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  • Unable to locate using find element by link

    - by First Rock
    Newbie in testing. I generated a test case using Selenium, and then exported it as a Python script. Now, when I try to run that in terminal, I get following error: raise exception_class(message, screen, stacktrace) NoSuchElementException: Message: u'Unable to locate element: {"method":"link text","selector":"delete"}' I am using the command generated by Selenium i.e driver.find_element_by_link_text("delete").click() The reason for the error I believe is that the link "delete" in my web page is seen only when I click on a particular line to be deleted. So I guess it is being unable to locate the link. Please suggest what alternative measure could I use to locate and click on the "delete" link. Thanks in Advance:)

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  • jQuery dont see onclick event on link inside infowindow in google maps v3

    - by Charles
    i have such problem that jQuery onclick event dont see click on link inside google map in infowindow. Thats how my infowindow link looks like: <a href="http://example.com/#ui-accordion-accordion-header-7" class="pull-right move-to-acc" id="itemH">See Details</a> Under map i have acordion list with detailed information about point so im trying to catch click on that link : jQuery("#itemH").click(function(event){ alert("qq"); }); When i click on marker infowindow open and i click on link but alert dont show up - im just moved to div #ui-accordion-accordion-header-7 What im doing wrong ? Thx for help

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  • Click at link by address template

    - by Ockonal
    Hello, I'm using Selenium for making some work: script should click at link followed by it's own address. For example, there is a method: clickAndWait. I have to pass it link title. But at my page this title changes, so I have to pass address to click at. Could you help me with this? p.s. I asked this question in selenium group, but still have no answer. upd: For exampe, I have such html-code: <a href="lalala.com">Some changeable title</a> <a href="another.com">Some changeable title</a> And selenium pseudocode: ClickAndWait('Some changeable title') But I have to click at site 'another.com', not 'lalala.com'. And link's title changes every time. Only link address is the same.

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  • How to make link become inactive?

    - by Konstantin Vasilcov
    The idea was simple: change li background color on hover to one color ul#menu li a:hover {...} change it on mouse press to the other color ul#menu li a:active {...} return the color to the original (normal) if the link is neither hover nor pressed The problem appeared to be that, if user rejected his intention and lets the mouse up away from the link, the back color stays as if it was pressed. Then I tried to research and came up with this: ul#menu li a:hover:active {...} It became better, and the link is not marked with special back color in a normal state after user presses the link and rejects. But the "on-hover" back color became equal to the active one. So it looks like the link gets "active" state and stays in it even after user releases mouse button. Hate to write this, but I am very new to html and css. So I may be missing something very basic here. Could you, please, suggest any way, how to achieve my goal? EDIT I've read this source CSS Styling links (thought there could be some other state to use instead of active), but found nothing suitable there...

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  • (JQuery) How to call a custom function before following link

    - by morpheous
    I want to achieve the following behavior in a page link. When the link is clicked, I want to: First, send (POST) some data back to the server Second, allow the browser to navigate to the url that the link was pointing to. I am relatively new to JQuery, and here is my first attempt below. I will be grateful to any jQuery gurus in here to fillin the blanks (and maybe point out how the snippet below may be improved). <html> <head>test page</head> <body> <div><a id="hotlink" href="http://www.example.com">Clik and see</a></div> </body> <script type="text/javascript"> $(document).ready(function(){ $('hotlink').click(function(){ //AJAX Post data here ... //follow the link url (i.e. navigate/browse to the link) ... }); }); </script> </html>

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  • TinyMce plugin, how to copy 'Link' functionality.

    - by Tom
    I'm creating a new plugin for TinyMce. However I cannot find any examples to see some of the functionality I've seen in other plugins. I've read their source code but I cannot find where it is done: When you click on an 'A' element, the link/unlink buttons in the taskbar become enabled. When you right click on an 'A' element, then click on the "Insert/edit link" icon that is shown in the popup menu, the "Insert/edit link" window is setup (has all the attributes for that particular link) prefilled. Could you suggest somewhere where I could learn how to do this? A file and line number is fine. Thanks in advance.

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  • Silverlight 4 Twitter Client &ndash; Part 6

    - by Max
    In this post, we are going to look into implementing lists into our twitter application and also about enhancing the data grid to display the status messages in a pleasing way with the profile images. Twitter lists are really cool feature that they recently added, I love them and I’ve quite a few lists setup one for DOTNET gurus, SQL Server gurus and one for a few celebrities. You can follow them here. Now let us move onto our tutorial. 1) Lists can be subscribed to in two ways, one can be user’s own lists, which he has created and another one is the lists that the user is following. Like for example, I’ve created 3 lists myself and I am following 1 other lists created by another user. Both of them cannot be fetched in the same api call, its a two step process. 2) In the TwitterCredentialsSubmit method we’ve in Home.xaml.cs, let us do the first api call to get the lists that the user has created. For this the call has to be made to https://twitter.com/<TwitterUsername>/lists.xml. The API reference is available here. myService1.AllowReadStreamBuffering = true; myService1.UseDefaultCredentials = false; myService1.Credentials = new NetworkCredential(GlobalVariable.getUserName(), GlobalVariable.getPassword()); myService1.DownloadStringCompleted += new DownloadStringCompletedEventHandler(ListsRequestCompleted); myService1.DownloadStringAsync(new Uri("https://twitter.com/" + GlobalVariable.getUserName() + "/lists.xml")); 3) Now let us look at implementing the event handler – ListRequestCompleted for this. public void ListsRequestCompleted(object sender, System.Net.DownloadStringCompletedEventArgs e) { if (e.Error != null) { StatusMessage.Text = "This application must be installed first."; parseXML(""); } else { //MessageBox.Show(e.Result.ToString()); parseXMLLists(e.Result.ToString()); } } 4) Now let us look at the parseXMLLists in detail xdoc = XDocument.Parse(text); var answer = (from status in xdoc.Descendants("list") select status.Element("name").Value); foreach (var p in answer) { Border bord = new Border(); bord.CornerRadius = new CornerRadius(10, 10, 10, 10); Button b = new Button(); b.MinWidth = 70; b.Background = new SolidColorBrush(Colors.Black); b.Foreground = new SolidColorBrush(Colors.Black); //b.Width = 70; b.Height = 25; b.Click += new RoutedEventHandler(b_Click); b.Content = p.ToString(); bord.Child = b; TwitterListStack.Children.Add(bord); } So here what am I doing, I am just dynamically creating a button for each of the lists and put them within a StackPanel and for each of these buttons, I am creating a event handler b_Click which will be fired on button click. We will look into this method in detail soon. For now let us get the buttons displayed. 5) Now the user might have some lists to which he has subscribed to. We need to create a button for these as well. In the end of TwitterCredentialsSubmit method, we need to make a call to http://api.twitter.com/1/<TwitterUsername>/lists/subscriptions.xml. Reference is available here. The code will look like this below. myService2.AllowReadStreamBuffering = true; myService2.UseDefaultCredentials = false; myService2.Credentials = new NetworkCredential(GlobalVariable.getUserName(), GlobalVariable.getPassword()); myService2.DownloadStringCompleted += new DownloadStringCompletedEventHandler(ListsSubsRequestCompleted); myService2.DownloadStringAsync(new Uri("http://api.twitter.com/1/" + GlobalVariable.getUserName() + "/lists/subscriptions.xml")); 6) In the event handler – ListsSubsRequestCompleted, we need to parse through the xml string and create a button for each of the lists subscribed, let us see how. I’ve taken only the “full_name”, you can choose what you want, refer the documentation here. Note the point that the full_name will have @<UserName>/<ListName> format – this will be useful very soon. xdoc = XDocument.Parse(text); var answer = (from status in xdoc.Descendants("list") select status.Element("full_name").Value); foreach (var p in answer) { Border bord = new Border(); bord.CornerRadius = new CornerRadius(10, 10, 10, 10); Button b = new Button(); b.Background = new SolidColorBrush(Colors.Black); b.Foreground = new SolidColorBrush(Colors.Black); //b.Width = 70; b.MinWidth = 70; b.Height = 25; b.Click += new RoutedEventHandler(b_Click); b.Content = p.ToString(); bord.Child = b; TwitterListStack.Children.Add(bord); } Please note, I am setting the button width to be auto based on the content and also giving it a midwidth value. I wanted to create a rounded corner buttons, but for some reason its not working. Also add this StackPanel – TwitterListStack of the Home.xaml <StackPanel HorizontalAlignment="Center" Orientation="Horizontal" Name="TwitterListStack"></StackPanel> After doing this, you would get a series of buttons in the top of the home page. 7) Now the button click event handler – b_Click, in this method, once the button is clicked, I call another method with the content string of the button which is clicked as the parameter. Button b = (Button)e.OriginalSource; getListStatuses(b.Content.ToString()); 8) Now the getListsStatuses method: toggleProgressBar(true); WebRequest.RegisterPrefix("http://", System.Net.Browser.WebRequestCreator.ClientHttp); WebClient myService = new WebClient(); myService.AllowReadStreamBuffering = true; myService.UseDefaultCredentials = false; myService.DownloadStringCompleted += new DownloadStringCompletedEventHandler(TimelineRequestCompleted); if (listName.IndexOf("@") > -1 && listName.IndexOf("/") > -1) { string[] arrays = null; arrays = listName.Split('/'); arrays[0] = arrays[0].Replace("@", " ").Trim(); //MessageBox.Show(arrays[0]); //MessageBox.Show(arrays[1]); string url = "http://api.twitter.com/1/" + arrays[0] + "/lists/" + arrays[1] + "/statuses.xml"; //MessageBox.Show(url); myService.DownloadStringAsync(new Uri(url)); } else myService.DownloadStringAsync(new Uri("http://api.twitter.com/1/" + GlobalVariable.getUserName() + "/lists/" + listName + "/statuses.xml")); Please note that the url to look at will be different based on the list clicked – if its user created, the url format will be http://api.twitter.com/1/<CurentUser>/lists/<ListName>/statuses.xml But if it is some lists subscribed, it will be http://api.twitter.com/1/<ListOwnerUserName>/lists/<ListName>/statuses.xml The first one is pretty straight forward to implement, but if its a list subscribed, we need to split the listName string to get the list owner and list name and user them to form the string. So that is what I’ve done in this method, if the listName has got “@” and “/” I build the url differently. 9) Until now, we’ve been using only a few nodes of the status message xml string, now we will look to fetch a new field - “profile_image_url”. Images in datagrid – COOL. So for that, we need to modify our Status.cs file to include two more fields one string another BitmapImage with get and set. public string profile_image_url { get; set; } public BitmapImage profileImage { get; set; } 10) Now let us change the generic parseXML method which is used for binding to the datagrid. public void parseXML(string text) { XDocument xdoc; xdoc = XDocument.Parse(text); statusList = new List<Status>(); statusList = (from status in xdoc.Descendants("status") select new Status { ID = status.Element("id").Value, Text = status.Element("text").Value, Source = status.Element("source").Value, UserID = status.Element("user").Element("id").Value, UserName = status.Element("user").Element("screen_name").Value, profile_image_url = status.Element("user").Element("profile_image_url").Value, profileImage = new BitmapImage(new Uri(status.Element("user").Element("profile_image_url").Value)) }).ToList(); DataGridStatus.ItemsSource = statusList; StatusMessage.Text = "Datagrid refreshed."; toggleProgressBar(false); } We are here creating a new bitmap image from the image url and creating a new Status object for every status and binding them to the data grid. Refer to the Twitter API documentation here. You can choose any column you want. 11) Until now, we’ve been using the auto generate columns for the data grid, but if you want it to be really cool, you need to define the columns with templates, etc… <data:DataGrid AutoGenerateColumns="False" Name="DataGridStatus" Height="Auto" MinWidth="400"> <data:DataGrid.Columns> <data:DataGridTemplateColumn Width="50" Header=""> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate> <Image Source="{Binding profileImage}" Width="50" Height="50" Margin="1"/> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> <data:DataGridTextColumn Width="Auto" Header="User Name" Binding="{Binding UserName}" /> <data:DataGridTemplateColumn MinWidth="300" Width="Auto" Header="Status"> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate> <TextBlock TextWrapping="Wrap" Text="{Binding Text}"/> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> </data:DataGrid.Columns> </data:DataGrid> I’ve used only three columns – Profile image, Username, Status text. Now our Datagrid will look super cool like this. Coincidentally,  Tim Heuer is on the screenshot , who is a Silverlight Guru and works on SL team in Microsoft. His blog is really super. Here is the zipped file for all the xaml, xaml.cs & class files pages. Ok let us stop here for now, will look into implementing few more features in the next few posts and then I am going to look into developing a ASP.NET MVC 2 application. Hope you all liked this post. If you have any queries / suggestions feel free to comment below or contact me. Cheers! Technorati Tags: Silverlight,LINQ,Twitter API,Twitter,Silverlight 4

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  • Why the Indian link builders or SEO companies can make so many high quality links at the same time? [closed]

    - by chiba
    There are a lot of Indian SEO companies or link builders that offer a lot of high quality link. Some of them for example offer links just from "co.uk" or "French site" with high page ranks. I have heard that even the SEO companies from other countries outsource link building to India. Do they have special connections for building links ? or Do they exchange the information between another Indian companies and have a big database of the sites where they can link?

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  • css problem with unordered lists (as usual with IE)

    - by Emin
    I am using un-ordered lists that nests some divs to show the desired output on screen. I am using css to style them and they seem to look perfect on chrome and firefox. But in IE(8) it looks there is a problem which I was unable to locate. I am using the below CSS <style type="text/css"> .ur_container {width:980px; padding: 0; margin: 0;} .ur_container ul.bx_grp {list-style-type: none; padding: 0px; margin: 0px; } .ur_container ul.bx_lnx {list-style-type: none; padding: 5px; margin: 0px; } .bx_grp {border:1px solid #c5c5c5; background-color: yellow; margin:0; padding:0;} .bx_grp_header {background-color: #d6d6d6; border-bottom:1px solid #acacac;} .bx_grp_title {float: left; font: bold 11px Arial; padding:5px;} .bx_grp_options {float: right; font: 10px Arial; padding: 5px;} .bx_grp_options a{color: #125B93; text-decoration: none; } .bx_lnx {padding:0px; background-color: red;} .bx_lnx_header {font:11px Arial; color:#333;} .bx_lnx_title {float: left;} .bx_lnx_refno {background-color:#333; color: fff; padding: 1px; margin-right: 5px; } .bx_lnx_options {float: right;} .bx_lnx_options a {color: #258CF4; text-decoration: none;} .bx_lnx_url {font: 9px Arial; color: #999; margin-top: 4px; } .bx_lnx_notes {} .bx_lnx_notes span {background-color: #FDFFCC; color: #666; font: 9px Arial; padding:2px;} .bx_lnx_tags {} .bx_lnx_tags span {background-color: #efefef; border-bottom: 1px solid #ccc; color: #666; font: 9px Arial; padding: 1px 2px 1px 2px; margin-right: 5px;} </style> Against the following HTML <div class="ur_container"> <ul class="bx_grp" id="grp_1"> <li> <div class="bx_grp_header"> <span class="bx_grp_title">Personal File</span> <span class="bx_grp_options"><a href="#">rename</a> &bull; <a href="#">make private</a> &bull; <a href="#">hide</a href="#"> &bull; <a href="#">delete</a></span> <div style="clear: both;"></div> </div> </li> <li> <ul class="bx_lnx" id="lnx_1"> <li> <div class="bx_lnx_header"> <span class="bx_linx_title"><span class="bx_lnx_refno">#3103</span>How to file personal files</span> <span class="bx_lnx_options"><a href="#">edit</a> &bull; <a href="#">move</a> &bull; <a href="#">delete</a></span> </div> </li> <li class="bx_lnx_url">http://www.google.com</li> <li class="bx_lnx_notes"><span>search google for this</span></li> <li class="bx_lnx_tags"><span>personal</span><span>file</span><span>google</span></li> </ul> </li> </ul> </div> Which produces this output in Chrome and Fireworks and the following in IE The yellow and red colors was used in order to show that is being going wrong. The yellow part is the undesired one. Can anyone point me in the right direction please ? Regards

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  • Linked lists in Java - Help with writing methods

    - by user368241
    Representation of a string in linked lists In every intersection in the list there will be 3 fields : The letter itself. The number of times it appears consecutively. A pointer to the next intersection in the list. The following class CharNode represents a intersection in the list : public class CharNode { private char _data; private int _value; private charNode _next; public CharNode (char c, int val, charNode n) { _data = c; _value = val; _next = n; } public charNode getNext() { return _next; } public void setNext (charNode node) { _next = node; } public int getValue() { return _value; } public void setValue (int v) { value = v; } public char getData() { return _data; } public void setData (char c) { _data = c; } } The class StringList represents the whole list : public class StringList { private charNode _head; public StringList() { _head = null; } public StringList (CharNode node) { _head = node; } } Add methods to the class StringList according to the details : (I will add methods gradually according to my specific questions) (Pay attention, these are methods from the class String and we want to fulfill them by the representation of a string by a list as explained above) Pay attention to all the possible error cases. Write what is the time complexity and space complexity of every method that you wrote. Make sure the methods you wrote are effective. It is NOT allowed to use ready classes of Java. It is NOT allowed to move to string and use string operations. 1) public int indexOf (int ch) - returns the index in the string it is operated on of the first appeareance of the char "ch". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex isn't in the range, returns -1. Here is my try : public int indexOf (int ch) { int count = 0; charNode pos = _head; if (pos == null ) { return -1; } for (pos = _head; pos!=null && pos.getData()!=ch; pos = pos.getNext()) { count = count + pos.getValue(); } if (pos==null) return -1; return count; } Time complexity = O(N) Space complexity = O(1) EDIT : I have a problem. I tested it in BlueJ and if the char ch doesn't appear it returns -1 but if it does, it always returns 0 and I don't understand why... I am confused. How can the compiler know that the value is the number of times the letter appears consecutively? Can I assume this because its given on the question or what? If it's true and I can assume this, then my code should be correct right? Ok I just spoke with my instructor and she said it isn't required to write it in the exercise but in order for me to test that it indeed works, I need to open a new class and write a code for making a list so that the the value of every node is the number of times the letter appears consecutively. Can someone please assist me? So I will copy+paste to BlueJ and this way I will be able to test all the methods. Meanwhile I am moving on to the next methods. 2) public int indexOf (int ch, int fromIndex) - returns the index in the string it is operated on of the first appeareance of the char "ch", as the search begins in the index "fromIndex". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex doesn't appear in the range, returns -1. Here is my try: public int indexOf (int ch, int fromIndex) { int count = 0, len=0, i; charNode pos = _head; CharNode cur = _head; for (pos = _head; pos!=null; pos = pos.getNext()) { len = len+1; } if (fromIndex<0 || fromIndex>=len) return -1; for (i=0; i<fromIndex; i++) { cur = cur.getNext(); } if (cur == null ) { return -1; } for (cur = _head; cur!=null && cur.getData()!=ch; cur = cur.getNext()) { count = count + cur.getValue(); } if (cur==null) return -1; return count; } Time complexity = O(N) ? Space complexity = O(1) 3) public StringList concat (String str) - returns a string that consists of the string that it is operated on and in its end the string "str" is concatenated. Here is my try : public StringList concat (String str) { String str = ""; charNode pos = _head; if (str == null) return -1; for (pos = _head; pos!=null; pos = pos.getNext()) { str = str + pos.getData(); } str = str + "str"; return str; } Time complexity = O(N) Space complexity = O(1)

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  • CSS Hover on parent list Item only

    - by Daniel O'Connor
    Hey Everyone, So I have some nested lists (only one level deep) and I'm running into trouble with the CSS :hover feature. I only want the hover to apply to the parent class, but I can't figure that one out. Here's my CSS <style type="text/css" media="screen"> .listblock li img { visibility: hidden; } .listblock li:hover img { visibility: visible; } </style> And here is a sample of one of the lists. <ul> <li>One <a href="#"><img src="img/basket.png" height="16" width="16" alt="Buy" class="buy" onClick="pageTracker._trackEvent('Outbound Links', 'Amazon');"/></a></li> <li>Two <a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a> <ul> <li>Uno<a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a></li> <li>Dos <a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a></li> </ul> </li> <li>Three <a href="#"><img src="img/basket.png" height="16" width="16" alt="Buy" class="buy" onClick="pageTracker._trackEvent('Outbound Links', 'Amazon');"/></a></li> </ul> The problem is that the image in the Uno and Dos list items also hovers. :( Help please! Thanks a lot

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  • Need help with copy constructor for very basic implementation of singly linked lists

    - by Jesus
    Last week, we created a program that manages sets of strings, using classes and vectors. I was able to complete this 100%. This week, we have to replace the vector we used to store strings in our class with simple singly linked lists. The function basically allows users to declare sets of strings that are empty, and sets with only one element. In the main file, there is a vector whose elements are a struct that contain setName and strSet (class). HERE IS MY PROBLEM: It deals with the copy constructor of the class. When I remove/comment out the copy constructor, I can declare as many empty or single sets as I want, and output their values without a problem. But I know I will obviously need the copy constructor for when I implement the rest of the program. When I leave the copy constructor in, I can declare one set, either single or empty, and output its value. But if I declare a 2nd set, and i try to output either of the first two sets, i get a Segmentation Fault. Moreover, if i try to declare more then 2 sets, I get a Segmentation Fault. Any help would be appreciated!! Here is my code for a very basic implementation of everything: Here is the setcalc.cpp: (main file) #include <iostream> #include <cctype> #include <cstring> #include <string> #include "help.h" #include "strset2.h" using namespace std; // Declares of structure to hold all the sets defined struct setsOfStr { string nameOfSet; strSet stringSet; }; // Checks if the set name inputted is unique bool isSetNameUnique( vector<setsOfStr> strSetArr, string setName) { for(unsigned int i = 0; i < strSetArr.size(); i++) { if( strSetArr[i].nameOfSet == setName ) { return false; } } return true; } int main(int argc, char *argv[]) { char commandChoice; // Declares a vector with our declared structure as the type vector<setsOfStr> strSetVec; string setName; string singleEle; // Sets a loop that will constantly ask for a command until 'q' is typed while (1) { // declaring a set to be empty if(commandChoice == 'd') { cin >> setName; // Check that the set name inputted is unique if (isSetNameUnique(strSetVec, setName) == true) { strSet emptyStrSet; setsOfStr set1; set1.nameOfSet = setName; set1.stringSet = emptyStrSet; strSetVec.push_back(set1); } else { cerr << "ERROR: Re-declaration of set '" << setName << "'\n"; } } // declaring a set to be a singleton else if(commandChoice == 's') { cin >> setName; cin >> singleEle; // Check that the set name inputted is unique if (isSetNameUnique(strSetVec, setName) == true) { strSet singleStrSet(singleEle); setsOfStr set2; set2.nameOfSet = setName; set2.stringSet = singleStrSet; strSetVec.push_back(set2); } else { cerr << "ERROR: Re-declaration of set '" << setName << "'\n"; } } // using the output function else if(commandChoice == 'o') { cin >> setName; if(isSetNameUnique(strSetVec, setName) == false) { // loop through until the set name is matched and call output on its strSet for(unsigned int k = 0; k < strSetVec.size(); k++) { if( strSetVec[k].nameOfSet == setName ) { (strSetVec[k].stringSet).output(); } } } else { cerr << "ERROR: No such set '" << setName << "'\n"; } } // quitting else if(commandChoice == 'q') { break; } else { cerr << "ERROR: Ignoring bad command: '" << commandChoice << "'\n"; } } return 0; } Here is the strSet2.h: #ifndef _STRSET_ #define _STRSET_ #include <iostream> #include <vector> #include <string> struct node { std::string s1; node * next; }; class strSet { private: node * first; public: strSet (); // Create empty set strSet (std::string s); // Create singleton set strSet (const strSet &copy); // Copy constructor // will implement destructor later void output() const; strSet& operator = (const strSet& rtSide); // Assignment }; // End of strSet class #endif // _STRSET_ And here is the strSet2.cpp (implementation of class) #include <iostream> #include <vector> #include <string> #include "strset2.h" using namespace std; strSet::strSet() { first = NULL; } strSet::strSet(string s) { node *temp; temp = new node; temp->s1 = s; temp->next = NULL; first = temp; } strSet::strSet(const strSet& copy) { cout << "copy-cst\n"; node *n = copy.first; node *prev = NULL; while (n) { node *newNode = new node; newNode->s1 = n->s1; newNode->next = NULL; if (prev) { prev->next = newNode; } else { first = newNode; } prev = newNode; n = n->next; } } void strSet::output() const { if(first == NULL) { cout << "Empty set\n"; } else { node *temp; temp = first; while(1) { cout << temp->s1 << endl; if(temp->next == NULL) break; temp = temp->next; } } } strSet& strSet::operator = (const strSet& rtSide) { first = rtSide.first; return *this; }

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  • Unix: softlinks, hardlinks

    - by sixtyfootersdude
    I am somewhat confused what the differences between a softlink, and a hardlink are (on unix). It seems like a softlink is the same as a shortcut in windows or an alias on Mac OS X. (Can someone confirm this?) Softlinks can link to both directories and files. I am uncertain of what a hardlink does or if it is useful.. Is it better to use one instead of the other? Thanks.

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  • How to Link Sub Taxonomy to products in wordpress

    - by rahul251
    I have created custom post types called Internal products I Have a page page-internal-products.php which list all the custom taxonomy for the Custom post type Internal product On clicking on the taxonomies takes me to a page which lists the sub taxonomies for the particular parent taxonomy for which i have created the page called taxonomy-internalproducts_categories.php On clicking on the sub taxonomy. I need to go to a page which lists all the products for this sub taxonomy. How can I achieve this?

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  • How do you create a mailing list with Lotus Notes?

    - by Richard Cotton
    I have a list of users of an application stored in an SQL database. I'd like to be able to email these people with useful information. Two parts to the question. How do I send queries to an SQL database from Lotus Notes (v6.5.5), in order to retrieve the email addresses? (I'm okay with what the contents of the query should be, I just need to know how to get Notes talking to the database.) How do I programmatically store these addresses as a group contact?

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  • Can't connect to LAN when connected to D-Link DIR-615

    - by Senseful
    I'm have a D-Link DIR-615 Wireless N 300 Router. I didn't use the CD it comes with to set up the network. Instead I configured it manually through the router's settings that are accessed via a web browser. The main changes I made are: Secured the router so that a password is required before clients can use the wireless internet. Broadcasting 802.11N only (not B or G). I can connect to the router just fine and I'm able to access the internet. The only problem is that I don't see any of the other computers in my LAN. When I try connecting to another Wi-Fi router that I have (which is connected to the same network), I can see all of the computer's on my LAN just fine. Therefore, I'm guessing that the reason I can't connect to the LAN is not a problem with my computer and is a problem with the router instead. I'm on a MacBook Air running Mac OS X 10.6.6. I tried contacting D-Link technical support, but they only try to help you if you have problems connecting to the internet. They aren't really concerned with problems that have to do with the accessing PC's on the same network.

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  • How can i link a oracle user to a business objects user

    - by Robert Speckmann
    I have a problem with linking the oracle user to a business objects user. I will try to explain it as detailed as possible; I have a Oracle database (10g) where a couple of users are defined. These users can query on information with application X. Those records will then be written into the oracle database. The records that is written into the database has a ID that links to the person that has run the query. I also have a active directory in wich a couple of users are made; testuser1, testuser2. When those users log on, and want to load a report in Business Objects XI i want them to see the information that was created when the report was activated by that same user that had runned the query before with application X. The name of the person in the active directory and the name in the oracle database are not the same but i dont think that would be a problem in this stage. So the steps i took: First, i run a report in application X (with a account prodpim_rs) wich fills my Oracle database with a record. The second step is logging on as testuser1 (from the AD) and then login on Business Objects XI with the account. Now i want to load a report with the information in my Oracle database. So the prodpim_rs user and the testuser must have a link between them. I am wondering how to forfill this. Can i link the account, wich is made in a Oracle database, with the user of BO wich is linked to my AD? Thank you in advance for your reply Robert

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  • Mailing List Solution

    - by Shoaibi
    I have more than 1M users and i need to send newsletters to. I have tried PHPList but it has failed as it gets stalled every 30K emails. I need a faster and more reliable solution.

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  • Linksys WAP54G v3.1 no access, power and link LED solid

    - by user142113
    I'm managing the Network of a small enterprise. A Linksys WAP54G v3.1 used to provide the WiFi network. I was called, because the device did not provide a WiFi network anymore. I first of all tried to ping the device via LAN, but there was no reaction. I've frequently reconnected the AP to the mains and always the POWER and the LINK LED keep solid, even if no network cable is connected. What I've done yet: Reset as documented: Pressed the RESET button for 10 seconds. After that I have tried to access the AP with a direct cable connection to my computer, that I've set to a static ip of 192.168.1.240, but i got no ping response on the default IP 192.168.1.245. Furthermore ipconfig reports "media disconnected". More complex reset method as described here http://bruceshankle.blogspot.de/2005/12/how-to-reset-linksys-wap54g.html as well had no effect. also tried to ping 192.168.1.1 without success Tried this method: http://www.daniweb.com/hardware-and-software/networking/threads/142437/linksys-wireless-access-point-problem#post680245 but there was no ping response when powering up. As well the tftp transfer timed out Finally tried to short pin 15 and 16 of the flash chip on the bottom side of the AP mainboard while booting to provoke a Checksum error. This should lead to the possibility to upload a firmware with tftp, as the AP stops booting and waits for a tftp connection on 192.168.1.1. But I've had no success. As well i've put pin 15 and 16 to ground while booting, also without an effect. After all that I still can't ping the AP, ipconfig still tells me "media disconnected". The POWER and LINK LED are solid. I would appreciate your answers

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