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  • create hgrc file for all paths on a machine

    - by noam
    I want to create a hgrc file to set the username and password for all paths on some machine, e.g no matter in which directory I am in, hg clone some_path will always work without prompting for a username and a password (this is for an auto-deploy script). I followed the instructions and created a file: /etc/mercurial/hgrc.d/deploy.rc it's contents: [auth] default.prefix= http://myrepo default.username = myuname default.password = pwd But when I do hg clone some_path I get abort: error: Connection refused. What Am i doing wrong?

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  • Android String.equals doesn't work when I trying to match from httpresponse

    - by user469652
    RestClient.post("auth/login/", loginparam, new AsyncHttpResponseHandler() { @Override public void onSuccess(String s) { Toast.makeText(getApplicationContext(), String.valueOf(s.toLowerCase().equals("ok")), Toast.LENGTH_LONG).show(); if (s.equals("ok")) { startActivity(new Intent(getApplication(), HomeActivity.class)); } } }); This is the code I used for login in android app, In the Toast text, I can see the server did returned "ok", but s.equals always failed in my case, can someone explain that? Thank you.

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  • How to protect an ASP Classic Page?

    - by SH
    How can I protect an ASP Classic page with either HTTP AUTH (you must provide a username and password to service) or a randomly generated access key that will be included as one of the parameters of the HTTP POST using the variable name access_key. Can anybody provide asp classic code in this regard? Quick help will be appreciated... PS: OrderGroove is a 3rd party service... neglect it.

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  • authlogic rails question - how to code for an API

    - by phil swenson
    I have authlogic going on my app, but now I need to have an an API. I don't want to establish a session, just want a user to send in data in a json request such as: {"type":"address","password":"mypassword","name":"my notificaiton name goes here","user":"myusername","text":"my interesting stuff goes here"} So questions - 1) is this a decent approach? 2) how do i do the auth inside my rails controller?

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  • Twitter + Grackle, determining the logged in user

    - by JP
    This is crazy, but I'm stumped! Once my user has logged into twitter via OAuth how do I determine their username using grackle? @twitter = Grackle::Client.new(:auth => { :type => :oauth, :consumer_key => consumer_key, :consumer_secret => consumer_secret, :token => @access_token.token, :token_secret => @access_token.secret }) username = @twitte.something_here?

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  • What is the best way to go about obscuring Java code?

    - by Waltzy
    Well, I'm planning on releasing a Jar into the world but would prefer if the code was not readably available to anyone with a Java Decompiler as I want to control access to the program with usernames / auth codes etc. After some Googling I haven't found any software to do this for me, so I was wondering what steps to take from here; if anyone can point me at any software or information on methodologies of obscurification I would be grateful. Cheers again Stack Overflow.

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  • How to stop Django "app not found" error?

    - by cml
    When I run python ./manage.py sql grading my django site comes up with: Error: App with label grading could not be found. Are you sure you INSTALLED_APPS setting is correct? I have the app grading with __init__.py and everything, and my INSTALLED APPS is: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'teachline.courses', 'teachline.grading', ) Why isn't this working?

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  • Web service security not working. Java

    - by Nitesh Panchal
    Hello, I have a ejb module which contains my ejbs as well as web services. I am using Netbeans 6.8 and Glassfish V3 I right clicked on my web service and clicked "edit web service attributes" and then checked "secure service" and then selected keystore of my server. This is my sun-ejb-jar.xml file :- <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE sun-ejb-jar PUBLIC "-//Sun Microsystems, Inc.//DTD Application Server 9.0 Servlet 2.5//EN" "http://www.sun.com/software/appserver/dtds/sun-web-app_2_5-0.dtd"> <sun-ejb-jar> <security-role-mapping> <role-name>Admin</role-name> <group-name>Admin</group-name> </security-role-mapping> <security-role-mapping> <role-name>General</role-name> <group-name>General</group-name> </security-role-mapping> <security-role-mapping> <role-name>Member</role-name> <group-name>Member</group-name> </security-role-mapping> <enterprise-beans> <ejb> <ejb-name>MemberBean</ejb-name> <webservice-endpoint> <port-component-name>wsMember</port-component-name> <login-config> <auth-method>BASIC</auth-method> <realm>file</realm> </login-config> </webservice-endpoint> </ejb> </enterprise-beans> </sun-ejb-jar> Here MemberBean is my ejb and wsMember is my webservice. Then i made another project and added web service client and again right clicked on "edit web service attributes" and gave password as test and test. This username and password (test) is in Glassfish server in file realm. But when i try to invoke my webservice i always get SEC5046: Audit: Authentication refused for [test]. SEC1201: Login failed for user: test What am i doing wrong? Am i missing something?

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  • Extract Data from a Website using PHP

    - by 01jayss
    I am trying to get PHP to extract the TOKEN (the uppercase one), USERID (uppercase), and the USER NAME (uppercase) from a web page with the following text. {"rsp":{"stat":"ok","auth":{"token":"**TOKEN**","perms":"read","user":{"id":"**USERID**","username":"**USER NAME**","fullname":"**NAME OF USER**"}}}} (This is from the RTM api, getting the authentication token of the user). How would I go about doing this? Thanks!

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  • sending data from appcontroller to default.ctp - CakePHP

    - by Astral Projection Forum
    I want to send the below data to default.ctp, I want to display menus in all the pages, I'm using Auth, The problem is if I'm logged in I get the Menus correctly, but if I logout, I'm getting error saying variable'$topMenu' not found. The MenuController can be accessed only if logged in. $this->loadModel('Menu'); $this->set('topMenu',$this->Menu->find('all')); Any help on how to solve this?

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  • How to project an ASP Classic Page?

    - by SH
    How to project an ASP Classic page with either HTTP AUTH (you must provide a username and password to OrderGroove) or a randomly generated access key that will be included as one of the parameters of the HTTP POST using the variable name access_key. Can anybody provide asp classic code in this regard? Quick help will be appreciated...

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  • How can I access the "through" object of a Django ManyToManyField?

    - by Macha
    I have the following models in my Django app. How can I from the Team model find all the User objects who have accepted as True in the Membership model? I know I need to use Team.objects.filter(), but I'm not sure how to check the value of the accepted field. from django.contrib.auth.models import User class Team(models.Model): members = models.ManyToManyField(User, through="Membership") class Membership(models.Model): user = models.ForeignKey(User) team = models.ForeignKey(Team) accepted = models.BooleanField(default=False)

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  • User permission check steps in CakePHP

    - by bancer
    I want to understand the sequence of steps how it is verified that a user has permission to particular application page ('Acl', 'Auth', 'Security' components are used). For example, a visitor clicks a link on another site that directs him to my application. What is the sequence of steps that my application does to verify that this user has access to the page? What controllers and methods are called?

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  • spring-security and jsf

    - by Mike
    Hi! i am developing in JSF a Spring Security application. the login form is fine. however, when i try to retrieve the authentication object, in future code, i always get the authentication pricipal as anonymous. i try to fetch is like this: Authentication auth = SecurityContextHolder.getContext().getAuthentication();

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  • Custom fail2ban Filter

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • Custom fail2ban Filter for phpMyadmin bruteforce attempts

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • SSH-forwarded X11 display from Linux to Mac lost after some time

    - by mklein9
    I have a new and vexing problem with ssh forwarding my X11 connection when logging in from a Mac (10.7.2) to Linux (Ubuntu 8.04). I have no trouble using ssh -X to log in to the remote machine and starting an X11-based application from that shell. What has recently started happening is that additional invocations of X11 applications from that same shell, after a while (on the order of hours), are unable to start because the forwarded display is being blocked (I presume). When attempting to start xterm, for example, I get the usual message about a bad DISPLAY setting, such as: xterm Xt error: Can't open display: localhost:10.0 But the X11 application I started right when I logged in is still running along just fine, using that exact same display (localhost:10.0), just that it was started earlier. I turned on verbose logging in sshd_config and I see this in the /var/log/auth.log file in response to the failed xterm startup attempt: sshd[22104]: channel 8: open failed: administratively prohibited: open failed If I ssh -X to the server again, starting a new shell and getting assigned a new display (localhost:11.0), the same process repeats: the X11 applications started early on run just fine for as long as I keep them open (days), but after a few hours I cannot start any new ones from that shell. Particulars: OpenSSH sshd server running on Ubuntu 8.04, display forwarded to a Mac running Lion (10.7.2) with the default Apple X server. The systems are connected on an Ethernet LAN with a single switch between them. Neither machine is running a firewall. Until recently (a few days ago) this setup worked perfectly so I am mystified as to where to look next. I am by no means an X11 or SSH expert but have good UNIX/Linux experience. Nothing obvious has changed in either client or server configuration although I have tried changing a few options to try to debug this, like setting sshd_config's TCPKeepAlive to no, and setting "host +localhost" (you can tell I've been Googling). When logging in from a Linux 11.10 laptop to the same remote host over the same network and switch, this problem does not occur -- an xterm can be invoked successfully hours later from the same ssh login shell while the same experiment from the Mac fails (tested this morning to be sure), so it would appear to be a Mac-specific issue. With "LogLevel DEBUG3" set on the remote machine (sshd server), and no change made in the client connections by me, /var/log/auth.log shows one slight change in connection status reports overnight, which is the port number used by the one successful ssh session from the Linux machine (I think), connection #7 below: sshd[20173]: debug3: channel 7: status: The following connections are open:\r\n #0 server-session (t4 r0 i0/0 o0/0 fd 14/13 cfd -1)\r\n #3 X11 connection from 127.0.0.1 port 57564 (t4 r1 i0/0 o0/0 fd 16/16 cfd -1)\r\n #4 X11 connection from 127.0.0.1 port 57565 (t4 r2 i0/0 o0/0 fd 17/17 cfd -1)\r\n #5 X11 connection from 127.0.0.1 port 57566 (t4 r3 i0/0 o0/0 fd 18/18 cfd -1)\r\n #6 X11 connection from 127.0.0.1 port 57567 (t4 r4 i0/0 o0/0 fd 19/19 cfd -1)\r\n #7 X11 connection from 127.0.0.1 port 59007 In this report, everything is the same between status reports except the port number used by connection #7 which I believe is the Linux client -- the only one still maintaining a display connection. It continues to increment over time, judging by a sequence of these reports overnight. Thanks for any help, -Mike

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