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  • DOMAIN REDIRECT PROBLEM WITH JQUERY / JAVASCRIPT

    - by GiovanniDema
    Hi guys, first time here. I got a strange problem. I have a fullscreen image scaler javascript (as GOTOCHINA website) that works very well on my website. Then, I purchased a domain redirect pointing on my website and when redirecting suddenly internet explorer 7 and internet explorer 8 give me this error Messagge: is not a valid argument. Line: 34 Char: 17 URI: http://*****/scaler.js The script is var db=document.body; var imag=document.getElementById('wallpaper'); var dbsize={}; var imgsrc=imag.src; var keyStop=function(e){ var e=window.event||e||{}; var tag=e.target.tagName.toLowerCase(); if(tag!='textarea'&&!(tag=='input'&&(e.target.type=='text'||e.target.type=='password'))){ if(e.keyCode==32||e.keyCode==39||e.keyCode==40){ if(e.preventDefault)e.preventDefault(); else e.returnValue=false; } } } if(this.addEventListener)window.addEventListener('keydown',keyStop,false); else window.attachEvent('onkeydown',keyStop); setInterval(function(){ window.scrollTo(0,0); if(imag.complete){ if(db.clientWidth!=dbsize.w||db.clientHeight!=dbsize.h||imag.src!=imgsrc){ imgsrc=imag.src; var dbsizew=db.clientWidth; var dbsizeh=db.clientHeight; var newwidth=Math.round(dbsizeh*(imag.offsetWidth/imag.offsetHeight)); var nextvar=dbsizewnewwidth?dbsizew:newwidth; imag.style.width=nextvar+'px'; } } },300); In other words when i open the official website everything's working correctly. When i open redirect domain pointing on official website... the previous error appears. The line is exactly this - imag.style.width=nextvar+'px'; Thanks in advance Giovanni

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  • How do I produce a screenshot of a flash swf on the server?

    - by indignant
    I'm writing a flash app using the open source tools. I would like to load a data file in to the app and capture a screenshot of the stage on the server. The only part that seems mysterious is running the app on the server. In fact, I don't even care if it's the same app running on the server and in the browser--if I can use the flash stage and drawing routines to produce an image server-side, I'm happy. If I have to delve in to flex, fine. Right now I'm having problems finding any starting point at all. I gather Adobe has some commercial products that may fit the bill, but I'd like to stick with open source, apache, and linux. I know this is probably possible with haxe/neko, but I'd like to use more mainstream tools if possible. Am I asking too much? EDIT/CLARIFICATION: Many thanks for the responses so far, but I think I've been a bit muddy in my description. I've already written the actual stage-grabbing stuff using the same PNGEncoder class as was suggested. The problem is in actually running the swf on the server side. I don't want to let the client take the screen shot itself, because this opens up the possibility of the client maliciously submitting a screenshot which does not correspond to what is on the stage, that is, I don't want users uploading porn. If I could run the the actionscript code on the server, then I could generate the screenshot from my data files and be sure that the screenshot matches the data, but I have no idea how to run the actionscript or swf on the server.

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  • Increasing figure size in Matplotlib

    - by Anirudh
    I am trying to plot a graph from a distance matrix. The code words fine and gives me a image in 800 * 600 pixels. The image being too small, All the nodes are packed together. I want increase the size of the image. so I added the following line to my code - figure(num=None, figsize=(10, 10), dpi=80, facecolor='w', edgecolor='k') After this all I get is a blank 1000 * 1000 image file. My overall code - import networkx as nx import pickle import matplotlib.pyplot as plt print "Reading from pickle." p_file = open('pickles/names') Names = pickle.load(p_file) p_file.close() p_file = open('pickles/distance') Dist = pickle.load(p_file) p_file.close() G = nx.Graph() print "Inserting Nodes." for n in Names: G.add_node(n) print "Inserting Edges." for i in range(601): for j in range(601): G.add_edge(Names[i],Names[j],weight=Dist[i][j]) print "Drawing Graph." nx.draw(G) print "Saving Figure." #plt.figure(num=None, figsize=(10, 10)) plt.savefig('new.png') print "Success!"

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  • OnConnect event not firing when using TClientSocket inside a TThread on non-blocking mode

    - by mathematician1975
    I am trying to make use of Borlands TClientSocket component in non-blocking mode inside a multithreaded C++ Windows application. I am creating multiple threads (classes derived from TThread), each of which creates its own TClientSocket object. I then assign member functions of the thread class to act as event handlers for the OnConnect, OnDisconnect and OnSocketError events of the socket. The problem I am having here is that whenever I call the TClientSocket::Open() function from within the TThread::Execute() function, the OnConnect event never fires. However, When I call the Open() function from the VCL thread prior to the TThread::Execute() function getting called, all of the events fire and I can use the thread-socket combination as I would like. Now I have not read anything in documentation that says that TClientSocket should not be used in non-blocking mode when used inside a thread, but it appears to me that there is perhaps something wrong conceptually in the way I am trying to use this class. Borland documentation is quite poor on the subject and these components have now been deprecated so reliable information is hard to come by. Despite being deprecated I have to use them as there is no alternative in the Builder 6 package I have. Can anyone please advise me if there is a right/wrong way to use TThread and a non-blocking TClientSocket in combination. I have never had problems using it as part of the VCL thread and never had problems using TServerSocket before and I really cannot understand why some events are not firing.

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  • How to use WebSockets refresh multi-window for play framework 1.2.7

    - by user2468652
    My code can work.But only refresh a page of one window. If I open window1 and window2 , both open websocket connect. I keyin word "test123" in window1, click sendbutton. Only refresh window1. How to refresh window1 and window2 ? Client <script> window.onload = function() { document.getElementById('sendbutton').addEventListener('click', sendMessage,false); document.getElementById('connectbutton').addEventListener('click', connect, false); } function writeStatus(message) { var html = document.createElement("div"); html.setAttribute('class', 'message'); html.innerHTML = message; document.getElementById("status").appendChild(html); } function connect() { ws = new WebSocket("ws://localhost:9000/ws?name=test"); ws.onopen = function(evt) { writeStatus("connected"); } ws.onmessage = function(evt) { writeStatus("response: " + evt.data); } } function sendMessage() { ws.send(document.getElementById('messagefield').value); } </script> </head> <body> <button id="connectbutton">Connect</button> <input type="text" id="messagefield"/> <button id="sendbutton">Send</button> <div id="status"></div> </body> Play Framework WebSocketController public class WebSocket extends WebSocketController { public static void test(String name) { while(inbound.isOpen()) { WebSocketEvent evt = await(inbound.nextEvent()); if(evt instanceof WebSocketFrame) { WebSocketFrame frame = (WebSocketFrame)evt; System.out.println("received: " + frame.getTextData()); if(!frame.isBinary()) { if(frame.getTextData().equals("quit")) { outbound.send("Bye!"); disconnect(); } else { outbound.send("Echo: %s", frame.getTextData()); } } } } } }

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  • Pymedia video encoding failed

    - by user1474837
    I am using Python 2.5 with Windows XP. I am trying to make a list of pygame images into a video file using this function. I found the function on the internet and edited it. It worked at first, than it stopped working. This is what it printed out: Making video... Formating 114 Frames... starting loop making encoder Frame 1 process 1 Frame 1 process 2 Frame 1 process 2.5 This is the error: Traceback (most recent call last): File "ScreenCapture.py", line 202, in <module> makeVideoUpdated(record_files, video_file) File "ScreenCapture.py", line 151, in makeVideoUpdated d = enc.encode(da) pymedia.video.vcodec.VCodecError: Failed to encode frame( error code is 0 ) This is my code: def makeVideoUpdated(files, outFile, outCodec='mpeg1video', info1=0.1): fw = open(outFile, 'wb') if (fw == None) : print "Cannot open file " + outFile return if outCodec == 'mpeg1video' : bitrate= 2700000 else: bitrate= 9800000 start = time.time() enc = None frame = 1 print "Formating "+str(len(files))+" Frames..." print "starting loop" for img in files: if enc == None: print "making encoder" params= {'type': 0, 'gop_size': 12, 'frame_rate_base': 125, 'max_b_frames': 90, 'height': img.get_height(), 'width': img.get_width(), 'frame_rate': 90, 'deinterlace': 0, 'bitrate': bitrate, 'id': vcodec.getCodecID(outCodec) } enc = vcodec.Encoder(params) # Create VFrame print "Frame "+str(frame)+" process 1" bmpFrame= vcodec.VFrame(vcodec.formats.PIX_FMT_RGB24, img.get_size(), # Covert image to 24bit RGB (pygame.image.tostring(img, "RGB"), None, None) ) print "Frame "+str(frame)+" process 2" # Convert to YUV, then codec da = bmpFrame.convert(vcodec.formats.PIX_FMT_YUV420P) print "Frame "+str(frame)+" process 2.5" d = enc.encode(da) #THIS IS WHERE IT STOPS print "Frame "+str(frame)+" process 3" fw.write(d.data) print "Frame "+str(frame)+" process 4" frame += 1 print "savng file" fw.close() Could somebody tell me why I have this error and possibly how to fix it? The files argument is a list of pygame images, outFile is a path, outCodec is default, and info1 is not used anymore. UPDATE 1 This is the code I used to make that list of pygame images. from PIL import ImageGrab import time, pygame pygame.init() f = [] #This is the list that contains the images fps = 1 for n in range(1, 100): info = ImageGrab.grab() size = info.size mode = info.mode data = info.tostring() info = pygame.image.fromstring(data, size, mode) f.append(info) time.sleep(fps)

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  • Why is calling close() after fopen() not closing?

    - by Richard Morgan
    I ran across the following code in one of our in-house dlls and I am trying to understand the behavior it was showing: long GetFD(long* fd, const char* fileName, const char* mode) { string fileMode; if (strlen(mode) == 0 || tolower(mode[0]) == 'w' || tolower(mode[0]) == 'o') fileMode = string("w"); else if (tolower(mode[0]) == 'a') fileMode = string("a"); else if (tolower(mode[0]) == 'r') fileMode = string("r"); else return -1; FILE* ofp; ofp = fopen(fileName, fileMode.c_str()); if (! ofp) return -1; *fd = (long)_fileno(ofp); if (*fd < 0) return -1; return 0; } long CloseFD(long fd) { close((int)fd); return 0; } After repeated calling of GetFD with the appropriate CloseFD, the whole dll would no longer be able to do any file IO. I wrote a tester program and found that I could GetFD 509 times, but the 510th time would error. Using Process Explorer, the number of Handles did not increase. So it seems that the dll is reaching the limit for the number of open files; setting _setmaxstdio(2048) does increase the amount of times we can call GetFD. Obviously, the close() is working quite right. After a bit of searching, I replaced the fopen() call with: long GetFD(long* fd, const char* fileName, const char* mode) { *fd = (long)open(fileName, 2); if (*fd < 0) return -1; return 0; } Now, repeatedly calling GetFD/CloseFD works. What is going on here?

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  • Server Push CGI Perl Problem writing the JPEG image

    - by Jujjuru
    I am a beginner in Perl CGI etc. I was experimenting with server-push concept with a piece of perl code. It is supposed to send a jpeg image to the client every 3 seconds. Unfortunately nothing seems to work. Can somebody help identify the problem? Here is the code.... use strict; # turn off io buffering $|=1; print "Content-type: multipart/x-mixed-replace;"; print "boundary=magicalboundarystring\n\n"; print "--magicalboundarystring\n"; #list the jpg images my(@file_list) = glob "*.jpg"; my($file) = ""; foreach $file(@file_list ) { open FILE,">", $file or die "Cannot open file $file: $!"; print "Content-type: image/jpeg\n\n"; while ( <FILE> ) { print "$_"; } close FILE; print "\n--magicalboundarystring\n"; sleep 3; next; } EDIT: added turn off i/o buffering, added "use strict" and "@file_list", "$file" are made local

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  • Can a WebServiceHost be changed to avoid the use of HttpListener?

    - by sbyse
    I am looking for a way to use a WCF WebServiceHost without having to rely on the HttpListener class and it's associated permission problems (see this question for details). I'm working on a application which communicates locally with another (third-party) application via their REST API. At the moment we are using WCF as an embedded HTTP server. We create a WebServiceHost as follows: String hostPath = "http://localhost:" + portNo; WebServiceHost host = new WebServiceHost(typeof(IntegrationService), new Uri(hostPath)); // create a webhttpbinding for rest/pox and enable cookie support for session management WebHttpBinding webHttpBinding = new WebHttpBinding(); webHttpBinding.AllowCookies = true; ServiceEndpoint ep = host.AddServiceEndpoint(typeof(IIntegrationService), webHttpBinding, ""); host.Open() ChannelFactory<IIntegrationService> cf = new ChannelFactory<IIntegrationService>(webHttpBinding, hostPath); IIntegrationService channel = cf.CreateChannel(); Everything works nicely as long as our application is run as administrator. If we run our application on a machine without administrative privileges the host.Open() will throw an HttpListenerException with ErrorCode == 5 (ERROR_ACCESS_DENIED). We can get around the problem by running httpcfg.exe from the command line but this is a one-click desktop application and that's not really as long term solution for us. We could ditch WCF and write our own HTTP server but I'd like to avoid that if possible. What's the easiest way to replace HttpListener with a standard TCP socket while still using all of the remaining HTTP scaffolding that WCF provides?

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  • Authentication Problem in Silverlight - Cannot connect to SQL Server

    - by Johann
    Hi All, At the moment, when I try to register a user using the default Business Template in Silverlight, I am getting an error. Basically I am following a tutorial found on Channel 9 on how to build a business app with Silverlight. "An error has occurred while establishing a connection to the server. (provider: Named Pipes Provider, error: 40 – Could not open a connection to SQL Server) (Microsoft SQL Server, Error: 5) An error has occurred while establishing a connection to the server. When connecting to SQL Server 2005, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections. (provider: Named Pipes Provider, error: 40 – Could not open a connection to SQL Server) (Microsoft SQL Server, Error: 1326)". I found a blog where it identifies the problem, and followed every step, however I am still getting the same problems. Here is my connection string:- <add name="SIEventManagerEntities" connectionString="metadata=res://*/EventManagerDBModel.csdl|res://*/EventManagerDBModel.ssdl|res://*/EventManagerDBModel.msl;provider=System.Data.SqlClient;provider connection string=&quot;Data Source=MONFU-PC;Initial Catalog=SIEventManager;Integrated Security=SSPI;MultipleActiveResultSets=True&quot;" providerName="System.Data.EntityClient" /> Any help would really be very much appreciated! Thanks

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Wrapping an additional element around an existing XDocument

    - by user1382827
    Let's say I have a converted HTML document, and I wanted to wrap an extra tag around the parent, so that I could read the head and body. How would I do that with C#? The file is used as an XDocument. change <html> <head> <!-- data --> </head> <body> <!-- data --> </body> </html> to <open> <html> <head> <!-- data --> </head> <body> <!-- data --> </body> </html> </open>

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  • Python FTP grabbing and saving images issue

    - by PylonsN00b
    OK So I have been messing with this all day long. I am fairly new to Python FTP. So I have searched through here and came up w/ this: images = notions_ftp.nlst() for image_name in image_names: if found_url == False: try: for image in images: ftp_image_name = "./%s" % image_name if ftp_image_name == image: found_url = True image_name_we_want = image_name except: pass # We failed to find an image for this product, it will have to be done manually if found_url == False: log.info("Image ain't there baby -- SKU: %s" % sku) return False # Hey we found something! Open the image.... notions_ftp.retrlines("RETR %s" % image_name_we_want, open(image_name_we_want, "rb")) 1/0 So I have narrowed the error down to the line before I divide by zero. Here is the error: Traceback (most recent call last): File "<console>", line 6, in <module> File "<console>", line 39, in insert_image IOError: [Errno 2] No such file or directory: '411483CC-IT,IM.jpg' So if you follow the code you will see that the image IS in the directory because image_name_we_want is set if found in that directory listing on the first line of my code. And I KNOW it's there because I am looking at the FTP site myself and ...it's freakin there. So at some point during all of this I got the image to save locally, which is most desired, but I have long since forgot what I used to make it do that. Either way, why does it think that the image isn't there when it clearly finds it in the listing.

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  • Creating Actions from UIActionSheets help

    - by user337174
    I am using two UIAction sheets within my current project. I can get one to work perfectly fine but when i insert a second action sheet it runs the same arguements as the first. How do i define the actionsheets seperatly? -(IBAction) phoneButtonClicked:(id)sender { // open a dialog with just an OK button UIActionSheet *actionSheet = [[UIActionSheet alloc] initWithTitle:nil delegate:self cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:[NSString stringWithFormat:@"Phone: %@",phone],nil]; actionSheet.actionSheetStyle = UIActionSheetStyleDefault; [actionSheet showInView:self.view]; // show from our table view (pops up in the middle of the table) [actionSheet release]; } -(IBAction) mapButtonClicked:(id)sender { // open a dialog with just an OK button UIActionSheet *mapActionSheet = [[UIActionSheet alloc] initWithTitle:nil delegate:self cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:[NSString stringWithFormat:@"Map"],nil]; mapActionSheet.actionSheetStyle = UIActionSheetStyleDefault; [mapActionSheet showInView:self.view]; // show from our table view (pops up in the middle of the table) [mapActionSheet release]; } -(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex { if(buttonIndex == 0){ NSString *callPhone = [NSString stringWithFormat:@"tel:%@",phone]; NSLog(@"Calling: %@", callPhone); [[UIApplication sharedApplication] openURL:[NSURL URLWithString:callPhone]]; } }

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  • How to make quicksilver remember custom trigger

    - by corroded
    I am trying to make a custom trigger for my shell/apple script file to run so I can just launch my dev environment at the push of a button. So basically: I have a shell script(and some apple script included) in ~ named start_server.sh which does 3 things: start up solr server start up memcached start up script/server I have a saved quicksilver command(.qs) that opens up start_server.sh(so start_server.sh, then the action is "Run in Terminal") I created a custom trigger that calls this saved qs command. I did that then tested it and it works. I then tried to double check it so I quit quicksilver and when I checked the triggers it just said: "Open (null)" as the action. I set the trigger again and when i restarted QS the same thing happened again. I don't know why but my old custom trigger to open terminal has worked since forever so why doesn't this one work? Here's a screenie of the triggers after I restart QS: http://grab.by/4XWW If you have any other suggestion on how to make a "push button" start for my server then please do so :) Thanks! As an added note, I have already tried the steps on this thread but to no avail: http://groups.google.com/group/blacktree-quicksilver/browse_thread/thread/7b65ecf6625f8989

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  • jquery show / hide div on click even in a slideshow?

    - by KnockKnockWhosThere
    Is it possible to combine a slideshow and show / hide div functionality? My html structure is below, and basically, I'm trying to get the tabs a links to open up the div with the corresponding class if a user clicks on it. If a user doesn't click on it, it should still just cycle through each image. So, if the images are rotating, and I click on <a class="t2"> then would open. The thing is, it's unknown how many divs / tabs there will be, but they'll always be named t{n}. <div id="tab-content"> <div class="t1">content</div> <div class="t2">lorem ipsum</div> <div class="t3">knock knock</div> </div> <div id="nav"> <div id="tabs"> <ul> <li class="t1"><a class="t1" href="#">tab 1</a></li> <li class="t2"><a class="t2" href="#">tab 2</a></li> <li class="t3"><a class="t3" href="#">tab 3</a></li> </ul> </div> </div>

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  • jsf, richfaces, popup window

    - by Hubidubi
    Hi I would like to make a list-detail view with richfaces. There will be a link for every record in the list that should open a new window containing record details. I tried to implement the link this way: <a4j:commandLink oncomplete="window.open('/pages/serviceDetail.jsf','popupWindow', 'dependent=yes, menubar=no, toolbar=no, height=500, width=400')" actionListener="#{monitoringBean.recordDetail}" value="details" /> I use <a4j:keepAlive beanName="monitoringBean" ajaxOnly="false" /> for both the list and the detail page. recordDetail method fills the data of the selected record to a variable of the bean that I would like to display on the detail page. The problem is that keepalive doesn't work, so I get new bean instance on the detail page every time. So the the previously selected record from the other bean is not accessible here. Is there a way to pass parameter (id) to the detail page to handle record selection. Or is there any way to make keepalive work? (I this this would be the easiest). Thanks

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  • Why do I get "Bad File Descriptor" when I try to read a file with Perl?

    - by Magicked
    I'm trying to read a binary file 40 bytes at a time, then check to see if all those bytes are 0x00, and if so ignore them. If not, it will write them back out to another file (basically just cutting out large blocks of null bytes). This may not be the most efficient way to do this, but I'm not worried about that. However, right now I'm getting a "Bad File Descriptor" error and I cannot figure out why. my $comp = "\x00" * 40; my $byte_count = 0; my $infile = "/home/magicked/image1"; my $outfile = "/home/magicked/image1_short"; open IN, "<$infile"; open OUT, ">$outfile"; binmode IN; binmode OUT; my ($buf, $data, $n); while (read (IN, $buf, 40)) { ### Problem is here ### $boo = 1; for ($i = 0; $i < 40; $i++) { if ($comp[$i] != $buf[$i]) { $i = 40; print OUT $buf; $byte_count += 40; } } } die "Problems! $!\n" if $!; close OUT; close IN; I marked with a comment where it is breaking. Thanks for any help!

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  • mysql: storing arbitrary data

    - by Hailwood
    Background: I was asking a question on stack overflow regarding creating tables on the fly where this conversation ensued: This smells like a terrible idea! In fact, it smells just like this one. What in the world do you want to use this for? – deceze @deceze: very true, However, How else would you store the contents of these CSV files. They must be stored in mysql for indexing. The only solid fact about them is that they all have a mobile column with a standard format. The CSV can have an arbitrary amount of columns with an arbitrary amount of rows. They can (with no exaggeration) range from a single row, 35 column csv to an 80k row single column CSV. I am open to other ideas. – Hailwood There are many solutions for this, from attribute-value schemas to JSON storage and NoSQL storage. Open a new question about it. Whatever you do though, don't dynamically create tables! – deceze Question: So my question is, What would you say is the best way to store this data? Are you in agreement with deceze about not creating dynamic tables?

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  • sql server mdf file database attachment

    - by jnsohnumr
    hello all i'm having a bear of a time getting visual studio 2010 (ultimate i think) to properly attach to my database. it was moved from original spot to #MYAPP#/#MYAPP#.Web/App_Data/#MDF_FILE#.mdf. I have three instances of sql server running on this machine. i have tried to replace the old mdf file with my new one and cannot get the connectionstring right for it. what i'm really wanting to do is to just open some DB instance, run a DB create script. Then I can have a DB that was generated via my edmx (generate database from model) in silverlight business application (c#) right now, when i go to server explorer in VS, choose add new connection, choose MS SQL Server Database FIle (SqlClient), choose my file location (app_data directory), use windows authentication, and hit the Test Connection button I get the following error: Unable to open the physical file "". Operating system error 5: "5(Access Denied.)". An attempt to attach to an auto-named database for file"" failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share. The mdf file was created on the same machine by connecting to (local) on the sql server management studio, getting a new query, pasting in the SQL from the generated ddl file, adding a CREATE DATABASE [NcrCarDatabase]; GO before the pasted SQL, and executing the query. I then disconnected from the DB in management studio, closed management studio, navigated to the DATA directory for that instance, and copying the mdf and ldf files to my application's app_data folder. I am then trying to connect to the same file inside visual studio. I hope that gives more clarity to my problems :). Connection string is: Data Source=.\SQLEXPRESS;AttachDbFilename=C:\SourceCode\NcrCarDatabase\NcrCarDatabase.Web\App_Data\NcrCarDatabase.mdf;Integrated Security=True;Connect Timeout=30;User Instance=True

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  • Amazon Product API ResponseGroups and Default results

    - by aboxy
    A. In our application, most of the data we work with is stored as free text .i.e. there is no categorization done as of now. We are using openNLP libraries to make sense of the data(extract keywords/classify) and do a query to Amazon web services to pull the results of the query. We use searchindex=All and keywords=. Results are not always returned and we basically get 'AWS.ECommerceService.NoExactMatches' How to avoid that? 1) Is there a way to specify default results if no match found? e.g. Amazon carousel widget does that if the search query did not return results, it basically show some computer items. 2) Should I batch the request always and add another search criteria to every request? If my first criteria does not pull any results, we can be sure that our 2nd query will always pull results(possibly caching?) Here is one search criteria 'Open Circle Hoop Earrings Polished Stainless Steel Open Circle Hoop Earrings Polished Stainless Steel DiamondShark' This return no results via API. On Amazon site,I get alternative suggestions with some results which are pretty relevant. Is there a way to pull those results? B. We just need a thumbnail image and a title and description for our app. Which responseGroup is appropriate? We are using medium rt now but there is awful lot of information even with that responseGroup. Any help is appreciated. thanks

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  • How can I send multiple images in a server push Perl CGI program?

    - by Jujjuru
    I am a beginner in Perl CGI etc. I was experimenting with server-push concept with a piece of Perl code. It is supposed to send a jpeg image to the client every three seconds. Unfortunately nothing seems to work. Can somebody help identify the problem? Here is the code: use strict; # turn off io buffering $|=1; print "Content-type: multipart/x-mixed-replace;"; print "boundary=magicalboundarystring\n\n"; print "--magicalboundarystring\n"; #list the jpg images my(@file_list) = glob "*.jpg"; my($file) = ""; foreach $file(@file_list ) { open FILE,">", $file or die "Cannot open file $file: $!"; print "Content-type: image/jpeg\n\n"; while ( <FILE> ) { print "$_"; } close FILE; print "\n--magicalboundarystring\n"; sleep 3; next; } EDIT: added turn off i/o buffering, added "use strict" and "@file_list", "$file" are made local

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  • c programming malloc question

    - by user535256
    Hello guys, Just got query regarding c malloc() function. I am read()ing x number of bytes from a file to get lenght of filename, like ' read(file, &namelen, sizeof(unsigned char)); ' . The variable namelen is a type unsigned char and was written into file as that type (1 byte). Now namelen has the lenght of filename ie namelen=8 if file name was 'data.txt', plus extra /0 at end, that working fine. Now I have a structure recording file info, ie filename, filelenght, content size etc. struct fileinfo { char *name; ...... other variable like size etc }; struct fileinfo *files; Question: I want to make that files.name variable the size of namelen ie 8 so I can successfully write the filename into it, like ' files[i].name = malloc(namelen) ' However, I dont want it to be malloc(sizeof(namelen)) as that would make it file.name[1] as the size of its type unsigned char. I want it to be the value thats stored inside variable &namelen ie 8 so file.name[8] so data.txt can be read() from file as 8 bytes and written straight into file.name[8? Is there a way to do this my current code is this and returns 4 not 8 files[i].name = malloc(namelen); //strlen(files[i].name) - returns 4 //perhaps something like malloc(sizeof(&namelen)) but does not work Thanks for any suggestions Have tried suggested suggestions guys, but I now get a segmentation fault error using: printf("\nsizeofnamelen=%x\n",namelen); //gives 8 for data.txt files[i].name = malloc(namelen + 1); read(file, &files[i].name, namelen); int len=strlen(files[i].name); printf("\nnamelen=%d",len); printf("\nname=%s\n",files[i].name); When I try to open() file with that files[i].name variable it wont open so the data does not appear to be getting written inside the read() &files[i].name and strlen() causes segemntation error as well as trying to print the filename

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  • Android XML Preference issue. Can't make it persistent

    - by Budius
    I have a very simple activity just to show the preference fragment: public class PreferencesActivity extends Activity { Fragment frag = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); FragmentTransaction ft = getFragmentManager().beginTransaction(); if (frag == null) { // If not, instantiate and add it to the activity frag = new PrefsFragment(); ft.add(android.R.id.content, frag, frag.getClass().getName()); } else { // If it exists, simply attach it in order to show it ft.attach(frag); } ft.commit(); } private static class PrefsFragment extends PreferenceFragment { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); addPreferencesFromResource(R.xml.preferences); } } } and preferences.xml with persistent to true: <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android" android:enabled="true" android:persistent="true" android:title="@string/settings" > <EditTextPreference android:dialogTitle="@string/dialog_ip" android:negativeButtonText="@android:string/cancel" android:persistent="true" android:positiveButtonText="@android:string/ok" android:title="@string/ip" /> </PreferenceScreen> if I open the EditTextPreference, write something, close the dialog and open it again. The value is still there. But that's it... if I click the Back button, and enter the again on the preferences screen, I already lost what was written. If you exit the application also doesn't save. Am I missing something here? Running on: Android 4.0.3 Asus TF300

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