Search Results

Search found 2177 results on 88 pages for 'children'.

Page 45/88 | < Previous Page | 41 42 43 44 45 46 47 48 49 50 51 52  | Next Page >

  • Saving JQuery Draggable Sitemap Values Correctly

    - by mdolon
    I am trying to implement Boagworld's Sitemap tutorial, however I am running into difficulty trying to correctly save the child/parent relationships. The HTML is as follows, however populated with other items as well: <input type="hidden" name="sitemap-order" id="sitemap-order" value="" /> <ul id=”sitemap”> <li id="1"> <dl> <dt><a href=”#”>expand/collapse</a> <a href=”#”>Page Title</a></dt> <dd>Text Page</dd> <dd>Published</dd> <dd><a href=”#”>delete</a></dd> </dl> <ul><!–child pages–></ul> </li> </ul> And here is the JQuery code: $('#sitemap li').prepend('<div class="dropzone"></div>'); $('#sitemap li').draggable({ handle: ' > dl', opacity: .8, addClasses: false, helper: 'clone', zIndex: 100 }); var order = ""; $('#sitemap dl, #sitemap .dropzone').droppable({ accept: '#sitemap li', tolerance: 'pointer', drop: function(e, ui) { var li = $(this).parent(); var child = !$(this).hasClass('dropzone'); //If this is our first child, we'll need a ul to drop into. if (child && li.children('ul').length == 0) { li.append('<ul/>'); } //ui.draggable is our reference to the item that's been dragged. if (child) { li.children('ul').append(ui.draggable); }else { li.before(ui.draggable); } //reset our background colours. li.find('dl,.dropzone').css({ backgroundColor: '', backgroundColor: '' }); li.find('.dropzone').css({ height: '8px', margin: '0' }); // THE PROBLEM: var parentid = $(this).parent().attr('id'); menuorder += ui.draggable.attr('id')+'=>'+parentid+','; $("#sitemap-order").val(order); }, over: function() { $(this).filter('dl').css({ backgroundColor: '#ccc' }); $(this).filter('.dropzone').css({ backgroundColor: '#aaa', height: '30px', margin: '5px 0'}); }, out: function() { $(this).filter('dl').css({ backgroundColor: '' }); $(this).filter('.dropzone').css({ backgroundColor: '', height: '8px', margin: '0' }); } }); When moving items into the top-level (without parents), the parentid value I get is of the first list item (the parent container), so I can never remove the parent value and have a top-level item. Is there a no-brainer answer that I'm just not seeing right now? Any help is appreciated.

    Read the article

  • Ruby (and Rails) nested module syntax

    - by brad
    I'm wondering what the difference is between the following two modules # First Example module Parent module Child end end and # Second Example module Parent::Child end Using the 2nd method, it appears as though the Parent module must be previously defined, otherwise I get an 'uninitialized constant' error Given this, what is the preferred way of defining modules such as this and then adding nested children with regards to syntax and file structure (ie. folders etc). Reference to a Rails way would be greatly appreciated. Are these two examples for all intents and purposes equivalent?

    Read the article

  • Is there a way that I can register an event, on a control that inherits from Canvas, that is fired w

    - by Justin
    I am trying to add horizontal and vertical "Position" attached properties to my canvas control that allow me to set a control's position (e.g. Horizontal: Left, Right, Center). I need a children size changed event handler so that I can adjust the position of an element whose size is changed if it's horizontal or vertical position is Center. Is there a way that I could do this?

    Read the article

  • getting attributes of href using libxml

    - by iSight
    Hi, I have xml file nameed Hello as under with starting node as under: /Hello xmlns:xsi: = "some text" xmlns:xsd = "some text" version="1.0"/ I tried to get the first and second attributes of node named Hello, using xmlAttr *attr = nodePtr-properties;//nurrent node is Hello while ( attr ) { NSLog(@"\n Attribute name:%s value:%s",attr->name,attr->children->content); attr = attr->next; }; But, i could not get the first and second attributes, instead it only returns third attribute. How can i get the first and second attributes

    Read the article

  • Working with a figure file in Matlab

    - by 49er
    I've got a .fig file showing the intensities of 2d data. How do I obtain the values when I load it in Matlab? Is it even possible? When I try playing with the children properties I am able to obtain only the size of my x and y vectors, not the values themselves which I don't know how to extract.

    Read the article

  • How can I trigger a transition effect when a child control is added or removed in flex?

    - by Jason Towne
    I've got a custom component that has children components dynamically added and removed to it depending on what button the user clicks. What I would like to do is trigger a transition effect that moves the child component onto the stage when it's added and then moves it off when it's removed. Does anyone have a good example on how to accomplish this? Edit: I figured it out and left my solution below. I hope it helps someone else!

    Read the article

  • Eclipse JFace TreeViewer level auto expansion doesn't work

    - by tamm0r
    According to the Eclipse documentation TreeViewer.setAutoExpandLevel(3) means that top-level elements are expanded, and their children, but not grandchildren. I used that in my code, but after setting the input the tree is not auto-expanded, neither on OS X nor on Linux. Expanding the tree manually (via mouse) works flawlessly. Am I missing anything?

    Read the article

  • Handling inheritance with overriding efficiently

    - by Fyodor Soikin
    I have the following two data structures. First, a list of properties applied to object triples: Object1 Object2 Object3 Property Value O1 O2 O3 P1 "abc" O1 O2 O3 P2 "xyz" O1 O3 O4 P1 "123" O2 O4 O5 P1 "098" Second, an inheritance tree: O1 O2 O4 O3 O5 Or viewed as a relation: Object Parent O2 O1 O4 O2 O3 O1 O5 O3 O1 null The semantics of this being that O2 inherits properties from O1; O4 - from O2 and O1; O3 - from O1; and O5 - from O3 and O1, in that order of precedence. NOTE 1: I have an efficient way to select all children or all parents of a given object. This is currently implemented with left and right indexes, but hierarchyid could also work. This does not seem important right now. NOTE 2: I have tiggers in place that make sure that the "Object" column always contains all possible objects, even when they do not really have to be there (i.e. have no parent or children defined). This makes it possible to use inner joins rather than severely less effiecient outer joins. The objective is: Given a pair of (Property, Value), return all object triples that have that property with that value either defined explicitly or inherited from a parent. NOTE 1: An object triple (X,Y,Z) is considered a "parent" of triple (A,B,C) when it is true that either X = A or X is a parent of A, and the same is true for (Y,B) and (Z,C). NOTE 2: A property defined on a closer parent "overrides" the same property defined on a more distant parent. NOTE 3: When (A,B,C) has two parents - (X1,Y1,Z1) and (X2,Y2,Z2), then (X1,Y1,Z1) is considered a "closer" parent when: (a) X2 is a parent of X1, or (b) X2 = X1 and Y2 is a parent of Y1, or (c) X2 = X1 and Y2 = Y1 and Z2 is a parent of Z1 In other words, the "closeness" in ancestry for triples is defined based on the first components of the triples first, then on the second components, then on the third components. This rule establishes an unambigous partial order for triples in terms of ancestry. For example, given the pair of (P1, "abc"), the result set of triples will be: O1, O2, O3 -- Defined explicitly O1, O2, O5 -- Because O5 inherits from O3 O1, O4, O3 -- Because O4 inherits from O2 O1, O4, O5 -- Because O4 inherits from O2 and O5 inherits from O3 O2, O2, O3 -- Because O2 inherits from O1 O2, O2, O5 -- Because O2 inherits from O1 and O5 inherits from O3 O2, O4, O3 -- Because O2 inherits from O1 and O4 inherits from O2 O3, O2, O3 -- Because O3 inherits from O1 O3, O2, O5 -- Because O3 inherits from O1 and O5 inherits from O3 O3, O4, O3 -- Because O3 inherits from O1 and O4 inherits from O2 O3, O4, O5 -- Because O3 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 O4, O2, O3 -- Because O4 inherits from O1 O4, O2, O5 -- Because O4 inherits from O1 and O5 inherits from O3 O4, O4, O3 -- Because O4 inherits from O1 and O4 inherits from O2 O5, O2, O3 -- Because O5 inherits from O1 O5, O2, O5 -- Because O5 inherits from O1 and O5 inherits from O3 O5, O4, O3 -- Because O5 inherits from O1 and O4 inherits from O2 O5, O4, O5 -- Because O5 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 Note that the triple (O2, O4, O5) is absent from this list. This is because property P1 is defined explicitly for the triple (O2, O4, O5) and this prevents that triple from inheriting that property from (O1, O2, O3). Also note that the triple (O4, O4, O5) is also absent. This is because that triple inherits its value of P1="098" from (O2, O4, O5), because it is a closer parent than (O1, O2, O3). The straightforward way to do it is the following. First, for every triple that a property is defined on, select all possible child triples: select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value from TriplesAndProperties tp -- Select corresponding objects of the triple inner join Objects as Objects1 on Objects1.Id = tp.O1 inner join Objects as Objects2 on Objects2.Id = tp.O2 inner join Objects as Objects3 on Objects3.Id = tp.O3 -- Then add all possible children of all those objects inner join Objects as Children1 on Objects1.Id [isparentof] Children1.Id inner join Objects as Children2 on Objects2.Id [isparentof] Children2.Id inner join Objects as Children3 on Objects3.Id [isparentof] Children3.Id But this is not the whole story: if some triple inherits the same property from several parents, this query will yield conflicting results. Therefore, second step is to select just one of those conflicting results: select * from ( select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value, row_number() over( partition by Children1.Id, Children2.Id, Children3.Id, tp.Property order by Objects1.[depthInTheTree] descending, Objects2.[depthInTheTree] descending, Objects3.[depthInTheTree] descending ) as InheritancePriority from ... (see above) ) where InheritancePriority = 1 The window function row_number() over( ... ) does the following: for every unique combination of objects triple and property, it sorts all values by the ancestral distance from the triple to the parents that the value is inherited from, and then I only select the very first of the resulting list of values. A similar effect can be achieved with a GROUP BY and ORDER BY statements, but I just find the window function semantically cleaner (the execution plans they yield are identical). The point is, I need to select the closest of contributing ancestors, and for that I need to group and then sort within the group. And finally, now I can simply filter the result set by Property and Value. This scheme works. Very reliably and predictably. It has proven to be very powerful for the business task it implements. The only trouble is, it is awfuly slow. One might point out the join of seven tables might be slowing things down, but that is actually not the bottleneck. According to the actual execution plan I'm getting from the SQL Management Studio (as well as SQL Profiler), the bottleneck is the sorting. The problem is, in order to satisfy my window function, the server has to sort by Children1.Id, Children2.Id, Children3.Id, tp.Property, Parents1.[depthInTheTree] descending, Parents2.[depthInTheTree] descending, Parents3.[depthInTheTree] descending, and there can be no indexes it can use, because the values come from a cross join of several tables. EDIT: Per Michael Buen's suggestion (thank you, Michael), I have posted the whole puzzle to sqlfiddle here. One can see in the execution plan that the Sort operation accounts for 32% of the whole query, and that is going to grow with the number of total rows, because all the other operations use indexes. Usually in such cases I would use an indexed view, but not in this case, because indexed views cannot contain self-joins, of which there are six. The only way that I can think of so far is to create six copies of the Objects table and then use them for the joins, thus enabling an indexed view. Did the time come that I shall be reduced to that kind of hacks? The despair sets in.

    Read the article

  • Complex movement within animation

    - by Irwin
    I've this application, where two children are playing catch. One throws and the other catches. While I can show a ball object moving between two stationary objects, how do I show the objects "releasing" and "catching" the ball, in a way that is close to lifelike? EDIT: The movement of the hands in this game: http://www.acreativedesktop.com/animation-game-slaphands.html is what I would like to replicate. Any tips on how to do that?

    Read the article

  • What is wrong in the jquery code?

    - by phpBOY
    I have been struggling in fixing this code, wonder what is wrong at all... var tips = "<p class="adobe-reader-download">Most computers will open PDF documents automatically, but you may need to download <a title='Link to Adobe website-opens in a new window'"; tips +=" href='http://www.adobe.com/products/acrobat/readstep2.html' target='_blank'>Adobe Reader</a>.</p>"; if($("div#maincontent a[href*='.pdf']").length>0){ $("div#maincontent").children(":last-child").after(tip);

    Read the article

  • how to make sub-muens line up below their parents in horizontal navbars?

    - by Joel
    Hi folks. I'm just putting together a simple nav bar using something similar to this tutorial: http://www.cssnewbie.com/horizontal-dropdown-menus/ The thing is, that I'd like to have the children lists first item to line up directly below the parent. Right now, they just go wherever I float them. Is there a way to do this without absolute positioning? I'd like to achieve something similar to what these guys have in their top nav bar: http://michaelfranti.com/

    Read the article

  • C++ linked list based tree structure. Sanely move nodes between lists.

    - by krunk
    The requirements: Each Node in the list must contain a reference to its previous sibling Each Node in the list must contain a reference to its next sibling Each Node may have a list of child nodes Each child Node must have a reference to its parent node Basically what we have is a tree structure of arbitrary depth and length. Something like: -root(NULL) --Node1 ----ChildNode1 ------ChildOfChild --------AnotherChild ----ChildNode2 --Node2 ----ChildNode1 ------ChildOfChild ----ChildNode2 ------ChildOfChild --Node3 ----ChildNode1 ----ChildNode2 Given any individual node, you need to be able to either traverse its siblings. the children, or up the tree to the root node. A Node ends up looking something like this: class Node { Node* previoius; Node* next; Node* child; Node* parent; } I have a container class that stores these and provides STL iterators. It performs your typical linked list accessors. So insertAfter looks like: void insertAfter(Node* after, Node* newNode) { Node* next = after->next; after->next = newNode; newNode->previous = after; next->previous = newNode; newNode->next = next; newNode->parent = after->parent; } That's the setup, now for the question. How would one move a node (and its children etc) to another list without leaving the previous list dangling? For example, if Node* myNode exists in ListOne and I want to append it to listTwo. Using pointers, listOne is left with a hole in its list since the next and previous pointers are changed. One solution is pass by value of the appended Node. So our insertAfter method would become: void insertAfter(Node* after, Node newNode); This seems like an awkward syntax. Another option is doing the copying internally, so you'd have: void insertAfter(Node* after, const Node* newNode) { Node *new_node = new Node(*newNode); Node* next = after->next; after->next = new_node; new_node->previous = after; next->previous = new_node; new_node->next = next; new_node->parent = after->parent; } Finally, you might create a moveNode method for moving and prevent raw insertion or appending of a node that already has been assigned siblings and parents. // default pointer value is 0 in constructor and a operator bool(..) // is defined for the Node bool isInList(const Node* node) const { return (node->previous || node->next || node->parent); } // then in insertAfter and friends if(isInList(newNode) // throw some error and bail I thought I'd toss this out there and see what folks came up with.

    Read the article

  • backbone.js - Having multiple instances of the same view

    - by TrueWheel
    I am having problems having multiple instances in of the same view in different div elements. When I try to initialize them only the second of the two elements appear no matter what order I put them in. Here is the code for my view. var BodyShapeView = Backbone.View.extend({ thingiview: null, scene: null, renderer: null, model: null, mouseX: 0, mouseY: 0, events:{ 'click button#front' : 'front', 'click button#diag' : 'diag', 'click button#in' : 'zoomIn', 'click button#out' : 'zoomOut', 'click button#on' : 'rotateOn', 'click button#off' : 'rotateOff', 'click button#wireframeOn' : 'wireOn', 'click button#wireframeOff' : 'wireOff', 'click button#distance' : 'dijkstra' }, initialize: function(name){ _.bindAll(this, 'render', 'animate'); scene = new THREE.Scene(); camera = new THREE.PerspectiveCamera( 15, 400 / 700, 1, 4000 ); camera.position.z = 3; scene.add( camera ); camera.position.y = -5; var ambient = new THREE.AmbientLight( 0x202020 ); scene.add( ambient ); var directionalLight = new THREE.DirectionalLight( 0xffffff, 0.75 ); directionalLight.position.set( 0, 0, 1 ); scene.add( directionalLight ); var pointLight = new THREE.PointLight( 0xffffff, 5, 29 ); pointLight.position.set( 0, -25, 10 ); scene.add( pointLight ); var loader = new THREE.OBJLoader(); loader.load( "img/originalMeanModel.obj", function ( object ) { object.children[0].geometry.computeFaceNormals(); var geometry = object.children[0].geometry; console.log(geometry); THREE.GeometryUtils.center(geometry); geometry.dynamic = true; var material = new THREE.MeshLambertMaterial({color: 0xffffff, shading: THREE.FlatShading, vertexColors: THREE.VertexColors }); mesh = new THREE.Mesh(geometry, material); model = mesh; // model = object; scene.add( model ); } ); // RENDERER renderer = new THREE.WebGLRenderer(); renderer.setSize( 400, 700 ); $(this.el).find('.obj').append( renderer.domElement ); this.animate(); }, Here is how I create the instances var morphableBody = new BodyShapeView({ el: $("#morphable-body") }); var bodyShapeView = new BodyShapeView({ el: $("#mean-body") }); Any help would be really appreciated. Thanks in advance.

    Read the article

  • ExtJS: Add Single Click Action To A Node In A TreePanel

    - by FluidFoundation
    [revised] I'm creating a TreePanel in ExtJs that is loading its children from a JSON file. I'm having trouble adding a click action to the nodes. I'm not sure whether it's added in the script creating the tree, or if its added as a property in the JSON, and if so, what the syntax would be. Any help would be appreciated! Please provide an example if possible.

    Read the article

  • facial comparison software

    - by chris beardmore
    I have images of my children we all do, but I have found a picture of a toddler that bears great resemblance to 1 of my own sons on the internet, is there any software available that I can perform side-by-side comparison with, or maybe software that can give an X-% probability match

    Read the article

  • XML Path needed

    - by user3696029
    I have the following XML file: <?xml version="1.0" encoding="UTF-8"?> <bookstore> <book category="COOKING"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="CHILDREN"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="WEB"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="WEB"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore> I need to write a XML path that returns a book published after 2003, category is children and I just need to display the author and title of the book? What is frustrating is that I have everything in the XPATH that wrote except I am missing the author.

    Read the article

  • proper way to hide dynamic elements with jQuery

    - by GrandVizier
    I have a div element which my code will fill with a dynamic amount of links. Using jquery, I want to hide all the links except the first one. This is what I came up with and it works, I was just wondering if this is the best way to do it: $("#panelContainer").each(function(n) { $(this).children().hide(); $("#panelContainer a:first").show(); });

    Read the article

  • JQuery input elements

    - by codeasp
    I need to get all input elements within a div and then attach event handlers, so that whenever values change it updates a hidden field. Children elements within the div might already contain event handlers, if so the attach should chain it. Any help is much appreciated.

    Read the article

  • Advanced datagrid in flex 3

    - by nimmyliji
    Hi, I have an XML file which is coming from the back end through an HTTP service(Using the perl cgi) and I want to display it in an advanced data grid....as in if I click the parent element the children have to be displayed in the corresponding columns...I'm trying it with my data provider but its not working. Is it possible? Thanks in Advance.

    Read the article

< Previous Page | 41 42 43 44 45 46 47 48 49 50 51 52  | Next Page >