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  • Get insert statement query

    - by Karthick
    Hi, Is there a way to get the insert statements for a table via some query in MySql? for ex: if the table name is Cards,which has 5 rows, i need to get the insert statements for that particular table. Thanks.

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  • The best way to return related data in a SQL statement

    - by Darvis Lombardo
    I have a question on the best method to get back to a piece of data that is in a related table on the other side of a many-to-many relationship table. My first method uses joins to get back to the data, but because there are multiple matching rows in the relationship table, I had to use a TOP 1 to get a single row result. My second method uses a subquery to get the data but this just doesn't feel right. So, my question is, which is the preferred method, or is there a better method? The script needed to create the test tables, insert data, and run the two queries is below. Thanks for your advice! Darvis -------------------------------------------------------------------------------------------- -- Create Tables -------------------------------------------------------------------------------------------- DECLARE @TableA TABLE ( [A_ID] [int] IDENTITY(1,1) NOT NULL, [Description] [varchar](50) NULL) DECLARE @TableB TABLE ( [B_ID] [int] IDENTITY(1,1) NOT NULL, [A_ID] [int] NOT NULL, [Description] [varchar](50) NOT NULL) DECLARE @TableC TABLE ( [C_ID] [int] IDENTITY(1,1) NOT NULL, [Description] [varchar](50) NOT NULL) DECLARE @TableB_C TABLE ( [B_ID] [int] NOT NULL, [C_ID] [int] NOT NULL) -------------------------------------------------------------------------------------------- -- Insert Test Data -------------------------------------------------------------------------------------------- INSERT INTO @TableA VALUES('A-One') INSERT INTO @TableA VALUES('A-Two') INSERT INTO @TableA VALUES('A-Three') INSERT INTO @TableB (A_ID, Description) VALUES(1,'B-One') INSERT INTO @TableB (A_ID, Description) VALUES(1,'B-Two') INSERT INTO @TableB (A_ID, Description) VALUES(1,'B-Three') INSERT INTO @TableB (A_ID, Description) VALUES(2,'B-Four') INSERT INTO @TableB (A_ID, Description) VALUES(2,'B-Five') INSERT INTO @TableB (A_ID, Description) VALUES(3,'B-Six') INSERT INTO @TableC VALUES('C-One') INSERT INTO @TableC VALUES('C-Two') INSERT INTO @TableC VALUES('C-Three') INSERT INTO @TableB_C (B_ID, C_ID) VALUES(1, 1) INSERT INTO @TableB_C (B_ID, C_ID) VALUES(2, 1) INSERT INTO @TableB_C (B_ID, C_ID) VALUES(3, 1) -------------------------------------------------------------------------------------------- -- Get result - method 1 -------------------------------------------------------------------------------------------- SELECT TOP 1 C.*, A.Description FROM @TableC C JOIN @TableB_C BC ON BC.C_ID = C.C_ID JOIN @TableB B ON B.B_ID = BC.B_ID JOIN @TableA A ON B.A_ID = A.A_ID WHERE C.C_ID = 1 -------------------------------------------------------------------------------------------- -- Get result - method 2 -------------------------------------------------------------------------------------------- SELECT C.*, (SELECT A.Description FROM @TableA A WHERE EXISTS (SELECT * FROM @TableB_C BC JOIN @TableB B ON B.B_ID = BC.B_ID WHERE BC.C_ID = C.C_ID AND B.A_ID = A.A_ID)) FROM @TableC C WHERE C.C_ID = 1

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  • Modifying MySQL Where Statement Based on Array

    - by Ryan
    Using an array like this: $data = array ( 'host' => 1, 'country' => 'fr', ) I would like to create a MySQL query that uses the values of the array to form its WHERE clause like: SELECT * FROM table WHERE host = 1 and country = 'fr' How can I generate this query string to use with MySQL?

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  • Java PreparedStatement Throws MySQLSyntaxErrorException

    - by sqlBugs
    I have the following Java code: String query = "Select 1 from myTable where name = ? and age = ?"; PreparedStatement stmt = conn.prepareStatement(query); stmt.setString(1, name); stmt.setInt(2, age); ResultSet rs = stmt.executeQuery(); Whenever I run the above code, it throws an exception on line 2 (where the PreparedStatement is declared): Error 0221202: SQLException = com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? AND age = ?' at line 1 Does anyone have any suggestions about what I am doing wrong? Thanks!

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  • SQLite: Simple DELETE statement did not work

    - by user186446
    I have a table MRU, that has 3 columns. (VALUE varchar(255); TYPE varchar(20); DT_ADD datetime) This is a table simply storing an entry and recording the date time it was recorded. What I wanted to do is: delete the oldest entry whenever I add a new entry that exceeds a certain number. here is my query: delete from MRU where type = 'FILENAME' ORDER BY DT_ADD limit 1; The query returns an error. Thanks

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  • Why do I need the isset() function in php?

    - by Chris
    I am trying to understand the difference between this: if (isset($_POST['Submit'])) { //do something } and if ($_POST['Submit']) { //do something } It seems to me that if the $_POST['Submit'] variable is true, then it is set. Why would I need the isset() function in this case?

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  • Lambda "if" statement?

    - by AndyC
    I have 2 objects, both of which I want to convert to dictionarys. I use toDictionary<(). The lambda expression for one object to get the key is (i = i.name). For the other, it's (i = i.inner.name). In the second one, i.name doesn't exist. i.inner.name ALWAYS exists if i.name doesn't. Is there a lambda expression I can use to combine these two? Basically to read as: "if i.name exists then set id to i.name, else set id to i.inner.name". Many thanks.

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  • Php function within SQL statement syntax

    - by Vafello
    I have the following code. I would like username to take the value of the getUserName function however I am fighting with syntax. Can anybody tell me what should be the correct one? $query = "SELECT user FROM users_entity WHERE username = getUserName()";

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  • one-liner if statements...

    - by snickered
    Total noob here so be gentle. I've looked everywhere and can't seem to find the answer to this. How do I condense the following? if (expression) { return true; } else { return false; } I can't get it to work since it's returning something vs. setting something. I've already seen things like this: somevar = (expression) ? value1 : value2; Like I said, please be gentle :)

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  • postgres syntax question for OR?

    - by Dashiell0415
    The first one below works, but, just wanted to see if there's a better way... If I'm trying to find all records that start with 'C' with either a flag of 2 or a status of 9, do I need to incorporate the 'C' criteria twice? i.e., "SELECT * FROM mytable WHERE name like 'C%' AND flag = 2 OR name like 'C%' AND status = 9" Or, is there a way quicker way to write it so that I only need to set 'C%' once?

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  • dynamically build Intersect statement ASP.NET

    - by TDDG
    I would like to use the IEnumerable function Intersect() to combine a few list and get the similar integers from each list. The problem I'm faced with is that I don't know how many list I will need to compare. Here is an example: A{1,2,3,4} B{1,2,3} C{1,2} results = A.Intersect(B).Intersect(C) This works great, but the next time around I may have a D{1,2} next time I come across the function. I'd like to use the Intersect method, but I'm open to new ideas as well.

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  • Which is faster: in_array() or a bunch of expressions in PHP?

    - by Darryl Hein
    Is it faster to do the following: if ($var != 'test1' && $var != 'test2' && $var != 'test3' && $var != 'test4') { ... } Or: if (!in_array($var, array('test1', 'test2', 'test3', 'test4') { ... } Is there a number of values at which point it's faster to do one or the other? (In this case, the array used in the second option doesn't alreay exist.)

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  • Javascript if/else statement in iframe

    - by gr33nh4t
    So I'm trying to use javascript to pop up a video, and need to know when I'm in an iframe so I can resize the video accordingly. When outside the iframe, I see three alerts ('this is seen by both', 'not in iframe', and 'this is after the fact') When in the iframe, I just see the first alert ('this is seen by both'). var handleViewVideoClick = function (dataAction, eventType, targetElement, dataActionElement) { alert('this is seen by both'); if ($('iframe', window.parent.document).length == 0) { alert('not in iframe'); } else { alert('in iframe'); } alert('this is after the fact...'); }; What's going on here?

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  • undefined index mode, which is the variable that case statement is looking for

    - by Brad
    receiving error: PHP Notice: Undefined index: mode in /web/ee_web/include/form-modal.php on line 51 line 51 switch($_GET["mode"]) { block of code it is in: switch($_GET["mode"]) { case "login": login_user(); break; case "logout": session_destroy(); print "<p>You are now logged out.</p>"; print "<p><input type=\"submit\" id=\"closeButton\" name=\"closeButton\" value=\"Close\" onclick=\"self.parent.tb_remove(); parent.location.reload(1);\" /></p>"; break; default: login_user(); //print "<p>How'd you end up here?</p>"; break; } The URL for the page is index.php?mode=logout, that is how I am passing the value into mode. Any way I could resolve this error message?

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  • Understanding PHP's way of reading if statements

    - by Masi
    How does PHP read if statements? I have the following if statements in this order if ( $number_of_figures_in_email < 6) { -- cut: gives false } if($number_of_emails > 0) { -- cut: gives false } if ( $number_of_emails == 0) { -- cut: gives true } The code behaves randomly. It sometimes goes to the third if clause and gives me a success, while sometimes to the one of the first two if clauses when the input variables are constant. This suggests me that I cannot code only with if statements.

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • Can this statement ever evaluate to FALSE?

    - by BojanG
    I stumbled upon this while doing a review and the author is not available: int n = Convert.ToInt32(text); if (((n > 0) || (n < 0)) || (n == 0)) { return 1; } The code in general looks solid and it's hard for me to believe that the only purpose of this snippet is to confuse reviewers, but I don't see a way for this condition to fail. Am I missing something?

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  • How to make NOT IN statement via Restrictions

    - by slavig
    I used this trick: List statuses = new ArrayList(); Criteria criteria = session.createCriteria(MessageQueue.class); criteria.add(Restrictions.not(Restrictions.in("message_status", statuses))); and this code creates: ...from MESSAGE_QUEUE mq where not (mq.message_status in (?, ?, ?, ?))... but I need: ...from MESSAGE_QUEUE mq where mq.message_status NOT IN (?, ?, ?, ?) Du you think they are equal statements?

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  • PHP, better to set the variable before if or use if/else?

    - by DssTrainer
    So a simple one that I just never could find a straight answer on. What is better (performance or otherwise): $var = false; If ($a == $b) { $var = true; } or If ($a == $b) { $var = true; } else { $var = false; } I've heard arguments for both ways. I find the first cleaner to ensure I have it set, and a little less code too. The pro being that you may only need to set it once without conditional. But the con being that if the argument is true, it gets set twice. I am assuming the second way is probably best practice

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  • Can't figure out what's wrong with my php/sql statement

    - by Olegious
    So this is probably a dumb beginner question, but I've been looking at it and can't figure it out. A bit of background: just practicing making a web app, a form on page 1 takes in some values from the user, posts them to the next page which contains the code to connect to the DB and populate the relevant tables. I establish the DB connection successfully, here's the code that contains the query: $conn->query("SET NAMES 'utf9'"); $query_str = "INSERT INTO 'qa'.'users' ('id', 'user_name','password' ,'email' ,'dob' ,'sx') VALUES (NULL, $username, $password, $email, $dob, $sx);"; $result = @$conn->query($query_str); Here's the error that is returned:Insert query failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''qa'.'users' ('id', 'user_name' ,'password' ,'email' ,'dob' ,'s' at line 1 Thanks in advance!

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  • Java using enum with switch statement

    - by MisterSquonk
    I've looked at various Q&As on SO similar to this question but haven't found a solution. What I have is an enum which represents different ways to view a TV Guide... static enum guideView { GUIDE_VIEW_SEVEN_DAY, GUIDE_VIEW_NOW_SHOWING, GUIDE_VIEW_ALL_TIMESLOTS } ...when the user changes the view an event handler receives an int from 0-2 and I'd like to do something like this... // 'which' is an int from 0-2 switch (which) { case NDroid.guideView.GUIDE_VIEW_SEVEN_DAY: ... break; } I'm used to C# enums and select/case statements which would allow something like the above and I know Java does things differently but I just can't make sense of what I need to do. Am I going to have to resort to if statements? There will likely only ever be 3 choices so I could do it but I wondered how it could be done with switch-case in Java.

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  • variable scope in statement blocks

    - by fearofawhackplanet
    for (int i = 0; i < 10; i++) { Foo(); } int i = 10; // error, 'i' already exists ---------------------------------------- for (int i = 0; i < 10; i++) { Foo(); } i = 10; // error, 'i' doesn't exist By my understanding of scope, the first example should be fine. The fact neither of them are allowed seems even more odd. Surely 'i' is either in scope or not. Is there something non-obvious about scope I don't understand which means the compiler genuinely can't resolve this? Or is just a case of nanny-state compilerism?

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