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  • Eclipse does not format this if statement correctly

    - by Maroloccio
    This should be easy to answer: I have Eclipse set to wrap Java code over 80 chars to respect my margin. This code never wraps: if (expressionItem.type.isTypeCompatibleWith(containingNameLink.type) == false) { reportParsingError("expression type incompatible with containing " + "context."); } Question: how do I set my code formatter preferences so that the margin is respected?

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  • Multiple actions upon a case statement in Haskell

    - by Schroedinger
    One last question for the evening, I'm building the main input function of my Haskell program and I have to check for the args that are brought in so I use args <- getArgs case length args of 0 -> putStrLn "No Arguments, exiting" otherwise -> { other methods here} Is there an intelligent way of setting up other methods, or is it in my best interest to write a function that the other case is thrown to within the main? Or is there an even better solution to the issue of cases. I've just got to take in one name.

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  • Insert statement with where clause.

    - by debraj
    I had a table with unique Date_t1 date type field, but in Table description field is not mentioned as unique, now while inserting new row i need to validate if date exist or not, If already exist i should not allow to make changes on that row, neither a new row needs to be created, Any idea how to resolve this problem in efficient way,

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  • DB2 CASE Statement

    - by gamerzfuse
    I need to somehow use the CASE syntax (which is beyond me) to affect the database results based on criteria. I have a bunch of royalties in 0.# form (royalty) I have a title ID # (title_id) and I need to show the new increase in royalties so that I can use the data. IF: they have a current royalty of 0.0 - 0.1 = 10% raise IF: they have 0.11 - 0.15 = 20% raise IF: royalty >= 0.16 = 20% raise Any help would be much appreciated. create table royalites ( title_id char(6), lorange integer, hirange integer, royalty decimal(5,2));

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  • Why isn't this javascript with else if working?

    - by Uni
    I'm sorry I can't be any more specific - I have no idea where the problem is. I'm a total beginner, and I've added everything I know to add to the coding, but nothing happens when I push the button. I don't know at this point if it's an error in the coding, or a syntax error that makes it not work. Basically I am trying to get this function "Rip It" to go through the list of Dewey decimal numbers, change some of them, and return the new number and a message saying it's been changed. There is also one labeled "no number" that has to return an error (not necessarily an alert box, a message in the same space is okay.) I am a total beginner and not particularly good at this stuff, so please be gentle! Many thanks! <!DOCTYPE html> <html> <head> <script type="text/javascript"> function RipIt() { for (var i = l; i <=10 i=i+l) { var dewey=document.getElementById(i); dewey=parseFloat(dewey); if (dewey >= 100 && 200 >= dewey) { document.getElementById('dewey'+ 100) } else if (dewey >= 400 && 500 >= dewey) { document.getElementById('dewey'+ 200) } else if (dewey >= 850 && 900 >= dewey) { document.getElementById('dewey'-100) } else if (dewey >= 600 && 650 >= dewey) { document.getElementById('dewey'+17) } } } </script> </head> <body> <h4>Records to Change</h4> <ul id="myList"> <li id ="1">101.33</li> <li id = "2">600.01</li> <li id = "3">001.11</li> <li id = "4">050.02</li> <li id = "5">199.52</li> <li id = "6">400.27</li> <li id = "7">401.73</li> <li id = "8">404.98</li> <li id = "9">no number</li> <li id = "10">850.68</li> <li id = "11">853.88</li> <li id = "12">407.8</li> <li id = "13">878.22</li> <li id = "14">175.93</li> <li id = "15">175.9</li> <li id = "16">176.11</li> <li id = "17">190.97</li> <li id = "18">90.01</li> <li id = "19">191.001</li> <li id = "20">600.95</li> <li id = "21">602.81</li> <li id = "22">604.14</li> <li id = "23">701.31</li> <li id = "24">606.44</li> <li id = "25">141.77</li> </ul> <b> </b> <input type="button" value="Click To Run" onclick="RipIt()"> <!-- <input type="button" value="Click Here" onClick="showAlert();"> --> </body> </html>

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  • SQL Distinct keyword in assignment statement

    - by Brandi
    I have a query that works: DECLARE @ProductID int SET @ProductID = '1234' SELECT DISTINCT TOP 12 a.ProductID FROM A a WHERE a.CategoryID IN (SELECT b.CategoryID FROM B b WHERE b.ProductID = @ProductID) AND a.ProductID != @ProductID It returns a list of 12 product numbers, all unique. I need to store these results in a variable, comma separated, because that's what 3rd party stored procedure needs. So I have this: DECLARE @ProductID int DECLARE @relatedprods varchar(8000) SET @ProductID = '1234' SET @relatedprods = '' SELECT TOP 12 @relatedprods = @relatedprods + CONVERT(VARCHAR(20), a.ProductID) + ', ' FROM A a WHERE a.CategoryID IN (SELECT b.CategoryID FROM B b WHERE B.ProductID = @ProductID) AND a.ProductID != @ProductID SELECT @relatedprods Now, none of these are distinct, but it is returning 12 rows. Now I add the 'distinct' back in, like in the first query: DECLARE @ProductID int DECLARE @relatedprods varchar(8000) SET @ProductID = '1234' SET @relatedprods = '' SELECT DISTINCT TOP 12 @relatedprods = @relatedprods + CONVERT(VARCHAR(20), a.ProductID) + ', ' FROM A a WHERE a.CategoryID IN (SELECT b.CategoryID FROM B b WHERE B.ProductID = @ProductID) AND a.ProductID != @ProductID SELECT @relatedprods Only one product is returned in the comma separated list! Does 'distinct' not work in assignment statements? What did I do wrong? Or is there a way to get around this? Thanks in advance!

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  • if statement OOP

    - by Luke
    I have the following code /* Errors exist, have user correct them */ if($form->num_errors > 0) { return 1; //Errors with form } /* No errors, add the new account to the */ else if($database->addLeagueInformation($subname, $subformat, $subgame, $subseason, $subwindow, $subadmin, $subchampion, $subtype)) { return 0; //New user added succesfully } else { return 2; //Registration attempt failed } I want to add the following to it $databases->addLeagueTable($name) This should happen at the same time as addLeagueInformation. Any ideas?

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  • Optimal two variable linear regression SQL statement

    - by Dave Jarvis
    Problem Am looking to apply the y = mx + b equation (where m is SLOPE, b is INTERCEPT) to a data set, which is retrieved as shown in the SQL code. The values from the (MySQL) query are: SLOPE = 0.0276653965651912 INTERCEPT = -57.2338357550468 SQL Code SELECT ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT FROM (SELECT D.AMOUNT, Y.YEAR FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE -- For a specific city ... -- C.ID = 8590 AND -- Find all the stations within a 5 unit radius ... -- SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) <15 AND -- Gather all known years for that station ... -- S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND -- The data before 1900 is shaky; and insufficient after 2009. -- Y.YEAR BETWEEN 1900 AND 2009 AND -- Filtered by all known months ... -- M.YEAR_REF_ID = Y.ID AND -- Whittled down by category ... -- M.CATEGORY_ID = '001' AND -- Into the valid daily climate data. -- M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ORDER BY Y.YEAR ) t Data The data is visualized here: Questions How do I return the y value against all rows without repeating the same query to collect and collate the data? That is, how do I "reuse" the list of t values? How would you change the query to eliminate outliers (at an 85% confidence interval)? The following results (to calculate the start and end points of the line) appear incorrect. Why are the results off by ~10 degrees (e.g., outliers skewing the data)? (1900 * 0.0276653965651912) + (-57.2338357550468) = -4.66958228 (2009 * 0.0276653965651912) + (-57.2338357550468) = -1.65405406 I would have expected the 1900 result to be around 10 (not -4.67) and the 2009 result to be around 11.50 (not -1.65). Thank you!

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  • Sql query to get this result..

    - by bala3569
    Consider i have a user table and i have three columns mobilePhone,homePhone and workPhone... I have to select homePhone for every user as first pref if there is no value i ll go for mobilePhone and if there is no value for it i ll go for workPhone.... Any suggestion how it can be done in mysql..

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  • Statement hierarchy in programming languages

    - by sudo
    I quickly wrote an interpreter for some sort of experimental programing language i came up with, in PHP (yes, in PHP). The language itself doesn't have anything really special, I just wanted to give it a try. I got the basic things working (Hello World, input to output, string manipulation, arithmetics) but I'm getting stuck with the management of blocks and grouped statements. What I mean is: PHP and most other languages let you do this: ((2+2)*(8+2)+2), of course not only with mathematical computations. My program structure currently consists of a multidimensional array built like this: ID => Type (Identifier, String, Int, Newline, EOF, Comma, ...) Contents (If identifier, int or string) How could I allow statements to be executed in a defined order like in the PHP example above?

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  • T-SQL GO Statement

    - by coffeeaddict
    I have read and read over MSDN, etc. Ok, so it signals the end of a batch. What defines a batch? I don't see why I need go when I'm pasting in a bunch of scripts to be run all at the same time. I've never understood GO. Can anyone explain this better and when I need to use it (after how many or what type of transactions)?

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  • OOP function and if statement

    - by Luke
    Not sure if I can ask two questions? If i run the following function in my database class function generateUserArray() { $u = array(); $result = $this->selectAllUsers(); while( $row=mysql_fetch_assoc($result)) { $u[] = $row['username']; } return $u; } Would i call it like this? $u[] = $datebase->generateUserArray(); My second question, will this work: else if($database->addLeagueInformation($subname, $subformat, $subgame, $subseason, $subwindow, $subadmin, $subchampion, $subtype) && $databases->addLeagueTable($name) && $_SESSION['players'] == $subplayers && $comp_name = "$format_$game_$name_$season" && $_SESSION['comp_name'] = $comp_name) Thankyou

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  • problem Keyword token antlr

    - by batman_for
    If the 'for' is used both as a command and as "the English word": for_statement: 'for' ... id: 'for' | ID ; ID: ... right? My problem is how to differentiate the two cases. For example for_statement is only possible beginning of a line (only if preceded by ' ' or '\t'). Thanks.

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  • MySQL Select statement Where table1.id != table2.id

    - by Michael
    I have a table of data which has posts, then I have a separate table of data which has deleted posts. What happens when a post is deleted is that it's ID get's added to the deleted table rather than removing the post entry. What is a clean efficient way of selecting all the posts from the posts table without selecting the ones that have their ID in the deleted table

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  • T_BOOLEAN_AND error?

    - by Ronnie Chester Lynwood
    whats wrong with this? anybody help me please.. if(stripos($nerde, $hf) !== false) && (stripos($nerde, $rs) !== false){ @mysql_query("update table set dltur = '3' where id = '".$ppl[id]."'"); } else { //dont do anything } i get T_BOOLEAN_AND error.

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  • Why no switch on pointers?

    - by meeselet
    For instance: #include <stdio.h> void why_cant_we_switch_him(void *ptr) { switch (ptr) { case NULL: printf("NULL!\n"); break; default: printf("%p!\n", ptr); break; } } int main(void) { void *foo = "toast"; why_cant_we_switch_him(foo); return 0; } gcc test.c -o test test.c: In function 'why_cant_we_switch_him': test.c:5: error: switch quantity not an integer test.c:6: error: pointers are not permitted as case values Just curious. Is this a technical limitation? EDIT People seem to think there is only one constant pointer expression. Is that is really true, though? For instance, here is a common paradigm in Objective-C (it is really only C aside from NSString, id and nil, which are merely a pointers, so it is still relevant — I just wanted to point out that there is, in fact, a common use for it, despite this being only a technical question): #include <stdio.h> #include <Foundation/Foundation.h> static NSString * const kMyConstantObject = @"Foo"; void why_cant_we_switch_him(id ptr) { switch (ptr) { case kMyConstantObject: // (Note that we are comparing pointers, not string values.) printf("We found him!\n"); break; case nil: printf("He appears to be nil (or NULL, whichever you prefer).\n"); break; default: printf("%p!\n", ptr); break; } } int main(void) { NSString *foo = @"toast"; why_cant_we_switch_him(foo); foo = kMyConstantObject; why_cant_we_switch_him(foo); return 0; } gcc test.c -o test -framework Foundation test.c: In function 'why_cant_we_switch_him': test.c:5: error: switch quantity not an integer test.c:6: error: pointers are not permitted as case values It appears that the reason is that switch only allows integral values (as the compiler warning said). So I suppose a better question would be to ask why this is the case? (though it is probably too late now.)

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  • PHP errors -> Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt | Warning: mysqli_stmt::c

    - by Tunji Gbadamosi
    I keep getting this error while trying to modify some tables. Here's my code: /** <- line 320 * * @param array $guests_array * @param array $tickets_array * @param integer $seat_count * @param integer $order_count * @param integer $guest_count */ private function book_guests($guests_array, $tickets_array, &$seat_count, &$order_count, &$guest_count){ /* @var $guests_array ArrayObject */ $sucess = false; if(sizeof($guests_array) >= 1){ //$this->mysqli->autocommit(FALSE); //insert the guests into guest, person, order, seat $menu_stmt = $this->mysqli->prepare("SELECT id FROM menu WHERE name=?"); $menu_stmt->bind_param('s',$menu); //$menu_stmt->bind_result($menu_id); $table_stmt = $this->mysqli->prepare("SELECT id FROM tables WHERE name=?"); $table_stmt->bind_param('s',$table); //$table_stmt->bind_result($table_id); $seat_stmt = $this->mysqli->prepare("SELECT id FROM seat WHERE name=? AND table_id=?"); $seat_stmt->bind_param('ss',$seat, $table_id); //$seat_stmt->bind_result($seat_id); for($i=0;$i<sizeof($guests_array);$i++){ $menu = $guests_array[$i]['menu']; $table = $guests_array[$i]['table']; $seat = $guests_array[$i]['seat']; //get menu id if($menu_stmt->execute()){ $menu_stmt->bind_result($menu_id); while($menu_stmt->fetch()) ; } $menu_stmt->close(); //get table id if($table_stmt->execute()){ $table_stmt->bind_result($table_id); while($table_stmt->fetch()) ; } $table_stmt->close(); //get seat id if($seat_stmt->execute()){ $seat_stmt->bind_result($seat_id); while($seat_stmt->fetch()) ; } $seat_stmt->close(); $dob = $this->create_date($guests_array[$i]['dob_day'], $guests_array[$i]['dob_month'], $guests_array[$i]['dob_year']); $id = $this->add_person($guests_array[$i]['first_name'], $guests_array[$i]['surname'], $dob, $guests_array[$i]['sex']); if(is_string($id)){ $seat = $this->add_seat($table_id, $seat_id, $id); /* @var $tickets_array ArrayObject */ $guest = $this->add_guest($id,$tickets_array[$i+1],$menu_id, $this->volunteer_id); /* @var $order integer */ $order = $this->add_order($this->volunteer_id, $table_id, $seat_id, $id); if($guest == 1 && $seat == 1 && $order == 1){ $seat_count += $seat; $guest_count += $guest; $order_count += $order; $success = true; } } } } return $success; } <- line 406 Here are the warnings: The person PRSN10500000LZPH has been added to the guest tablePRSN10500000LZPH added to table (1), seat (1)The order for person(PRSN10500000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (1)PRSN10600000LZPH added to table (1), seat (13)The person PRSN10600000LZPH has been added to the guest tableThe order for person(PRSN10600000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13) Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 358 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 363 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 366 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 371 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 374 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 379 PRSN10700000LZPH added to table (1), seat (13)The person PRSN10700000LZPH has been added to the guest tableThe order for person(PRSN10700000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13) Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 358 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 363 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 366 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 371 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 374 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 379 PRSN10800000LZPH added to table (1), seat (13)The person PRSN10800000LZPH has been added to the guest tableThe order for person(PRSN10800000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13)

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  • Simpler range finder?

    - by dotty
    Hay guys I've programmed a very simple range finder. The user can only select numbers 1 - 180 (axis) if the number is 90 or below i have to add 90 on to it if the number is 91 - 180 i have to take off 90 from it. Here's what i have $min_range = range(1,90); $max_range = range(91,180); if(in_array($axis, $min_range)){ $c = $axis + 90; }elseif(in_array($axis, $max_range)){ $c = $axis - 90; } Has anyone got a better solution

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  • What does this MySQL statement do?

    - by user198729
    INSERT IGNORE INTO `PREFIX_tab_lang` (`id_tab`, `id_lang`, `name`) (SELECT `id_tab`, id_lang, (SELECT tl.`name` FROM `PREFIX_tab_lang` tl WHERE tl.`id_lang` = (SELECT c.`value` FROM `PREFIX_configuration` c WHERE c.`name` = 'PS_LANG_DEFAULT' LIMIT 1) AND tl.`id_tab`=`PREFIX_tab`.`id_tab`) FROM `PREFIX_lang` CROSS JOIN `PREFIX_tab`); It's from an opensource project,and no documentation available. Especially,what does cross-join mean? I've only used join/left join .

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  • PHP, create_function or evalute it at runtime?

    - by blow
    Hi all, i have a class with some method that depend by one parameter. What is the best way to write this method? Example: First way class Test{ var $code; function Test($type){ if($type=="A"){ $this->code=create_function(/*some args and some code*/); } else if($type=="B"){ $this->code=create_function(/*some args and some code*/); } } function use(/*some args*/){ return call_user_func($this->code,/*some args*/); } } Second way class Test{ var $type; function Test($type){ $this->type=$type; } function use(/*some args*/){ if($this->type=="A"){ //some code } else if($this->type=="B"){ //some code } } } $test=new Test("A"); $test->use(); Which way you would choose? Thanks.

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  • MySQLi Prepared Statement Query Issue

    - by Benjamin Flak
    I'm relatively new to MySQLi prepared statements, and running into an error. Take this code: $user = 'admin'; $pass = 'admin'; if ($stmt = $mysqli->query("SELECT * FROM members WHERE username='$user' AND password='$pass'")) { echo $stmt->num_rows; } This will display "1", as it should. This next piece of code though, returns "0": $user = 'admin'; $pass = 'admin'; if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE username=? AND password=?")) { $stmt->bind_param("ss", $user, $pass); $stmt->execute(); echo $stmt->num_rows; } Any ideas why?

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  • Putting Select Statement on Hibernate Transaction

    - by Mark Estrada
    Hi All, I have been reading the net for a while regarding Hibernate but I can seem to understand one concept regarding Transaction. On some site that I have visit, Select statements are in transaction mode like this. public List<Book> readAll() { Session session = HibernateUtil.getSessionFactory() .getCurrentSession(); session.beginTransaction(); List<Book> booksList = session.createQuery("from Book").list(); session.getTransaction().commit(); return booksList; } While on some site, it does not advocate the use of transaction on Select statements public List<Book> readAll() { Session session = HibernateUtil.getSessionFactory() .getCurrentSession(); List<Book> booksList = session.createQuery("from Book").list(); return booksList; } I am thinking which one should I follow. Any thoughts please? Are transactions needed on Select Statements or not? Thanks

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  • How does this "&" work in this statement?

    - by aquaibm
    I know how bitwise AND works,but I don't understand how does (sourceDragMask & NSDragOperationGeneric) work here,I don't get the point.Is there anyone can explain to me?Thanks a lot. (NSDragOperation)draggingEntered:(id )sender { NSPasteboard *pboard; NSDragOperation sourceDragMask; sourceDragMask = [sender draggingSourceOperationMask]; pboard = [sender draggingPasteboard]; if ( [[pboard types] containsObject:NSColorPboardType] ) { if (sourceDragMask & NSDragOperationGeneric) { return NSDragOperationGeneric; } } return NSDragOperationNone; }

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