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  • How to show jQuery is working/waiting/loading ?

    - by Kim
    How do I show a loading picture and/or message to the user ? If possible, would I like to know how to make it full screen with grey-dimmed background. Kinda like when viewing the large picture from some galleries (sorry, no example link). Currently do I add a CSS class which has the image and other formating, but its not working for some reason. Results from the search do get inserted into the div. HTML <div id="searchresults"></div> CSS div.loading { background-image: url('../img/loading.gif'); background-position: center; width: 80px; height: 80px; } JS $(document).ready(function(){ $('#searchform').submit(function(){ $('#searchresults').addClass('loading'); $.post('search.php', $('#'+this.id).serialize(),function(result){ $('#searchresults').html(result); }); $('#searchresults').removeClass('loading'); return false; }); });

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  • ASP.NET MVC Newbie: why isn't my model available when creating a strongly-typed view?

    - by Rax Olgud
    I'm starting with ASP.NET MVC, and working with NerdDinner as reference. I did the following: Created a new project Added a couple of tables Created LINQ to SQL for them Created a new controller My Models directory now contains MyModel.dbml, under which I have MyModel.designer.cs, that contains classes for models relating to both of my tables (let's call them Categories and Products). Now, under my new controller, I would like to create a strongly typed view. So for example I have the following code in my controller (for my application I must work by name, and the "Name" field is unique): public ActionResult Details(string name) { MyModelDataContext db = new MyModelDataContext(); Product user = db.Products.Single(t => t.Name == name); return View(user); } I would like to create a strongly-typed view. So I right-click the line "return View(user)", and choose "Add View...". I click "Create a strongly-typed view". When I click the dropdown of "View data class", I don't see my models, but only: MyProject.Controllers.AccountMembershipService MyProject.Controllers.FormsAuthenticationService What am I missing?

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  • Hibernate design to speed up querying of large dataset

    - by paddydub
    I currently have the below tables representing a bus network mapped in hibernate, accessed from a Spring MVC based bus route planner I'm trying to make my route planner application perform faster, I load all the above tables into Lists to perform the route planner logic. I would appreciate if anyone has any ideas of how to speed my performace Or any suggestions of another method to approach this problem of handling a large set of data Coordinate Connections Table (INT,INT,INT, DOUBLE)( Containing 50,000 Coordinate Connections) ID, FROMCOORDID, TOCOORDID, DISTANCE 1 1 2 0.383657 2 1 17 0.173201 3 1 63 0.258781 4 1 64 0.013726 5 1 65 0.459829 6 1 95 0.458769 Coordinate Table (INT,DECIMAL, DECIMAL) (Containing 4700 Coordinates) ID , LAT, LNG 0 59.352669 -7.264341 1 59.352669 -7.264341 2 59.350012 -7.260653 3 59.337585 -7.189798 4 59.339221 -7.193582 5 59.341408 -7.205888 Bus Stop Table (INT, INT, INT)(Containing 15000 Stops) StopID RouteID COORDINATEID 1000100001 100 17 1000100002 100 18 1000100003 100 19 1000100004 100 20 1000100005 100 21 1000100006 100 22 1000100007 100 23 This is how long it takes to load all the data from each table: stop.findAll = 148ms, stops.size: 15670 Hibernate: select coordinate0_.COORDINATEID as COORDINA1_2_, coordinate0_.LAT as LAT2_, coordinate0_.LNG as LNG2_ from COORDINATES coordinate0_ coord.findAll = 51ms , coordinates.size: 4704 Hibernate: select coordconne0_.COORDCONNECTIONID as COORDCON1_3_, coordconne0_.DISTANCE as DISTANCE3_, coordconne0_.FROMCOORDID as FROMCOOR3_3_, coordconne0_.TOCOORDID as TOCOORDID3_ from COORDCONNECTIONS coordconne0_ coordinateConnectionDao.findAll = 238ms ; coordConnectioninates.size:48132 Hibernate Annotations @Entity @Table(name = "STOPS") public class Stop implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "STOPID") private int stopID; @Column(name = "ROUTEID", nullable = false) private int routeID; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "COORDINATEID", nullable = false) private Coordinate coordinate; } @Table(name = "COORDINATES") public class Coordinate { @Id @GeneratedValue @Column(name = "COORDINATEID") private int CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Entity @Table(name = "COORDCONNECTIONS") public class CoordConnection { @Id @GeneratedValue @Column(name = "COORDCONNECTIONID") private int CoordinateID; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "FROMCOORDID", nullable = false) private Coordinate fromCoordID; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "TOCOORDID", nullable = false) private Coordinate toCoordID; @Column(name = "DISTANCE", nullable = false) private double distance; }

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  • Understanding many to many relationships and Entity Framework

    - by Anders Svensson
    I'm trying to understand the Entity Framework, and I have a table "Users" and a table "Pages". These are related in a many-to-many relationship with a junction table "UserPages". First of all I'd like to know if I'm designing this relationship correctly using many-to-many: One user can visit multiple pages, and each page can be visited by multiple users..., so am I right in using many2many? Secondly, and more importantly, as I have understood m2m relationships, the User and Page tables should not repeat information. I.e. there should be only one record for each user and each page. But then in the entity framework, how am I able to add new visits to the same page for the same user? That is, I was thinking I could simply use the Count() method on the IEnumerable returned by a LINQ query to get the number of times a user has visited a certain page. But I see no way of doing that. In Linq to Sql I could access the junction table and add records there to reflect added visits to a certain page by a certain user, as many times as necessary. But in the EF I can't access the junction table. I can only go from User to a Pages collection and vice versa. I'm sure I'm misunderstanding relationships or something, but I just can't figure out how to model this. I could always have a Count column in the Page table, but as far as I have understood you're not supposed to design database tables like that, those values should be collected by queries... Please help me understand what I'm doing wrong...

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  • LEFT OUTER JOIN with a WHERE clause

    - by Wesley
    I have two tables. indRailType contains a list of the names paired with an ID value that I use in other tables to indicate the rail type. WO_BreakerRail contains a date column and a rail code colume that corresponds to the same code in indRailType and some other data. There's a row in WO_BreakerRail for any activity on each rail type, for every date. So I could have 3 rows dated for 3/19/2010, each row indicates a different rail code, and what happened. When I use the following LEFT OUTER JOIN, I get a table with all the types of rail, with nulls in the rows where nothing happened on the 19th. Now, this is only working because I only have one date represented in my WO_BreakerRail table right now, the 19th. When I add more rows with different dates, things will go haywire. This is my SQL statement, which right now gives me exactly the results I want: SELECT WO_BreakerRail.ID, indRailType.RailType, WO_BreakerRail.CreatedPieces, WO_BreakerRail.OutsideSource, WO_BreakerRail.Charged, WO_BreakerRail.Rejected, WO_BreakerRail.RejectedToCrop FROM indRailType LEFT OUTER JOIN WO_BreakerRail ON indRailType.RailCode = WO_BreakerRail.RailCode Now, when I add in a WHERE WO_BreakerRail.Date = @Date clause I lose all the rows in the JOIN which nothing happened. I don't want that. From reading up, it sounds like a FULL OUTER JOIN is what I want, but SQL Server Compact Edition doesn't support FULL OUTER JOINs. Is there a way around this, or am I looking for something else entirely?

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  • How do I write this MySQL query?

    - by CT
    I am working on an Asset DB using a lamp stack. In this example consider the following 5 tables: asset, server, laptop, desktop, software All tables have a primary key of id, which is a unique asset id. Every object has all asset attributes and then depending on type of asset has additional attributes in the corresponding table. If the type is a server, desktop or laptop it also has items in the software table. Here are the table create statements: // connect to mysql server and database "asset_db" mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); // create asset table mysql_query("CREATE TABLE asset( id VARCHAR(50) PRIMARY KEY, company VARCHAR(50), location VARCHAR(50), purchase_date VARCHAR(50), purchase_order VARCHAR(50), value VARCHAR(50), type VARCHAR(50), notes VARCHAR(200))") or die(mysql_error()); echo "Asset Table Created.</br />"; // create software table mysql_query("CREATE TABLE software( id VARCHAR(50) PRIMARY KEY, software VARCHAR(50), license VARCHAR(50))") or die(mysql_error()); echo "Software Table Created.</br />"; // create laptop table mysql_query("CREATE TABLE laptop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Laptop Table Created.</br />"; // create desktop table mysql_query("CREATE TABLE desktop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Desktop Table Created.</br />"; // create server table mysql_query("CREATE TABLE server( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Server Table Created.</br />"; ?> How do I query the database so that if I search by id, I receive all related fields to that asset id? Thank you.

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  • Add delay and focus for a dead simple accordion jquery

    - by kuswantin
    I found the code somewhere in the world, and due to its dead simple nature, I found some things in need to fix, like when hovering the trigger, the content is jumping up down before it settled. I have tried to change the trigger from the title of the accordion block to the whole accordion block to no use. I need help to add a delay and only do the accordion when the cursor is focus in the block. I have corrected my css to make sure the block is covering the hidden part as well when toggled. Here is my latest modified code: var acTrig = ".accordion .title"; $(acTrig).hover(function() { $(".accordion .content").slideUp("normal"); $(this).next(".content").slideDown("normal"); }); $(acTrig).next(".content").hide(); $(acTrig).next(".content").eq(0).css('display', 'block'); This is the HTML: <div class="accordion clearfix"> <div class="title">some Title 1</div> <div class="content"> some content blah </div> </div> <div class="accordion clearfix"> <div class="title">some Title 2</div> <div class="content"> some content blah </div> </div> <div class="accordion clearfix"> <div class="title">some Title 3</div> <div class="content"> some content blah </div> </div> I think I need a way to stop event bubbling somewhere around the code, but can't get it right. Any help would be very much appreciated. Thanks as always.

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  • Why is this bookmarklet code saying jQuery is not defined even though jQuery is included?

    - by Josh Brown
    I am creating a bookmarklet and the code below is not working on first try. When I goto a page, it says "jQuery is not defined". But, if I click it again, it works perfectly? var qrcodetogo = { jQURL: 'http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js', jQUIURL: 'http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/jquery-ui.min.js', jQUIThemeURL: 'http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/themes/ui-lightness/jquery-ui.css', init: function(){ this.createLink('qrcodetogo_UI-Lightness', this.jQUIThemeURL); this.createScript('qrcodetogo_jQuery', this.jQURL); this.createScript('qrcodetogo_jQueryUI', this.jQUIURL); this.createHiddenDiv('qrcodetogo_dialog','This is a Test.'); jQuery.noConflict(); }, showQRCode: function() { jQuery('#qrcodetogo_dialog').dialog(); }, createLink: function(id, url) { var l = document.createElement('link'); l.href = url; l.rel = 'stylesheet'; l.type = 'text/css'; l.media = 'screen'; l.charset = 'utf-8'; document.getElementsByTagName('head')[0].appendChild(l); }, createScript: function(id, url) { var s = document.createElement('script'); s.src = url; s.id = id; document.getElementsByTagName('head')[0].appendChild(s); }, createHiddenDiv: function(id, body) { var div = document.createElement('div'); div.id = id; div.innerHTML = body; div.style.display = 'none'; document.getElementsByTagName('body')[0].appendChild(div) } } qrcodetogo.init(); qrcodetogo.showQRCode();

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  • Many to many table design question

    - by user169867
    Originally I had 2 tables in my DB, [Property] and [Employee]. Each employee can have 1 "Home Property" so the employee table has a HomePropertyID FK field to Property. Later I needed to model the situation where despite having only 1 "Home Property" the employee did work at or cover for multiple properties. So I created an [Employee2Property] table that has EmployeeID and PropertyID FK fields to model this many 2 many relationship. Now I find that I need to create other many-to-many relationships between employees and properties. For example if there are multiple employees that are managers for a property or multiple employees that perform maintenance work at a property, etc. My questions are: 1) Should I create seperate many-to-many tables for each of these situations or should I just create 1 more table like [PropertyAssociatonType] that lists the types of associations an emploee can have with a property and just add a FK field to [Employee2Property] such a PropertyAssociationTypeID that explains what the association is? I'm curious about the pros/cons or if there's another better way. 2) Am I stupid and going about this all worng? Thanks for any suggestions :)

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  • Create bookmark into 1st column of MSWord table

    - by MikeD
    Hello All, does anyone have a VBA code to create a bookmark into the first column of an MSWord table? Let's say I have a table looking like this .-----.----------------. . ref . Title . .-----.----------------. . 1 . Title 1 . .-----.----------------. . 2 . Title 2 . .-----.----------------. . foo . Title 3 . .-----.----------------. . bar . Title 4 . .-----.----------------. and I want a VBA code fragment that creates a bookmark named "T1_1" on the string "1" in row 2 / column 1, and bookmarks named "T1_2", "T1_foo" and "T1_bar" on the strings in the other cells of column 1. I don't mind to hardcode the prefix "T1" (and substitute for other tables each time). I don't mind to select tables before running the macro, I don't mind giving those cells a special format, and I don't mind to get a superfluous bookmark "T1_ref" from the first row - so the code doesn't need to distinguish between table title and table row. Thanks a lot in advance

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  • SQL UNION ALL with a INNER JOIN

    - by kOhm
    I'm looking for the best way to display all rows from two tables while joining first by one field (dwg) then where applicable a 2nd join on part. Table1 data consists of schematics(dwg) along with a list of parts required to build the item depicted in the drawing. Table2 consists of data about the actual parts ordered to build the schematic. Some parts in table2 are a combination of parts in table1 (ex: foo and bar in table1 were ordered as foobar in table2). I can display all rows in both tables with UNION ALL, but this doesn't join on both the dwg and part fields. I looked at FULL OUTER JOIN also, but I haven't figured out how to join first by dwg, then by part. Here is an example of the data. table1 table2 dwg part qty order dwg part qty ----- ----- ----- ----- ----- ----- ----- 123 foo 1 ord1 123 foobar 1 123 bar 1 ord1 123 bracket 2 123 widget 2 ord2 123 screw 4 123 bracket 4 ord2 123 nut 4 456 foo 1 ord2 123 widget 2 ord2 123 bracket 2 ord3 456 foo 1 Desired output: The goal is to create a view that provides visibility to all parts in table1 and the associated orders in table2 (including those parts that appear in one but not the other table) so that I can see all the drawing parts in table1 and the associated records in table2 along with records in table2 where the part wasn't in table1. part_request_order_report dwg part qty order part qty ----- ----- ----- ------ ----- ----- 123 foo 1 123 bar 1 123 widget 2 ord2 widget 2 123 bracket 4 ord1 bracket 2 123 bracket 4 ord2 bracket 2 123 ord1 foobar 1 123 ord1 screw 4 123 ord1 nut 4 456 foo 1 ord3 foo 1 Is this possible? Or am I better off iterating through the data to build the report table? Thanks in advance.

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  • python packaging causes importerror

    - by Absolute0
    I am getting an annoying import error when I try to import a variable in an init.py file. I have attached the files involved and my directory structure: #/home/me/app/app/__init__.py from flaskext.sqlalchemy import SQLAlchemy db = SQLAlchemy(app) #/home/me/app/app/models/__init__.py from datetime import datetime from app import db #shell [me@archlinux app]$ pwd /home/me/app [me@archlinux app]$ ./manage.py /home/me/app/app/__init__.pyc Traceback (most recent call last): File "./manage.py", line 7, in <module> from app import app File "/home/me/app/app/__init__.py", line 3, in <module> from app.views.post import post File "/home/me/app/app/views/post.py", line 4, in <module> from app.models import Post File "/home/me/app/app/models/__init__.py", line 5, in <module> from app import db ImportError: cannot import name db [me@archlinux app]$ tree . +-- apikey.txt +-- manage.py +-- app ¦   +-- forms ¦   ¦   +-- __init__.py ¦   ¦   +-- __init__.py~ ¦   +-- __init__.py ¦   +-- __init__.py~ ¦   +-- __init__.pyc ¦   +-- models ¦   ¦   +-- __init__.py ¦   ¦   +-- __init__.py~ ¦   ¦   +-- __init__.pyc ¦   +-- static ¦   ¦   +-- css ¦   ¦   ¦   +-- style.css ¦   ¦   +-- images ¦   ¦   ¦   +-- favicon.png ¦   ¦   ¦   +-- logo.png ¦   ¦   ¦   +-- text_logo.png ¦   ¦   ¦   +-- thumb_down_active.png ¦   ¦   ¦   +-- thumb_down_inactive.png ¦   ¦   ¦   +-- thumb_up_active.png ¦   ¦   ¦   +-- thumb_up_inactive.png ¦   ¦   +-- js ¦   ¦   ¦   +-- index.js ¦   ¦   +-- sitemap.xml ¦   +-- templates ¦   ¦   +-- 404.html ¦   ¦   +-- 500.html ¦   ¦   +-- about.html ¦   ¦   +-- base.html ¦   ¦   +-- feedback ¦   ¦   ¦   +-- feedback_form.html ¦   ¦   +-- form.html ¦   ¦   +-- posts ¦   ¦   ¦   +-- comment.html ¦   ¦   ¦   +-- post.html ¦   ¦   ¦   +-- posts.html ¦   ¦   +-- spam.html ¦   ¦   +-- terms.html ¦   ¦   +-- users ¦   ¦   +-- login_form.html ¦   ¦   +-- sign_up_form.html ¦   +-- util ¦   ¦   +-- forms.py ¦   ¦   +-- honeypot.py ¦   ¦   +-- __init__.py ¦   ¦   +-- __init__.py~ ¦   ¦   +-- json_http.py ¦   ¦   +-- models.py ¦   ¦   +-- spam.py ¦   +-- views ¦   +-- feedback.py ¦   +-- __init__.py ¦   +-- __init__.pyc ¦   +-- post.py ¦   +-- post.pyc ¦   +-- user.py +-- settings.py +-- settings.pyc +-- TiddlyWiki.html 13 directories, 49 files What might be the problem?

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  • Database design MySQL using foreign keys

    - by dscher
    I'm having some a little trouble understanding how to handle the database end of a program I'm making. I'm using an ORM in Kohana, but am hoping that a generalized understanding of how to solve this issue will lead me to an answer with the ORM. I'm writing a program for users to manage their stock research information. My tables are basically like so: CREATE TABLE tags( id INT AUTO_INCREMENT NOT NULL PRIMARY KEY, tags VARCHAR(30), UNIQUE(tags) ) ENGINE=INNODB DEFAULT CHARSET=utf8; CREATE TABLE stock_tags( id INT AUTO_INCREMENT NOT NULL PRIMARY KEY, tag_id INT NOT NULL, stock_id INT NOT NULL, FOREIGN KEY (tag_id) REFERENCES tags(id), FOREIGN KEY(stock_id) REFERENCES stocks(id) ON DELETE CASCADE ) ENGINE=INNODB DEFAULT CHARSET=utf8; CREATE TABLE notes( id INT AUTO_INCREMENT NOT NULL, stock_id INT NOT NULL, notes TEXT NOT NULL, FOREIGN KEY (stock_id) REFERENCES stocks(id) ON DELETE CASCADE, PRIMARY KEY(id) ) ENGINE=INNODB DEFAULT CHARSET=utf8; CREATE TABLE links( id INT AUTO_INCREMENT NOT NULL, stock_id INT NOT NULL, links VARCHAR(2083) NOT NULL, FOREIGN KEY (stock_id) REFERENCES stocks(id) ON DELETE CASCADE, PRIMARY KEY(id) ) ENGINE=INNODB DEFAULT CHARSET=utf8; How would I get all the attributes of a single stock, including its links, notes, and tags? Do I have to add links, notes, and tags columns to the stocks table and then how do you call it? I know this differs using an ORM and I'd assume that I can use join tables in SQL. Thanks for any help, this will really help me understand the issue a lot better.

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  • jQuery .html not writing span on page load, rights the span on ajax response

    - by pedalpete
    I've got a bit of a calendar I'm building with events that go beyond the boundary of one day. I've got a graph which shows how many events are running concurrently. In order to graph out the events which go into another day, I look for hours24, and run an extra bit of code. jQuery('li#hour'+placeGroup+'_'+schedDay2+'_'+thisHour,nextDay).data('count', numStaff).html(''+printHour+''+numEvents+' scheduled').css('height',numEvents*5+'px'); The code is working, the li items are being found, proper height is the css is being applied, data is set, which I've checked by running alert(jQuery('li#hour'+placeGroup+'_'+schedDay2+'_'+thisHour,nextDay).data('count')); right after the pervious bit of code. The only thing that isn't being done is the .html(add span) stuff. I run this code in two places. Once when the page loads, and once when an action is taken which changes the number of events via an ajax response. The li DOM object I'm writting to is created before the script is run, and the height is being applied, but not the span, and only on page load. Any ideas on this one? I'm stumped.

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  • How to show a server side error message in a popup using php

    - by Fero
    Hi all, I found some of the similar questions here but they are all in C#. So kindly tell me the easiest way to show the server side error message using popup. The popup may be anything like thickbox, modalpopup etc... Here is the sample code. I didn't get the error message in the popup. <script type="text/javascript" src="thickbox/jquery-latest.js"></script> <script type="text/javascript" src="thickbox/thickbox.js"></script> <link href="thickbox/thickbox.css" rel="stylesheet" type="text/css" /> <span class="prtexterror" style="color:#FF0000;display:none;" id="hiddenModalContent" >{$error_login}</span> {literal} <script language="javascript" type="text/javascript"> $(document).ready(function() { tb_show("Please, login", "?tb_inline=true&inlineId=hiddenModalContent&height=180&width=300&modal=true", null); }); </script> {/literal} Any other ways are always welcome. thanks in advance

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  • How to sort an XML file by date in XLST

    - by AdRock
    I am trying to sort by date and get an error message about the stylesheet can't be loaded I found an answer on how others have suggested but it doesn't work for me Here is where it is supposed to sort. The commented out line is where the sort should occur <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template name="hoo" match="/"> <html> <head> <title>Registered Festival Organisers and Festivals</title> <link rel="stylesheet" type="text/css" href="userfestival.css" /> </head> <body> <h1>Registered Festival Organisers and Festivals</h1> <xsl:for-each select="folktask/member"> <xsl:if test="user/account/userlevel='3'"> <!--<xsl:sort select="concat(substring(festival/event/datefrom,1,4),substring(festival/event/datefrom, 6,2),substring(festival/event/datefrom, 9,2))" data-type="number" order="ascending"/>--> Sample node from XML <festival id="1"> <event> <eventname>Oxford Folk Festival</eventname> <url>http://www.oxfordfolkfestival.com/</url> <datefrom>2010-04-07</datefrom> <dateto>2010-04-09</dateto> <location>Oxford</location> <eventpostcode>OX1 9BE</eventpostcode> <coords> <lat>51.735640</lat> <lng>-1.276136</lng> </coords> </event> </festival>

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  • Jquery draggable not working in chrome/safari

    - by jbatson
    I have created a page that uses ajax calls to load product images. The jquery code for drag, drop and clone would not work when in the index.php page so I moved it to the page that gets called to request the products as each product has drag, drop code created for it. Works fine in FF, even IE but not in Safari or Chrome. Below is the jquery code in load_products.php that gets created when the ajax call is made to load the products. http://tandyleatherfactory.net/ Anyone have any idea why wouldn't work in Safari? $(function() {$("#concho_4_2").draggable({ helper: 'clone', cursor: 'pointer', zIndex: '1001', stop: function(event, ui) { offsetElement = $(ui.helper).offset(); offNewContainer = $('#belts').offset(); var dataId = $(ui.helper).attr('id'); ajaxRequest('http://tandyleatherfactory.net/includes/ahah/add_product.php', 'product=4', '#conchos'); var randomnumber = Math.floor(Math.random()*1000000); var newId = 'concho_4_2_'+randomnumber; $(ui.helper).clone(true).removeAttr('id').attr('id',newId).css("left", offsetElement.left-offNewContainer.left-10).css("top", offsetElement.top-offNewContainer.top-10).appendTo('#belts'); $('#'+newId).draggable(); } });

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  • how to design a schema where the columns of a table are not fixed

    - by hIpPy
    I am trying to design a schema where the columns of a table are not fixed. Ex: I have an Employee table where the columns of the table are not fixed and vary (attributes of Employee are not fixed and vary). Nullable columns in the Employee table itself i.e. no normalization Instead of adding nullable columns, separate those columns out in their individual tables ex: if Address is a column to be added then create table Address[EmployeeId, AddressValue]. Create tables ExtensionColumnName [EmployeeId, ColumnName] and ExtensionColumnValue [EmployeeId, ColumnValue]. ExtensionColumnName would have ColumnName as "Address" and ExtensionColumnValue would have ColumnValue as address value. Employee table EmployeeId Name ExtensionColumnName table ColumnNameId EmployeeId ColumnName ExtensionColumnValue table EmployeeId ColumnNameId ColumnValue There is a drawback is the first two ways as the schema changes with every new attribute. Note that adding a new attribute is frequent. I am not sure if this is the good or bad design. If someone had a similar decision to make, please give an insight on things like foreign keys / data integrity, indexing, performance, reporting etc.

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  • jquery-ui autocomplete with ASP MVC suggestions not displaying

    - by adamnickerson
    I have been trying to get a simple example of the jquery-ui autocomplete to work. I have a controller setup to handle the query, and it returns the json that looks to be in order, but I am getting no suggestions showing up. Here are the js libraries I am including: <script type="text/javascript" language="javascript" src="/Scripts/jquery-1.4.1.js"></script> <script type="text/javascript" language="javascript" src="/Scripts/jquery-ui-1.8.1.custom.min.js"></script> <link href="/Content/jquery-ui-1.8.1.custom.css" rel="stylesheet" type="text/css" /> and here is the javascript and the form tags: <script type="text/javascript"> $(function () { $("#organization").autocomplete({ source: function (request, response) { $.ajax({ url: '/Organization/OrganizationLookup', dataType: "json", data: { limit: 12, q: request.term } }) }, minLength: 2 }); }); </script> <div class="ui-widget"> <label for="organization">Organization: </label> <input id="organization" /> </div> I get back a json response that looks reasonable from my controller: [{"id":"Sector A","value":"Sector A"},{"id":"Sector B","value":"Sector B"},{"id":"Sector C","value":"Sector C"}] id and value seem to be the default naming that autocomplete is looking for. But I get no joy at all. Any thoughts?

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  • Copying contents of a MySQL table to a table in another (local) database

    - by Philip Eve
    I have two MySQL databases for my site - one is for a production environment and the other, much smaller, is for a testing/development environment. Both have identical schemas (except when I am testing something I intend to change, of course). A small number of the tables are for internationalisation purposes: TransLanguage - non-English languages TransModule - modules (bundles of phrases for translation, that can be loaded individually by PHP scripts) TransPhrase - individual phrases, in English, for potential translation TranslatedPhrase - translations of phrases that are submitted by volunteers ChosenTranslatedPhrase - screened translations of phrases. The volunteers who do translation are all working on the production site, as they are regular users. I wanted to create a stored procedure that could be used to synchronise the contents of four of these tables - TransLanguage, TransModule, TransPhrase and ChosenTranslatedPhrase - from the production database to the testing database, so as to keep the test environment up-to-date and prevent "unknown phrase" errors from being in the way while testing. My first effort was to create the following procedure in the test database: CREATE PROCEDURE `SynchroniseTranslations` () LANGUAGE SQL NOT DETERMINISTIC MODIFIES SQL DATA SQL SECURITY DEFINER BEGIN DELETE FROM `TransLanguage`; DELETE FROM `TransModule`; INSERT INTO `TransLanguage` SELECT * FROM `PRODUCTION_DB`.`TransLanguage`; INSERT INTO `TransModule` SELECT * FROM `PRODUCTION_DB`.`TransModule`; INSERT INTO `TransPhrase` SELECT * FROM `PRODUCTION_DB`.`TransPhrase`; INSERT INTO `ChosenTranslatedPhrase` SELECT * FROM `PRODUCTION_DB`.`ChosenTranslatedPhrase`; END When I try to run this, I get an error message: "SELECT command denied to user 'username'@'localhost' for table 'TransLanguage'". I also tried to create the procedure to work the other way around (that is, to exist as part of the data dictionary for the production database rather than the test database). If I do it that, way, I get an identical message except it tells me I'm denied the DELETE command rather than SELECT. I have made sure that my user has INSERT, DELETE, SELECT, UPDATE and CREATE ROUTINE privileges on both databases. However, it seems as though MySQL is reluctant to let this user exercise its privileges on both databases at the same time. How come, and is there a way around this?

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  • Improve speed of a JOIN in MySQL

    - by ran2
    Dear all, I know there a similar threads around, but this is really the first time I realize that query speed might affect me - so it´s not that easy for me to really make the transfer from other folks problems. That being said I have using the following query successfully with smaller data, but if I use it on what are mildly large tables (about 120,000 records). I am waiting for hours. INSERT INTO anothertable (id,someint1,someint1,somevarchar1,somevarchar1) SELECT DISTINCT md.id,md.someint1,md.someint1,md.somevarchar1,pd.somevarchar1 from table1 AS md JOIN table2 AS pd ON (md.id = pd.id); Tables 1 and 2 contain about 120,000 records. The query has been running for almost 2 hours right now. Is this normal? Do I just have to wait. I really have no idea, but I am pretty sure that one could do it better since it´s my very first try. I read about indexing, but dont know yet what to index in my case? Thanks for any suggestions - feel free to point my to the very beginners guides ! best matt

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  • jQuery-driven app. won't work without alert()

    - by webjawns.com
    I have seen a lot of articles on this, but none dealing with jQuery, so here I go... I am implementing a version of a script from http://javascript-array.com/scripts/jquery_simple_drop_down_menu/ into an existing application; however, I cannot get it to work without adding alert('msg...') as the first method within the $(document).ready() call. This has nothing to do with load time... no matter how long I wait, the menu does not work. Add alert(), however, and it works like a charm. var timeout = 500; var closetimer = 0; var ddmenuitem = 0; function jsddm_open() { jsddm_canceltimer(); jsddm_close(); ddmenuitem = $(this).find('ul').css('visibility', 'visible');} function jsddm_close() { if(ddmenuitem) ddmenuitem.css('visibility', 'hidden');} function jsddm_timer() { closetimer = window.setTimeout(jsddm_close, timeout);} function jsddm_canceltimer() { if(closetimer) { window.clearTimeout(closetimer); closetimer = null;}} $(document).ready(function() { $('#jsddm > li').bind('mouseover', jsddm_open) $('#jsddm > li').bind('mouseout', jsddm_timer)}); document.onclick = jsddm_close;

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  • ManyToOne annotation fails with Hibernate 4.1: MappingException

    - by barelas
    Using Hibernate 4.1.1.Final. When I try to add @ManyToOne, schema creation fails with: org.hibernate.MappingException: Could not instantiate persister org.hibernate.persister.entity.SingleTableEntityPersister User.java: @Entity public class User { @Id private int id; public int getId() {return id;} public void setId(int id) {this.id = id;} @ManyToOne Department department; public Department getDepartment() {return department;} public void setDepartment(Department department) {this.department = department;} } Department.java @Entity public class Department { @Id private int departmentNumber; public int getDepartmentNumber() {return departmentNumber;} public void setDepartmentNumber(int departmentNumber) {this.departmentNumber = departmentNumber;} } hibernate.properties: hibernate.connection.driver_class=com.mysql.jdbc.Driver hibernate.connection.url=jdbc:mysql://localhost:3306/dbname hibernate.connection.username=user hibernate.connection.password=pass hibernate.connection.pool_size=5 hibernate.dialect=org.hibernate.dialect.MySQL5InnoDBDialect hibernate.hbm2ddl.auto=create init (throwing exception): ServiceRegistry serviceRegistry = new ServiceRegistryBuilder().buildServiceRegistry(); sessionFactory = new MetadataSources( serviceRegistrY.addAnnotatedClass(Department.class).addAnnotatedClass(User.class).buildMetadata().buildSessionFactory(); exception throwed at init: org.hibernate.MappingException: Could not instantiate persister org.hibernate.persister.entity.SingleTableEntityPersister at org.hibernate.persister.internal.PersisterFactoryImpl.create(PersisterFactoryImpl.java:174) at org.hibernate.persister.internal.PersisterFactoryImpl.createEntityPersister(PersisterFactoryImpl.java:148) at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:820) at org.hibernate.metamodel.source.internal.SessionFactoryBuilderImpl.buildSessionFactory(SessionFactoryBuilderImpl.java:65) at org.hibernate.metamodel.source.internal.MetadataImpl.buildSessionFactory(MetadataImpl.java:340) I have tried adding some other annotations, but shouldn't the defaults work and create the tables and foreign key? If I remove the department from User, tables get generated fine. Thanks in advance!

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  • How to do binding programmically?

    - by user175908
    Hello, Could anyone identify the problem in this code? (I'm kinda newbie in WPF bindings.) This code executes after chart is loaded when I click a button: I get this error: Update: I dont get that error anymore. Thanks to Tomas. Now no error occur but chart looks completely blank (no columns) Update: Code now looks like this: // create a very simple DataSet var dataSet = new DataSet("MyDataSet"); var table = dataSet.Tables.Add("MyTable"); table.Columns.Add("Name"); table.Columns.Add("Price"); table.Rows.Add("Brick", 1.5d); table.Rows.Add("Soap", 4.99d); table.Rows.Add("Comic Book", 0.99d); // chart series var series = new ColumnSeries() { IndependentValueBinding = new Binding("[Name]"), // How to deal with DependentValueBinding = new Binding("[Price]"), // these two? ItemsSource = dataSet.Tables[0].DefaultView // or maybe I do mistake here? }; // ---------- set additional binding as adviced ------------------ series.SetBinding(ColumnSeries.ItemsSourceProperty, new Binding()); // chart stuff MyChart.Series.Add(series); MyChart.Title = "Names 'n Prices"; // some code to remove legend var style = new Style(typeof(Control)); style.Setters.Add(new Setter(LegendItem.TemplateProperty, null)); MyChart.LegendStyle = style; XAML: <Window x:Class="BindingzTest.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="MainWindow" Height="606" Width="988" xmlns:charting="clr-namespace:System.Windows.Controls.DataVisualization.Charting;assembly=System.Windows.Controls.DataVisualization.Toolkit"> <Grid Name="LayoutRoot"> <charting:Chart Name="MyChart" Margin="0,0,573,0" Height="289" VerticalAlignment="Top" /> <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="272,361,0,0" Name="button1" VerticalAlignment="Top" Width="75" Click="chart1_Loaded" /> </Grid> Thanks for help in advance once more.

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  • Load SQL query result data into cache in advance

    - by Marc
    I have the following situation: .net 3.5 WinForm client app accessing SQL Server 2008 Some queries returning relatively big amount of data are used quite often by a form Users are using local SQL Express and restarting their machines at least daily Other users are working remotely over slow network connections The problem is that after a restart, the first time users open this form the queries are extremely slow and take more or less 15s on a fast machine to execute. Afterwards the same queries take only 3s. Of course this comes from the fact that no data is cached and must be loaded from disk first. My question: Would it be possible to force the loading of the required data in advance into SQL Server cache? Note My first idea was to execute the queries in a background worker when the application starts, so that when the user starts the form the queries will already be cached and execute fast directly. I however don't want to load the result of the queries over to the client as some users are working remotely or have otherwise slow networks. So I thought just executing the queries from a stored procedure and putting the results into temporary tables so that nothing would be returned. Turned out that some of the result sets are using dynamic columns so I couldn't create the corresponding temp tables and thus this isn't a solution. Do you happen to have any other idea?

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