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  • Why doesn't the "scroll bar" on my laptop touchpad work?

    - by Antonio Guzman Belmont
    EDIT, from Google translate: Well buy my laptop with windows 7 and the touchpad has some arrows up and down to q deslises finger on the right side as if the q scroll the scroll bar handles, recently installed Ubuntu 11.10 and there is also served by the touchpad scroll so to speak but then asked me and I did update (late hours) and longer term attempt q dezlizar my finger down the right side of the touchpad and now low, anyone can tell me I can do about q to q and windows function as and ubuntu 11.10, I think now I have ubuntu 4.12 EDIT.2 (minimal tidy-up) I bought my laptop with Windows 7 installed. The touchpad has up/down arrows on the right side, as if this would scroll. When I installed Ubuntu 11.10, I was able to use this touchpad scroll function. I recently did an update (at some late hours) and i can no longer use right side of the touchpad to scroll. Can anyone tell me how to get the same function as I had in Windows and Ubuntu 11.10 ? I think I now have Ubuntu 12.04 Original question: Bueno compre mi lap con windows 7 y en el touchpad tiene unas flechitas arriba y abajo para q deslises el dedo del lado derecho como si fuese el scroll q maneja la barra de desplazamiento, recientemente instale ubuntu 11.10 y ahi servia tambien el scroll del touchpad por asi decirlo pero luego me pidio actualizar y lo hice(tardo horas) y ya q termino intento dezlizar mi dedo para bajar por la parte derecha del touchpad y ahora no baja, alguien me puede decir q puedo hacer al respecto para q funcione como e windows y en ubuntu 11.10, ahora tengo ubuntu 12.04 creo

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  • Recursive list of lists in XSL

    - by Paul Tomblin
    I have a recursive nodes that I'm trying to set up for jquery-checktree. The nodes look like foo/bar/ID /NAME /CHECKED bar/ID /NAME /CHECKED /bar/ID /NAME /bar/ID /NAME /bar/ID /NAME /CHECKED /bar/ID /NAME /CHECKED Where any bar may or may not have one or more bar nodes below it, but any bar will have ID and NAME and might have a CHECKED. and I want to turn that into <ul> <li><input type="checkbox" name="..." value="..." checked="checked"></input> <label for="...">...</label> <ul> <li><input type="checkbox" name="..." value="..." checked="checked"></input> <label for="...">...</label> </li> </ul> <li>....</li> </ul> I can get the first level by doing: <ul class="tree"> <xsl:for-each select="/foo/bar/"> <li><input type="checkbox" name="{ID}" value="{ID}"> <xsl:if test="CHECKED = 'Y'"><xsl:attribute name="checked">checked</xsl:attribute></xsl:if> </input><label for="{ID}"><xsl:value-of select="NAME"/></label> </li> </xsl:for-each> </ul> But I don't know how to recurse down to the embedded "bar" within the "bar", down to however many levels there might be.

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  • Temporary non-const istream reference in constructor (C++)

    - by Christopher Bruns
    It seems that a constructor that takes a non-const reference to an istream cannot be constructed with a temporary value in C++. #include <iostream> #include <sstream> using namespace std; class Bar { public: explicit Bar(std::istream& is) {} }; int main() { istringstream stream1("bar1"); Bar bar1(stream1); // OK on all platforms // compile error on linux, Mac gcc; OK on Windows MSVC Bar bar2(istringstream("bar2")); return 0; } This compiles fine with MSVC, but not with gcc. Using gcc I get a compile error: g++ test.cpp -o test test.cpp: In function ‘int main()’: test.cpp:18: error: no matching function for call to ‘Bar::Bar(std::istringstream)’ test.cpp:9: note: candidates are: Bar::Bar(std::istream&) test.cpp:7: note: Bar::Bar(const Bar&) Is there something philosophically wrong with the second way (bar2) of constructing a Bar object? It looks nicer to me, and does not require that stream1 variable that is only needed for a moment.

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  • Nginx + PHPBB3 reverse proxy images problem

    - by siberiano
    Hello all I have a problem with my Nginx Frontend + Apache2 backend + PHPBB3 software. It doesn't load the CSS and the images neither. I get constant errors like these: 2010/04/14 16:57:25 [error] 13365#0: *69 open() "/var/www/foo/styles/styles/coffee_time/theme/large.css" failed (2: No such file or directory), client: 83.44.175.237, server: www.foo.com, request: "GET /styles/coffee_time/theme/large.css HTTP/1.1", host: "www.foo.com", referrer: "http://www.foo.com/viewforum.php?f=43" This is my config of the site: server { listen 80; server_name www.foo.com; access_log /var/log/nginx/foo.access.log; # serve static files directly location ~* ^.+.(jpg|jpeg|gif|css|png|js|ico)$ { access_log off; expires 30d; root /var/www/trasteando/; } location / { root /var/www/foo/; index /var/www/foo/index.php; } # proxy the PHP scripts to predefined upstream .apache. # location ~ .php$ { proxy_pass http://apache; } location /styles/ { root /var/www/foo/styles/; }

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  • Apache: Isn't chmod 755 enough to set up symlink or alias on Apache httpd on Mac OS 10.5?

    - by eed3si9n
    On my Mac OS 10.5 machine, I would like to set up a subfolder of ~/Documents like ~/Documents/foo/html to be http://localhost/foo. The first thing I thought of doing is using Alias as follows: Alias /foo /Users/someone/Documents/foo/html <Directory "/Users/someone/Documents/foo/html"> Options Indexes FollowSymLinks MultiViews Order allow,deny Allow from all </Directory> This got me 403 Forbidden. In the error_log I got: [error] [client ::1] (13)Permission denied: access to /foo denied The subfolder in question has chmod 755 access. I've tried specifying likes like http://localhost/foo/test.php, but that didn't work either. Next, I tried the symlink route. Went into /Library/WebServer/Documents and made a symlink to ~/Documents/foo/html. The document root has Options Indexes FollowSymLinks MultiViews This still got me 403 Forbidden: Symbolic link not allowed or link target not accessible: /Library/WebServer/Documents/foo What else do I need to set this up? Solution: $ chmod 755 ~/Documents In general, the folder to be shared and all of its ancestor folder needs to be viewable by the www service user.

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  • Is there any way to open more than one folders(Home folder, videps etc..) by clicking the 'files' icon on the unity bar?

    - by 001neeraj
    Why only one nautilus window manager is opens when clicking on the 'Files' icon on the unity bar? I need to open two or more HomeFolder windows by clicking on the 'files' icon on the unity pane. I cannot create more than one nautilus window manager unless i tap superkey(windows key) and type homefolder,videos etc or typing the same in gnome-do. Is there any way to open more than one folders(Home folder, videos etc..) by clicking the 'files' icon on the unity bar??

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  • Django QuerySet ordering by number of reverse ForeignKey matches

    - by msanders
    I have the following Django models: class Foo(models.Model): title = models.CharField(_(u'Title'), max_length=600) class Bar(models.Model): foo = models.ForeignKey(Foo) eg_id = models.PositiveIntegerField(_(u'Example ID'), default=0) I wish to return a list of Foo objects which have a reverse relationship with Bar objects that have a eg_id value contained in a list of values. So I have: id_list = [7, 8, 9, 10] qs = Foo.objects.filter(bar__eg_id__in=id_list) How do I order the matching Foo objects according to the number of related Bar objects which have an eg_id value in the id_list?

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  • .php files see Apache environment variables, .html files don't

    - by dotancohen
    Consider this environment: $ cat .htaccess AddType application/x-httpd-php .php .html SetEnv Foo Bar $ cat test.php <?php echo "Hello: "; echo $_SERVER['Foo']; echo $_ENV['Foo']; echo getenv('Foo'); ?> $ cat test.html <?php echo "Hello: "; echo $_SERVER['Foo']; echo $_ENV['Foo']; echo getenv('Foo'); ?> This is the output of test.php: Hello BarBarBar This is the output of test.html: Hello Why might that be? How might I fix it? Here is phpinfo.php: http://pastebin.com/rgq7up61 Here is phpinfo.html: http://pastebin.com/VUKFNZ36 If anyone knows where I can host a real webpage instead of just the HTML for one, please let me know and I'll move the content to there. Thanks.

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  • How does Unity.Resolve know which constructor to use?

    - by stiank81
    Given a class with several constructors - how can I tell Resolve which constructor to use? Consider the following example class: public class Foo { public Foo() { } public Foo(IBar bar) { Bar = bar; } public Foo(string name, IBar bar) { Bar = bar; Name = name; } public IBar Bar { get; set; } public string Name { get; set; } } If I want to create an object of type Foo using Resolve how will Resolve know which constructor to use? And how can I tell it to use the right one? Let's say I have a container with an IBar registered - will it understand that it should favor the constructor taking IBar? And if I specify a string too - will it use the (string, IBar) constructor? Foo foo = unityContainer.Resolve<Foo>(); And please ignore the fact that it would probably be easier if the class just had a single constructor...

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  • Bottom button bar overlaps the last element of Listview!!

    - by elto
    I have a listview which is part of an Activity. I want user to have a choice for batch deleting the items in the listview, so when he chooses the corresponding option from the menu, every list item gets a checkbox next to it. When user clicks any checkbox, a button bar is to slide up from bottom (as in gmail app) and clicking delete button deletes the selected items, however clicking cancel button on the bar would uncheck all the checked items. This is my page layout.xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@android:color/transparent" > <FrameLayout android:layout_width="fill_parent" android:layout_height="fill_parent" > <LinearLayout android:id="@+id/list_area" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="1" > <ListView android:id="@+id/mylist" android:layout_width="fill_parent" android:layout_height="wrap_content" android:background="@android:color/transparent" android:drawSelectorOnTop="false" android:layout_weight="1" /> <TextView android:id="@+id/empty_list_message" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textColor="#FFFFFF" android:layout_gravity="center_vertical|center_horizontal" android:text="@string/msg_for_emptyschd" android:layout_margin="14dip" android:layout_weight="1" /> </LinearLayout> <RelativeLayout android:id="@+id/bottom_action_bar" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:background="@drawable/schedule_bottom_actionbar_border" android:layout_marginBottom="2dip" android:layout_gravity="bottom" android:visibility="gone" > <Button android:id="@+id/delete_selecteditems_button" android:text="Deleted Selected" android:layout_width="140dip" android:layout_height="40dip" android:layout_alignParentLeft="true" android:layout_marginLeft="3dip" android:layout_marginTop="3dip" /> <Button android:id="@+id/cancel_button" android:text="Cancel" android:layout_width="140dip" android:layout_height="40dip" android:layout_alignParentRight="true" android:layout_marginRight="3dip" android:layout_marginTop="3dip" /> </RelativeLayout> </FrameLayout> </LinearLayout> so far, I have got everything working except that when the bottom bar becomes visible upon checkbox selection, it overlaps the last element of the list. All other list items can be scrolled up, but you cant scroll up the very last item of the list, therefore user can not select that item if he intends to. Here is the screenshot of the overlap. I have tried using the listview footer option, but that appends the bar to the end of the list instead of keeping it fixed at the bottom of the screen. Is there a way I could "raise" the listview enough so that the overlap wont happen?? BTW, I have already tried adding the bottom-margin to the listview itself, or the LinearLayout wrapping the listview right before making the button-bar visible, but it introduces other bugs like clicking one checkbox checks some another checkbox in listview.

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  • Why does 6.times.map work in ruby 1.8.7 but not 1.8.6

    - by Lee
    The following code snippet works fine in 1.8.7 on Mac OS X, but not in 1.8.6 on Ubuntu. Why? Is there a workaround? Works in 1.8.7: $ ruby --version ruby 1.8.7 (2009-06-08 patchlevel 173) [universal-darwin10.0] ltredgate15:eegl leem$ irb >> 6.times.map {'foo'} => ["foo", "foo", "foo", "foo", "foo", "foo"] >> But not in 1.8.6: # ruby --version ruby 1.8.6 (2008-08-11 patchlevel 287) [i686-linux] Ruby Enterprise Edition 20090610 # irb irb(main):001:0> 6.times.map {'foo'} LocalJumpError: no block given from (irb):1:in `times' from (irb):1 irb(main):002:0> Why is there a difference? What's the workaround for 1.8.6?

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  • App crashes often in a for-loop

    - by Flocked
    Hello, my app crashes often in this for-loop: for (int a = 0; a <= 20; a++) { int b = arc4random() % [newsStories count]; NSString * foo = [[NSString alloc]initWithString:[[newsStories objectAtIndex: arc4random() % b]objectForKey:@"title"]]; foo = [foo stringByReplacingOccurrencesOfString:@"’" withString:@""]; foo = [[foo componentsSeparatedByCharactersInSet:[[NSCharacterSet letterCharacterSet] invertedSet]] componentsJoinedByString:@" "]; foo = [foo stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]; textView.text = [textView.text stringByAppendingString:[NSString stringWithFormat:@"%@ ", foo]]; } The code changes a NSString from a NSDictionary and adds it into a textView. Sometimes it first crashes in the second time using the for-loop. What did I wrong?

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  • Populating an association with children in factory_girl

    - by Craig Walker
    I have a model Foo that has_many 'Bar'. I have a factory_girl factory for each of these objects. The factory for Bar has an association to Foo; it will instantiate a Foo when it creates the Bar. I'd like a Factory that creates a Foo that contains a Bar. Ideally this Bar would be created through the :bar factory, and respect the build strategy (create/build) used to create the Foo. I know I could just call the :bar factory and then grab the Foo reference from the new Bar. I'd like to avoid this; in my test case, the important object is Foo; calling the Bar factory seems a bit circuitous. Also, I can see the need for a Foo with multiple Bars. Is this possible in factory_girl? How do you define this relationship in the parent?

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  • Linux's thread local storage implementation

    - by anon
    __thread Foo foo; How is "foo" actually resolved? Does the compiler silently replace every instance of "foo" with a function call? Is "foo" stored somewhere relative to the bottom of the stack, and the compiler stores this as "hey, for each thread, have this space near the bottom of the stack, and foo is stored as 'offset x from bottom of stack'"?

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  • help with htaccess

    - by Matías
    I want to do this: foo.com/xxx= foo.com/somepage.php?id=xxx This is how I do it: Options +FollowSymLinks RewriteEngine On RewriteCond %{QUERY_STRING} ^$ RewriteRule ^([^/]+)$ http://foo.com/somepage.php?id=$1 [L] the problem now, is that foo.com doesn't work any more. I can't see foo.com neither foo.com/index.php help me! :)

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  • SBT run differences between scala and java?

    - by Eric Cartner
    I'm trying to follow the log4j2 configuration tutorials in a SBT 0.12.1 project. Here is my build.sbt: name := "Logging Test" version := "0.0" scalaVersion := "2.9.2" libraryDependencies ++= Seq( "org.apache.logging.log4j" % "log4j-api" % "2.0-beta3", "org.apache.logging.log4j" % "log4j-core" % "2.0-beta3" ) When I run the main() defined in src/main/scala/logtest/Foo.scala: package logtest import org.apache.logging.log4j.{Logger, LogManager} object Foo { private val logger = LogManager.getLogger(getClass()) def main(args: Array[String]) { logger.trace("Entering application.") val bar = new Bar() if (!bar.doIt()) logger.error("Didn't do it.") logger.trace("Exiting application.") } } I get the output I was expecting given that src/main/resources/log4j2.xml sets the root logging level to trace: [info] Running logtest.Foo 08:39:55.627 [run-main] TRACE logtest.Foo$ - Entering application. 08:39:55.630 [run-main] TRACE logtest.Bar - entry 08:39:55.630 [run-main] ERROR logtest.Bar - Did it again! 08:39:55.630 [run-main] TRACE logtest.Bar - exit with (false) 08:39:55.630 [run-main] ERROR logtest.Foo$ - Didn't do it. 08:39:55.630 [run-main] TRACE logtest.Foo$ - Exiting application. However, when I run the main() defined in src/main/java/logtest/LoggerTest.java: package logtest; import org.apache.logging.log4j.Logger; import org.apache.logging.log4j.LogManager; public class LoggerTest { private static Logger logger = LogManager.getLogger(LoggerTest.class.getName()); public static void main(String[] args) { logger.trace("Entering application."); Bar bar = new Bar(); if (!bar.doIt()) logger.error("Didn't do it."); logger.trace("Exiting application."); } } I get the output: [info] Running logtest.LoggerTest ERROR StatusLogger Unable to locate a logging implementation, using SimpleLogger ERROR Bar Did it again! ERROR LoggerTest Didn't do it. From what I can tell, ERROR StatusLogger Unable to ... is usually a sign that log4j-core is not on my classpath. The lack of TRACE messages seems to indicate that my log4j2.xml settings aren't on the classpath either. Why should there be any difference in classpath if I'm running Foo.main versus LoggerTest.main? Or is there something else causing this behavior? Update I used SBT Assembly to build a fat jar of this project and specified logtest.LoggerTest to be the main class. Running it from the command line produced correct results: Eric-Cartners-iMac:target ecartner$ java -jar "Logging Test-assembly-0.0.jar" 10:52:23.220 [main] TRACE logtest.LoggerTest - Entering application. 10:52:23.221 [main] TRACE logtest.Bar - entry 10:52:23.221 [main] ERROR logtest.Bar - Did it again! 10:52:23.221 [main] TRACE logtest.Bar - exit with (false) 10:52:23.221 [main] ERROR logtest.LoggerTest - Didn't do it. 10:52:23.221 [main] TRACE logtest.LoggerTest - Exiting application.

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  • Icinga notifications are being marked as spam when sent to my mailbox

    - by user784637
    I'm using gmail and my domain is foo.com About half the notifications from my icinga server, [email protected] go to my spam folder for [email protected] Received-SPF: fail (google.com: domain of [email protected] does not designate <ip6> as permitted sender) client-ip=<ip6>; Authentication-Results: mx.google.com; spf=hardfail (google.com: domain of [email protected] does not designate <ip6> as permitted sender) [email protected] Is my current SPF record set up to allow my icinga server with the ip <ip4> and <ip6> to send email from the domain foo.com? ;; ANSWER SECTION: foo.com. 300 IN TXT "v=spf1 ip4:<ip4> ip6:<ip6> -all"

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  • Using PIG with Hadoop, how do I regex match parts of text with an unknown number of groups?

    - by lmonson
    I'm using Amazon's elastic map reduce. I have log files that look something like this random text foo="1" more random text foo="2" more text noise foo="1" blah blah blah foo="1" blah blah foo="3" blah blah foo="4" ... How can I write a pig expression to pick out all the numbers in the 'foo' expressions? I prefer tuples that look something like this: (1,2) (1) (1,3,4) I've tried the following: TUPLES = foreach LINES generate FLATTEN(EXTRACT(line,'foo="([0-9]+)"')); But this yields only the first match in each line: (1) (1) (1)

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  • How do I split filenames from paths using python?

    - by Rasputin Jones
    I have a list of files that look like this: Input /foo/bar/baz/d4dc7c496100e8ce0166e84699b4e267fe652faeb070db18c76669d1c6f69f92.mp4 /foo/baz/bar/60d24a24f19a6b6c1c4734e0f288720c9ce429bc41c2620d32e01e934bfcd344.mp4 /bar/baz/foo/cd53fe086717a9f6fecb1d0567f6d76e93c48d7790c55e83e83dd1c43251e40e.mp4 And I would like to split out the filenames from the path while retaining both. Output ['/foo/bar/baz/', 'd4dc7c496100e8ce0166e84699b4e267fe652faeb070db18c76669d1c6f69f92.mp4'] ['/foo/baz/bar/', '60d24a24f19a6b6c1c4734e0f288720c9ce429bc41c2620d32e01e934bfcd344.mp4'] ['/bar/baz/foo', 'd53fe086717a9f6fecb1d0567f6d76e93c48d7790c55e83e83dd1c43251e40e.mp4'] How would one go about this? Thanks!

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  • How do I include a module in a namespaced class?

    - by snl
    I am having trouble including a module in a namespaced class. The example below throws the error uninitialized constant Bar::Foo::Baz (NameError). What basic piece of Ruby knowledge am I missing here? module Foo module Baz def hello puts 'hello' end end end module Bar class Foo include Foo::Baz end end foo = Bar::Foo.new

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  • C++ vs. C++/CLI: Const qualification of virtual function parameters

    - by James McNellis
    [All of the following was tested using Visual Studio 2008 SP1] In C++, const qualification of parameter types does not affect the type of a function (8.3.5/3: "Any cv-qualifier modifying a parameter type is deleted") So, for example, in the following class hierarchy, Derived::Foo overrides Base::Foo: struct Base { virtual void Foo(const int i) { } }; struct Derived : Base { virtual void Foo(int i) { } }; Consider a similar hierarchy in C++/CLI: ref class Base abstract { public: virtual void Foo(const int) = 0; }; ref class Derived : public Base { public: virtual void Foo(int i) override { } }; If I then create an instance of Derived: int main(array<System::String ^> ^args) { Derived^ d = gcnew Derived; } it compiles without errors or warnings. When I run it, it throws the following exception and then terminates: An unhandled exception of type 'System.TypeLoadException' occurred in ClrVirtualTest.exe Additional information: Method 'Foo' in type 'Derived'...does not have an implementation. That exception seems to indicate that the const qualification of the parameter does affect the type of the function in C++/CLI (or, at least it affects overriding in some way). However, if I comment out the line containing the definition of Derived::Foo, the compiler reports the following error (on the line in main where the instance of Derived is instantiated): error C2259: 'Derived': cannot instantiate abstract class If I add the const qualifier to the parameter of Derived::Foo or remove the const qualifier from the parameter of Base::Foo, it compiles and runs with no errors. I would think that if the const qualification of the parameter affects the type of the function, I should get this error if the const qualification of the parameter in the derived class virtual function does not match the const qualification of the parameter in the base class virtual function. If I change the type of Derived::Foo's parameter from an int to a double, I get the following warning (in addition to the aforementioned error, C2259): warning C4490: 'override': incorrect use of override specifier; 'Derived::Foo' does not match a base ref class method So, my question is, effectively, does the const qualification of function parameters affect the type of the function in C++/CLI? If so, why does this compile and why are there no errors or warnings? If not, why is an exception thrown?

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  • Cant deploy "war" file from Virtual Hosts, see a directory listing.

    - by Kaustubh P
    This is my httpd.conf configured with Virtual hosts: NameVirtualHost *:80 <VirtualHost *:80> ServerName http://foo.baz.in DocumentRoot /var/www/foo/ </VirtualHost> <VirtualHost *:80> ServerName http://bar.baz.in DocumentRoot /var/www/ </VirtualHost> The second virtual host is a Wordpress blog, configured with .htaccess, and index.php in the root i.e. /var/www, and rest of the files in wordpress's own folder. However, the first virtual host is a "war" file, and when I goto foo.baz.in, I see the directory listing, containing the war. I also tried changing the DocumentRoot to /var/www/foo/foo.war` but I get an error Restarting web server: apache2Warning: DocumentRoot [/var/www/foo/foo.war] does not exist I also changed the owner and permission of the war to www-data:www-data and changed the permissions to 755, but to no avail. How do I make apache deploy my "war"? Thanks.

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  • Inheritance in Java

    - by stevebot
    If I have an abstract class in java named Foo and it has an implementor named Bar then I want to know the following. lets say Foo looks something like public abstract class Foo { Service serviceFoo ... } And Bar is public class Bar extends Foo { ... } Also, lets assume I have an instance with Foo, named foo, currently that has serviceFoo instantiated If I then declare: Foo foo = new Bar(); will this create a a new instance of Bar that has serviceFoo instantiated or not? E.g. will that field be inherited and instantiated or just inherited?

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