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  • Can't Enter Password in Recovery Mode

    - by Mike Lentini
    When I go into recovery mode to get to the command line, I enter "telinit 3" to drop out of root. This works on my desktop, but on my laptop it asks for my username and password, then I hit enter and the first letter of my password appears and it doesn't log me in. It then proceeds to ask me for my username and password again, and the issue continues. Am I doing something wrong? Is this a known issue with a solution? EDIT: Worked around this by going into /etc/default/grub and setting it to boot in text mode. Still would like a solution for this though.

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  • Can not enter password for sudo [duplicate]

    - by Michael
    This question already has an answer here: add repository to ubuntu from terminal with pgp key 3 answers I have used Ubuntu for several years, and I can not enter password for sudo, and this is when i wanna add a key to public.gpg for itunes10 it dos not work, and the password normal works wite sudo but not in the terminal when i enter: sudo wget -q "http:// deb.playonlinux.com/public.gpg" -o- | sudo apt-get add - and it says this 'sorry try again', and i just had installed itunes10, and have to add a key whit wget to public.gpg, and i tried to enter in the terminal: sudo apt-get update and the password works fine but not whit using sudo wget, and can some one please help.

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  • System that splits passwords across two servers

    - by Burning the Codeigniter
    I stumbled upon this news article on BBC, RSA splits passwords in two to foil hackers' attacks tl;dr - a (randomized) password is split in half and is stored across two separate servers, to foil hackers that gained access to either server upon a security breach. Now the main question is, how would this kind of system would be made... codespeaking, for PHP which I commonly develop on my web applications, the database password is normally stored in a configuration file, i.e. config.php with the username and password, in that case it is understandable that the passwords can be stolen if the security was compromised. However when splitting and sending the other half to the other server, how would this go on when making a communication to the other server (keeping in mind with PHP) since the other server password would be stored in a configuration file, wouldn't it? In terms of security is to keep the other server password away from the main one, just exactly how would the main server communicate, without exposing any other password, apart from the first server. This certainly makes me think...

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  • How to disable password prompt for default keyring?

    - by user110431
    I'm using Ubuntu 12.10 64Bit. How to disable ubuntu enter password for keyring default to unlock prompt ? Every time I open Chrome or ubuntu software center, this annoying window jump out. I have being searching online for a long time, most of the answers are like delete ~/.gnome2/keyring XX , but I don't have such directory or go to password and keys , disable some option, but this window is empty in my case, very strange , even I add a new password keyring, it is still empty. None of these methods works in my case. I will be very appreciate if you can help

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  • installation password

    - by tdot
    I just updated to ubuntu 11.10 and am getting "Your authentication attempt was unsuccessful." I am the only user and am the Administrator, during login on my keyring i set to logon automatically, but it still askes me for my password. So i put in my old one and it works. But when i go to install apps it asks again and nothing works! Also if i go to user accounts and try to unlock or change my password it won't let me! It says under password "None" so what's going on?! I'm new to Ubuntu! Help!

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  • WinRAR extracting file before checking password? [closed]

    - by opatachibueze
    I tried extracting an encrypted rar file today, and I discovered that I had to wait the same amount of time I'll wait before a file is extracted (extraction reaches 99% completion) for WinRAR to conclude it's the wrong password (winrar message: "CRC failed wrong password or corrupt file?") . My guess is that this file is somewhere on the Computer just before the detection, - it has to be and then gets deleted after it's verified that the password is not the same? Is there anyway I can forcefully get this file from the PC? Thanks.

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  • Encryption Password help!

    - by Carlos L.
    Ok so let me summarize this up. I encrypted my Home to protect against hackers of course when I first installed Ubuntu. It loaded up the Terminal and was attempting to show me my encryption password incase it ever needed to be used. So I thought "Ehh what the heck, I can find it out later..." So I closed Terminal and went on with the (amazing!) Ubuntu life. But now I am having to install Java JDK 7.0.0.4 onto my computer to ya know, play games and such. But it is asking for my password for the encrypted Home folder but it never gave it to me... HELP!!! Does anyone remember the command for Terminal to give you you're randomly generated Encryption password pop up on the famous purple window? Please give legitimate answer and fast please!

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  • Can't access my Ubuntu admin account

    - by Kermilli
    It just shows a black screen with words in it for a fraction of a second and then gets back to users screen(where you choose your user). I tried to enter from another account and removed the password for the admin account , but it didn't work too , and then I couldn't access my admin privileged places with my old password ? What should I do ? I tried to change my password from recovery but no success.

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  • Can't access my admin ubuntu account

    - by Kermilli
    It just shows a black screen with words in it for a fraction of a second and then gets back to users screen(where you choose your user). I tried to enter from another account and removed the password for the admin account , but it didn't work too , and then I couldn't access my admin privileged places with my old password ? What should I do ? I tried to change my password from recovery but no success.

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  • MySQL prevents server from booting unless password is entered

    - by ZaneKullman
    I am kind of new with Ubuntu but I have been working on setting up a LAMP server with hamachi as a vpn client for management. The issue is that when we turn the server on or restart it we are required to enter the MySQL password before it will continue. Where can we script a password or disable this? I have attached a partial of less /var/log/boot.log * Starting MySQL ServerESC[204G[ OK ] ....... ok Password: If I haven't provided enough information please just comment and Ill try my best.

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  • Remmina password problem with windows server 2008 R2

    - by Hcbayram
    I use Ubuntu 12.04. I am already using Remmina both with RDP and VNC connections for several servers. For one of my servers I have a problem to login after login window opens. The server is Windows 2008 R2. The screen for entering user and password comes but does not accept the password. I guess the problem is with language but password does not contain any problematic letter except a $ sign. When connecting from Windows 7 there is no problem.

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  • Full password not required to access password protected directory?

    - by user617123
    I password protected a directory in cPanel. When I went to access the page in my browser, I accidentally hit backspace on the password before I hit enter. Surprisingly, the page still loaded. I played around with it and realized that I could remove the last 4 or 5 characters and the password would still work. Any more than that and it would fail. I'm just curious why this behavior is happening and whether or not it's anything to worry about?

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  • Reuse security code between WCF and MVC.NET

    - by mrjoltcola
    First the background: I jumped into MVC.NET from the Java MVC world, so my implementation below is possibly cheating, I don't know. I avoided fooling with a custom membership provider and I just implemented the base code needed to authenticate and load roles in my LogOn action. Typically I just need to check roles programatically, and have no use for all of the other membership features, so I didn't originally think I needed a full Membership provider. I have a successful WCF project with a custom authentication and authorization layer that I did at least write per the proper API. I implemented it with custom IPrincipal, UserNamePasswordValidator and IAuthorizationPolicy classes to load from an Oracle database. In my WCF services, I use declarative security: [PrincipalPermission(SecurityAction.Demand, Role="ADMIN")]. The question (on the ASP.NET/MCV.NET side): All my reading indicates I should implement a custom Membership/Roles provider, and use [Authorize(Roles="ADMIN")] on my controller actions. At this point, I don't have a true Membership provider, but I'm using the same User class that implements the IPrincipal interface that works with the WCF security. I plan to share common code between the WCF and ASP.NET modules. So my LogOn action is not using the FormsService (and I assume this is bad). I had commented it out, and just used my "UserService" to access the Oracle db. Note my "TODO" comment below. public ActionResult LogOn(LogOnModel model, string returnUrl) { log.Info("Login attempt by " + model.UserName); if (ModelState.IsValid) { User user = userService.findByUserName(model.UserName); // Commented original MemberShipService code, this is probably bad // if (MembershipService.ValidateUser(model.UserName, model.Password)) if (user != null && user.Authenticate(model.Password) == true) { log.Info("Login success by " + model.UserName); FormsService.SignIn(model.UserName, model.RememberMe); // TODO: Override with Custom identity / roles? user.AddRoles(userService.listRolesByUser(user)); // pull in roles from db if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } else { log.Info("Login failure by " + model.UserName); ModelState.AddModelError("", "The user name or password provided is incorrect."); } } // If we got this far, something failed, redisplay form return View(model); } So can I make the above work? Can I stick the IPrincipal (User) into the CurrentContext or HttpContext? Can I integrate the custom IPrincipal I've already created without writing a full Membership/Roles Provider? I currently stick the User object into the session and access it from all MVC.NET controllers with "CurrentUser" property which grabs it from the session on demand. But this doesn't work with the [Authorize] attribute; I assume that is because it knows nothing about my custom Principal in the session, and is instead using whatever FormsService.SignIn() produces. I also found that session timeouts screw up the login redirect, the user doesn't get forwarded, instead we get a null exception accessing User from the session, and I assume it is related to my "skipping steps" to get a quick implementation. Thanks.

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  • OWSM custom security policy for JAX-WS, GenericFault

    - by sachin
    Hi, I tried creating custom security and policy as given here: http://download.oracle.com/docs/cd/E15523_01/relnotes.1111/e10132/owsm.htm#CIADFGGC when I run the service client custom assertion is executed, returning successfully. public IResult execute(IContext context) throws WSMException { try { System.out.println("public execute"); IAssertionBindings bindings = ((SimpleAssertion)(this.assertion)).getBindings(); IConfig config = bindings.getConfigs().get(0); IPropertySet propertyset = config.getPropertySets().get(0); String valid_ips = propertyset.getPropertyByName("valid_ips").getValue(); String ipAddr = ((IMessageContext)context).getRemoteAddr(); IResult result = new Result(); System.out.println("valid_ips "+valid_ips); if (valid_ips != null && valid_ips.trim().length() > 0) { String[] valid_ips_array = valid_ips.split(","); boolean isPresent = false; for (String valid_ip : valid_ips_array) { if (ipAddr.equals(valid_ip.trim())) { isPresent = true; } } System.out.println("isPresent "+isPresent); if (isPresent) { result.setStatus(IResult.SUCCEEDED); } else { result.setStatus(IResult.FAILED); result.setFault(new WSMException(WSMException.FAULT_FAILED_CHECK)); } } else { result.setStatus(IResult.SUCCEEDED); } System.out.println("result "+result); System.out.println("public execute complete"); return result; } catch (Exception e) { System.out.println("Exception e"); e.printStackTrace(); throw new WSMException(WSMException.FAULT_FAILED_CHECK, e); } } Console output is: public execute valid_ips 127.0.0.1,192.168.1.1 isPresent true result Succeeded public execute complete but, webservice throws GenericFault . Arguments: [void] Fault: GenericFault : generic error I have no clue what could be wrong, any ideas? here is the full stack trace: Exception in thread "main" javax.xml.ws.soap.SOAPFaultException: GenericFault : generic error at com.sun.xml.internal.ws.fault.SOAP12Fault.getProtocolException(SOAP12Fault.java:210) at com.sun.xml.internal.ws.fault.SOAPFaultBuilder.createException(SOAPFaultBuilder.java:119) at com.sun.xml.internal.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:108) at com.sun.xml.internal.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:78) at com.sun.xml.internal.ws.client.sei.SEIStub.invoke(SEIStub.java:107) at $Proxy30.sayHello(Unknown Source) at creditproxy.CreditRatingSoap12HttpPortClient.main(CreditRatingSoap12HttpPortClient.java:21) Caused by: javax.xml.ws.soap.SOAPFaultException: GenericFault : generic error at weblogic.wsee.jaxws.framework.jaxrpc.TubeFactory$JAXRPCTube.processRequest(TubeFactory.java:203) at weblogic.wsee.jaxws.tubeline.FlowControlTube.processRequest(FlowControlTube.java:99) at com.sun.xml.ws.api.pipe.Fiber.__doRun(Fiber.java:604) at com.sun.xml.ws.api.pipe.Fiber._doRun(Fiber.java:563) at com.sun.xml.ws.api.pipe.Fiber.doRun(Fiber.java:548) at com.sun.xml.ws.api.pipe.Fiber.runSync(Fiber.java:445) at com.sun.xml.ws.server.WSEndpointImpl$2.process(WSEndpointImpl.java:275) at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:454) at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:250) at com.sun.xml.ws.transport.http.servlet.ServletAdapter.handle(ServletAdapter.java:140) at weblogic.wsee.jaxws.HttpServletAdapter$AuthorizedInvoke.run(HttpServletAdapter.java:319) at weblogic.wsee.jaxws.HttpServletAdapter.post(HttpServletAdapter.java:232) at weblogic.wsee.jaxws.JAXWSServlet.doPost(JAXWSServlet.java:310) at javax.servlet.http.HttpServlet.service(HttpServlet.java:727) at weblogic.wsee.jaxws.JAXWSServlet.service(JAXWSServlet.java:87) at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) at weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227) at weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125) at weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:292) at weblogic.servlet.internal.TailFilter.doFilter(TailFilter.java:26) at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56) at oracle.dms.wls.DMSServletFilter.doFilter(DMSServletFilter.java:326) at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56) at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3592) at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321) at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:121) at weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2202) at weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2108) at weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1432) at weblogic.work.ExecuteThread.execute(ExecuteThread.java:201) at weblogic.work.ExecuteThread.run(ExecuteThread.java:173) Process exited with exit code 1.

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  • ldapsearch password file format

    - by orsogufo
    How am I supposed to pass a password to ldapsearch using the -y <password file> option? If I write the password in the password file in plain text, I get this error: ldap_bind: Invalid credentials (49) additional info: 80090308: LdapErr: DSID-0C0903AA, comment: AcceptSecurityContext error, data 52e, v1772 The same happens if I use the -w <password> option. Am I missing something?

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  • ec2 LAMP REDhat distro change mysql password error

    - by t q
    i am on ec2 plain linux and wish to change my mySQL password ive tried: sudo mysqladmin -u root -p '***old***' password '***new****' then it prompts me to enter password then i enter ***old*** but i keep getting an error message mysqladmin: connect to server at 'localhost' failed error: 'Access denied for user 'root'@'localhost' (using password: YES)' question: how do i change my current password?

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  • changing mysql password via java

    - by Osama Abukmail
    I'm trying to change a user's password on mysql using java, i successfully changed it on phpmyadmin but same command doesnt work on java SET PASSWORD = PASSWORD('12345') this command will change the current logged in user, i have tried it on java like this statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD = PASSWORD('12345')"); but nothing happened i also tried this with root logged in statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD FOR 'username'@'localhost' = PASSWORD('123456')"); and nothing work,, any help please

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  • PHP:How to send the original password to the user when he clicks forgot password which is encrypted

    - by kishore
    Hi all, I am using md5 to encrypt the passwords in my project. When user clicks on forgot password and submits his email,I have to send His password to him. But the password is encrypted using md5.Generating new password should not do. The initial password is very important. SO how can i decrypt the password or any other way to send him original password? Thanks in advance...

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  • Spring Security session-management setting and IllegalStateException

    - by JayL
    I'm trying to add <session-management> in my Spring Security namespace configuration so that I can provide a different message than the login page when the session times out. As soon as I add it to my configuration it starts throwing "IllegalStateException: Cannot create a session after the response has been committed" when I access the app. I'm using Spring Security 3 and Tomcat 6. Here's my configuration: <http> <intercept-url pattern="/go.htm" access="ROLE_RESPONDENT" /> <intercept-url pattern="/complete.htm" access="ROLE_RESPONDENT" /> <intercept-url pattern="/**" access="IS_AUTHENTICATED_ANONYMOUSLY" /> <form-login login-processing-url="/j_spring_security_check" login-page="/login.htm" authentication-failure-url="/login.htm?error=true" default-target-url="/go.htm" /> <anonymous/> <logout logout-success-url="/logout_message.htm"/> <session-management invalid-session-url="/login.htm" /> </http> Everything works great until I add in the <session-management> line. What am I missing?

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  • security policy error iphone ipod touch issue

    - by Joey
    I'm getting an "Error from Debugger: Error launching remote program: security policy error" when I try to run my app on my ipod touch. The provisions look in order, and the app builds to my iphone 3gs just fine. The app used to build just fine to my ipod touch, so I'm flustered what could have changed and wondering if anyone has any thoughts on what might be causing this issue. The build logs are below. Mon Mar 15 14:25:54 unknown com.apple.debugserver-43[449] : Connecting to com.apple.debugserver service... Mon Mar 15 14:25:55 unknown SpringBoard[24] : Unable to launch com.yourcompany.Unearthed because it has an invalid code signature, inadequate entitlements or its profile has not been explicitly trusted by the user. Mon Mar 15 14:25:55 unknown com.apple.debugserver-43[449] : error: unable to launch the application with CFBundleIdentifier 'com.yourcompany.Unearthed' sbs_error = 9 Mon Mar 15 14:25:55 unknown com.apple.debugserver-43[449] : 1 [01c1/0903]: RNBRunLoopLaunchInferior DNBProcessLaunch() returned error: '' Mon Mar 15 14:25:55 unknown com.apple.debugserver-43[449] : error: failed to launch process (null): security policy error Mon Mar 15 14:26:03 unknown MobileSafari[72] : void SendDelegateMessage(NSInvocation*): delegate (webView:decidePolicyForNavigationAction:request:frame:decisionListener:) failed to return after waiting 10 seconds. main run loop mode: UITrackingRunLoopMode

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  • How to access/use custom attribute in spring security based CAS client

    - by Bill Li
    I need send certain attributes(say, human readable user name) from server to client after a successful authentication. Server part was done. Now attribute was sent to client. From log, I can see: 2010-03-28 23:48:56,669 DEBUG Cas20ServiceTicketValidator:185 - Server response: [email protected] <cas:proxyGrantingTicket>PGTIOU-1-QZgcN61oAZcunsC9aKxj-cas</cas:proxyGrantingTicket> <cas:attributes> <cas:FullName>Test account 1</cas:FullName> </cas:attributes> </cas:authenticationSuccess> </cas:serviceResponse> Yet, I don't know how to access the attribute in client(I am using Spring security 2.0.5). In authenticationProvider, a userDetailsService is configured to read db for authenticated principal. <bean id="casAuthenticationProvider" class="org.springframework.security.providers.cas.CasAuthenticationProvider"> <sec:custom-authentication-provider /> <property name="userDetailsService" ref="clerkManager"/> <!-- other stuff goes here --> </bean> Now in my controller, I can easily do this: Clerk currentClerk = (Clerk)SecurityContextHolder.getContext().getAuthentication().getPrincipal(); Ideally, I can fill the attribute to this Clerk object as another property in some way. How to do this? Or what is recommended approach to share attributes across all apps under CAS's centralized nature?

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  • How do I use WS-Security with WCF?

    - by Jonathan Allen
    Below is the style of header I need to create. I am expected to use either a public/private key or a SSL style certificate. I don't know for certain, but I think my counter-party is using some form of Java. <soap-env:Header> <wsse:Security xmlns:wsse="http://schemas.xmlsoap.org/ws/2002/04/secext"> <ds:Signature xmlns:ds="http://www.w3.org/2000/09/xmldsig#"> <ds:SignedInfo xmlns:ds="http://www.w3.org/2000/09/xmldsig#"> <ds:CanonicalizationMethod Algorithm="http://www.w3.org/2001/10/xml-exc-c14n#" /> <ds:SignatureMethod Algorithm="http://www.w3.org/2000/09/xmldsig#rsa-sha1" /> <ds:Reference URI="#secinfo"> <ds:DigestMethod Algorithm="http://www.w3.org/2000/09/xmldsig#sha1" /> <ds:DigestValue>xxxxxxxxxxxxx</ds:DigestValue> <ds:Transforms> <ds:Transform Algorithm="http://www.w3.org/TR/1999/REC-xpath-19991116"> <ds:XPath>//*[@id='secinfo']/child::*/text()</ds:XPath> </ds:Transform> </ds:Transforms> </ds:Reference> </ds:SignedInfo> <ds:SignatureValue>xxxxxxxxxxds:SignatureValue> <ds:KeyInfo> <ds:KeyName>xxxxxxx</ds:KeyName> </ds:KeyInfo> </ds:Signature> <t:UsernameToken xmlns:t="http://schemas.xmlsoap.org/ws/2002/04/secext" id="secinfo"> <t:UserInfo>USER=xxxx;CORR=xxxx;TIMESTAMP=201003161916</t:UserInfo> </t:UsernameToken> </wsse:Security> </soap-env:Header>

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  • Flash Security Error Accessing URL with crossdomain.xml

    - by user163757
    Hello, I recently deployed a Flash application to a server, and am now experiencing errors when making HTTPService requests. I have put what I believe to be the most permissive crossdomain.xml possible in the wwwroot folder, and still get the errors. Interestingly enough, the error only seems to occur when the request is made from a direct user interaction (i.e. button click). The application makes other requests that are initiated by other means(i.e creationComplete) , and they seem to work as expected. Anyone see anything wrong with the crossdomain.xml, or have any other suggestions? ERROR MESSAGE [RPC Fault faultString="Security error accessing url" faultCode="Channel.Security.Error" faultDetail="Destination: DefaultHTTP"] at mx.rpc::AbstractInvoker/http://www.adobe.com/2006/flex/mx/internal%3A%3AfaultHandler() at mx.rpc::Responder/fault() at mx.rpc::AsyncRequest/fault() at DirectHTTPMessageResponder/securityErrorHandler() at flash.events::EventDispatcher/dispatchEventFunction() at flash.events::EventDispatcher/dispatchEvent() at flash.net::URLLoader/redirectEvent() <!DOCTYPE cross-domain-policy SYSTEM "http://www.macromedia.com/xml/dtds/cross-domain-policy.dtd"> <cross-domain-policy> <site-control permitted-cross-domain-policies="all" /> <allow-access-from domain="*" secure="false" /> <allow-http-request-headers-from domain="*" headers="*" secure="false" /> </cross-domain-policy>

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  • IE Security Warning with widgets

    - by superexsl
    Hey I'm creating an ASP.NET application which uses Facebook Connect and fbml tags. It also uses the LinkedIn widget. When I run this app in any browser, there are no warnings and everything works. However, in IE, a message like this comes up: Security Warning: The current webpage is trying to open a site in your Trusted sites list. Do you want to allow this? Current site:http://www.facebook.com Trusted site:http://localhost (same for LinkedIn.com). I know how to fix this from a client perspective and to stop the security warning showing up. However, is it possible to ensure this message doesn't come up as it could be off putting for users who don't know how to suppress this warning? I haven't tried uploading it to my webhost, so not sure if this message will appear for everyone in production. However, I always get it on my local machine. (None of my pages use SSL, so I don't think that's the issue. I tried using FB's HTTPS urls but that didn't make a difference). Thanks

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