Search Results

Search found 7577 results on 304 pages for 'admin generator'.

Page 44/304 | < Previous Page | 40 41 42 43 44 45 46 47 48 49 50 51  | Next Page >

  • Do you know a good html mailing list management software with admin levels?

    - by SirG
    I'm basically looking for a program/app/script (can be commercial) which I can ideally install on a windows server (we can run asp, asp.net php mssql) we have different groups of people who send newsletters to web members, I want to bring it all into one app which I can monitor and control. Ideally it would be able to create html newsletters, (with some templates) track emails and click throughs. Manage email lists subscribe/unsubscribes. And importantly have different levels of admin, so a newsletter creator could log in and create and send off an email, it goes into a queue where a communications editor can have an overview of all newsletters and approve the sending of the emails or edit them before they are sent off. before I start coding something up myself I thought I'd ask if anyone has any advice! Cheers!

    Read the article

  • How to fix “Install-SPSolution: Admin SVC must be running in order to create deployment timer job”

    - by ybbest
    When I try to install a SharePoint Solution using PowerShell, I got the error “How to fix Install-SPSolution: Admin SVC must be running in order to create deployment timer job”. The reason you got error is that SharePoint 2010 Administration is not started, so to fix it you just need to start the services. Problem: Solution: To fix the issues, you need to start the SharePoint 2010 Administration service. 1. Go to services control panel. 2. Start the SharePoint 2010 Administration service. 3. Rerun your PowerShell, it should fix the problem. However, you might get another problem “A deployment or retraction is already under way for the solution “*.wsp”, and only one deployment or retraction at a time is supported”, for this problem you can check my other blog here.

    Read the article

  • I cannot login to my ubuntu admin!!!! HELP!

    - by Spinz01
    I used lightdm to hide the users at the login prompt of ubuntu and it hid my account. The only one visible is "other" and it doesn't even have a known password. So, I have accessed the terminal and created a guest account and another account without passwords and they are not visible. I am new to using the terminal so I don't know how to write the commands for either: making all users/accounts visible to the login and/or making the guest accounts visible, and then once in the GUI change the login settings to see my admin account. I have no idea of what else I could do, or even how to do it. I would appreciate any help, I'm in a desperate situation because I really need to access my desktop! THANK YOU!!! Any ideas are appreciated!!!

    Read the article

  • How to run a command as admin in MSDos?

    - by tech
    I want to run a dos command in dos prompt, but this dos command is only executed using admin right. So, I can right click the command prompt to run as administrator, but I wanna to run one line of dos command using the admin right, can I run dos command in dos prompt like sudo in DOS cmd? thz u.

    Read the article

  • Add the current admin user to SQL Server Express 2008.

    - by BradyKelly
    I have managed (in 'eksperiments') to remove both my Windows users from my SQL Express instance. I am now logged in as windows admin, and have re-created the corresponding SQL login, but I cannot assign sysadmin rights. I get the error: User does not have permission to perform this action. (Microsoft SQL Server, Error: 15247) If admin can't do this, should I start looking for a small animal to sacrifice?

    Read the article

  • admin right to IIS7 for user using group policy or script?

    - by Mit Naik
    I want to provide administrator rights to user account under windows 7 just for IIS7 and user shouldn't be able to manage any other application. I have create group policy rules using applocker for windows7 where user can manage all the installed application, but it doesn't works for IIS7 as it need admin rights. Can we do this using group policy or by adding scripts under group policy for users. Also any vbscript which can provide admin rights to IIS7 for a particular user will do.

    Read the article

  • How to connect to the guest console via SSH without being admin on host?

    - by Sorin Sbarnea
    How can someone connect to a VM console via SSH, without being an admin on VM-host. This means that you should be able to see the guest boot screen and grub menu in a ssh session. That's important because in some cases you may need to fix the VM without having access to the VM-host admin console. Mainly this is about how you can have your own VM-guest which you can fully control but without having access to VM-host.

    Read the article

  • WNA Configuration in OAM 11g

    - by P Patra
    Pre-Requisite: Kerberos authentication scheme has to exist. This is usually pre-configured OAM authentication scheme. It should have Authentication Level - "2", Challenge Method - "WNA", Challenge Direct URL - "/oam/server" and Authentication Module- "Kerberos". The default authentication scheme name is "KerberosScheme", this name can be changed. The DNS name has to be resolvable on the OAM Server. The DNS name with referrals to AD have to be resolvable on OAM Server. Ensure nslookup work for the referrals. Pre-Install: AD team to produce keytab file on the AD server by running ktpass command. Provide OAM Hostname to AD Team. Receive from AD team the following: Keypass file produced when running the ktpass command ktpass username ktpass password Copy the keytab file to convenient location in OAM install tree and rename the file if desired. For instance where oam-policy.xml file resides. i.e. /fa_gai2_d/idm/admin/domains/idm-admin/IDMDomain/config/fmwconfig/keytab.kt Configure WNA Authentication on OAM Server: Create config file krb.config and set the environment variable to the path to this file: KRB_CONFIG=/fa_gai2_d/idm/admin/domains/idm-admin/IDMDomain/config/fmwconfig/krb.conf The variable KRB_CONFIG has to be set in the profile for the user that OAM java container(i.e. Wbelogic Server) runs as, so that this setting is available to the OAM server. i.e. "applmgr" user. In the krb.conf file specify: [libdefaults] default_realm= NOA.ABC.COM dns_lookup_realm= true dns_lookup_kdc= true ticket_lifetime= 24h forwardable= yes [realms] NOA.ABC.COM={ kdc=hub21.noa.abc.com:88 admin_server=hub21.noa.abc.com:749 default_domain=NOA.ABC.COM [domain_realm] .abc.com=ABC.COM abc.com=ABC.COM .noa.abc.com=NOA.ABC.COM noa.abc.com=NOA.ABC.COM Where hub21.noa.abc.com is load balanced DNS VIP name for AD Server and NOA.ABC.COM is the name of the domain. Create authentication policy to WNA protect the resource( i.e. EBSR12) and choose the "KerberosScheme" as authentication scheme. Login to OAM Console => Policy Configuration Tab => Browse Tab => Shared Components => Application Domains => IAM Suite => Authentication Policies => Create Name: ABC WNA Auth Policy Authentication Scheme: KerberosScheme Failure URL: http://hcm.noa.abc.com/cgi-bin/welcome Edit System Configuration for Kerberos System Configuration Tab => Access Manager Settings => expand Authentication Modules => expand Kerberos Authentication Module => double click on Kerberos Edit "Key Tab File" textbox - put in /fa_gai2_d/idm/admin/domains/idm-admin/IDMDomain/config/fmwconfig/keytab.kt Edit "Principal" textbox - put in HTTP/[email protected] Edit "KRB Config File" textbox - put in /fa-gai2_d/idm/admin/domains/idm-admin/IDMDomain/config/fmwconfig/krb.conf Cilck "Apply" In the script setting environment for the WLS server where OAM is deployed set the variable: KRB_CONFIG=/fa_gai2_d/idm/admin/domains/idm-admin/IDMDomain/config/fmwconfig/krb.conf Re-start OAM server and OAM Server Container( Weblogic Server)

    Read the article

  • Database development/admin - What exactly should I be trying to learn? [closed]

    - by Sauron
    I've been a bit weary about approaching learning databases. I've dabbled into them before, and "DATA" in itself appeals to me a lot. Maintaining/searching/moving, everything about it in the abstract sense I love. (This isn't a career question, this is a learning question.) But as RDBMS's begin to be easier to maintain, and with tools that "anyone" can use to manage data I feared for the database admin jobs. (Yet I see jobs for SQL everywhere!). I know "No-SQL" was a big deal but it kinda has its niche. But that leaves me here... unsure of really "what" to study. What tools should I have in my tool belt? I'm sure RDBMS's will be around in both use and maintaining legacy code. But what else? Obviously data will always be around, but is this a secure field or a dying one? And what should I be concentrating on?

    Read the article

  • 10 CSS Grid Layout Generators

    - by Jyoti
    There are a lot of online generators which are of no use to any designers, however some can help designers to an extent. Some example of online generators are favicon generators, background generators, button generators, and badge generators. Some of the useful kinds are the ones that solve one purpose with quick and easy steps, especially useful for new designers, following is a list of some useful CSS grid layout generators. Grid Layout Generator By PageColumn: Blueprint Grid CSS Generator: Grid Generator By NetProtozo: Grid Generator By DegisnByGrid: Grid System Generator: YUI CSS Grid Builder: Variable Grid System: Firdamatic: CSS Sourced Ordered Variable Border Columed Page Maker: Grid Designer:

    Read the article

  • Event Logging in LINQ C# .NET

    The first thing you'll want to do before using this code is to create a table in your database called TableHistory: CREATE TABLE [dbo].[TableHistory] (     [TableHistoryID] [int] IDENTITY NOT NULL ,     [TableName] [varchar] (50) NOT NULL ,     [Key1] [varchar] (50) NOT NULL ,     [Key2] [varchar] (50) NULL ,     [Key3] [varchar] (50) NULL ,     [Key4] [varchar] (50) NULL ,     [Key5] [varchar] (50) NULL ,     [Key6] [varchar] (50)NULL ,     [ActionType] [varchar] (50) NULL ,     [Property] [varchar] (50) NULL ,     [OldValue] [varchar] (8000) NULL ,     [NewValue] [varchar] (8000) NULL ,     [ActionUserName] [varchar] (50) NOT NULL ,     [ActionDateTime] [datetime] NOT NULL ) Once you have created the table, you'll need to add it to your custom LINQ class (which I will refer to as DboDataContext), thus creating the TableHistory class. Then, you'll need to add the History.cs file to your project. You'll also want to add the following code to your project to get the system date: public partial class DboDataContext{ [Function(Name = "GetDate", IsComposable = true)] public DateTime GetSystemDate() { MethodInfo mi = MethodBase.GetCurrentMethod() as MethodInfo; return (DateTime)this.ExecuteMethodCall(this, mi, new object[] { }).ReturnValue; }}private static Dictionary<type,> _cachedIL = new Dictionary<type,>();public static T CloneObjectWithIL<t>(T myObject){ Delegate myExec = null; if (!_cachedIL.TryGetValue(typeof(T), out myExec)) { // Create ILGenerator DynamicMethod dymMethod = new DynamicMethod("DoClone", typeof(T), new Type[] { typeof(T) }, true); ConstructorInfo cInfo = myObject.GetType().GetConstructor(new Type[] { }); ILGenerator generator = dymMethod.GetILGenerator(); LocalBuilder lbf = generator.DeclareLocal(typeof(T)); //lbf.SetLocalSymInfo("_temp"); generator.Emit(OpCodes.Newobj, cInfo); generator.Emit(OpCodes.Stloc_0); foreach (FieldInfo field in myObject.GetType().GetFields( System.Reflection.BindingFlags.Instance | System.Reflection.BindingFlags.Public | System.Reflection.BindingFlags.NonPublic)) { // Load the new object on the eval stack... (currently 1 item on eval stack) generator.Emit(OpCodes.Ldloc_0); // Load initial object (parameter) (currently 2 items on eval stack) generator.Emit(OpCodes.Ldarg_0); // Replace value by field value (still currently 2 items on eval stack) generator.Emit(OpCodes.Ldfld, field); // Store the value of the top on the eval stack into // the object underneath that value on the value stack. // (0 items on eval stack) generator.Emit(OpCodes.Stfld, field); } // Load new constructed obj on eval stack -> 1 item on stack generator.Emit(OpCodes.Ldloc_0); // Return constructed object. --> 0 items on stack generator.Emit(OpCodes.Ret); myExec = dymMethod.CreateDelegate(typeof(Func<t,>)); _cachedIL.Add(typeof(T), myExec); } return ((Func<t,>)myExec)(myObject);}I got both of the above methods off of the net somewhere (maybe even from CodeProject), but it's been long enough that I can't recall where I got them.Explanation of the History ClassThe History class records changes by creating a TableHistory record, inserting the values for the primary key for the table being modified into the Key1, Key2, ..., Key6 columns (if you have more than 6 values that make up a primary key on any table, you'll want to modify this), setting the type of change being made in the ActionType column (INSERT, UPDATE, or DELETE), old value and new value if it happens to be an update action, and the date and Windows identity of the user who made the change.Let's examine what happens when a call is made to the RecordLinqInsert method:public static void RecordLinqInsert(DboDataContext dbo, IIdentity user, object obj){ TableHistory hist = NewHistoryRecord(obj); hist.ActionType = "INSERT"; hist.ActionUserName = user.Name; hist.ActionDateTime = dbo.GetSystemDate(); dbo.TableHistories.InsertOnSubmit(hist);}private static TableHistory NewHistoryRecord(object obj){ TableHistory hist = new TableHistory(); Type type = obj.GetType(); PropertyInfo[] keys; if (historyRecordExceptions.ContainsKey(type)) { keys = historyRecordExceptions[type].ToArray(); } else { keys = type.GetProperties().Where(o => AttrIsPrimaryKey(o)).ToArray(); } if (keys.Length > KeyMax) throw new HistoryException("object has more than " + KeyMax.ToString() + " keys."); for (int i = 1; i <= keys.Length; i++) { typeof(TableHistory) .GetProperty("Key" + i.ToString()) .SetValue(hist, keys[i - 1].GetValue(obj, null).ToString(), null); } hist.TableName = type.Name; return hist;}protected static bool AttrIsPrimaryKey(PropertyInfo pi){ var attrs = from attr in pi.GetCustomAttributes(typeof(ColumnAttribute), true) where ((ColumnAttribute)attr).IsPrimaryKey select attr; if (attrs != null && attrs.Count() > 0) return true; else return false;}RecordLinqInsert takes as input a data context which it will use to write to the database, the user, and the LINQ object to be recorded (a single object, for instance, a Customer or Order object if you're using AdventureWorks). It then calls the NewHistoryRecord method, which uses LINQ to Objects in conjunction with the AttrIsPrimaryKey method to pull all the primary key properties, set the Key1-KeyN properties of the TableHistory object, and return the new TableHistory object. The code would be called in an application, like so: Continue span.fullpost {display:none;}

    Read the article

  • Module configuration and layout configuration in zend framework.

    - by Prasanth P
    Hi all, I got some codes from other articles for configuring module and layout in zend framework. I tried with in my local. i didn't get different layout for default and admin module. Here is my code for configuring module and layout for zend framework. configs/application.ini [production] # Debug output phpSettings.display_startup_errors = 0 phpSettings.display_errors = 0 # Include path includePaths.library = APPLICATION_PATH "/../library" # Bootstrap bootstrap.path = APPLICATION_PATH "/Bootstrap.php" bootstrap.class = "Bootstrap" admin.bootstrap.path = APPLICATION_PATH "/modules/admin/Bootstrap.php" admin.bootstrap.class = "admin_Bootstrap" # Front Controller resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.env = APPLICATION_ENV # Session resources.session.name = "ZendSession" resources.session.save_path = APPLICATION_PATH "/../data/session" resources.session.remember_me_seconds = 86400 # Layout resources.layout.layout = "layout" resources.layout.layoutPath = APPLICATION_PATH "/layouts" admin.resources.layout.layout = "admin" admin.resources.layout.layoutPath = APPLICATION_PATH "/modules/admin/layouts" # Views resources.view.encoding = "UTF-8" resources.view.basePath = APPLICATION_PATH "/views/" resources.view[] = resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" resources.modules[] = resources.view[] = admin.resources.view[] = [staging : production] [testing : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 application/Bootstrap.php <?php /** * Ensure all communications are managed by sessions. */ require_once ('Zend/Session.php'); Zend_Session::start(); class Bootstrap extends Zend_Application_Bootstrap_Bootstrap { protected function _initDoctype() { $this->bootstrap( 'view' ); $view = $this->getResource( 'view' ); $view->navigation = array(); $view->subnavigation = array(); $view->headTitle( 'Module One' ); $view->headLink()->appendStylesheet('/css/clear.css'); $view->headLink()->appendStylesheet('/css/main.css'); $view->headScript()->appendFile('/js/jquery.js'); $view->doctype( 'XHTML1_STRICT' ); //$view->navigation = $this->buildMenu(); } /*protected function _initAppAutoLoad() { $autoloader = new Zend_Application_Module_Autoloader(array( 'namespace' => 'default', 'basePath' => APPLICATION_PATH )); return $autoloader; }*/ protected function _initLayoutHelper() { $this->bootstrap('frontController'); $layout = Zend_Controller_Action_HelperBroker::addHelper( new ModuleLayoutLoader()); } public function _initControllers() { $front = Zend_Controller_Front::getInstance(); $front->addModuleDirectory(APPLICATION_PATH . '/modules/admin/', 'admin'); } protected function _initAutoLoadModuleAdmin() { $autoloader = new Zend_Application_module_Autoloader(array( 'namespace' => 'Admin', 'basePath' => APPLICATION_PATH . '/modules/admin' )); return $autoloader; } protected function _initModuleutoload() { $autoloader = new Zend_Application_Module_Autoloader ( array ('namespace' => '', 'basePath' => APPLICATION_PATH ) ); return $autoloader; } } class ModuleLayoutLoader extends Zend_Controller_Action_Helper_Abstract // looks up layout by module in application.ini { public function preDispatch() { $bootstrap = $this->getActionController() ->getInvokeArg('bootstrap'); $config = $bootstrap->getOptions(); echo $module = $this->getRequest()->getModuleName(); /*echo "Configs : <pre>"; print_r($config[$module]);*/ if (isset($config[$module]['resources']['layout']['layout'])) { $layoutScript = $config[$module]['resources']['layout']['layout']; $this->getActionController() ->getHelper('layout') ->setLayout($layoutScript); } } } application/modules/admin/Bootstrap.php <?php class Admin_Bootstrap extends Zend_Application_Module_Bootstrap { /*protected function _initAppAutoload() { $autoloader = new Zend_Application_Module_Autoloader(array( 'namespace' => 'admin', 'basePath' => APPLICATION_PATH . '/modules/admin/' )); return $autoloader; }*/ protected function _initDoctype() { $this->bootstrap( 'view' ); $view = $this->getResource( 'view' ); $view->navigation = array(); $view->subnavigation = array(); $view->headTitle( 'Module One' ); $view->headLink()->appendStylesheet('/css/clear.css'); $view->headLink()->appendStylesheet('/css/main.css'); $view->headScript()->appendFile('/js/jquery.js'); $view->doctype( 'XHTML1_STRICT' ); //$view->navigation = $this->buildMenu(); } } Please go through it and let me know any knows how do configure module and layout in right way.. Thanks and regards, Prasanth P

    Read the article

  • heimdal kerberos in openldap issue

    - by Brian
    I think I posted this on the wrong 'sister site', so here it is. I'm having a bit of trouble getting Kerberos (Heimdal version) to work nicely with OpenLDAP. The kerberos database is being stored in LDAP itself. The KDC uses SASL EXTERNAL authentication as root to access the container ou. I created the database in LDAP fine using kadmin -l, but it won't let me use kadmin without the -l flag: root@rds0:~# kadmin -l kadmin> list * krbtgt/REALM kadmin/changepw kadmin/admin changepw/kerberos kadmin/hprop WELLKNOWN/ANONYMOUS WELLKNOWN/org.h5l.fast-cookie@WELLKNOWN:ORG.H5L default brian.empson brian.empson/admin host/rds0.example.net ldap/rds0.example.net host/localhost kadmin> exit root@rds0:~# kadmin kadmin> list * brian.empson/admin@REALM's Password: <----- With right password kadmin: kadm5_get_principals: Key table entry not found kadmin> list * brian.empson/admin@REALM's Password: <------ With wrong password kadmin: kadm5_get_principals: Already tried ENC-TS-info, looping kadmin> I can get tickets without a problem: root@rds0:~# klist Credentials cache: FILE:/tmp/krb5cc_0 Principal: brian.empson@REALM Issued Expires Principal Nov 11 14:14:40 2012 Nov 12 00:14:37 2012 krbtgt/REALM@REALM Nov 11 14:40:35 2012 Nov 12 00:14:37 2012 ldap/rds0.example.net@REALM But I can't seem to change my own password without kadmin -l: root@rds0:~# kpasswd brian.empson@REALM's Password: <---- Right password New password: Verify password - New password: Auth error : Authentication failed root@rds0:~# kpasswd brian.empson@REALM's Password: <---- Wrong password kpasswd: krb5_get_init_creds: Already tried ENC-TS-info, looping kadmin's logs are not helpful at all: 2012-11-11T13:48:33 krb5_recvauth: Key table entry not found 2012-11-11T13:51:18 krb5_recvauth: Key table entry not found 2012-11-11T13:53:02 krb5_recvauth: Key table entry not found 2012-11-11T14:16:34 krb5_recvauth: Key table entry not found 2012-11-11T14:20:24 krb5_recvauth: Key table entry not found 2012-11-11T14:20:44 krb5_recvauth: Key table entry not found 2012-11-11T14:21:29 krb5_recvauth: Key table entry not found 2012-11-11T14:21:46 krb5_recvauth: Key table entry not found 2012-11-11T14:23:09 krb5_recvauth: Key table entry not found 2012-11-11T14:45:39 krb5_recvauth: Key table entry not found The KDC reports that both accounts succeed in authenticating: 2012-11-11T14:48:03 AS-REQ brian.empson@REALM from IPv4:192.168.72.10 for kadmin/changepw@REALM 2012-11-11T14:48:03 Client sent patypes: REQ-ENC-PA-REP 2012-11-11T14:48:03 Looking for PK-INIT(ietf) pa-data -- brian.empson@REALM 2012-11-11T14:48:03 Looking for PK-INIT(win2k) pa-data -- brian.empson@REALM 2012-11-11T14:48:03 Looking for ENC-TS pa-data -- brian.empson@REALM 2012-11-11T14:48:03 Need to use PA-ENC-TIMESTAMP/PA-PK-AS-REQ 2012-11-11T14:48:03 sending 294 bytes to IPv4:192.168.72.10 2012-11-11T14:48:03 AS-REQ brian.empson@REALM from IPv4:192.168.72.10 for kadmin/changepw@REALM 2012-11-11T14:48:03 Client sent patypes: ENC-TS, REQ-ENC-PA-REP 2012-11-11T14:48:03 Looking for PK-INIT(ietf) pa-data -- brian.empson@REALM 2012-11-11T14:48:03 Looking for PK-INIT(win2k) pa-data -- brian.empson@REALM 2012-11-11T14:48:03 Looking for ENC-TS pa-data -- brian.empson@REALM 2012-11-11T14:48:03 ENC-TS Pre-authentication succeeded -- brian.empson@REALM using aes256-cts-hmac-sha1-96 2012-11-11T14:48:03 ENC-TS pre-authentication succeeded -- brian.empson@REALM 2012-11-11T14:48:03 AS-REQ authtime: 2012-11-11T14:48:03 starttime: unset endtime: 2012-11-11T14:53:00 renew till: unset 2012-11-11T14:48:03 Client supported enctypes: aes256-cts-hmac-sha1-96, aes128-cts-hmac-sha1-96, des3-cbc-sha1, arcfour-hmac-md5, using aes256-cts-hmac-sha1-96/aes256-cts-hmac-sha1-96 2012-11-11T14:48:03 sending 704 bytes to IPv4:192.168.72.10 2012-11-11T14:45:39 AS-REQ brian.empson/admin@REALM from IPv4:192.168.72.10 for kadmin/admin@REALM 2012-11-11T14:45:39 Client sent patypes: REQ-ENC-PA-REP 2012-11-11T14:45:39 Looking for PK-INIT(ietf) pa-data -- brian.empson/admin@REALM 2012-11-11T14:45:39 Looking for PK-INIT(win2k) pa-data -- brian.empson/admin@REALM 2012-11-11T14:45:39 Looking for ENC-TS pa-data -- brian.empson/admin@REALM 2012-11-11T14:45:39 Need to use PA-ENC-TIMESTAMP/PA-PK-AS-REQ 2012-11-11T14:45:39 sending 303 bytes to IPv4:192.168.72.10 2012-11-11T14:45:39 AS-REQ brian.empson/admin@REALM from IPv4:192.168.72.10 for kadmin/admin@REALM 2012-11-11T14:45:39 Client sent patypes: ENC-TS, REQ-ENC-PA-REP 2012-11-11T14:45:39 Looking for PK-INIT(ietf) pa-data -- brian.empson/admin@REALM 2012-11-11T14:45:39 Looking for PK-INIT(win2k) pa-data -- brian.empson/admin@REALM 2012-11-11T14:45:39 Looking for ENC-TS pa-data -- brian.empson/admin@REALM 2012-11-11T14:45:39 ENC-TS Pre-authentication succeeded -- brian.empson/admin@REALM using aes256-cts-hmac-sha1-96 2012-11-11T14:45:39 ENC-TS pre-authentication succeeded -- brian.empson/admin@REALM 2012-11-11T14:45:39 AS-REQ authtime: 2012-11-11T14:45:39 starttime: unset endtime: 2012-11-11T15:45:39 renew till: unset 2012-11-11T14:45:39 Client supported enctypes: aes256-cts-hmac-sha1-96, aes128-cts-hmac-sha1-96, des3-cbc-sha1, arcfour-hmac-md5, using aes256-cts-hmac-sha1-96/aes256-cts-hmac-sha1-96 2012-11-11T14:45:39 sending 717 bytes to IPv4:192.168.72.10 I wish I had more detailed logging messages, running kadmind in debug mode seems to almost work but it just kicks me back to the shell when I type in the correct password. GSSAPI via LDAP doesn't work either, but I suspect it's because some parts of kerberos aren't working either: root@rds0:~# ldapsearch -Y GSSAPI -H ldaps:/// -b "o=mybase" o=mybase SASL/GSSAPI authentication started ldap_sasl_interactive_bind_s: Other (e.g., implementation specific) error (80) additional info: SASL(-1): generic failure: GSSAPI Error: Unspecified GSS failure. Minor code may provide more information () root@rds0:~# ldapsearch -Y EXTERNAL -H ldapi:/// -b "o=mybase" o=mybase SASL/EXTERNAL authentication started SASL username: gidNumber=0+uidNumber=0,cn=peercred,cn=external,cn=auth SASL SSF: 0 # extended LDIF <snip> Would anyone be able to point me in the right direction?

    Read the article

  • Secure method of changing a user's password via Python script/non-interactively

    - by Matthew Rankin
    I've created a Python script using Fabric to configure a freshly built Slicehost Ubuntu slice. In case you're not familiar with Fabric, it uses Paramiko, a Python SSH2 client, to provide remote access "for application deployment or systems administration tasks." One of the first things I have the Fabric script do is to create a new admin user and set their password. Unlike Pexpect, Fabric cannot handle interactive commands on the remote system, so I need to set the user's password non-interactively. At present, I'm using the chpasswd command to change the password. This transmits the password as clear text over SSH to the remote system. Questions Is my current method of setting the password a security concern? Currently, the drawback I see is that Fabric shows the password as clear text on my local system as follows: [xxx.xx.xx.xxx] run: echo "johnsmith:supersecretpassw0rd" | chpasswd. Since I only run the Fabric script from my laptop, I don't think this is a security issue, but I'm interested in others' input. Is there a better method for setting the user's password non-interactively? Another option, would be to use Pexpect from within the Fabric script to set the password. Current Code # Fabric imports and host configuration excluded for brevity root_password = getpass.getpass("Root's password given by SliceManager: ") admin_username = prompt("Enter a username for the admin user to create: ") admin_password = getpass.getpass("Enter a password for the admin user: ") env.user = 'root' env.password = root_password # Create the admin group and add it to the sudoers file admin_group = 'admin' run('addgroup {group}'.format(group=admin_group)) run('echo "%{group} ALL=(ALL) ALL" >> /etc/sudoers'.format( group=admin_group) ) # Create the new admin user (default group=username); add to admin group run('adduser {username} --disabled-password --gecos ""'.format( username=admin_username) ) run('adduser {username} {group}'.format( username=admin_username, group=admin_group) ) # Set the password for the new admin user run('echo "{username}:{password}" | chpasswd'.format( username=admin_username, password=admin_password) ) Local System Terminal I/O $ fab config_rebuilt_slice Root's password given by SliceManager: Enter a username for the admin user to create: johnsmith Enter a password for the admin user: [xxx.xx.xx.xxx] run: addgroup admin [xxx.xx.xx.xxx] out: Adding group `admin' (GID 1000) ... [xxx.xx.xx.xxx] out: Done. [xxx.xx.xx.xxx] run: echo "%admin ALL=(ALL) ALL" >> /etc/sudoers [xxx.xx.xx.xxx] run: adduser johnsmith --disabled-password --gecos "" [xxx.xx.xx.xxx] out: Adding user `johnsmith' ... [xxx.xx.xx.xxx] out: Adding new group `johnsmith' (1001) ... [xxx.xx.xx.xxx] out: Adding new user `johnsmith' (1000) with group `johnsmith' ... [xxx.xx.xx.xxx] out: Creating home directory `/home/johnsmith' ... [xxx.xx.xx.xxx] out: Copying files from `/etc/skel' ... [xxx.xx.xx.xxx] run: adduser johnsmith admin [xxx.xx.xx.xxx] out: Adding user `johnsmith' to group `admin' ... [xxx.xx.xx.xxx] out: Adding user johnsmith to group admin [xxx.xx.xx.xxx] out: Done. [xxx.xx.xx.xxx] run: echo "johnsmith:supersecretpassw0rd" | chpasswd [xxx.xx.xx.xxx] run: passwd --lock root [xxx.xx.xx.xxx] out: passwd: password expiry information changed. Done. Disconnecting from [email protected]... done.

    Read the article

  • Is there anyway way to speed up Exchange 2007's Load Generator tool?

    - by JohnM
    I'm running Load Generator to test our new deployment before going live and the initialization process has been running for two days and is only at 25% for ~58000 user test. Does anyone know of a way to speed up this process? Surely it shouldn't take this long. Currently, I've got it running with one master and two remote servers and they aren't peaking out on CPU or Network utilization. Any help you could provide would be greatly appreciated.

    Read the article

  • (PHP) User is being forced to RE-LOGIN after trying to do something on an admin page

    - by hatorade
    I have created an admin panel for a client in PHP, which requires a login. Here is the code at the top of the admin page requiring the user to be logged in: admin.php <?php session_start(); require("_lib/session_functions.php"); require("_lib/db.php"); db_connect(); //if the user has not logged in if(!isLoggedIn()) { header('Location: login_form.php'); die(); } ?> Obviously, the if statement is what catches them and forces them to log in. Here is the code on the resulting login page: login_form.php <form name="login" action="login.php" method="post"> Username: <input type="text" name="username" /> Password: <input type="password" name="password" /> <input type="submit" value="Login" /> </form> Which posts info to this controller page: login.php <?php session_start(); //must call session_start before using any $_SESSION variables include '_lib/session_functions.php'; $username = $_POST['username']; $password = $_POST['password']; include '_lib/db.php'; db_connect(); // Connect to the DB $username = mysql_real_escape_string($username); $query = "SELECT password, salt FROM users WHERE username = '$username';"; $result = mysql_query($query); if(mysql_num_rows($result) < 1) //no such user exists { header('Location: login_form.php?login=fail'); die(); } $userData = mysql_fetch_array($result, MYSQL_ASSOC); db_disconnect(); $hash = hash('sha256', $password . $userData['salt']); if($hash != $userData['password']) //incorrect password { header('Location: login_form.php?login=fail'); die(); } else { validateUser(); //sets the session data for this user } header('Location: admin.php'); ?> and the session functions page that provides login functions contains this: session_functions.php <?php function validateUser() { session_regenerate_id (); //this is a security measure $_SESSION['valid'] = 1; $_SESSION['userid'] = $username; } function isLoggedIn() { if($_SESSION['valid']) return true; return false; } function logout() { $_SESSION = array(); //destroy all of the session variables if (ini_get("session.use_cookies")) { $params = session_get_cookie_params(); setcookie(session_name(), '', time() - 42000, $params["path"], $params["domain"], $params["secure"], $params["httponly"] ); } session_destroy(); } ?> I grabbed the sessions_functions.php code of an online tutorial, so it could be suspicious. Any ideas why the user logs in to the admin panel, tries to do something, is forced to re-login, and THEN is allowed to do stuff like normal in the admin panel?

    Read the article

  • What does the @ symbol mean in a file's permission settings?

    - by Shiki
    I'm on MacOSX, I did ln -s on a directory and these are the results: -rwxrwxr-x@ 1 shiki admin 970332 Mar 6 16:38 apc.so -rwxrwxr-x@ 1 shiki admin 653884 Mar 6 16:38 eaccelerator.so -rw-rw-r--@ 1 shiki admin 60064 Mar 6 16:38 gettext.a -rwxrwxr-x@ 1 shiki admin 80320 Mar 6 16:38 gettext.so -rw-rw-r--@ 1 shiki admin 514784 Mar 6 16:38 imap.a -rwxrwxr-x@ 1 shiki admin 3886132 Mar 6 16:38 imap.so What do those @ symbols mean?

    Read the article

  • How can I change my admin theme in symfony 1.4?

    - by JG
    I am using sfAdminJrollerTheme Plugin for some parts of my application, but when I generate new modules without admin generator, I lose same look and feel than jroller in my other application pages. I know maybe is good idea to use admin generator for everything but I cannot change all my modules. Regards,

    Read the article

  • "ldap_add: Naming violation (64)" error when configuring OpenLDAP

    - by user3215
    I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

    Read the article

  • How to Configure OpenLDAP on Ubuntu 10.04 Server

    - by user3215
    I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

    Read the article

  • How to configure ldap on ubuntu 10.04 server

    - by user3215
    I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

    Read the article

  • Anomaly with bash PS1 definition

    - by Michael Wiles
    My root and admin user both have the same .bashrc file. The prompt section of the .bashrc is the following: if [ "$color_prompt" = yes ]; then PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u@\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$ ' else PS1='${debian_chroot:+($debian_chroot)}\u@\h:\w\$ ' fi unset color_prompt force_color_prompt # If this is an xterm set the title to user@host:dir case "$TERM" in xterm*|rxvt*) PS1="\[\e]0;${debian_chroot:+($debian_chroot)}\u@\h: \w\a\]$PS1" ;; *) ;; esac But the problem is that the admin user and root user have different prompts. admin's prompt is: admin@hostname:~$ and root's prompt is root@hostname:/home# So it seems root is using the "xterm" version and admin is not. Why does the .bashrc file have this difference in prompts? How do I get the admin user to also use the xterm version? How would I test that condition? If I run echo $TERM while running as the admin user I get xterm so as far as I can tell, it should be using the xterm version for the admin user.

    Read the article

  • django urls.py regex isn't working

    - by Phil
    This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

    Read the article

  • No route matches - after login attempt - even though the route exists?

    - by datorum
    I am working on a rails application and added a simple login system according to a book. I created the controller admin: rails generate controller admin login logout index It added the following routes to routes.db get "admin/login" get "admin/logout" get "admin/index" I can got to http://localhost:3000/admin/login there is no problem at all. But when I try to login I get: No route matches "/admin/login"! Now, the first confusing part is that the "login" method of my AdminController is not executed at all. The second confusing part is that this code works like a charm - redirects everything to /admin/login: def authorize unless User.find_by_id(session[:user_id]) flash[:notice] = "you need to login" redirect_to :controller => 'admin', :action => 'login' end end Sidenotes: I restarted the server several times. I tried a different browser - to be sure there is no caching problem.

    Read the article

< Previous Page | 40 41 42 43 44 45 46 47 48 49 50 51  | Next Page >