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  • Having to hit the site login button twice after first turning on computer

    - by John
    Hello, The code below is for a login that I'm using. It works fine, but when I first try logging in after turning on my computer, it only works the second time that I hit the "Login" button. Any idea how I can make it not require hitting the "Login" button twice in this situation? Thanks in advance, John function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; } EDIT: Here is another function that is used. function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; }

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  • Positioning Text Triggered by a Function

    - by John
    Hello, I would like the text below classed with "logintocomment" to appear 30 px below the bottom of the table classed with "commentecho." Instead, with the CSS and code below, the text classed with "logintocomment" is appearing at the bottom of the browser window. Any idea how I can make it do what I want? Thanks in advance, John In index file: include "comments.php"; include "commentformonoff.php"; In the file comments.php: echo "<table class=\"commentecho\">"; The file: commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } ?> The CSS: table.commentecho { margin-top: 230px; margin-left: 30px; text-align: left; font-family: "Times New Roman", Times, serif; font-weight: normal; font-size: 15px; color: #000000; width: 600px; table-layout:fixed; background-color: #FFFFFF; border: 2px #FFFFFF; border-collapse: collapse; border-spacing: 2px; padding: 1px; text-decoration: none; vertical-align: text-bottom; margin-bottom: 30px; } table.commentecho td { border: 2px solid #fff; text-align: left; height: 18px; overflow:hidden; } table.commentecho td a{ padding: 2px; color: #000000; text-decoration: none; overflow:hidden; height: 18px; } table.commentecho td a:hover{ background-color: #FFFFFF; padding: 2px; color: #FF0000; text-decoration: none; overflow:hidden; height: 18px; } .logintocomment { margin-top: 30px; margin-left: 30px; width:250px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 20px; color:#000000; }

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  • How to find index of an object by key and value in an javascript array

    - by return1.at
    Given: var peoples = [ { "attr1": "bob", "attr2": "pizza" }, { "attr1": "john", "attr2": "sushi" }, { "attr1": "larry", "attr2": "hummus" } ]; Wanted: Index of object where attr === value for example attr1 === "john" or attr2 === "hummus" Update: Please, read my question carefully, i do not want to find the object via $.inArray nor i want to get the value of a specific object attribute. Please consider this for your answers. Thanks!

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  • Need help with SQL Query

    - by StackOverflowNewbie
    Say I have 2 tables: Person - Id - Name PersonAttribute - Id - PersonId - Name - Value Further, let's say that each person had 2 attributes (say, gender and age). A sample record would be like this: Person->Id = 1 Person->Name = 'John Doe' PersonAttribute->Id = 1 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Gender' PersonAttribute->Value = 'Male' PersonAttribute->Id = 2 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Age' PersonAttribute->Value = '30' Question: how do I query this such that I get a result like this: 'John Doe', 'Male', '30'

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  • Get list of duplicate rows in MySql

    - by user347033
    Hi, i have a table like this ID nachname vorname 1 john doe 2 john doe 3 jim doe 4 Michael Knight I need a query that will return all the fields (select *) from the records that have the same nachname and vorname (in this case, records 1 and 2). Can anyone help me with this? Thanks

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  • Can Ejabberd Support Offline File Transfer?

    - by user359277
    Hi, I am working on a xmpp client, using eJabberd as server. My question is How can I support offline file transferring? I only want to do the offline file transferring for Image file. For example, I can transfer an image to John even he is offline. When John come back Online, the server will send him the image. How can I do that? Thanks

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  • Using GET Method to Maintain Variables After Logging In

    - by John
    Hello, I am using a login system. When I navigate to comments/index.php without logging in, some variables get passed along using the GET method just fine. Then, if I log in while I am on this page, these variables disappear. The variables that disappear are $submission, $submissionid, and $url. I thought I could use the GET method to keep them live after logging in by appending ?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.' to the URL of the login form action as seen below. But the variables still disappeared after I made this addition. The relevant code I am trying to use is below. Any idea what I can do to make it do what I want? Thanks in advance, John In comments/index.php: require_once "header.php"; include "login.php"; include "comments.php"; In login.php: if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } In comments.php: $url = mysql_real_escape_string($_GET['url']); echo '<div class="subcommenttitle"><a href="http://www.'.$url.'">'.$submission.'</a></div>'; $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); The login function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • Passing Variables Along in a Function

    - by John
    Hello, In the function show_commentbox() below, I would like to pass along the variables $_SESSION['loginid'], $submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl. With the setup below, it's not working. How could I change it to make show_commentbox() pass the variables along? Thanks in advance, John index.php: <?php $submission = $_GET['submission']; require_once "header.php"; include "login.php"; include "comments.php"; include "commentformonoff.php"; ?> In header.php: require_once ("function.inc.php"); In comments.php: $uid = $_SESSION['loginid']; $submissiondate = mysql_real_escape_string($_GET['submissiondate']); $submittor = mysql_real_escape_string($_GET['submittor']); $countcomments = mysql_real_escape_string($_GET['countcomments']); $dispurl = mysql_real_escape_string($_GET['dispurl']); $url = mysql_real_escape_string($_GET['url']); $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox(); } else { echo "Login to comment"; } } else { echo "Login to comment"; } } else { show_commentbox(); } ?> In display.functions.inc.php: function show_commentbox() { echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; }

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  • Converting OpenGL co-ordinates to lower UIView (and UIImagePickerController)

    - by John Qualis
    Hi, I am new to OpenGL over iPhone. I am developing an iPhone app similar to a barcode reader but with an extra OpenGL layer. The bottommost layer is UIImagePickerController, then I use UIView on top and draw a rectangle at certain co-ordinates on the iphone screen. So far everything is OK. Then I am trying to draw an OpenGL 3-D model in that rectangle. I am able to load a 3-D model in the iPhone based on this code here - http://iphonedevelopment.blogspot.com/2008/12/start-of-wavefront-obj-file-loader.html I am not able to transform the co-ordinates of the rectangle into OpenGL co-ordinates. Appreciate any help. Do I need to use a matrix to translate the currentPosition of the 3-D model so it is drawn within myRect? The code is given below.. Appreciate any help/pointers in this regards. John -(void)setupView:(GLView*)view { const GLfloat zNear = 0.01, zFar = 1000.0, fieldOfView = 45.0; GLfloat size; glEnable(GL_DEPTH_TEST); glMatrixMode(GL_PROJECTION); size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); CGRect rect = view.bounds; glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glViewport(0, 0, rect.size.width, rect.size.height); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glClearColor(0.0f, 0.0f, 0.0f, 0.0f); NSString *path = [[NSBundle mainBundle] pathForResource:@"plane" ofType:@"obj"]; OpenGLWaveFrontObject *theObject = [[OpenGLWaveFrontObject alloc] initWithPath:path]; Vertex3D position; position.z = -8.0; position.y = 3.0; position.x = 2.0; theObject.currentPosition = position; self.plane = theObject; [theObject release]; } (void)drawView:(GLView*)view; { static GLfloat rotation = 0.0; glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glLoadIdentity(); glColor4f(0.0, 0.5, 1.0, 1.0); // the coordinates of the rectangle are // myRect.x, myRect.y, myRect.width, myRect.height // Do I need to use a matrix to translate the currentPosition of the // 3-D model so it is drawn within myRect? //glOrthof(-160.0f, 160.0f, -240.0f, 240.0f, -1.0f, 1.0f); [plane drawSelf]; }

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  • Document-oriented database - What if the document definitions change?

    - by Sebastian Hoitz
    As I understand it, you can enter any non-structured information into a document-oriented database. Let's imagine a document like this: { name: 'John Blank', yearOfBirth: 1960 } Later, in a new version, this structure is refactored to { firstname: 'John', lastname: 'Blank', yearOfBirth: 1960 } How do you do this with Document-Oriented databases? Do you have to prepare merge-scripts, that alter all your entries in the database? Or are there better ways you can handle changes in the structure?

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  • How to order by last name on a full name column?

    - by GateKiller
    I have a SQL Table with a column called FullName which contains, for example, "John Smith". How can order the data by the last name that appears in the FullName column? For a long name like "Laurence John Fishburne", I would like to order the data by the word "Fishburne". Thus, names are stored in the order First Name Middle Names Last Name I am using Microsoft SQL Server 2005.

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  • Making a Login Work After Cache, Cookies, etc. Have Been Cleared

    - by John
    Hello, I am using the code below for a user login. The first I try to login after cache / cookies, etc. have been cleared, the browser refreshes and the user name is not logged in. After that, logging in works fine. Any idea how I can make it work the first time? Thanks in advance, John index.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../index.php?username='.$username.'&password='.$password.'');} require_once "header.php"; include "login.php"; require_once "footer.php"; ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?> show_loginform function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?'.$_SERVER['QUERY_STRING'].'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/.../register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/.../lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • Simplest way to print an array in Java

    - by Alex Spurling
    What's the simplest way of printing an array of primitives or of objects in Java? Here are some example inputs and outputs: int[] intArray = new int[] {1, 2, 3, 4, 5}; //output: [1, 2, 3, 4, 5] String[] strArray = new String[] {"John", "Mary", "Bob"}; //output: [John, Mary, Bob]

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  • Arrays of Objects: For each element in array 1, does an object value exist as a value in any of the objects in array 2

    - by DevOtts
    I have two arrays which contain objects in each element of the array. var array1 = [{firstName: "John", lastName: "McDonald"}, {firstName: "Sandy", lastName: "Johnson"},....,] var array2 = [{userName: "Donald"}, {userName: "John"},....,] In psuedo-code, I want to do the following: for each element in array1, is array1[i].firstName == to any of the userName's in array2. In plain english I want to look at each firstname in array1 and see if it exists at all in array2 as the value associated with the userName property.

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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • Variable name as a string in Javascript

    - by fish potato
    Is there a way to get a variable name as a string in Javascript? (like NSStringFromSelector in Cocoa) I would like to do like this: var myFirstName = 'John'; alert(variablesName(myFirstName) + ":" + myFirstName); --> myFirstName:John -- added I'm trying to connect a browser and another program using JavaScript. I would like to send instance names from a browser to another program for callback method.

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  • printing dynamically string in one line in python

    - by EngHamoud
    I'm trying to print strings in one line. I've found solutions but they don't works with windows correctly. I have text file contains names and I want to print them like this name=john then change john to next name and keep name=, I've made this code but didn't work correctly with windows: op = open('names.txt','r') print 'name=', for i in op.readlines(): print '\r'+i.strip('\n') thank you for your time

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  • Add custom method to string object [closed]

    - by cru3l
    Possible Duplicate: Can I add custom methods/attributes to built-in Python types? In Ruby you can override any built-in object class with custom method, like this: class String def sayHello return self+" is saying hello!" end end puts 'JOHN'.downcase.sayHello # >>> 'john is saying hello!' How can i do that in python? Is there a normally way or just hacks?

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  • Creating a Comment Anchor

    - by John
    Hello, The function below allows a user to insert a comment into a MySQL table called "comment." Then, the file "comments2.php" displays all comments for a given submission. Right after a user submits a comment, I would like the top of the user's browser to be anchored by the comment the user just submitted. How can I do this? Thanks in advance, John The function: function show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl) { echo '<form action="http://www...com/.../comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.stripslashes($submission).'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="checkMax" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; } The file comments2.php contains: $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); $submissionid = mysql_real_escape_string($_POST['submissionid']); $submissionid = mysql_real_escape_string($_GET['submissionid']); $sqlStr = "SELECT comment.comment, comment.datecommented, login.username FROM comment LEFT JOIN login ON comment.loginid=login.loginid WHERE submissionid=$submissionid ORDER BY comment.datecommented ASC LIMIT 100"; $tzFrom1 = new DateTimeZone('America/New_York'); $tzTo1 = new DateTimeZone('America/Phoenix'); $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"commentecho\">"; $count = 1; while ($row = mysql_fetch_array($result)) { $dt1 = new DateTime($row["datecommented"], $tzFrom1); $dt1->setTimezone($tzTo1); echo '<tr>'; echo '<td rowspan="3" class="commentnamecount">'.$count++.'.</td>'; echo '<td class="commentname2"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.$row["username"].'</a></td>'; echo '<td rowspan="3" class="commentname1">'.stripslashes($row["comment"]).'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2">'.$dt1->format('F j, Y').'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2a">'.$dt1->format('g:i a').'</td>'; echo '</tr>'; } echo "</table>"; The fields in the MySQL table "comment": commentid loginid submissionid comment datecommented

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  • boost::function & boost::lambda again

    - by John Dibling
    Follow-up to post: http://stackoverflow.com/questions/2978096/using-width-precision-specifiers-with-boostformat I'm trying to use boost::function to create a function that uses lambdas to format a string with boost::format. Ultimately what I'm trying to achieve is using width & precision specifiers for strings with format. boost::format does not support the use of the * width & precision specifiers, as indicated in the docs: Width or precision set to asterisk (*) are used by printf to read this field from an argument. e.g. printf("%1$d:%2$.*3$d:%4$.*3$d\n", hour, min, precision, sec); This class does not support this mechanism for now. so such precision or width fields are quietly ignored by the parsing. so I'm trying to find other ways to accomplish the same goal. Here is what I have so far, which isn't working: #include <string> #include <boost\function.hpp> #include <boost\lambda\lambda.hpp> #include <iostream> #include <boost\format.hpp> #include <iomanip> #include <boost\bind.hpp> int main() { using namespace boost::lambda; using namespace std; boost::function<std::string(int, std::string)> f = (boost::format("%s") % boost::io::group(setw(_1*2), setprecision(_2*2), _3)).str(); std::string s = (boost::format("%s") % f(15, "Hello")).str(); return 0; } This generates many compiler errors: 1>------ Build started: Project: hacks, Configuration: Debug x64 ------ 1>Compiling... 1>main.cpp 1>.\main.cpp(15) : error C2872: '_1' : ambiguous symbol 1> could be 'D:\Program Files (x86)\boost\boost_1_42\boost/lambda/core.hpp(69) : boost::lambda::placeholder1_type &boost::lambda::`anonymous-namespace'::_1' 1> or 'D:\Program Files (x86)\boost\boost_1_42\boost/bind/placeholders.hpp(43) : boost::arg<I> `anonymous-namespace'::_1' 1> with 1> [ 1> I=1 1> ] 1>.\main.cpp(15) : error C2664: 'std::setw' : cannot convert parameter 1 from 'boost::lambda::placeholder1_type' to 'std::streamsize' 1> No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called 1>.\main.cpp(15) : error C2872: '_2' : ambiguous symbol 1> could be 'D:\Program Files (x86)\boost\boost_1_42\boost/lambda/core.hpp(70) : boost::lambda::placeholder2_type &boost::lambda::`anonymous-namespace'::_2' 1> or 'D:\Program Files (x86)\boost\boost_1_42\boost/bind/placeholders.hpp(44) : boost::arg<I> `anonymous-namespace'::_2' 1> with 1> [ 1> I=2 1> ] 1>.\main.cpp(15) : error C2664: 'std::setprecision' : cannot convert parameter 1 from 'boost::lambda::placeholder2_type' to 'std::streamsize' 1> No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called 1>.\main.cpp(15) : error C2872: '_3' : ambiguous symbol 1> could be 'D:\Program Files (x86)\boost\boost_1_42\boost/lambda/core.hpp(71) : boost::lambda::placeholder3_type &boost::lambda::`anonymous-namespace'::_3' 1> or 'D:\Program Files (x86)\boost\boost_1_42\boost/bind/placeholders.hpp(45) : boost::arg<I> `anonymous-namespace'::_3' 1> with 1> [ 1> I=3 1> ] 1>.\main.cpp(15) : error C2660: 'boost::io::group' : function does not take 3 arguments 1>.\main.cpp(15) : error C2228: left of '.str' must have class/struct/union 1>Build log was saved at "file://c:\Users\john\Documents\Visual Studio 2005\Projects\hacks\x64\Debug\BuildLog.htm" 1>hacks - 7 error(s), 0 warning(s) ========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ========== My fundamental understanding of boost's lambdas and functions is probably lacking. How can I get this to work?

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  • Match over multiple lines perl regular expression

    - by John
    Hi, I have a file like this: 01 00 01 14 c0 00 01 10 01 00 00 16 00 00 00 64 00 00 00 65 00 00 01 07 40 00 00 22 68 61 6c 2e 6f 70 65 6e 65 74 2e 63 6f 6d 3b 30 30 30 30 30 30 30 30 32 3b 30 00 00 00 00 01 08 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 28 40 00 00 21 72 65 61 6c 6d 31 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 00 01 25 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 1b 40 00 00 20 72 65 61 6c 6d 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 01 02 40 00 00 0c 01 00 00 16 00 00 01 a0 40 00 00 0c 00 00 00 01 00 00 01 9f 40 00 00 0c 00 00 00 00 00 00 01 16 40 00 00 0c 00 00 00 00 00 00 01 bb 40 00 00 28 00 00 01 c2 40 00 00 0c 00 00 00 00 00 00 01 bc 40 00 00 13 31 39 37 37 31 31 31 32 32 33 31 00 I am reading the file and then finding certain octets and replacing them with tags: while(<FH>){ $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; # } So for example, 00 00 00 64 would be replaced by the tag. This was working fine, but it doesn't seem to able to match over multiple lines any more. For example the pattern 31 31 32 32 33 31 runs over multiple lines, and the regular expression doesn't seem to catch it. I tried using /m /s pattern modifiers to ignore new lines but they didn't match it either. The only way around it I can come up with, is to read the whole file into a string using: undef $/; my $whole_file = <FH>; my $line = $whole_file; $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; This works, the tags get inserted correctly, but the structure of the file is radically altered. It is all dumped out on a single line. I would like to retain the structure of the file as it appears here. Any ideas as to how I might do this? /john

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  • User Getting Logged Out After Making First Comment

    - by John
    Hello, I am using a login system that works well. I am also using a comment system. The comment function does not show up unless the user is logged in (as shown in commentformonoff.php below). When a user makes a comment, the info is passed from the function "show_commentbox" to the file comments2a.php. Then, the info is passed to the file comments2.php. When the site is first pulled up on a browser, after logging in and making a comment, the user is logged out. After logging in a second time during the same browser session, the user is no longer logged out after making a comment. How can I keep the user logged in after making the first comment? Thanks in advance, John Commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } ?> Function "show_commentbox": function show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl) { echo '<form action="http://www...com/.../comments/comments2a.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$_SESSION['username'].'" name="u"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.stripslashes($submission).'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="checkMax" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; } Included in comments2a.php: $uid = mysql_real_escape_string($_POST['uid']); $u = mysql_real_escape_string($_POST['u']); $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); $lastcommentid = mysql_insert_id(); header("Location: comments2.php?submission=".$submission."&submissionid=".$submissionid."&url=".$url."&submissiondate=".$submissiondate."&comment=".$comment."&subid=".$subid."&uid=".$uid."&u=".$u."&submittor=".$submittor."&countcomments=".$countcomments."&dispurl=".$dispurl."#comment-$lastcommentid"); exit(); Included in comments2.php: if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../comments/comments2.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'&submissiondate='.$submissiondate.'&submittor='.$submittor.'&countcomments='.$countcomments.'&dispurl='.$dispurl.'');} $uid = mysql_real_escape_string($_GET['uid']); $u = mysql_real_escape_string($_GET['u']);

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  • Submitting a URL into a Form without "http://", with "www.", or with neither

    - by John
    (EDITED) Hello, In the form below, the filed for <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> fine when a URL is submitted that has a "http://" at the beginning of it. However, it doesn't work if a URL is submitted with only a "www." in front of it, or with neither a "http://" nor a "www." How can I make it work in all if the submitted URL has any or none of the following at the beginning of it: http:// www. http://www. Thanks in advance, John Form: echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; submit2.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $cleanurl = stripslashes($cleanurl); $title = $_POST['title']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $title = stripslashes($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { show_loginform(); } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } require_once "footer.php"; ?>

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