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  • tint2 - short format date?

    - by Tedee12345
    How to shorten the format of the date on this format? 09:58 @ nie 20 paz This is the configuration file: #--------------------------------------------- # CLOCK #--------------------------------------------- time1_format = %H:%M @ %A %d %B time1_font = Visitor TT1 BRK 10 #time2_format = %A %d %B time2_font = (null) clock_font_color = #ffffff 76 clock_padding = 2 1 clock_background_id = 0 Thank you for your help.

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  • How to insert custom date time in oracle using java?

    - by shree
    Hi i have a column (type date).I want to insert custom date and time without using Preparedstatement .i have used String date = sf.format(Calendar.getInstance().getTime()); String query = "Insert into entryTbl(name, joinedDate, ..etc) values ("abc", to_date(date, 'yyyy/mm/dd HH:mm:ss'))"; statement.executeUpdate(query); but am getting literal doesnot match error. so even tried with "SYSDATE".Its inserting only date not time.So how to insert the datetime using java into oracle?please any one help..

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  • Making bash script to check connectivity and change connection if necessary. Help me improve it?

    - by cypherpunks
    My connection is flaky, however I have a backup one. I made some bash script to check for connectivity and change connection if the present one is dead. Please help me improve them. The scripts almost works, except for not waiting long enough to receive an IP (it cycles to next step in the until loop too quick). Here goes: #!/bin/bash # Invoke this script with paths to your connection specific scripts, for example # ./gotnet.sh ./connection.sh ./connection2.sh until [ -z "$1" ] # Try different connections until we are online... do if eval "ping -c 1 google.com" then echo "we are online!" && break else $1 # Runs (next) connection-script. echo fi shift done echo # Extra line feed. exit 0 And here is an example of the slave scripts: #!/bin/bash ifconfig wlan0 down ifconfig wlan0 up iwconfig wlan0 key 1234567890 iwconfig wlan0 essid example sleep 1 dhclient -1 -nw wlan0 sleep 3 exit 0

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  • How can I program ksh93 to use bash autocompletion?

    - by Norman Ramsey
    In a comment in response to a shell question, user tinkertim said that it was easy to hack ksh to use the bash autocompletion library. I would like nothing better than to use bash autocompletion with AT&T ksh93. How can this be done? ksh93 has a new release several times a year, so I am looking for a solution that does not involve modifying the source code. ksh93 can link new C modules dynamically and also is highly programmable (I run a ksh function at every keystroke), so modifying the source should not really be necessary. Note: I am not talking about filename autocompletion, which is easy to do in ksh. I'm talking about all the other yummy autocompletion stuff that bash does, like autocompletion options for nmh commands or autocompleting Mercurial commmands. Stuff like that.

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  • Transmogrify into date from multiple columns

    - by Dave Jarvis
    What is a better way to program the following SQL: str_to_date( concat(convert(D.DAY, CHAR(2)), '-', convert(M.MONTH, CHAR(2)), '-', convert(M.YEAR, CHAR(4))), '%e-%m-%Y' ) as AMOUNT_DATE I want to convert the columns D.DAY, M.MONTH, and M.YEAR to a date field using MySQL. The above works, but seems much more complicated than it needs to be. (If there's an ANSI SQL way to do it, that would be even better.) Thank you!

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  • Is there a better way to format this date string

    - by Mark Breen
    Hello is there are better way to structure this line of code, as you can see, I am changing the format of a string that contains a date. lblCourseStartDate.Text = String.Format("{0:D}", DateTime.Parse(CourseStartDate)); I just found it untidy that I am converting twice or three times to get the format I want. Thanks

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  • Compare two times without regard to Date associated - Ruby

    - by H55nick
    I am trying to find the difference in time (without days/years/months) of two different days. Example: #ruby >1.9 time1 = Time.now - 1.day time2 = Time.now #code to make changes #test: time1 == time2 # TRUE My solution: time1 = time1.strftime("%h:%m").to_time time2 = time2.strftime("%h:%m").to_time #test time1 == time2 #True #passes I was wondering if there was a better way of doing this? Maybe we could keep the Date the same as time1/time2?

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  • JavaScript date comparisons

    - by Kyle
    I am new to the lower level useful functions of JavaScript, and I find myself needing to compare two date objects, but within an hourly range. For example, if Date1 is less then two hours until (or from) Date2. How could this be done?

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  • extending Bash tab completion: how to handle paths / partial commands?

    - by Rawing
    I've added tab completion for my program to bash. It works quite well, but I don't know how to handle partial completion of words. Example: the user types ./program /home/user/De and presses TAB. This is then completed to ./program /home/user/Desktop/ , but there's now a trailing whitespace after 'Desktop/', which is not what I want. Basically, I need a way of preventing bash from adding whitespace after the completed word. I don't want to use bash's completion for paths.

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  • What scripts should not be ported from bash to python?

    - by Jack
    I decided to rewrite all our Bash scripts in Python (there are not so many of them) as my first Python project. The reason for it is that although being quite fluent in Bash I feel it's somewhat archaic language and since our system is in the first stages of its developments I think switching to Python now will be the right thing to do. Are there scripts that should always be written in Bash? For example, we have an init.d daemon script - is it OK to use Python for it? We run CentOS. Thanks.

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  • JQuery Date() Function Not Working

    - by bdaniels
    Anyone know why this doesn't work? var lastReceivedBeginDate = new Date($("input[name='lastReceivedFromYear']").val(),$("input[name='lastReceivedFromMonth']").val(),$("input[name='lastReceivedFromDay']").val(),$("input[name='lastReceivedFromHour']").val(),$("input[name='lastReceivedFromMinute']").val(),$("input[name='lastReceivedFromSecond']").val()); Thx

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  • Javascript Date: Ensure getMinutes(), getHours(), getSeconds() puts 0 in front if necessary

    - by Mega Matt
    Hi all, Looking for a creative way to be sure values that come from the getHours, getMinutes, and getSeconds() method for the javascript Date object return "06" instead of 6 (for example). Are there any parameters that I don't know about? Obviously I could write a function that does it by checking the length and prepending a "0" if need be, but I thought there might be something more streamlined than that. Thanks.

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  • Print ssh and su chain

    - by user1824885
    Is there a way to show the complete ssh and su chain in bash? For example. In Server A as user aa: su - ab ssh ba@B su - bb Thus, I would like a command that prints something like this: 1 bash aa in A 2 su ab in A 3 ssh ba in B 4 su bb in B I tried pstree but it does not print the users and only works with the processes of the last ssh'ed server: $ pstree | grep -C 5 pstree serversshd---sshd---sshd---bash---su---bash-+-grep | `-pstree Thanks and regards.

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  • Why does bash sometimes think my $HOME isn't the correct directory?

    - by Adam Yanalunas
    Like the title says it seems that bash sometimes misidentifies my $HOME. This cropped up after a seemingly unique series of events that I will now replay in broad strokes. Running OS X 10.6 with normal, local account Work binds my account to Active Directory Much time passes with no issues Set up rvm to manage Ruby installs (this becomes important later) Upgraded to OS X 10.7 a few days ago After successful install, attempted to log in, was presented with "Must reset password" dialog that never allowed a password to be reset. Would simply shake the box after new password was entered. Much googling was done. Much more googling was done. Swearing was had. Logged in as root, created new account, set as admin, deleted /Users/[new account], renamed /Users/[old account] to /Users/[new account] Logged out of root, logged into new account with no issues After OS X asking for a my account password a few times to update Keychain and other system-level stuff it was back to business as usual. Opened Terminal, cd to project folder, tried "rails server" and was presented with: /usr/local/lib/ruby/1.9.1/rubygems/dependency.rb:247:in to_specs': Could not find rails (>= 0) amongst [] (Gem::LoadError) from /usr/local/lib/ruby/1.9.1/rubygems/dependency.rb:256:into_spec' from /usr/local/lib/ruby/1.9.1/rubygems.rb:1210:in gem' from /usr/local/bin/rails:18:in' Ran through a few exercises, decided to rm -rf ~/.rvm and reinstall. Running a --trace on the rvm installer shows it dies on this line: mkdir: /Users/[old account]: Permission denied Scrolling back through the --trace log I see many more mentions of /Users/[old account]. When inspect the install script the offending line is looking at "${HOME}/.rvm" as it tries to run the mkdir. To my confusion I also see mentions of /Users/[new account] in the log. I've tried exporting a new HOME in my .bash_profile to no luck. Can anyone guess why /Users/[old account] would still be kicking around?

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  • On Ubuntu get: "-bash: ./flume No such file or directory" BUT flume is there and executable. Same binary OK on RHEL

    - by lcbrevard
    This is already posted in serverfault - and may be more apprpriate there. Reworked a bit from the orginal posting. We have a product built on CentOS 4 32-bit Linux that runs unmodified on 32- and 64-bit CentOS/RHEL 4 and 5 and SLES 10. It also runs unmodified on SLES 9 64-bit. [SLES 9 32-bit requires a different libstdc++.] The name of the main binary executable is 'flume' Yesterday we tried to put this on 64-bit Ubuntu 10 and, even though the file is there and the right size, we get: -bash: ./flume: No such file or directory 'file flume' shows it to be a 32-bit ELF (can't remember the exact output and the system is on an isolated network) If put into /usr/local/bin, then 'which flume' returns: /usr/local/bin/flume The file is marked as executable (did 'chmod +x flume') and lsattr shows no problems with attribute bits. I was not able to try 'ldd flume' yet. I have also not tried 'strace flume'. Currently I am with an air conditioning failure. [It's been that kind of week!] I now suspect that some library is not there. This is a profoundly unhelpful message and one I have never seen before. Is this peculiar to Ubuntu or perhaps just to this installation. We gave up and moved to a RHEL 4 system and everything is fine. But I sure would like to know what causes this.

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  • Recommended: git-completion.bash

    - by andy.grover
    If you use git on a daily basis like I do, git-completion.bash is a great way to make your life a little easier. While I guess it does add tab-completion for git commands, the most useful feature for me is the ability to put the current branch into the cmdline prompt. Now that I am comfortable working with multiple git branches and remotes, a little reminder where I am prevents time-consuming mistakes. git-completion.bash lives in git's git tree.git clone git://git.kernel.org/pub/scm/git/git.gitcopy git/contrib/completion/git-completion.bash to ~/.git-completion.shFollow the instructions in the file to set up, and enable showing branch in $PS1I also use this alias in my ~/.gitconfig, which is convenient:[alias]        log1 = log --pretty=oneline --abbrev-commitHave fun!

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  • Javascript Date Range Validation

    Here is a Javascript function that will tell you if 2 dates make a valid date range. function isValidDateRange( objstartMonth,objstartDay, objstartYear, objendMonth,objendDay, objendYear) { var startDate = new Date(objstartYear.options[objstartYear.selectedIndex].value, objstartMonth.options[objstartMonth.selectedIndex].value, objstartDay.options[objstartDay.selectedIndex].value); var endDate = new Date(objendYear.options[objendYear.selectedIndex].value, objendMonth.options[objendMonth.selectedIndex].value, objendDay.options[objendDay.selectedIndex].value); if (startDate >= endDate){ alert("Invaild Date Range"); return false; } else{ return true; } }

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  • How to improve this bash shell script for turning hardlinks into symlinks?

    - by MountainX
    This shell script is mostly the work of other people. It has gone through several iterations, and I have tweaked it slightly while also trying to fully understand how it works. I think I understand it now, but I don't have confidence to significantly alter it on my own and risk losing data when I run the altered version. So I would appreciate some expert guidance on how to improve this script. The changes I am seeking are: make it even more robust to any strange file names, if possible. It currently handles spaces in file names, but not newlines. I can live with that (because I try to find any file names with newlines and get rid of them). make it more intelligent about which file gets retained as the actual inode content and which file(s) become sym links. I would like to be able to choose to retain the file that is either a) the shortest path, b) the longest path or c) has the filename with the most alpha characters (which will probably be the most descriptive name). allow it to read the directories to process either from parameters passed in or from a file. optionally, write a long of all changes and/or all files not processed. Of all of these, #2 is the most important for me right now. I need to process some files with it and I need to improve the way it chooses which files to turn into symlinks. (I tried using things like the find option -depth without success.) Here's the current script: #!/bin/bash # clean up known problematic files first. ## find /home -type f -wholename '*Icon* ## *' -exec rm '{}' \; # Configure script environment # ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ set -o nounset dir='/SOME/PATH/HERE/' # For each path which has multiple links # ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ # (except ones containing newline) last_inode= while IFS= read -r path_info do #echo "DEBUG: path_info: '$path_info'" inode=${path_info%%:*} path=${path_info#*:} if [[ $last_inode != $inode ]]; then last_inode=$inode path_to_keep=$path else printf "ln -s\t'$path_to_keep'\t'$path'\n" rm "$path" ln -s "$path_to_keep" "$path" fi done < <( find "$dir" -type f -links +1 ! -wholename '* *' -printf '%i:%p\n' | sort --field-separator=: ) # Warn about any excluded files # ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ buf=$( find "$dir" -type f -links +1 -path '* *' ) if [[ $buf != '' ]]; then echo 'Some files not processed because their paths contained newline(s):'$'\n'"$buf" fi exit 0

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  • How to convert String format dates to Date format dates?

    - by Jani Bela
    I have a string with dates it looks like: "20120316 20120317 20120318" ... I store this dates in this format, but I would like to make a Date array from these numbers with the format 03/16 03/17 03/18 ... So far: String[] DailyDatasOnce2 = DatesOnce.split(" "); DailyDatasOnce = new String[DailyDatasOnce2.length]; for (int i=0;i< (DailyDatasOnce2.length) ;i++){ DailyDatasOnce[i]=DailyDatasOnce2[i]; } datumok = new Date[DailyDatasOnce.length]; for (int i=0;i< (DailyDatasOnce.length) ;i++){ SimpleDateFormat curFormater = new SimpleDateFormat("yyyyMMdd"); java.util.Date dateObj = null; java.util.Date dateObj2 = null; try { dateObj = curFormater.parse(DailyDatasOnce[i]); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } SimpleDateFormat postFormater = new SimpleDateFormat("MM/dd"); String newDateStr = postFormater.format(dateObj); try { dateObj2 = curFormater.parse(newDateStr); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } datumok[i] = dateObj2; } So first I make a string array with the string dates (DailyDatasOnce), maybe that first for loop is useless but i can skip it. Now I make a Date array and I want to put the dates into it. I format the dates to format I want, then I try to convert them to Date format. Until the String newDateStr it is working, I manage to change the type of the date. But I get syntax error: Type mismatch: Cannot convert from java.util.date to java.sql.data. I suspect the problem but if it is not possible, how can i do this?

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  • how to transfer a time which was zero at year of 0000(maybe) to java.util.Date

    - by hguser
    I have a gps time in the database,and when I do some query,I have to use the java.util.Date,however I found that I do not know how to change the gps time to java.util.Date. Here is a example: The readable time === The GPS time 2010-11-15 13:10:00 === 634254192000000000 2010-11-15 14:10:00 === 634254228000000000 The period of the two date is "36000000000",,obviously it stands for one hour,so I think the unit of the gps time in the db must be nanosecond. 1 hour =3600 seconds= 3600*1000 milliseconds == 3600*1000*10000 nanoseconds Then I try to convert the gps time: Take the " 634254228000000000" as example,it stands for("2010-11-15 14:10:00"); SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ssZ"); Date d = new Date(63425422800000L); System.out.println(sdf.format(d)); The result is 3979-11-15 13:00:00+0000. Of course it is wrong,then I try to calculate : 63425422800000/3600000/24/365=2011.xxx So it seems that the gps time here is not calcuated from Epoch(1970-01-01 00:00:00+0000). It maybe something like (0001-01-01 00:00:00+0000). Then I try to use the following method: Date date_0=sdf.parse("0001-01-01 00:00:00+0000"); Date d = new Date(63425422800000L); System.out.println(sdf.format(d.getTime() + date_0.getTime())); The result is: 2010-11-13 13:00:00+0000. :( Now I am confusing about how to calculate this gps time. Any suggestion?

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