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  • Recursive COUNT Query (SQL Server)

    - by Cosmo
    Hello Guys! I've two MS SQL tables: Category, Question. Each Question is assigned to exactly one Category. One Category may have many subcategories. Category Id : bigint (PK) Name : nvarchar(255) AcceptQuestions : bit IdParent : bigint (FK) Question Id : bigint (PK) Title : nvarchar(255) ... IdCategory : bigint (FK) How do I recursively count all Questions for a given Category (including questions in subcategories). I've tried it already based on several tutorials but still can't figure it out :(

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  • Table format for Click stats

    - by Francesc
    Hello. I'm currently developing an URL shortening service. I want to allow users to see the stats for their URLs. How has to be the table. First, it has to be the url ID, but then, how I can sort the clicks per day?

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  • MySQL query for initial filling of order column

    - by Sejanus
    Sorry for vague question title. I've got a table containing huge list of, say, products, belonging to different categories. There's a foreign key column indicating which category that particular product belongs to. I.e. in "bananas" row category might be 3 which indicates "fruits". Now I added additional column "order" which is for display order within that particular category. I need to do initial ordering. Since the list is big, I dont wanna change every row by hand. Is it possible to do with one or two queries? I dont care what initial order is as long as it starts with 1 and goes up. I cant do something like SET order = id because id counts from 1 up regardless of product category and order must start anew from 1 up for every different category.

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  • mySQL query : working with INTERVAL and CURDATE

    - by Tristan
    Hello, i'm building a chart and i want to recieve data for each months Here's my first request which is working : SELECT s.GSP_nom AS nom, timestamp, AVG( v.vote + v.prix ) /2 AS avg FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ WHERE s.valide =1 AND v.date > CURDATE() -30 GROUP BY s.GSP_nom ORDER BY avg DESC But, in my case i've to write 12 request to recieve datas for the 12 previous months, is there any trick to avoid writing : // example for the previous month AND v.date > CURDATE() -60 AND v.date < CURDATE () -30 I heard about INTERVAL, i went to the mySQL doc but i didn't manage to implement it. Any ideas / example of using INTERVAL please ? Thank you

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  • Recursive COUNT Query (MS SQL)

    - by Cosmo
    Hello Guys! I've two MS SQL tables: Category, Question. Each Question is assigned to exactly one Category. One Category may have many subcategories. Category Id : bigint (PK) Name : nvarchar(255) AcceptQuestions : bit IdParent : bigint (FK) Question Id : bigint (PK) Title : nvarchar(255) ... IdCategory : bigint (FK) How do I recursively count all Questions for a given Category (including questions in subcategories). I've tried it already based on several tutorials but still can't figure it out :(

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  • help! Linq query

    - by menon
    I am getting error msg on the word Records - Type or namespace could not be found. Please help debugging it, what is missing? if (ProjDDL1.SelectedItem.Value != "--") results = CustomSearch<Records>(results, s => s.Business == ProjDDL1.SelectedItem.Value); Method CustomSearch: private DataTable CustomSearch<TKEY>(DataTable dt, Func<Records, bool> selector) { DataTable results = (dt.AsEnumerable().Where(selector).CopyToDataTable()); return results; }

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  • SQL query: Last but one rank for user

    - by Derk
    My table structure looks like this: create table rankings ( id IDENTITY NOT NULL, user_id INT NOT NULL, game_poule_id INT NOT NULL, rank INT NOT NULL, insertDate DATETIME NOT NULL, FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE, FOREIGN KEY (game_poule_id) REFERENCES game_poules(id) ON DELETE CASCADE ); All old rankings of users per game are saved in this table. Now I want to have the last but one rank in the table for all users in a gamepoule. Has someone an idea how to achive this? Thanks

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  • NHibernate - using custom sql query for a column

    - by stacker
    Is there anyway to use custom sql with NHibernate? I want to use custom sql for a specific column. select id, viewsCount, commentsCount, 0.2 * viewsCount / (select top 1 viewsCount from articles where isActive = 1 order by viewsCount DESC) as priorityViews, 0.8 * commentsCount / (select top 1 commentsCount from articles where isActive = 1 order by commentsCount DESC) as priorityComments, round(0.2 * viewsCount / (select top 1 viewsCount from articles where isActive = 1 order by viewsCount DESC) + 0.8 * commentsCount / (select top 1 commentsCount from articles where isActive = 1 order by commentsCount DESC), 1) as priority from articles

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  • Php/Mysql - need help to insert and update multiple rows with a single query

    - by Guanche
    Hello, is there any way how in this situation insert and update DB with single queries? $message = 'Hello to all group members'; $userdata = mysql_query("SELECT memberid, membernick FROM members WHERE groupid='$cid'") or die('Error'); while(list($memberid, $membernick) = mysql_fetch_row($userdata)) { $result1 = mysql_query("INSERT INTO messages VALUES (NULL,'$membernick', '$memberid', '$message')") or die('Error'); $result2 = mysql_query("UPDATE users SET new_messages=new_messages+1, total_messages=total_messages+1 WHERE id='$memberid'") or die('Error'); }

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  • Mysql query: count and distinct

    - by Azevedo
    I have this hypotetical MySQL table: TABLE cars: (year, color, brand) How do I count # of cars grouped by brand and year? I mean, how can I get to know how many colors are there grouped by brand like: brand "GM": total # of colors: 8. brand "GM": total # of years (grouped together): 14 (meaning there are count of 14 different years). brand "TOYOTA": total # of colors: 3. brand "TOYOTA": total # of years (grouped together): 10 (meaning there are count of 14 different years) I tried playing some queries with COUNT, DISTINCT, GROUP BY but I can't get to it. Actually I'm trying to get the 2 queries... +-------+---------------+ | brand | count(colors) | +-------+---------------+ +-------+--------------+ | brand | count(years) | +-------+--------------+ thanks a lot!

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  • PHP - SQL query to get update time from table status

    - by Tribalcomm
    This is my php code (I already have a connection to the db): $array = mysql_query("SHOW TABLE STATUS FROM mytable;"); while ($array = mysql_fetch_array($result)) { $updatetime = $array['Update_time']; } echo $updatetime; I get: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource. I am running MySQL 5.0.89 and PHP5. I do not want to add a new field to the table... I want to use the table status... Any help? Thanks!

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  • MS Access query for time

    - by nisha
    following data and using MS Access with VB6 UserID UserName LogTime LogDate 1 S 9:00 21/5/2010 1 S 10:00 21/5/2010 1 S 11:00 21/5/2010 1 S 12:00 21/5/2010 1 S 14:00 21/5/2010 1 S 17:00 21/5/2010 Need Output as in below 6 columns:- 1 S 21/5/2010 9:00 21/5/2010 10:00 1 S 21/5/2010 11:00 21/5/2010 12:00 1 S 21/5/2010 14:00 21/5/2010 17:00

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  • Why won't this sql update query work?

    - by Wesley
    I have a table that has 5,000(table1) lines in it. Currently, 3,000 of them are filled up with data. The remaining values are currently null. In a separate table(table2), I have the remaining 2,000 rows of data. I am simply trying to take the values in table2 and put them in table1, but this statement isn't working: Update table1 Set field1 = (Select field1 From table2 Where table1.id = table2.id) Where Exists(Select field1 From table2 Where table1.id = table2.id) It looks like this should be working, but I am getting an error from Base, the db program I am using that just says error Near " ": syntax error...any help?? Thanks!

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  • Help needed to construct a SQL query

    - by song202y
    Need your help to get the list of suggested friends (who aren't friends of the current user but are friends of 2 or more of the current user's friends). The primary ordering should put people at the same school at the top, and the secondary ordering should put people with more common friends (that is, the number of people who are friends of that person and the current user) near the top. Users: user_id PK, user_name Profiles: user_id PK, school_name, ... Friendships: id PK, user_id FK, friend_id FK Thank you in advance. Joe

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  • web page db query optimisation

    - by morpheous
    I am putting together a web page which is quite 'expensive' in terms of Db hits. I dont want to start optimizing at this stage - though with me trying to hit a deadline, I may end up not optimising at all. Currently the page requires 18 (thats right eighteen) hits to the db. I am already using joins, and some of the queries are UNIONed to minimize the trips to the db. My local dev machine can handle this (page is not slow) however, I feel if I release this into the wild, the number of queries will quickly overwhelm my database (mySQL). I could always use memcache or something similar, but I would much rather continue with my other dev work that needs to be completed before the deadline - at least retrieving the page work, its simply a matter of optimization. My question therefore is - is 18 db queries for a single page retrieval completely outrageous - (i.e. I should put everything on hold and optimize the hell of the retrieval logic), or shall I continue as normal, meet the deadline and release on schedule and see what happens?

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  • Problem in Union Join For MySQL Query

    - by Mac Taylor
    hey guys i managed to select from a table that saves my latest posts but i need to have double condition in selection here is my code : $sql_query = "SELECT b.*,u.username AS MY_Sender FROM TABLE_users u,TABLE_blogs b Where b.reciever = '0' AND u.user_id = b.sender UNION SELECT b.*,u.username AS MY_reciever FROM TABLE_users u,TABLE_blogs b Where b.reciever != '0' AND u.user_id = b.reciever ORDER BY bid DESC LIMIT 0,7 "; but MY_reciever is Null and empty Am i wrong in using UNION for this need ?!

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  • How can i rewrite this query for faster execution

    - by sam
    SELECT s1.ID FROM binventory_ostemp s1 JOIN ( SELECT Cust_FkId, ProcessID, MAX(Service_Duration) AS duration FROM binventory_ostemp WHERE ProcessID='4d2d6068678bc' AND Overall_Rank IN ( SELECT MIN(Overall_Rank) FROM binventory_ostemp WHERE ProcessID='4d2d6068678bc' GROUP BY Cust_FkId ) GROUP BY Cust_FkId ) AS s2 ON s1.Cust_FkId = s2.Cust_FkId AND s1.ProcessID=s2.ProcessID AND s1.Service_Duration=s2.duration AND s1.ProcessID='4d2d6068678bc' GROUP BY s1.Cust_FkId It just goes away if there are more than 10K rows in that table. What it does is find rows for each customer who has min. of overall rank and in those max. of service duration for a given processid Table Data ID Cust_FkId Overall_Rank Service_Duration ProcessID 1 23 2 30 4d2d6068678bc 2 23 1 45 4d2d6068678bc 3 23 1 60 4d2d6068678bc 4 56 3 90 4d2d6068678bc 5 56 2 50 4d2d6068678bc 6 56 2 85 4d2d6068678bc

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  • mySQL query: How to insert with UNION?

    - by Industrial
    Hi everybody, I am kind of new to mySQL:s union functions, at least when doing inserts with them. I have gotten the following to work based upon a example found on the net: INSERT INTO tableOne(a, b) SELECT a, $var FROM tableOne WHERE b = $var2 UNION ALL SELECT $var,$var Ok, nothing strange about that. But what happens when I want to insert a third value into the database that has nothing to do with the logic of the Select being done? Like : INSERT INTO tableOne(a, b, c ) How could that be done?

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