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  • reuse generators

    - by wiso
    I need to check the central limit with dices. Rool D dices. Sum the results. Repeat the same thing for N times. Change D and repeat. There's no need to store random values so I want to use only generators. The problem is that generators are consuming, I can't resuging them more times. Now my code use explicit for and I don't like it. dice_numbers = (1, 2, 10, 100, 1000) repetitions = 10000 for dice_number in dice_numbers: # how many dice to sum sum_container = [] for r in range(repetitions): rool_sum = sum((random.randint(1,6) for _ in range(dice_number))) sum_container.append(rool_sum) plot_histogram(sum_container) I want to create something like for r in repetitions: rools_generator = (random.randint(1,6) for _ in range(dice_number) sum_generator = (sum(rools_generator) for _ in range(r)) but the second time I resuse rools_generator it is condumed. I need to construct generator class?

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  • Fetch Subject & sender in IMAP

    - by shadyabhi
    After the following code:- import imaplib conn = imaplib.IMAP4("mail.daiict.ac.in") conn.login("200801076","mypass") # OUT: ('OK', ['Logged in.']) conn.select() # OUT: ('OK', ['166']) Now, how do I fetch the sender and subject of mails in the inbox?

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  • writing 'bits' to c++ file streams

    - by Sorush Rabiee
    How can i write 'one bit' into a file stream or file structure each time? is it possible to write to a queue and then flush it ? is it possible with c# or java? this was needed when i try to implement an instance of Huffman codding. i can't write bits into files. so write them to a bitset and then (when compression was completed) write 8-bit piece of it each time (exclude last one).

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  • Is this the right way of handling command line arguments?

    - by shadyabhi
    ask_username = True ask_password = True ask_message = True ask_number = True def Usage(): print '\t-h, --help: View help' print '\t-u, --username: Username' print '\t-p, --password: Password' print '\t-n, --number: numbber to send the sms' print '\t-m, --message: Message to send' sys.exit(1) opts, args = getopt(sys.argv[1:], 'u:p:m:n:h',["username=","password=","message=","number=","help"]) print opts, args for o,v in opts: if o in ("-h", "--help"): Usage() elif o in ("-u", "--username"): username = v ask_username = False elif o in ("-p", "--password"): passwd = v ask_password = False elif o in ("-m", "--message"): message = v ask_message = False elif o in ("-n", "--number"): number = v ask_number = False #Credentials taken here if ask_username: username = raw_input("Enter USERNAME: ") if ask_password: passwd = getpass() if ask_message: message = raw_input("Enter Message: ") if ask_number: number = raw_input("Enter Mobile number: ") I dont think it is, because I am using 4 objects just for checking if command line argument was provided... Guide me with the best way of doing it..

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  • Matching Strings: a biological perspective

    - by sun
    Write a function, called constrainedMatchPair which takes three arguments: a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple (call it k) such that n+m+1 = k, where m is the length of the first substring. Complete the definition def constrainedMatchPair(firstMatch,secondMatch,length):

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  • Efficiently generate numpy array from list comprehension output?

    - by shootingstars
    Is there a more efficient way than using numpy.asarray() to generate an array from output in the form of a list? This appears to be copying everything in memory, which doesn't seem like it would be that efficient with very large arrays. (Updated) Example: import numpy as np a1 = np.array([1,2,3,4,5,6,7,8,9,10]) # pretend this has thousands of elements a2 = np.array([3,7,8]) results = np.asarray([np.amax(np.where(a1 > element)) for element in a2])

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  • method works fine, until it is called in a function, then UnboundLocalError

    - by user1776100
    I define a method called dist, to calculate the distance between two points which I does it correctly when directly using the method. However, when I get a function to call it to calculate the distance between two points, I get UnboundLocalError: local variable 'minkowski_distance' referenced before assignment edit sorry, I just realised, this function does work. However I have another method calling it that doesn't. I put the last method at the bottom This is the method: class MinkowskiDistance(Distance): def __init__(self, dist_funct_name_str = 'Minkowski distance', p=2): self.p = p def dist(self, obj_a, obj_b): distance_to_power_p=0 p=self.p for i in range(len(obj_a)): distance_to_power_p += abs((obj_a[i]-obj_b[i]))**(p) minkowski_distance = (distance_to_power_p)**(1/p) return minkowski_distance and this is the function: (it basically splits the tuples x and y into their number and string components and calculates the distance between the numeric part of x and y and then the distance between the string parts, then adds them. def total_dist(x, y, p=2, q=2): jacard = QGramDistance(q=q) minkowski = MinkowskiDistance(p=p) x_num = [] x_str = [] y_num = [] y_str = [] #I am spliting each vector into its numerical parts and its string parts so that the distances #of each part can be found, then summed together. for i in range(len(x)): if type(x[i]) == float or type(x[i]) == int: x_num.append(x[i]) y_num.append(y[i]) else: x_str.append(x[i]) y_str.append(y[i]) num_dist = minkowski.dist(x_num,y_num) str_dist = I find using some more steps #I am simply adding the two types of distance to get the total distance: return num_dist + str_dist class NearestNeighbourClustering(Clustering): def __init__(self, data_file, clust_algo_name_str='', strip_header = "no", remove = -1): self.data_file= data_file self.header_strip = strip_header self.remove_column = remove def run_clustering(self, max_dist, p=2, q=2): K = {} #dictionary of clusters data_points = self.read_data_file() K[0]=[data_points[0]] k=0 #I added the first point in the data to the 0th cluster #k = number of clusters minus 1 n = len(data_points) for i in range(1,n): data_point_in_a_cluster = "no" for c in range(k+1): distances_from_i = [total_dist(data_points[i],K[c][j], p=p, q=q) for j in range(len(K[c]))] d = min(distances_from_i) if d <= max_dist: K[c].append(data_points[i]) data_point_in_a_cluster = "yes" if data_point_in_a_cluster == "no": k += 1 K[k]=[data_points[i]] return K

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  • What is an alternative to eval in this situation?

    - by CppLearner
    Many of my view functions do similar things. For the most part, they reverse to a different views upon clicking a button / a text link. So I wrote a helper function render_reverse def render_reverse(f, args): # args are all string type return eval('reverse(' + f + ', ' + args + ')' ) eval is a bad practice, and is pretty slow. It takes 3 seconds to start redirecting, whereas calling reverse directly takes less than 1 second to start redirecting. What alternative do I have? By the way, the function above doesn't work properly. I was modelling after this line (which works) eval('reverse("homepage", args=["abcdefg"])') Thanks.

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  • Django: Converting an entire Model into a single dictionary

    - by LarrikJ
    Is there a good way in Django to convert an entire model to a dictionary? I mean, like this: class DictModel(models.Model): key = models.CharField(20) value = models.CharField(200) DictModel.objects.all().to_dict() ... with the result being a dictionary with the key/value pairs made up of records in the Model? Has anyone else seen this as being useful for them? Thanks. Update I just wanted to add is that my ultimate goal is to be able to do a simple variable lookup inside a Template. Something like: {{ DictModel.exampleKey }} With a result of DictModel.objects.get(key__exact=exampleKey).value Overall, though, you guys have really surprised me with how helpful allof your responses are, and how different the ways to approach it can be. Thanks a lot.

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  • Python2.7: How can I speed up this bit of code (loop/lists/tuple optimization)?

    - by user89
    I repeat the following idiom again and again. I read from a large file (sometimes, up to 1.2 million records!) and store the output into an SQLite databse. Putting stuff into the SQLite DB seems to be fairly fast. def readerFunction(recordSize, recordFormat, connection, outputDirectory, outputFile, numObjects): insertString = "insert into NODE_DISP_INFO(node, analysis, timeStep, H1_translation, H2_translation, V_translation, H1_rotation, H2_rotation, V_rotation) values (?, ?, ?, ?, ?, ?, ?, ?, ?)" analysisNumber = int(outputPath[-3:]) outputFileObject = open(os.path.join(outputDirectory, outputFile), "rb") outputFileObject, numberOfRecordsInFileObject = determineNumberOfRecordsInFileObjectGivenRecordSize(recordSize, outputFileObject) numberOfRecordsPerObject = (numberOfRecordsInFileObject//numberOfObjects) loop1StartTime = time.time() for i in range(numberOfRecordsPerObject ): processedRecords = [] loop2StartTime = time.time() for j in range(numberOfObjects): fout = outputFileObject .read(recordSize) processedRecords.append(tuple([j+1, analysisNumber, i] + [x for x in list(struct.unpack(recordFormat, fout))])) loop2EndTime = time.time() print "Time taken to finish loop2: {}".format(loop2EndTime-loop2StartTime) dbInsertStartTime = time.time() connection.executemany(insertString, processedRecords) dbInsertEndTime = time.time() loop1EndTime = time.time() print "Time taken to finish loop1: {}".format(loop1EndTime-loop1StartTime) outputFileObject.close() print "Finished reading output file for analysis {}...".format(analysisNumber) When I run the code, it seems that "loop 2" and "inserting into the database" is where most execution time is spent. Average "loop 2" time is 0.003s, but it is run up to 50,000 times, in some analyses. The time spent putting stuff into the database is about the same: 0.004s. Currently, I am inserting into the database every time after loop2 finishes so that I don't have to deal with running out RAM. What could I do to speed up "loop 2"?

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  • Why is my socket closing?

    - by Tommy3244
    Ok, so I am making a multiplayer game. I am working out the kinks in the server/client connectivity system. I can't seam to work out this error. Mainly, my server code does the following: Accepts Client Using SocketServer Module CLIENT -- SERVER sends Login byte (1 byte) + login username and password (200 bytes) SERVER request for 1 byte by struct.calcsize('b') CLIENT has exception on read SERVER recieves byte from CLIENT and sends CLIENT a struct packed byte with the value of 4 SERVER has exception on send So, it is the client excepting. The client exception is: socket.error: (10054, 'Connection reset by peer') And the server error is this: error: (9, 'Bad file descriptor')

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  • Parse items from text file

    - by chris
    I have a text file that includes data inside {[]} tags. What would be the suggested way to parse that data so I can just use the data inside the tags? Example text file would look like this: 'this is a bunch of text that is not {[really]} useful in any {[way]}. I need to {[get]} some items {[from]} it.' I would like to end up with 'really', 'way', 'get', 'from' in a list. I guess I could use split to do it.. but seems like there might be a better way out there. I have seen a ton parsing libraries, is there one that would be perfect for what I want to do?

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  • Matplotlib Contour Clabel Location

    - by jotimaz
    I would like to control the location of matplotlib clabels on a contour plot, but without utilizing the manual=True flag in clabel. For example, I would like to specify an x-coordinate, and have labels created at the points that pass through this line. I see that you can get the location of the individual labels using get_position(), but I am stuck at that. Any help would be greatly appreciated. Thanks! EDIT: The above image is an example plot that I would like to apply this method to. The default label positions are inconvenient -- the flat areas between Day 2 and Day 4 would be more visually appealing.

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  • Returning binomal as a tuple

    - by Mike
    I want to save the results of my function binomal_aux to a tuple but I don't have an idea how to, here is my code I have right now. def binomal (n): i=0 for i in range(n): binomal_aux(n,i) #want this to be in a tuple so, binomal (2) = (1,2,1) return def binomal_aux (n,k): if (k==0): return 1 elif (n==k): return 1 else: return (binomal_aux(n-1,k) + binomal_aux(n-1,k-1))

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  • Permission to view, but not to change! - Django

    - by RadiantHex
    Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

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  • Why doesn't this work?

    - by Kyle W
    take = raw_input('Please enter the string of numbers that compose code\n\n\t') y = str(take) l = [] for i in xrange(0, len(y), 3):         l.append(str(y[i:i+3])) b = len(l) a = 0 while(a!=b):         c = l[a].replace('444', ' ')         c = l[a].replace('111', 'a')         c = l[a].replace('112', 'b')         c = l[a].replace('113', 'c')         c = l[a].replace('114', 'd')         c = l[a].replace('115', 'e')         etc...         a = a + 1 filename = 'decmes.txt' file = open(filename, 'w') file.write(c) file.close() I can enter anything, just 111 for example and it gives me back the same thing I put in. Maybe it's something dumb, but I can't figure it out.

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  • How to append a tag after a link with BeaufitulSoup

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com">this if foo</a> <a href="http://www.bar.com">this if bar</a> </p> using BeautifulSoup, i would like to change this Html in: <p> <a href="http://www.foo.com">this if foo</a><b>OK</b> <a href="http://www.bar.com">this if bar</a><b>OK</b> </p> Is it possible to do this using BeautifulSoup?

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