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  • Two quick Mathematica questions

    - by sciguy
    How do I remove the numbers on the x-axis only not the y-axis? Is it possible to shift the y-axis without shifting the functions? What I mean is, instead of having the y-axis at x = 0, could I have it at x = -5?

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  • C++ help and questions

    - by user267237
    I need help making an c++ program with a function that uses int Disc(int A, int B, int C) and calculates returns B*B-4*A*C and use the function Disc in the program..... i have this so far. void main(){ cout << Disc(a,b,c); }

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  • LLBLGen Pro v3.5 has been released!

    - by FransBouma
    Last weekend we released LLBLGen Pro v3.5! Below the list of what's new in this release. Of course, not everything is on this list, like the large amount of work we put in refactoring the runtime framework. The refactoring was necessary because our framework has two paradigms which are added to the framework at a different time, and from a design perspective in the wrong order (the paradigm we added first, SelfServicing, should have been built on top of Adapter, the other paradigm, which was added more than a year after the first released version). The refactoring made sure the framework re-uses more code across the two paradigms (they already shared a lot of code) and is better prepared for the future. We're not done yet, but refactoring a massive framework like ours without breaking interfaces and existing applications is ... a bit of a challenge ;) To celebrate the release of v3.5, we give every customer a 30% discount! Use the coupon code NR1ORM with your order :) The full list of what's new: Designer Rule based .NET Attribute definitions. It's now possible to specify a rule using fine-grained expressions with an attribute definition to define which elements of a given type will receive the attribute definition. Rules can be assigned to attribute definitions on the project level, to make it even easier to define attribute definitions in bulk for many elements in the project. More information... Revamped Project Settings dialog. Multiple project related properties and settings dialogs have been merged into a single dialog called Project Settings, which makes it easier to configure the various settings related to project elements. It also makes it easier to find features previously not used  by many (e.g. type conversions) More information... Home tab with Quick Start Guides. To make new users feel right at home, we added a home tab with quick start guides which guide you through four main use cases of the designer. System Type Converters. Many common conversions have been implemented by default in system type converters so users don't have to develop their own type converters anymore for these type conversions. Bulk Element Setting Manipulator. To change setting values for multiple project elements, it was a little cumbersome to do that without a lot of clicking and opening various editors. This dialog makes changing settings for multiple elements very easy. EDMX Importer. It's now possible to import entity model data information from an existing Entity Framework EDMX file. Other changes and fixes See for the full list of changes and fixes the online documentation. LLBLGen Pro Runtime Framework WCF Data Services (OData) support has been added. It's now possible to use your LLBLGen Pro runtime framework powered domain layer in a WCF Data Services application using the VS.NET tools for WCF Data Services. WCF Data Services is a Microsoft technology for .NET 4 to expose your domain model using OData. More information... New query specification and execution API: QuerySpec. QuerySpec is our new query specification and execution API as an alternative to Linq and our more low-level API. It's build, like our Linq provider, on top of our lower-level API. More information... SQL Server 2012 support. The SQL Server DQE allows paging using the new SQL Server 2012 style. More information... System Type converters. For a common set of types the LLBLGen Pro runtime framework contains built-in type conversions so you don't need to write your own type converters anymore. Public/NonPublic property support. It's now possible to mark a field / navigator as non-public which is reflected in the runtime framework as an internal/friend property instead of a public property. This way you can hide properties from the public interface of a generated class and still access it through code added to the generated code base. FULL JOIN support. It's now possible to perform FULL JOIN joins using the native query api and QuerySpec. It's left to the developer to check whether the used target database supports FULL (OUTER) JOINs. Using a FULL JOIN with entity fetches is not recommended, and should only be used when both participants in the join aren't the target of the fetch. Dependency Injection Tracing. It's now possible to enable tracing on dependency injection. Enable tracing at level '4' on the traceswitch 'ORMGeneral'. This will emit trace information about which instance of which type got an instance of type T injected into property P. Entity Instances in projections in Linq. It's now possible to return an entity instance in a custom Linq projection. It's now also possible to pass this instance to a method inside the query projection. Inheritance fully supported in this construct. Entity Framework support The Entity Framework has been updated in the recent year with code-first support and a new simpler context api: DbContext (with DbSet). The amount of code to generate is smaller and the context simpler. LLBLGen Pro v3.5 comes with support for DbContext and DbSet and generates code which utilizes these new classes. NHibernate support NHibernate v3.2+ built-in proxy factory factory support. By default the built-in ProxyFactoryFactory is selected. FluentNHibernate Session Manager uses 1.2 syntax. Fluent NHibernate mappings generate a SessionManager which uses the v1.2 syntax for the ProxyFactoryFactory location Optionally emit schema / catalog name in mappings Two settings have been added which allow the user to control whether the catalog name and/or schema name as known in the project in the designer is emitted into the mappings.

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  • Null Values And The T-SQL IN Operator

    - by Jesse
    I came across some unexpected behavior while troubleshooting a failing test the other day that took me long enough to figure out that I thought it was worth sharing here. I finally traced the failing test back to a SELECT statement in a stored procedure that was using the IN t-sql operator to exclude a certain set of values. Here’s a very simple example table to illustrate the issue: Customers CustomerId INT, NOT NULL, Primary Key CustomerName nvarchar(100) NOT NULL SalesRegionId INT NULL   The ‘SalesRegionId’ column contains a number representing the sales region that the customer belongs to. This column is nullable because new customers get created all the time but assigning them to sales regions is a process that is handled by a regional manager on a periodic basis. For the purposes of this example, the Customers table currently has the following rows: CustomerId CustomerName SalesRegionId 1 Customer A 1 2 Customer B NULL 3 Customer C 4 4 Customer D 2 5 Customer E 3   How could we write a query against this table for all customers that are NOT in sales regions 2 or 4? You might try something like this: 1: SELECT 2: CustomerId, 3: CustomerName, 4: SalesRegionId 5: FROM Customers 6: WHERE SalesRegionId NOT IN (2,4)   Will this work? In short, no; at least not in the way that you might expect. Here’s what this query will return given the example data we’re working with: CustomerId CustomerName SalesRegionId 1 Customer A 1 5 Customer E 5   I was expecting that this query would also return ‘Customer B’, since that customer has a NULL SalesRegionId. In my mind, having a customer with no sales region should be included in a set of customers that are not in sales regions 2 or 4.When I first started troubleshooting my issue I made note of the fact that this query should probably be re-written without the NOT IN clause, but I didn’t suspect that the NOT IN clause was actually the source of the issue. This particular query was only one minor piece in a much larger process that was being exercised via an automated integration test and I simply made a poor assumption that the NOT IN would work the way that I thought it should. So why doesn’t this work the way that I thought it should? From the MSDN documentation on the t-sql IN operator: If the value of test_expression is equal to any value returned by subquery or is equal to any expression from the comma-separated list, the result value is TRUE; otherwise, the result value is FALSE. Using NOT IN negates the subquery value or expression. The key phrase out of that quote is, “… is equal to any expression from the comma-separated list…”. The NULL SalesRegionId isn’t included in the NOT IN because of how NULL values are handled in equality comparisons. From the MSDN documentation on ANSI_NULLS: The SQL-92 standard requires that an equals (=) or not equal to (<>) comparison against a null value evaluates to FALSE. When SET ANSI_NULLS is ON, a SELECT statement using WHERE column_name = NULL returns zero rows even if there are null values in column_name. A SELECT statement using WHERE column_name <> NULL returns zero rows even if there are nonnull values in column_name. In fact, the MSDN documentation on the IN operator includes the following blurb about using NULL values in IN sub-queries or expressions that are used with the IN operator: Any null values returned by subquery or expression that are compared to test_expression using IN or NOT IN return UNKNOWN. Using null values in together with IN or NOT IN can produce unexpected results. If I were to include a ‘SET ANSI_NULLS OFF’ command right above my SELECT statement I would get ‘Customer B’ returned in the results, but that’s definitely not the right way to deal with this. We could re-write the query to explicitly include the NULL value in the WHERE clause: 1: SELECT 2: CustomerId, 3: CustomerName, 4: SalesRegionId 5: FROM Customers 6: WHERE (SalesRegionId NOT IN (2,4) OR SalesRegionId IS NULL)   This query works and properly includes ‘Customer B’ in the results, but I ultimately opted to re-write the query using a LEFT OUTER JOIN against a table variable containing all of the values that I wanted to exclude because, in my case, there could potentially be several hundred values to be excluded. If we were to apply the same refactoring to our simple sales region example we’d end up with: 1: DECLARE @regionsToIgnore TABLE (IgnoredRegionId INT) 2: INSERT @regionsToIgnore values (2),(4) 3:  4: SELECT 5: c.CustomerId, 6: c.CustomerName, 7: c.SalesRegionId 8: FROM Customers c 9: LEFT OUTER JOIN @regionsToIgnore r ON r.IgnoredRegionId = c.SalesRegionId 10: WHERE r.IgnoredRegionId IS NULL By performing a LEFT OUTER JOIN from Customers to the @regionsToIgnore table variable we can simply exclude any rows where the IgnoredRegionId is null, as those represent customers that DO NOT appear in the ignored regions list. This approach will likely perform better if the number of sales regions to ignore gets very large and it also will correctly include any customers that do not yet have a sales region.

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  • SQL Server - Rebuilding Indexes

    - by Renso
    Goal: Rebuild indexes in SQL server. This can be done one at a time or with the example script below to rebuild all index for a specified table or for all tables in a given database. Why? The data in indexes gets fragmented over time. That means that as the index grows, the newly added rows to the index are physically stored in other sections of the allocated database storage space. Kind of like when you load your Christmas shopping into the trunk of your car and it is full you continue to load some on the back seat, in the same way some storage buffer is created for your index but once that runs out the data is then stored in other storage space and your data in your index is no longer stored in contiguous physical pages. To access the index the database manager has to "string together" disparate fragments to create the full-index and create one contiguous set of pages for that index. Defragmentation fixes that. What does the fragmentation affect?Depending of course on how large the table is and how fragmented the data is, can cause SQL Server to perform unnecessary data reads, slowing down SQL Server’s performance.Which index to rebuild?As a rule consider that when reorganize a table's clustered index, all other non-clustered indexes on that same table will automatically be rebuilt. A table can only have one clustered index.How to rebuild all the index for one table:The DBCC DBREINDEX command will not automatically rebuild all of the indexes on a given table in a databaseHow to rebuild all indexes for all tables in a given database:USE [myDB]    -- enter your database name hereDECLARE @tableName varchar(255)DECLARE TableCursor CURSOR FORSELECT table_name FROM information_schema.tablesWHERE table_type = 'base table'OPEN TableCursorFETCH NEXT FROM TableCursor INTO @tableNameWHILE @@FETCH_STATUS = 0BEGINDBCC DBREINDEX(@tableName,' ',90)     --a fill factor of 90%FETCH NEXT FROM TableCursor INTO @tableNameENDCLOSE TableCursorDEALLOCATE TableCursorWhat does this script do?Reindexes all indexes in all tables of the given database. Each index is filled with a fill factor of 90%. While the command DBCC DBREINDEX runs and rebuilds the indexes, that the table becomes unavailable for use by your users temporarily until the rebuild has completed, so don't do this during production  hours as it will create a shared lock on the tables, although it will allow for read-only uncommitted data reads; i.e.e SELECT.What is the fill factor?Is the percentage of space on each index page for storing data when the index is created or rebuilt. It replaces the fill factor when the index was created, becoming the new default for the index and for any other nonclustered indexes rebuilt because a clustered index is rebuilt. When fillfactor is 0, DBCC DBREINDEX uses the fill factor value last specified for the index. This value is stored in the sys.indexes catalog view. If fillfactor is specified, table_name and index_name must be specified. If fillfactor is not specified, the default fill factor, 100, is used.How do I determine the level of fragmentation?Run the DBCC SHOWCONTIG command. However this requires you to specify the ID of both the table and index being. To make it a lot easier by only requiring you to specify the table name and/or index you can run this script:DECLARE@ID int,@IndexID int,@IndexName varchar(128)--Specify the table and index namesSELECT @IndexName = ‘index_name’    --name of the indexSET @ID = OBJECT_ID(‘table_name’)  -- name of the tableSELECT @IndexID = IndIDFROM sysindexesWHERE id = @ID AND name = @IndexName--Show the level of fragmentationDBCC SHOWCONTIG (@id, @IndexID)Here is an example:DBCC SHOWCONTIG scanning 'Tickets' table...Table: 'Tickets' (1829581556); index ID: 1, database ID: 13TABLE level scan performed.- Pages Scanned................................: 915- Extents Scanned..............................: 119- Extent Switches..............................: 281- Avg. Pages per Extent........................: 7.7- Scan Density [Best Count:Actual Count].......: 40.78% [115:282]- Logical Scan Fragmentation ..................: 16.28%- Extent Scan Fragmentation ...................: 99.16%- Avg. Bytes Free per Page.....................: 2457.0- Avg. Page Density (full).....................: 69.64%DBCC execution completed. If DBCC printed error messages, contact your system administrator.What's important here?The Scan Density; Ideally it should be 100%. As time goes by it drops as fragmentation occurs. When the level drops below 75%, you should consider re-indexing.Here are the results of the same table and clustered index after running the script:DBCC SHOWCONTIG scanning 'Tickets' table...Table: 'Tickets' (1829581556); index ID: 1, database ID: 13TABLE level scan performed.- Pages Scanned................................: 692- Extents Scanned..............................: 87- Extent Switches..............................: 86- Avg. Pages per Extent........................: 8.0- Scan Density [Best Count:Actual Count].......: 100.00% [87:87]- Logical Scan Fragmentation ..................: 0.00%- Extent Scan Fragmentation ...................: 22.99%- Avg. Bytes Free per Page.....................: 639.8- Avg. Page Density (full).....................: 92.10%DBCC execution completed. If DBCC printed error messages, contact your system administrator.What's different?The Scan Density has increased from 40.78% to 100%; no fragmentation on the clustered index. Note that since we rebuilt the clustered index, all other index were also rebuilt.

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  • MySQL query works in PHPMyAdmin but not PHP

    - by Su4p
    I do not understand what's happening. I have a query in PHP who crashes -with a strange error-. When I copy/paste the exact same request in PHPMyAdmin it works as expected. What am I doing wrong here ? SELECT oms_patient.id, oms_patient.date, oms_patient.date_modif, date_modif, AES_DECRYPT(nom,"xxxxx") AS "Nom", AES_DECRYPT(prenom,"xxxxx") AS "Prénom usuel", DATE_FORMAT(ddn, "%d/%m/%Y") AS "Date de naissance", villeNaissance AS "Lieu de naissance (ville)", CONCAT(oms_departement.libelle,"(",id_departement,")") AS "Lieu de vie", CONCAT(oms_pays.libelle,"(",id_pays,")") AS "Pays", CONCAT(patientsexe.libelle,"(",id_sexe,")") AS "Sexe", CONCAT(patientprofession.libelle,"(",id_profession,")") AS "Profession", IF(asthme>0,"Oui","Non") AS "Asthme", IF(rhinite>0,"Oui","Non") AS "Rhinite", IF(bcpo>0,"Oui","Non") AS "BPCO", IF(insuffisanceResp>0,"Oui","Non") AS "Insuffisance respiratoire chronique", IF(chirurgieOrl>0,"Oui","Non") AS "Chirurgie ORL du ronflement", IF(autreChirurgie>0,"Oui","Non") AS "Autre chirurgie ORL", IF(allergies>0,"Oui","Non") AS "Allergies", IF(OLD>0,"Oui","Non") AS "OLD", IF(hypertensionArterielle>0,"Oui","Non") AS "Hypertension artérielle", IF(infarctusMyocarde>0,"Oui","Non") AS "Infarctus du myocarde", IF(insuffisanceCoronaire>0,"Oui","Non") AS "Insuffisance coronaire", IF(troubleRythme>0,"Oui","Non") AS "Trouble du rythme", IF(accidentVasculaireCerebral>0,"Oui","Non") AS "Accident vasculaire cérébral", IF(insuffisanceCardiaque>0,"Oui","Non") AS "Insuffisance cardiaque", IF(arteriopathie>0,"Oui","Non") AS "Artériopathie", IF(tabagismeActuel>0,"Oui","Non") AS "Tabagisme actuel", CONCAT(nbPaquetsActuel," ","PA") AS "", IF(tabagismeAncien>0,"Oui","Non") AS "Tabagisme ancien", CONCAT(nbPaquetsAncien," ","PA") AS "", IF(alcool>0,"Oui","Non") AS "Alcool (conso régulière)", IF(refluxGastro>0,"Oui","Non") AS "Reflux gastro-oesophagien", IF(glaucome>0,"Oui","Non") AS "Glaucome", IF(diabete>0,"Oui","Non") AS "Diabète", CONCAT(patienttypeDiabete.libelle,"(",id_typeDiabete,")") AS "", IF(hypercholesterolemie>0,"Oui","Non") AS "Hypercholestérolémie", IF(hypertriglyceridemie>0,"Oui","Non") AS "Hypertriglycéridémie", IF(dysthyroidie>0,"Oui","Non") AS "Dysthyroïdie", IF(depression>0,"Oui","Non") AS "Dépression", IF(sedentarite>0,"Oui","Non") AS "Sédentarité", IF(syndromeDApneesSommeil>0,"Oui","Non") AS "SAS", IF(obesite>0,"Oui","Non") AS "Obésité", IF(dysmorphieFaciale>0,"Oui","Non") AS "Dysmorphie faciale", TextObservations AS "", id_user FROM oms_patient LEFT JOIN oms_departement ON oms_departement.id = id_departement LEFT JOIN oms_pays ON oms_pays.id = id_pays LEFT JOIN patientsexe ON patientsexe.id = id_sexe LEFT JOIN patientprofession ON patientprofession.id = id_profession LEFT JOIN patienttypeDiabete ON patienttypeDiabete.id = id_typeDiabete WHERE oms_patient.id=1 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'small"(conso régulière)", IF(refluxGastro0,"Oui","Non") as "Reflux ga' at line 1 "near 'small" <-- where is small o_O The PHP code isn't really relevant cause you won't see a lot. $db = mysql_connect(); mysql_select_db();//TODO SWITCH TO PDO mysql_query("SET NAMES UTF8"); $fields = $form->getFields($form); $settingsForm = $form->getSettings(); $sql = 'SELECT oms_patient.id,oms_patient.date,oms_patient.date_modif,'; foreach ($fields as $field) { if (!$field->isMultiSelect()) { $field->select_full(&$sql, 'oms_patient', null); } } if (isset($settingsForm['linkTo'])) { $idLinkTo = 'id_' . str_replace('oms_', '', $settingsForm['linkTo']); $sql .= $idLinkTo; } $sql.=' FROM oms_patient'; foreach ($fields as $field) { if (!$field->isMultiSelect() && $field->getTable('oms_patient')) { $sql .=' LEFT JOIN ' . $field->getTable('oms_patient') . ' ON ' . $field->getTable('oms_patient') . '.id = '.$field->getFieldName().' '; } } $sql.=' where oms_patient.id=' . $this->m_settings['e']; $result = mysql_query($sql) or die('Erreur SQL !<br>' . $sql . '<br>' . mysql_error()); $data = mysql_fetch_assoc($result); var_dump of $sql string(2663) "SELECT oms_patient.id,oms_patient.date,oms_patient.date_modif,date_modif,AES_DECRYPT(nom,"xxxxx") as "Nom",AES_DECRYPT("prenom","xxxxx") as "Prénom usuel",DATE_FORMAT(ddn, "%d/%m/%Y") as "Date de naissance",villeNaissance as "Lieu de naissance (ville)",CONCAT(oms_departement.libelle,"(",id_departement,")") as "Lieu de vie",CONCAT(oms_pays.libelle,"(",id_pays,")") as "Pays",CONCAT(patientsexe.libelle,"(",id_sexe,")") as "Sexe",CONCAT(patientprofession.libelle,"(",id_profession,")") as "Profession", IF"... can't go further to see what is in the output after the "..." <-- if you have an idea

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  • Maximum number of characters using keystrokes A, Ctrl+A, Ctrl+C and Ctrl+V

    - by munda
    This is an interview question from google. I am not able to solve it by myself. Can somebody shed some light? Write a program to print the sequence of keystrokes such that it generates the maximum number of character 'A's. You are allowed to use only 4 keys: A, Ctrl+A, Ctrl+C and Ctrl+V. Only N keystrokes are allowed. All Ctrl+ characters are considered as one keystroke, so Ctrl+A is one keystroke. For example, the sequence A, Ctrl+A, Ctrl+C, Ctrl+V generates two A's in 4 keystrokes. Ctrl+A is Select All Ctrl+C is Copy Ctrl+V is Paste I did some mathematics. For any N, using x numbers of A's , one Ctrl+A, one Ctrl+C and y Ctrl+V, we can generate max ((N-1)/2)2 number of A's. For some N M, it is better to use as many Ctrl+A's, Ctrl+C and Ctrl+V sequences as it doubles the number of A's. The sequence Ctrl+A, Ctrl+V, Ctrl+C will not overwrite the existing selection. It will append the copied selection to selected one.

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  • Leveraging hobby experience to get a job

    - by Bernard
    Like many other's I began programming at an early age. I started when I was 11 and I learned C when I was 14 (now 26). While most of what I did were games just to entertain myself I did everything from low level 2D graphics, and binary I/O, to interfacing with free API's, custom file systems, audio, 3D animations, OpenGL, web sites, etc. I worked on a wide variety of things trying to make various games. Because of this experience I have tested out of every college level C/C++ programming course I have ever been offered. In the classes I took, my classmates would need a week to do what I finished in class with an hour or two of work. I now have my degree now and I have 2 years of experience working full time as a web developer however I would like to get back into C++ and hopefully do simulation programming. Unfortunately I have yet to do C++ as a job, I have only done it for testing out of classes and doing my senior project in college. So most of what I have in C++ is still hobby experience and I don't know how to best convey that so that I don't end up stuck doing something too low level for me. Right now I see a job offer that requires 2 years of C++ experience, but I have at least 9 (I didn't do C++ everyday for the last 14 years). How do I convey my experience? How much is it truly worth? and How do I get it's full value? The best thing that I can think of is a demo and a portfolio, however that only comes into play after an interview has been secured. I used a portfolio to land my current job. All answers and advice are appreciated.

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  • webscraper grabbing images, but not entering info into database

    - by Jason
    Hello, again. I'm having more issues with my script entering info into my database. The script below grabs a page, strips down the necessary info, then downloads the related image file. After that, it is supposed to enter the information gleaned from the URL into the database. For some reason, the script seems to iterate through the URLs, as I get downloaded images for each URL, but each URL's product is not entered into the database. The script will insert the first product's categories and product info, and then it just stops, and continues to download images. Any suggestions? <?php define('IN_PHPBB', true); $phpbb_root_path = (defined('PHPBB_ROOT_PATH')) ? PHPBB_ROOT_PATH : './'; $phpEx = substr(strrchr(__FILE__, '.'), 1); include($phpbb_root_path . 'common.' . $phpEx); include($phpbb_root_path . 'includes/simple_html_dom.' . $phpEx); // Start session management $user->session_begin(); $auth->acl($user->data); $user->setup(); set_time_limit(259200); function save($in, $out) { $ch = curl_init ($in); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_BINARYTRANSFER,1); $rawdata=curl_exec($ch); curl_close ($ch); if(file_exists($out)) { unlink($out); } $fp = fopen($out,'x'); fwrite($fp, $rawdata); fclose($fp); } function scrape($i) { $url = 'http:/xxxxxxxx/index.php?main_page=product_info&products_id='.$i.'&zenid=e4b7dde8de02e1df005d4549e2e3e529'; echo "$url -- "; $exists = file_get_contents($url); if ($exists != false) { $html = file_get_html($url); foreach($html->find('body') as $html) { $test = $html->find('#productName', 0); if ($test) { $item['title'] = trim($html->find('#productName', 0)->plaintext); $item['price'] = trim($html->find('#productPrices', 0)->plaintext); $item['cat'] = $html->find('#navBreadCrumb', 0)->plaintext; list($home, $item['cat'], $item['subcat'], $title) = explode("::", $item['cat']); $item['cat'] = str_replace("&nbsp;", "", $item['cat']); $item['subcat'] = str_replace("\n", "", str_replace("&nbsp;", "", $item['subcat'])); $item['desc'] = trim($html->find('#productDescription', 0)->plaintext); $item['model'] = $html->find('ul#productDetailsList', 0)->find('li', 0)->plaintext; $item['model'] = explode(":", $item['model']); $item['model'] = trim($item['model'][1]); $item['manufacturer'] = $html->find('ul#productDetailsList', 0)->find('li', 1)->plaintext; $item['manufacturer'] = explode(":", $item['manufacturer']); $item['manufacturer'] = trim($item['manufacturer'][1]); foreach($html->find('img') as $img) { if($img->alt == $item['title']) { $item['img_sm'] = $img->src; } } $ret[] = $item; } } $html->clear(); unset($html); unset($item); return $ret; } else { echo "Could not find page<br />"; } unset($exists); } $i = 1; $end = 9999999; while($i < $end) { $ret = scrape($i); if(isset($ret)) { foreach($ret as $v) { $item['title'] = $v['title']; $item['price'] = $v['price']; $item['desc'] = $v['desc']; $item['model'] = $v['model']; $item['manufacturer'] = $v['manufacturer']; $item['image'] = $v['image']; $item['cat'] = $v['cat']; $item['subcat'] = $v['subcat']; $item['img_sm'] = $v['img_sm']; } unset($ret); unset($v); $sm_img_src = "http://xxxxxx/".$item['img_sm']; $ext = strrchr($item['img_sm'], '.'); $filename = $item['model'] . $ext; $lg_img_src = "http://xxxxx/images/STC/".$filename; $new_sm = "./rip_images/small/{$filename}"; $new_lg = "./rip_images/large/{$filename}"; $item['image'] = $filename; save($lg_img_src,$new_lg); save($sm_img_src,$new_sm); //see if parent cat exists $sql = 'SELECT cat_id FROM ' . SHOP_CAT_TABLE . ' WHERE cat_name = "'.$db->sql_escape($item['cat']).'"'; $result = $db->sql_query($sql); $parent = $db->sql_fetchrow($result); $db->sql_freeresult($result); // if not exists if($parent['cat_id'] == '') { //add the parent cat to the db $sql_ary = array( 'cat_name' => $item['cat'], 'cat_parent' => 0 ); $sql = 'INSERT INTO '.SHOP_CAT_TABLE.' '.$db->sql_build_array('INSERT', $sql_ary); $db->sql_query($sql); $cat_id = $db->sql_nextid(); //see if subcat exists $sql = 'SELECT cat_id FROM ' . SHOP_CAT_TABLE . ' WHERE cat_name = "'.$db->sql_escape($item['subcat']).'"'; $result = $db->sql_query($sql); $row = $db->sql_fetchrow($result); $db->sql_freeresult($result); // if not exists if($row['cat_id'] == '') { //add subcat to db $sql_ary = array( 'cat_name' => $db->sql_escape($item['subcat']), 'cat_parent' => $cat_id ); $sql = 'INSERT INTO '.SHOP_CAT_TABLE.' '.$db->sql_build_array('INSERT', $sql_ary); $db->sql_query($sql); $item_cat = $db->sql_nextid(); } else //if exists { $item_cat = $row['cat_id']; } } else //if parent cat exists { //see if subcat exists $sql = 'SELECT cat_id FROM ' . SHOP_CAT_TABLE . ' WHERE cat_name = "'.$db->sql_escape($item['subcat']).'"'; $result = $db->sql_query($sql); $row = $db->sql_fetchrow($result); $db->sql_freeresult($result); // if not exists if($row['cat_id'] == '') { //add the subcat to the db $sql_ary = array( 'cat_name' => $db->sql_escape($item['subcat']), 'cat_parent' => $parent['cat_id'] ); $sql = 'INSERT INTO '.SHOP_CAT_TABLE.' '.$db->sql_build_array('INSERT', $sql_ary); $db->sql_query($sql); $item_cat = $db->sql_nextid(); } else //if exists { $item_cat = $row['cat_id']; } } $sql_ary = array( 'item_title' => $db->sql_escape($item['title']), 'item_price' => $db->sql_escape($item['price']), 'item_desc' => $db->sql_escape($item['desc']), 'item_model' => $db->sql_escape($item['model']), 'item_manufacturer' => $db->sql_escape($item['manufacturer']), 'item_image' => $db->sql_escape($item['image']), 'item_cat' => $db->sql_escape($item_cat) ); $sql = 'INSERT INTO ' . SHOP_ITEM_TABLE . ' ' . $db->sql_build_array('INSERT', $sql_ary); $db->sql_query($sql); garbage_collection(); echo 'Done<br />'; } $i++; unset($item); } ?>

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  • algorithm to generate maximum number of character 'A' using keystrokes 'A', CTRL + 'A', CTRL + 'C' and CTRL + 'V'

    - by munda
    This is an interview question from google. I am not able to solve it by myself. Can somebody throw some light? The question goes like this. Write a program to print the sequence of keystrokes such that it generates the maximum number of character 'A's. You are allowed to use only 4 keys: 'A', CTRL + 'A', CTRL + 'C' and CTRL + 'V'. Only N keystrokes are allowed. All CTRL+ characters are considered as one keystroke, so CTRL+A is one keystroke. e.g.: A, ctrl+A, ctrl+C, ctrl+V generates two As in 4 keystrokes. Edit: CTRL + A is Select All CTRL + C is copy CTRL + V is paste I did some mathematics. For any N, using x numbers of A's , one CTRL+A, one CTRL+C and y CTRL+V, we can generate max ((N-1)/2)^2 numbers of A's. But for some N M, it is better to use as many ^A, ^C and ^V as it doubles the number of As. Edit 2: ^A, ^V and ^C will not overwrite on the existing selection but it will append the copied selection to selected one.

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  • Algorithm to determine indices i..j of array A containing all the elements of another array B

    - by Skylark
    I came across this question on an interview questions thread. Here is the question: Given two integer arrays A [1..n] and B[1..m], find the smallest window in A that contains all elements of B. In other words, find a pair < i , j such that A[i..j] contains B[1..m]. If A doesn't contain all the elements of B, then i,j can be returned as -1. The integers in A need not be in the same order as they are in B. If there are more than one smallest window (different, but have the same size), then its enough to return one of them. Example: A[1,2,5,11,2,6,8,24,101,17,8] and B[5,2,11,8,17]. The algorithm should return i = 2 (index of 5 in A) and j = 9 (index of 17 in A). Now I can think of two variations. Let's suppose that B has duplicates. This variation doesn't consider the number of times each element occurs in B. It just checks for all the unique elements that occur in B and finds the smallest corresponding window in A that satisfies the above problem. For example, if A[1,2,4,5,7] and B[2,2,5], this variation doesn't bother about there being two 2's in B and just checks A for the unique integers in B namely 2 and 5 and hence returns i=1, j=3. This variation accounts for duplicates in B. If there are two 2's in B, then it expects to see at least two 2's in A as well. If not, it returns -1,-1. When you answer, please do let me know which variation you are answering. Pseudocode should do. Please mention space and time complexity if it is tricky to calculate it. Mention if your solution assumes array indices to start at 1 or 0 too. Thanks in advance.

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  • In the meantime, to be or not to be ... productive!

    - by Jan Kuboschek
    I just moved back to Europe from the US after living there for 7 years. Apart from major adjustment issues, I'm currently looking for a job over here. I'm mainly interested in (IT) Consulting and, since these jobs typically require programming knowledge, such as Java, I'm trying to think of something productive to write (perhaps to demo my skills) while I'm waiting for my interviews (starting in two weeks. Folks here are a bit slower than in the US apparently...). I graduated from college about a year and a half ago and have a 4 year degree in international management/economics and about 3/4 of a 2 year degree in computer science finished. I've written my fair share of web software over the years, but nothing concrete that I could show, especially not in Java. Now, I've never had the problem of not having any idea what to write. Basic games I could write, but I'm not sure how well that'll come over when I walk into my interview and say "hey, I was bored. Take a look at my multiplayer space invaders game! Wanna try beating me??". Any thoughts? I browsed SourceForge the other day to find a nice little project to contribute to, but decided that I don't want to commit to someone else's project at this time. Any ideas, perhaps from someone who has been, or currently is, in a similar position would be much appreciated. Oh, and lastly: Instead of developing a program or two to demonstrate my skills, I could spend my time brushing up on UML and Perl. Any suggestions regarding that? Writing a demo vs. learning something new?

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  • Algorithm to determine if array contains n...n+m?

    - by Kyle Cronin
    I saw this question on Reddit, and there were no positive solutions presented, and I thought it would be a perfect question to ask here. This was in a thread about interview questions: Write a method that takes an int array of size m, and returns (True/False) if the array consists of the numbers n...n+m-1, all numbers in that range and only numbers in that range. The array is not guaranteed to be sorted. (For instance, {2,3,4} would return true. {1,3,1} would return false, {1,2,4} would return false. The problem I had with this one is that my interviewer kept asking me to optimize (faster O(n), less memory, etc), to the point where he claimed you could do it in one pass of the array using a constant amount of memory. Never figured that one out. Along with your solutions please indicate if they assume that the array contains unique items. Also indicate if your solution assumes the sequence starts at 1. (I've modified the question slightly to allow cases where it goes 2, 3, 4...) edit: I am now of the opinion that there does not exist a linear in time and constant in space algorithm that handles duplicates. Can anyone verify this? The duplicate problem boils down to testing to see if the array contains duplicates in O(n) time, O(1) space. If this can be done you can simply test first and if there are no duplicates run the algorithms posted. So can you test for dupes in O(n) time O(1) space?

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  • How can we find second maximum from array efficiently?

    - by Xinus
    Is it possible to find the second maximum number from an array of integers by traversing the array only once? As an example, I have a array of five integers from which I want to find second maximum number. Here is an attempt I gave in the interview: #define MIN -1 int main() { int max=MIN,second_max=MIN; int arr[6]={0,1,2,3,4,5}; for(int i=0;i<5;i++){ cout<<"::"<<arr[i]; } for(int i=0;i<5;i++){ if(arr[i]>max){ second_max=max; max=arr[i]; } } cout<<endl<<"Second Max:"<<second_max; int i; cin>>i; return 0; } The interviewer, however, came up with the test case int arr[6]={5,4,3,2,1,0};, which prevents it from going to the if condition the second time. I said to the interviewer that the only way would be to parse the array two times (two for loops). Does anybody have a better solution?

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  • Given a 2d array sorted in increasing order from left to right and top to bottom, what is the best w

    - by Phukab
    I was recently given this interview question and I'm curious what a good solution to it would be. Say I'm given a 2d array where all the numbers in the array are in increasing order from left to right and top to bottom. What is the best way to search and determine if a target number is in the array? Now, my first inclination is to utilize a binary search since my data is sorted. I can determine if a number is in a single row in O(log N) time. However, it is the 2 directions that throw me off. Another solution I could use, if I could be sure the matrix is n x n, is to start at the middle. If the middle value is less than my target, then I can be sure it is in the left square portion of the matrix from the middle. I then move diagnally and check again, reducing the size of the square that the target could potentially be in until I have honed in on the target number. Does anyone have any good ideas on solving this problem? Example array: Sorted left to right, top to bottom. 1 2 4 5 6 2 3 5 7 8 4 6 8 9 10 5 8 9 10 11

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  • Where is my app.config for SSIS?

    Sometimes when working with SSIS you need to add or change settings in the .NET application configuration file, which can be a bit confusing when you are building a SSIS package not an application. First of all lets review a couple of examples where you may need to do this. You are using referencing an assembly in a Script Task that uses Enterprise Library (aka EntLib), so you need to add the relevant configuration sections and settings, perhaps for the logging application block. You are using using Enterprise Library in a custom task or component, and again you need to add the relevant configuration sections and settings. You are using a web service with Microsoft Web Services Enhancements (WSE) 3.0 and hosting the proxy in SSIS, in an assembly used by your package, and need to add the configuration sections and settings. You need to change behaviours of the .NET framework which can be influenced by a configuration file, such as the System.Net.Mail default SMTP settings. Perhaps you wish to configure System.Net and the httpWebRequest header for parsing unsafe header (useUnsafeHeaderParsing), which will change the way the HTTP Connection manager behaves. You are consuming a WCF service and wish to specify the endpoint in configuration. There are no doubt plenty more examples but each of these requires us to identify the correct configuration file and and make the relevant changes. There are actually several configuration files, each used by a different execution host depending on how you are working with the SSIS package. The folders we need to look in will actually vary depending on the version of SQL Server as well as the processor architecture, but most are all what we can call the Binn folder. The SQL Server 2005 Binn folder is at C:\Program Files\Microsoft SQL Server\90\DTS\Binn\, compared to C:\Program Files\Microsoft SQL Server\100\DTS\Binn\ for SQL Server 2008. If you are on a 64-bit machine then you will see C:\Program Files (x86)\Microsoft SQL Server\90\DTS\Binn\ for the 32-bit executables and C:\Program Files\Microsoft SQL Server\90\DTS\Binn\ for 64-bit, so be sure to check all relevant locations. Of course SQL Server 2008 may have a C:\Program Files (x86)\Microsoft SQL Server\100\DTS\Binn\ on a 64-bit machine too. To recap, the version of SQL Server determines if you look in the 90 or 100 sub-folder under SQL Server in Program Files (C:\Program Files\Microsoft SQL Server\nn\) . If you are running a 64-bit operating system then you will have two instances program files, C:\Program Files (x86)\ for 32-bit and  C:\Program Files\ for 64-bit. You may wish to check both depending on what you are doing, but this is covered more under each section below. There are a total of five specific configuration files that you may need to change, each one is detailed below: DTExec.exe.config DTExec.exe is the standalone command line tool used for executing SSIS packages, and therefore it is an execution host with an app.config file. e.g. C:\Program Files\Microsoft SQL Server\90\DTS\Binn\DTExec.exe.config The file can be found in both the 32-bit and 64-bit Binn folders. DtsDebugHost.exe.config DtsDebugHost.exe is the execution host used by Business Intelligence Development Studio (BIDS) / Visual Studio when executing a package from the designer in debug mode, which is the default behaviour. e.g. C:\Program Files\Microsoft SQL Server\90\DTS\Binn\DtsDebugHost.exe.config The file can be found in both the 32-bit and 64-bit Binn folders. This may surprise some people as Visual Studio is only 32-bit, but thankfully the debugger supports both. This can be set in the project properties, see the Run64BitRuntime property (true or false) in the Debugging pane of the Project Properties. dtshost.exe.config dtshost.exe is the execution host used by what I think of as the built-in features of SQL Server such as SQL Server Agent e.g. C:\Program Files\Microsoft SQL Server\90\DTS\Binn\dtshost.exe.config This file can be found in both the 32-bit and 64-bit Binn folders devenv.exe.config Something slightly different is devenv.exe which is Visual Studio. This configuration file may also need changing if you need a feature at design-time such as in a Task Editor or Connection Manager editor. Visual Studio 2005 for SQL Server 2005  - C:\Program Files\Microsoft Visual Studio 8\Common7\IDE\devenv.exe.config Visual Studio 2008 for SQL Server 2008  - C:\Program Files\Microsoft Visual Studio 9.0\Common7\IDE\devenv.exe.config Visual Studio is only available for 32-bit so on a 64-bit machine you will have to look in C:\Program Files (x86)\ only. DTExecUI.exe.config The DTExec UI tool can also have a configuration file and these cab be found under the Tools folders for SQL Sever as shown below. C:\Program Files\Microsoft SQL Server\90\Tools\Binn\VSShell\Common7\IDE\DTExecUI.exe C:\Program Files\Microsoft SQL Server\100\Tools\Binn\VSShell\Common7\IDE\DTExecUI.exe A configuration file may not exist, but if you can find the matching executable you know you are in the right place so can go ahead and add a new file yourself. In summary we have covered the assembly configuration files for all of the standard methods of building and running a SSIS package, but obviously if you are working programmatically you will need to make the relevant modifications to your program’s app.config as well.

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  • Where is my app.config for SSIS?

    Sometimes when working with SSIS you need to add or change settings in the .NET application configuration file, which can be a bit confusing when you are building a SSIS package not an application. First of all lets review a couple of examples where you may need to do this. You are using referencing an assembly in a Script Task that uses Enterprise Library (aka EntLib), so you need to add the relevant configuration sections and settings, perhaps for the logging application block. You are using using Enterprise Library in a custom task or component, and again you need to add the relevant configuration sections and settings. You are using a web service with Microsoft Web Services Enhancements (WSE) 3.0 and hosting the proxy in SSIS, in an assembly used by your package, and need to add the configuration sections and settings. You need to change behaviours of the .NET framework which can be influenced by a configuration file, such as the System.Net.Mail default SMTP settings. Perhaps you wish to configure System.Net and the httpWebRequest header for parsing unsafe header (useUnsafeHeaderParsing), which will change the way the HTTP Connection manager behaves. You are consuming a WCF service and wish to specify the endpoint in configuration. There are no doubt plenty more examples but each of these requires us to identify the correct configuration file and and make the relevant changes. There are actually several configuration files, each used by a different execution host depending on how you are working with the SSIS package. The folders we need to look in will actually vary depending on the version of SQL Server as well as the processor architecture, but most are all what we can call the Binn folder. The SQL Server 2005 Binn folder is at C:\Program Files\Microsoft SQL Server\90\DTS\Binn\, compared to C:\Program Files\Microsoft SQL Server\100\DTS\Binn\ for SQL Server 2008. If you are on a 64-bit machine then you will see C:\Program Files (x86)\Microsoft SQL Server\90\DTS\Binn\ for the 32-bit executables and C:\Program Files\Microsoft SQL Server\90\DTS\Binn\ for 64-bit, so be sure to check all relevant locations. Of course SQL Server 2008 may have a C:\Program Files (x86)\Microsoft SQL Server\100\DTS\Binn\ on a 64-bit machine too. To recap, the version of SQL Server determines if you look in the 90 or 100 sub-folder under SQL Server in Program Files (C:\Program Files\Microsoft SQL Server\nn\) . If you are running a 64-bit operating system then you will have two instances program files, C:\Program Files (x86)\ for 32-bit and  C:\Program Files\ for 64-bit. You may wish to check both depending on what you are doing, but this is covered more under each section below. There are a total of five specific configuration files that you may need to change, each one is detailed below: DTExec.exe.config DTExec.exe is the standalone command line tool used for executing SSIS packages, and therefore it is an execution host with an app.config file. e.g. C:\Program Files\Microsoft SQL Server\90\DTS\Binn\DTExec.exe.config The file can be found in both the 32-bit and 64-bit Binn folders. DtsDebugHost.exe.config DtsDebugHost.exe is the execution host used by Business Intelligence Development Studio (BIDS) / Visual Studio when executing a package from the designer in debug mode, which is the default behaviour. e.g. C:\Program Files\Microsoft SQL Server\90\DTS\Binn\DtsDebugHost.exe.config The file can be found in both the 32-bit and 64-bit Binn folders. This may surprise some people as Visual Studio is only 32-bit, but thankfully the debugger supports both. This can be set in the project properties, see the Run64BitRuntime property (true or false) in the Debugging pane of the Project Properties. dtshost.exe.config dtshost.exe is the execution host used by what I think of as the built-in features of SQL Server such as SQL Server Agent e.g. C:\Program Files\Microsoft SQL Server\90\DTS\Binn\dtshost.exe.config This file can be found in both the 32-bit and 64-bit Binn folders devenv.exe.config Something slightly different is devenv.exe which is Visual Studio. This configuration file may also need changing if you need a feature at design-time such as in a Task Editor or Connection Manager editor. Visual Studio 2005 for SQL Server 2005  - C:\Program Files\Microsoft Visual Studio 8\Common7\IDE\devenv.exe.config Visual Studio 2008 for SQL Server 2008  - C:\Program Files\Microsoft Visual Studio 9.0\Common7\IDE\devenv.exe.config Visual Studio is only available for 32-bit so on a 64-bit machine you will have to look in C:\Program Files (x86)\ only. DTExecUI.exe.config The DTExec UI tool can also have a configuration file and these cab be found under the Tools folders for SQL Sever as shown below. C:\Program Files\Microsoft SQL Server\90\Tools\Binn\VSShell\Common7\IDE\DTExecUI.exe C:\Program Files\Microsoft SQL Server\100\Tools\Binn\VSShell\Common7\IDE\DTExecUI.exe A configuration file may not exist, but if you can find the matching executable you know you are in the right place so can go ahead and add a new file yourself. In summary we have covered the assembly configuration files for all of the standard methods of building and running a SSIS package, but obviously if you are working programmatically you will need to make the relevant modifications to your program’s app.config as well.

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  • Where can I ask web design questions of a more amateur nature?

    - by Warren van Rooyen
    I don't want to bother pro web designers with simple questions as I see most of the questions here are quite technical. An example would be, 'I have a template I've downloaded. The folder contains a css folder and PHP files. How would I bring this into Dreamweaver?' It's unfortunately in a space between what I'd be able to find on Google and asking here without feeling like a hinderance for those who don't want to answer such simple questions. Thanks, Warren.

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  • "Je suis un ingénieur, pas un compilateur", les questions d'entretiens sont-elles trop orientées vers la maîtrise des instructions et concepts ?

    « Je suis un ingénieur, pas un compilateur » les questions d'entretiens sont-elles trop orientées vers la maitrise des instructions et concepts des langages De nos jours, les offres d'emplois sont de plus en plus orientées vers des langages bien définis. Conséquence : les questions d'entretiens abordent beaucoup plus les aspects liés aux concepts du langage. C'est en tout cas le constat d'un développeur au pseudo de clements, dans un billet de blog intitulé « je suis un ingénieur, pas un compilateur ». Celui-ci s'est rendu compte lors de plusieurs entretiens que des questions standards comme : qu'est-ce que le polymorphisme ? Quelle est la différence entre « List » et « S...

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  • Can Questions be Reopened After They've Been Closed by Some Self Appointed Gestapo Moderators? [migrated]

    - by GenericJam
    This is obviously begging to be shut down right away and have all my privileges revoked or whatever but why do some people feel they have the right to shut down legitimate discussion? Who decides what is a "real" question or topic of interest? If you don't think it's valid, just click somewhere else but it is really getting to me on this site and StackOverflow how many really useful questions are shut down because people are asking opinions not textbook facts. Questions like this one are genuinely useful. Don't shut them down. You are making this site less useful for everyone else. Do people get their kicks by just wandering around the site closing questions? It seems many of the same names appear on the "closed down" box. Just go to a different page, don't ruin everyone else's education the way they choose it.

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  • Linq 2 SQL One to Zero or One relationship possible?

    - by Mr. Flibble
    Is it possible to create a one to zero or one relationship in Linq2SQL? My understanding is that to create a one to one relationship you create a FK relationship on the PK of each table. But you cannot make the PK nullable, so I don't see how to make a one to zero or one relationship work? I'm using the designer to automatically create the model - so I would like to know how to set up the SQL tables to induce the relationship - not some custom ORM code.

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