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  • Connection for control user as defined in your configuration failed. xampp

    - by Zann
    when i tried to uninstall xampp and reinstall xampp.I received below error message when i go phpmyadmin Need help and guide to solve it .thanks Error MySQL said: Documentation 1045 - Access denied for user 'root'@'localhost' (using password: NO) Connection for controluser as defined in your configuration failed. phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server.

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  • Dynamically generate client-side HTML form control using JavaScript and server-side Python code in Google App Engine

    - by gisc
    I have the following client-side front-end HTML using Jinja2 template engine: {% for record in result %} <textarea name="remark">{{ record.remark }}</textarea> <input type="submit" name="approve" value="Approve" /> {% endfor %} Thus the HTML may show more than 1 set of textarea and submit button. The back-end Python code retrieves a variable number of records from a gql query using the model, and pass this to the Jinja2 template in result. When a submit button is clicked, it triggers the post method to update the record: def post(self): if self.request.get('approve'): updated_remark = self.request.get('remark') record.remark = db.Text(updated_remark) record.put() However, in some instances, the record updated is NOT the one that correspond to the submit button clicked (eg if a user clicks on record 1 submit, record 2 remark gets updated, but not record 1). I gather that this is due to the duplicate attribute name remark. I can possibly use JavaScript/jQuery to generate different attribute names. The question is, how do I code the back-end Python to get the (variable number of) names generated by the JavaScript? Thanks.

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  • If I CFRelease() an image in core data, how do I get it back?

    - by Sam
    My iphone app plays a slide show made up of 5 user images.  These images are stored using core data.  I was noticing that memory was building up every time a different slide show was played and it was not releasing any of the previously played slide shows.   These images are showing up in Object Allocations as CFData. So I tried releasing this data in the dealloc method CFRelease(slideshow.image1); CFRelease(slideshow.image2); CFRelease(slideshow.image3); CFRelease(slideshow.image4); CFRelease(slideshow.image5); This releases the previous slideshow great...BUT when I go back to view that same slideshow again, it crashes.   I am guessing that I need to alloc/init these images again, but I am not sure how?  Or maybe I should be managing this memory in a different way?

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  • Codeigniter not returning me to upload form after image upload.

    - by Drew
    I'm still very new to codeigniter. The issue i'm having is that the file uploads fine and it writes to the database without issue but it just doesn't return me to the upload form. Instead it stays in the do_upload and doesn't display anything. Even more bizarrely there is some source code behind the scenes. Can someone tell my what it is i'm doing wrong because I want to be returning to my upload form after submission. Thanks in advance. Below is my code: Controller: function do_upload() { if($this->Upload_model->do_upload()) { $this->load->view('home/upload_form'); }else{ $this->load->view('home/upload_success', $error); } } Model: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '2000'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $data = $this->upload->data(); $full_path = 'uploads/' . $data['file_name']; $spam = array( 'image_url' => $full_path, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } View (called upload_form): <html> <head> <title>Upload Form</title> </head> <body> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->image_url; ?></h2> <p><?php echo $row->url; ?></p> <p><?php echo $row->name; ?></p> <p><?php echo anchor("upload/update_nav/$row->id", 'edit'); ?></p> <?php endforeach; ?> <?php endif; ?> </body> </html>

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  • How to mask an view with an black-white image?

    - by mystify
    I've heard that it's possible to mask views with black/white images, where black means fully transparent and white means view is visible. The big difference to clipsToBounds is that the view could be clipped in funny shapes like circles or stars. How could I do that?

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  • How to set the HomeScreen image without using method HomeScreen.setBackgroundImage(url)?

    - by Richa
    Hello, Can anyone help me out as I am looking for a method that helps me to set the wallpaper using the images from the Pictures folder on Blackberry Curve 8310. I found one method HomeScreen.setBackground(url), but it doen't works on Blackberry Curve. I am using Operating system 4.5 and this method is useable with operating systems 4.7 & above So, i want to know is their any method for blackberry curve to set the wallpaper or is their any operating system that supports the above method? Kindly reply Thanks a lot Best Regards, Richa Bhatia

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  • How can I by using the FormHelper ,or some other method, render an image link that runs javascript w

    - by chiggsy
    Background: I want to render this: <a href="javascript:myfunction('Somevar')"><img src="some.png" width="20" height="20" border="0" /></a> in a cakephp app. Note: this link is not associated with a model at all, it's just part of a form going off-site. I'm unsure of how to proceed: I've seen this on the cakephp site, but with all that goes on in cake, I'm not sure about the whole javascript calling business. What's the best way to create such a thing?

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  • The scroll viewer is not updating in silverlight

    - by Malcolm
    I have an image inside scroll viewer and i have a control for zooming the image and in zooming event i change the scale of an image ,as below : void zoomSlider_ValueChanged(object sender, RoutedPropertyChangedEventArgs<double> e) { scale.ScaleX = e.NewValue; scale.ScaleY = e.NewValue; //scroll is a name of scrolviewer scroll.UpdateLayout(); } And a xaml below <Grid x:Name="Preview" Grid.Column="1"> <Border x:Name="OuterBorder" BorderThickness="1" BorderBrush="#A3A3A3" > <Border x:Name="InnerBorder" BorderBrush="Transparent" Margin="2" > <Grid Background="White" > <Grid.ColumnDefinitions> <ColumnDefinition Width="*"/> </Grid.ColumnDefinitions> <ScrollViewer x:Name="scroll" HorizontalScrollBarVisibility="Auto" Grid.Column="0" VerticalScrollBarVisibility="Auto" HorizontalAlignment="Stretch" VerticalAlignment="Stretch" Themes:ThemeManager.StyleKey="TreeScrollViewer"> <Image Source="../charge_chargeline.PNG" > <Image.RenderTransform> <CompositeTransform x:Name="**scale**" /> </Image.RenderTransform> </Image> </ScrollViewer> <Border HorizontalAlignment="Center" CornerRadius="0,0,2,2" Width="250" Height="24" VerticalAlignment="Top"> <Border.Background> <LinearGradientBrush StartPoint="0,0" EndPoint="0,1"> <GradientStop Color="#CDD1D4" Offset="0.0"/> <GradientStop Color="#C8CACD" Offset="1.0"/> </LinearGradientBrush> </Border.Background> <ChargeEntry:Zoom x:Name="zoominout" /> </Border> </Grid> </Border> </Border> </Grid>

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  • How do I control Google Search Results display properties?

    - by fmz
    I am putting the finishing touches on a customized Google Search for a site and need a little assistance tweaking the header on the results page. I was able to manage the spacing of the results content with: #results4 { width: 620px; padding: 20px; } However you will notice that the top row of information Results 1 - 10 for search... runs off the right side of the content area. I tried using the following code, but it didn't help: .t td { align:left; } I also tried margin-right and padding but those didn't work either. what is the best way to get that content to move over into the content area? thanks.

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  • How does one control select lists using form API ?

    - by user363036
    I know this is somewhat of a newb question but I am running into a deadline and 3 days of Drupal experience will just not cut it... $form['gender'] = array('#type' = 'select', '#title' = t('Gender: *'), '#options' = array(t('Male'), t('Female')), '#required' = TRUE, '#weight' = 2, ); How do I assign values to select values ? For example Male - 'm' and Female- 'f'. Also how do I give the select box a default caption "please select gender..." Thanks guys

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  • How to zoom image on mouseover at some XY coordinate in JSF?

    - by Paul
    This is the code I use to display images. <t:dataList var="item" value="#{occasionBean.messageInfo}" layout="simple"> <h:commandLink action="#{occasionBean.selectedImage}" > <h:graphicImage styleClass="thumbnail" width="100" height="100" url="#{item.imageSnapUrl}" onclick="return setMsgId(this.id,#{item.img_id},'#{item.imageUrl}');" id="test" onmouseover="" onmouseout=""> </h:graphicImage> </h:commandLink> </t:dataList> Please give some solution.

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  • Titanium TableViewRow classname with custom rows

    - by pancake
    I would like to know in what way the 'className' property of a Ti.UI.TableViewRow helps when creating custom rows. For example, I populate a tableview with custom rows in the following way: function populateTableView(tableView, data) { var rows = []; var row; var title, image; var i; for (i = 0; i < data.length; i++) { title = Ti.UI.createLabel({ text : data[i].title, width : 100, height: 30, top: 5, left: 25 }); image = Ti.UI.createImage({ image : 'some_image.png', width: 30, height: 30, top: 5, left: 5 }); /* and, like, 5+ more views or whatever */ row = Ti.UI.createTableViewRow(); row.add(titleLabel); row.add(image); rows.push(row); } tableView.setData(rows); } Of course, this example of a "custom" row is easily created using the standard title and image properties of the TableViewRow, but that isn't the point. How is the allocation of new labels, image views and other child views of a table view prevented in favour of their reuse? I know in iOS this is achieved by using the method -[UITableView dequeueReusableCellWithIdentifier:] to fetch a row object from a 'reservoir' (so 'className' is 'identifier' here) that isn't currently being used for displaying data, but already has the needed child views laid out correctly in it, thus only requiring to update the data contained within (text, image data, etc). As this system is so unbelievably simple, I have a lot of trouble believing the method employed by the Titanium API does not support this. After reading through the API and searching the web, I do however suspect this is the case. The 'className' property is recommended as an easy way to make table views more efficient in Titanium, but its relation to custom table view rows is not explained in any way. If anyone could clarify this matter for me, I would be very grateful.

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  • How set the response header's Cache-Control in Sitecore?

    - by user822211
    By default, it looks like Sitecore does not cache pages. In web.config, set this <setting name="DisableBrowserCaching" value="false"/> and create pipeline processor page.Response.Cache.SetExpires(DateTime.Now.AddSeconds(60)); page.Response.Cache.SetCacheability(HttpCacheability.Public); but it did not work, the repose head stays no-cache. By the way, I add the pipeline in the renderLayout, anyone knows? thanks!

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  • Livevalidation clientside validation - can you control the position of the validation messages?

    - by JK
    I'm using LiveValidaion for my clientside validation http://livevalidation.com/ and DataAnnotations for my validation rules. This all works fine except that the clientside error messages are only ever displayed to the right of the element being validated. Is it possible to move this validation message below the element being validated? Or even better, group all messages in a div at the top/bottom of the page? I dont see anything in their docs or examples

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  • Use of RegularExpressionValidator in MS .Net Framework

    - by Lawk Salih
    Hi- I am trying to use the RegularExpressionValidator Control in Visual Studio to validate a textbox for email address expressions. Here's my code (very basic) Email:&nbsp; <input id="Text1" type="text" /><br /> <br /> <input id="Validate" type="button" value="Validate" runat="server" /><br /> <br /> <asp:RegularExpressionValidator ID="RegularExpressionValidator1" runat="server" ErrorMessage="RegularExpressionValidator" ControlToValidate="Validate" ValidationExpression="\w+([-+.']\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*"></asp:RegularExpressionValidator> Now, when I set controlToValidate to Validate, I get the following error message: Server Error in '/' Application. Control 'Validate' referenced by the ControlToValidate property of 'RegularExpressionValidator1' cannot be validated. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Web.HttpException: Control 'Validate' referenced by the ControlToValidate property of 'RegularExpressionValidator1' cannot be validated. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [HttpException (0x80004005): Control 'Validate' referenced by the ControlToValidate property of 'RegularExpressionValidator1' cannot be validated.] System.Web.UI.WebControls.BaseValidator.CheckControlValidationProperty(String name, String propertyName) +8734357 System.Web.UI.WebControls.BaseValidator.ControlPropertiesValid() +40 System.Web.UI.WebControls.BaseValidator.get_PropertiesValid() +21 System.Web.UI.WebControls.BaseValidator.OnPreRender(EventArgs e) +27 System.Web.UI.Control.PreRenderRecursiveInternal() +80 System.Web.UI.Control.PreRenderRecursiveInternal() +171 System.Web.UI.Control.PreRenderRecursiveInternal() +171 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +842 Version Information: Microsoft .NET Framework Version:2.0.50727.3607; ASP.NET Version:2.0.50727.3082 I have tried the same mechanism before and have worked; however, this time I am on a new machine, WinXP Pro running IIS v5.1. Any direction would be appreciated.

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  • Struts 2 discard cache header

    - by Dewfy
    I have strange discarding behavior of struts2 while setting cache option for my image. I'm trying to put image from db to be cached on client side To render image I use ( http://struts.apache.org/2.x/docs/how-can-we-display-dynamic-or-static-images-that-can-be-provided-as-an-array-of-bytes.html ) where special result type render as follow: public void execute(ActionInvocation invocation) throws Exception { ...//some preparation HttpServletResponse response = ServletActionContext.getResponse(); HttpServletRequest request = ServletActionContext.getRequest(); ServletOutputStream os = response.getOutputStream(); try { byte[] imageBytes = action.getImage(); response.setContentType("image/gif"); response.setContentLength(imageBytes.length); //I want cache up to 10 min Date future = new Date(((new Date()).getTime() + 1000 * 10*60l)); ; response.addDateHeader("Expires", future.getTime()); response.setHeader("Cache-Control", "max-age=" + 10*60 + ""); response.addHeader("cache-Control", "public"); response.setHeader("ETag", request.getRequestURI()); os.write(imageBytes); } catch(Exception e) { response.sendError(HttpServletResponse.SC_NOT_FOUND); } os.flush(); os.close(); } But when image is embedded to page it is always reloaded (Firebug shows code 200), and neither Expires, nor max-age are presented in header Host localhost:9090 Accept image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Referer http://localhost:9090/web/result?matchId=1 Cookie JSESSIONID=4156BEED69CAB0B84D950932AB9EA1AC; If-None-Match /web/_srv/teamcolor Cache-Control max-age=0 I have no idea why it is dissapered, may be problem in url? It is forms with parameter: http://localhost:9090/web/_srv/teamcolor?loginId=3

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  • How does browser work with expiration headers, cache-control headers, last-modified-header ?

    - by Umair
    I am a web developer, have worked with PHP and .NET both. having over a year of experience working on web I haven't been able to understand the browser caching features thoroughly, I hope Web Gurus here can help me with it. Questions I have in my mind are : How does browser actually caches stuff, does it request for to see if the cached file has changed on the server or not, What is the Ideal way for a developer to make use of browser chaching to its full, but also to be able to push new changes on the site with no hassle at all. I think if browser somehow chaches my CSS and JS and Images, and then just makes a checks for their modification to the server everytime, this can sort the issue. but I am not sure how to do it, waiting for interesting answers :)

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  • Incorrect syntax inserting data into table

    - by SelectDistinct
    I am having some trouble with my update() method. The idea is that the user Provides a recipe name, ingredients, instructions and then selects an image using Filestream. Once the user clicks 'Add Recipe' this will call the update method, however as things stand I am getting an error which is mentioning the contents of the text box: Here is the update() method code: private void updatedata() { // filesteam object to read the image // full length of image to a byte array try { // try to see if the image has a valid path if (imagename != "") { FileStream fs; fs = new FileStream(@imagename, FileMode.Open, FileAccess.Read); // a byte array to read the image byte[] picbyte = new byte[fs.Length]; fs.Read(picbyte, 0, System.Convert.ToInt32(fs.Length)); fs.Close(); //open the database using odp.net and insert the lines string connstr = @"Server=mypcname\SQLEXPRESS;Database=RecipeOrganiser;Trusted_Connection=True"; SqlConnection conn = new SqlConnection(connstr); conn.Open(); string query; query = "insert into Recipes(RecipeName,RecipeImage,RecipeIngredients,RecipeInstructions) values (" + textBox1.Text + "," + " @pic" + "," + textBox2.Text + "," + textBox3.Text + ")"; SqlParameter picparameter = new SqlParameter(); picparameter.SqlDbType = SqlDbType.Image; picparameter.ParameterName = "pic"; picparameter.Value = picbyte; SqlCommand cmd = new SqlCommand(query, conn); cmd.Parameters.Add(picparameter); cmd.ExecuteNonQuery(); MessageBox.Show("Image successfully saved"); cmd.Dispose(); conn.Close(); conn.Dispose(); Connection(); } } catch (Exception ex) { MessageBox.Show(ex.Message); } } Can anyone see where I have gone wrong with the insert into Recipes query or suggest an alternative approach to this part of the code?

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  • How can I limit asp.net control actions based on user role?

    - by Duke
    I have several pages or views in my application which are essentially the same for both authenticated users and anonymous users. I'd like to limit the insert/update/delete actions in formviews and gridviews to authenticated users only, and allow read access for both authed and anon users. I'm using the asp.net configuration system for handling authentication and roles. This system limits access based on path so I've been creating duplicate pages for authed and anon paths. The solution that comes to mind immediately is to check roles in the appropriate event handlers, limiting what possible actions are displayed (insert/update/delete buttons) and also limiting what actions are performed (for users that may know how to perform an action in the absence of a button.) However, this solution doesn't eliminate duplication - I'd be duplicating security code on a series of pages rather than duplicating pages and limiting access based on path; the latter would be significantly less complicated. I could always build some controls that offered role-based configuration, but I don't think I have time for that kind of commitment right now. Is there a relatively easy way to do this (do such controls exist?) or should I just stick to path-based access and duplicate pages? Does it even make sense to use two methods of authorization? There are still some pages which are strictly for either role so I'll be making use of path-based authorization anyway. Finally, would using something other than path-based authorization be contrary to typical asp.net design practices, at least in the context of using the asp.net configuration system?

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  • Best way to version control a WCF application with Git?

    - by Sam
    Suppose I have the following projects. The format is [ProjectName] : [ProjectDependency1, ProjectDependency2, etc.] // Service CoolLibrary WcfApp.Core WcfApp.Contracts WcfApp.Services : CoolLibrary, WcfApp.Core, WcfApp.Contracts // Clients CustomerX.App : WcfApp.Contracts CustomerY.App : WcfApp.Contracts CustomerZ.App : WcfApp.Contracts (On a side note, WcfApp.Contracts should not depend on WcfApp.Core, right? Else CustomerX.App would also depend on and thus be exposed to the service domain model?) (CoolLibrary is shared with other applications, so I can't just put it inside of WcfApp.Services.) All of this code is in-house. I was thinking of having 6 repositories for this. The format is [repository folder name] : [Projects included in repository.] 1. CoolLibrary.git : CoolLibrary 2. WcfApp.Contracts.git : WcfApp.Contracts 3. WcfApp.git : WcfApp.Core, WcfApp.Services 4. CustomerX.App.git : CustomerX.App 5. CustomerY.App.git : CustomerY.App 6. CustomerZ.App.git : CustomerZ.App How should I manage my project dependencies? I see three options: I could use binaries which I have to manually copy to each dependent repository. This would be easiest at the start, but my repositories would be a little bloated, and it'd become more tedious as I add more client apps for customers. I could import dependent code as submodules. This is what I will probably end up doing, although I keep reading on the web that submodules are a hassle. I also read that I can use something called the subtree merge strategy, but I am not sure how it is different from just cloning the repo into a subdirectory and adding the subdirectory to .gitignore. Is the difference that the subtree is recorded in the master repository, so (for example) cloning it from a different location will also pull the subtree? I know I asked a lot of questions in this post, but the most important two questions I have are: 1. Am I using the right number and layout of repositories? Should I use less or more? 2. Which of the three dependency management strategies would you recommend? Is there another strategy I haven't considered?

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  • .next is undefined, jquery plugin problem

    - by ndelangen
    I'm trying to create my own plugin. But I'm having trouble getting things right. It appears when I'm trying to traverse inside .each things go wrong. I'm trying to go to the next item every 6 seconds by fading. jQuery(function($){ $.fn.rotator = function(options){ this.each(function() { var container = $(this); var images = container.children(); //Set the opacity of all images to 0 images.css({opacity: 0.0}); //Get the first image and display it (gets set to full opacity) $('div:first',this).css({opacity: 1.0}).addClass('show'); //Call the rotator function to run the slideshow, 6000 = change to next image after 6 seconds var obj = $(this); setInterval(nextimage(obj),6000); }); }; // rotate function function nextimage(obj) { var container = $(obj); var images = container.children(); //Get the current image var current = (images.hasClass('show')? images.hasClass('show') : images.first()); //Get next image, when it reaches the end, rotate it back to the first image var next = ((current.next().length) ? ((current.next().hasClass('show')) ? images.first() :current.next()) : images.first()); //Set the fade in effect for the next image, the show class has higher z-index next.css({opacity: 0.0}) .addClass('show') .animate({opacity: 1.0}, 1000); //Hide the current image current.animate({opacity: 0.0}, 1000) .removeClass('show'); }; }); $(document).ready(function(){ $("#bg").rotator({ }) }); The error I get is: current.next is not a function Line 35 Line 35 = var next = ((current.next().length) ? ((current.next().hasClass('show')) ? images.first() :current.next()) : images.first()); Can someone tell me what I'm doing wrong?

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