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  • ASP.Net MVC 2 - How to set up a Cancel button with client side navigation

    - by arame3333
    Thanks to a previous question I found a useful link on multiple buttons. http://weblogs.asp.net/dfindley/archive/2009/05/31/asp-net-mvc-multiple-buttons-in-the-same-form.aspx What I want to do is have a cancel button on my page, similar to this; <button name="button" type="button" onclick="document.location.href=$('#cancelUrl').attr('href')">Cancel</button> <a id="cancelUrl" href="<%: Url.Action("Index", "Home") %>" style="display:none;"></a> However although this code works, I really want to go back to the previous page. For Web Forms I could use the javascript Back() or Go(-1) functions, but they relied on postbacks. I could of course hard code the previous page and controller as I have done above. However I am struggling to find links that explain to me how Url.Action works. Because if I do this, I also need to include an index parameter, and I am not clear how the syntax works for that. It seems odd the amount of coding to do this. Out of curiosity, I am also wondering how you TDD client side code like this.

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  • UITableView : detecting click on '-' button in edit mode

    - by synthez84
    Hi all, On my iphone app, I have a UITableView in edit mode, containing custom UITableViewCell. I would like to detect when user has clicked on the left button of each cell (minus circular red button, the one that is animated with a rotation), just before the "Delete" button appears. I would like to be able to change my cell content in that case... Is that possible ? Thanks !

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  • Suppressing the language select button iPhone

    - by AWinter
    I'm working on an application now that contains an account register section. One field with secureTextEntry = NO (for registering only). The idea is this make registration faster and hopefully increases the number of signups. It's simple enough for me to just place a regular UITextField but if the user has any additional language keyboards then it's possible for the user to enter non-password friendly characters. Unlike in when secureTextEntry = YES. I know I can do textField.keyboardType = UIKeyboardTypeASCIICapable to get the text field to display the ASCII keyboard first, but the user will still have the keyboard switch button which will allow them to get to undesirable characters. Is there a simple method for suppressing the international button or forcing ASCII only keyboard with no international button? [EDIT] Another perhaps better option might be to suppress multi byte keyboards or even to display the text in the case that secureTextEntry = YES any ideas here? [EDIT AGAIN] I've decided it's a really bad idea to suppress the international button as non-multibyte characters should all be allowed.

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  • "Outward" border-radius in css?

    - by MaxMackie
    Currently, the links at the top of my website look like this: However, I am trying to "round" the bottom edges of the buttons to make it look like they are coming out of the page and into the ribbon at the top. I am aware that you can hack it and add a "separator" div with rounded corners between each entry, but this would be difficult to do seeing at the borders used are not all from the same div. Also, it wouldn't be easy seeing as my buttons are very close to each other. The css for the "button": .button { border-top: 3px solid #A1C1BE; border-left: 3px solid #A1C1BE; border-right: 3px solid #A1C1BE; border-bottom: 0px; padding: 5px 8px 5px 8px; margin: 0 0 -9px 0; border-radius: 5px 5px 0 0; font-size: 12px; font-family: 'PT Sans', sans-serif; background-color: #f8f8ff; color: #484848; } css for the "ribbon": #top-wrapper { border-bottom: 5px solid #A1C1BE; width: 100%; background-color: #59554E; padding: 10px 0 0 0; color: #C0C0A8; } As you can see, the thicker border belongs to the ribbon which stretches the length of the webpage, whereas the thinner blue border is part of the button.

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  • how to create button in internet explorer?

    - by karikari
    I am developing a simple c++ program inside Microsoft Visual Studio. This program will later be convert to DLL, in order to register it to Internet Explorer. Inside my program, I would like to do like this: if flag=1, toolbar_button = green; else toolbar button = red; I want to create a simple button on the Internet Explorer, and the button can reflects the color that I pass from my c++ program. How can I achieve this?

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  • ASP.NET AsyncPostBackTrigger disables button's OnClick function???

    - by hahuang65
    I saw another post like this: http://stackoverflow.com/questions/1795621/asyncpostbacktrigger-disables-buttons But I don't really know what to make of it. The accepted answer was poorly typed. Basically, I have a button with an OnClick function. I also have a UpdatePanel, with is AsyncPostBackTrigger set to that same button. It seems that if I do this, my Button no longer does ANYTHING. I guess it's because I have a Page_Load() event... Can anyone explain why this is? And how should I set up my webpage if I can't use the Page_Load() function? Oh and if I put my Button in a UpdatePanel, it also won't do anything, probably because of the same reason. This is a section of my code: <asp:FileUpload id="FileUploadControl" runat="server" /> <asp:Button runat="server" id="UploadButton" text="Upload" OnClick="uploadClicked" /> <br /><br /> <asp:Label runat="server" id="StatusLabel" text="Upload status: " /> <br /> <asp:UpdatePanel ID="UpdatePanel2" runat="server" updatemode="Conditional" > <ContentTemplate> <asp:DropDownList ID="songList" runat="server" /> </ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="RefreshButton" /> </Triggers> </asp:UpdatePanel> Thanks in advance.

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  • How to get Facebook Login Button To Display "Logout"

    - by Will Merydith
    I apologize ahead of time if this is clearly documented somewhere on the FB developer site - but I can't find it (so please link me if appropriate). I've implemented the FB login button on a website using GAE + Python. Here is the HTML: <fb:login-button></fb:login-button> <div id="fb-root"></div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script> FB.init({appId: 'ad16a806fc10bef5d30881322e73be68', status: true, cookie: true, xfbml: true}); FB.Event.subscribe('auth.sessionChange', function(response) { if (response.session) { // A user has logged in, and a new cookie has been saved } else { // The user has logged out, and the cookie has been cleared } }); </script> Currently the behavior is - if I click on the "login" button, I am asked to allow the application access to FB. Which I then choose, "OK". But then the login button is still showing "login" and not "logout". How do I implement that? On the server or client side?

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  • C#: Drag & Drop with right mouse button

    - by stefan.at.wpf
    Hello, I'd like to do Drag & Drop with the right mouse button instead with the left one. However calling DragDrop.DoDragDrop() from MouseRightButtonDown instead of MouseLeftButtonDown doesn't do the job - DragDrop.DoDragDrop looks for mouse movements while holding down the left mouse button. Any idea how to realise Drag & Drop using the right mouse button? Thanks for any hint!

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  • JqueryUI dialog box causes button to lose styling

    - by superexsl
    Hey everyone, I'm using JQueryUI dialog boxes and, while it works, it seems to remove any CSS styling on the button that opens the dialog. I have to manually refresh the page to get the styling back. An example button which launches the dialog: (button_submit is my CSS theme and launc_popup is used to detect the button click in JQuery. <asp:Button ID="btnLaunch" CssClass="button_sub launch_popup" runat="server" Text="Dialog..." CausesValidation="false" OnClientClick="return false;" /> My jquery: $('.launch_popup').click(function() { $("#dialog-form").dialog("open"); }); My dialog-form: $("#dialog-form").dialog({ autoOpen: false, height: 300, width: 300, modal: true, buttons: { 'Close': function() { $(this).dialog('close'); } } }); This happens to all the buttons that open dialogs. Is there a way to 'restyle' the button without refreshing the page? (It's in an updatepanel if that makes a difference, although this bit's client-side so not sure if that should affect it). Thanks for any help

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  • Facebook like button not going back side on the fixed div

    - by Lahiru Chathuranga
    I added a Facebook like button to my website.My website has a fixed div on top of the page(blue color div in the image). The like button is below that(in a div which can scroll) My problem is when the page is scroll down the like button comes on top of the fixed div(blue color).I want to scroll it from the backside of the div.How can I do that? There are couple of screenshots I added Before Scroll After Scroll Here is my code of the fixed div <script type="text/javascript"> function got_to_signup(){ window.location.href = "view/policy"; } </script> <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_GB/all.js#xfbml=1&appId=368003049941951"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> <div style="width:100%;background-color:#0094d6;" > <div id="dd" style="background-color:#0094d6; width:100%; height:75px;position:fixed; " class="center "><div id="a" style="width:1010px; height:75px; background-color:#000000;background:url(xx.png); background-repeat:no-repeat; font-family:Arial, Helvetica, sans-serif; font-size:11px; color:#003; " class="inner div_border"> <table width="1010" border="0" > <tr > <td width="15%" rowspan="2"><a href="" style="cursor:pointer; cursor:hand;"><div style="width:200px; height:50px;background-color:none;"></div></a></td> <td width="22%" height="14">&nbsp;</td> <td width="5%">&nbsp;</td> <td width="5%">&nbsp;</td> <td width="28%">&nbsp;</td> <td width="2%">&nbsp;</td> <td width="23%">&nbsp;</td> </tr> <tr> <td colspan="4"> </td> <td colspan="2"><span style="float: right; " ><div style="background-color:#006d9e;border-radius:3px; width:250px; height:34px; display: table; vertical-align: middle; color:#FFF; "> <table width="100%" border="0" > <tr > <td width="43%" style="text-align:center"> Start to bump !</td> <td width="29%"><div id='basic-modal'><span style="float: right; " ><input name="login_btn" type="button" class="login_button basic" id="login_btn" value="Sign in" /></span></div></td> <td width="28%"><span style="float: right; " ><form id="form_reg" method="post"><input name="register_btn" type="button" class="register_button" id="register_btn" value="Sign up" onclick="got_to_signup()"/></form></span></td> </tr> </table> </div></span></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td style="color:#FFF; font:Arial, Helvetica, sans-serif; font-size:9px; text-align:right;"> Beta Version </td> </tr> </table> </div></div></div> here is my facebook like button code </script> <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_GB/all.js#xfbml=1&appId=368003049941951"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> <td height="21" colspan="2"> <table width="187" style="margin-left:3px;font-size:1px;background-image:url(share_back.png);background-repeat:no-repeat;border-radius:3px;" > <!--tweeter button--> <tr><td width="71"><a href="https://twitter.com/bump_lk" class="twitter-follow-button" data-show-count="false" style="float:right;">Follow @bump_lk</a> <script>!function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs");</script></td> <!--facebook like button--> <td width="48"><div class="fb-like" data-href="https://www.facebook.com/Bump.lk" data-send="false" data-layout="button_count" data-width="10" data-show-faces="false" style="position:relative;"></div> </td></tr></table></td> <td>&nbsp;</td> <td>&nbsp;</td> <td >

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  • open iphone google maps with back button

    - by christian
    Hi, i have a webview in my iphone app where a google map location is opened like; Directions now the google map native app opens fine, but how could i add a RETURN button so it would jump back to my html page. Now i have to click my home button and the app close back to the desktop, so i have to start my webview again. in android its more easy, because there is always a back button and after viewing my gmap i simply back in my webview. thx chris

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  • Browser back button broken between hidden div's

    - by Linda
    First of all, these pages will never be on the web but will be in internal memory. They are a group of linked documents---an ebook. http://www.anmldr.com/testdivs When I click on the link in the first div, the second div becomes visible and the first div is hidden. The problem is with the browser's back button. If you then click on the back button, the URL updates but the first div does not show again. How can I correct the back button so that the first div shows? The link from the second div to the first div works fine but it is the browser back button that I do not know how to work with. Thanks, Linda P.S. These are using CSS3 so it is better to use a WebKit based browser.

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  • Javascript button

    - by Deven
    hello friends i am developing button which generate another button and this button also calls function in which its id is passed as argument but i am getting error that id is undifined even i set its id attribute before it is added to ma web page

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  • How to disable html button using JavaScript?

    - by Jack Roscoe
    Hi, I've read that you can disable (make physically unclickable) a html button simply but appending 'disable' to its tag, but not as an attribute, as follows: <input type="button" name=myButton value="disable" disabled> Since this setting is not an attribute, how can I add this in dynamically via JavaScript to disable a button that was previously enabled?

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  • Simple Binding question, unable to bind to button command in a DataTemplate using MVVM Light Toolkit

    - by deliberative assembly
    I've been attempting to bind to buttons within a DataTemplate without much success. The button does not fire. Button Click works successfully outside of the DataTemplate. Yet if I create a Click="button_click" the click button is fired. The Button Content binds perfectly as well. Example to illustrate.. Why does the command not fire? Advice on how this should be handled this? The example is a simplified version of my real problem, I am currently not using a Listbox. I only recreated the same problem with a listbox..

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  • Set focus to a button in a new TabItem

    - by Jan
    I use a TabControl to display a list of items. The ItemView is a separate control I wrote. <TabControl SelectedItem="{Binding CurrentItem}" IsSynchronizedWithCurrentItem="True" ItemsSource="{Binding ItemList}"> <TabControl.ContentTemplate> <DataTemplate> <ctrls:ItemView/> </DataTemplate> </TabControl.ContentTemplate> <TabControl.ItemTemplate> <DataTemplate> <TextBlock Text="{Binding ShortItemDescription}"/> </DataTemplate> </TabControl.ItemTemplate> </TabControl> If the user presses a Button a new ViewModel is added to the list of ViewModels and the TabControl displays it as a new tab. After adding the new tab is selected. <Button Command="{Binding AddItemCommand}" Content="Add item"/> Inside of the new ViewModel is a button that needs to be focused each time a new tab is added. I have tried to use the FocusManager and the Initialized event in the ItemView but these are only called for the first time I add a new tab. <UserControl x:Class="ItemView" ... Initialized="ViewInitialized"> <Grid> ... <!-- Set focus to this button --> <Button Content="Search" Command="{Binding SearchCommand}" Name="SearchButton" Grid.Column="0" Grid.Row="0"/> </Grid> </UserControl> Any ideas?

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  • LinearLayout as custom button, OnClickListener never called

    - by ohra
    I've been using the common Android Button with both icon (drawableTop) and text. It works really poorly if you want to have a non-standard size button, so I decided to make a custom button with a LinearLayout having the following layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" style="@style/ButtonHoloDark" android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="center" android:clickable="true" android:focusable="true" android:orientation="vertical" > <ImageView android:id="@+id/buttonIcon" android:layout_width="fill_parent" android:layout_height="wrap_content" android:duplicateParentState="true" /> <TextView android:id="@+id/buttonText" android:layout_width="fill_parent" android:layout_height="wrap_content" android:duplicateParentState="true" android:gravity="center" android:textColor="@color/white" /> </LinearLayout> The layout is used by a custom class: public class CustomIconButton extends LinearLayout { public CustomIconButton(Context context, AttributeSet attrs) { super(context, attrs); setAttributes(context, attrs); LayoutInflater.from(context).inflate(R.layout.custom_icon_button, this, true); } ... But when I set an OnClickListener on my button in its parent layout it never gets called. I can only receive clicks if a set the listener to the ImageView and/or TextView. This leads to two possible effects when the button is clicked: The click is inside the ImageView or the TextView. The click is registered ok, but the buttons state drawable doesn't change i.e. it doesn't appear depressed. The click is inside the "empty area" of the button. The click is not registered, but the state drawable works ok. Neither of these is feasible. I've played around with the following attributes on the LinearLayout or its children, but none really seem to have any effect whether true or false: duplicateParentState clickable focusable There doesn't seem to be any reasonable way to get the LinearLayout parent receive clicks instead of its children. I've seen some possible solutions overriding dispatchTouchEvent or onInterceptTouchEvent on the custom component itself, but that really seems like a big mess if I have to start analyzing touch events to identify proper clicks. So OnClickListener on a LinearLayout with children = no go?

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  • immediate=true is set on a jsf command button but still seeing validation

    - by Zack Macomber
    I have the following command button set up in a facelet: <h:commandButton action="#{addressAction.deletePreviousAddress}" value="#{bundle['button.deleteAddress']}" styleClass="deg-form-button" immediate="true"> <f:setPropertyActionListener target="#{addressAction.addressActionForm.previousAddress}" value="#{address}"> </f:setPropertyActionListener> </h:commandButton> In AddressAction, the following code gets run to delete a previous address on the form: public Enum<NavigationConstants> deletePreviousAddress() { addressActionForm.getPreviousAddresses().remove(addressActionForm.getPreviousAddress()); return NavigationConstants.addresses; } Before I made the address input components "required=true", this code worked fine and removed the previous address from the jsf form successfully. Right now, I can't successfully delete a previous address because validation is occurring and stating that the input components need to be filled in on the previous address record on the form. How can I bypass this validation? I thought the "immediate=true" attribute on the command button would have accomplished it but that's not cutting it in my case...

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