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• how to know who is accessing my system?

  - by calvin

  Is it possible to know if anyone is accessing any of folders or drives in my system(32 bit windows 2003)? I mean shared folders or non-shared folders, anything. And once if we know, how to deny access to particular host. For shared folders i know how to do, but if anyone is accessing some folder with proper credentials, i don't know how to control. Please ignore cases like bit torrent etc. All i wanted to know is if anyone is accessing my system folders in this way \\10.30.188.231\d$\calvin_docs with some valid username and password. I wanted to know ip/username of system who is accessing

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• Accessing mySQL from two ports: Problems with iptables

  - by marekventur

  Hi! I'm trying to make my mySQL-server (running on Ubuntu) listen on port 3306 and 110, because I would like to access it from a network with very few open ports. So far I've found this answer telling me to do iptables -t nat -A PREROUTING -i eth0 -p tcp --dport 110 -j REDIRECT --to-port 3306 but all I got is: # mysql -h mydomain.com -P 3306 -u username --password=xyz Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 68863 Server version: 5.0.75-0ubuntu10.5 (Ubuntu) Type 'help;' or '\h' for help. Type '\c' to clear the buffer. mysql> exit Bye # mysql -h mydomain.com -P 110 -u username --password=xyz ERROR 2003 (HY000): Can't connect to MySQL server on 'mydomain.com' (111) I'm not an expert with iptables, so I not sure where to look for the problem. I'm googling around for quite some time, but haven't found anything to help me yet. This is what iptable tells me: # iptables -t nat -L -n -v Chain PREROUTING (policy ACCEPT 32M packets, 1674M bytes) pkts bytes target prot opt in out source destination 0 0 REDIRECT tcp -- eth0 * 0.0.0.0/0 0.0.0.0/0 tcp dpt:110 redir ports 3306 Chain POSTROUTING (policy ACCEPT 855K packets, 55M bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy ACCEPT 837K packets, 54M bytes) pkts bytes target prot opt in out source destination # iptables -L -n -v Chain INPUT (policy DROP 7 packets, 340 bytes) pkts bytes target prot opt in out source destination 107K 5390K LOG all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `INPUT INVALID ' 131K 6614K DROP all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x3F/0x00 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x03/0x03 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x06/0x06 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x05/0x05 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x11/0x01 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x18/0x08 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x30/0x20 6948K 12G ACCEPT all -- lo * 0.0.0.0/0 0.0.0.0/0 151M 34G ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0 state RELATED,ESTABLISHED 32M 1666M ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:80 1833 106K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:443 603 29392 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:25 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:465 24 1180 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:110 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:995 7919 400K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:143 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:993 0 0 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:119 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:53 7 517 ACCEPT udp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:53 1110 65364 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:21 139K 8313K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:22 10176 499K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:3306 2 80 ACCEPT udp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:123 0 0 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:6060 4 176 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:6667 20987 1179K MY_REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 Chain FORWARD (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination 2159 284K LOG all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `OUTPUT INVALID ' 2630 304K DROP all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID 6948K 12G ACCEPT all -- * lo 0.0.0.0/0 0.0.0.0/0 181M 34G ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0 state NEW,RELATED,ESTABLISHED 0 0 MY_REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 Chain MY_DROP (7 references) pkts bytes target prot opt in out source destination 0 0 LOG all -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `PORTSCAN DROP ' 0 0 DROP all -- * * 0.0.0.0/0 0.0.0.0/0 Chain MY_REJECT (2 references) pkts bytes target prot opt in out source destination 13806 652K LOG tcp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT TCP ' 18171 830K REJECT tcp -- * * 0.0.0.0/0 0.0.0.0/0 reject-with tcp-reset 912 242K LOG udp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT UDP ' 912 242K REJECT udp -- * * 0.0.0.0/0 0.0.0.0/0 reject-with icmp-port-unreachable 1904 107K LOG icmp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `DROP ICMP ' 1904 107K DROP icmp -- * * 0.0.0.0/0 0.0.0.0/0 0 0 LOG all -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT OTHER ' 0 0 REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 reject-with icmp-proto-unreachable Is there anyone who can give ma a hint where to look for the problem? Thank you!

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• Timeout ssh sessions after inactivity?

  - by Insyte

  PCI requirement 8.5.15 states: "If a session has been idle for more than 15 minutes, require the user to re-enter the password to re-activate the terminal." The first, and most obvious, way to deal with ssh sessions that are idling at the bash prompt is by enforcing a read-only, global $TMOUT of 900. Unfortunately, that only covers sessions sitting at the bash prompt. The spirit of the PCI spec would also require killing sessions running top/vim/etc. I've considered writing a */1 cron job that parses the output of "/usr/bin/w" and kills the associated shell, but that seems like a blunt instrument. Any ideas for something that would actually do what the spec requires and just lock the terminal? I've looked at away and vlock; they both seem great for voluntarily locking your terminal, but I need a cron/daemon task that will enforce locking.

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• How can I configure Windows Server 2008/IIS 7 to send email via an asp.net web application?

  - by Steve French

  I recently moved a long-functioning web app from a Windows 2003 server to a windows 2008 server. Everything works fine, save for the email service (send password and the like). The code works on my local machine and the original web server. The system throws no errors, but the message stays endlessly in the Queue. I have granted full access to all relevant users (Network Service, IISUsers, etc). Is there something I'm missing, or does IIS7 just not send email via web applications?

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• Mail being sent as root on Ubuntu 14.04

  - by Benjamin Allison

  I'm really struggling with this. I'm trying to set up this server to send mail using Gmail's SMTP. Google keeps bouncing the messages, saying that that Authentication is required: smtp.gmail.com[74.125.196.109]:25: 530-5.5.1 Authentication Required. Learn more at smtp.gmail.com[74.125.196.109]:25: 530 5.5.1 http://support.google.com/mail/bin/answer.py?answer=14257 But it seems my server is trying to send mail as [email protected]. I'm baffled. Here's what I've done so far: Updated mail.cf relayhost = [smtp.gmail.com]:587 smtp_sasl_auth_enable = yes smtp_sasl_password_maps = hash:/etc/postfix/sasl_passwd smtp_sasl_security_options = noanonymous smtp_tls_CAfile = /etc/postfix/cacert.pem smtp_use_tls = yes Created /etc/postfix/sasl_passwd: [smtp.gmail.com]:587 [email protected]:password Then did the following: sudo chmod 400 /etc/postfix/sasl_passwd sudo postmap /etc/postfix/sasl_passwd cat /etc/ssl/certs/Thawte_Premium_Server_CA.pem | sudo tee -a /etc/postfix/cacert.pem service postfix restart I can't for the life me get a mail message to send, or change the default mail user from [email protected] to [email protected] (FWIW, I'm using Google Apps, that's why it's not a .gmail address).

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• Randomize table guests in Excel

  - by Jo Voud

  I have a list of people: Column A: person A, person A guest, person B, person C, person C guest, ... Column B: 1, 1, 2, 3, 3, ... So in column A there is the person's name, column B gives a person a unique ID (the same id for their guest so we know that they are together). Now pretend we have a list of 100 people (also note that not all persons have guests) and we have to seat them. We have a list of tables (for example 10 * 4 person table and 10*6 person tables). We have to randomize that each person is assigned to a table and the guest is seated on the same table. What is the best way to do this? (it is also needed that I can generate this 4 times in a row without the same results, so when during the 4 courses of the diner the person are switching tables but not losing their guest).

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• Save Usercredentials permanently without prompt when opening Document from Webdavserver

  - by cpt.oneeye

  i am opening a word document from a url like https://myurl.com/mydoc.doc. The Webdavserver uses Basic Authentication. At the beginning the Office 2003 is asking for the Username and Password. After i have typed them in I click the checkbox "Save Usercredentials" and the word is opened. When i open the document the next time the login prompt is appearing again (username and passwort are already set in the textfields and I only have to click "Ok"). Is it possible to avoid this one click and make office not show this prompt at all after the first login? Greetings Klaus

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• How do you launch an SSH connection with port forwarding without interrupting your screen access?

  - by vfclists

  I want to make an SSH connection to another server with forwarding, but without having to log on to the remote server, nor interfere with the screen I am working on. I also need to access the connection to terminate it when I finish with it. eg. say I want to do a mysql backup on a remote server so I use the command ssh user@remote -L 1234:localhost:3306 but after issuing the password I want to run the mysql command in the session, but be able to access the SSH connection when I finish with mysql and terminate it. Is there some way this can be done?

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• How to use ssh-agent (and graphic passphrase dialog) in Kubuntu 10.10?

  - by halo

  I have recently switched from Ubuntu to kubuntu, both version 10.10. Unfortunately in KDE the ssh passphrase dialog doesn't work out of the box. Everytime my ssh private key is used I need to enter my password. This is neither secure nor comfortable. I have done comprehensive research on the net but only found out dated documentation. Several things I tried didn't work out. Current status: SSH setup working with direct passphrase input ssh-agent running in X session $SSH_AUTH_SOCK set to ssh-agent's socket in X session How to enable ssh-agent for keeping the passphrase in memory for ~15mins and as a bonus always use a graphical dialog for its input? I use asymmetric SSH key pairs for pushing/pulling in Git VCS logging remotely into different server systems

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• How to keep program always in memory (no swapping)

  - by Yossarian

  I'm using KeePass (on Windows 7) for storing passwords. The application is running on my laptop almost 100% of the time, but I'm using it rarely. The problem is, that activating the window after long time takes huge amount of time, I'd say that OS realized the application is no longer used and swapped it. I don't want OS to swap my KeePass (because of the loading lag, and also because of security - I don't like the idea of password keeping program's memory to be stored anywhere on HDD). Is there any possibility how to tell OS not to swap some program? Or, is this achievable by some programming?

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• How to back up OWA exchange emails without Outlook

  - by fpghost

  My university uses Microsoft Outlook Web Access (OWA) e-mail. Soon they will close my e-mail account as my course has ended, but I really do not want to lose the archive of emails and attachments. I've read a backup to something called a .pst can be made if one has access to Microsoft Outlook but I do not. Is there any other way I could back these up? (preferably on Ubuntu 12.04 but I also have access to Win 7 if need be). One idea I played with is using davmail to allow access via Thunderbird and performing some kind of backup with that. However, I cannot seem to get past Authentication failed: invalid user or password, retry with domain\user.

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• Adding a web folder via command line (Windows)

  - by Ryan

  I am trying to add a web folder via command line in windows. At first I though I should use the "net use" command, but when I tried I kept getting System error 67: C:net use * http://dev.subdomain.domain.tdl/dav/ the user name for 'dev.subdomain.domain.tdl': correctusername the password for dev.subdomain.domain.tdl: System error 67 has occurred. The network name cannot be found. The url I used works in a browser. It's an Apache dav on basic auth LDAP authentication method being used. Here's the thing... I CAN create a web folder when I use the "Add a network place" wizard. When I do net use, I don't see it listed in the prompt that follows. What utility do I need to use to mount a web folder in command line?

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• Proxy server on windows with SSL encrypted exchange with client

  - by Syffys

  I want to set up a classic proxy server (HTTPS, HTTPS, SSH, FTP, etc...) on a windows platform, but I need the following features: password authentication for clients data exchanged between clients and server to be SSL encrypted I've been trying to set this up various application to get this result, but without success so far: Squid for windows ccproxy wingate Alternatively, an other solution would be an HTTP SSL tunnel encapsulating an unencrypted proxy connection between clients and the server. I've spent a lot of time without any result so far, so I'm wondering if anyone faced this kind of issue. Thanks in advance!

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• Where are the SQLServer jobs stored?

  - by Saiyine

  I'd like to know what is the process a SqlServer job is executing, but I only can find that it calls DTSRun with an encrypted string. After decoding the string, it results is just the name of the job with the user and the password. How can I find what is this job really calling? Edit: I've found a candidate, they could be at the msdb.sysdtspackages, but again, can't read them as SQLServer says the data is binary. How can I read them to confirm they are the jobs?

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• Simple secured SFTP tunnel?

  - by babonk

  I'd like to setup an sftp tunnel so that I can connect to an IP-secured SFTP server through a gateway computer from anywhere, and download the files to anywhere. I was thinking of using a combination with netcat, having it listen to either WinSCP or PuTTY sFTP (doesn't matter which). Not sure how I would download the files to the connecting computer though. I would like the tunnel to be secured, preferably, with a username/password. I'm open to using alternative software but I'm looking for unintrusive, simple command line stuff because I don't want to install a lot on this computer. Thanks

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• Changing languages rapidly causes Linux to crash.

  - by eZanmoto

  So I'm running Xmonad on my college computer (which runs Kubuntu) and whenever I leave my desk, instead of using x-screensaver which is incredibly buggy and slow, I just change to another workstation, open a terminal and change language to a language which uses symbols instead of letters, and then change back using an aliased command. For example, my .profile has the lines alias qwer="setxkbmap jp" alias *******="setxkbmap ie" where ******* is my password, using japanese characters. Changing languages seems to be much faster than running x-screensaver. The problem: rapidly changing languages seems to crash Linux; it just won't accept input (and it's not because the language hasn't changed back, nothing is output to the console). I can't use Ctrl+Alt+F1..F7, I can't "raise the elephants", anything, it just won't work. I'm just wondering, is this a known issue, and if so, is there something I can do about it?

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• Homegroup sharing problems

  - by soandos

  I can see other people in my homegroup and their folders, but when I click on those folders, I cannot see the contents (no error message, just nothing happens). The other people in the Homegroup can see me just fine, and my files In addition, I cannot see the files that they have under the network tab, though they can all see each others stuff. What could be the issue? The homegroup has already be created and recreated numerous times. Perhaps unrelated, but I am unable to turn off password protected sharing.

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• DSA private key format

  - by ansur

  So I used puttygen to generate a DSA private key and then exported that to the OpenSSH format and here's what I got when I ran OpenSSL's asn1parse on it: 0:d=0 hl=4 l= 443 cons: SEQUENCE 4:d=1 hl=2 l= 1 prim: INTEGER :00 7:d=1 hl=3 l= 129 prim: INTEGER :B9916796B7A3EFFD5CA36368186D0ED 193BE7FDD61CC6851174F3E9781A0C0CEA7473E528372F559A1DB2A7E049A9BEFAE2CAAC55527049 2A0CD55B59A48A53BCADD32181F519EA9E6A98EF8EF59DE314A2E69606C728F2F8DEE722B4C67BA6 8EB8A619B6006804F83740F9C74C38136522E7E83F22920AA39822FBDA0DF4D0B 139:d=1 hl=2 l= 21 prim: INTEGER :D832F5B01F075FEC0F162B91982F34D B26A0CC29 162:d=1 hl=3 l= 129 prim: INTEGER :9B73F47AEFF8E39584FD10ACF81CCD5 75C96FC5558A5C94B941EF76318D132007ACAE1EA22E95CE0B13FC7875CE4D4ED33BA639CD8C2AC9 C0A0530FB7786F584A62EBAE5985E1C26ED0D0B9FDD5E8DB0142BE182A4E5359307007060C327FEE C2F8D04EABB37D7B74076EB9BDB4885F627DE85708D5BDBF5177A05721E09A367 294:d=1 hl=3 l= 128 prim: INTEGER :6BD9267D2D1E4546EE05F6CD087F311 93C0EEB13B1E139F5072E900AB2EEF68EEC28BF4D7D6CAE4DEE59005F00BAE07343EE520C217FF6E 7880DC788E4555F78CCB5E89A10CDC71A663DA696C5BC34E296CEB3518D65A79BF00B6D592B1399A 9F0D79AE3F3FB445EE1F2B4B72515F036C8E1D5C7FAD336FD3503874645C5C264 425:d=1 hl=2 l= 20 prim: INTEGER :15295A12325E5F1A6F7243B7BB3BE74 6FE7B76E9 My question is... where is this format described? What does the first 0 integer value mean for example? I guess I could look in the puttygen source code but is there an RFC describing this format or something?

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• Automatically Connecting to Hidden SSID WiFi Network

  - by Zack

  My MacBook Pro will not automatically connect to a Wireless network with a hidden SSID. It makes me select the "Join Other Network..." in the Airport menu (in the system tray), where I need to input the name of the network, then security type, password and wait for it to connect. This is becoming increasingly annoying to have to do every time I come back to my desk. I'm running Mac OS X 10.5 and there doesn't seem to be an option to connect to a specific network, but rather "Preferred Networks." The only network I have set as Preferred that's in range is my home network, and it still doesn't automatically connect. Making the network publicly visible isn't under my control, so I'm stuck with what's currently in place. Reader's Digest version: How do I make my MacBook Pro automatically connect to a WiFi Network with a hidden SSID without having to "configure" it every time I want to connect?

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• How to logon to a non-domain computer from one in a domain

  - by Svish

  I've met a rather annoying problem that should be very simple, but I can't seem to figure it out. I have a work laptop that is part of a domain, so my username is foobar\bob. I also have my home computer with no domain, just the username bob. I'm trying to connect to a share on my home computer from my work computer. It's asking me for my username and password, which is bob, but when I type in bob it assumes I mean foobar\bob, which of course doesn't work. I've tried to use hostname\bob, but that doesn't seem to work either... What can I do here? Both computers are running Windows 7.

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• How to use ssh-agent (and graphic passphrase dialog) in Kubuntu 10.10?

  - by halo

  I have recently switched from Ubuntu to kubuntu, both version 10.10. Unfortunately in KDE the ssh passphrase dialog doesn't work out of the box. Everytime my ssh private key is used I need to enter my password. This is neither secure nor comfortable. I have done comprehensive research on the net but only found out dated documentation. Several things I tried didn't work out. Current status: SSH setup working with direct passphrase input ssh-agent running in X session $SSH_AUTH_SOCK set to ssh-agent's socket in X session How to enable ssh-agent for keeping the passphrase in memory for ~15mins and as a bonus always use a graphical dialog for its input? I use asymmetric SSH key pairs for pushing/pulling in Git VCS logging remotely into different server systems

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• How do I get rid of the Cisco CP one-time user message on a Cisco 2901 router?

  - by user65712

  I get this message on a new 2901 Cisco router: Cisco Configuration Professional (Cisco CP) is installed on this device and it provides the default username "cisco" for one-time use. If you have already used the username "cisco" to login to the router and your IOS image supports the "one-time" user option, then this username has already expired. You will not be able to login to the router with this username after you exit this session. It is strongly suggested that you create a new username with a privilege level of 15 using the following command. username <myuser> privilege 15 secret 0 <mypassword> Replace and with the username and password you want to use. It appears every time I login and everytime I show run. I already set up my username. How do I turn it off?

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• Java login through LDAP

  - by Salda

  I am starting to write an application for our office and the first step is authentication through LDAP where all users already exist. Everything I need is a code in Java to check if the pair <nick,password> is right. Google found me many links, but I think that I will find here the most sofisticate, short and up to date solution (I don't want to read all articles like 2 whole days to do something so simple). I have written many dkBs of code in C++, but in Java I am total noob and I haven't coded anything with LDAP yet so try to be simple if speaking in Java and LDAP terms if possible.

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• Start TLS and 389 Directory

  - by Kyle Flavin

  I'm trying to configure Start TLS on 389 Directory server, but I'm having all sorts of issues. I've been following this doc: https://access.redhat.com/knowledge/docs/en-US/Red_Hat_Directory_Server/9.0/html/Administration_Guide/managing-certs.html which specifies that I should create a certificate for both the directory server and admin server. I've imported the CA cert on both servers. I've tried to use the same server certificate for both. It will not allow me to do so. However, the admin and directory servers reside on the same host. If I generate a new certificate it will need to use the same hostname. I'm not sure if that's valid... Has anyone out there set this up before? Any direction would be helpful. I have multmaster replication set up. From an external client, I'm attempting to do an ldapsearch -ZZ -x -h "myhost" -b "dc=example,dc=com" -D "cn=Directory Manager" -W "", and I'm getting a protocol error.

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• why need select privileges on *.* to use view?

  - by profy

  I have a problem using view with MySQL server 5.0 (5.0.92) I cannot use view with a user granted like that : GRANT USAGE ON *.* TO 'testuser'@'' IDENTIFIED BY PASSWORD '**********'; GRANT ALL PRIVILEGES ON `testuser`.* TO 'testuser'@''; I can create view, but when I try to select in, I have this messages : ERROR 1356 (HY000): View 'testuser.v' references invalid table(s) or column(s) or function(s) or definer/invoker of view lack rights to use them I need to "GRANT SELECT ON . TO 'testuser'@''" to make select working on the view. Why ? Do you know a solution to use VIEW's without the select privileges on . ? Thanks a lots for your answers.

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