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  • MySQL Rating system (calculating average from two tables).

    - by MussuR
    I have two tables, videos and videos_ratings. The videos table has an int videoid field (and many others but those fields are not important I think) and many records. The videos_ratings table has 3 int fields: videoid, rating, rated_by which has many records (multiple records for each fields from the videos table) but not for all records from the videos table. Currently I have the following mysql query: SELECT `videos`.*, avg(`videos_ratings`.`vote`) FROM `videos`, `videos_ratings` WHERE `videos_ratings`.`videoid` = `videos`.`videoid` GROUP BY `videos_ratings`.`videoid` ORDER BY RAND() LIMIT 0, 12 It selects all the records from table videos that have a rating in table video_ratings and calculates the average correctly. But what I need is to select all records from the videos table, no matter if there is a rating for that record or not. And if there aren't any records in the videos_ratings table for that particular videos record, the average function should show 0. Hope someone could understand what I want... :) Thanks!

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  • MySQL query problem

    - by SaltLake
    I've got MySQL table CREATE TABLE stat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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  • PHP MySQL Insert Data

    - by happyCoding25
    Hello, Im trying to insert data into a table in MySQL. I found/modified some code from w3Schools and still couldn't get it working. Heres what I have so far: <?php $rusername=$_POST['username']; $rname=$_POST['name']; $remail=$_POST['emailadr']; $rpassword=$_POST['pass']; $rconfirmpassword=$_POST['cpass']; if ($rpassword==$rconfirmpassword) { $con = mysql_connect("host","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydbname ", $con); } mysql_query("INSERT INTO members (id, username, password) VALUES ('4', $rusername, $rpassword)"); ?> Did I mistype something? To my understanding "members" is the name of the table. If anyone knows whats wrong I appreciate the help. Thanks

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  • mysql select multiple rows in join

    - by julio
    Hi-- I have a simple mySQL problem-- I have two tables, one is a user's table, and one is a photos table (each user can upload multiple photos). I'd like to write a query to join these tables, so I can pull all photos associated with a user (up to a certain limit). However, when I do something obvious like this: SELECT *.a, *.b FROM user_table a JOIN photos_table b ON a.id = b.userid it returns a.id, a.name, a.email, a.address, b.id, b.userid, b.photo_title, b.location but it only returns a single photo. Is there a way to return something like: a.id, a.name, a.email, a.address, b.id, b.userid, b.photo_title, b.location, b.id2, b.photo_title2, b.location2 etc. . . for a given LIMIT of photos? Thanks for any ideas.

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  • wanted to get all dates in mysql result

    - by PankajK
    I have mysql table called user(id, name, join_on) join on is a date field what I want is to show in each day how many uses has been created I can use group by but it will only give me the dates when users get added like if date 4/12/10 5 users added 4/13/10 2 users added 4/15/10 7 users added here date 4/14/10 is missing and I want listing of all dates in one month. I have one solution for it by creating another table only for adding date and that table will left join my users table on join_on and will give total result but I don't want to do that as for creating that I need to create and add entries in date table please suggest the different approach for doing so. Thank you.

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  • Can't Connect To Local Mysql Using IP Address, but CAN connect from remote server

    - by user1782041
    Here's an interesting one that does not seem to fall into any of the mysql connection issues I've read about or searched for: On an Ubuntu 12.04 box I had some system updates waiting to install, and I took care of that this evening. After the install, I started seeing some errors in my syslog complaining about a particular php script that could no longer connect to the mysql instance on the box. Here is the specific error: PHP Warning: mysql_connect(): Can't connect to MySQL server on '192.168.0.40' (4) Now, the server's IP address is 192.168.0.40, and I've checked to make sure that I have mysql listening on 0.0.0.0 so that I can connect using either "localhost" or "192.168.0.40". Here's where things get odd: From the local machine, if I try the following: mysql -uroot -p -h192.168.0.40 I get this error: ERROR 2003 (HY000): Can't connect to MySQL server on '192.168.0.40' (110) I've checked, and error 110 indicates an OS timeout, and error 2003 is the mysql generic "can't connect" error. This indicates that it is not permissions with the user. However, if I do the same thing from a remote machine (say, from 192.168.0.30), I log right in with no problems. Futher, other scripts on the local machine that connect to mysql using "localhost" for the host rather than "192.168.0.40" connect with no problems. Also, I can connect via the mysql socket with no problems both from the command line and php scripts. So, this feels like a networking issue of some kind on the local box, but there are no iptables rules on this box (it is firewalled externally) and I can't figure out what else may be causing this. This problematic script worked perfectly prior to the latest system update. For now, I'll simply change the script to connect via localhost, but I'd really like to know why it broke for 2 reasons: There may be other scripts that connect using 192.168.0.40 that don't run very often which are now broken. Auditing them all will take more time than I feel like devoting at the moment. I'm curious, and want to know why it broke so I can fix it correctly. Any help?

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  • mysql command line not working

    - by Sandeepan Nath
    I have mysql running in my fedora system. I have xampp setup on the system and php projects present in the webspace are working fine. PhpMyAdmin is working fine. echoing phpinfo() in a PHP script also shows mysql enabled. But running mysql connect command mysql -u[username] -p[password] Gives this - bash: mysql: command not found How do I fix that? Any pointers? I guess I need to do some pointing (define some path in some file) so that my system knows that mysql is installed. What exactly do I have to do? Additional Details This system was someone else's and he is not available here. May be PHP/Mysql was setup already in the system. I just freshly extracted xampp for linux into /opt/lampp/ and have put all the above mentioned things (PHP projects and PhpMyAdmin) there. After doing that I had a socket problem (PhpMyAdmin was not working and showing this)- #2002 - The server is not responding (or the local MySQL server's socket is not correctly configured) I restarted lampp using ./lampp restart but problem remained. Then after turning on system today, I started lampp and everything worked just fine. No project issues anymore only command line Mysql not working

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  • MySQL partition "full"?

    - by gdea73
    I have a server that runs Debian 6.2, with Apache, PHP5, and MySQL. Well, I hadn't done anything with MySQL at all so far, just Apache and PHP; I must have installed it (mysql-server) at some point along the line, and I decided to login to the database for the first time a couple days ago as I was considering using the database for a future website project. I noticed that the "root" user had a password, and I didn't recall having set one. My usual root password was incorrect. So I attempted to reset the password. sudo service mysql stop (stopped successfully) sudo /usr/bin/mysqld_safe --skip-grant-tables --skip-networking & started successfully, from what I can tell. However, mysql itself returns "Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld,sock' (2)", and additionally sudo service mysql start returns "/etc/init.d/mysql: ERROR: The partition with /var/lib/mysql is too full! ... failed!" df -h tells me that / is 26% used, a 20GB partition, and /home, roughly 900GB, has only 5% usage. On a potentially related note, I've been experiencing random hangs since I noticed this problem, my tty2 randomly froze several times while idle, and the entire system is suddenly unstable. gnome-terminal also does not open. (Gnome-terminal apparently works now, disregard that part, but the server is still being somewhat unstable, I randomly lost connection when I was SSHed into it from my laptop, twice now.)

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  • Spring-mvc project can't select from a particular mysql table

    - by Dan Ray
    I'm building a Spring-mvc project (using JPA and Hibernate for DB access) that is running just great locally, on my dev box, with a local MySQL database. Now I'm trying to put a snapshot up on a staging server for my client to play with, and I'm having trouble. Tomcat (after some wrestling) deploys my war file without complaint, and I can get some response from the application over the browser. When I hit my main page, which is behind Spring Security authentication, it redirects me to the login page, which works perfectly. I have Security configured to query the database for user details, and that works fine. In fact, a change to a password in the database is reflected in the behavior of the login form, so I'm confident it IS reaching the database and querying the user table. Once authenticated, we go to the first "real" page of the app, and I get a "data access failure" error. The server's console log gets this line (redacted): ERROR org.hibernate.util.JDBCExceptionReporter - SELECT command denied to user 'myDbUser'@'localhost' for table 'asset' However, if I go to MySQL from the shell using exactly the same creds, I have no problem at all selecting from the asset table: [development@tomcat01stg]$ mysql -u myDbUser -pmyDbPwd dbName ... mysql> \s -------------- mysql Ver 14.12 Distrib 5.0.77, for redhat-linux-gnu (i686) using readline 5.1 Connection id: 199 Current database: dbName Current user: myDbUser@localhost ... UNIX socket: /var/lib/mysql/mysql.sock -------------- mysql> select count(*) from asset; +----------+ | count(*) | +----------+ | 19 | +----------+ 1 row in set (0.00 sec) I've broken down my MySQL access settings, cleaned out the user and re-run the grant commands, set up a version of the user from 'localhost' and another from '%', making sure to flush permissions.... Nothing is changing the behavior of this thing. What gives?

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  • Upgrading PHP, MySQL old-passwords issue

    - by Rushyo
    I've inherited a Windows 2k3 server running an XAMPP-installation from the stone age. I needed to upgrade PHP to facilitate an upgrade to MediaWiki to facilitate a new MediaWiki extension (to facilitate some documentation to facilitate doing my job to facilitate getting paid to facilit... you get the idea). However... installing a new version of PHP resulted in PHP's MySQL libraries refusing to communicate using MySQL's 'old style' 152-bit passwords. Not a problem in theory. The MySQL installation is post-4.1, so it should have the functionality to upgrade the user's passwords from 152-bit to 328-bit (what a weird hashing algorithm...). I ran the following: SET PASSWORD = PASSWORD('foo'); on MySQL but querying: SELECT user, password FROM mysql.user; returned just the same password I started out with - 152-bit. Now... I suspect you're thinking 'AHA! old-passwords is on!'. Unfortunately it's not - I've disabled it in the configuration (explicitly set it to 0), made doubly sure I have an absolute reference to that configuration file and ensured the service isn't using the --old-passwords flag. The service was reset after each and every operation. So I went onto another system and generated the 328-bit hash on there, copying the hash over to the first MySQL instance. Unfortunately, that didn't work either (I did remember to FLUSH PRIVILEGES). The application error is: "'mysqlnd cannot connect to MySQL 4.1+ using the old insecure authentication. Please use an administration tool [...snip...] Is there anything else I can try to get PHP to recognise MySQL as not using the 'old insecure authentication'? MySQL seems to be stuck in 'old-passwords' mode and I can't get it out of it.

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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Web page database query optimization

    - by morpheous
    I am putting together a web page which is quite 'expensive' in terms of database hits. I don't want to start optimizing at this stage - though with me trying to hit a deadline, I may end up not optimizing at all. Currently the page requires 18 (that's right eighteen) hits to the db. I am already using joins, and some of the queries are UNIONed to minimize the trips to the db. My local dev machine can handle this (page is not slow) however, I feel if I release this into the wild, the number of queries will quickly overwhelm my database (MySQL). I could always use memcache or something similar, but I would much rather continue with my other dev work that needs to be completed before the deadline - at least retrieving the page works - its simply a matter of optimization now (if required). My question therefore is - is 18 db queries for a single page retrieval completely outrageous - (i.e. I should put everything on hold and optimize the hell of the retrieval logic), or shall I continue as normal, meet the deadline and release on schedule and see what happens? [Edit] Just to clarify, I have already done the 'obvious' things like using (single and composite) indexes for fields used in the queries. What I haven't yet done is to run a query analyzer to see if my indexes etc are optimal.

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  • Too many columns to index - use mySQL Partitions?

    - by Christopher Padfield
    We have an application with a table with 20+ columns that are all searchable. Building indexes for all these columns would make write queries very slow; and any really useful index would often have to be across multiple columns increasing the number of indexes needed. However, for 95% of these searches, only a small subset of those rows need to be searched upon, and quite a small number - say 50,000 rows. So, we have considered using mySQL Partition tables - having a column that is basically isActive which is what we divide the two partitions by. Most search queries would be run with isActive=1. Most queries would then be run against the small 50,000 row partition and be quick without other indexes. Only issue is the rows where isActive=1 is not fixed; i.e. it's not based on the date of the row or anything fixed like that; we will need to update isActive based on use of the data in that row. As I understand it that is no problem though; the data would just be moved from one partition to another during the UPDATE query. We do have a PK on id for the row though; and I am not sure if this is a problem; the manual seemed to suggest the partition had to be based on any primary keys. This would be a huge problem for us because the primary key ID has no basis on whether the row isActive.

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  • MySQL died during the night on a 12.04.1 Ubuntu

    - by Olivier
    I can't explain why, but somehow during the night, one of my MySQL running on an Ubuntu 12.04.1 box broke. The service is running but I can't login anymore (to SQL), the previous password is not working anymore. It does not looks like the server has been compromised (nothing in /var/auth.log) It looks like some automatic security upgrade (server is configured to perform those) has occured and broke something. The MySQL server has restarted a couple of times in the logs at the time errors started to happen (I get email when CRON task fail). In the logs it complains about an unset root password (I do have cron job running all day using SQL so the password was set & working for months). Anyway I can't login without password either! Do you have any idea of what could have happened? How do I get my databases back? This line looks strange : Nov 6 06:36:12 ns398758 mysqld_safe[6676]: ERROR: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ALTER TABLE user ADD column Show_view_priv enum('N','Y') CHARACTER SET utf8 NOT ' at line 1 Here is the full log below : Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: PLEASE REMEMBER TO SET A PASSWORD FOR THE MySQL root USER ! Nov 6 06:36:06 ns398758 mysqld_safe[6586]: To do so, start the server, then issue the following commands: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: /usr/bin/mysqladmin -u root password 'new-password' Nov 6 06:36:06 ns398758 mysqld_safe[6586]: /usr/bin/mysqladmin -u root -h ns398758.ovh.net password 'new-password' Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Alternatively you can run: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: /usr/bin/mysql_secure_installation Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: which will also give you the option of removing the test Nov 6 06:36:06 ns398758 mysqld_safe[6586]: databases and anonymous user created by default. This is Nov 6 06:36:06 ns398758 mysqld_safe[6586]: strongly recommended for production servers. Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: See the manual for more instructions. Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Please report any problems with the /usr/scripts/mysqlbug script! Nov 6 06:36:06 ns398758 mysqld_safe[6586]: Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 [Note] Plugin 'FEDERATED' is disabled. Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 InnoDB: The InnoDB memory heap is disabled Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 InnoDB: Mutexes and rw_locks use GCC atomic builtins Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 InnoDB: Compressed tables use zlib 1.2.3.4 Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 InnoDB: Initializing buffer pool, size = 128.0M Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 InnoDB: Completed initialization of buffer pool Nov 6 06:36:06 ns398758 mysqld_safe[6632]: 121106 6:36:06 InnoDB: highest supported file format is Barracuda. Nov 6 06:36:07 ns398758 mysqld_safe[6632]: 121106 6:36:07 InnoDB: Waiting for the background threads to start Nov 6 06:36:08 ns398758 mysqld_safe[6632]: 121106 6:36:08 InnoDB: 1.1.8 started; log sequence number 29276459701 Nov 6 06:36:08 ns398758 mysqld_safe[6632]: 121106 6:36:08 InnoDB: Starting shutdown... Nov 6 06:36:09 ns398758 mysqld_safe[6632]: 121106 6:36:09 InnoDB: Shutdown completed; log sequence number 29276459701 Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 [Note] Plugin 'FEDERATED' is disabled. Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: The InnoDB memory heap is disabled Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: Mutexes and rw_locks use GCC atomic builtins Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: Compressed tables use zlib 1.2.3.4 Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: Initializing buffer pool, size = 128.0M Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: Completed initialization of buffer pool Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: highest supported file format is Barracuda. Nov 6 06:36:11 ns398758 mysqld_safe[6676]: 121106 6:36:11 InnoDB: Waiting for the background threads to start Nov 6 06:36:12 ns398758 mysqld_safe[6676]: 121106 6:36:12 InnoDB: 1.1.8 started; log sequence number 29276459701 Nov 6 06:36:12 ns398758 mysqld_safe[6676]: ERROR: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ALTER TABLE user ADD column Show_view_priv enum('N','Y') CHARACTER SET utf8 NOT ' at line 1 Nov 6 06:36:12 ns398758 mysqld_safe[6676]: 121106 6:36:12 [ERROR] Aborting Nov 6 06:36:12 ns398758 mysqld_safe[6676]: Nov 6 06:36:12 ns398758 mysqld_safe[6676]: 121106 6:36:12 InnoDB: Starting shutdown... Nov 6 06:36:13 ns398758 mysqld_safe[6676]: 121106 6:36:13 InnoDB: Shutdown completed; log sequence number 29276459701 Nov 6 06:36:13 ns398758 mysqld_safe[6676]: 121106 6:36:13 [Note] /usr/sbin/mysqld: Shutdown complete Nov 6 06:36:13 ns398758 mysqld_safe[6676]: Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 [Note] Plugin 'FEDERATED' is disabled. Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: The InnoDB memory heap is disabled Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: Mutexes and rw_locks use GCC atomic builtins Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: Compressed tables use zlib 1.2.3.4 Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: Initializing buffer pool, size = 128.0M Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: Completed initialization of buffer pool Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: highest supported file format is Barracuda. Nov 6 06:36:13 ns398758 mysqld_safe[6697]: 121106 6:36:13 InnoDB: Waiting for the background threads to start Nov 6 06:36:14 ns398758 mysqld_safe[6697]: 121106 6:36:14 InnoDB: 1.1.8 started; log sequence number 29276459701 Nov 6 06:36:14 ns398758 mysqld_safe[6697]: 121106 6:36:14 InnoDB: Starting shutdown... Nov 6 06:36:15 ns398758 mysqld_safe[6697]: 121106 6:36:15 InnoDB: Shutdown completed; log sequence number 29276459701 Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 [Note] Plugin 'FEDERATED' is disabled. Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: The InnoDB memory heap is disabled Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: Mutexes and rw_locks use GCC atomic builtins Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: Compressed tables use zlib 1.2.3.4 Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: Initializing buffer pool, size = 128.0M Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: Completed initialization of buffer pool Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: highest supported file format is Barracuda. Nov 6 06:36:15 ns398758 mysqld_safe[6718]: 121106 6:36:15 InnoDB: Waiting for the background threads to start Nov 6 06:36:16 ns398758 mysqld_safe[6718]: 121106 6:36:16 InnoDB: 1.1.8 started; log sequence number 29276459701 Nov 6 06:36:16 ns398758 mysqld_safe[6718]: ERROR: 1050 Table 'plugin' already exists Nov 6 06:36:16 ns398758 mysqld_safe[6718]: 121106 6:36:16 [ERROR] Aborting Nov 6 06:36:16 ns398758 mysqld_safe[6718]: Nov 6 06:36:16 ns398758 mysqld_safe[6718]: 121106 6:36:16 InnoDB: Starting shutdown... Nov 6 06:36:17 ns398758 mysqld_safe[6718]: 121106 6:36:17 InnoDB: Shutdown completed; log sequence number 29276459701 Nov 6 06:36:17 ns398758 mysqld_safe[6718]: 121106 6:36:17 [Note] /usr/sbin/mysqld: Shutdown complete Nov 6 06:36:17 ns398758 mysqld_safe[6718]: Nov 6 06:36:19 ns398758 /etc/mysql/debian-start[6816]: Upgrading MySQL tables if necessary. Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: /usr/bin/mysql_upgrade: the '--basedir' option is always ignored Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: Looking for 'mysql' as: /usr/bin/mysql Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: Looking for 'mysqlcheck' as: /usr/bin/mysqlcheck Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: Running 'mysqlcheck' with connection arguments: '--port=3306' '--socket=/var/run/mysqld/mysqld.sock' '--host=localhost' '--socket=/var/run/mysqld/mysqld.sock' '--host=localhost' '--socket=/var/run/mysqld/mysqld.sock' Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: Running 'mysqlcheck' with connection arguments: '--port=3306' '--socket=/var/run/mysqld/mysqld.sock' '--host=localhost' '--socket=/var/run/mysqld/mysqld.sock' '--host=localhost' '--socket=/var/run/mysqld/mysqld.sock' Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: col_digitas.acos OK Nov 6 06:36:20 ns398758 /etc/mysql/debian-start[6819]: col_digitas.aros OK ...

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  • Help with SQL query (add 5% to users with conditions)

    - by Mestika
    Hi everyone, I’m having some difficulties with a query which purpose is to give users with more than one thread (called CS) in current year a 5% point “raise”. My relational schema looks like this: Thread = (threadid, threadname, threadLocation) threadoffering = (threadid, season, year, user) user = (name, points) Then, what I need is to check: WHERE thread.threadid = threadoffering.threadid AND where threadoffering.year AND threadoffering.season = currentDate AND where threadoffering.User 1 GIVE 5 % raise TO user.points I hope it is explained thoroughly but otherwise here it is in short text: Give a 5 % “point raise” to all users who has more than 1 thread in threadLocation CS in the current year and season (always dynamic, so for example now is year = 2010 and season is = spring). I am looking forward to your answer Sincerely, Emil

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  • mySQL date range problem

    - by StealthRT
    Hey all i am in need of a little help with figuring out how to get a range of days for my select query. Here is the code i am trying out: select id, idNumber, theDateStart, theDateEnd from clients WHERE idNumber = '010203' AND theDateStart >= '2010-04-09' AND theDateEnd <= '2010-04-09'; This is what the data in the table looks like: TheDateStart = 2010-04-09 TheDateEnd = 2010-04-11 When testing that code above, it does not populate anything. If i take out the TheEndDate, it populates but with some other tables data as well which it should not do (it should only get one record). I know the problem is within the two date's. I'm not sure how to go about getting a date range for theDateStart and theDateEnd since if someone tries it, say, on 2010-04-10, it still needs to know its within rage of the 2010-04-09 - 2010-04-11. But right now, it does not... Any help would be great! :o) David

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  • mysql query the latest date

    - by user295189
    I am running this query SEL ECT sh.*, u.initials AS initals FROM database1.table1 AS sh JOIN database2.user AS u ON u.userID = sh.userid WHERE id = 123456 AND dts = ( SELECT MAX(dts) from database1.table1 ) ORDER BY sort_by, category In the table1 I have records like this dts status category sort_by 2010-04-29 12:20:27 Civil Engineers Occupation 1 2010-04-28 12:20:27 Civil Engineers Occupation 1 2010-04-28 12:20:54 Married Marital Status 2 2010-04-28 12:21:15 Smoker Tobbaco 3 2010-04-27 12:20:27 Civil Engineers Occupation 1 2010-04-27 12:20:54 Married Marital Status 2 2010-04-27 12:21:15 Smoker Tobbaco 3 2010-04-26 12:20:27 Civil Engineers Occupation 1 2010-04-26 12:20:54 Married Marital Status 2 2010-04-26 12:21:15 Smoker Tobbaco 3 so if you look at my data, I am choosing the latest entry by category and sort_id. however in some case such as on 29th (2010-04-29 12:20:27) I have only one record. So in this case I want to show occupation for latest and then the rest of them (latest). But currently it displays only one row. Thanks

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  • Join Query returns empty result, unexpected result

    - by Abs
    Hello all, Can anyone explain why this query returns an empty result. SELECT * FROM (`bookmarks`) JOIN `tags` ON `tags`.`bookmark_id` = `bookmarks`.`id` WHERE `tag` = 'clean' AND `tag` = 'simple' In my bookmarks table, I have a bookmark with an id of 70 and in my tags table i have two tags 'clean' and 'simple' both that have the column bookmark_id as 70. I would of thought a result would have been returned? How can I remedy this so that I have the bookmark returned when it has a tag of 'clean' and 'simple'? Thanks all for any explanation and solution to this.

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  • MySQL top count({column}) with a limit

    - by Josh K
    I have a table with an ip address column. I would like to find the top five addresses which are listed. Right now I'm planning it out the following: Select all distinct ip addresses Loop through them all saying count(id) where IP='{ip}' and storing the count List the top five counts. Downsides include what if I have 500 ip addresses. That's 500 queries I have to run to figure out what are the top five. I'd like to build a query like so select ip from table where 1 order by count({distinct ip}) asc limit 5

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  • MySQL: Copy a field to another table

    - by harpax
    I have a table posts that could look like this: id | title | body | created | .. ------------------------------------------- I would like to use the boolean search feature that is offered by a MyISAM Table, but the posts table is InnoDB. So I created another table 'post_contents' that looks like this: post_id | body -------------------- That table is already filled with some contents and I can use the boolean search. However, I need to move the title field in the post_contents table as well and then copy the existing title-data to the new field. I know about the INSERT .. SELECT syntax, but I don't seem to be able to create the correct query.

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  • MySql SELECT AS - Append all field names

    - by jeerose
    I'd like to do something like this: SELECT table.id AS prefix_id, table.name AS prefix_name ... and have the prefix added dynamically to all field names rather than selecting them all manually (ie SELECT table.* AS prefix_* or something) Hopefully I've described that accurately. Any thoughts? Edit To be clear, the reason I'm asking is to make sure that my query result contains every column from each table I call even if there are duplicate field names. For example, I might have a table with lots of fields which means I don't want to alias all the fields manually. Further if 3 tables have a field called name my result won't contain three name results; it will have one. I want to avoid ambiguity with my column names.

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  • mySQL Left Join on multiple tables with conditions

    - by Jarrod
    Hi, I have a problem. I have 4 tables: Invoice_Payment, Invoice, Client, and Calendar Basically, I have the below query, which works well, except, months with no date_due don't return. I.E only months with a date_due will be returned. I think I have to use a left join and join the calendar table with something like: LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field. But I'm having no luck SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Any help appreciated.

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  • A better way to build this MySQL statement with subselects

    - by Corey Maass
    I have five tables in my database. Members, items, comments, votes and countries. I want to get 10 items. I want to get the count of comments and votes for each item. I also want the member that submitted each item, and the country they are from. After posting here and elsewhere, I started using subselects to get the counts, but this query is taking 10 seconds or more! SELECT `items_2`.*, (SELECT COUNT(*) FROM `comments` WHERE (comments.Script = items_2.Id) AND (comments.Active = 1)) AS `Comments`, (SELECT COUNT(votes.Member) FROM `votes` WHERE (votes.Script = items_2.Id) AND (votes.Active = 1)) AS `votes`, `countrys`.`Name` AS `Country` FROM `items` AS `items_2` INNER JOIN `members` ON items_2.Member=members.Id AND members.Active = 1 INNER JOIN `members` AS `members_2` ON items_2.Member=members.Id LEFT JOIN `countrys` ON countrys.Id = members.Country GROUP BY `items_2`.`Id` ORDER BY `Created` DESC LIMIT 10 My question is whether this is the right way to do this, if there's better way to write this statement OR if there's a whole different approach that will be better. Should I run the subselects separately and aggregate the information?

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  • Count query with 3 coloumn iin SQL

    - by asher baig
    I have one database Library with table named called Medien. Having multiple columns named as Fname,Mname,Lname and ISBN. I want to calculate database records with ISBN and without ISBN? I have execute following command Select COUNT(ISBN) as Verf1 FROM library.MEDIEN where verf1 = isbn; Select COUNT(ISBN) as Verf2 FROM library.MEDIEN where verf2 = isbn; Select COUNT(ISBN) as Verf3 FROM library.MEDIEN where verf3 = isbn; Select COUNT(ISBN) as Ntverf1 FROM library.MEDIENwhere verf1 != isbn; Select COUNT(ISBN) as Ntverf2 FROM library.MEDIENwhere verf2 != isbn; Select COUNT(ISBN) as Ntverf3 FROM library.MEDIENwhere verf3 != isbn; I am not sure i execute correct command or not. Because some ISBN records have Fname,Mname or Fname,Lname or Mname,Lname or Fname , Lname,Mname only respectively. Please kindly help me solving this query

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  • Mysql query different group by

    - by solomongaby
    Hello i have a products table that contains normal products and configurable product It has a basic stucture of: id name price configurable ('yes', 'no') id_configuration Normal products have configurable no and 0 as id configuration, and configurable products have it set to yes and have the same id_configuration value. The current query is: SELECT `products`.* FROM `products`, `categories`, `product_categories` WHERE `categories`.`id` = 23 AND `products`.`id` = `product_categories`.`id_product` AND `categories`.`id` = `product_categories`.`id_category` AND `products`.`active` = 'yes' AND ORDER BY `pos_new` ASC, `created` DESC LIMIT 0,20 I was wondering if there is a way to group by id_configuration, but only for the configurable products. The reason is that i want only one of the configuration products to show in search. I was thinking i could do a join, but was wondering if there is a way to do some kind of special group by. For example for configurable yes the field should be id_configuration otherwise it should be the id field Thanks a lot for any sugestions

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