `parentid` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; I will appreciate your help. Thanks in advance.

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  • no ocijdbc10 in java.library.path

    - by B.Z.B
    Hey all, So I've been plagued by this issue, whenever I try to run my app in eclipse, I get this error. 2011-02-23 09:55:08,388 ERROR (com.xxxxx.services.factory.ServiceInvokerLocal:21) - java.lang.UnsatisfiedLinkError: no ocijdbc10 in java.library.path I've tried following the steps I found here with no luck. I've tried this on a XP VM as well as windows 7 (although in win 7 I get a different error, below) java.lang.UnsatisfiedLinkError: no ocijdbc9 in java.library.path I've made sure my oracle client was ok (by running TOAD) and I also re-added the classes12.jar / ojdbc14.jars to my WEB-INF/lib folder taken directly from my %ORACLE_HOME% folder (also re-added them to the lib path). I've also tried just adding the ojdbc14.jar without the classes12.jar. Any suggestions appreciated. In the XP VM I have my PATH variable set to C:\Program Files\Java\jdk1.6.0_24\bin;C:\ORACLE\product\10.2.0.1\BIN. I'm using Tomcat server 5.0

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  • Find all html characters in drop-down option text and replace them via jQuery

    - by Jon Harding
    I have a dropdown menu that pulls in text from a database column. The database column can include HTML mark-up. In the drop-down I obviously don't need that in the text. I am working on some jquery and it partially accomplished what I'm looking for. However, it seems to only be replacing the first instance of each character $('select option').each(function() { this.text = this.text.replace('&nbsp;', ' '); this.text = this.text.replace('<div>', '' ); this.text = this.text.replace('</div>', '' ); }); Here is the HTML for the drop-down: <select name="ctl00$SubPageBody$ClassList" id="ctl00_SubPageBody_ClassList"> <option value="196">Four Week Series: July 19, 2012, 11:00am-12:00pm&<div>July 26, 2012, 11:00am-12:00pm&nbsp;</div><div>August 2, 2012, 11:00am-12:00pm</div><div>August 9, 2012, 11:00am-12:00pm</div></option> </select>

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  • Better data-structure design

    - by Tempname
    Currently in my application I have a single table that is giving me a bit of trouble. The issue at hand is I have a value object that is mapped to this table. When the data is returned to me as an array of value objects, I have to then loop through this array and begin my recursion by matching the ParentID to parent ObjectID's. The column ParentID is either null (acts a parent) or it holds the value of an ObjectID. I know there has to be a better way to create this data structure so that I do not have to do recursive loops to match ParentID's with their ObjectID's. Any help with this is greatly appreciated. Here is the table in describe form: +----------------+------------------+------+-----+---------------------+-----------------------------+ | Field | Type | Null | Key | Default | Extra | +----------------+------------------+------+-----+---------------------+-----------------------------+ | ObjectID | int(11) unsigned | NO | PRI | NULL | auto_increment | | ObjectHeight | decimal(6,2) | NO | | NULL | | | ObjectWidth | decimal(6,2) | NO | | NULL | | | ObjectX | decimal(6,2) | NO | | NULL | | | ObjectY | decimal(6,2) | NO | | NULL | | | ObjectLabel | varchar(255) | NO | | NULL | | | TemplateID | int(11) unsigned | NO | MUL | NULL | | | ObjectTypeID | int(11) unsigned | NO | MUL | NULL | | | ParentID | int(11) unsigned | YES | MUL | NULL | | | CreationDate | datetime | YES | | 0000-00-00 00:00:00 | | | LastModifyDate | timestamp | YES | | NULL | on update CURRENT_TIMESTAMP | +----------------+------------------+------+-----+---------------------+-----------------------------+e

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  • Implications of trying to double free memory space in C

    - by SidNoob
    Here' my piece of code: #include <stdio.h> #include<stdlib.h> struct student{ char *name; }; int main() { struct student s; s.name = malloc(sizeof(char *)); // I hope this is the right way... printf("Name: "); scanf("%[^\n]", s.name); printf("You Entered: \n\n"); printf("%s\n", s.name); free(s.name); // This will cause my code to break } All I know is that dynamic allocation on the 'heap' needs to be freed. My question is, when I run the program, sometimes the code runs successfully. i.e. ./struct Name: Thisis Myname You Entered: Thisis Myname I tried reading this I've concluded that I'm trying to double-free a piece of memory i.e. I'm trying to free a piece of memory that is already free? (hope I'm correct here. If Yes, what could be the Security Implications of a double-free?) While it fails sometimes as its supposed to: ./struct Name: CrazyFishMotorhead Rider You Entered: CrazyFishMotorhead Rider *** glibc detected *** ./struct: free(): invalid next size (fast): 0x08adb008 *** ======= Backtrace: ========= /lib/tls/i686/cmov/libc.so.6(+0x6b161)[0xb7612161] /lib/tls/i686/cmov/libc.so.6(+0x6c9b8)[0xb76139b8] /lib/tls/i686/cmov/libc.so.6(cfree+0x6d)[0xb7616a9d] ./struct[0x8048533] /lib/tls/i686/cmov/libc.so.6(__libc_start_main+0xe6)[0xb75bdbd6] ./struct[0x8048441] ======= Memory map: ======== 08048000-08049000 r-xp 00000000 08:01 288098 /root/struct 08049000-0804a000 r--p 00000000 08:01 288098 /root/struct 0804a000-0804b000 rw-p 00001000 08:01 288098 /root/struct 08adb000-08afc000 rw-p 00000000 00:00 0 [heap] b7400000-b7421000 rw-p 00000000 00:00 0 b7421000-b7500000 ---p 00000000 00:00 0 b7575000-b7592000 r-xp 00000000 08:01 788956 /lib/libgcc_s.so.1 b7592000-b7593000 r--p 0001c000 08:01 788956 /lib/libgcc_s.so.1 b7593000-b7594000 rw-p 0001d000 08:01 788956 /lib/libgcc_s.so.1 b75a6000-b75a7000 rw-p 00000000 00:00 0 b75a7000-b76fa000 r-xp 00000000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fa000-b76fc000 r--p 00153000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fc000-b76fd000 rw-p 00155000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fd000-b7700000 rw-p 00000000 00:00 0 b7710000-b7714000 rw-p 00000000 00:00 0 b7714000-b7715000 r-xp 00000000 00:00 0 [vdso] b7715000-b7730000 r-xp 00000000 08:01 788898 /lib/ld-2.11.1.so b7730000-b7731000 r--p 0001a000 08:01 788898 /lib/ld-2.11.1.so b7731000-b7732000 rw-p 0001b000 08:01 788898 /lib/ld-2.11.1.so bffd5000-bfff6000 rw-p 00000000 00:00 0 [stack] Aborted So why is it that my code does work sometimes? i.e. the compiler is not able to detect at times that I'm trying to free an already freed memory. Has it got to do something with my stack/heap size?

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  • How to have partial incremental synchronizations based on a GUID?

    - by Gonçalo Veiga
    I need to synchronize an SQL Server database to Oracle through an Oracle Transparent Gateway. The synchronization is performed in batches, so I need to get the next set of data from the point where I left off. The problem I'm having is that the only field I have in the source, to help me, is a GUID. If it were a number I could just order by it, keep the last one processed and restart the process by getting the records which are my recorded number. This won't work with a GUID. Any ideas?

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  • How do I add values from two separate queries in SQL

    - by fishhead
    Below is my attempt at adding two values from separate select statements...it's not working, and I can't see why. I'm looking for some direction. select (v1.Value + v2.Value) as total from ( (Select Max(Value) as [Value] from History WHERE Datetime>='Apr 11 2010 6:05AM' and Datetime<='Apr 11 2010 6:05PM' and Tagname ='RWQ272017DTD' ) as v1 (Select Max(Value) as [Value] from History WHERE Datetime>='Apr 11 2010 6:05AM' and Datetime<='Apr 11 2010 6:05PM' and Tagname ='RU282001DTD' ) as v2 ) EDIT: Boy do I feel foolish...I asked the same question a few days ago...now I can't delete this.

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  • PL/SQL exception and Java programs

    - by edwards
    Hi Business logic is coded in pl/sql packages procedures and functions. Java programs call pl/sql packages procedures and functions to do database work. pl/sql programs store exceptions into Oracle tables whenever an exception is raised. How would my java programs get the exceptions since the exception instead of being propagated from pl/sql to java is getting persisted to a oracle table and the procs/functions just return 1 or 0. Sorry folks i should have added this constraint much earlier and avoided this confusion. As with many legacy projects we don't have the freedom to modify the stored procedures.

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  • Query to sum duplicated fields

    - by g0sha
    Here is mysql data id usr good quant delayed cart_ts ------------------------------------------------------ 14 4 1 1 0 20100601235348 13 4 11 1 0 20100601235345 12 4 4 1 0 20100601235335 11 4 1 1 0 20100601235051 10 4 11 1 0 20100601235051 9 4 4 1 0 20100601235051 15 4 2 1 0 20100601235350 16 4 7 1 0 20100602000537 17 4 3 1 0 20100602000610 18 4 3 1 0 20100602000616 19 4 8 1 0 20100602000802 20 4 8 1 0 20100602000806 21 4 8 1 0 20100602000828 22 4 8 1 0 20100602000828 23 4 8 1 0 20100602000828 24 4 8 1 0 20100602000828 25 4 8 1 0 20100602000828 26 4 8 1 0 20100602000829 27 4 8 1 0 20100602000829 28 4 9 1 0 20100602001045 29 4 10 1 0 20100602001046 I need to group fields in witch usr & good has duplicated values with summing quant field for getting smth like this: id usr good quant delayed cart_ts ------------------------------------------------------ 14 4 1 2 0 20100601235348 13 4 11 2 0 20100601235345 12 4 4 2 0 20100601235335 15 4 2 1 0 20100601235350 16 4 7 1 0 20100602000537 17 4 3 2 0 20100602000610 19 4 8 9 0 20100602000802 28 4 9 1 0 20100602001045 29 4 10 1 0 20100602001046 Which MySQL query I need to do to have this effect?

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  • MySQL: Combining multiple where conditions

    - by Karl
    I'm working on a menu system that takes a url and then queries the db to build the menu. My menu table is: +---------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | node_id | int(11) | YES | | NULL | | | parent | int(11) | YES | | NULL | | | weight | int(11) | YES | | NULL | | | title | varchar(250) | YES | | NULL | | | alias | varchar(250) | YES | | NULL | | | exclude | int(11) | YES | | NULL | | +---------+--------------+------+-----+---------+----------------+ The relevant columns for my question are alias, parent and node_id. So for a url like: http://example.com/folder1/folder2/filename Alias would potentially = "filename", "folder1", "folder2" Parent = the node_id of the parent folder. What I know is how to split the url up into an array and check the alias for a match to each part. What I don't know is how to have it then filter by parent whose alias matches "folder2" and whose parent alias matches "folder1". I'm imagining a query like so: select * from menu where alias='filename' and where parent = node_id where alias='folder2' and parent = node_id where alias='folder1' Except I know that the above is wrong. I'm hoping this can be done in a single query. Thanks for any help in advance!

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  • How do I use Perl to parse the output of the sqlplus command?

    - by benjamin button
    I have an SQL file which will give me an output like below: 10|1 10|2 10|3 11|2 11|4 . . . I am using this in a Perl script like below: my @tmp_cycledef = `sqlplus -s $connstr \@DLCycleState.sql`; after this above statement, since @tmp_cycledef has all the output of the SQL query, I want to show the output as: 10 1,2,3 11 2,4 How could I do this using Perl?

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  • A hard Question ?

    - by the-ifl
    Hi Guys , I try To find a solution to a question .... we have a number , example : 20 ... and we have 6 number :{ a ,b , c , d , e , f} < 20 , t try to find all values of these numbers , but only if we can combinate (whit + or -) whit 2 of this numbers and getting all the value below to 20 : for example we choose 31 : a = 22 b = 21 c = 14 d = 11 e = 9 f = 5 we have : 22 - 21 = 1 ; 11 - 9 = 2 ; 14 - 11 = 3 ; 9 - 5 = 4 ; f = 5 ; 11 - 5 = 6 ; 21 - 14 = 7 ; .... .... .... .... .... 21 + 9 = 30 ; 9 + 22 = 31 ;

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  • Cannot add or update a child row: a foreign key constraint fails

    - by Tom
    table 1 +----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------+-------------+------+-----+---------+----------------+ | UserID | int(11) | NO | PRI | NULL | auto_increment | | Password | varchar(20) | NO | | | | | Username | varchar(25) | NO | | | | | Email | varchar(60) | NO | | | | +----------+-------------+------+-----+---------+----------------+ table2 +------------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------+----------------+ | UserID | int(11) | NO | MUL | | | | PostID | int(11) | NO | PRI | NULL | auto_increment | | Title | varchar(50) | NO | | | | | Summary | varchar(500) | NO | | | | +------------------+--------------+------+-----+---------+----------------+ com.mysql.jdbc.exceptions.MySQLIntegrityConstraintViolationException: Cannot add or update a child row: a foreign key constraint fails (myapp/table2, CONSTRAINT table2_ibfk_1 FOREIGN KEY (UserID) REFERENCES table1 (UserID)) What have I done wrong? I read this: http://www.w3schools.com/Sql/sql_foreignkey.asp and i don't see whats wrong. :S

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  • Significance of date 02/31/2157?

    - by dpatchery
    I work in a large scale IT support environment. Twice now we have seen an invalid date of 02/31/2157 being inserted in an Oracle DATE column. So far I have not been able to reproduce this problem, but it appears to be happening occasionally when a user attempts to save '00/00/0000' into the column. I believe the value is originating from a PowerBuilder DataWindow update. The application uses myriad libraries for all sorts of technologies, so this question may be a bit vague, but... Has anyone seen the date 02/31/2157 in some established library that Oracle could be defaulting to when some other invalid date is entered? Perhaps an end-of-time concept analogous to the beginning-of-time date of 1/1/1970?

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  • How can I read a continuously updating log file in Perl?

    - by Octopus
    I have a application generating logs in every 5 sec. The logs are in below format. 11:13:49.250,interface,0,RX,0 11:13:49.250,interface,0,TX,0 11:13:49.250,interface,1,close,0 11:13:49.250,interface,4,error,593 11:13:49.250,interface,4,idle,2994215 and so on for other interfaces... I am working to convert these into below CSV format: Time,interface.RX,interface.TX,interface.close.... 11:13:49,0,0,0,.... Simple as of now but the problem is, I have to get the data in CSV format online, i.e as soon the log file updated the CSV should also be updated. What I have tried to read the output and make the header is: #!/usr/bin/perl -w use strict; use File::Tail; my $head=["Time"]; my $pos={}; my $last_pos=0; my $current_event=[]; my $events=[]; my $file = shift; $file = File::Tail->new($file); while(defined($_=$file->read)) { next if $_ =~ some filters; my ($time,$interface,$count,$eve,$value) = split /[,\n]/, $_; my $key = $interface.".".$eve; if (not defined $pos->{$eve_key}) { $last_pos+=1; $pos->{$eve_key}=$last_pos; push @$head,$eve; } print join(",", @$head) . "\n"; } Is there any way to do this using Perl?

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  • Need MYSQL query for finding lowest score per game player

    - by Chris Barnhill
    I have a game on Facebook called Rails Across Europe. I have a Best Scores page where I show the players with the best 20 scores, which in game terms refers to the lowest winning turn. The problem is that there are a small number of players who play frequently, and their scores dominate the page. I'd like to make the scores page open to more players. So I thought that I could display the single lowest winning turn for each player instead of displaying all of the lowest winning turns for all players. The problem is that the query for this eludes me. So I hope that one of you brilliant StackOverflow folks can help me with this. I have included the relevant MYSQL table schemas below. Here are the the table relationships: player_stats contains statistics for either a game in progress or a completed game. If a game is in progress, winning_turn is zero (which means that games with a winning_turn of zero should not be included in the query). player_stats has a game_player table id reference. game_player contains data describing games currently in progress. game_player has a player table id reference. player contains data describing a person who plays the game. Here's the query I'm currently using: 'SELECT p.fb_user_id, ps.winning_turn, gp.difficulty_level, c.name as city_name, g.name as goods_name, d.cost FROM game_player as gp, player as p, player_stats as ps, demand as d, city as c, goods as g WHERE p.status = "ACTIVE" AND gp.player_id = p.id AND ps.game_player_id = gp.id AND d.id = ps.highest_demand_id AND c.id = d.city_id AND g.id = d.goods_id AND ps.winning_turn > 0 ORDER BY ps.winning_turn ASC, d.cost DESC LIMIT '.$limit.';'; Here are the relevant table schemas: -- -- Table structure for table `player_stats` -- CREATE TABLE IF NOT EXISTS `player_stats` ( `id` int(11) NOT NULL auto_increment, `game_player_id` int(11) NOT NULL, `winning_turn` int(11) NOT NULL, `highest_demand_id` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `game_player_id` (`game_player_id`,`highest_demand_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `game_player` -- CREATE TABLE IF NOT EXISTS `game_player` ( `id` int(10) unsigned NOT NULL auto_increment, `game_id` int(10) unsigned NOT NULL, `player_id` int(10) unsigned NOT NULL, `player_number` int(11) NOT NULL, `funds` int(10) unsigned NOT NULL, `turn` int(10) unsigned NOT NULL, `difficulty_level` enum('STANDARD','ADVANCED','MASTER','ULTIMATE') NOT NULL, `date_last_used` datetime NOT NULL, PRIMARY KEY (`id`), KEY `game_id` (`game_id`,`player_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `player` -- CREATE TABLE IF NOT EXISTS `player` ( `id` int(11) NOT NULL auto_increment, `fb_user_id` char(255) NOT NULL, `fb_proxied_email` text NOT NULL, `first_name` char(255) NOT NULL, `last_name` char(255) NOT NULL, `birthdate` date NOT NULL, `date_registered` datetime NOT NULL, `date_last_logged_in` datetime NOT NULL, `status` enum('ACTIVE','SUSPENDED','CLOSED') NOT NULL, PRIMARY KEY (`id`), KEY `fb_user_id` (`fb_user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=1646 ;

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