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  • Can I do a "one-time" file content search in Windows Server 2008 without adding the folder to the index?

    - by G-.
    Can I search for files which contain a specific string in a folder if that folder is not in the search index? So, lets say folder 'textFiles' is not in the index. I navigate to this folder in windows explorer. I type '.ini' in the search box I want to see a result list containing only 'b.txt' FOLDER C:\textFiles\ FILE a.php CONTENT once twice thrice mice moose monkey FILE b.txt CONTENT mingle muddle middle.ini banana beer FILE c.spo CONTENT sellotape stapler phone book I do not have permission to add folders to the windows index and I do not have permission to install or run any executables that did not ship with the server or approved applications. I'd be happy with a windows native command line solution if necessary? Thanks G

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  • Windows 7 search for files with special characters in name.

    - by Luke
    I have a rather large source code repository on my machine; it is not indexed by Windows Search. I am trying to find some oddly-named generated files of the form .#name.extension.version where name and extension are normal names and extensions and version is a numeric value (e.g. something like 1.186). On Windows XP I could find these files by searching for .#*; on Windows 7 that just returns every single file and directory. So my question is this: is it possible to find files named like that using the built-in Windows 7 search functionality? I did find this question which is very similar, but the answer doesn't work for me; it seems like any special character I put in the query is either ignored or treated as a wildcard, and as a result it matches every single file and directory. Is there perhaps some registry value I can set to make the search-by-filename feature work with special characters?

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  • Problems in Binary Search Tree

    - by user2782324
    This is my first ever trial at implementing the BST, and I am unable to get it done. Please help The problem is that When I delete the node if the node is in the right subtree from the root or if its a right child in the left subtree, then it works fine. But if the node is in the left subtree from root and its any left child, then it does not get deleted. Can someone show me what mistake am I doing?? the markedNode here gets allocated to the parent node of the node to be deleted. the minValueNode here gets allocated to a node whose left value child is the smallest value and it will be used to replace the value to be deleted. package DataStructures; class Node { int value; Node rightNode; Node leftNode; } class BST { Node rootOfTree = null; public void insertintoBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { Node newNode = new Node(); newNode.value = value; rootOfTree = newNode; newNode.rightNode = null; newNode.leftNode = null; } else { while (true) { if (value >= markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.rightNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.leftNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } } } } public void searchBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { System.out.println("Element Not Found"); } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { System.out.println("Element Not Found"); break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { System.out.println("Element Not Found"); break; } } if (value == markedNode.value) { System.out.println("Element Found"); break; } } } } public void deleteFromBST(int value) { Node markedNode = rootOfTree; Node minValueNode = null; if (rootOfTree == null) { System.out.println("Element Not Found"); return; } if (rootOfTree.value == value) { if (rootOfTree.leftNode == null && rootOfTree.rightNode == null) { rootOfTree = null; return; } else if (rootOfTree.leftNode == null ^ rootOfTree.rightNode == null) { if (rootOfTree.rightNode != null) { rootOfTree = rootOfTree.rightNode; return; } else { rootOfTree = rootOfTree.leftNode; return; } } else { minValueNode = rootOfTree.rightNode; if (minValueNode.leftNode == null) { rootOfTree.rightNode.leftNode = rootOfTree.leftNode; rootOfTree = rootOfTree.rightNode; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node rootOfTree.value = minValueNode.leftNode.value; // The value has been swapped if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { break; } else { markedNode = markedNode.rightNode; } } else { System.out.println("Element Not Found"); return; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { break; } else { markedNode = markedNode.leftNode; } } else { System.out.println("Element Not Found"); return; } } } // Parent of the required element found // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { if (markedNode.rightNode.rightNode == null && markedNode.rightNode.leftNode == null) { markedNode.rightNode = null; return; } else if (markedNode.rightNode.rightNode == null ^ markedNode.rightNode.leftNode == null) { if (markedNode.rightNode.rightNode != null) { markedNode.rightNode = markedNode.rightNode.rightNode; return; } else { markedNode.rightNode = markedNode.rightNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.rightNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { if (markedNode.leftNode.rightNode == null && markedNode.leftNode.leftNode == null) { markedNode.leftNode = null; return; } else if (markedNode.leftNode.rightNode == null ^ markedNode.leftNode.leftNode == null) { if (markedNode.leftNode.rightNode != null) { markedNode.leftNode = markedNode.leftNode.rightNode; return; } else { markedNode.leftNode = markedNode.leftNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.leftNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// } } } } } } public class BSTImplementation { public static void main(String[] args) { BST newBst = new BST(); newBst.insertintoBST(19); newBst.insertintoBST(13); newBst.insertintoBST(10); newBst.insertintoBST(20); newBst.insertintoBST(5); newBst.insertintoBST(23); newBst.insertintoBST(28); newBst.insertintoBST(16); newBst.insertintoBST(27); newBst.insertintoBST(9); newBst.insertintoBST(4); newBst.insertintoBST(22); newBst.insertintoBST(17); newBst.insertintoBST(30); newBst.insertintoBST(40); newBst.deleteFromBST(5); newBst.deleteFromBST(4); newBst.deleteFromBST(9); newBst.deleteFromBST(10); newBst.deleteFromBST(13); newBst.deleteFromBST(16); newBst.deleteFromBST(17); newBst.searchBST(5); newBst.searchBST(4); newBst.searchBST(9); newBst.searchBST(10); newBst.searchBST(13); newBst.searchBST(16); newBst.searchBST(17); System.out.println(); newBst.deleteFromBST(20); newBst.deleteFromBST(23); newBst.deleteFromBST(27); newBst.deleteFromBST(28); newBst.deleteFromBST(30); newBst.deleteFromBST(40); newBst.searchBST(20); newBst.searchBST(23); newBst.searchBST(27); newBst.searchBST(28); newBst.searchBST(30); newBst.searchBST(40); } }

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  • Search and Highlight search text in items in the Listview in WPF

    - by kiran-k
    Hi, I am using MVVM to show the database records in a gridview (ListView view). i have a textbox where we can enter the text to be searched in the results listed in the gridview. i tried many ways to highlight the search text (Not the entire row only the text matches in the record) in the records displayed in the list view but unable to highlight. i am able to find the starting and ending indexes. i tried to created rectangles using those indexes on the text block but unable to highlight. Can anyone have solution for this. Thanks in advance.

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  • Quick guide to Oracle IRM 11g: Creating your first sealed document

    - by Simon Thorpe
    Quick guide to Oracle IRM 11g indexThe previous articles in this guide have detailed how to install, configure and secure your Oracle IRM 11g service. This article walks you through the process of now creating your first context and securing a document against it. I should mention that it would be worth reviewing the following to ensure your installation is ready for that all important first document. Ensure you have correctly configured the keystore for the IRM wrapper keys. If this is not correctly configured, creating the context below will fail. Make sure the IRM server URL correctly resolves and uses the right protocol (HTTP or HTTPS) ContentsCreate the first contextInstall the Oracle IRM Desktop Seal your first document Create the first contextIn Oracle 11g there is a built in classification and rights system called the "standard rights model" which is based on 10 years of customer use cases and innovation. It is a system which enables IRM to scale massively whilst retaining the ability to balance security and usability and also separate duties by allowing contacts in the business to own classifications. The final article in this guide goes into detail on this inbuilt classification model, but for the purposes of this current article all we need to do is create at least one context to test our system out.With a new IRM server there are a set of predefined context templates and roles which again are setup in a way which reflects the most common use we've learned from our customers. We will use these out of the box configurations as they are to create the first context against which we will seal some content.First login to your Oracle IRM Management Website located at https://irm.company.com/irm_rights/. Currently the system is only configured to use the built in LDAP for users, so use the only account we have at the moment, which by default is weblogic. Once logged in switch to the Contexts tab. Click on the New Context icon () in the menu bar on the left. In the resulting dialog select the Standard context template and enter in a name for the context. Then just hit finish, the weblogic account will automatically be made the manager. You'll now see your brand new context ready for users to be assigned. Now click on the Assign Role icon () in the menu bar and in the resulting dialog search for your only user account, weblogic, and add to the list on the right. Now select a role for this user. Because we need to create a document with this user we must select contributor, as this is the only role which allows for the ability to seal. Finally hit next and then finish. We now have a context with a user that has the rights to create a document. The next step is to configure the IRM Desktop to get these rights from the server. Install the Oracle IRM Desktop Before we can seal a document we need the client software installed. Oracle IRM has a very small, lightweight client called the Oracle IRM Desktop which can be freely downloaded in 27 languages from here. Double click on the installer and click on next... Next again... And finally on install... Very easy. You may get a warning about closing Outlook, Word or another application and most of the time no reboots are required. Once it is installed you will see the IRM Desktop icon running in your tool tray, bottom right of the desktop. Seal your first document Finally the prize is within reach, creating your first sealed document. The server is running, we've got a context ready, a user assigned a role in the context but there is the simple and obvious hoop left to jump through. To seal a document we need to have the users rights cached to the local machine. For this to take place, the IRM Desktop needs to know where the Oracle IRM server is on the network so we can synchronize these rights and then be able to seal a document. The usual way for the IRM Desktop to know about the IRM server is it learns automatically when you open an existing piece of content that someone has sent you... ack. Bit of a chicken or the egg dilemma. The solution is to manually tell the IRM Desktop the location of the IRM Server and then force a synchronization of rights. Right click on the Oracle IRM Desktop icon in the system tray and select Options.... Then switch to the Servers tab in the resulting dialog. There are no servers in the list because you've never opened any content. This list is usually populated automatically but we are going to add a server manually, so click on New.... Into the dialog enter in the full URL to the IRM server. Note that this time you use the path /irm_desktop/ and not /irm_rights/. You can see an example from the image below. Click on the validate button and you'll be asked to authenticate. Enter in your weblogic username and password and also check the Remember my password check box. Click OK and the IRM Desktop will confirm a successful connection to the server. OK all the dialogs and we are ready to Synchronize this users rights to the desktop. Right click once more on the Oracle IRM Desktop icon in the system tray. Now the Synchronize menu option is available. Select this and the IRM Desktop will now talk to the IRM server, authenticate using your weblogic account and get your rights to the context we created. Because this is the first time this users has communicated with the IRM server the IRM Desktop presents a privacy policy dialog. This is a chance for the business to ask users to agree to any policy about the use of IRM before opening secured documents. In our guide we've not bothered to setup this URL so just click on the check box and hit Accept. The IRM Desktop will then talk to the server, get your rights and display a success dialog. Lets protect a documentNow we are ready to seal a piece of content. In my guide i'm going to protect a Microsoft Word document. This mean's I have to have copy of Office installed, in this guide i'm using Microsoft Office 2007. You could also seal a PDF document, you'll need to download and install Adobe Acrobat Reader. A very simple test could be to seal a GIF/JPG/PNG or piece of HTML because this is rendered using Internet Explorer. But as I say, i'm going to protect a Word document. The following example demonstrates choosing a file in Windows Explorer, there are many ways to seal a file and you can watch a few in this video.Open a copy of Windows Explorer and locate the file you wish to seal. Right click on the document and select Seal To -> Context You are now presented with the Select Context dialog. You'll now have a sealed copy of the document sat in the same location. Double click on this document and it will open, again using the credentials you've already provided. That is it, now you just need to add more users, more documents, more classifications and start exploring the different roles and experiment with different offline periods etc. You may wish to setup the server against an existing LDAP or Active Directory environment instead of using the built in WebLogic LDAP store. You can read how to use your corporate directory here. But before we finish this guide, there is one more article and arguably the most important article of all. Next I discuss the all important decision making surrounding the actually implementation of Oracle IRM inside your business. Who has rights to what? How do you map contexts to your existing business practices? It is the next article which actually ensures you deploy a successful IRM solution by looking at the business and understanding how they use your sensitive information and then configuring Oracle IRM to reflect their use.

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  • Trying to style the first tbody different than others without introducing another class.

    - by mwiik
    I have a table with multiple tbody's, each of which has a classed row, and I want it so that the classed row in the first tbody has style differences, but am unable to get tbody:first-child to work in any browser. Perhaps I am missing something, or maybe there is a workaround. Ideally, I would like to provide the programmers with a single tbody section they can use as a template, but will otherwise have to add a class to the first tbody, making for an extra test in the programming. The html is straightforward: <tbody class="subGroup"> <tr class="subGroupHeader"> <th colspan="8">All Grades: Special Education</th> <td class="grid" colspan="2"><!-- contains AMO line --></td> <td><!-- right 100 --></td> </tr> <tr>...</tr> <!-- several more rows of data --> </tbody> There are several tbody's per table. I want to style the th and td's within tr.subGroupHeader in the very first tbody differently than the rest. Just to illustrate, I want to add a border-top to the tr.subGroupHeader cells. The tr.subGroupHeader will be styled with a border-top, such as: table.databargraph.continued tr.subGroupHeader th, table.databargraph.continued tr.subGroupHeader td { border-top: 6px solid red; } For the first tbody, I am trying: table.databargraph.continued tbody:first-child tr.subGroupHeader th { border-top: 6px solid blue ; } However, this doesn't seem to work in any browser (I've tested in Safari, Opera, Firefox, and PrinceXML, all on my Mac) Curiously, the usually excellent Xyle Scope tool indicates that the blue border should be taking precedence, though it obviously is not. See the screenshot at http://s3.amazonaws.com/ember/kUD8DHrz06xowTBK3qpB2biPJrLWTZCP_o.png This screenshot shows (top left) the American Indian th is selected, and (bottom right), shows (via black instead of gray text for the css declaration), that, indeed, the blue border should be given precedence. Yet the border is red. I may be missing something fundamental, like pseudo-classes not working for tbodys at all... This really only needs to work in PrinceXML, and maybe Safari so I can see what I'm doing with webkit-based css tools. Note I did try a selector like tr.subGroupHeader:first-child, but such tr's apparently consider the tbody the parent (as I would suspect), thus made every border blue. Thanks...

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  • Fast file search algorithm for IP addresses

    - by Dave Jarvis
    Question What is the fastest way to find if an IP address exists in a file that contains IP addresses sorted as: 219.93.88.62 219.94.181.87 219.94.193.96 220.1.72.201 220.110.162.50 220.126.52.187 220.126.52.247 Constraints No database (e.g., MySQL, PostgreSQL, Oracle, etc.). Infrequent pre-processing is allowed (see possibilities section) Would be nice not to have to load the file each query (131Kb) Uses under 5 megabytes of disk space File Details One IP address per line 9500+ lines Possible Solutions Create a directory hierarchy (radix tree?) then use is_dir() (sadly, this uses 87 megabytes)

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  • Alpha Beta Search

    - by Becky
    I'm making a version of Martian Chess in java with AI and so far I THINK my move searching is semi-working, it seems to work alright for some depths but if I use a depth of 3 it returns a move for the opposite side...now the game is a bit weird because when a piece crosses half of the board, it becomes property of the other player so I think this is part of the problem. I'd be really greatful if someone could look over my code and point out any errors you think are there! (pls note that my evaluation function isn't nearly complete lol) MoveSearch.java public class MoveSearch { private Evaluation evaluate = new Evaluation(); private int blackPlayerScore, whitePlayerScore; public MoveContent bestMove; public MoveSearch(int blackScore, int whiteScore) { blackPlayerScore = blackScore; whitePlayerScore = whiteScore; } private Vector<Position> EvaluateMoves(Board board) { Vector<Position> positions = new Vector<Position>(); for (int i = 0; i < 32; i++) { Piece piece = null; if (!board.chessBoard[i].square.isEmpty()) { // store the piece piece = board.chessBoard[i].square.firstElement(); } // skip empty squares if (piece == null) { continue; } // skip the other players pieces if (piece.pieceColour != board.whosMove) { continue; } // generate valid moves for the piece PieceValidMoves validMoves = new PieceValidMoves(board.chessBoard, i, board.whosMove); validMoves.generateMoves(); // for each valid move for (int j = 0; j < piece.validMoves.size(); j++) { // store it as a position Position move = new Position(); move.startPosition = i; move.endPosition = piece.validMoves.elementAt(j); Piece pieceAttacked = null; if (!board.chessBoard[move.endPosition].square.isEmpty()) { // if the end position is not empty, store the attacked piece pieceAttacked = board.chessBoard[move.endPosition].square.firstElement(); } // if a piece is attacked if (pieceAttacked != null) { // append its value to the move score move.score += pieceAttacked.pieceValue; // if the moving pieces value is less than the value of the attacked piece if (piece.pieceValue < pieceAttacked.pieceValue) { // score extra points move.score += pieceAttacked.pieceValue - piece.pieceValue; } } // add the move to the set of positions positions.add(move); } } return positions; } // EvaluateMoves() private int SideToMoveScore(int score, PieceColour colour) { if (colour == PieceColour.Black){ return -score; } else { return score; } } public int AlphaBeta(Board board, int depth, int alpha, int beta) { //int best = -9999; // if the depth is 0, return the score of the current board if (depth <= 0) { board.printBoard(); System.out.println("Score: " + evaluate.EvaluateBoardScore(board)); System.out.println(""); int boardScore = evaluate.EvaluateBoardScore(board); return SideToMoveScore(boardScore, board.whosMove); } // fill the positions with valid moves Vector<Position> positions = EvaluateMoves(board); // if there are no available positions if (positions.size() == 0) { // and its blacks move if (board.whosMove == PieceColour.Black) { if (blackPlayerScore > whitePlayerScore) { // and they are winning, return a high number return 9999; } else if (whitePlayerScore == blackPlayerScore) { // if its a draw, lower number return 500; } else { // if they are losing, return a very low number return -9999; } } if (board.whosMove == PieceColour.White) { if (whitePlayerScore > blackPlayerScore) { return 9999; } else if (blackPlayerScore == whitePlayerScore) { return 500; } else { return -9999; } } } // for each position for (int i = 0; i < positions.size(); i++) { // store the position Position move = positions.elementAt(i); // temporarily copy the board Board temp = board.copyBoard(board); // make the move temp.makeMove(move.startPosition, move.endPosition); for (int x = 0; x < 32; x++) { if (!temp.chessBoard[x].square.isEmpty()) { PieceValidMoves validMoves = new PieceValidMoves(temp.chessBoard, x, temp.whosMove); validMoves.generateMoves(); } } // repeat the process recursively, decrementing the depth int val = -AlphaBeta(temp, depth - 1, -beta, -alpha); // if the value returned is better than the current best score, replace it if (val >= beta) { // beta cut-off return beta; } if (val > alpha) { alpha = val; bestMove = new MoveContent(alpha, move.startPosition, move.endPosition); } } // return the best score return alpha; } // AlphaBeta() } This is the makeMove method public void makeMove(int startPosition, int endPosition) { // quick reference to selected piece and attacked piece Piece selectedPiece = null; if (!(chessBoard[startPosition].square.isEmpty())) { selectedPiece = chessBoard[startPosition].square.firstElement(); } Piece attackedPiece = null; if (!(chessBoard[endPosition].square.isEmpty())) { attackedPiece = chessBoard[endPosition].square.firstElement(); } // if a piece is taken, amend score if (!(chessBoard[endPosition].square.isEmpty()) && attackedPiece != null) { if (attackedPiece.pieceColour == PieceColour.White) { blackScore = blackScore + attackedPiece.pieceValue; } if (attackedPiece.pieceColour == PieceColour.Black) { whiteScore = whiteScore + attackedPiece.pieceValue; } } // actually move the piece chessBoard[endPosition].square.removeAllElements(); chessBoard[endPosition].addPieceToSquare(selectedPiece); chessBoard[startPosition].square.removeAllElements(); // changing piece colour based on position if (endPosition > 15) { selectedPiece.pieceColour = PieceColour.White; } if (endPosition <= 15) { selectedPiece.pieceColour = PieceColour.Black; } //change to other player if (whosMove == PieceColour.Black) whosMove = PieceColour.White; else if (whosMove == PieceColour.White) whosMove = PieceColour.Black; } // makeMove()

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  • Binary Search Tree in Java

    - by John R
    I want to make a generic BST, that can be made up of any data type, but i'm not sure how I could add things to the tree, if my BST is generic. All of my needed code is below. I want my BST made up of Locations, and sorted by the x variable. Any help is appreciated. Major thanks for looking. public void add(E element) { if (root == null) root = element; if (element < root) add(element, root.leftChild); if (element > root) add(element, root.rightChild); else System.out.println("Element Already Exists"); } private void add(E element, E currLoc) { if (currLoc == null) currLoc = element; if (element < root) add(element, currLoc.leftChild); if (element > root) add(element, currLoc.rightChild); else System.out.println("Element Already Exists); } Other Code public class BinaryNode<E> { E BinaryNode; BinaryNode nextBinaryNode; BinaryNode prevBinaryNode; public BinaryNode() { BinaryNode = null; nextBinaryNode = null; prevBinaryNode = null; } } public class Location<AnyType> extends BinaryNode { String name; int x,y; public Location() { name = null; x = 0; y = 0; } public Location(String newName, int xCord, int yCord) { name = newName; x = xCord; y = yCord; } public int equals(Location otherScene) { return name.compareToIgnoreCase(otherScene.name); } }

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  • jqGrid search/filter data api

    - by McLovin
    I've already read all available documentation and I cannot find a solution. I have a calendar outside of the grid which on click returns a date. All I need to do is filter my jqGrid based on that date. Can someone point me to the correct API method? Thanks!

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  • Anyone has implemented SMA* search algorithm?

    - by Endy
    I find the algorithm description in AIMA (Artificial Intelligence: A Modern Approach) is not correct at all. What does 'necessary' mean? What is the memory limit? The queue size or processed nodes? What if the current node has no children at all? I am wondering if this algorithm itself is correct or not. Because I searched the Internet and nobody has implemented it yet. Thanks.

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  • Sunspot / Solr full text search - how to index Rails associations

    - by Sam
    Is it possible to index through an association with Sunspot? For example, if a Customer has_many Contacts, I want a 'searchable' block on my Customer model that indexes the Contact#first_name and Contact#last_name columns for use in searches on Customer. acts_as_solr has an :include option for this. I've simply been combining the associated column names into a text field on Customer like shown below, but this doesn't seem very flexible. searchable do text :organization_name, :default_boost => 2 text :billing_address1, :default_boost => 2 text :contact_names do contacts.map { |contact| contact.to_s } end Any suggestions?

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  • Best practice No1: inline search layout across browsers

    - by Sixfoot Studio
    Ok, I have managed to fix my version of this example using a multitude of hacks and I would like to see how others would tackle this problem making this cross-browser compatible without too many hacks. <div class="searchDiv"> <img src="Images/left.gif" class="left" height="19" width="3" /> <input id="TextBox" type="text" class="searchField" /> <img src="Images/right.gif" height="19"width="3" class="right" /> <a href="" class="submit">Submit</a> <img src="Images/box-arrow.gif" class="linkArrow" width="8" height="14" /> </div> I am using a Transitional DTD in my example. Based on the everyone else's CSS examples, comments and answers I will make the final vote. I'd love to see more of these scenarios come up so that people have a library of "best practice" methods which they can find on SO. Good luck

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  • shortest directed odd cycle

    - by gleb-pendler
    6.1.4 Describe an algorithm based on breadth-first search for finding a shortest odd cycle in a graph. 6.3.5 Describe an algorithm based on directed breadth-first search for finding a shortest directed odd cycle in a digraph. what is most importent is that it must be a directed graph not necessary bfs but must be the shortest directed odd cycle!!! Question was taken from "Graph Theory" by J.A. Bondy and U.S.R. Murty thanks in advance!!!

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  • Wordpress, PodCMS and Search

    - by Vian Esterhuizen
    Hey guys, I have a WordPress site for a client. He owns a video store, and I made a site for him to update the list of movies, usually just the "new this week" movies. The Pod has a field where you insert the release date. 2010-04-20 Then there is a Pod page/template combo that calls the movies with a certain release date like this: $date = pods_url_variable('last'); He then just creates a blank WP page with the slug 2010-04-20 So when you open that page, the Pod page/template reads that slug and renders a list of the appropriate movies. My problem: I need these to be searchable. Is this possible. I'm also open to suggestions on other ways to go about making this site work. I need it to be as simple as that. Uploads some movies and creates a new page. Then the rest is done automatically. Please and thank you guys

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  • Full-text search on App Engine with Whoosh

    - by Martin
    I need to do full text searching with Google App Engine. I found the project Whoosh and it works really well, as long as I use the App Engine Development Environement... When I upload my application to App Engine, I am getting the following TraceBack. For my tests, I am using the example application provided in this project. Any idea of what I am doing wrong? <type 'exceptions.ImportError'>: cannot import name loads Traceback (most recent call last): File "/base/data/home/apps/myapp/1.334374478538362709/hello.py", line 6, in <module> from whoosh import store File "/base/data/home/apps/myapp/1.334374478538362709/whoosh/__init__.py", line 17, in <module> from whoosh.index import open_dir, create_in File "/base/data/home/apps/myapp/1.334374478538362709/whoosh/index.py", line 31, in <module> from whoosh import fields, store File "/base/data/home/apps/myapp/1.334374478538362709/whoosh/store.py", line 27, in <module> from whoosh import tables File "/base/data/home/apps/myapp/1.334374478538362709/whoosh/tables.py", line 43, in <module> from marshal import loads Here is the import I have in my Python file. # Whoosh ---------------------------------------------------------------------- sys.path.append(os.path.abspath(os.path.join(os.path.dirname(__file__), '..', 'utils'))) from whoosh.fields import Schema, STORED, ID, KEYWORD, TEXT from whoosh.index import getdatastoreindex from whoosh.qparser import QueryParser, MultifieldParser Thank you in advance for your help!

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  • Sphinx search distributed index tuning

    - by Andriy Bohdan
    I'm deciding how to split 3 large sphinx indexes between 3 servers. Each of the 3 indexes is searched separately. What's more effective: to host each index on separate machine Example machine1 - index1 machine2 - index2 machine3 - index3 or to split each index into 3 parts and host each part of the same index on separate machine. Example machine1 - index1_chunk1, index2_chunk1, index3_chunk1 machine2 - index1_chunk2, index2_chunk2, index3_chunk2 machine3 - index1_chunk3, index2_chunk3, index3_chunk3 ?

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  • Inverted index in a search engine

    - by Ayman
    Hello there, I'm trying to write some code to make a small application for searching text from files. Files should be crawled, and I need to put an inverted index to boost searches. My problem is that I kind of have ideas about how the parser would be, I'm willing to implement the AND, NOT, OR in the query. Whereas, I couldn't figure out how my index should be... I have never created an inverted index so if any body could suggest a feasable way to do it I would be very grateful... I do know in theory how it works but my problem is I absolutely have no idea to make happen in MySql I need to give keywords being indexed a weight too... Thank you so much.

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  • multiline perl search and replace (one-liner)

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with perl. I would prefer to allow for any occurences of white space and/or new lines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> </div>

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  • C++ string array binary search

    - by Jose Vega
    string Haystack[] = { "Alabama", "Alaska", "American Samoa", "Arizona", "Arkansas", "California", "Colorado", "Connecticut", "Delaware", "District of Columbia", "Florida", "Georgia", "Guam", "Hawaii", "Idaho", "Illinois", "Indiana", "Iowa", "Kansas", "Kentucky", "Louisiana", "Maine", "Maryland", "Massachusetts", "Michigan", "Minnesota", "Mississippi", "Missouri", "Montana", "Nebraska", "Nevada", "New Hampshire", "New Jersey", "New Mexico", "New York", "North Carolina", "North Dakota", "Northern Mariana Islands", "Ohio", "Oklahoma", "Oregon", "Pennsylvania", "Puerto Rico", "Rhode Island", "South Carolina", "South Dakota", "Tennessee", "Texas", "US Virgin Islands", "Utah", "Vermont", "Virginia", "Washington", "West Virginia", "Wisconsin", "Wyoming"}; string Needle = "Virginia"; if(std::binary_search(Haystack, Haystack+56, Needle)) cout<<"Found"; If I also wanted to find the location of the needle in the string array, is there an "easy" way to find out?

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