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• How to authenticate users against a Windows AD?

  - by Potinos

  I've a JSF-Hibernate web application. I need to authenticate users against a Windows AD and the web application should only allow logins from members of group X, otherwise it should redirect to an error page. How can I configure this? Also, I would like to display the name of the logged-in user on all pages, not the name of the Windows user of the server machine. I have tried the System.property("user.name") for this, but this only returns the name of the Windows user of the server name.

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• Broken count(*) after adding LEFT JOIN

  - by Iain Urquhart

  Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

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• If a Matlab function returns a variable number of values, how can I get all of them as a cellarray,

  - by kaleidomedallion

  I am writing a function to remove some values from a cellarray, like so: function left = remove(cells, item); left = cells{cellfun(@(i) ~isequal(item, i), cells)}; But when I run this, left has only the first value, as the call to cells{} with a logical array returns all of the matching cells as separate values. How do I group these separate return values into a single cellarray? Also, perhaps there is already a way to remove a given item from a cellarray? I could not find it in the documentation.

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• Serialized task distribution: use thread or epoll?

  - by hpsmouse

  Now I'm in such a situation that there is a group of predefined tasks for multiple clients to do(any client can take any task). When a client connects to the server, server choose a task from the uncompleted tasks and send it to the client. It takes a while for the client to finish the task and send the result back to the server. Since a task should be sent to only one client, server should process requests in a serialized way. Now I have two plans to do it: create a thread for each client connection and all the threads take turns accessing the task pool, or use epoll listening on all the connection and process for each event of clients. Which one is better for the job? Or is there any other ideas? The server will be run on a multi-core machine.

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• Google App Engine datastore-primary key

  - by megala

  Hi, I've created a table in the Google App Engine Datastore. It contains the following FIELDS(GROUPNAME,GROUPID,GROUPDESC). How do I set GROUPID as the primary key? My code is as follows: @Entity @Table(name="group" , schema="PUBLIC") public class Creategroup { @Basic private String groupname; @Basic private String groupid; @Basic private String groupdesc; public void setGroupname(String groupname) { this.groupname = groupname; } public String getGroupname() { return groupname; } public void setGroupid(String groupid) { this.groupid = groupid; } public String getGroupid() { return groupid; } public void setGroupdesc(String groupdesc) { this.groupdesc = groupdesc; } public String getGroupdesc() { return groupdesc; } public Creategroup(String groupname, String groupid, String groupdesc ) { // TODO Auto-generated constructor stub this.groupname = groupname; this.groupid = groupid; this.groupdesc = groupdesc; } }

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• MySQL how to display data from two tables.

  - by gew

  I'm trying to display the username of the person who has submitted the most articles but I don't know how to do it using MySQL & PHP, can someone help me? Here is the MySQL code. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, username VARCHAR(255) DEFAULT NULL, pass CHAR(40) NOT NULL, PRIMARY KEY (user_id) ); CREATE TABLE users_articles ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, user_id INT UNSIGNED mNOT NULL, title TEXT NOT NULL, acontent LONGTEXT NOT NULL, PRIMARY KEY (id) ); Here is the code I have so far. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT COUNT(*) as coun, user_id FROM users_articles GROUP BY user_id ORDER BY coun DESC LIMIT 1");

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• Create a link to delete membership in web2py

  - by user1741325

  I'm trying to do something really simple but it's taking me ages to figure out how to do it properly. I want to have a button that simply deletes a member from a group. So in my view I have <div id="del-role">{{=A('Delete Role',_class="btn btn-danger", callback=URL('test'),delete='#del-role')}}</div> However, when I click the button, the only thing I get is a Javascript prompt asking whether I'm sure I want to delete the specified object, yes/no. That's fine but, what I'd really like to do is just auth.del_membership('role') What needs to go in my controller? I do not want any page redirection, I just want to auth.del_membership(role) This seemingly simple thing is taking me forever to understand. Thanks!

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• Trying to create fields based on a case statement

  - by dido

  I'm having some trouble with the query below. I am trying to determine if the "category" field is A, B or C and then creating a field based on the category. That field would sum up payments field. But I'm running into error saying "incorrect syntax near keyword As". I am creating this in a SQL View. Using SQL Server 2008 SELECT r.id, r.category CASE WHEN r.category = 'A' then SUM(r.payment) As A_payments WHEN r.category = 'B' then SUM(r.payment) As B_payments WHEN r.category = 'C' then SUM(r.payment) As C_payments END FROM r_invoiceTable As r GROUP BY r.id, r.category I have data where all of the above cases should be executed because the data that I have has A,B and C Sample Data- r_invoiceTable Id --- Category ---- Payment 222 A ---- 50 444 A ---- 30 111 B ---- 90 777 C ---- 20 555 C ---- 40 Desired Output A_payments = 80, B_payments = 90, C_payments = 60

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• MySQL: Records inserted by hour, for the last 24 hours

  - by Andrew M

  I'm trying to list the number of records per hour inserted into a database for the last 24 hours. Each row displays the records inserted that hour, as well as how many hours ago it was. Here's my query now: SELECT COUNT(*), FLOOR( TIME_TO_SEC( TIMEDIFF( NOW(), time)) / 3600 ) FROM `records` WHERE time > DATE_SUB(NOW(), INTERVAL 24 HOUR) GROUP BY HOUR(time) ORDER BY time ASC right now it returns: 28 23 62 23 14 20 1 4 28 3 19 1 That shows two rows from 23 hours ago, when it should only show one per hour. I think it has something to do with using NOW() instead of getting the time at the start of the hour, which I'm unsure on how to get. There must be a simpler way of doing this.

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• Drupal: Views: grouping relationship in block list

  - by Ronn

  I have a question about views, specifically about grouping a relationship. I have a "partner" node that has many "docs", I want to list the name of the "partner" along with its corresponding "docs" below. I have the relationship set up correctly(I think) but can't figure out how or where to group it correctly. I get this: partner name 1 - doc name 1 partner name 1 - doc name 2 partner name 1 - doc name 3 partner name 2 - doc name 4 partner name 2 - doc name 5 partner name 3 - doc name 6 but would like this: partner name 1 - doc name 1 - doc name 2 - doc name 3 partner name 2 - doc name 4 - doc name 5 - doc name 6

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• MySQL COUNT() multiple columns

  - by liam

  Hello, I'm trying to fetch the most popular tags from all videos in my database (ignoring blank tags). I also need the 'flv' for each tag. I have this working as I want if each video has one tag: SELECT tag_1, flv, COUNT(tag_1) AS tagcount FROM videos WHERE NOT tag_1='' GROUP BY tag_1 ORDER BY tagcount DESC LIMIT 0, 10 However in my database, each video is allowed three tags - tag_1, tag_2 and tag_3. Is there a way to get the most popular tags reading from multiple columns? The record structure is: +-----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | flv | varchar(150) | YES | | NULL | | | tag_1 | varchar(75) | YES | | NULL | | | tag_2 | varchar(75) | YES | | NULL | | | tag_3 | varchar(75) | YES | | NULL | | +-----------------+--------------+------+-----+---------+----------------+

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• Select all items of union but not the last one!

  - by 100r

  I have few texboxes, dropdown lists, etc.. They have their css classes. I want to select all elements of specific class(es) but NOT the last element from group of all classes. <asp:TextBox ID="TextBox1" runat="server" CssClass="class1" ></asp:TextBox> <asp:TextBox ID="TextBox2" runat="server" CssClass="class2" ></asp:TextBox> <asp:TextBox ID="TextBox3" runat="server" CssClass="class2" ></asp:TextBox> I want to select only TextBox1 and TextBox2, not TextBox3! selector should be something like this $("(.class1,.class1):not(:last)") or something like $(".class1,.class1").filter(":not(:last)") but of course none of it is working :) any sugestions? tnx in advance!

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• Presentation to under privileged students about what programming is. How? Any ideas.

  - by Quigrim

  Next week I have to give a presentation to a group of under privileged college students about the possibilities of a career in software development. These students have no exposure to programming what-so-ever. I have a good idea of how to tackle the non-technical, general portion of the presentation. However, notwithstanding my decade of experience, I am finding myself at somewhat of a loss how to convey the concept of programming in a meaningful way in under 20 minutes. Do I demonstrate actual simple code, or do I stick with concepts? I need to be able to scratch the surface of the vastness of the programming realm, to create just enough of a handle to those students, to peak the interest of those who might have the aptitude for it. Any ideas that are concise and clear would be greatly appreciated. Also, if anybody knows of online resources that addresses this topic, please share. Looking forward to some great input from this community. Thank you.

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• Using LEFT JOIN to only selection one joined row

  - by Alex

  I'm trying to LEFT JOIN two tables, to get a list of all rows from TABLE_1 and ONE related row from TABLE_2. I have tried LEFT JOIN and GROUP BY c_id, however I wan't the related row from TABLE_2 to be sorted by isHeadOffice DESC. Here are some sample tables TABLE 1 c_id Name ---------------- 1 USA 2 Canada 3 England 4 France 5 Spain TABLE2 o_id c_id Office isHeadOffice ------------------------------------------------ 1 1 New York 1 2 1 Washington 0 3 1 Boston 0 4 2 Toronto 0 5 3 London 0 6 3 Manchester 1 7 4 Paris 1 8 4 Lyon 0 So what I am trying to get from this would be something like: RESULTS c_id Name Office ---------------------------- 1 USA New York 2 Canada Toronto 3 England Manchester 4 France Paris 5 Spain NULL I'm using PHP & MySQL. Any ideas?

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• How do I run multiple objects through an IF statement in rails?

  - by codyvbrown

  I am creating an application that highlights user messages from a stream based on whether or not the user has been 'vouched'. It works fine if it's setup for a single author. For example controller: @vouch = Vouch.last.vouched_user_nickname view: <% if tweet.from_user == @vouch %> <div class="flit_message_containerh">.... But I'm having trouble doing it for multiple user nicknames. @vouch = Vouch.find(:all, :select => "vouched_user_nickname", :group => 'vouched_user_nickname' ) Any ideas would be greatly appreciated. I'm a rails noob.

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• Insert something .after a set of elements if the first in the set has a certain class.

  - by Adripants

  I would like to add a label AFTER a group of radio inputs IF the first has a certain class <label>Has the strategy and all of it's relevant background documents been uploaded</label> <label for="Radio1"><input type="radio" name="uploaded" class="required cat1" id="Radio1">Yes</label> <label for="Radio2"><input type="radio" name="uploaded" id="Radio2">No</label> Radio1 has the class, but I'd like to insert a label after the last (in this case Radio2) I thought I could use this: $('input[type="radio"].cat1').siblings('input:last').after('<label>Hi!</label>'); But it doesn't work. Can you pick what I am doing wrong?

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• Bash file - if then-

  - by user2949827

  I want to wright a login script for my organization, The script needs to discover users by Group id's and then define the map drive they need on their computer. I started writing down the script and it looks like this: ID if [gid=10524657] then mkdir /home/likewise-open/Domain/Username/Desktop/Share sudo mount.cifs //fs01/salesnew /home/likewise-open/Domain/Username/Desktop/share -o user=X else [gid=41654564] (etc....) That is the first time i am writing a script in Ubuntu, Can you tell me what am i doing wrong ? Is it possible for Linux to identify the gid from the ID command ? if not what is the alternative option? Can someone please advise ?

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• Query to find all bars that sell three different beers at the same price

  - by Eternal Learner

  Query to find "All bars that sell three different beers at the same price?" My Tables are Sells(bar,beer,price) - bar - foreign Key.. Bars(name,addr) - name primary key. I thought of something like this but that dosent seem to work ... Select A.bar As bar , B.bar as bar From Sells AS A, Sells AS B Where A.bar = B.bar and A.beer <> B.beer Group By(A.beer) Having Count(Distinct A.beer) >= 2 Is this the correct SQL query ?

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• setting minDate in datepicker in Rails

  - by Sakshi Jain

  I need to apply minDate attribute to the datepicker in Rails App. In _admin_controls.html.erb <%= f.input :end_date, wrapper: :append do %> <div id="datepicker" class="datepicker input-group edit-left"> <%= f.text_field :end_date, :class => "datetime form-control" %> application.js contains jQuery(document).on('focus', 'input.datetime', function() { opts = {format: 'M dd, yyyy', autoclose: true}; jQuery(this).datepicker(opts); jQuery(".datepicker").css("z-index",10000); }); What should be the javascript to do so only for _admin_controls.html.erb?

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• Wrapping 3 objects or less inside a while / foreach in PHP

  - by DarkGhostHunter

  Simple question. I have an array of 21 elements, and show every three of them inside a <div> block. The code is something like this: <?php $faces= array( 1 => 'happy', 2 => 'sad', (sic) 21 => 'angry' ); $i = 1; foreach ($faces as $face) { echo $face; $i++; } ?> The problem lies when this array doesn't have 21 elements, sometimes it gets 24, an other times 17. How I wrap every three of them, and wrap alone the rest? I came up with using switch and case, but that works only when there are 21 elements only. I think I could count them beforehand and put a closing in the last one (even if it is a group of one element).

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• Get latest record from second table left joined to first table

  - by codef0rmer

  I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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• JavaScript greybox -- slidehow won't work in FF/Safari...

  - by kali

  hi, is anybody familiar with greyBox JavaScript plugin? orangoo.com/labs/GreyBox/ it's for slideshows and stuff.. I can't get it to work in FF/Safari; it works great in IE, but FF/Safari won't play ball.. orensanz.org/photos.html would very much appreciate some suggestions.. supposedly there's a google group (forum) for this thing (can't post url.. this thing limits how many urls u can include in a post, it's linked to from their home pg (url above.. oh brother..) but when you link to it you land on a pg that says they've been booted out b/c they violated google's terms of service....;-) thank you..

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• Exists a replacement for the command-line-tool CASPOL.exe?

  - by tantran

  When trying to execute a .NET-App, it throws a "PolicyException", because "only one group is allowed". The tool should list existing settings, and allow to delete selected settings. Using caspol to list is not helpful, it is cruel. I've seen there is a simple gui-frontend, which allows to define NEW settings, but it does not allow to list or delete existing settings. Caspol is a nightmare, no wonder anyone uses it by choice. With .NET 1.1 Microsoft delivered a configuration-utility, but for .NET 2.0 i've found nothing.

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• Vim plugin Align fails to work. Can it be installed without vimball?

  - by Leonard

  I've happily installed the vim Align plugin on my home computer, but on the Red Hat servers at work, the installation doesn't work. The servers at work have a very old copy (2006) of vimball, which from Googling I know doesn't support more recent vimballs, including Align. I can't get the systems group (IT department) to upgrade vimball, so I thought perhaps I could simply copy the various files into ~/.vim/plugin by hand. I copied the 3 files from my home system AlignMapsPlugin.vim AlignPlugin.vim cecutil.vim, but when I attempt to use Align from within vim I get the following error message E117: Unknown function: Align#Align I know that it's seeing the plugin, because when I remove the plugin the error message is different (it says "Not an editor command Align"). Is there a workaround for this? I love "Align" and would sure like to use it at work as well as at home.

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• how rspec creates database between specs

  - by timpone

  This is a bit of a naive / simple question. I'm having a hard time finding this info online. Basically, does rspec run rake db:test:prepare between every rspec group? Or is it between every example or model? Or does the schema get loaded once and then truncated between each. I need to add a rake task directly after this call to create a view since they are not supported in schema.rb. Either a link or explanation would be greatly appreciated so that I know where to insert my rake task to create a view. Or whether there is a callback like rake db:test:after_prepare thx

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