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  • JPA + Hibernate + Named Query + how to JOIN a subquery result

    - by Srihari
    Can anybody help me in converting the following native query into a Named Query? Native Query: SELECT usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, count(material.material_id) as "Total Book Count", fpc.FOLLETT_PENDING_COUNT as "Follett Pending Count", rrc.RESOLUTION_REQUIRED_COUNT as "Resolution Required Count" FROM va_school sch JOIN va_user_school_rel usr1 on sch.school_id=usr1.school_id JOIN va_user_role_rel urr1 on usr1.user_id=urr1.user_id and urr1.role_id=1001 JOIN va_user_school_rel usr2 on sch.school_id=usr2.school_id JOIN va_user_role_rel urr2 on usr2.user_id=urr2.user_id and urr2.role_id=1002 JOIN va_term term on term.school_id = usr1.school_id JOIN va_class course on course.term_id = term.term_id JOIN va_material material on material.class_id = course.class_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "FOLLETT_PENDING_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 0 GROUP BY VA_CLASS.TERM_ID) fpc on term.term_id = fpc.term_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "RESOLUTION_REQUIRED_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 1 GROUP BY VA_CLASS.TERM_ID) rrc on term.term_id = rrc.term_id WHERE course.reference_flag = 'A' GROUP BY usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, fpc.FOLLETT_PENDING_COUNT, rrc.RESOLUTION_REQUIRED_COUNT ORDER BY usr1.school_id, term.term_name; Thanks in advance. Srihari

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  • get equation from XML, AS3

    - by VideoDnd
    There's an variable in my swf I want to receive XML. It's an integer value in the form of an equation. How do I receive the XML value for 'formatcount'? My Variable //Variable I want to grab XML<br> //formatcount=int('want xml value to go here'); formatcount=int(count*count/100); Path formatcount = myXML.FORMATCOUNT.text() My XML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">1000</TIMER> <COUNT TITLE="starting position">10000</COUNT> <FORMATCOUNT TITLE="ramp">count*count/1000</FORMATCOUNT> </SESSION>

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  • Do MSDN subscriptions count as licenses for the purposes of upgrade pricing?

    - by Roger Lipscombe
    To qualify for upgrade pricing of Expression Studio... You must be a licensed user of one of the following products to be eligible for the upgrade versions. Any Microsoft® Expression product Any Adobe Creative Suite product Microsoft Visual Studio 2005 or later I've got a boxed, retail copy of Visual Studio 2003, so it appears I've missed that particular boat. On the other hand, I've got an MSDN Professional subscription, which includes Visual Studio. Does this copy of Visual Studio entitle me to upgrade pricing on Expression Studio? Given that you can't get Visual Studio without an MSDN subscription, I figure it does, but I can't find anything definitive.

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  • How to the view count of a question in momery?

    - by Freewind
    My website is like stackoverflow, there are many questions. I want to record how many times a question has been visited. I have a column called "view_count" in the question table to save it. When a user visited a question many times, the view_count should be increased only 1. So I have to record which user has visited which question, and I think it is too much expensive to save them in the database, because the records will be huge. So I want to keep them in the memory, and persistent the number to database every 10 minutes. I have searched about "cache" of rails, but I haven't found an example. I need an simple sample of how to do this, thanks for help~

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  • JPA + Hibernate + Named Query + how to JOIN a subquery result

    - by Srihari
    Hi, Can anybody help me in converting the following native query into a Named Query? Native Query: SELECT usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, count(material.material_id) as "Total Book Count", fpc.FOLLETT_PENDING_COUNT as "Follett Pending Count", rrc.RESOLUTION_REQUIRED_COUNT as "Resolution Required Count" FROM va_school sch JOIN va_user_school_rel usr1 on sch.school_id=usr1.school_id JOIN va_user_role_rel urr1 on usr1.user_id=urr1.user_id and urr1.role_id=1001 JOIN va_user_school_rel usr2 on sch.school_id=usr2.school_id JOIN va_user_role_rel urr2 on usr2.user_id=urr2.user_id and urr2.role_id=1002 JOIN va_term term on term.school_id = usr1.school_id JOIN va_class course on course.term_id = term.term_id JOIN va_material material on material.class_id = course.class_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "FOLLETT_PENDING_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 0 GROUP BY VA_CLASS.TERM_ID) fpc on term.term_id = fpc.term_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "RESOLUTION_REQUIRED_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 1 GROUP BY VA_CLASS.TERM_ID) rrc on term.term_id = rrc.term_id WHERE course.reference_flag = 'A' GROUP BY usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, fpc.FOLLETT_PENDING_COUNT, rrc.RESOLUTION_REQUIRED_COUNT ORDER BY usr1.school_id, term.term_name; Thanks in advance. Srihari

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  • What calendar appears to count days since december 28, 1800?

    - by Sander Marechal
    Hello, I have been tasked to read in some data from some weird old system. The system contains many dates but they are all oddly formatted. They are integer numbers ranging from approximately 55,000 to 80,000. I know two dates for certain: 58,112 equals February 2, 1960 61,439 equals March 16, 1969 It appears to me that those integer numbers are the number of days elapsed since December 28, 1800. But I think that's a very strange date to start a calendar on. There is probably going something on with leap years and what-not that is doing to bite me in the ass later on. Does anyone recognise this calendar? Can anyone tell me what the proper way is to convert those integers to human readable dates? Thanks in advance!

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  • Problem with Core Data - EXC_BAD_ACCESS

    - by BarrettJ
    I'm using the following code and I'm getting an EXC_BAD_ACCESS when trying to get the count of objects - anyone have any idea why? Oddly enough, the error only happens if the count should be one or greater, if there are no objects it seems to work fine (it outputs null). NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"TVShow" inManagedObjectContext:[self managedObjectContext]]; [fetchRequest setEntity:entity]; [fetchRequest includesPendingChanges]; //NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ID == %@", showId]; //[fetchRequest setPredicate:predicate]; NSError *error; NSLog(@"Generating Count"); NSUInteger count = [[self managedObjectContext] countForFetchRequest:fetchRequest error:&error]; if(count == NSNotFound) { NSLog(@"error"); } else { NSLog(@"%@", count); // EXC_BAD_ACCESS here } [fetchRequest release];

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  • How to save the view count of a question in memory?

    - by Freewind
    My website is like stackoverflow, there are many questions. I want to record how many times a question has been visited. I have a column called "view_count" in the question table to save it. If a user visits a question many times, the view_count should be increased only 1. So I have to record which user has visited which question, and I think it is too much expensive to save this information in the database because the records will be huge. So, I would like to keep the information in memory and only persist the number to the database every 10 minutes. I have searched about "cache" in Rails, but I haven't found an example. I would like a simple sample of how to do this, thanks for help~

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  • How to the view count of a question in memory?

    - by Freewind
    My website is like stackoverflow, there are many questions. I want to record how many times a question has been visited. I have a column called "view_count" in the question table to save it. If a user visits a question many times, the view_count should be increased only 1. So I have to record which user has visited which question, and I think it is too much expensive to save this information in the database because the records will be huge. So, I would like to keep the information in memory and only persist the number to the database every 10 minutes. I have searched about "cache" in Rails, but I haven't found an example. I would like a simple sample of how to do this, thanks for help~

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  • Apache with JBOSS using AJP (mod_jk) giving spikes in thread count.

    - by Beginner
    We used Apache with JBOSS for hosting our Application, but we found some issues related to thread handling of mod_jk. Our website comes under low traffic websites and has maximum 200-300 concurrent users during our website's peak activity time. As the traffic grows (not in terms of concurrent users, but in terms of cumulative requests which came to our server), the server stopped serving requests for long, although it didn't crash but could not serve the request till 20 mins. The JBOSS server console showed that 350 thread were busy on both servers although there was enough free memory say, more than 1-1.5 GB (2 servers for JBOSS were used which were 64 bits, 4 GB RAM allocated for JBOSS) In order to check the problem we were using JBOSS and Apache Web Consoles, and we were seeing that the thread were showing in S state for as long as minutes although our pages take around 4-5 seconds to be served. We took the thread dump and found that the threads were mostly in WAITING state which means that they were waiting indefinitely. These threads were not of our Application Classes but of AJP 8009 port. Could somebody help me in this, as somebody else might also got this issue and solved it somehow. In case any more information is required then let me know. Also is mod_proxy better than using mod_jk, or there are some other problems with mod_proxy which can be fatal for me if I switch to mod__proxy? The versions I used are as follows: Apache 2.0.52 JBOSS: 4.2.2 MOD_JK: 1.2.20 JDK: 1.6 Operating System: RHEL 4 Thanks for the help.

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  • Count all lists of adjacent nodes stored in an array.

    - by Ben Brodie
    There are many naive approaches to this problem, but I'm looking for a good solution. Here is the problem (will be implemented in Java): You have a function foo(int a, int b) that returns true if 'a' is "adjacent" to 'b' and false if 'a' is not adjacent to 'b'. You have an array such as this [1,4,5,9,3,2,6,15,89,11,24], but in reality has a very long length, like 120, and will be repeated over and over (its a genetic algorithm fitness function) which is why efficiency is important. I want a function that returns the length of each possible 'list' of adjacencies in the array, but not including the 'lists' which simply subsets of a larger list. For example, if foo(1,4) - true, foo(4,5) - true, foo(5,9)- false, foo(9,3) & foo(3,2) & foo(2,6), foo(6,15) - true, then there are 'lists' (1,4,5) and (9,3,2,6), so length 3 and 4. I don't want it to return (3,2,6), though, because this is simply a subset of 9,3,2,6. Thanks.

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  • How can I count paragraphs in text file using Perl?

    - by robjez
    I need to create Perl code which allows counting paragraphs in text files. I tried this and doesn't work: open(READFILE, "<$filename") or die "could not open file \"$filename\":$!"; $paragraphs = 0; my($c); while($c = getc(READFILE)) { if($C ne"\n") { $paragraphs++; } } close(READFILE); print("Paragraphs: $paragraphs\n");

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  • Need Help With Simple Counting Bug in iPhone SDK

    - by seanny94
    So I'm basically making an app that adds a count to a number and then displays it each time you tap the button. However, the first tap issued doesn't take any action but adds one (just as planned) on the second tap. I've searched to the ends of the earth looking for the solution with no luck, so I'll see what you guys can make of this. :) #import "MainView.h" @implementation MainView int count = 0; -(void)awakeFromNib { counter.text = @"0"; } - (IBAction)addUnit { if(count >= 999) return; NSString *numValue = [[NSString alloc] initWithFormat:@"%d", count++]; counter.text = numValue; [numValue release]; } - (IBAction)subtractUnit { if(count <= 0) return; NSString *numValue = [[NSString alloc] initWithFormat:@"%d", count--]; counter.text = numValue; [numValue release]; } @end

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  • SQL Query to delete oldest rows over a certain row count?

    - by Casey
    I have a table that contains log entries for a program I'm writing. I'm looking for ideas on an SQL query (I'm using SQL Server Express 2005) that will keep the newest X number of records, and delete the rest. I have a datetime column that is a timestamp for the log entry. I figure something like the following would work, but I'm not sure of the performance with the IN clause for larger numbers of records. Performance isn't critical, but I might as well do the best I can the first time. DELETE FROM MyTable WHERE PrimaryKey NOT IN (SELECT TOP 10,000 PrimaryKey FROM MyTable ORDER BY TimeStamp DESC)

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  • Python: does it make sense to refactor this check into it's own method?

    - by Jeff Fry
    I'm still learning python. I just wrote this method to determine if a player has won a game of tic-tac-toe yet, given a board state like:'[['o','x','x'],['x','o','-'],['x','o','o']]' def hasWon(board): players = ['x', 'o'] for player in players: for row in board: if row.count(player) == 3: return player top, mid, low = board for i in range(3): if [ top[i],mid[i],low[i] ].count(player) == 3: return player if [top[0],mid[1],low[2]].count(player) == 3: return player if [top[2],mid[1],low[0]].count(player) == 3: return player return None It occurred to me that I check lists of 3 chars several times and could refactor the checking to its own method like so: def check(list, player): if list.count(player) == 3: return player ...but then realized that all that really does is change lines like: if [ top[i],mid[i],low[i] ].count(player) == 3: return player to: if check( [top[i],mid[i],low[i]], player ): return player ...which frankly doesn't seem like much of an improvement. Do you see a better way to refactor this? Or in general a more Pythonic option? I'd love to hear it!

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  • Find out 20th, 30th, nth prime number. (I'm getting 20th but not 30th?) [Python]

    - by gsin
    The question is to find the 1000th prime number. I wrote the following python code for this. The problem is, I get the right answer for the 10th , 20th prime but after that each increment of 10 leaves me one off the mark. I can't catch the bug here :( count=1 #to keep count of prime numbers primes=() #tuple to hold primes candidate=3 #variable to test for primes while count<20: for x in range(2,candidate): if candidate%x==0: candidate=candidate+2 else : pass primes=primes+(candidate,) candidate=candidate+2 count=count+1 print primes print "20th prime is ", primes[-1] In case you're wondering, count is initialised as 1 because I am not testing for 2 as a prime number(I'm starting from 3) and candidate is being incremented by 2 because only odd numbers can be prime numbers. I know there are other ways of solving this problem, such as the prime number theorem but I wanna know what's wrong with this approach. Also if there are any optimisations you have in mind, please suggest. Thank You

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  • Selecting pictures with Jquery and Javascript

    - by Axschech
    I'm testing out a layout on a website using 3 pictures here: Schechterbusiness.info the left button works, making it go through the pictures. But I can't figure out how to get the right button to work, which is supposed to scroll through the other way. I know there's probably a way to do it with arrays but I can't wrap my brain around it. Halp! Code to scroll through pictures: $('#fryLink').click(function() { $('#hide').hide(); $('#img').hide(); count++; if(count == 1) { $('#img').attr("src","images/fry.png"); } else if(count == 2) { $('#img').attr("src","images/bender.png"); } else if(count == 3) { $('#img').attr("src","images/zoidberg.png"); } $('#img').show("fade"); if(count > 2) { count = 0; }

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  • How to make a report with count of type of cases in each month in Acess 2010

    - by amir shadaab
    I have a database is access with each record having a date and yes/no type columns for each record which shows which category the record comes under. I want to create a report which shows the types of cases in each month by taking a date range as a parameter through prompts. I have done the prompt part but I'm not sure how the query should be to show values for each month in that date range. Can someone please help me with this?

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  • How can I have sub-elements of a complex/mixed type with unrestricted order and count?

    - by mbmcavoy
    I am working with XML where some elements will contain text with additional markup. This is similar to this example at W3Schools. However, I need the markup tags to be able to appear in any order and possibly more than once. To modify their example for illustration: <letter> Dear Mr.<name>John Smith</name>. Your order <orderid>1032</orderid> will be shipped on <shipdate>2001-07-13</shipdate>. Thank you, <name>Bob Adams</name> </letter> None of the options presented by W3Schools (on the page following the linked example) allow this XML due to the second <name> element. Their explanation of the "indicators" and my testing are consistent. <xs:sequence> - violates the element order <xs:choice> - more than one kind of element is used. <xs:all> - maxOccurs is restricted to "1". This seems like it should be basic, after all, XHTML allows such things. How do I define my schema to allow this?

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  • how can we count the time interval of the animation in cocos2d ?

    - by srikanth rongali
    Hi, I am doing my program in cocos2d. I am using NSDate to get the current time of the start of animation. And I know my animation takes 3 seconds. So I can get the time at completion of animation by using NSInterval and using the previous time and animation time. But, if If the animation time interval is not fixed how can I calculate the time interval of the animation and time at the completion of the animation ? I am animating a sprite. Please help how can I make it. Thank You.

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